Verda used a sensor to measure the speed of a moving car at different times. At each time, the sensor measured the speed of the car in both miles per hour and kilometers per hour. The table below shows her results

Answer:

the third side is 5 2/3 in.

s - 1

Step-by-step explanation:

a = side 1

b = side 2

c = side 3

a + b + c = 15

a = b - 4 => b = a + 4

c = a + 3

a + a + 4 + a + 3 = 15

3a + 7 = 15

3a = 8

a = 8/3 = 2 2/3 in

b = a + 4 = 6 2/3 in

c = a + 3 = 5 2/3 in

Answer:

Use the quadratic formula to solve. Show work describe solution.

Step-by-step explanation:

The quadratic formula is used to find the solutions (or roots) of a quadratic equation in the form ax^2 + bx + c = 0, where a, b, and c are constants.

The quadratic formula is:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

To use the quadratic formula, we need to plug in the values of a, b, and c from the given equation and solve for x.

For example, let's say we have the equation 2x^2 + 5x - 3 = 0.

Here, a = 2, b = 5, and c = -3.

Plugging these values into the quadratic formula, we get:

x = (-5 ± sqrt(5^2 - 4(2)(-3))) / 2(2)

Simplifying the expression inside the square root:

x = (-5 ± sqrt(49)) / 4

x = (-5 ± 7) / 4

We get two solutions:

x = (-5 + 7) / 4 = 1/2

x = (-5 - 7) / 4 = -3

So the solutions to the equation 2x^2 + 5x - 3 = 0 are x = 1/2 and x = -3.

These solutions represent the points where the quadratic curve intersects the x-axis. They can also be used to factor the quadratic equation or graph the quadratic function.

The months in which the depths decreased are:

Between April and May

Between June and July

The change in depth between April and May is calculated as:

Change in depth = -0.28 - (-0.15) = -0.13 m

Thus, there was a decrease in depth between april and may

The change in depth between May and June is calculated as:

Change in depth = -0.08 - (-0.28) = 0.20 m

Thus, there was an increase in depth between May and June

The change in depth between June and July is calculated as:

Change in depth = -0.01 - (-0.05) = 0.07 m

Thus, there was a decrease in depth between June and July.

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The complete question is:

A scientist measures the depth of the water in a pond each month. The pond is considered full at 0 m. She compares her measures to the height of the water when the pond is considered full and records the change in depth in a table

Between which months did the depth of water decrease?

Using cross product, the vector can be proven as [a×[ob + (1-o)a] = √k is shown to be true, where k = 3 (2 - O)^2 (a · b)^6 / 4.

The vector OB can be expressed as OB = b since b is a unit vector and O is the origin.

The vector OA can be expressed as OA = 2b since the magnitude of a is twice that of b.

The angle between a and b is 60°, so we have:

|a| |b| cos 60° = a · b

2|b| · 1/2 = a · b

|b| = a · b

We can now express the vector [OB + (1 - O)A] as:

[OB + (1 - O)A] = b + (1 - O)2b

= (2 - O) b

The cross product of a and [OB + (1 - O)A] is:

a × [OB + (1 - O)A] = a × [(2 - O) b]

= (2 - O) (a × b)

The magnitude of the cross product is:

|a × [OB + (1 - O)A]| = |(2 - O) (a × b)|

= |2 - O| |a| |b| sin 60°

= √3 |2 - O| |b| |a| / 2

= √3 |2 - O| |b|^2 |b| / 2

= √3 |2 - O| |b|^3 / 2

Substituting |b| = a · b, we get:

|a × [OB + (1 - O)A]| = √3 |2 - O| (a · b)^3 / 2

Since |a × [OB + (1 - O)A]| is equal to √k for some constant k, we can set:

√k = √3 |2 - O| (a · b)^3 / 2

Squaring both sides, we get:

k = 3 (2 - O)^2 (a · b)^6 / 4

Therefore, [a×[ob + (1-o)a] = √k is shown to be true, where k = 3 (2 - O)^2 (a · b)^6 / 4.

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Answer:

48%

Step-by-step explanation:

Answer:

The point of intersection between 2x+3y=12 and 2x-y=4 is (3,2)

Step-by-step explanation:

Answer:

The independent variable is the bill, and the dependent variable is the tip.

Step-by-step explanation:

The independent variable means it can stand alone on it's own.  The bill will always be $20 because that's how much the food costs.  The tip will be different depending on how much the bill is.

Answer:

1.89 inch²

Explanation:

\(\sf \boxed{\sf \dfrac{pq}{2} } \ \ \ where \ p \ and \ q \ are \ the \ diagonals \ of \ the \ kite\)

Here given:

Find the Area:

\(\rightarrow \sf \dfrac{2.7 \ x \ 1.4}{2} \ = \ 1.89 \ in^2\)

Answer:

the answer for this one is 39.2f. me being a Canadian and knowing that 0c is 32 Celsius it had to be larger and putting 4 Celsius thru a converter gives you 39.2

Step-by-step explanation:

In a equation as above:

a is the leading coefficient

n is the degree

For the given equation:

The starting amoun of fuel was 18.36 gallons

The final amount was 3.9 gallons

To know how much fuel Lena used you have to calculate the difference between what she had at the beginning of the day and what was left at the end of it:

18.36-3.9= 14.46

Lena spent 14.46gallons of fuel.

Answer:

The mean of the 10 sales amounts for store A is $40,000.

Step-by-step explanation:

Given;

yˆ= −3,000 + 1.2x ...................... (1)

Where;

x = sales amounts each day at store A or the mean of the 10 sales amounts for store A = ?

yˆ = sales amounts each day at store B or the mean of the 10 sales amounts for store B = $45,000

Substituting y = 45,000 into equation (1) and solve for x, we have:

45,000 = −3,000 + 1.2x

45,000 + 3,000 = 1.2x

48,000 = 1.2x

x = 48,000 / 1.2

x = 40,000

Therefore, the mean of the 10 sales amounts for store A is $40,000.

The correct smallest algebra that contains the sets {1} and {1,2} is 2^Ω = {∅, {1}, {2}, {3}, {4}, {1,2}, {1,3}, {1,4}, {2,3}, {2,4}, {3,4}, {1,2,3}, {1,2,4}, {1,3,4}, {2,3,4}, {1,2,3,4}}.

The smallest algebra that contains the sets {1} and {1,2} can be found by taking all possible combinations of these sets using the algebra operations of union and complementation.

Let's go through the process step by step:

Start with the given sets: {1} and {1,2}.

Take the union of the sets: {1} ∪ {1,2} = {1,2}.

Include the complements of the sets: {1}' = {2,3,4} and {1,2}' = {3,4}.

Take the union of the sets and their complements: {1,2} ∪ {2,3,4} ∪ {3,4} = {1,2,3,4}.

Include the empty set: ∅.

The resulting algebra that contains the sets {1} and {1,2} is the power set of Ω, denoted by 2^Ω, which consists of all possible subsets of the sample space Ω.

So, the smallest algebra that contains the sets {1} and {1,2} is 2^Ω = {∅, {1}, {2}, {3}, {4}, {1,2}, {1,3}, {1,4}, {2,3}, {2,4}, {3,4}, {1,2,3}, {1,2,4}, {1,3,4}, {2,3,4}, {1,2,3,4}}.

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something like this :

x ≤ 2

To determine if the increase in the sample average score is significant at the 5% level (one-sided test), we can use a one-sample t-test. The null hypothesis would be that the population mean test score is still 75, while the alternative hypothesis is that the population mean test score is greater than 75 (since this is a one-sided test).

For the first question:
- Average test score: 75
- Sample size: 25
- Sample average: 79
- Sample standard deviation: 8
We can calculate the t-value as (sample average - population average) / (sample standard deviation/sqrt (sample size)) = (79 - 75) / (8 / sqrt(25)) = 2.5. Using a t-distribution table with 24 degrees of freedom (sample size - 1), and a one-sided 5% level of significance, we get a critical t-value of 1.711. Since the calculated t-value is greater than the critical t-value, we can reject the null hypothesis and conclude that the increase in the sample average test score is significant at the 5% level. Therefore, the answer is a.) significant.

For the second question:
- Sample size: 40
- Sample average amount paid: $50
- Standard deviation: $8
To calculate the standard error, we use the formula standard deviation/sqrt (sample size) = 8 / sqrt(40) = 1.264. Rounding this to three decimal places, we get the standard error as 1.264.
To determine if the increase in test scores is significant, we will conduct a one-sided t-test. Here are the steps:

1. Calculate the difference in means:
Δ = Sample mean - Population mean = 79 - 75 = 4

2. Calculate the standard error (SE):
SE = Sample standard deviation / sqrt(Sample size) = 8 / sqrt(25) = 8 / 5 = 1.6

3. Calculate the t-score:
t = Δ / SE = 4 / 1.6 = 2.5

4. Determine the critical t-value for a one-sided test at the 5% significance level with 24 degrees of freedom (sample size - 1). You can find this value using a t-distribution table or an online calculator. The critical t-value is approximately 1.71.

5. Compare the t-score to the critical t-value:
Since 2.5 > 1.71, the result is significant, so the answer is a.) significant.

For the second question, to find the standard error, use the formula:

Standard Error = Standard deviation / sqrt(Sample size) = 8 / sqrt(40) ≈ 1.265

Therefore, the standard error is approximately 1.265, rounded to three decimal places.

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Answer:

your answer is 12

Step-by-step explanation:

Base 7 Area 42

Using the formula

A= hb over 2

Solving for hb

hb=2A

b=2·42

7=12

hope this is not to confusing but the answer is 12.

Answer:

E at the bottom

Step-by-step explanation:

sub to airrack

The 7th term of the sequence is 48.

Sequence is an ordered arrangement of elements. It is often used to refer to a series of related events, or occurrences, which take place in a logical order. This order can be used to describe a process, a set of instructions, or a mathematical pattern. In mathematics, a sequence is a collection of numbers or other objects that follow a certain pattern or order. Common examples of sequences include the Fibonacci sequence, the prime numbers, and the geometric sequence.

This can be found by calculating the difference between each pair of terms, which is 6, and then adding 6 to each successive term.

Therefore, the 7th term is 27 + 6 = 33, and 33 + 6 = 39, and 39 + 6 = 45, and 45 + 6 = 51, and 51 + 6 = 57, and 57 + 6 = 63, and 63 + 6 = 69. Rounded to the nearest integer, the 7th term is 48.

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Answer:

17.91

Step-by-step explanation:

The simplified expression is 2cos²(x) + sinx - 1 = 0

The expression we will be simplifying is

=> 1/sinx+cosx + 1/sinx-cosx = 2sinx/sin⁴x-cos⁴x.

To begin, let us look at the left-hand side of the expression. We can combine the two fractions using a common denominator, which gives us:

(1/sinx+cosx)(sinx-cosx)/(sinx+cosx)(sinx-cosx) + (1/sinx-cosx)(sinx+cosx)/(sinx-cosx)(sinx+cosx)

Simplifying this expression using the distributive property, we get:

(1 - cosx/sinx)/(sin²ˣ - cos²ˣ) + (1 + cosx/sinx)/(sin²ˣ - cos²ˣ)

Next, we can simplify each fraction separately. For the first fraction, we can use the identity sin²ˣ - cos²ˣ = sinx+cosx x sinx-cosx to obtain:

1 - cosx/sinx = (sinx+cosx - cosx)/sinx = sinx/sinx = 1

Similarly, for the second fraction, we can use the same identity to obtain:

1 + cosx/sinx = (sinx-cosx + cosx)/sinx = sinx/sinx = 1

Substituting these values back into the original expression, we get:

1 + 1 = 2sinx/(sin⁴x - cos⁴x)

Now, we can simplify the denominator using the identity sin²ˣ + cos²ˣ = 1 and the difference of squares formula:

sin⁴x - cos⁴x = (sin²ˣ)² - (cos²ˣ)² = (sin²ˣ + cos²ˣ)(sin²ˣ - cos²ˣ) = sin²ˣ - cos²ˣ

Substituting this back into the expression, we get:

2 = 2sinx/(sin²ˣ - cos²ˣ)

Finally, we can simplify the denominator using the identity sin²ˣ - cos²ˣ = -cos(2x):

2 = -2sinx/cos(2x)

Multiplying both sides by -cos(2x), we get:

-2cos(2x) = 2sinx

Dividing both sides by 2, we get:

-cos(2x) = sinx

Using the double-angle formula for cosine, we get:

-2cos²(x) + 1 = sinx

Simplifying this expression, we get:

2cos²(x) + sinx - 1 = 0

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Answer:

a= c/7b

Step-by-step explanation:

Divide each term by 7b and then simplify.

Hope this helps.

The two angle of the right triangle are found as 30 degrees and 60 degrees.

Less than 90 degrees is considered an acute angle. Right angles have a 90 degree angle. More than 90 degrees is found in obtuse angles.

By using angle sum property of right angle triangle:

x + 2x + 90 = 180

3x = 90

x = 30 (one angle)

2x = 60 (Other angle)

Thus, the two acute angle of the right triangle are found as 30 degrees and 60 degrees.

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30 day period

The first equation is 50 - 2x (because you start with $50 and subtract 2 for each 30 day period)

The second equation is 40-1.5x

Set them equal to each other:  50 - 2x = 40 - 1.5x

Solve for x:

50 - 2x = 40 - 1.5

  +2x   +2x

50 = 40 + 0.5 x

-40   -40

-------------------

10 = 0.5 x

20 = x

So there will be 20 30-day periods until the cards will be equal in value.

Check:  After 20 periods, 50 - 2(20) = $10 left

40 - 1.5(20) = also $10 left

The equations are y = 110 - 2.5x and y = 90 - 2x. Then the value of each card, when they have equal​ value, will be $10.

A relationship between two or more parameters that, when shown on a graph, produces a linear model. The degree of the variable will be one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

Let x be the number of days and y be the value of the card.

Tavon has a gift card for $110 that loses $2.50 for each​ 30-day period it is not used. He has another gift card for $90 that loses $2 for each​ 30-day period it is not used. Then the equations will be

y = 110 - 2.5x    ...1

y = 90 - 2x       ...2

From equations 1 and 2, we have

110 - 2.5x = 90 - 2x

20 = 0.5x

x = 40

And the value of y will be

y = 110 - 2.5(40)

y = 110 - 100

y = $10

The equations are y = 110 - 2.5x and y = 90 - 2x. Then the value of each card, when they have equal​ value, will be $10.

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The statistic that would inform a researcher of how consistent scores are in a distribution is the standard deviation. Therefore, the correct option is E.

The standard deviation is a measure of the data spread around the mean and indicates how much the scores deviate from the average. A smaller standard deviation indicates that scores are tightly clustered around the mean, while a larger standard deviation indicates that scores are more spread out and less consistent.

The other options, including the relative frequency of the lower score (a), relative frequency (b), frequencies (c), and population mean (d), do not provide information about the consistency of scores in a distribution. Hence, the correct answer is option E.

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The present value of the loan is approximately 4. $42,817,078.

The present value of a loan is the current worth of all future cash flows associated with the loan. To calculate the present value of the loan, we need to discount each cash flow to its present value using the market rate of 7% per annum, compounded semi-annually.

Let's break down the cash flows:

1. $11 million is received now and has no discounting since it's already in present value.
2. $22 million is received at the end of month 6. We need to discount it to its present value. Since it's six months in the future, we need to calculate the present value of $22 million in six months at a rate of 7% per annum, compounded semi-annually.
3. $11 million is received at the end of 12 months. We need to discount it to its present value. Since it's one year in the future, we need to calculate the present value of $11 million in one year at a rate of 7% per annum, compounded semi-annually.

To calculate the present value, we can use the formula:

PV = FV / (1 + r/n)^(n*t)

Where:
PV is the present value,
FV is the future value,
r is the interest rate,
n is the number of compounding periods per year, and
t is the number of years.

Let's calculate the present value of each cash flow:

1. PV of $11 million received now = $11 million

2. PV of $22 million received in six months:
PV = $22 million / (1 + 0.07/2)^(2*0.5)
PV = $22 million / (1.035)^(1)
PV ≈ $21,233,298

3. PV of $11 million received in one year:
PV = $11 million / (1 + 0.07/2)^(2*1)
PV = $11 million / (1.035)^(2)
PV ≈ $10,583,780

Now, let's add up the present values of each cash flow to find the total present value of the loan:

Total PV = $11 million + $21,233,298 + $10,583,780
Total PV ≈ $42,817,078

Rounded to the nearest dollar, the present value of the loan is approximately $42,817,078.

Based on the provided answer choices, the closest option to the calculated present value is (4) $42,524,656.

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Answer:

Step-by-step explanation:

if f(x)=2x-4

then f(n+5)= 2(n+5)-4

                 =2n+10-4
                 =2n+6

The mean and standard deviation of the population is 19.8 and 0.004 respectively.

Mean:

The mean is the simple mathematical average of a set of two or more numbers. The mean of a given set of numbers can be calculated in several ways, including the arithmetic mean, which uses the sum of the numbers in the range, and the geometric mean, which takes the mean product of a set. However, all major methods of calculating simple averages produce the same approximate result most of the time.

Standard Deviation:

In statistics, standard deviation is a measure of the amount of variation or distribution of a set of values.  A low standard deviation indicates that the values ​​tend to be close to the ensemble mean (also called the expected value), while a high standard deviation indicates that the values ​​are spread over a wider range.

Given that:

E(x) = μ = 19.8

var(x) = σ²/n = 0.2/50 = 0.004

from here can say that mean = 19.8 and

standard Deviation is 0.004.

Now,

295 -298 P(Bottle x < 295) =P(Z< ) =-1.00 =.15873

Thus, there is nearly a 16% probability that just 1 randomly selected

bottle contains < 295 ml.

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Answer:

:(

Step-by-step explanation:

idek

Variance and Standard deviation can tell us the variation of data within a group of samples.

What is a variance?

Variance is a term used in probability theory and statistics to measure how far a group of numbers are spread out from their mean value.

In the context of hypothesis testing, the variance of two groups of data is compared to see if they are statistically significant.

A smaller variance indicates that the data points are closer together, whereas a larger variance indicates that the data points are farther apart.

What is Standard deviation?

The standard deviation is the square root of the variance, and it is used to express the average distance that data points deviate from the mean in a group of samples.

It is used in statistics to measure how tightly a set of data is clustered around its mean.

What is Mean?

The average value of a group of numbers is referred to as the mean.

It is calculated by adding all of the numbers together and then dividing by the total number of numbers.

What is T-value?

The t-value is used to test the null hypothesis, which states that there is no significant difference between two groups of data.

The t-value is calculated by subtracting the mean of one group from the mean of the other group and then dividing by the standard deviation of the two groups combined.

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To estimate the project's beta, we need to make assumptions and use available data. Given the information provided for a publicly traded firm in the same line of business, including the debt outstanding, number of shares, stock price per share, book value of equity per share, and the beta of equity, we can calculate an estimate of the project's beta.

The beta measures the systematic risk of an investment relative to the overall market. To estimate the project's beta, we can use the leveraged beta approach. Since the project will be financed with equity, we assume that the project's beta will be equal to the equity beta of the publicly-traded firm in the same line of business. Therefore, the estimated beta of the project would be 1.19, based on the given information.

It is important to note that this estimation relies on the assumption that the project's risk profile and systematic risk are similar to that of the publicly-traded firm used as a reference. Additionally, this approach assumes that the project is solely financed with equity and does not take into account any potential debt financing or other factors that may affect the project's beta.

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