The mean is the sum of all data divided by the number of data.
You have 6 data:
Mean: 90.7\(\frac{98+98+90+82+89+87}{6}=\frac{544}{6}=90.7\)-----------------------------------------------
The Median is the data in the middled of the data when the data is froms least to greatest.
\(82,87,89,90,98,98\)In this case as the number of data is 6 you take third and fourth data and find the average (sum the data and divide into 2):
\(\frac{89+90}{2}=89.5\)Median: 89.5----------------------------------
The mode is the data that appears the most:
Mode:98----------------------
The Range is the difference between the largest and the smallest data.
\(98-82=16\)Range: 16What is the equation of a line that passes through the given point m=-6 (4,6)
Answer:
The equation of the line that passes through the point (4,6) with a slope of -6
is y=-6x+30
Step-by-step explanation:
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was -6. So you can right away fill in the equation for a line somewhat to read:
y=-6x+b.
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(4,6). When x of the line is 4, y of the line must be 6.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the -6 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the point (4,6).
So, why not plug in for x the number 4 and for y the number 6? This will allow you to solve the particular line that passes through the point you gave!.
(4,6). y=mx+b or 6=-6 × 4+b, or solving for b: b=6-(-6)(4). b=30.
5 cm
6 cm
13 cm
Help me find the area of this please
The area should be 47.5 CM.
Answer:
Step-by-step explanation:
The figure you see here is a trapezoid.
Area = \(\frac{(a + b)h}{2}\) = \(\frac{(6 + 13)(5)}{2}\) = \(\frac{(19)(5)}{2}\) = \(\frac{95}{2}\) = 47.5 cm
Suppose cos(O) = 12/13, Quadrant I. Find sin(O).
A:13/12
B:5/13
C:13/5
D:5/12
Answer:
B: 5/13
Step-by-step explanation:
pythagoras theorem: a^2 + b^2 (sides) = c^2 (hypotenuse)
a^2 + 12^2 = 13^2
a^2 + 144 = 169
a^2 = 25
a = 5
sin = opp/hyp
sin 5/13
Hope this helps
Find the volume and surface area of the trapezoidal prism.
Answer:
sa =45
vol = 6000.
I hope it helps. and if you can, give me the brainlist
Kelli swam upstream for some distance in one hour. She then swam downstream the same river for the same distance in only 6 minutes. If the river flows at 5 km/hr, how fast can Kelli swim in still water?
Choose the most logical value for the variable to represent.
Let x = .
3m = 15
9 + 15m = 12m – 1
3m = 18
9 + 6 – 15 = 15m – 12m
By solving a system of equations, we conclude that Kelli's speed on still water is 6.1km/h
How fast can Kelli swim in still water?Let's say that the speed of Kelli in still water is S. And we know that the speed of the river is 5km/h.
When she swims upstream, her velocity is:
(S - 5km/h)
When she swims downstream, her velocity is:
(S + 5km/h)
With the given information, we can write for a distance D:
(S - 5km/h)*1h = D
(S + 5km/h)*6min = D
First, let's rewrite 6 minutes into hours.
1 hour = 60min
6 min = 6/(60) hours = 0.1 hours
Then the system of equations that we need to solve is:
(S - 5km/h)*1h = D
(S + 5km/h)*0.1h = D
D is the same distance in both cases, then we can write:
(S - 5km/h)*1h = (S + 5km/h)*0.1h
Now we can solve this for S.
S*1h - 5km = S*0.1h + 0.5km
S*1h - S*0.1h = 5km + 0.5km
S*(0.9h) = 5.5km
S = 5.5km/0.9h = 6.1km/h
Kelli's speed on still water is 6.1km/h
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Find the critical value ta/2 needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places.
(a) For level 90% and sample size 8.
(b) For level 99% and sample size 11.
(c) For level 95% and sample size 25.
(d) For level 99.5% and sample size 10.
Answer:
1.894
3.169
2.064
3.690
Step-by-step explanation:
A.) 90% ; sample size = 8
Degree of freedom, df = n - 1
t(1 - α/2, 7) = t0.05, 7 = 1.894
B.) 99% ; sample size = 11
Degree of freedom, df = n - 1
t(1 - α/2, 10) = t0.005, 10 = 3.169
C.) 95% ; sample size = 25
Degree of freedom, df = n - 1
t(1 - α/2, 24) = t0.025,24 = 2.064
(D.) 99.5% and sample size 10.
Degree of freedom, df = n - 1
t(1 - α/2, 9) = t0.0025,9 = 3.690
In the square pyramid shown, points and are midpoints of the edges of one face. If the figure is sliced through points and and through the base, which best describes the shape of the resulting cross section? The picture shows a triangular prism. M and N are the points on the prism. A. rectangle B. trapezoid C. quadrilateral D. parallelogram
Based on the given information, we have a square pyramid with points M and N being the midpoints of the edges of one face. and forms a parallelogram. Option D
Since the base of the pyramid is a square, the cross section will consist of a square shape. Additionally, since the slice is made through the midpoints of the edges of the face, the resulting cross section will have parallel sides.
Considering these characteristics, we can conclude that the shape of the resulting cross section is a parallelogram. A parallelogram is a quadrilateral with opposite sides parallel. In this case, the opposite sides of the square cross section will be parallel, as the slice passes through the midpoints of the edges.
Therefore, the correct answer is D. parallelogram.
It's important to note that a triangular prism is not the correct answer because a triangular prism is a three-dimensional figure with two triangular bases and three rectangular faces. The cross section resulting from the given slice will not have the characteristics of a triangular prism. Option D.
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Answer all questions shown
unit 7 right triangles & trigonometry homework 5: trigonometry : finding sides and angles
Answer:
1. 7.3
2. 33.3
3. 21.3
4. 31.9
5. 25.6
6. 11.0
7. 42°
8. 64°
9. 13°
10. 51°
Step-by-step explanation:
make sure if you're using a math calculator that it is in degree mode.
SIN, COS, OR TAN. SOH CAH TOA. Sin is Opposite/hypotenus.
Cos is Adjacent(next to it)/hypotenus.
Tan is Opposite/Adjacent.
~~
PROBLEM 1:
So we have 63°, 16 as hypotenus, and x as one of the legs.
1. Figure out whether it is Sin, Cos, or Tan. (It's adj and hyp. of the angle degree (63° listed so it's cos.)
2. Once you set it up, it is Cos 63°= x/16 then flip it around. which makes it 16 COS 63= X.
3. Input it into your calculator as 16cos(63, then it will give you.. 7.263847996
4. Don't forget to round to the nearest tenth, which gives you
x = 7.3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 2:
Given: 39°, 27 is opposite of the °, and adj is x. So this is Tan.
1. Set it up, Tan 39° = 27/x can't solve this way so fix it.
2. rewritten as X = 27/tan39
3. round ur answer.
x = 33.3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 3:
Given: 49°, adj is 14, hyp is x. So this is Cos.
1. Set up according to CAH, Cos 49=(14/x).
We can't solve it this way since the X is on the bottom. So we have to fix it!
2. Turns into X Cos 49 = 14, which then turns into X= 14/cos49.
3. Put it in your calculator as 14 DIVIDED BY cos 49. ( Put image example)
4. Round.
x= 21.3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 4:
Given: 15°, 33 hyp, adj x. Which is Cos.
1. Cos 15= x/33 and rewrite.
2. Input as 33 cos(15 into calculator = 31.875...
3. Round to tenth.
x = 31.9
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 5:
Given: 52°, 20 adj of °, and x opp of °. Will use TAN.
1. Tan 52° = x/20
2. 20 Tan(52 into calculator
3. Round
x = 25.6
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 6:
Given: 27°, opp of ° is 5, hyp is x. Will use Sin.
1. Write out as I have the last few times, Sin 27 = 5/x rewrite cause x can't be at the bottom.
2. Input into calculator as: 5/sin 27 which equals 11.01...
3. Round.
x = 11.0
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 7:
Given: x°, 6 as hyp, 4 opp. now we have to solve this different since we don't know the degree. Now when we input into the calculator you will press 2nd, then sin/cos/tan so it will be negative this is depending on which one ur solving for.
We will be using SIN, x is still a °.
1. Sin X = 4/6 Rewrite.
2. X= Sin^-1 (4/6)
Make sure ur sin is negative in calculator when doing this.
3. It SHOULD give you 41.81, round.
x = 42°
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 8:
Given: x°, 29 opp, 14 adj. TAN.
1. Tan x°= 29/14 or..
2. X = Tan^-1(29/14) solve..
3. gives u 64.23.... round.
x = 64°
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 9:
Given: x°, hyp 54, opp 12. SIN
1. Sin x°=(12/54)
2. X= Sin^-1(12/54) solve. (dont put x= into calculator.)
3. Don't Forget to round, answer unrounded: 12.839..
x = 13°
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 10:
Given: x°, adj 25, hyp 40. COS
1. Cos x°=25/40 rewrite.
2. X= Cos^-1(25/40) Solve.
3. Round.
X= 51°
Write the number in standard form and expanded form. Three million four hundred eighty- seven thousand six hundred fifty-one
Answer:
down below
Step-by-step explanation:
3,487, 651
(3 x 1,000,000) + (4 x 100,000) + (8 x 10,000) + ( 7 x 1,000) + (6 x 100 ) +
(5 x 10) + (1 x 1)
The slope of the tangent line to the curve y= 3/x
at the point 5, 3/5 is-
The equation of this tangent line can be written in the form y = mx + b
where:
m is:
b is:
The tangent line at that point is:
y = (-3/25)*x + 6/5
so m = -3/25, and b = 6/5
How to find the slope of the tangent line?To find the slope at that point, we need to evaluate the derivative at that point.
y = 3/x
The derivative is:
y' = -3/x²
When x = 5, we have:
y' = -3/5² = -3/25
So that is the slope, m.
Now let's find the line.
The line must pass trhough the point (5, 3/5), then:
3/5 = (-3/25)*5 + b
3/5 = -3/5 + b
3/5 + 3/5 = b
6/5 = b
The equation of the line is:
y = (-3/25)*x + 6/5
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Which comparison is correct?
Answer:
C is correct
Step-by-step explanation:
10/12=0.83...
2/3=0.66...
2/3<10/12
Answer:
C
Step-by-step explanation:
Why the others are incorrect:
A: \(\frac{2}{10} > \frac{3*2}{5*2}\) → \(\frac{2}{10} > \frac{ 6}{10}\) This statement/comparison is false
B : \(\frac{2*2}{4*2} > \frac{4}{8}\) → \(\frac{4}{8} > \frac{4}{8}\) This statement/comparison is false
D:\(\frac{9}{12} < \frac{3*2}{6*2}\) → \(\frac{9}{12} < \frac{6}{12}\) This statement/comparison is false
Why answer C is CorrectC: \(\frac{2*4}{3*4} < \frac{10}{12}\) → \(\frac{8}{12} < \frac{10}{12}\) This statement/comparison is true
Consumer Price Index, 1970-2002
Year
1970
1975
1980
1985
1990
1995
2002
Source: World Almanac 2003
CPI
116.3
161.2
248.8
322.2
391.4
456.5
535.8
Describe how the CPI is related to the year.
As the year increases, the CPI decreases and then increases.
As the year increases, the CPI increases and then decreases.
As the year increases, the CPI decreases.
d. As the year increases, the CPI increases.
C.
a.
b.
The computation of the increased in salary is $500.
Here, we have,
Explanation:
Data provided in the question
Salary for the first year = $50,000
CPI increase during the year = 4%
Overstated inflation = 1% i.e. 5%
The computation of the increased in salary is shown below:
= Salary of the first year × inflation rate - salary of the first year × CPI increase during the year
= $50,000 × 5% - $50,000 × 4%
= $2,500 - $2,000
= $500
Hence, The computation of the increased in salary is $500.
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complete question:
Mark's wage contract specifies a $50,000 salary for the first year, and specifies a salary increase equal to the percentage increase in the CPI during the second year. The increase in the CPI during the year was 4.0%. If the CPI overstates inflation by 1.0% (that is, the actual price increase was 3% and not 4%), at the end of the first year Mark's salary increased by $________ more than it would have without the upward bias.
PLEASE I NEED HELP!! LOOK AT THE PHOTO!!
ILL GIVE POINTS!!
Answer:
The system of inequalities representing the situation above is given as:
Number of ink drawings x ≥ 0
Number of water colors ≥ 0
Number of preparation time: 0.3x + 0.5y ≤ 120
Number of packaging time: 0.2x + 0.2y ≤ 60
Step-by-step explanation:
They volunteered to spend:
Number of hours for preparation = 120
Number of hours for packaging = 60
Number of hours to prepare ink drawing = 0.3
Number of hours to prepare water colour = 0.5
Number of hours it takes to package each card = 0.2
x = number of ink drawings
y = number rod water colour
The system of inequalities representing the situation above is given as:
Number of ink drawings x ≥ 0
Number of water colors ≥ 0
Number of preparation time: 0.3x + 0.5y ≤ 120
Number of packaging time: 0.2x + 0.2y ≤ 60
Option d is the correct option
Anastasia is grocery shopping with her father and wonders how much shopping is left to do. "We already have 60\%60%60, percent of the items on our list," her father says. Anastasia sees 121212 items in the cart.
The number of items on their grocery shopping list given the percentage already bought is 20 items.
How many grocery items are on the list?Percentage of items bought already= 60%
Number of items bought already= 12
Total number of items on the list= x
Number of items bought already = Percentage of items bought already × Total number of items on the list
12 = 60% × x
12 = 0.6 × x
12 = 0.6x
divide both sides by 0.6
x = 12/0.6
x = 20 items
Hence, there are a total of 20 items on their grocery list.
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Which of the following are solutions to the equation below? Check all that apply. x2 + 10x + 25 = 2
Answer:
-5+√2 and -5-√2
Step-by-step explanation:
With the quadratic formula:
\(\displaystyle x^2 + 10x + 25 = 2\\\\x^2+10x+23=0\\\\x=\frac{-10\pm\sqrt{10^2-4(1)(23)}}{2(1)}=\frac{-10\pm\sqrt{100-92}}{2}=\frac{-10\pm\sqrt{8}}{2}=\frac{-10\pm2\sqrt{2}}{2}=-5\pm\sqrt{2}\)
We can also complete the square (which is faster):
\(x^2+10x+25=2\\(x+5)^2=2\\x+5=\pm\sqrt{2}\\x=-5\pm\sqrt{2}\)
Figure NN is the result of a transformation on Figure MM. Which transformation would accomplish this?
The transformation that is used is a translation of 3 units upwards.
Numerous different coordinate systems can be used to describe geometrical figures.
The connection between several systems is defined by coordinate transformations, which offer formulas for the coordinates in one system in terms of the coordinates in another system. For example, if the polar axis on a plane is the positive x axis and the origins of the Cartesian coordinates (x, y) and the polar coordinates (r), respectively, are the same. The transformation of the coordinates from the polar to the Cartesian coordinate system is x = r cos α and y = r sin α.From the diagram of the graph we can see that the transformation that is used is translation of 3 units upwards.
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Differentiate. F(x) = (x3 - 3)2/3 2x f'(x) - 3 8 O f'(x) = 3 8 2x2 f'(x) 3 VX3 -8 f(x) 3 V3-8
Answer:
\( f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } }\)
Step-by-step explanation:
\(f(x) = ( {x}^{3} - 8)^{ \frac{2}{3} } \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2} - 0) \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2 - 3}{3} } \times 3 {x}^{2} \\ \\ f'(x) = 2{x}^{2}( {x}^{3} - 8)^{ \frac{ - 1}{3} } \\ \\ f'(x) = \frac{2{x}^{2}}{( {x}^{3} - 8)^{ \frac{ 1}{3} } } \\ \\ \huge \red{ \boxed{ f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } } }}\)
Please help worth 10 points is this true that line n is perpendicular to line p? I think the answer is C, is this correct or not?
Answer: A
because slope are
Calcular los 3/5 de los 2/3 de las 3/4 de 560
For the fractions, the calculation of 3/5 of 2/3 of 3/4 of 560 is equal to 168.
How to solve fractions?To calculate 3/5 of 2/3 of 3/4 of 560, break it down step by step:
Step 1: Calculate 3/4 of 560:
3/4 × 560 = (3 × 560) / 4 = 1680 / 4 = 420
Step 2: Calculate 2/3 of the result from Step 1:
2/3 × 420 = (2 × 420) / 3 = 840 / 3 = 280
Step 3: Calculate 3/5 of the result from Step 2:
3/5 × 280 = (3 × 280) / 5 = 840 / 5 = 168
Therefore, 3/5 of 2/3 of 3/4 of 560 is equal to 168.
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Find the area of ABC
Help
The value of the scale factor is 3. Then the height and area of the triangle ΔABC will be 9 ft and 54 square ft.
What is dilation?Dilation means the changing of the size of the object without changing the shape. The size of the object may be increased or decreased based on the scale factor.
The area of the triangle ΔDEF is 6 square ft. And the base length of the triangle ΔDEF is 4 ft.
The area of the triangle is given as
\(\rm Area = \dfrac{1}{2} \times bh\\\\\)
Then the height of the triangle ΔDEF will be
\(\rm 6 = \dfrac{1}{2} \times 4 \times h\\\\h = \dfrac{12}{4}\\\\h = 3\)
Then the scale factor will be
\(\rm SF = \dfrac{12}{4} = 3\)
Then the height of the triangle ΔABC will be
\(\rm \dfrac{H}{3} = 3\\\\H \ = 9\)
Then the area of the dilated triangle ΔABC will be
\(\rm Dilated \ Area = \dfrac{1}{2} \times 12 \times 9\\\\Dilated \ Area = 54 \ ft^2\)
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Question 1 of 10
Evaluate the following expression. Round your answer to two decimal places.
log79
A. 0.89
Step-by-step explanation:
log(79) = 1.897627091... ≈ 1.90
please help me
A book is marked 21% off. If the original price is $23.42, what will the sale price be?
Round your answer to the nearest cent. Do not include units with your answer.
Answer:
$18.51
Step-by-step explanation:
23.42×.21= 4.91 then 23.42-4.91= your sale price which is $18.51
Find the product of smallest natural number and the smallest whole number , 보라해
Answer:
smallest whole number is 0 so product of 0 is 0
smallest natural number is 1 so product of 1 is 1
What is the midpoint of the line segment with endpoints (-4, 5)
and (4, 3).
Answer:
(0,4)
Step-by-step explanation:
use midpoint formula
Calculate the size of the marked angles
Answer:
see below
Step-by-step explanation:
\(l=\frac{360-2(85)}{2}=180-85 = 95\)
\(m=\frac{360-2(30+95)}{2}=180-125 = 55\)
\(n=180-95=85\\p=360-(30+95+85+55)=95\\q=180-30-95=55\)
A new computer graphics company employs 10 programmers. The company decides to expand into digital animation and needs to transfer 3 of the programmers into the new department. How many different combinations of 3 programmers can be chosen to transfer to the new department?
A. 3
B. 30
C. 120
D. 840
There are 120 different combinations of 3 programmers that can be chosen to transfer to the new department
How to determine the ways of selection?From the question, we have
Total number of programmers, n = 10
Numbers to programmers to select, r = 3
The number of ways of selection could be drawn is calculated using the following combination formula
Total = ⁿCᵣ
Where
n = 10 and r = 3
Substitute the known values in the above equation
Total = ¹⁰C₃
Apply the combination formula
ⁿCᵣ = n!/(n - r)!r!
So, we have
Total = 10!/(7! * 3!)
Evaluate
Total = 120
Hence, the number of ways is 120
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Please explain your answer to the question in the picture with steps.
i need help with "A group of friends were working on a student film. They spent all their budget on equipment and props. They spent $712 on equipment, and 11% of the total budget on props. What was the total budget for their student film?"
The total budget for their student film $800
How to finding the total money your group spent on props?11% of total budget = (11/100) * total budget
= 0.11 * total budget
Let P be the amount the group spent on props.
Now we can write the equation:
P = 0.11 * total budget
We also know that this group spent $712 on equipment. Let E be the amount they spent on equipment.
So it looks like this:
E=$712
Your total budget is the total cost of your equipment and props. This can be written as:
Total Budget = E + P
Plugging in the E and P values, we get:
Total Budget = $712 + 0.11 * Total Budget
Simplifying this equation, we get:
0.89 * total budget = $712
Dividing both sides by 0.89 gives:
Total budget = $800
So her student film had a total budget of $800.
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The slipe of the line passing through the points (7, 5) and (21, 15) is
Answer:
5/7
Step-by-step explanation:
You find a slope by using the equation y2-y1/x2-x1.
In this case: 15-5/21-7
10/14
5/7