Answer:
A. The maximum is 8cm. B. 5 pieces of wire.
Explanation:
To find each pieces' length we need to find what can divide both wires = 8cm
A. The maximum is 8cm.
The amount of pieces = 16m/8m = 2 pieces and 24m/8m = 3 pieces. 2 pieces + 3 pieces = 5 pieces of wire.
B. 5 pieces of wire.
statics and strength of materials
The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.
What is the force P?The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;
Take moment about the joint to determine the magnitude of the force along part BC.
120 kN x 750 mm = F x 1000 mm
F = ( 120 kN x 750 mm ) / ( 1000 mm )
F = 90 kN
Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.
Stress in AB = 2 times stress in BC
P/A₁ = 2F/A₂
where;
A₁ is the area of segment ABA₂ is the area of segment BCA₁ = πd²/4 = π(50 x 10⁻³)²/4
A₁ = 1.96 x 10⁻⁵ m²
A₂ = πd²/4 = π(75 x 10⁻³)²/4
A₂ = 4.42 x 10⁻³ m²
P/A₁ = 2F/A₂
P = (2F x A₁) / (A₂)
P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = 798.2 N
P = 0.798 kN
P ≈ 0.8 kN
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in coming to a stop, an old truck leaves skid marks 45 m long on the highway. assuming a deceleration of 6m/s2 , estimate the speed of the truck just before braking.
The speed of the truck just before braking is 23.24 m/s.
What is the speed of the clock before braking?
The speed of the truck before braking is calculated by applying the third kinematic equation as shown below.
v² = u² - 2as
where;
v is the final velocity of the truck when it stopsa is the acceleration of the trucks is the distance travelled by the truckWhen the truck stops, the final velocity = 0
0 = u² - 2as
u² = 2as
u = √2as
u = √ ( 2 x 6 x 45 )
u = 23.24 m/s
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omparing Technological Design and Scientific Investigation
Explain how the stages of technological design are similar to the process of scientific investigation. Use specific stages from each process to support your answer
Answer:
杰恩斯克克斯克奇沃伊斯克克斯克什德布德克什恩克恩德恩克恩茨克杰兹姆克斯恩斯姆斯姆德恩德姆德武伊乔奥斯克斯杰德布德赫德夫赫富伊什杰吉迪赫德赫夫赫德
Answer:
Scientists learn more about the natural world through investigation by identifying a problem, researching related information, designing and conducting an investigation, analyzing the results, evaluating the conclusion, and communicating the findings. Engineers follow similar steps when creating new products or solutions through technological design. The four stages of technological design include identifying a need, designing and implementing a solution, and evaluating the solution.
A bungee jumper with mass 50.0 kg jumps from a high bridge. After arriving at his lowest point, he oscillates up and down, reaching a low point five more times in 28.0 s. He eventually comes to rest 27.0 m below the level of the bridge. Assume very little damping.
Estimate the spring constant of the bungee cord assuming SHM.
Estimate the unstretched length of the bungee cord assuming SHM.
Express your answer with the appropriate units.
The unstretched length of the bungee cord is 29.4 m.
Simple harmonic motion is a type of periodic motion in which the displacement of an object from its equilibrium position is directly proportional to the force acting on it and is always directed towards the equilibrium position. It is characterized by a sinusoidal pattern of motion and has many real-world applications, including in oscillations of springs and pendulums.
We can solve this problem by applying the principles of simple harmonic motion (SHM) to the bungee jumper's oscillations.
Let's begin by finding the period of oscillation, T. The time it takes for the bungee jumper to reach the lowest point and return to the same point is one period of oscillation. From the problem, we know that the bungee jumper completes 6 cycles (5 low points plus the initial jump) in 28.0 s. Therefore, the period of oscillation is:
T = 28.0 s / 6 = 4.67 s
Next, we can use the formula for the period of an object undergoing SHM to find the spring constant, k, of the bungee cord:
T = 2π √(m/k)
where m is the mass of the bungee jumper. Rearranging this formula to solve for k, we get:
k = (4π²m) / T²
Substituting the given values, we get:
k = (4π² × 50.0 kg) / (4.67 s)² = 360 N/m
So the spring constant of the bungee cord is approximately 360 N/m.
To find the unstretched length of the bungee cord, we can use the fact that the bungee jumper comes to rest 27.0 m below the level of the bridge. At this point, all of the potential energy from the initial jump has been converted into elastic potential energy stored in the bungee cord. Therefore, the total energy of the system is:
E = mgh = (1/2)kx²
where h is the height from which the bungee jumper initially jumped (we assume that there is no air resistance), and x is the unstretched length of the bungee cord.
Substituting the given values, we get:
(50.0 kg)(9.81 m/s²)(27.0 m) = (1/2)kx²
Solving for x, we get:
x = √[(2mgh)/k] = √[(2 × 50.0 kg × 9.81 m/s² × 27.0 m) / 360 N/m] ≈ 29.4 m
Hence, the unstretched length of the bungee cord is approximately 29.4 m.
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I need help with this problem
If we rank these magnets from the strongest to the weakest magnetic field the correct order is 4, 3, 2, 1.
How does the magnetic field relate to the radius of a magnet?The magnetic field and radius are related in the context of a charged particle moving in a circular path under the influence of a magnetic field. When a charged particle moves in a circular path under the influence of a magnetic field, the force on the particle is directed toward the center of the circle. In this force, the radius can be expressed as r = mv / Bq.
This equation shows that the radius of the circular path is directly proportional to the velocity of the particle, and inversely proportional to the magnetic field strength and the charge of the particle.
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pls help in astronomy didn’t know what subject to put it under
The subject depicted in the attached image is Astronomy and Astrophysics.
Definitely younger than the SunAO main sequence starB-type starsF-type stars (some)Possibly younger than the SunF1 main sequence starG2 main sequence starMO main sequence starDefinitely older than the SunM-type stars (some)M1, 1 Msun red giantM1, 18 Msun red supergiantWhat is Astronomy?Astronomy is the scientific study of celestial objects such as stars, planets, galaxies, and other phenomena that exist outside of Earth's atmosphere.
Astronomers use a variety of methods to observe and study these objects, including telescopes, spacecraft, and computer simulations.
Astronomy is a broad field that includes many different sub-disciplines, such as astrophysics, planetary science, and cosmology.
Astronomers study the physical properties and behavior of celestial objects, such as their composition, temperature, motion, and evolution.
They also seek to understand the structure and history of the universe as a whole.
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The anomalous expansion characteristics of liquid water are crucial to many biological systems. Rather than an approximately constant value for the coefficient of volume expansion, the value for water changes drastically, as illustrated in the figure.
Below what temperature T
does water shrink when heated?
If the temperature of water at 30 ∘C
is raised by 1 ∘C
, the water will expand. At approximately what initial temperature T
will water expand by twice as much when raised by 1 ∘C
?
(A) The water will shrink when is heated above 4°C. (B).water at an initial temperature of 33.3°C will be expand by twice as much when it is raised by 1°C compared to water at 30°C.
The anomalous expansion of water refers to the fact that its volume increases upon cooling from 4°C to 0°C, and then contracts upon further cooling to 0°C, and continues to contract upon further cooling. Similarly, when water is heated, its volume first contracts until it reaches 4°C, and then expands upon further heating.
To determine at what temperature water shrinks when heated, we need to find the point at which the coefficient of volume expansion, β, becomes negative. The coefficient of volume expansion is defined as the fractional change in volume per degree Celsius change in temperature, i.e.,
β = (1/V) (dV/dT)
where V is the volume of the water and dV/dT is the rate of change of volume with respect to temperature.
At temperatures below 4°C, the coefficient of volume expansion is positive, indicating that water expands upon heating. However, at temperatures above 4°C, the coefficient of volume expansion becomes negative, indicating that water contracts upon heating.
Therefore, water will shrink when heated above 4°C.
To determine the initial temperature at which water will expand by twice as much when raised by 1°C, we can use the formula for the coefficient of volume expansion:
β = (1/V) (dV/dT)
We want to find the initial temperature T such that
(dV/dT)T = 2 (dV/dT)30
where (dV/dT)T is the rate of change of volume with respect to temperature at temperature T, and (dV/dT)30 is the rate of change of volume with respect to temperature at 30°C.
Using the coefficient of volume expansion for water, we have
β = 3α
where α is the coefficient of linear expansion, which is approximately constant for small temperature changes. Therefore, we can write
(dV/dT) = V × 3α
Substituting this into the equation above and simplifying, we get
T = 30 + 10/3 = 33.3°C
Therefore, water at an initial temperature of 33.3°C will expand by twice as much when raised by 1°C compared to water at 30°C.
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Heat rash is caused by chemical exposure Truth or false
Answer:
This is false.
Explanation:
Heat rash develops when some of your sweat ducts clog. Instead of evaporating, perspiration gets trapped beneath the skin, causing inflammation and rash. Heat rash is usually self-limited, meaning it resolves on its own without treatment. Over-the-counter treatments such as calamine, hydrocortisone cream, itch preparations (such as Benadryl spray), or sunburn lotions can be used as skincare to treat the itching and burning symptoms. Heat rash usually goes away on its own within three or four days so long as you don't irritate the site further. Heat rash happens when the sweat glands get blocked. The trapped sweat irritates the skin and leads to small bumps.
Answer:
FALSE
Explanation:
Heat rash develops when blocked pores or sweat ducts trap perspiration under your skin. Symptoms range from superficial blisters to deep, red lumps. Some forms of heat rash feel tingly or intensely itchy.
A wave travels at a consent speed. how does the frequency change if the wavelength is reduced by a factor of 4?
Answer:
The frequency increases by 4 because it is inversely proportional to the wavelength.
What is the turning effect of a force?
A force may cause an object to turn about a pivot. The turning effect of a force is called the moment of the force. Moments act about a pivot in a clockwise or anticlockwise direction.
Answer:
A force may cause an object to turn about a pivot. The turning effect of a force is called the moment of the force. Moments act about a pivot in a clockwise or anticlockwise direction.
Explanation:
What is the displacement of a car traveling 14 km North on I985 then 20 km South on I985?
Displacement = (14-20) Km = -6 Km
The displacement of a car is -6 Km South
I need help pls !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
figure d
Explanation:
The Eyebrow Trimmer 5000 XL that Duncan's "friends" used in themalicious eyebrow-shavingattack works at 30 J/s and gaveout a total of 450J of pure trimming energy.How long did it take for Duncan's friends to shave off his eyebrows?
In order to determine the time, use the following formula for the power:
\(P=\frac{E}{t}\)where,
P = 30J/s
E = 450J
t = ?
Solve the equation above for t and simplify:
\(t=\frac{E}{P}=\frac{450J}{30\frac{J}{s}}=15s\)Hence, the time was 15s
Which of the three types of encoding do you think would give
you the best memory of verbal information?
Answer:
The four primary types of encoding are visual, acoustic, elaborative, and semantic. Encoding of memories in the brain can be optimized in a variety of ways, including mnemonics, chunking, and state-dependent learning.
Explanation:
4. When scientists calculate the trajectory a satellite takes on its way to
study a planet, what do you think they use?
5 points
A Speed and velocity
B. Velocity and acceleration
O C. Speed, velocity, and acceleration
O D. Speed only
When scientists calculate the trajectory a satellite takes on its way to
study a planet, they use C. Speed, Velocity, and acceleration.
A trajectory, often known as a flight path, is the route taken by an object moving under the influence of gravity. Typically, the phrase is applied when referring to projectiles or satellites. A parabola curve is usually a decent approximation of the trajectory form when an object is propelled for in a short distance.
When scientists calculate the trajectory a satellite takes on its way to
study a planet they take the speed, velocity, and acceleration into consideration.
The formula for calculating the trajectory can be expressed as:
\(\mathbf{y = h + xtan (\alpha) - \dfrac{gx^2 }{2V_o^2cos^2 (\alpha)}}\)
where;
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An ice skater at rest on ice catches a dance partner moving 2.5 m/s during a performance. The ice skater has a mass of 68 kg and the dance partner has a mass of 54 kg. What is the speed of the ice skater and dance partner after the collision?
Answer:
A 2.0 m/s
Explanation:
Consider the equation −4x−y=3 A line parallel to the above line would have a slope of Correct A line perpendicular to the above line would have a slope of
ANSWER:
Paralell: -4
Perpendicular: 1/4
STEP-BY-STEP EXPLANATION:
We have the following equation:
\(-4x-y=3\)Now, we have that an equation of a line in its slope-intercept form has the following form:
\(\begin{gathered} y=mx+b \\ \text{where m is the slope and b is y-intercept} \end{gathered}\)We apply it in this case:
\(\begin{gathered} -y=4x+3 \\ y=-4x-3 \\ \text{therefore} \\ m=-4 \end{gathered}\)When two lines are parallel, the slope is the same, while when they are perpendicular, the product of the slopes is equal to -1, we calculate each case below as follows:
\(\begin{gathered} \text{ Parallel} \\ m_1=m_2 \\ m_2=-4 \\ \\ \text{ Perpendicular} \\ m_1\cdot m_2=-1 \\ m_2=\frac{-1}{m_1} \\ m_2=\frac{-1}{-4} \\ m_2=\frac{1}{4} \end{gathered}\)03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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A bicycle travels at a velocity of 2.33 m/s, and has a displacement of -58.3 m. How much time did it take?
Answer:
The time will be: 25.02 seconds
Explanation:
Given
A bicycle travels at a velocity of 2.33 m/s.
i.e.
v = 2.33 m/sand
displacement = d = 58.3 mAs we know the formula to find the time
Time = Displacement/Velocity
= d/v
= 58.3/2.33
= 25.02 seconds
Therefore, the time will be: 25.02 seconds
A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?
Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.
In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.
The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.
A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.
Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.
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Another elephant pushes with 3500 N on a load of trees. It then pushes these trees for 225 m. How much work did he elephant do?
Answer:
787, 500 N/m
Explanation:
Work = Force • displacement
\(Work = (3500 N)(225 m) = 787500\frac{N}{m}\)
\(W = (3500 N)(225 m) = 787500\frac{N}{m}\)
1. Two vectors A and B are perpendicular to each other. The magnitude of the resultant is √80 unit and vector à is twice vector B. Calculate the value of the two vectors.
The magnitude of the resultant is √80 unit and vector à is twice vector B ,hence The two vectors are A = 8 and B = 4.
Given that Two vectors A and B are perpendicular to each other.
The magnitude of the resultant is √80 unit and vector à is twice vector B.
So, the resultant of vectors A and B can be represented as;
\(`A^2 + B^2 = (\sqrt(80)^2`\)
Where \(A^2 and B^2\) are the magnitudes of vectors A and B respectively.
So, `\(A^2 + B^2 = 80`\)
We also know that `A = 2B`
Substitute A with 2B in equation `\(A^2 + B^2 = 80\)` and simplify.
\(`(2B)^2 + B^2 = 80``5B^2 = 80``B^2 = 16``B = ±4`\)
Since B is a vector, we take the positive value of B i.e.
`B = 4`
Then `A = 2B = 2 × 4 = 8`
Hence, the two vectors are A = 8 and B = 4.
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A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?
The answer is that the time the diver was in the air is 1.13 seconds.
To determine the time the diver was in the air, we can use the kinematic equation:
Δy = viΔt + 1/2at²,
where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0
m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²
Simplifying, we get:
4.9t² + 5.5t - 3.0 = 0
We can solve for t using the quadratic formula:
t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s
Since time cannot be negative, the time the diver was in the air is 1.13 seconds.
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The speeds of a 600-kg roller coaster car at the top of three consecutive hills are shown below. The radii of the hills are shown. Determine the acceleration, net force, and normal force experienced by the car at the top of each hill.
Answer:
they will fly
Explanation:
yes flying is fun
The acceleration, net force, and normal force by the car at the top of hill A are 4.5 meter/second² , 3180 N and 3180 N.
The acceleration, net force, and normal force by the car at the top of hill B are 4.17 meter/second² , 3379N and 3379 N.
The acceleration, net force, and normal force by the car at the top of hill C are 4.0 meter/second² , 3480 N and 3480 N.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
On hill A;
The centripetal acceleration = v²/r = 6²/8 meter/second² = 4.5 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.5) N = 3180 N.
The normal force = 3180 N
On hill B;
The centripetal acceleration = v²/r = 5²/6 meter/second² = 4.17 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.17) N = 3379 N.
The normal force = 3379 N.
On hill A;
The centripetal acceleration = v²/r = 4²/4 meter/second² = 4.0 meter/second² .
The net force = m(g -a) = 600 (9.8 - 4.0) N = 3480 N.
The normal force = 3480 N.
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A student drops a ball from a window 5.0 m above the sidewalk. How fast is it moving when it hits the sidewalk?
The ball's velocity is 9.9 m/s fast when it hits the sidewalk.
What is velocity?Velocity is the rate of change of displacement.
To calculate how fast the ball was moving when it hits the sidewalk, we use the formula below.
Fromula:
V² = U²+2gS......... Equation 1Where:
V = Final velocityU = Initial velocityg = Acceleration due to gravityS = DistanceFrom the question,
Given:
U = 0 m/sg = 9.8 m/s²S = 5 mSubstitute these values into equation 1
V² = 0²+2×5×9.8V² = 98V = √98V = 9.9 m/sHence, the ball's velocity is 9.9 m/s fast when it hits the sidewalk.
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What is the acceleration of a softball with a mass 0.5kg that is thrown with a force of 25 N?
Answer:
50 m/s^2
Explanation:
F=ma
25 N= 0.5 kg • a
divide both sides by 0.5 kg
a=50 m/s^2
1.) A roller coaster travels on a frictionless track as shown in the illustration.
a.) If the speed of the car at Pt A is 5.0 m/s, what is the speed at Pt B
(More in the photo provided)
For the roller coaster on a frictionless track:
a. The speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.b. The height between Points A and B where kinetic energy equals potential energy is 5.0 m.c. For the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.d. For the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.How to solve speed and height?a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.
Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.
Answer: A. 5.0 m/s
b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.
At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:
Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A
At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."
Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B
Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.
Equating the mechanical energy at Point A to the mechanical energy at Point B:
Initial mechanical energy at Point A = Mechanical energy at Point B
Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B
Since the kinetic energy is the same at both points, simplify the equation:
Potential energy at Point A = Potential energy at Point B
The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.
Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:
mgh = mghA
Since the mass and acceleration due to gravity are the same, cancel them out:
h = hA
This means that the height where kinetic energy equals potential energy is the same as the height at Point A.
Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.
c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.
Potential energy at Point B = mghB
Potential energy at Point C = mghC
Given that the height at Point C is 8.0 m, compare the potential energies:
Potential energy at Point B ≥ Potential energy at Point C
mghB ≥ mghC
Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:
hB ≥ hC
Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.
d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.
Potential energy at Point A = mghA
Potential energy at Point C = mghC
Given that the height at Point A is 5.0 m, compare the potential energies:
Potential energy at Point A ≥ Potential energy at Point C
mghA ≥ mghC
Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:
hA ≥ hC
Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.
To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.
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The speed of light is the fastest in which medium
In vacuum, going at 2.99×10^8 m/s.
An object floats in water with 5/8 of its volume submerged. The ratio of the density of the obkect to that of water is:
(a) 8/5
(b) 1/2
(c) 3/8
(d) 5/8
(e) 2/1
An object floats in water with 5/8 of its volume submerged. The ratio of the density of the obkect to that of water is 5/8.
What is meant by density ?
The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition.Symbol for density: D or Formula for Density: Where is the density, m is the object's mass, and V is its volume, the equation is: = m/V.How much matter is confined within a volume is determined by density. For an identical size object, a dense object weighs more than a less dense one.A substance that is less dense than water will float on it; a substance that is denser will sink.Density equals mass per unit volume, or D = M / V, is the density equation.To learn more about density refer to
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A miniature quadcopter is located at
xi = −1.75 m
and
yi = 2.70 m
at
t = 0
and moves with an average velocity having components
vav, x = 1.70 m/s
and
vav, y = −2.50 m/s.
What are the x-coordinate and y-coordinate (in m) of the quadcopter's position at
t = 2.10 s?
A miniature quadcopter is located at xi = −1.75 m and yi = 2.70 m at t = 0, so the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.
What is the quadcopter's position?
The equation that is used here is the kinematic equations to find the position of the quadcopter at time t,
x = xi + vav, x × t
y = yi + vav, y × t
Substituting the given values, one can get:
x = -1.75 m + 1.70 m/s × 2.10 s = -0.185 m
y = 2.70 m - 2.50 m/s × 2.10 s = -3.175 m
Hence, the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.
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