Two people stand across from one another at the top edges of identical buildings, 50 meters above the ground. One person throws a rock straight upwards with an initial speed of 15 m/s, while the other person throws their rock straight downwards with an initial speed of 15 m/s. If both of the rocks miss the building and continue down to the street,
a. How long will it take for the rock thrown upwards to reach the ground?
b. How long will it take for the rock thrown downwards to reach the ground?
c. How fast will the upward thrown rock be travelling just before it hits the ground? The downward thrown rock?

Answers

Answer 1

Answer:

C

Explanation:

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Related Questions

What is curved space?

Answers

Curved space often refers to a spatial geometry which is not "flat", where a flat space is described by Euclidean geometry. Curved spaces can generally be described by Riemannian geometry though some simple cases can be described in other ways.

What is the charge of the particle on an aluminum rod with a 0.946 that you pass between the poles of a 0.41-T permanent magnet at a speed of 4.05 m/s at a 90o angle?

Answers

The charge of the particle on the aluminum rod is 9.26 x 10^-6 C.

When a charged particle moves through a magnetic field, it experiences a force known as the Lorentz force. The Lorentz force is given by the equation F = qvBsinθ, where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.

In this scenario, an aluminum rod with a mass of 0.946 g is passed between the poles of a 0.41-T permanent magnet at a speed of 4.05 m/s at a 90o angle. Since aluminum is a conductor, it is expected that electrons in the metal will be free to move, allowing for a current to flow through the rod.

We can calculate the charge of the particle by using the equation F = ma, where F is the Lorentz force, m is the mass of the particle, and a is the acceleration of the particle.

The acceleration of the aluminum rod can be calculated using the equation a = F/m. Since the rod is moving at a constant velocity, the force due to air resistance can be ignored. Therefore, the force acting on the rod is solely due to the Lorentz force. Thus, we can write: a = F/m = qvBsinθ/m, Solving for q, we get: q = ma/vBsinθ = (0.946 x 10^-3 kg x 4.05 m/s)/(0.41 T x sin90o) = 9.26 x 10^-6 C.

Therefore, the charge of the particle on the aluminum rod is 9.26 x 10^-6 C.

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The position-time equation for a certain train is
2.9m + (8.8m/s)t + (2.4m/s2)+2

What is it’s acceleration?

Answers

Answer:

\(a=4.8m/s^2\)

Explanation:

Hello,

In this case, since the acceleration in terms of position is defined as its second derivative:

\(a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)\)

The purpose here is derive x(t) twice as follows:

\(a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2\)

Thus, the acceleration turns out 4.8 meters per squared seconds.

Best regards.

1. What types of elements does an ionic bond occur between?

Answers

Answer:

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.

Explanation:

what units of measurement measures both velocity and speed

Answers

Answer:

\(metre \: per \: second\)

Explanation:

Velocity is a derived quantity and the S.I unit is metre per second.Speed is also a derived quantity which is has the S.I unit to be metre per second.

Does anybody know how to solve this? Thanks!!
The position x of a bowling ball rolling on a smooth floor as a function of time t is given by: x(t)=v0t+x0 , where v0=2.5m/s and x0=−5.0m . The polynomial relationship between position and time for the bowling ball is _______________.

exponential
inverse
linear
cubic
quadratic

Answers

The polynomial relationship between position and time for the bowling ball is linear.

What is a linear relationship between two variables?

A linear relationship between two variables is a term used to describe a straight-line relationship between the two variables.

Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b.

From the equation of linear relationship between two variable, the highest power of x is one.

The given equation for position and time;

x(t) = vot + xo

From this given equation, the highest power of t is one, hence it is called linear relationship.

Thus, the polynomial relationship between position and time for the bowling ball is linear.

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If a quarterback gets hit by a defensive lineman with a mass of 100 kg and accelerating at a rate of 1m/s2 at what force is the quarterback getting hit? ​

Answers

The quarterback is getting hit with a force of 100 Newtons.

How to calculate the force with which the quarterback is getting hit

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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Complete the following statement: Different types of collisions between interacting bodies
are categorized on the basis of
a. linear momentum conservation
b. mechanical energy conservation.
c. kinetic energy conservation.
d. the magnitude of the forces
involved

Answers

B. Mechanical energy conservation

a wall, a 55.6 kg painter is standing on a 3.15 m long homogeneous board that is resting on two saw horses. The board’s mass is 14.5 kg. The saw horse on the right is 1.00 m from the right. How far away can the painter walk from the saw horse on the right until the board begins to tip?

Answers

Answer:

0.15 m

Explanation:

First calculating the center of mass from the saw horse

\(\frac{3.15}{2} -1=0.575 m\)

from the free body diagram we can write

Taking moment about the saw horse

55.9×9.81×y=14.5×0.575×9.81

y= 0.15 m

So, the painter walk from the saw horse on the right until the board begins to tip is 0.15 m far.

a wall, a 55.6 kg painter is standing on a 3.15 m long homogeneous board that is resting on two saw horses.

Car wheel's slip in mud. why?

Answers

Answer:

Because its wet

Explanation:

the more you spin the car wheels the more slippery it gets

Suppose that the stone is launched with a speed of 3 m/s and travels 40 m before coming to rest. What is the approximate magnitude of the friction force on the stone?.

Answers

The relationship between velocity, acceleration, and displacement is given by v2 = vo2 + 2as, which is derived from Newton's law of motion. Where a, and s are the acceleration and displacement, and v and vo are the final and starting velocities, respectively. Using the second law of Newton,

The problem mentions the stone's initial speed as 3 m/s. Moreover, the stone will stop after 40m. This indicates that the displacement is 40m, and the final speed is 0 m/s. Calculations for rock acceleration are as follows:

(0 m/s)^2 = (3 m/s)^2 + 2a (40m).

9 m^2/s^2 = -2a(40m) (40m)

0.1 m/s2 is equal to a=-9m2/s2/80m.

This implies that the stone will slow down and come to a stop as a result.

F = 20 kg * -0.1 m/s2. To continue,

F = 2N = 20 kg * 0.1 m/s2. Thus, the frictional force is 2N in magnitude.

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A 25 kg sled is pulled across a horizontal surface by a 200 N force at a constant velocity. What is the coefficient of friction between the sled and the surface?

Answers

Answer:

0.82

Explanation:

constant velocity.means acceleration a = 0, so net force = 0

F - μmg = ma = 0

so μ = F/(mg) = 200/(25*9.8) = 0.82

feather is dropped from 13 m high after it has fallen 3 m what is its acceleration

Answers

Answer:

Explanation:

The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:

\(s(t)=-4.9t^2+13\) which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:

\(v(t)=-9.8t\). We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:

a(t) = -9.8

It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.

A wheel rolling on a horizontal surface with an angular speed of 2.5 rad/s gets on a ramp and rolls down the ramp with a constant angular acceleration of 2.0 rad/s2. If it takes 11.5 us to reach the bottom of the ramp, what is the final angular speed of the wheel at the bottom

Answers

Answer:

the final angular speed of the wheel at the bottom is 25.5 rad/s

Explanation:

The computation of the final angular speed of the wheel at the bottom is as follows:

As we know that

\(W_f = W_{in} + \alpha t\\\\= 2.5 + (2 \times 11.5)\\\\= 2.5 + 23\\\\= 25.5 rad/s\)

Hence, the final angular speed of the wheel at the bottom is 25.5 rad/s

We simply applied the above formula so that the final angular speed could come

When a 6.0-F capacitor is connected to a generator whose rms output is 25 V, the current in the circuit is observed to be 0.40 A. What is the frequency of the source?

Answers

The frequency of the source is  1.66 Hz.

What is the impedance?

Let us recall that the impedance of the circuit is the opposition that is offered to the flow of current by a circuit component that is not a resistor. Now let us find the impedance.

I = V/Z

I = current

V = voltage

Z = impedance

Z = V/I

Z = 25/0.4

Z = 62.5 ohm

Z^2 = R^2 + Xc^2

Z^2 =  Xc^2

Xc= Z

Xc = 2πfC

f = frequency

C = capacitance

f= Xc/2πC

f =  62.5/2 * 3.142 * 6

f = 1.66 Hz

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Do You think History is the most important subject that deserves first place? Do you see a way that learning history could assist you in your future career?

Answers

yes

Explanation:

history is an important class and it helps to you understand what went on in the past so that we can learn from our mistakes and help us grow

A
6. All other changeable factors that must
be kept the same to ensure a fair test
(what you keep the same).​

Answers

Answer:

a constant variable?

Explanation:

A constant variable is any aspect of an experiment that a researcher intentionally keeps unchanged throughout an experiment.

Experiments are always testing for measurable change, which is the dependent variable. You can also think of a dependent variable as the result obtained from an experiment. It is dependent on the change that occurs

Assess platos theory of the forms from Aristotle's standpoint. is he correct? Explain..it’s philosophy

Answers

Answer:

The task of philosophy, for Plato, is to discover through reason (“dialectic”) the nature of the Forms, the only true reality, and their interrelations, culminating in an understanding of the most fundamental Form, the Good or the One. Aristotle rejected Plato’s theory of Forms but not the notion of form itself. For Aristotle, forms do not exist independently of things—every form is the form of some thing. A …

Explanation:

Which statement is the best interpretation of the ray diagram shown below?
plz help

Which statement is the best interpretation of the ray diagram shown below?plz help

Answers

Answer:

Option B. A convex mirror forming a smaller, virtual image.

Explanation:

The diagram above illustrate the formation of image by a convex mirror.

The image formed by a convex mirror has the following characteristics:

1. The image is always formed behind the mirror.

2. The image is always virtual.

3. The image is always erect.

4. The image is always diminished i.e smaller than the object.

A careful observation of the diagram above shows that the mirror is a convex mirror as the outer surface is the reflecting part and the inside surface of the spherical part is silvered or polished.

Now, since the mirror is convex mirror, therefore, the image formed by the mirror will be smaller and virtual as explained above.

Answer:  A concave lens forms a smaller, virtual image

Explanation:

4.3.2 introduction to optics A P E X

a toy is tossed from the edge of a table. its path is shown; air resisitance is ignored. use the picture below to answer the following questions

Answers

As there is only one force acting on the ball i.e. gravitational force, the acceleration will be constant and downward. Also because ball moves in the direction of the acceleration, the velocity increases.

Acceleration - constant; velocity - increasing.

What is Acceleration?

Acceleration is the rate of change of velocity of an object over time. It can be positive, negative, or zero. Positive acceleration is when an object speeds up, negative acceleration is when an object slows down, and zero acceleration is when an object's velocity remains constant.

What is velocity?

Velocity is a measure of the speed and direction of an object's motion. It is typically measured in meters per second (m/s) or kilometers per hour (km/h). Velocity can also be expressed in other units, such as miles per hour (mph) or feet per second (ft/s). Velocity is related to a object's acceleration, as an object's acceleration is the rate of change in its velocity over time.

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Please explain thoroughly and show work if needed! Thank youuu :) -If the period of a pendulum decreases from 8 seconds to 2 seconds, how will that affect the frequency of the pendulum?

Answers

Answer:

Physics

Explanation:

The period of a pendulum is the time it takes for the pendulum to complete one full oscillation, or swing back and forth. The frequency of a pendulum, on the other hand, is the number of oscillations it completes in one second. The frequency is calculated by taking the reciprocal of the period, or 1/period.

If the period of a pendulum decreases from 8 seconds to 2 seconds, it means that the pendulum is swinging back and forth more quickly, as it is taking less time to complete one full oscillation. To find the new frequency of the pendulum, we can use the formula:

frequency = 1 / period

Initially, when the period was 8 seconds, the frequency was:

frequency = 1 / 8 = 0.125 Hz

After the period decreased to 2 seconds, the new frequency can be calculated as:

frequency = 1 / 2 = 0.5 Hz

So, the frequency of the pendulum increases from 0.125 Hz to 0.5 Hz when the period decreases from 8 seconds to 2 seconds. This means that the pendulum is oscillating at a faster rate, completing more oscillations in one second.

During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ± 0.001) kg with a speed of (3.2 ± 0.01) ms-1. The second trolley is moving away with a distance of (2.5 ± 0.01) ms-1.

What is the absolute uncertainty of the ratio of momentum of the two trolleys X/Y?

Answers

Answer:

P = 1 (14,045 ± 0.03 )  k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

            Δ (Pₓ / Py) =?

 Let's start by finding the momentum of each vehicle

car X

        Pₓ = m vₓ

        Pₓ = 2.34 2.5

        Pₓ = 5.85 kg m

car Y

        Py = 2,561 3.2

        Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

          ΔPₓ = m Δv + v Δm

          ΔPₓ = 2.34 0.01 + 2.561 0.01

          ΔPₓ = 0.05 kg m

         Δ\(P_{y}\) = m Δv + v Δm

         ΔP_{y} = 2,561 0.01+ 3.2 0.001

         ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

          P = Pₓ / \(P_{y}\)

          ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

          ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²

          ΔP = 0.006 + 0.0026

          ΔP = 0.009 kg m

The result is

           P = 14,045 ± 0.039 = (14,045 ± 0.03 )  k gm/s

Can someone please help me with this I will make you Brainly I need help on this

Can someone please help me with this I will make you Brainly I need help on this

Answers

Answer:

everything is in the file seriously..

Explanation:

Can someone please help me with this I will make you Brainly I need help on this

Which statement is true?
A)
All waves travel at the same speed through any medium.
B)
All waves travel at the same speed if no medium is present.
Electromagnetic waves require a medium, but mechanical waves do not.
D)
Mechanical waves require a medium, but electromagnetic waves do not

Answers

Answer:

B.

Explanation:

B)all waves travel at the same speed if no medium is present


Hope I helped :))


Which of the following sequences correctly lists the different in earthquake waves
magnitude from strongest to weakest (left to right)?
- Surface waves ... P waves .... S waves
- S waves ... P waves .... Surface waves
- P waves ... S waves .... Surface waves
- P waves ... Surface waves ... S waves

Answers

The sequence that correctly lists earthquake waves from strongest to weakest is : ( C ) P waves -- S waves-- Surface waves

Types of earthquake waves

P waves are the strongest waves because they move more rapidly inside the incompressible earth core sending its energy at a hazardous rate, while the S waves are slower and produces vertical movement of the earth surface.

The weakest waves are the S waves which sweeps across the outer surface of the earth and they are also the slowest of all the waves.

Hence we can conclude that the sequence that correctly lists earthquake waves from strongest to weakest is P waves -- S waves-- Surface waves

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Question 2
A photon of green light has a wavelength of 520 nm. Find the green photon's frequency in Hz?
Hints: C=fa ; this will give you the frequency in Hz; 1 nm = 1x10-⁹ nm

Question 2A photon of green light has a wavelength of 520 nm. Find the green photon's frequency in Hz?Hints:

Answers

5.77 ×\(10^1^4\) Hz is the green photon's frequency .

The distance between similar points (adjacent crests) in adjacent cycles of a waveform signal that is propagated in space is known as the wavelength. A wave's wavelength is often measured in meters (m), centimeters (cm), or millimeters (mm) (mm). The relationship between frequency and wavelength is inverse.

Given:

Wavelength of green light = 520 nm

f = c / λ

where, f = Frequency

            c = Speed of light = 3 × \(10^8\) m/s

            λ = Wavelength of light

∴ f = c / λ

  f = \(\frac{3*10^8}{520 * 10^-^9}\)

    = 5.77 ×\(10^1^4\) Hz

Therefore,  5.77 ×\(10^1^4\) Hz is the green photon's frequency .

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A car accelerates uniformly from rest and
reaches a speed of 28.7 m/s in 6 s. The
diameter of a tire is 58 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slipping.
Answer in units of rev

Answers

The number of revolutions the tire makes in 6 s is

N = (58π)/(12π) = 4.83 rev.

What is revolutions?

Revolutions min physics is the study of the physical aspects of revolutions, including the forces and motions that cause them, the structures and systems that are produced in their wake, and the physical processes that lead to their initiation and termination. It has roots in the study of revolutions in the social sciences, but has developed its own principles and techniques to study physical phenomena related to revolutions. These techniques include the use of mathematical models, experiments, numerical simulations, and computer visualizations.

The linear velocity of a point on the tire's circumference is given by

v = (dπ)/t

where d is the diameter of the tire and t is the time.

Substituting d = 58 cm and t = 6 s, the linear velocity of a point on the tire's circumference is

v = (58π)/6 m/s.

The number of revolutions the tire makes in 6 s is given by

N = (v/2π)

Substituting v = (58π)/6 m/s, the number of revolutions the tire makes in 6 s is

N = (58π)/(12π) = 4.83 rev.

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When is an example of a time a Christmas movie modeled acceleration on incline with friction (physics)?

Answers

An example of a time a Christmas movie modeled acceleration on incline with friction (physics) is:

One example of a Christmas movie that features characters moving up an incline with friction could be the film "Elf," in which the main character, Buddy, runs up a steep hill covered in snow in order to catch a runaway sleigh. In this scene, Buddy's acceleration up the hill is likely influenced by the friction between his feet and the snow-covered surface, as well as other factors such as his mass and the slope of the hill.

What is the case above about?

It is not uncommon for movies, including Christmas movies, to depict characters moving up or down inclines or hills. In such cases, the motion of the characters can be analyzed using the principles of physics, including acceleration and friction.

In continuation of the story above:

To model the acceleration of Buddy as he runs up the hill, we would need to consider the forces acting on him, including the force of gravity pulling him downward, the normal force of the ground pushing against him, and the friction force between his feet and the ground. We would also need to consider any external forces, such as the force of the wind, and take into account the effects of air resistance.

Therefore, By applying the laws of motion to these forces, we could calculate Buddy's acceleration as he runs up the hill.

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At a weightlifting competition two competitors list of the same way to the same height the second competitor accomplished to live two seconds faster than the first competitor this demonstrates that the second competitor had one more

Answers

one more what ? I’m confused ?

7.a railway truck A of a mass of 2000kg moves westwards with a velocity of 3m/s. It collides with a stationary truck B 1200kg, loaded with electronic equipment of mass 300kg. The two trucks combined after collision. Ignore the effects of friction. 7.1. Write down magnitude and direction of the 'reaction force' to the weight
of truck A.
(2)
7.2. Calculate the velocity of truck B after the collision.
(5)
7.3. Calculate the magnitude of the force that the truck A exert on truck B if
the collision lasts for 0,5 s.
(4)
8. The most common reasons for rear-end collisions are too shortfollowing a
distance, speeding and failing brakes. The sketch below represents one such​

Answers

Answer:

9. A 1500kg car traveling +6m/s with a 2000kg truck at rest. The vehicles collide, but do not stick together. The car has a velocity -3m/s after the collision. What is the velocity of the truck? a. What type of collision occurred above?

Answer yess it’s not

Explanation:

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