Answers
Answer:
The two masses are 3.39 Kg and 1.75 Kg
Explanation:
The gravitational force of attraction between two bodies is given by the formula;
F = Gm₁m₂/d²
where G is the gravitational force constant = 6.67 * 10⁻¹¹ Nm²Kg⁻²
m₁ = mass of first object; m₂ = mass of second object; d = distance of separation between the objects
Further calculations are provided in the attachment below
Related Questions
A car traveling at 31 m/s runs out of gas while traveling up a 7.0 ∘ slope. How far will it coast before starting to roll back down?
I tried using a=g in a kinematic equation but my homework hint said my "a" value is incorrect.
Answers
Hi there!
On an incline, the acceleration due to gravity is: (g = 9.81 m/s²)
a = gsinФ ≈ 1.196 m/s²
We can use the following kinematic equation to solve:
vf² = vi² + 2ad
Since the car will start to roll back when v = 0 m/s, we can write that vf = 0.
0 = vi² + 2ad
Plug in values:
0 = 31² + 2(-1.196)(d)
Rearrange for d:
31²/(2.392) = d
d = 401.756 m
The car will coast for 7885.49 meters before starting to roll back down.
The car is subject to two forces: the force of gravity, which is pulling it down the hill, and the force of friction, which is trying to slow it down. The force of friction is equal to the coefficient of friction between the tires and the road multiplied by the normal force, which is equal to the weight of the car.
The car will stop coasting when the force of gravity is equal to the force of friction. We can set up an equation to find the distance the car will coast before stopping:
d = (\(v^{2}\)) / (2 * μ * g * sin(θ))
where:
d is the distance the car will coast before stopping
v is the initial speed of the car
μ is the coefficient of friction between the tires and the road
g is the acceleration due to gravity
θ is the angle of the slope
Plugging in the values from the problem, we get:
d = \((31 m/s)^2\) / (2 * 0.01 * 9.8 m/\(s^{2}\) * sin(7.0°))
d = 7885.49 meters
Therefore, the car will coast for 7885.49 meters before starting to roll back down.
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Relationship between SI unit for area and other units of area
Answers
The SI unit for area is the square meter (m²). It is a fundamental unit of measurement in the International System of Units (SI). Here are some common units of area and their relationships to the square meter:
Square kilometer (km²): 1 km² is equal to 1,000,000 square meters (1 km² = 1,000,000 m²). It is used for large-scale measurements, such as land area or geographical regions.
Hectare (ha): 1 hectare is equal to 10,000 square meters (1 ha = 10,000 m²).
Square centimeter (cm²): 1 cm² is equal to 0.0001 square meters (1 cm² = 0.0001 m²).
Square millimeter (mm²): 1 mm² is equal to 0.000001 square meters (1 mm² = 0.000001 m²).
Acre: 1 acre is equal to approximately 4046.86 square meters.
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At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm.
Calculate the pressure of the gas when it is heated to 900 K.
Answers
The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.
What is the pressure of the gas when it is heated to 900 Kelvin?Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.
It is expressed as;
P₁/T₁ = P₂/T₂
From the data:
Initial pressure P₁ = 3 atmInitial temperature T₁ = 300 KFinal pressure P₂ = ?Initial temperature T₂ = 900 KWe substitute our values into the expression above and solve for final pressure.
P₁/T₁ = P₂/T₂
P₁T₂ = P₂T₁
P₂ = P₁T₂ / T₁
P₂ = ( 3 atm × 900 K ) / 300 K
P₂ = 9.0 atm
Therefore, the final pressure is 9.0 atm.
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What happens after we die on earth?
Answers
Your heart stops beating, your breathing stops, and your brain stops working. According to research, brain activity may continue for several minutes after a person is declared dead.
What do people see when they die?Visual or auditory hallucinations are common during the dying process. The reappearance of deceased family members or loved ones is common. These visions are thought to be normal.
The dying may shift their focus to "another world," where they may converse with people or see things that others do not.
Thus, brain activity is not synonymous with consciousness or awareness. It does not imply that the individual is aware that they have died.
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
Answers
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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. Which of the following is the last part of the technological design process? test and evaluate a solution research existing solutions refine the original solution design decide on a solution
Answers
According to the research, the correct option is to refine the original solution design. It is the last part of the technological design process.
What is the technological design process?It is the process and problem solving using design as a methodological strategy that allows identifying and solving a problem through inductive procedures and logical reasoning.
In this sense, the last part of this process includes what refers to the production of a first model of the solution, which is tested to evaluate its performance, the result of this evaluation must influence the modification or refinement of the original solution design that is implemented in the solution of the problem that gave rise to the generation of the project.
Therefore, we can conclude that according to the research, the correct option is to refine the original solution design. It is the last part of the technological design process.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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3. Is it possible for a scientific theory to become a law? Why or why not?
Answers
A theory does not change into a scientific law with the accumulation of new or better evidence. A theory will always remain a theory; a law will always remain a law. Both theories and laws could potentially be falsified by countervailing evidence. Theories and laws are also distinct from hypotheses.
Suppose that the separation between two speakers A and B is 4.80 m and the speakers are vibrating in-phase. They are playing identical 134-Hz tones and the speed of sound is 343 m/s. An observer is seated at a position directly facing speaker B in such a way that his line of sight extending to B is perpendicular to the imaginary line between A and B. What is the largest possible distance between speaker B and the observer, such that he observes destructive interference
Answers
Answer:
\(X=8.44m\)
Explanation:
From the question we are told that
Distance b/w A&B \(x=4.80m\)
Frequency \(f=134Hz\)
Sound speed \(v=343m/s\)
Generally the equation for wavelength is mathematically given as
\(\lambda=v/f\)
\(\lambda/2=1/2*v/f\)
\(\lambda/2=1/2*\frac{343}{135}\)
\(\lambda/2=1.27037037\)
Generally the destructive interference X is mathematically given by
\(\sqrt{4.8^2 +X^2} -X=1.27037037\\\)
\(23.04+BC^2=X^2+1.613+2.54*X\)
Therefore the destructive interference is
\(X=8.44m\)
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
Answers
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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Assuming that all the numbers given are exact, what is John's position at a time of 4.53 s? Enter your answer to at least three significant digits.
Answers
The position of John at a time of 4.53 s is 20.8 m.
It is essential to know that the formula for position, velocity, and acceleration is given as:
\($$x=x_0+v_0t+\frac{1}{2}at^2$$\)
\($$v=v_0+at$$\)
\($$v^2=v_0^2+2a(x-x_0)$$\)
Here, x is the position, v is the velocity, t is the time elapsed, and a is the acceleration. John's position at a time of 4.53 s is given as follows:
Given,
\($$x_0=0, v_0=4.6 m/s, t=4.53s, a=-9.8m/s^2$$\)
From the above formula, we can calculate the position of John at a time of 4.53 s.Substitute all the values in the formula for position, and we get,
\($$x=x_0+v_0t+\frac{1}{2}at^2$$\)
\($$x=0+(4.6)(4.53)+\frac{1}{2}(-9.8)(4.53)^2$$\)
\($$x=20.8 m$$\)
Therefore, the position of John at a time of 4.53 s is 20.8 m.
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when a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g÷2 (gravity over 2) show that : density of metal =2density of liquid
Answers
The density of the metal sphere is 2 times the density of the liquid as proved.
Net upward force acting on the metal sphereThe net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;
F = σVg - ρVg
ma = σVg - ρVg
where;
ρ is density of the liquidσ is the density of the metala is acceleration of the metalσV(a) = σVg - ρVg
σ(a) = σg - ρg
σ(g/2) = σg - ρg
g(σ/2) = g(σ - ρ)
σ/2 = σ - ρ
σ/2 - σ = - ρ
-σ/2 = - ρ
σ = 2ρ
Thus, the density of the metal sphere is 2 times the density of the liquid as proved.
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To better understand crash dynamics we have to look at "__________."
A. the law of gravity
B. Bernoulli's principle
C. the laws of motion
D. Archimedes' principle
Answers
To better understand crash dynamics we have to look at "the laws of motion."
The laws of motion
The laws of motion were introduced by Sir Isaac Newton in 1687 in his book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), which defined the laws of motion, or three fundamental laws that govern the movement of bodies. The laws of motion, according to Newton, govern the motion of an object or a system of objects that interact.
It defines the concepts of force and mass, and the fundamental dynamics of motion.The following are the laws of motion:Every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. The velocity of an object changes proportional to the force applied to it, and the acceleration of an object is proportional to both its force and its mass. For every action, there is an equal and opposite reaction.
Therefore, these laws are necessary to fully grasp crash dynamics because they explain how objects respond to outside forces that cause them to accelerate or decelerate.
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An object is attached to a spring scale, which reads 2 N. If the same object were attached to two identical spring scales placed sideby side, what would be the readings on each spring scale?
Answers
The readings of the scales will have to add 2N. This comes from the fact that each scale is supporting a part of the weight of the object. Now, if the center of gravity is midway between the two scales the readings will be the same on each spring scale; assuming this is the case the reading on each scale is 1N.
Can positive charges be liberated by the photoelectric effect?
yes
rarely
no
sometimes
Answers
Answer:
No, positive charges cannot be liberated by the photoelectric effect.
Explanation:
Question 6 of 10
How would you change the distance between two charged particles to
increase the electric force between them by a factor of 16?
A. Reduce the distance by a factor of 4.
B. Increase the distance by a factor of 4.
C. Reduce the distance by a factor of 16.
D. Increase the distance by a factor of 16.
SUBMIT
Answers
Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.
Thus, When charged things interact with other objects, there is an electric force present in the system.
The electric force between them is appealing because positive charges are attracted to negative charges. For two positive charges or two negative charges, the electric force is repellent.
A typical illustration of this is what happens when two balloons are rubbed on a blanket. When you rub the balloons against the blanket, electrons from the blanket transfer to the balloons, leaving the blanket positively charged and the balloons negatively charged.
Thus, Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.
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The constant 40-N force is applied to the 36-kg stepped cylinder as shown. The centroidal radius of gyration of the cylinder is k = 200 mm, and it rolls on the incline without slipping. If the cylinder is at rest when the force is first ap- plied, determine its angular velocity weight seconds later.
Answers
The angular velocity of the stepped cylinder is determined as 2.35 rad/s.
Centripetal acceleration of the cylinder
The centripetal acceleration of the cylinder is calculated as follows;
F = ma
a = F/m
a = 40/ 36
a = 1.11 m/s²
Velocity of the cylindera = v²/r
v² = ar
v² = 1.11 x 0.2
v² = 0.222
v = 0.47 m/s
Angular velocity of the cylinderv = ωr
ω = v/r
ω = 0.47/0.2
ω = 2.35 rad/s
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A lounging leopard decides to come down out of her tree and hunt for her lunch in the savanna. The graph above represents the motion of the leopard as a function of time.
What is the distance traveled by the leopard during the entire 11 seconds? Please include a number and uni
Answers
Theory or Law: based on more than just a guess; supported by large amounts of evidence.
A. Law
B.Theory
Answers
Answer:
A Law must hold within its realm of jurisdiction.
Example: Newton's Laws of Motion are always found to be true at non-relativistic speeds.
At speeds where relativity becomes important Newtons Laws (in particular
F = M a) are not necessarily true - but, the relativistic equations must agree with Newton's Laws at non-relativistic speeds.
A large amount of evidence is necessary to support a Law but in itself is not necessarily true.
Quantum Mechanics has been found to agree with results, but there are different theories as to why this is true - even Einstein did not like Quantum Mechanics as formulated because it deals in probabilities
. Acceleration is the rate at which/what hap-
pens?
Answers
Joe rides south on his bicycle in a straight line for 16 min with an average speed of 11.6 km/h , how far has he ridden? Answer in units of km.
Answers
Explanation:
Distance = speed × time
d = (11.6 km/h) (16 min × 1 hr / 60 min)
d = 3.09 km
Answer: distance = 3.09 km
Explanation: Distance = speed × time
distance = (11.6 km/h) (16 min × 1 hr / 60 min)
distance = 3.09 km
HOPE THIS HELPS YOU..
PLS MARK ME IN BRAINLIESTI need help pls !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
figure d
Explanation:
A girl of mass m1=60.0 kilograms springs from a trampoline with an initial upward velocity of vi=8.00 meters per second. At height h=2.00 meters above the trampoline, the girl grabs a box of mass m2=15.0 kilograms. (Figure 1)
For this problem, use g=9.80 meters per second per second for the magnitude of the acceleration due to gravity.
What is the speed vbefore of the girl immediately before she grabs the box?
Express your answer numerically in meters per second.
What is the speed vafter of the girl immediately after she grabs the box?
Express your answer numerically in meters per second.
What is the maximum height hmax that the girl (with box) reaches? Measure hmax with respect to the top of the trampoline.
Answers
The conservation of momentum and energy allows to shorten the results for the movement of the girl on the trampoline holding the box are:
a) the girl's speed is v = 4.98 m / s
b) The speed of the girl + box system is: v_f = 0.996 m / s
c) the maximum height is: y = 2.05 m
Kinematics studies the movement of bodies, looking for relationships between the position, velocity and acceleration of bodies.
The momentum is defined by the product of mass and the velocity, when a system is isolated the momentum is conserved.
The mechanical energy is the sum of the kinetic energy plus the potential energies, when there is no friction in the system the mechanical energy is conserved.
Let's solve this exercise in parts:
a) Let's use kinematics to find the speed of the girl before she grabs the box
v² = v₀² - 2 g y₁
v² = 8² - 2 9.8 2.00
v = R 24.8 = 4.98 m / s
b) Let's use momentum conservation for when the speed of the girl and the box together. Let's write the moment in two moments.
Initial instant. Just before you grab the box.
p₀ = M v + 0
Final moment. Right after taking the box
\(p_f\) = (m + M) \(v_f\)
In system this form by the girl and the box therefore it is an isolated system and the momentum is conserved.
\(p_o = p_f\)
mv = (m + M) \(v_f\)
\(v_f = \frac{m}{m+M} \ v\)
Let's calculate
\(v_f = \frac{15}{15+ 60} \ 4.98\)
\(v_f\) = 0.996 m / s
c) Now we use conservation of energy after the girl has the box.
Starting point. When the girl has the box
Em₀ = K + U
Em₀ = ½ (m + M) v² + (m + M) g y₁
Final point. At the highest point of the trajectory
\(Em_f\) = U
\(Em_f\) = (m + M) g y₁
As there is no friction, the energy is conserved.
\(Em_o = Em_f\)
½ (m + M) v² + (m + M) g y₁ = (m + M) g y
y = \(\frac{v^2}{2g} + y_1\)
Let's calculate
y = \(\frac{0.996^2}{2 \ 9.8} + 2.0\)
y = 2.05 m
In conclusion using the conservation of momentum and energy we can shorten the results for the movement of the girl on the trampoline holding the box are:
a) the girl's speed is v = 4.98 m / s
b) The speed of the girl + box system is: v_f = 0.996 m / s
c) the maximum height is: y = 2.05 m
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Answer:
Vbefore = 4.98 m/s
Vafter = 3.98 m/s
Hmax = 2.81 m
how would you write 4.3756 in standard decimal form
Answers
5.64x 10^8
HELP ASAP PLZ
What is the most likely reason for using the following model? A diagram that shows the different layers inside the sun Image © 2010 NASA The object is too small. The object represents a set of data. The object cannot be directly observed. The object represents a prediction about the future.
Answers
Answer:
Option C, The object cannot be directly observed.
Explanation:The temperature of sun is extremely high due to which it is almost impossible to land on its surface and explore the depth of it. Thus a prototype of it is required to predict its probable internal structure and associated feature which effect our planet "earth".
This prototype/model is based on the deduction arrived after analyzing the satellite information available in the form of high resolution images.
Hence, option C is correct
Answer:
The answer is c the object cannot be directly observed.
Explanation:
I took the test and got it right.
Pls help physics homework
True or False:
- Gravity depends on the material of the objects.
- Gravity is not a force because it cant move objects
- Gravity is a force because a force is a push or a pull
- The moon has less gravity than the earth because it has less mass than the earth
- The moon has less gravity than the earth because it has no atmosphere
Answers
False
False
False
True
How do I find the mass in kg
Answers
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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Strontium has neutrons
Answers
Answer:
strontium has 50 neutrons
Answer:
the answer is 50 hope it helps =)
Explanation:
A block of mass, m=4.80 kg is placed on the edge of a rough surface of height h = 0.5 2m as shown above. The block is released and moves until it stops momentarily after compressing a horizontal spring (with a spring constant k = 2,000 N/m) by a compression distance x = 12.1 cm. Find the work done by friction.
Answers
This question can be easily solved by using the law of conservation of energy.
The work done by the friction is "9.9 J".
The law of conservation of energy applied to this condition gives the following equation:
\(Potential\ Energy\ Lost\ by\ Block = Energy\ Stored\ by\ Spring\ +\ Work\ done\ by\ friction\\\\mgh = \frac{1}{2}kx^2\ +\ W\)where,
W = Work done by friction = ?
m = mass of the block = 4.8 kg
g = acceleration due to gravity = 9.81 m/s²
h = height = 0.52 m
k = spring constant = 2000 N/m
x = compression distance = 12.1 cm = 0.121 m
Therefore,
\((4.8\ kg)(9.81\ m/s^2)(0.52\ m)=\frac{1}{2}(2000\ N/m)(0.121\ m)^2+W\\W = 24.5\ J - 14.6\ J\)
W = 9.9 J
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The attached picture explains the law of conservation of energy.
A box full of charged plastic balls sits on a table. The electric force exerted on a ball near one upper corner of the box has components 1.2 x 10^-3 N directed north, 5.7 x 10^-4 N directed east and 2.2 x 10^-4 N directed vertically upward. The charge on this ball is 110 nC.
If this ball were replaced with one that has a charge of -50nC , what would be the force components exerted one the replacement ball?
F north=?
F east=?
F up=?
Answers
We have that the values for F north, F east, F up are
\(F_N=1.09090909*10^{-5}\)\(F_E=5.18181818*10^{-6}\)\(F_E=2*10^{-6}\)
From the Question we are told that
electric force \(F_1 = 1.2 x 10^{-3} N(N)\)
electric force , \(F_2=5.7 x 10^{-4} N(E)\)
electric force , \(F_3=2.2 x 10^{-4} N (U)\)
charge on this ball one \(q_1= 110 nC.\)
charge on this ball two \(q_2= -50 nC.\)
Generally the equation for the F north is mathematically given as
\(F_N=\frac{F_1}{q_1}\\\\F_N=\frac{ 1.2 * 10^{-3} )}{110}\)
\(F_N=1.09090909*10^{-5}\)
For F East
\(F_E=\frac{F_2}{q_1}\\\\F_E=\frac{5.7 x 10^-4 }{110}\)
\(F_E=5.18181818*10^{-6}\)
For F UP
\(F_U=\frac{F_3}{q_1}\\\\F_U=\frac{2.2 x 10^-4 }{110}\)
\(F_E=2*10^{-6}\)
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