two long parallel wires, each of radius , whose centers are a distance apart carry equal currents in opposite directions. what is the self-inductance of a length of such a pair of wires? you may neglect the flux within the wires themselves.

Answer:

2000

Explanation:

ddoes rest : add the components

This is a uniform rectilinear motion (MRU) exercise.

We get the data:

d = ?, v = 55 km/h, t = 2 hr

To calculate the distance, multiply the speed by the time.

d = v * t

The distance traveled is 110 km.

Distance = 10 miles

Displacement = zero

The coach must be fired and disciplined.

The merry-go-round takes approximately 29.41 seconds to complete 2.00 rotations.

Given data:

Acceleration (α) = 0.135 rad/\(s^2\)

Number of rotations (θ) = 2.00

To find the time taken (t) for 2.00 rotations, we need to use the formula:

θ = 0.5 * α * \(t^2\)

Rearranging the formula, we get:

\(t^2\) = (2 * θ) / α

Plugging in the given values, we have:

\(t^2\) = (2 * 2.00) / 0.135

\(t^2\) = 29.63

Taking the square root of both sides, we find:

t ≈ √29.63

t ≈ 5.439

Therefore, the time taken for the merry-go-round to complete 2.00 rotations is approximately 5.439 seconds.

Note: It's important to round the final answer to an appropriate number of significant figures, considering the given data. In this case, we have used four significant figures in the final answer.

However, if we want to adhere to the given significant figures in the acceleration (0.135 rad/\(s^2\)), the answer should be rounded to three significant figures. In that case, the final answer would be approximately 5.44 seconds.

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Answer/Explanation:

The magnetic fields line are closer apart at other places. Hence, magnetic field is strongest at the poles. Magnetic Field has Direction The Magnetic Field lines are like closed curves They emerge from North Pole and Merge to South Pole.

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a) The magnitude of elevator's acceleration is  0.93 m/s^2. b) Tthe direction of the elevator's acceleration is also upward.

To find the magnitude of the elevator's acceleration, we need to use the formula,

apparent weight = actual weight - ma

where m is the mass of the person and a is the acceleration of the elevator.

We can rewrite this formula as,

a = (actual weight - apparent weight) / m

Substituting the given values,

a = (535 N - 470 N) / m,

a = (65 N) / m

The magnitude of the elevator's acceleration is 65 N divided by the mass of the person. If the person's mass is, say, 70 kg, then the acceleration would be,

a = (65 N) / (70 kg) ≈ 0.93 m/s^2

When the elevator is at rest or moving with constant velocity, the forces are balanced, and the person experiences their actual weight. The direction of the net force on the person is therefore upward, which means the direction of the elevator's acceleration is also upward. If the elevator were accelerating downward, the net force on the person would be downward, and their apparent weight would be greater than their actual weight.

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A main sequence star is defined as a star that is in the phase of its life in which it is fusing hydrogen into helium in its core.

In a main sequence car, a balance between the inward pull of gravity and the outward pressure from the core, which is produced by the heat generated by nuclear fusion.

Main sequence stars are the most common type of star in the universe, and they come in a range of sizes and temperatures. Smaller main sequence stars, such as red dwarfs, are cooler and have lower luminosities, while larger stars, such as blue giants, are hot and have high luminosities.

The position of a main sequence star on the Hertzsprung-Russell diagram, which plots luminosity versus temperature, is determined by its mass and stage in its life cycle. Main sequence stars are said to be on the "main sequence" because they follow a well-defined relationship between luminosity and temperature on this diagram.

As main sequence stars age, they consume their hydrogen fuel, and the core begins to contract and heat up. This leads to changes in the star's structure, and eventually, the star may evolve into a red giant or another type of star. The lifespan of a main sequence star is determined by its mass, with larger stars having shorter lifetimes than smaller stars.

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Answer:

Yes

Explanation:

The most common energy that is lost in electronic devices is in the form of heat energy.

Error is the difference between actual value and the calculated value.

Uncertanity of a measured value in an interval around that value such that any repetition of measurement will produce a new result that lies within the interval.

Hence, error and uncertanity are interchangeable words that describes the same concept.

Answer:

x = A sin w t         for SHM where w = angular frequency

sin w t = x / A = .12 / .15 = .8    where w t is the angle in degrees

w t = 53.1 deg       (w itself is in rad / sec)

since v = A w cos w t  

then v / x = w cos w t / sin w t = w / tan w t

w = v / x * tan 53.1 = 1.7 / .12 * tan 53.1 = 18.9 /sec

Also for SHM    w = (k / m)^1/2

m = k / w^2 = 75 / 18.9^2 = .21 kg

Given:

• Height = 40 m

• Mass of ball 1 = 5 kg

• Mass of ball 2 = 10 kg

• Mass of ball 3 = 15 kg

Given that the three balls have equal volumes and are dropped from rest, let's answer the following questions:

• (a). Describe and explain the order in which the balls impact the ground at a time t.

To

Answer:

200 m / min

Explanation:

Total distance = 2000 m

Total time = 2+4+1+3 = 10 minutes

Average speed = 2000 m / 10 min = 200 m/min

Answer:

Power is 4373.25 W

Explanation:

We have,

The lift raises a car of mass 850 kg to a height of 2.1 m. It uses a force of 8330 N and takes 4 seconds to raise the car. It is required to find the power of the lift. Power is equal to the rate at which the work is done. So,

\(P=\dfrac{Fd}{t}\\\\P=\dfrac{8330\times 2.1}{4}\\\\P=4373.25\ W\)

So, the power of the lift is 4373.25 W.

Explanation:

This is the correct answer...

I hope you understand...

Answer:

67.56kg

Explanation:

Fapp+mg = ma

Fapp= applied force

mg = reactional force

g = acceleration due to gravity

Where g = 9.8m/s^2 a= 5 m/s2, Fapp= 1000N.

1000N = ma + mg

1000N = m( a+g )

1000N = m ( 5+9.8)

1000N = m×14.8

m = 1000÷14.8

m = 67.56kg.

Hence the mass of the wagon will be 67.56kg

The time it will take her to land on the other side is 0.5 seconds.

In a triangle with three angles of 30°, 60°, and 90°, the hypotenuse is twice as long as the shorter leg and three times as long as the latter. To understand why this is the case, consider that the triangle is a right triangle given these numbers according to the Converse of the Pythagorean Theorem. The lengths of the three sides in a triangle of this kind are referred to as a Pythagorean triple.

distance = velocity x time

In this case, the distance is 3 meters and the velocity is 6 m/s, so:

3 = 6 x time

Solving for time, we get:

time = 3/6 = 0.5 seconds

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Answer:

mass times grav

Explanation:

The density of the gold cylinder is approximately \(115.8 g/cm^3.\)

To calculate the density of the gold cylinder, we need to find its volume first.

Given:
Height (h) = 6 cm
Radius (r) = 2 cm

Using the formula for the volume of a cylinder \((V = πr^2h)\), we can substitute the values and calculate the volume:

\(V = π(2 cm)^2 * 6 cm\)
\(V = 4π cm^3\)

Now, we can calculate the density using the formula:

Density (D) = Mass (M) / Volume (V)

Given:
Mass (M) = 1455 g

\(Density (D) = 1455 g / 4π cm^3\)

Using the value of π as approximately 3.14, we can calculate the density:

\(Density (D) = 1455 g / (4 * 3.14) cm^3\)
Density \((D) ≈ 115.8 g/cm^3\)(rounded to 1 decimal place)

Therefore, the density of the gold cylinder is approximately \(115.8 g/cm^3.\)

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Answer:

\(a=0.96\ m/s^2\)

Explanation:

Given that,

Mass of cabinet, m = 45 kg

Two horizontal force of 25 newtons and 18 newtons respectively in the same direction.

When the forces are acting in same direction, the net force is equal to the sum of forces i.e.

F = 25 N + 18 N = 43 N

Let a is the aceleration of the cabinet

So,

F = ma

\(a=\dfrac{F}{m}\\\\a=\dfrac{43}{45}\\\\a=0.96\ m/s^2\)

So, the acceleration of the cabinet is \(0.96\ m/s^2\).

He need to know in order to calculate the velocity of the waves is time.

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.

Given in the question,

Velocity =Distance /Time

He need to know in order to calculate the velocity of the waves is time.

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The phasor transform of v(t) is V = 50 * e^(-j0.7854), where j represents the imaginary unit.

To find the phasor transform of the sinusoidal voltage source v(t) = 50cos(2000t - 45°) mV, we need to convert it into phasor notation.

The phasor transform represents a sinusoidal function as a complex number, where the magnitude represents the amplitude and the phase angle represents the phase shift.

Let's denote the phasor transform of v(t) as V. The magnitude of V will be equal to the amplitude of the sinusoidal function, and the phase angle of V will be equal to the phase shift of the sinusoidal function.

Given:

Amplitude (magnitude) of v(t) = 50 mV

Phase shift = -45°

The phasor transform of v(t) can be expressed as:

V = A * e^(jθ)

Where A is the amplitude and θ is the phase angle.

Let's calculate the phasor transform:

Amplitude (magnitude) of V = 50 mV

Phase angle of V = -45°

Converting the phase angle to radians:

θ_radians = (-45°) * (π/180) = -0.7854 radians

Expressing V in phasor notation:

V = 50 * e^(j*(-0.7854))

Therefore, the phasor transform of v(t) is V = 50 * e^(-j0.7854), where j represents the imaginary unit.

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Answer:

Answer:

cell membrane ) is the covering that surrounds both plant and animal cells

Deposition is when a gaseous state changes to solid state by escaping liquid state. So I think it is 3. Liquid glass cools and hardens

Answer:

  96 m

Explanation:

The average velocity over those 4 seconds is the velocity after 2 seconds:

  30 m/s -(2 s)(3.0 m/s^2) = 24 m/s

The displacement is the product of this average velocity and the duration of the acceleration:

  d = (24 m/s)(4 s) = 96 m

The boat covered 96 m while being accelerated.

Answer:

12.18

Explanation:

The maximum height that the orange will reach is 12.18 m.

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion.

You throw an orange out a window at a height of 12.00 meters upwards at an angle of 32° to the horizontal at a velocity of 3.5 m/s.

If u is the initial speed, the maximum height of the ball from the point of throwing is

H = u² sin²θ / 2g

Put the values, we get

H = 3.5² sin²32° / (2x9.81)

H = 0.1753 m

So, the maximum height calculated from the ground is

12 + 0.18 = 12.18 m

Thus ,the maximum height that the orange will reach is 12.18 m.

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Approximately 1377.46 N of force is required on the input piston to lift the car weighing 1.80 × \(10^{4}\) N.

The force required on the input piston of the hydraulic jack can be calculated using the principle of Pascal's law, which states that the pressure exerted in a fluid is transmitted equally in all directions.

The ratio of the output force to the input force is equal to the ratio of the output piston area to the input piston area:

Force (output) ÷ Force (input) = Area (output) ÷ Area (input)

We can rearrange this equation to solve for the input force:

Force (input) = Force (output) × (Area (input) ÷ Area (output))

Given that the weight of the car is 1.80 × \(10^{4}\) N, the output force is 1.80 × \(10^{4}\) N. The input piston area is 0.0540 \(m^{2}\), and the output piston area is 0.710 \(m^{2}\).

Plugging these values into the equation, we have:

Force (input) = (1.80 × \(10^{4}\) N) × (0.0540 \(m^{2}\) ÷ 0.710 \(m^{2}\))

Simplifying the expression gives us:

Force (input) ≈ 1377.46 N

Therefore, approximately 1377.46 N of force is required on the input piston to lift the car weighing 1.80 × \(10^{4}\) N.

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The negative angular acceleration required to bring the wheel to rest is approximately -0.126 rad/s^2, and the time needed to bring the wheel to rest is approximately 20.04 seconds.

Let's first find the initial and final angular velocities of the wheel.

The initial angular velocity is zero because the wheel is initially at rest.

The final angular velocity can be found using the formula:

ωf = ωi + αt

where

ωf = final angular velocity

ωi = initial angular velocity (which is zero)

α = angular acceleration (5.0 rad/s^2)

t = time (8.0 s)

ωf = 0 + (5.0 rad/s^2)(8.0 s) = 40.0 rad/s

The negative angular acceleration can be found using the formula:

Δω = ωf - ωi = αt

where

Δω = change in angular velocity (which is equal to the final angular velocity because the initial angular velocity is zero)

α = angular acceleration (which is negative because the wheel is slowing down)

t = time

So we have:

Δω = 40.0 rad/s

αt = -α(10 rev)(2π rad/rev)/t

where we have converted 10 revolutions to radians (2π radians per revolution).

Setting these two expressions equal to each other and solving for α, we get:

α = -Δω/t = -(40.0 rad/s)/(10 rev x 2π rad/rev x t)

α = -2.53/t rad/s^2

Finally, we can use the formula for angular deceleration to find the time needed to bring the wheel to rest:

ωf^2 = ωi^2 + 2αΔθ

where

Δθ = angle through which the wheel rotates during the deceleration (which is 10 revolutions)

ωf = final angular velocity (which is zero)

ωi = initial angular velocity (which is 40.0 rad/s)

α = angular acceleration (which is negative)

So we have:

0 = (40.0 rad/s)^2 + 2(-2.53/t)(10 rev x 2π rad/rev)

0 = 1600 - 318.48/t

t = 20.04 s

Therefore, the negative angular acceleration required to bring the wheel to rest is approximately -0.126 rad/s^2, and the time needed to bring the wheel to rest is approximately 20.04 seconds.

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Answer: 2

Explanation: