True or False: bulk deformation of magnesium is only possible at hot-working temperatures somewhat above the melting point

Answer:

0.77 M

Explanation:

Molarity is the concentration of a solution per liter

C= concentration

n= number of moles

V= volume of solution

The formula we will use is C= n/V

C= n/V

C= (1.93 mol NaCl)/(2.5 L of solution)

C= 0.772 mol/L

Since this concentration is given in moles per liters of a solution, this concentration is also the molarity.

C= 0.772 mol/L

*Include two significant digits in final answer*

M= 0.77 M

Answer:

0.856

Explanation:

Given data:

Feed molar rate ( Fao ) = 10 mol/min

Feed concentration ( Cao ) = 0.4 mol/dm^3

current conversion rate = 80%  

Temperature = 305 K

catalyst = 100 kg

entering pressure = 20 atm

exit pressure = 2 atm

Determine the conversion if the catalyst particle size were doubled and everything else remained the same

The conversion if the catalyst particle size were doubled and other factors remains the same = 0.856

attached below is a detailed solution

Answer:

I think it's raising an objective higher to increase it....I don't really know but here's an explanation I researched on.

Explanation:

To increase the gravitational potential energy of an object, the object show be raised higher. The higher the object, the higher gravitational potential energy.

Answer:

it is outside the nucleus  F

it has a positive charge  T

it has no mass  F

it has a negative charge  F

it is inside the nucleus  ...it is part OF the nucleus.

it is the same as the atomic number  T

it is the same as the number of neutrons  F

75% of the isotopes have a mass ima just guess cuz i dunno about this one...i think it matters on the atom element.

Explanation:

Answer:

56.11 g/mol

Explanation:

Answer:

56.105 g/mol

Explanation:

KOH is Potassium Hydroxide, a strong base commonly used in various industrial and laboratory applications.

The molar mass of KOH can be calculated by adding the atomic masses of its elements:

Potassium (K) - 39.098 g/mol

Oxygen (O) - 15.999 g/mol

Hydrogen (H) - 1.008 g/mol

So, the molar mass of KOH is:

39.098 g/mol + 15.999 g/mol + 1.008 g/mol = 56.105 g/mol


ALLEN

Sulphur (S) is the species that has the greatest rate of appearance in the given reaction.

2 H₂S + O₂ → 2 S + 2 H₂O

Sulphur (S) is the species that has the greatest rate of appearance in the given reaction . This can be determined by analysing the reaction's stoichiometry. Two molecules of sulphur (S) are created for each O2 molecule that interacts. The reactant species, H₂S and O₂, on the other hand, have coefficients of 2 and 1, respectively.

Therefore, the rate at which sulfur (S) appears is twice the rate of appearance of any other species in the reaction.

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Answer:

increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object would make the oppositely charged objects attract each other more.

Answer: 3.32060434 × 10^-23

Explanation: Divide the number of atoms (20) by 6.023 x 10^23 (Avogadro’s number) to get the number of moles.

The bond order of BF₄⁻ is 1 and the bond order of BF₃ is 1.33

So, BF₃ is having more bond order than BF₄⁻.

In other words, BF₃ > BF₄⁻ ( You can write Bond Order or in B.O it's the abbreviation of Bond Order ).

\longrightarrow{\green{F=5000N}}

Rough ER is connected to the nuclear membrane and is responsible for the synthesis and processing of proteins.

The rough endoplasmic reticulum (ER) is a network of membrane-bound sacs and tubules that is studded with ribosomes on its surface. These ribosomes are responsible for protein synthesis. The rough ER is connected to the nuclear membrane because it receives instructions for protein synthesis from the DNA in the nucleus. This connection allows for the efficient transfer of genetic information from the nucleus to the rough ER.

Once the ribosomes on the rough ER synthesize proteins, the rough ER is also involved in the processing and modification of these proteins. It helps in folding the newly synthesized proteins into their functional three-dimensional shapes and also adds various modifications such as glycosylation (the addition of sugar molecules) or signal sequences that target the proteins to specific locations within or outside the cell.

After processing, the proteins may be transported to other parts of the cell or exported to the cell membrane or extracellular space. The connection between the rough ER and the nuclear membrane ensures a coordinated flow of genetic information and protein synthesis, allowing the cell to efficiently carry out its functions.

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Answer:

..............,.,.,.,,..,,.,.,

For each color of paper, the part of white light that is reflected depends on the color of the paper. When white light strikes an object, some of the light is absorbed by the object, some of it is transmitted through the object, and some of it is reflected.

The color of the object that we see is the color of the light that is reflected by the object.

For example, when white light strikes blue paper, the blue color of the paper absorbs all the other colors of the spectrum except blue, which is reflected back to our eyes. This is why we see the paper as blue. Similarly, when white light strikes red paper, the red color of the paper absorbs all the other colors except red, which is reflected back to our eyes. This is why we see the paper as red.

In summary, the color of an object is determined by the color of the light that is reflected by the object, and the color of the light that is reflected depends on the color of the object and the colors of the spectrum that are absorbed or transmitted by the object.

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The unit commonly used to measure pressure is the Pascal (Pa), which is equivalent to a force of 1 Newton per square meter: [Pressure] = 1 [kg/s²·m] = 1 Pa

Pressure is defined as the force per unit area. It can be represented using dimensional analysis by considering the fundamental units of force and area. Force is represented by the fundamental unit of mass (kg) multiplied by the fundamental unit of acceleration (m/s²). Therefore, the dimension of force is [kg·m/s²]. Area is represented by the fundamental unit of length (m) squared. Therefore, the dimension of area is [m²]. To determine the dimension of pressure, we divide the dimension of force by the dimension of area: [Pressure] = [Force] / [Area] = [kg·m/s²] / [m²]

Simplifying the expression, we can cancel out the common unit of length:

[Pressure] = [kg/s²·m] The unit commonly used to measure pressure is the Pascal (Pa), which is equivalent to a force of 1 Newton per square meter: [Pressure] = 1 [kg/s²·m] = 1 Pa Therefore, the dimension of pressure is [kg/s²·m] and its unit is the Pascal (Pa).

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Answer:

12.6 g of H₂O can be produced in the combustion

Explanation:

This excersise involves an easy combustion reaction:

2C₄H₁₀  +  13O₂  →   8CO₂  +  10H₂O

First step: calculate moles of reactants in order to find out the limiting.

23 g . 1mol / 58g = 0.396 moles of butane

29.1 g . 1mol /32g = 0.909 moles of O₂

2 moles of butane react to 13 moles of oxygen

Then, 0.396 moles of butane may react to (0.396 . 13) / 2 = 2.574 moles

Certainly we do not have enough oxygen, so O₂ becomes the limiting reactant

13 moles of O₂ can produce 10 moles of water

Then 0.909 moles may produce (0.909 . 10) /13 = 0.699 moles H₂O

We convert moles to mass → 0.699 mol . 18 g/mol = 12.6 g

Explanation:

Explanation:

Nucleons can be either protons or neutrons contained in an atom, and since Carbon-14, has a mass number of 14, it is evident that it contains 14 nucleons, as the mass number of an element is the sum of the protons and neutrons of an element

Answer:

you need to state the options

Answer:

Nitrogen is limiting reactant and 30.4kg of ammonia can be formed

Explanation:

Nitrogen, N₂, reacts with hydrogen, H₂ to produce ammonia, NH₃, as follows:

2N₂ + 3H₂ → 2NH₃

Where 2 moles nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia

To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles and the mass of ammonia formed as follows:

Moles N2 -Molar mass: 28g/mol-

50000g * (1mol / 28g) = 1786 moles N2

Moles H2 -Molar mass: 2g/mol-

10000g * (1mol / 2g) = 5000 moles H2

For a complete reaction of 5000 moles H2 are needed:

5000 mol H2 * (2mol N2 / 3mol H2) = 3333 moles N2. As there are just 1786 moles, Nitrogen is limiting reactant

The moles of ammonia that can be produced are 1786 moles because 2mol N2 = 2moles NH3.

The mass of ammonia -Molar mass NH3: 17g/mol- is:

1786 moles NH3 * (17g / mol) = 30362g =

30.4kg of ammonia can be formed

The mass of silicon, Si produced from the reaction is 329.41 g

SiCl₄ + 2Mg —> 2MgCl₂ + Si

Molar mass of SiCl₄ = 28 + (35.5×4) = 170 g/mol

Mass of SiCl₄ from the balanced equation = 1 × 170 = 170 g

Molar mass of Si = 28 g/mol

Mass of Si from the balanced equation = 1 × 28 = 28 g

From the balanced equation above,

170 g of SiCl₄ reacted to produce 28 g of Si.

From the balanced equation above,

170 g of SiCl₄ reacted to produce 28 g of Si.

Therefore,

2 Kg (i.e 2000 g) of SiCl₄ will react to produce = (2000 × 28) / 170 = 329.41 g of Si

Thus, 329.41 g of Si were obtained from the reaction

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Answer: 0.276g of H2 could be obtained from the reaction, considering the mass of reactants given

Explanation:

The question requires us to determine the amount of hydrogen gas (H2) that would be obtained when 10.0g of metallic magnesium (Mg) and 10.0g of chloridric acid (HCl) are reacted.

The following unbalanced chemical equation was provided:

To solve this problem, we'll need:

1) obtain the balanced chemical equation;

2) determine the limiting reactant considering the amount of reactants used and the stoichiometry of the reaction;

3) calculate the mass of hydrogen gas produced, considering the limiting reactant

1) Balancing the chemical equation

From the unbalaced chemical equation, we can see that there is the same amount of Mg on both sides of the equation, but we need to adjust the amount of H and Cl atoms.

There are 2 Cl atoms and 2 H atoms on the right side, and 1 Cl and 1 H atom on the left side, thus we can adjust the coefficient of HCl from 1 to 2 to adjust these elements. The balanced chemical equation can be written as:

2) Determining the limiting reactant

Now that we know the balanced chemical equation, we can say that 2 moles of HCl are necessary to react with 1 mol of Mg. Thus, we can write:

1 mol Mg ----------------------- 2 mol HCl

From this stoichiometric relation, we can calculate the amount of HCl that would be necessary to react with 10.0 g of Mg.

First, let's determine the amount of moles of Mg contained in 10.0g of this metal and the number of moles of HCl in 10.0g of this acid:

(the atomic mass of Mg is 24.31 amu, which is numerically identical to its molar mass, 24.31 g/mol, and the molar mass of HCl is 36.4g g/mol)

Therefore, 0.411 moles of Mg and 0.274 moles of HCl were used in the reaction.

Next, we can determine how many moles of HCl would be necessary to react with 0.411 moles of Mg:

1 mol Mg ----------------------- 2 mol HCl

0.411 mol Mg ----------------- x

Solving for x, we have that 0.822 moles of HCl would be necessary to react with the given amount of Mg. Since the amount actually used of HCl (0.274 mol) is smaller than the necessary amount, we can say that HCl is the limiting reactant.

3) Calculating the mass of H2 obtained

Using the limiting reactant and the stoichiometry of the reaction, we can determine the amount of H2 that could be produced.

From the balanced chemical equation, we know that 2 moles of HCl are necessary to produce 1 mol of H2. Thus, we can write:

2 mol HCl ------------------- 1 mol H2

0.274 mol HCl ------------ y

Solving for y, we have that 0.137 moles of H2 would be obtained.

We can convert the number of moles of H2 to its correspondent mass as it follows (the molar mass of H2 is 2.016 g/mol):

Therefore, 0.276g of H2 could be obtained from the reaction, considering the mass of reactants given.

Answer:

120N

Explanation:

Answer:

3

Explanation:

Load / Effort

The effort is 30N and the Load is 90N.

So the MA is equal to 90/30 = 3

25.0grams of bromine is equivalent to 1.881 × 10²³ molecules.

The number of molecules of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number (6.02 × 10²³).

Avogadro's number is the number of atoms present in 12 grams of isotopically pure carbon-12, being 6.02214076 × 10²³. By definition, it is the number of elementary entities (atoms or molecules) comprising one mole of a given substance.

According to this question, sodium is combined with bromine to produce sodium bromide. If one uses 25.0g of bromine, the number of moles of bromine used is as follows:

no of moles = 25.0g ÷ 80g/mol

no of moles = 0.3125moles

no of molecules = 0.3125 × 6.02 × 10²³ = 1.881 × 10²³ molecules

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Explanation:

I hope it helps you

good luck

Answer for the question

Answer:

Mass is the independent variable, and boiling point is the dependent variable.

The percent yield of the reaction is 45.44%

Percentage yield is basically,

 \(\rm Percent\ yield\ = \frac{actual\ yield}{theoretical\ yield} \times 100\)

2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O

To calculate the theoretical yield, consider the stoichiometry of the reaction.

2 moles of NaOH reacts with 1 mole of H₂SO₄ to give 1 mole of Na₂SO₄ and 2 moles of H₂O. The mole ratio of H₂SO₄ and Na₂SO₄ is 1:1

For this mole ratio to be useful, convert the given concentration of H₂SO₄ into moles.  

     \(\rm Molarity\ =\ \frac{No.\ of\ moles}{Volume\ of\ solution (L)}\)

            \(\rm 3.10\ =\ \frac{No.\ of\ moles}{0.125}\)

\(\rm No.\ of\ moles\ =\ 3.10 \times 0.125\\)

                     \(=\ 0.38\)

Since, mole ratio of H₂SO₄ and Na₂SO₄ is 1:1

Amount of Na₂SO₄ formed would be also 0.38 mol

Convert this amount in moles to amount in grams

\(\rm No.\ of\ moles\ =\ \frac{Mass\ formed\ }{Molecular\ mass}\)

\(\rm Mass\ formed\ =\ No.\ of\ moles\times molecular\ mass\)

                     \(\rm =\ 0.38\times 142.04\)

                     \(\rm =\ 53.97\ grams\)

Theorical yield of Na₂SO₄ is 53.97 grams

Therefore,   \(\rm Percent\ yield\ = \frac{actual\ yield}{theoretical\ yield} \times 100\)

                                          \(\rm =\ \frac{24.5}{53.97}\times 100\)

                                          =  45.44%

The percent yield of the reaction is 45.44%

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Answer:

The charge on the compound

Explanation:

The charge on the compound signifies that the compound is not in its neutral state.

Therefore, the oxidation state would be equal to the charge on the compound.

Answer:

The charge on the compound

Explanation:

The charge on the compound signifies that the compound is not in its neutral state.

Therefore, the oxidation state would be equal to the charge on the compound.

Work can be totally transformed into heat (for example, by friction), whereas heat can only be partially converted into work.

A model is a depiction of something that is frequently too difficult to directly observe or display. Although experimental testing validates a model, it is only accurate in explaining specific characteristics of a physical system.

Work is defined as the transfer of energy to or from a system by any means other than heat.

A transfer of energy to or from a system by any means other than heat is called “work”. Work can be completely converted into heat (by friction, for example), but heat can only be partially converted to work. The Second Law of Thermodynamics, states that the complete conversion of heat into work is impossible.

Heat transmission in materials can be described using the kinetic particle model. Heat energy always travels from a high-temperature zone to a low-temperature region.

Thus, heat can do work by constructing a model.

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The compound solubility which will not be affected by a low pH in solution is AgBr.

pH is a measure of the acidity or basicity of any solution and according to the pH scale 0 to 6.9 shows the acidity, 7 is neutral and 7.1 to 14 shows the basicity of any solution.

AgBr is not affected by a low pH in solution.

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