To qualify for the finals in a racing event, a race car must achieve an average speed of 255 km/h on a track with a total length of 2,200 m. If a particular car covers the first half of the track at an average speed of 213 km/h, what minimum average speed must it have in the second half of the event in order to qualify

Answers

Answer 1

Please find attached photographs of your answer. Hope it helps. Please do comment

To Qualify For The Finals In A Racing Event, A Race Car Must Achieve An Average Speed Of 255 Km/h On
To Qualify For The Finals In A Racing Event, A Race Car Must Achieve An Average Speed Of 255 Km/h On

Related Questions

Suppose the starter cable of a car is carrying 135 A of current. Assume this cable is long and straight How many meters from the cable must you be to experience a field less than the Earth's (5.00 x 10-T)?

Answers

You must be at least 0.54 meters (or about 1.8 feet) away from the cable to experience a magnetic field less than the Earth's magnetic field.

What is magnetic field?

A magnetic field is a physical field generated by moving electric charges or the intrinsic magnetic moments of elementary particles associated with their spin. A magnetic field is a vector field, which means that it has both magnitude and direction. It can exert a force on other moving charges or magnetic materials, causing them to experience a magnetic force.

In the classical picture, a magnetic field is created by a magnet or by a moving electric charge, such as an electric current. The strength of the magnetic field at a given point is proportional to the magnitude of the current or the strength of the magnet, and it decreases with distance from the source.

To calculate the distance from the cable at which the magnetic field is less than the Earth's magnetic field, we can use the formula for the magnetic field around a long, straight wire:

B = μ0 * I / (2πr)

where B is the magnetic field, μ0 is the permeability of free space (4π x  10⁻⁷T m/A), I is the current, and r is the distance from the wire.

Rearranging the formula, we get:

r = μ0 * I / (2π * B)

Plugging in the given values, we get:

r = (4π x 10⁻⁷T m/A) * 135 A / (2π * 5.00 x 10⁻⁵ T)

r = 0.54 meters

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Without collecting any data, describe the motion of the puck while it is on the curved portion of the ramp - is it more similar to motion with constant velocity or motion with constant acceleration? Explain your reasoning. Assume we can ignore friction.

Answers

A constant acceleration for an object guarantees that its velocity will change continuously throughout time and not remain constant.

What parallels exist between acceleration and speed?

Similarities.Acceleration and velocity are both vector quantities, meaning they have both a magnitude and a direction.Both expressions are capable of being zero, positive, or both.

What are the parallels and differences between acceleration and velocity?

The rate at which in displacement is known as velocity.The rate at which velocity changes is called acceleration.Due to the fact that it includes both magnitude and direction, velocity is an vector quantity.As the rate at which velocity changes, acceleration is likewise a vector quantity.

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During an experiment, your teacher gives you two objects: tissue paper and a balloon. You observe that the tissue paper repels the balloon. What does this most likely tell you about the charges of the two objects?

Both objects have negative charges.
The tissue has a positive charge, and the balloon has a negative charge.
The tissue has a negative charge, and the balloon has a positive charge.
The objects have no interactive with each other.

Answers

Answer:

i think your answer is this: the objects have no interactive with each other.

Explanation:

if you think about it tissue paper doesn't really have a static electrical charge if it does it is very weak so therefore cannot really attract or repel anything.

Which statements accurately describe matter? Check all that apply.

Only living things are made up of matter.
Matter is made up of tiny particles called atoms.
Atoms were discovered in the twenty-first century.
Atoms cannot be divided and still retain the properties of its original state.
A single atom can be seen only with a standard microscope

Answers

The following statements accurately describe matter:

Matter is made up of tiny particles called atoms.

Atoms cannot be divided and still retain the properties of their original state.

What is Atom?

An atom is the basic unit of matter, consisting of a nucleus composed of protons and neutrons, surrounded by electrons in electron shells or energy levels. Atoms are the building blocks of all matter and are the smallest unit of an element that retains the chemical properties of that element.

The statement "Atoms cannot be divided and still retain the properties of their original state" refers to the concept of the indivisibility of atoms, as proposed by John Dalton in the early 19th century. According to Dalton's atomic theory, atoms are considered to be the smallest unit of matter that retains the properties of an element. In other words, atoms are considered to be indivisible and cannot be further broken down into smaller particles without losing their characteristic properties.

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A 3kg book falls from a 2m tall bookshelf what is the speed

PICTURE included

A 3kg book falls from a 2m tall bookshelf what is the speed PICTURE included

Answers

Answer:

39.2m/s

Explanation:

The potential energy the book has right before it falls is equal to the kinetic energy in falling.

PE = KE

mgh = (1/2)mv

2gh=v

v=(2)(9.81)(2)

v=39.24m/s

In a hydraulic press the large piston has cross-sectional area 230 cm2 and the small piston has cross-sectional area 5 cm2. If a force of 250 N is applied to the small piston, what is the force (in kN) on the large piston? Give the answer with one decimal an no unit.

Answers

The force on the larger piston of cross-sectional area 230 cm² is 11500 N.

What is force?

Force can be defined as the product of mass and acceleration.

To calculate the force on the larger piston, we use the formula below.

Formula:

F = fA/a............... Equation 1

Where:

F = Force on the larger pistonf = Force applied to the smaller pistonA = Cross-sectional  Area of the larger pistona = Cross-sectional Area of the smaller piston

From the question,

Given:

A = 230 cm²a = 5 cm²f = 250 N

Susbtitute these values into equation 1

F = (250×230)/5F = 11500 N

Hence, the force on the larger piston is 11500 N.

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Which pair of vectors could produce a resultant of 32?
Group of answer choices

30 and 70

20 and 20

20 and 25

15 and 15

Answers

The resultant vector of 32 is produced is 20 and 25.

What are resultant vector?

To determine the resultant value of two or more vectors, use the resultant vector formula. This is created by computing the vectors depending on how they relate to one another. The resultant vector formula has many uses in physics and engineering. This may be seen in the way that many force vectors interact with one another when acting on a body; the resultant vector is then calculated using this formula.

The resultant vector is defined as the square root of the sum of squares of each vector. Hence the formula we get 20 and 25 squared and added as 32

Hence, the resultant vector of 32 is produced is 20 and 25

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Normal forces are applied uniformly over the surface of a spherical volume of water whose radius is 20.0 cm. If the pressure on the surface is increased by 200 MPa, by how much does the radius of the sphere decrease?

Answers

The radius of the sphere decreases by 11 mm when the pressure on its surface is increased by 200 MPa.

To determine the decrease in radius of the spherical volume of water when the pressure on its surface is increased, we can use the equation relating pressure to the radius of a sphere:

ΔP = K/R

Where ΔP is the change in pressure, K is a constant, and R is the radius of the sphere.

In this case, we're given that ΔP (change in pressure) is 200 MPa and the initial radius R is 20.0 cm. We need to find the change in radius ΔR.

We can rearrange the equation to solve for ΔR:

ΔR = K/ΔP

Now, we need to determine the value of the constant K. The constant K depends on the bulk modulus of the material, which is a measure of its resistance to compression. For water, the bulk modulus is approximately 2.2 GPa (gigapascals).

Substituting the values into the equation, we have:

ΔR = (2.2 GPa) / (200 MPa)

To simplify the calculation, we need to convert the units so that they are consistent. Let's convert GPa to MPa:

ΔR = (2.2 GPa * 1000 MPa/GPa) / (200 MPa)

ΔR = 11 mm

Therefore, the radius of the sphere decreases by 11 mm when the pressure on its surface is increased by 200 MPa.

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which is true of the motion of two free falling objects of mass m and 2m dropped from equal heights d in a vacuum?
A. both object land in the same time, but the heavier object has a greater final speed
B. both objects land in the same time, but the lighter object has greater final speed
C. both objects land at the same time, and both objects have the same final speed
D. both objects have the same final speed, but the lighter object lands first
E. both objects have the same final speed, but the heavier object lands first

Answers

True of the motion of two free falling objects of mass m and 2m dropped from equal heights d in a vacuum, the correct option is (c) Both items touch down at the same time and travel at the same pace.

In a vacuum, all objects, regardless of their mass, fall with the same acceleration due to gravity, which is approximately 9.8 m/s^2. Therefore, the motion of two free-falling objects of different masses dropped from the same height will reach the same final speed at the same time, regardless of their masses. This is known as the equivalence of gravitational and inertial mass, and is described by Einstein's theory of general relativity. In a vacuum, where there is no air resistance, the motion of two freely falling bodies will be described by parabolic paths. The final velocity and position of the bodies will depend on their initial conditions and the strength of the gravitational field.

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A 1 kg block is released from the rest from the top of an incline of height h = 1 m (point A) as shown in the figure. The block travels down the incline, passes over a horizontal surface and stops at point C which is x = 1 m from the bottom of the incline (point B). What is the coefficient of kinetic friction between the block and the sliding surface? (The coefficients of kinetic friction between the block and incline and the block and horizontal surface are the same). The incline angle q = 45.

A 1 kg block is released from the rest from the top of an incline of height h = 1 m (point A) as shown

Answers

The coefficient of kinetic friction between the block and the surface is 0.5.

What is the coefficient of kinetic friction?

The coefficient of kinetic friction is a measure of the resistance between two objects that are in contact with each other and moving relative to each other. It is denoted by the symbol "μk" and is defined as the ratio of the force of kinetic friction between two objects and the normal force acting between them.

Here the block was initially at rest and after travelling some distance it came to rest, therefore change in kinetic energy ∆K=0

Therefore mgh = unghcotx - umgx = 0

where h = 1m, x = 1m

u= 1 / 1+1

= 0.5

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En 2.0 s, una particula con aceleración constante a lo largo del eje x se mueve desde x =10 m
hasta x =50 m. La rapidez al final del recorrido es de 10 m/s. ¿Cuál es la aceleración de la partícula?

Answers

The correct response is x23

A bubble of air has a diameter of 1 mm whe
n it is 0.5 m under the surface of water (coefficient of surface tension 0.073 N/m). Find the gauge pressure inside the bubble.


A bubble of air has a diameter of 1 mm when it is 0.5 m under the surface of water (coefficient of surface

Answers

Gauge pressure inside the bubble is: Pgauge = -4846.6 Pa

What is gauge pressure?

Pressure measured relative to local atmospheric pressure is known as gauge pressure.

As ΔP = 4γ/r

ΔP -- pressure difference, γ -- coefficient of surface tension, r -- radius of bubble.

r = 0.5 mm = 0.0005 m

ΔP = 4 × 0.073 N/m ÷ 0.0005 m

ΔP = 58.4 N/m²

Patm = ρgh

Patm = 1000 kg/m³ × 9.81 m/s² × 0.5 m

Patm = 4905 Pa

Therefore, gauge pressure inside the bubble is:

Pgauge = ΔP - Patm

= 58.4 N/m² - 4905 Pa

Pgauge = -4846.6 Pa

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Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter

Answers

8.27 x 1013 meres is the orbital radius.

Additional details:-

Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution

The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.

6.67 x 10⁻¹¹ N/m²kg

2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7

What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?

The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.

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Three tiny charged metal balls are arranged on a straight line. The middle ball is positively charged and the two outside balls are negatively charged. The two outside balls are separated by 20 cm and the middle ball is exactly halfway in between. (HINT: Draw a picture; in your picture, the distance between the two outermost balls should be 20 cm.) The absolute value of the charge on each ball is the same, 1.45 μCoulombs (the meaning of μ, which is read as "micro", is 10-6). Give your answers in newtons.

a) What is the magnitude of the attractive force on either outside ball due ONLY to the positively-charged middle ball?

(b) What is the magnitude of the repulsive force on either outside ball due ONLY to the other outside ball?

(c) What is the magnitude of the net force on the outside of the ball

Answers

Answer:

\((a) 189.23 N\), \((b) 47.31 N\) and \((c) 141.92 N\).

Explanation:

Three balls are shown in figure having charge \(q=1.45 \mu C\). The middle ball, \(B\), is positively charged having charge \(+q\), and the remaining two outside balls, \(A\) and \(C\), are negatively charged having charged \(-q\) as shown.

\(AC=20 cm\) and \(AB=BC=10\) cm as B is the mid-point of AC.

Let \(d_1=AC=20\times 10^{-3}m\) and \(d_2=AB=BC=10\times 10^{-3}m\)

From Coulomb's law, the magnitude of the force, \(F\), between two point charges having magnitudes \(q_1 \& q_2\), separated by distance, \(d\), is

\(F=\frac {1}{4\pi\epsilon_0}\frac {q_1q_2}{d^2}\;\cdots (i)\)

where, \(\epsilon_0\) is the permittivity of free space and

\(\frac {1}{4\pi\epsilon_0}=9\times 10^9\) in SI units.

This force is repulsive for the same nature of charges and attractive for the different nature of charges.

Now, Using equations(i),

(a) The magnitude of attraction force between balls A and B is

\(F_{AB}=F_{BC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_2)^2}\)

\(\Rightarrow F_{AB}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(10\times 10^{-3}\right)^2}\)

\(\Rightarrow F_{AB}=189.23 N\)

(a) The magnitude of the repulsive force between balls A and C is

\(F_{AC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_1)^2}\)

\(\Rightarrow F_{AC}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(20\times 10^{-3}\right)^2}\)

\(\Rightarrow F_{AC}=47.31 N\)

(c) The magnitude of the net force, \(F_{net}\), on the outside of the ball is,

\(F_{net}=189.23-47.31 N\)

\(\Rightarrow F_{net}=141.92 N\)

Three tiny charged metal balls are arranged on a straight line. The middle ball is positively charged

A customs inspector was suspecting that some of the 12 plastic spheres, which were shipped out of the country, had something in them. Each sphere weighted the same and had hard walls everywhere. Inspector thought that it was possible to hide something inside each sphere. He was correct, and was able to use a simple experiment in determining which sphere had diamonds inside. How did he do it?

Answers

Answer:

use a hammer to hit it

Explanation:

if u hit it u will be able to hear the shattered noise

The Mars Rover Curiosity has a mass of 900 kg. Taking the gravitational field strength to be 9.8 N/kg
on Earth and 3.7 N/kg on Mars, give the value of the weight of the Rover on earth and mars

Answers

The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.

Weight of objects on Earth and on Mars

The weight of an object is given by the product of its mass and the gravitational field strength at its location.

On Earth:

Weight = mass x gravitational field strengthWeight = 900 kg x 9.8 N/kgWeight = 8820 N

On Mars:

Weight = mass x gravitational field strengthWeight = 900 kg x 3.7 N/kgWeight = 3330 N

Therefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.

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Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2​

Answers

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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Which of the following would be most likely to form a negative -1 anion A. Sulfur (S) B. Beryllium (Be) C. Sodium (Na) D. Bromine (Br)

Answers

Answer:

bromine is ur answer.......

may be it helps you.... friend...

A skier starts from rest at the top of a 20 degree incline and skis in a straight line to the bottom of the slope, a distance d (measured along the slope) of 400 m. If the coefficient of kinetic friction between the skis and the snow is 0.2, calculate the skier's speed at the bottom of the run.

Answers

Answer:

Explanation:

Loss of potential energy = mgh.

h = d sin 20

= 400 sin20 = 136.8 m

Loss of potential energy = m x 9.8 x  136.8

= 1340.64 m

negative work done by friction = μ mg cosθ x d

= .2 x m x 9.8 x cos 20 x 400

= 736.72 m

Net loss of potential energy = 1340.64 m - 736.72 m

= 603.92 m

= gain of kinetic energy = 1/2 m v²

1/2 m v² = 603.92 m

v² = 1207.84

v = 34.75 m /s .

How does an electric motor use magnetic force to produce motion?

The north pole of a permanent magnet placed in the center of an electromagnet attracts the north pole of the electromagnet.
The north pole of an electromagnet placed in the center of a permanent magnet attracts the north pole of the permanent magnet.
The north pole of a permanent magnet placed in the center of an electromagnet repels the north pole of the electromagnet.
The north pole of an electromagnet placed in the center of a permanent magnet repels the north pole of the permanent magnet.

Answers

Answer:

The north pole of an electromagnet placed in the center of a permanent magnet repels the north pole of the permanent magnet.

Explanation:

The commutator of the electric motor reverses the current in each half revolution to keep the torque, turning the coil in the same direction. This occurs as the north pole of the electromagnet nears the south pole of the permanent magnet, and the current reverses, which causes the poles of the magnets to repel.

Thus, the correct answer is "the north pole of an electromagnet placed in the center of a permanent magnet repels the north pole of the permanent magnet".

Answer:

The answer is D

Explanation:

Just took the test on Edge :)

A softball has a mass of 0.180 kg. What is its weight on earth?

Answers

Answer:

for a mass m = 10kg on Earth it`s weight is W = mg = 10 x 10 = 100N.

Explanation:

Answer:

F= mg= 0.180 kg x 9.8 m/s^2= 1.80 N

the weight of three castings are 45.302kg 44.982kg and 45.716kg find the average weight if the 4th casting is taken the average weight becomes 46kg what is the weight of the 4th casting​

Answers

The weight of the fourth casting is 48 kg.

Given - The weight of three castings -

45.302kg

44.982kg

45.716kg

To find - The average weight if the 4th casting is taken the average weight becomes 46kg what is the weight of the 4th casting​

Solution -

Let's calculate the average weight of the first three castings using the given weights:

Average weight = (Weight of first casting + Weight of second casting + Weight of third casting) / 3

Average weight = (45.302 kg + 44.982 kg + 45.716 kg) / 3

Average weight = 136.000 kg / 3

Average weight = 45.3333... kg (rounded to four decimal places)

Now, let's calculate the weight of the fourth casting by using the average weight and the desired overall average weight:

Total weight of all four castings = Average weight * 4

Total weight of all four castings = 46 kg * 4

Total weight of all four castings = 184 kg

To find the weight of the fourth casting, we subtract the total weight of the first three castings from the total weight of all four castings:

Weight of the fourth casting = Total weight of all four castings - Total weight of first three castings

Weight of the fourth casting = 184 kg - 136 kg

Weight of the fourth casting = 48 kg

Therefore, the weight of the fourth casting is 48 kg

Could someone please help me? If you wear kneepads when skating, after a fall to your knees, it will take 3 times as long for them to come to a rest. How does this affect the change in momentum of your knees during the fall?

Could someone please help me? If you wear kneepads when skating, after a fall to your knees, it will

Answers

The change in momentum of your knees during the fall is the same with or without the kneepads.

option B is the correct answer.

What is law of conservation of linear momentum?

The law of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

The sum of the initial momentum of the system is equal to sum of the final momentum of the system.

Pi = Pf

where;

Pi is the initial momentum of the systemPf is the final momentum of the system

Thus, according the law of conservation of linear momentum, the change in the momentum of the skater is constant. That is the change in momentum is the same with or without the kneepads.

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How does a wind turbine transform mechanical energy into electrical energy?

Answers

Answer:

"A turbine takes the kinetic energy of a moving fluid, air in this case, and converts it to a rotary motion. As wind moves past the blades of a wind turbine, it moves or rotates the blades. These blades turn a generator."

What do scientists collect to answer questions and support ideas? O A. Hypotheses OB. Opinions O C. Theories D. Evidence​

Answers

Answer:

The answer is D.

Explanation:

A Hypothesis is what they think is gonna happen or n educated guess. An opinion is someone's point of view on something. A theory is an idea intended to explain something. Evidence is an object you collect to find out something and it helps support your research. Evidence matches your question best.

The water in a tank is pressurized by air,and the pressure is measured by a multifluid manometer as shown in the Fig. The tank is located on a mountain at an altitude of 1400 m where the atmospheric pressure is 85.6 kPa. Determine the air pressure in the tank if ℎ1 = 0.1 m, ℎ2 =0.2 m, and ℎ3 = 0.35 m. Take the densities of water, oil, and mercury to be1000 kg/m3, 850 kg/m3, and 13,600 kg/m3
, respectively?

Answers

Air is used to pressurize water in a tank, and the pressure is then measured. by a multifluid manometer so Consequently, the air pressure in the tank is 129.45KPa.

In the physical sciences, pressure is defined as either the stress at a place within a confined fluid or the perpendicular force per unit area. The weight of the atm is atmospheric pressure, which is approximately 15 pounds per square inch at sea level. Each square meter of the Earth's surface is under pressure from the atmosphere.

atmospheric pressure (\(P_{atm\))=85.6kPa

 \(P_{atm\)=85600Pa

density of water=\(\rho =\)1000 kg/\(m^3\)

density of oil(\(\rho_0\))=850kg/\(m^3\)

density of mercury(\(\rho_{m\))=13600 kg/\(m^3\)

height of water column(\(h_1\))= 0.1m

height of oil column from water level(\(h_2\))=0.2m

height of mercury column (\(h_3\))=0.35m

pressure at point B

\(P_B=P_{air} +\:\rho_0gh_1\: +\rho_wgh_2 \: \rightarrow(1)\)

\(P_B=P_{atm} +\:\rho_mgh_3\: \rightarrow(2)\)

\(P_{air} +\:\rho_0gh_1\: +\rho_wgh_2 \:=P_{atm} +\:\rho_mgh_3\:\)

\(P_{air} =\:-\rho_0gh_1\: -\rho_wgh_2 \:+P_{atm} +\:\rho_mgh_3\:\rightarrow(3)\)

\(\rho _mgh_3\)=13600x9.8x0.35=46648 Pa

\(\rho _0gh_1\) =850x9.8x0.1=833 Pa

\(\rho _wgh_2\) =1000x9.8x0.2=1960 Pa

By putting the value in eq.3

\(P_{air\)=85600+46648−833−1960 = 129455Pa

therefore pressure of air in the tank is 129.45KPa

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basics of gravitation:
Planet a exerts a force on planet b. What can be said about the magnitude and direction of the gravitational force planet b exerts on planet a?

Answers

Answer:

Explanation:

According to Newton's Law of Gravitation, the gravitational force between two objects is always mutual, meaning that the force that one object exerts on the other is equal in magnitude but opposite in direction.

This means that if planet A exerts a gravitational force on planet B, then planet B will also exert a gravitational force on planet A. The magnitude of this force will be equal to the magnitude of the force that planet A exerts on planet B, but the direction will be opposite.

For example, if planet A exerts a gravitational force on planet B that is pulling planet B towards planet A, then planet B will also exert a gravitational force on planet A that is pulling planet A towards planet B. The magnitude of these two forces will be equal, but the directions will be opposite.

hat he sais

Answer:w

Explanation:

No no no no. no no no no

Answers

No no no no. no no no no

A golf ball has a mass of 0.046 kg. The final velocity of the ball
after being struck by a golf club is 50 ms-1. The golf club is in
contact with the ball for a time of 1.3 ms. Calculate the average
force exerted by the golf club on the ball.

Answers

The average force exerted by the golf club on the golf ball is equal to 1769.2N.

What is force?

Force acting on an object can be described as the influence that changes the state of the object of motion or rest. The S.I. unit of force is Newton (N) and force is a vector parameter.

The mathematical formula of the 2nd law of motion for force is written as follows:

F = ma

Given the mass of the ball, m= 0.046 Kg

The golf club was in contact with the ball for time, t = 1.3 ms = 1.3 ×10⁻³s

The speed of the golf ball, v = 50 m/s

We know that, equation of motion: \(v = u + at\)

50 = 0  + a (1.3 ×10⁻³)

a = 38.46 ×10³ m/s²

The average force on the golf ball will be:

F = ma = 0.046 ×38.46 ×10³

F = 1769.2 N

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An astronomer discovers a new galaxy using a telescope. The astronomer wants to investigate how the galaxy is moving relative to the Milky Way galaxy.

In one or two sentences, make a hypothesis about the movement of the galaxy and explain at least one way to test the hypothesis.

Answers

No matter what, if you’re in an already existing galaxy, any galaxy outside of your existing territory will be moving away from yours.

The hypothesis about the movement of the galaxy is that;

Galaxies move far from each other continuously

      The milky way galaxy is the galaxy system that has over hundred billion stars and it also includes the solar system. It is also referred to as galaxy and the milky was is described like that because that is its' appearance when viewed from the earth.

       Now, since the astronomer has discovered a new galaxy, it means that the universe is continuously expanding. This is because the universe encompasses everything that exists.

        Now, galaxies move in space and since the universe space is continuously expanding, it means that the galaxies move from each other continuously. This means the farther the galaxy is from the earth or milky way which is an observable part of the universe, the faster will be the movement of the galaxy and the nearer the galaxy is to the milky way, the lesser will be the movement of the galaxy.

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