To determine the number of deer in a forest, a forest ranger tags 280 and releases them back into the forest. Later, 405 deer are caught, out of which 45 of them are tagged. About how many deer are in the forest?

The C(12) represents the total cost of $348 for renting the industrial cleaning unit for 12 hours.

C(12) represents the total cost (in dollars) of renting an industrial cleaning unit for 12 hours. Substituting 12 for t in the function C(t)=60+24t, we get C(12)=60+24(12)=60+288=348. Therefore, the total cost of renting the industrial cleaning unit for 12 hours would be $348.

The function C(t) = 60 + 24t is used to calculate the total cost of renting an industrial cleaning unit for t hours. In this equation, C represents the total cost in dollars, and t represents the number of hours.

C(12) represents the total cost of renting the cleaning unit for 12 hours. To find the cost, substitute t with 12 in the equation:
C(12) = 60 + 24(12)

Now, perform the calculations:
C(12) = 60 + 288
C(12) = 348

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The correct statement is the percent increase of her salary is 20% every year. Hence, the answer is option E. Given that a company's vice president's salary n years after becoming vice president is defined by the formula S(n) = 70000(1.2)". We have to determine which of the following statements is true:

Given that a company's vice president's salary n years after becoming vice president is defined by the formula S(n) = 70000(1.2)". We have to determine which of the following statements is true:

She will be receiving a 2% raise per year. Her salary will increase $14,000 every year. The percent increase of her salary is 120% every year. Her salary is always 0.2 times the previous year's salary. The percent increase of her salary is 20% every year.

To calculate the salary of the vice president after n years of becoming a vice president, we use the given formula:

S(n) = 70000(1.2)

S(n) = 84000

The salary of the vice president after one year of becoming a vice president: S(1) = 70000(1.2)

S(1) = 84000

The percent increase of her salary is: S(n) = 70000(1.2)n

S(n) - S(n-1) / S(n-1) × 100%

S(n) - S(n-1) / S(n-1) × 100% = (70000(1.2)n) - (70000(1.2)n-1) / (70000(1.2)n-1) × 100%

S(n) - S(n-1) / S(n-1) × 100% = 20%

Therefore, the correct statement is the percent increase of her salary is 20% every year. Hence, the answer is option E.

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Given :

There are currently 260 people in archery clubs across the city, and this number is increasing by 11% per year.

To Find :

An equation that can be used to find the number of people, y, in archery clubs across the city after 8 years.

Solution :

Increase in people after 1 years :

\(P = 260 + 260\times 0.11\\\\P = 260( 1 + 0.11)\\\\P = 260\times 1.11\)

After 2 years :

\(P = 260\times 1.11 + 260\times 1.11\times 0.11\\\\P = 260\times 1.11 ( 1 + 0.11)\\\\P = 260\times 1.11^2\)

Therefore, after 8 years the expression of population is :

\(P = 260\times 1.11^8\)

Hence, this is the required solution.

So the right answer is of option D.

Look at the attached picture

Hope it will help you

Good luck on your assignment

Answer:

(6x + 11)(x – 5)

Step-by-step explanation:

It's D on edg

The solution to the fraction two and one-third times four-fifths equals one and thirteen-fifteenths.

The correct answer option is option C

A fraction refers to a part of a whole, especially a comparatively small part. It is also the ratio of two numbers, the numerator and the denominator, usually written as one above the other and separated by a horizontal bar.

A numerator is the number above the horizontal bar while the denominator is the number below the horizontal bar in a fraction.

Two and one-third times four-fifths

= 2 1/3 × 4/5

= 7/3 × 4/5

= (7 × 4) / (3 × 5)

= 28 / 15

= 1 13/15

Therefore, the fraction two and one-third times four-fifths equals one and thirteen-fifteenths.

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Answer: 55%

Step-by-step explanation:

Answer:

55%

Step-by-step explanation:

The reason is math hope this helped :)

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Answer:

5 minutes

Step-by-step explanation:

150-50=100

100/20=5

a) If two points on a line are A(-5,7) and B(-2,1), the rise -6, the run is of 3, and then the slope is of -2.

b) If two points on a line are A(10,-3) and B(12,9), the rise 12, the run is of 2, and then the slope is of 6.

c) If two points on a line are A(4,6) and B(8,-8), the rise -14, the run is of 4, and then the slope is of -3.5.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

For which the parameters are given as follows:

As the slope represents the rate of change of the output relative to the input, it is calculated as the change in the output y divided by the change in the input x, that is, the rise divided by the run.

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a) The values of X and Y that maximize the utility are X = 250 and Y = 125.

b) T he values of X and Y that maximize the utility using the Lagrangean method are X = 250 and Y = 125.

a) To find the values of X and Y that maximize the utility using the substitution method, we can start by substituting the budget constraint into the utility function.

Since the budget constraint is given by 2X + 4Y = 1000 (kr), we can rearrange it to solve for X: X = (1000 - 4Y)/2 = 500 - 2Y.

Now substitute this expression for X in the utility function: U(Y) = 100(500 - 2Y)Y + (500 - 2Y) + 2Y.

Expand and simplify the expression: U(Y) = 50000Y - 200Y^2 + 500 - 2Y + 2Y.

Combine like terms: U(Y) = -200Y^2 + 50000Y + 500.

To maximize the utility, we need to find the critical points. Take the derivative of U(Y) with respect to Y and set it equal to zero:

dU(Y)/dY = -400Y + 50000 = 0.

Solve for Y: Y = 50000/400 = 125.

Now substitute this value of Y back into the budget constraint to find the corresponding value of X:

2X + 4(125) = 1000,
2X + 500 = 1000,
2X = 500,
X = 250.



b) To find the values of X and Y that maximize the utility using the Lagrangean method, we need to set up the following equation:

L(X,Y,λ) = U(X,Y) - λ(2X + 4Y - 1000),

where λ is the Lagrange multiplier.

Taking the partial derivatives of L with respect to X, Y, and λ, we have:

dL/dX = 100Y + 1 - 2λ,
dL/dY = 100X + 2 - 4λ,
dL/dλ = -(2X + 4Y - 1000).

Setting these derivatives equal to zero, we have the following system of equations:

100Y + 1 - 2λ = 0,
100X + 2 - 4λ = 0,
2X + 4Y - 1000 = 0.

Solving this system of equations, we find:

λ = 1/2,
X = 250,
Y = 125.

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Answer:

BOC= 110 degrees

Step-by-step explanation:

you can refer the above explanation

Answer:

f = 3

Step-by-step explanation:

8 = 2f + 2

-2         -2

6 = 2f

/2    /2

3 = f

The marginal product of capital is 3000 units of output when 5 units of capital and 10 units of labor are employed.

The marginal product of capital (MPK) is defined as the additional output that results from adding one more unit of capital while holding other inputs constant.

To find the MPK when 5 units of capital and 10 units of labor are employed, we need to take the partial derivative of the production function with respect to capital, holding labor constant at 10:

MPK = ∂q/∂k | l=10

Taking the partial derivative of the production function with respect to k, we get:

\(∂q/∂k = 12k^2l\)

Substituting k=5 and l=10, we get:

MPK = ∂q/∂k | l=10 = \(12(5)^2(10) = 3000\)

Therefore, the marginal product of capital is 3000 units of output when 5 units of capital and 10 units of labor are employed.

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To show that λâ1 is an eigenvalue of aâ1, we need to show that there exists a nonzero vector y such that aâ1y = λâ1y.
Let's use the hint and suppose that a nonzero vector x satisfies ax = λx. Then we can multiply both sides of this equation by aâ1 on the left to get:
aâ1(ax) = aâ1(λx)
x = aâ1(λx)
λâ1x = aâ1x
So if we let y = x, we have aâ1y = aâ1x = λâ1x = λâ1y. And since we started with a nonzero x, we know that y is also nonzero.
Therefore, we have shown that λâ1 is an eigenvalue of aâ1, as required.

To show that λ^(-1) is an eigenvalue of A^(-1), we will use the hint provided. Suppose a nonzero vector x satisfies Ax = λx, where λ is an eigenvalue of the invertible matrix A.

Since A is invertible, A^(-1) exists. Now, we can multiply both sides of Ax = λx by A^(-1) on the left:
A^(-1)(Ax) = A^(-1)(λx)

Using the associative property of matrix multiplication, we have:
(A^(-1)A)x = λ(A^(-1)x)

As A^(-1)A is the identity matrix I, the equation becomes:

Ix = λ(A^(-1)x)

Since Ix = x, we have:

x = λ(A^(-1)x)

Now, we want to find the eigenvalue of A^(-1). To do this, we'll divide both sides of the equation by λ:

x/λ = A^(-1)x

Since x is a nonzero vector, we can rewrite the equation as:

A^(-1)x = λ^(-1)x

Here, we see that λ^(-1) is indeed an eigenvalue of A^(-1), as it satisfies the eigenvalue equation A^(-1)x = λ^(-1)x for the nonzero vector x.

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Answer:

431.36

Step-by-step explanation:

The number in the thousandths is smaller than 5 so the hundredth will stay the same.

Answer:

C = 38n + 1750; 15,050

Step-by-step explanation:

We know that for each person, there's a fee of 38. That signifies that the n will be after 38. 1,750 is a one-time fee, so that's by itself. Plug it into the equation to get your first answer. Now, solve for b) by writing C = 38(350) + 1750; C = 15,050

Answer:

C = 38n + 1750; 15,050

Step-by-step explanation:

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Contrast ratio is a measurement that indicates the ability of a monitor to display colors by comparing the brightness of the brightest white to the darkness of the darkest black. The correct option is A.

The contrast ratio is usually expressed as a ratio, such as 1000:1 or 5000:1, with the first number indicating the brightness of the white and the second number indicating the darkness of the black. The higher the contrast ratio, the better the monitor is able to display a wide range of colors and shades. A high contrast ratio is important for tasks such as image and video editing, as it allows for more accurate color representation and contrast in the final product.

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Full Question ;

This indicates the monitor's ability to display colors by comparing the light intensity of the brightest white to the darkest black.

Question 1 options:

A) Contrast ratio

B) Dot Pitch

C) Active display area

D) Resolution

Contrast ratio Indicates a monitor's ability to display colors by comparing the light intensity of the brightest white to the

darkest black. The term you are looking for is "contrast ratio."

The brightness of the brightest shade (white) to the deepest shade (black) that the system is capable of producing is

measured as the contrast ratio (CR), a display system characteristic.

A display's desired feature is a high ratio of contrast. It resembles dynamic range in certain ways.

Ratings provided by various manufacturers of display devices are not always comparable to one another due to

differences in method of measurement, operation, and unstated variables.

This is because there is no official,  standardised way to measure contrast ratio for a system or its parts, nor is there a

standard for defining "Contrast Ratio" that is accepted by any standards organisation.[1] While other designers have

more frequently taken the effect of the environment into account, manufacturers have historically preferred

measurement methods that isolate the gadget from the system.

This is a key aspect of monitor performance, as it directly impacts the overall image quality and color reproduction.

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Answer:

Airplane goes 550 mph

Bike goes 9 mph

Ship goes 27 mph

Step-by-step explanation:

The airplane goes 1,925 every 3.5 hours

Divide 1925 by 3.5

1925/3.5 = 550mph

Do the same thing with the bike’s numbers:

45/5 = 9

So 9mph

And again with the ship:

432/16 = 27

It also says its three times as fast as the bike so:

9 x 3 = 27

So the ship goes 27 mph

Answer:

-4/9z-7

Step-by-step explanation:

7/9z-6/9z+2-5/9z-9

=7/9z-6/9z-5/9z+2-9

=(7-6-5)/9z+(2-9)

=-4/9z-7

Answer:

35.7 meters

Step-by-step explanation:

Literally all you do is divide the overall amount by how many rolls there were. That easy.

Cases (iii) and (iv) are left as exercises, meaning the proof for those cases is not provided in the given information. To fully establish the Characterization Theorem, the proof for these remaining cases needs to be completed.

Theorem 2.5.1 (Characterization Theorem):

If S is a subset of R that contains at least two points and has the property that if x, y ES and x < y, then (x, y)C S, then S is an interval.Proof.

There are four cases to consider:

(i) S is bounded,

(ii) S is bounded above but not below,

(iii) S is bounded below but not above, and

(iv) S is neither bounded above nor below.

Case (i): Let a = inf S and b = sup S.

Then SC[a, b] and we will show that (a, b)C S. If a < z < b, then there exist x, y

ES such that x < z < y. Since x < y and S has property (1), we have (x, y)C S.

Since zEP(x, y), it follows that zES.

Thus (a, b)C S.

Now if a S and b S, then S =[a, b].

If a S and b S, then S=(a, b).

The other possibilities lead to either S = (a, b) or S = [a, b].

Case (ii): Let b = sup S.

Then SC (-[infinity]o, b] and we will show that (-oo, b)C S. For, if z < b, then there exists y

ES such that z < y < b.

Since b is the least upper bound of S and yES, it follows that y 6S. But then (z, y)C (-oo, b) and (z, y)C S.

Thus (-oo, b)C S. Now if S contains its smallest element a, then S = [a, b]. Otherwise, S=(a, b).

Cases (iii) and (iv) are left as exercises.

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Answer:

32 sqrt(35)

16 sqrt(33)

Step-by-step explanation:

Multiply the numbers outside the square root and then multiply the numbers inside the square root.  Check to see if you can simplify inside the square root.

8 sqrt(7) * 4 sqrt(5) = 32 sqrt(35)

2 sqrt(11) * 8 sqrt(3) = 16 sqrt(33)

If a and b two values then

\(\\ \sf\Rrightarrow 3√6(5√7)\)

\(\\ \sf\Rrightarrow 15√6(7)\)

\(\\ \sf\Rrightarrow 15√42\)

#2

\(\\ \sf\Rrightarrow 8√7(4√5)\)

\(\\ \sf\Rrightarrow 32√7(5)\)

\(\\ \sf\Rrightarrow 32√35\)

#3

\(\\ \sf\Rrightarrow 2√11(8√3)\)

\(\\ \sf\Rrightarrow 16√11(3)\)

\(\\ \sf\Rrightarrow 16√33\)

Answer:

\(f(t) = 7.23( {1.0114}^{t} )\)

t = 0 represents January 1, 2014

(a)

\(f(6) = 7.23( {1.0114}^{6} ) = 7.739\)

The population of the world is expected to be about 7.739 billion people on January 1, 2020.

(b)

\(7.23( {1.0114}^{t} ) = 10\)

\(t = about \: 28.61 \: years\)

The population of the world is expected to be 10 billion people in about 28.61 years after January 1, 2014 (sometime in August 2042).

The derivative of the function is

A) dw/dz=z^5 (7z-18)

B) dh/dx=192x^11+36x^5-6x^2+19

C) dy/dx=24x^2-38x-15

In mathematics, the derivative of a function measures the sensitivity to change of the function value with respect to a change in its argument. It is the rate of change of a function with respect to a variable.

A) w = z^7 – 3z^6 + 14

dw/dz=7z^6-18z^5

dw/dz=z^5 (7z-18)

B) h(x) = 16x^12 + 6x^6 – 2x^3 + 19x – 7

dh/dx=192x^11+36x^5-6x^2+19

C) y = (8x + 5)(x^2 – 3x)

dy/dx=  d/dx  [8x+5]*〖(x〗^2-3x)+(8x+5)*d/dx[x^2-3x]

dy/dx=(8*  d/dx  [x}+d/dx[5])*〖(x〗^2-3x)+(8x+5)*(d/dx[x^2]-3 d/dx[x])

dy/dx=(8*1+0)(x^2-3x)+(8x+5)(2x-3*1)

dy/dx=8(x^2-3x)+(2x-3)(8x+5)

dy/dx=24x^2-38x-15

Note: The question is incomplete. The complete question probably is: Find the derivative of the following function: A) w = z^7 – 3z^6 + 14 B) h(x) = 16x^12 + 6x^6 – 2x^3 + 19x – 7 C) y = (8x + 5)(x^2 – 3x).

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Answer:

Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result. Therefore, the value of x is -10.

Step-by-step explanation:

I hope you can please mark me as

Answer:

Round 4264 to the nearest hundred so the answer is 4300.

Answer:

4300

Step-by-step explanation:

Answer: C.)32 Bestieeeee

Step-by-step explanation:

Answer:

C

Step-by-step explanation: