three electrons form an equilateral triangle 1.00 nmnm on each side. a proton is at the center of the triangle. part a what is the potential energy of this group of charges?
Answers
The potential energy of this group of charges is -0.67 x 10^-18 J. The potential energy of this group of charges forming an equilateral triangle can be calculated using the formula for the potential energy of a point charge:
U = kq1q2 / r
where k is the Coulomb constant, q1 and q2 are the charges of the two particles, and r is the distance between them.
Since there are three electrons and one proton, we need to calculate the potential energy between each pair of charges and add them together:
U = k(-e)(-e) / r + k(-e)(-e) / r + k(-e)(-e) / r + k(-e)(e) / r + k(-e)(e) / r + k(-e)(e) / r
where e is the charge of an electron and r is the distance between the charges.
Since the electrons form an equilateral triangle, the distance between each pair of electrons is 1.00 nm, and the distance between each electron and the proton is the same as the distance from the center of the triangle to one of the vertices, which is:
r = (1.00 nm) / (2 sin(60°)) = 0.577 nm
Plugging in the values for the Coulomb constant, the charge of an electron, and the distance between the charges, we get:
U = (8.99 x 10^9 Nm^2/C^2)(-1.60 x 10^-19 C)(-1.60 x 10^-19 C) / (1.00 x 10^-9 m) + (8.99 x 10^9 Nm^2/C^2)(-1.60 x 10^-19 C)(-1.60 x 10^-19 C) / (1.00 x 10^-9 m) + (8.99 x 10^9 Nm^2/C^2)(-1.60 x 10^-19 C)(-1.60 x 10^-19 C) / (1.00 x 10^-9 m) + (8.99 x 10^9 Nm^2/C^2)(-1.60 x 10^-19 C)(1.60 x 10^-19 C) / (0.577 x 10^-9 m) + (8.99 x 10^9 Nm^2/C^2)(-1.60 x 10^-19 C)(1.60 x 10^-19 C) / (0.577 x 10^-9 m) + (8.99 x 10^9 Nm^2/C^2)(-1.60 x 10^-19 C)(1.60 x 10^-19 C) / (0.577 x 10^-9 m)
U = 2.30 x 10^-18 J + 2.30 x 10^-18 J + 2.30 x 10^-18 J - 2.49 x 10^-18 J - 2.49 x 10^-18 J - 2.49 x 10^-18 J
U = -0.67 x 10^-18 J
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Related Questions
Please this is killing me I have no idea how to answer it it’s due in 10 mins please please help
How much sugar is in a 100 mL, 25% sugar solution? How much water?
Answers
the maximum amount of sugar in a 100ml water is 180 and 25% of 180 is 45
Please help me what is the answer
Answers
There are 20.8 moles of propanol
Further explanationThe mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
1.2 x 10⁵ molecules of propanol
\(\tt \dfrac{1.25\times 10^{25}}{6.02\times 10^{23}}=20.8~moles\)
How many grams are in 4.50x1023 molecules of CO2? [Molar mass CO2 = 44.01 g/mol CO2]
7.48x10-11 g CO2
32.9 g CO2
44.01 g CO2
6.16x1045 g CO2
Answers
The mass of 4.5 moles of CO2 is 7.48x10-11 g CO2 Option b)
What are 4 types of moles mass?The ratio between the mass and the quantity of material (measured in moles) of any sample of a chemical compound is known as the molar mass (M) in chemistry. The molar mass of a material is a bulk characteristic rather than a molecular one. The compound's molar mass is an average over many samples, which frequently have different masses because of elements.
A terrestrial average and a result of the relative frequency of the isotopes of the component elements on Earth, the molar mass is most frequently calculated from the standard atomic weights. For changing between a substance's mass and quantity in bulk amounts, the molar mass is the proper unit.
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3.7+5.894+782.52=
in sig fig rules
Answers
In scientific notation, "significant figures" refers to the significant single digits (0 to 9, inclusive) of the coefficient of expression.
What do you mean by significant numbers using an example?A significant figure in a given number is made up of all the certain digits plus one uncertain digit. They are reliant on the scale's or measurement tool's accuracy.
What is the example of significant figure?1. 587 is an example of four important digits (three are certain and one is doubtful).
What is the calculation of the above problem?On solving above problem we get,
3.7 + 5.894 + 782.52
9.594 + 782.52
792.114
792.1
The answer of the above problem is 792.1.
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What is the frequency of a red laser that has a wavelength of 676 mn
Answers
The frequency of a red laser that has a wavelength of 676 nm would be 4.43 x \(10^{14\) hertz.
Frequency of wavesThe frequency and wavelength of a wave are related by the following equation:
λf = c
Where λ is the wavelength of the wave in meters, f is the frequency in Hertz, and c is the speed of light in a vacuum.
in this case, λ = 676 nm = 6.76 x \(10^{-7\) m
c = 299,792,458 m/s
Making f the subject of the formula:
f = c/λ
= 299,792,458/6.76 x \(10^{-7\)
= 4.43 x \(10^{14\) hertz
In other words, the frequency of a red laser that has a wavelength of 676 nm would be 4.43 x \(10^{14\) hertz.
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Calculate the answers to the appropriate number of significant numbers
32.567
135.0
+ 1.4567
—————
Answers
Answer:
32.567+135.0+1.4567=169.027
to significant figures is 16
four solutions are made by dissolving a certain amount of each of the four substances in 450. g water. if the freezing point of each aqueous solution is the same, which substance is added to water in the greatest amount, in grams? assume all ionic compounds dissociate 100% to form ions in solution.
Answers
Four solutions are made by dissolving a certain amount of each of the four substances in 450. g water. The substance that is added to water in the greatest amount is the one with the lowest molar mass.
The freezing point is the temperature at which the vapor pressure of a liquid equals the atmospheric pressure exerted on the liquid. This temperature represents the point at which the liquid turns into a solid.
Ionic compounds dissolve in water and dissociate into cations and anions. Therefore, they are able to change the freezing point of the solvent. The freezing point depression can be calculated using the following equation:
ΔT = Kf·m
where ΔT is the freezing point depression, Kf is the freezing point depression constant for the solvent (water in this case), and m is the molality of the solution.
The molality of a solution is defined as the number of moles of solute per kilogram of solvent. The amount of solute that is added to the solution can be calculated using the following formula:
m = n / (m solvent · w solvent)
where m is the molality of the solution, n is the number of moles of solute, m solvent is the molar mass of the solvent, and w solvent is the mass of the solvent in kilograms.
The four solutions have the same freezing point, which means that they have the same molality.
Therefore, the amount of solute that is added to the solution can be calculated using the following formula:
m = n / (m solvent · w solvent)
where m is the molality of the solution, n is the number of moles of solute, m solvent is the molar mass of the solvent, and w solvent is the mass of the solvent in kilograms.
The molality of the solution is the same for all four solutions, so the amount of solute added to the solution is inversely proportional to the molar mass of the solute.
Therefore, the substance that is added to water in the greatest amount is the one with the lowest molar mass.
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which statement describes a mixture
Answers
Answer:
Mixtures are one product of mechanically blending or mixing chemical substances such as elements and compounds, without chemical bonding or other chemical change, so that each ingredient substance retains its own chemical properties and makeup.
consider the reaction when aqueous solutions of ammonium phosphate and chromium(ii) sulfate are combined. the net ionic equation for this reaction is:
Answers
Explanation:
The reaction of aqueous solutions of iron(II) sulfate and ammonium phosphate leads to the formation of solid precipitate of iron phosphate and an aqueous solution of ammonium sulphate.
Molecular equation :
3
F
e
(
S
O
4
)
(
a
q
)
+
2
(
N
H
4
)
3
P
O
4
(
a
q
)
→
F
e
3
(
P
O
4
)
2
(
s
)
+
3
(
N
H
4
)
2
S
O
4
(
a
q
)
Total ionic equation :
3
F
e
+
2
(
a
)
+
3
(
S
O
4
)
2
−
(
a
q
)
+
6
(
N
H
4
)
+
(
a
q
)
+
2
P
O
3
−
4
(
a
q
)
→
F
e
3
(
P
O
4
)
2
(
s
)
+
6
(
N
H
4
)
+
(
a
q
)
+
3
S
O
2
−
4
(
a
q
)
Net ionic equation :
By canceling the spectator ions from total ionic equation, we get
3
F
e
+
2
(
a
q
)
+
2
P
O
3
−
4
(
a
q
)
→
F
e
3
(
P
O
4
)
2
(
s
)
suppose you misread the final volume of base in the buret and record a volume that is greater than the true value. will your final calculated percent of acetic acid in vinegar be too high, too low, or unaffected?
Answers
The buret's final base volume and record a volume that is higher than the actual value. Acetic acid content in vinegar will be overestimated in the final calculation.
Explain about the Acetic acid?In addition to its other names, acetic acid is also referred to as ethanoic acid, ethylic acid, vinegar acid, and methane carboxylic acid; its chemical formula is CH3COOH. Vinegar gets its distinctive smell from acetic acid, a byproduct of fermentation. A 4-6% acetic acid solution makes up vinegar.
Vinegar, which includes 4 to 18% acetic acid, has acetic acid as its primary ingredient. It serves as an ingredient and food preservative (known as E260).
Acetic acid is a strong irritant to the eyes, mucous membranes, upper respiratory tract, and skin when it is in vapor form. 80% or higher acetic acid solutions can be corrosive when they come into contact with the skin or eyes, severely burning any exposed tissue.
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decomposition of ozone to oxygen occurs as a series of radical reactions. the individual reactions in this series are listed below but they are not in the correct order. use the labels on the right to correct the order of the reactions.
Answers
The correct order of the reactions for the decomposition reaction of ozone to oxygen is as follows:
O3 + O → 2 O2O3 + O → 2 O2O3 + O → 2 O2This series of radical reactions occurs in the stratosphere, where ozone O3 and an oxygen atom (O). The oxygen atom then reacts with another ozone molecule in the second reaction, forming two oxygen molecules. The third reaction is similar to the first, with an ozone molecule reacting with an oxygen atom to form two oxygen molecules. These reactions continue until all of the ozone has been converted to oxygen.
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Decane is a minor component in some gasolines. The standard molar enthalpy of formation of n-decane C₁0H22(0) is-249.4 kJ/mol. For the balanced reaction equation of
decane use:
C10H22(I)+ 12.5O2 --> 10CO₂ + 11H₂O.
Decane is a liquid, but all the other chemicals in this reaction are gases. What is the enthalpy change of this reaction in kJ/mol of decane?
The standard molar enthalpies of formation of:
O₂(s) - 0 kJ/mol;
CO₂(g)--393.5 kJ/mol; and
H₂O(g)--241.8 kJ/mol.
Answers
The enthalpy change of the reaction of decane would be -6582.3 kJ/mol of decane.
Enthalpy change calculationThe enthalpy change of a reaction can be calculated using the following equation:
ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)
We are given the standard molar enthalpy of formation of n-decane, C10H22, which is -249.4 kJ/mol.
Using the balanced chemical equation, we can identify the stoichiometric coefficients of the reactants and products:
C10H22(I) + 12.5O2(g) --> 10CO2(g) + 11H2O(g)
Reactants:
n(C10H22) = 1
n(O2) = 12.5
Products:
n(CO2) = 10
n(H2O) = 11
Now we can calculate the enthalpy change of the reaction:
ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)
ΔH = [10(-393.5 kJ/mol) + 11(-241.8 kJ/mol)] - [1(-249.4 kJ/mol) + 12.5(0 kJ/mol)]
ΔH = -6582.3 kJ/mol
The enthalpy change of the reaction is -6582.3 kJ/mol of decane.
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The fraction of a radioactive isotope remaining at time t is (1/2)t/t₁/₂, where t₁/₂ is the half-life. If the half-life of carbon-14 is 5730 yr, what fraction of carbon-14 in a piece of charcoal remains after(a) 10.0 yr;
Answers
the fraction that will be remaining after 10.0 x 10^4 yrs is :
144 x \(e^{-0.000121 * 10 }\)
WHAT IS CARBON - 14 ?Mono-carbon, also referred to as atomic carbon and 0-methane, is an inorganic gaseous substance with the chemical formula C. (also written [C]). It is kinetically unstable at room temperature and pressure and is removed through auto-polymerization.
Atomic carbon, which is also the source of carbon clusters, is the most basic form of carbon. It is also possible to look at the monomer of any (condensed) carbon allotrope, including graphite and diamond.
CALCULATIONthe half life of carbon - 14 is \(t_{1/2}\) = 5730 yrs
this means that 5730 yrs , the initial amount of carbon -14 will be halved
the radioactive constant is
λ = ln 2 / \(t_{1/2}\)
= ln 2 / 5730
= 0.000121
the fundamental decay question is
m = \(m_{0}\) \(e^{-λt}\)
the initial amount of carbon - 14 is \(m_{0}\) = 144 g
the time is t = 10 yrs
m = 144 x \(e^{-0.000121 * 10 }\)
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A 16.4-g sample of HF is dissolved in water to give 2.0 102 mL of solution. The concentration of the solution is:
A) 0.82 M
B) 0.16 M
C) 0.08 M
D) 4.1M
E) 8.2M
Answers
The concentration of the solution is D) 4.1M
To determine the concentration of the HF solution, we need to use the formula for molarity:
Concentration (M) = moles of solute / volume of solution (in liters)
First, we need to find the moles of HF. The molar mass of HF is 20.01 g/mol (F = 19.00 g/mol and H = 1.01 g/mol). Given the 16.4 g sample, we can find the moles as follows:
Moles of HF = (16.4 g) / (20.01 g/mol) = 0.82 mol
Next, convert the volume of the solution to liters:
Volume in liters = 2.0 x 10^2 mL * (1 L / 1000 mL) = 0.2 L
Now we can find the concentration:
Concentration (M) = (0.82 mol) / (0.2 L) = 4.1 M
So, the concentration is 4.1 M (option D).
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Find the volume of 53.5 g of O2 at 30.1°C and 110.0 kPa. Round to the nearest tenth.
Answers
The volume of 53.5 g of O₂ at 30.1°C and 110.0 kPa is 1 m³ approximately
The Charles Law: What is it explained?According to Charles' Law, while pressure is maintained constant, the volume of a given amount of gas varies in direct proportion to the absolute temperature of the gas. The Kelvin scale is used to measure temperature to determine the absolute temperature.
To find the volume of a gas, we can use the Ideal Gas Law:
PV = nRT
where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the universal gas constant, and T is the temperature of the gas in Kelvin.
First, we need to convert the given temperature of 30.1°C to Kelvin:
T = 30.1°C + 273.15 = 303.25 K
Next, we need to determine the number of moles of O₂ present. We can use the molar mass of O₂ to convert from grams to moles:
molar mass of O₂ = 32.00 g/mol
moles of O₂ = 53.5 g / 32.00 g/mol = 1.671875 mol
Now we can rearrange the Ideal Gas Law to solve for V:
V = nRT / P
V = 1.671875 × 8.3145 × 303.25 /110 k × 1000 Pa / kPa
V = 0.062878 m³
Finally, we round the answer to the nearest tenth: (rounded to one decimal place) V = 1 m³
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Which joint in the human body is similar to the chicken wing joint?
Answers
The joint in the human body which is similar to the chicken wing joint is referred to as the elbow joint.
What is a Joint?This is referred to as a point where two or more bones meet and are usually lined with cartilages so as to reduce the effect of friction as it causes wear and tear of the skeletal structures which are important for our movement.
The chicken has a structure called wing as its hands which is therefore the reason why it is similar to that of the elbow joint in humans and makes it the correct choice.
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A sample of gas has a volume of 2.00L at 25.0 degrees Celcius and 1.08atm. What volume ( in liters) will it have at 100 degrees Celcius and 1.5atm?
Answers
Answer:
Explanation:
The question requires us to calculate the volume (in L) of a gas under the conditions given.
The following information was provided by the question:
Initial volume of gas = V1 = 2.00 L
Initial temperature of gas = T1 = 25.0 °C
Initial pressure of gas = P1 = 1.08 atm
Final temperature of gas = T2 = 100 °C
Final pressure of gas = P2 = 1.50 atm
To solve this problem, we'll need to apply the equation of ideal gases (shown below) twice: first, to determine the number of moles of gas, and again to calculate the volume of gas under the final conditions. Note that we'll determine the number of moles of gas under the initial conditions because this amount won't change (as we're talking about the same sample of gas).
\(undefined\)The molecular geometry (shape) of the PF4+ ion IS tetrahedral trigonal planar trigonal bipyramidal octahedral trigonal pyramidal Using VSEPR Theory, the predicted Cl-B-Cl bond angle for BCI3 is 180° 107° 120° 109.5° 900 Using VSEPR Theory the molecular geometry (shape) for SF4 is square planar trigonal bipyramidal T-shaped octahedral see-saw
Answers
According to the modern VSEPR theory, the shape of \(PF^{+}_4\) is Tetrahedral. The predicted Cl - B - Cl bond angle forming \(BCl_{3}\) is 120°. The molecular geometry (shape) of \(SF_{4}\) is See-saw.
According to the modern VSEPR theory, we can calculate geometry(shape) by calculating the valence electrons.
number of electron - shape
6 - Trigonal
8 - Tetrahedral
10 - Trigonal bipyramidal (TBP)
12 - Octahedral
a. \(PF^{+}_4\)
Here, the total valence electrons = 5 + 4 - 1 = 8.
valence electrons of P = 5
Valence electrons of F = 1.
hence, we get the total F = 4.
So, the number of valence electrons is 8. So the shape is Tetrahedral.
b. \(BCl_{3}\)
Here, the total valence electrons = 3 + 3 = 6.
this means that the shape is trigonal planar.
So, the predicted Cl - B - Cl bond angle forming \(BCl_{3}\) is 120°.
c. \(SF_{4}\)
Here, the total valence electrons = 6 + 4 = 10.
valence electrons of P = 6
Valence electrons of 4 F = 4.
So, the number of valence electrons is 10. So the shape is Trigonal Bipyramidal (TBP).
Geometry is TBP according to VSEPR but the shape is see-saw according to Bents rule.
Check out the molecular geometry (shape) given below.
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Pls answer asap! NO ATTACHMENTS!!!
Answers
molecular formula: c57h110o6. what is the minimum amount of oxygen required, in g, for complete combustion?
Answers
The minimum amount of oxygen required, in g, for complete combustion of C₅₇H₁₁₀O₆ will be 1304 g
Molecular formula = C₅₇H₁₁₀O₆
The amount is not given so we take it as 1 mol
The minimum amount of oxygen required for combustion = ?
First, we will write the chemical equation
C₅₇H₁₁₀O₆ + O₂ = CO₂ + H₂O
Balance the chemical equation
2C₅₇H₁₁₀O₆ + 163O₂ = 114CO₂ + 110H₂O
The molar ratio of C₅₇H₁₁₀O₆ to oxygen is 2 : 163
As we have 1 mol C₅₇H₁₁₀O₆; 163 / 2 = 81.5 mol
number of moles of O₂ required = 81.5 mol
Covert the number of moles to grams
grams = number of moles × molar mass
grams of O₂ required = 81.5 mol × 16 g/mol
grams of O₂ required = 1304 g
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When titrating a strong acid with a strong base, after the equivalence point is reached, the pH will be determined exclusively by:
Answers
When titrating a strong acid with a strong base, after the equivalence point is reached, the pH will be determined exclusively by the excess amount of base added.
This is because the strong acid has been completely neutralized by the strong base at the equivalence point, and any further addition of the base will result in an excess amount of OH- ions in solution. These excess OH- ions will react with water to form more OH- ions, which will increase the pH of the solution. The amount of excess base added will determine the final pH of the solution after the equivalence point.
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Question 4 of 10
What effect does adding a solute have on the freezing point of a solution?
A. The solution will not reach a freezing point temperature.
B. The temperature at which the solution freezes is raised.
C. The temperature at which the solution freezes is lowered.
D. The temperature at which the solution freezes is unchanged.
Answers
Answer:
C. The temperature at which the solution freezes is lowered.
Please answer these. It's part of Quantitave Chemistry. Calculating limiting raegents
Answers
The limiting reactant refers to the reactant that is in small amount. The extent of the reaction depends on the amount of the limiting reactant.
What is limiting reactant?The term limiting reactant refers to the reactant that is in small amount, We shall now solve the questions individually.
1) The reaction equation is;
CaO + H2O → Ca(OH)2
Number of moles of CaO = 10 g/56 g/mol = 0.18 moles
Number of moles of H2O = 10 g/18 g/mol = 0.56
Since the reaction is 1:1, CaO is the limiting reactant
Mass of calcium hydroxide = 0.18 moles * 74 g/mol = 13.32 g
2) The reaction equation is;
Mg + Br2 → MgBr2
Number of moles of Mg = 1 g/24 g/mol = 0.042 moles
Number of moles of Br2= 5 g/160 g/mol = 0.031 moles
Since the reaction is 1:1, Br2 is the limiting reactant
Mass of MgBr2 = 0.031 moles * 184 g/mol = 5.7 g
3) The reaction equation is;
CuO + H2 → Cu + H2O
Number of moles of CuO= 2.00 g/80 g/mol = 0.025 moles
Number of moles of H2 = 1.00g/2 g/mol = 0.5 moles
Since the reaction is 1:1, CuO is the limiting reactant
Mass of Cu = 0.025 moles * 63.5 g/mol = 1.59 g
4) The reaction equation is;
2Na + F2 → 2NaF
Number of moles of Na = 2.30 g/23 g/mol = 0.10 moles
Number of moles of F2 = 2.85 g/38 g/mol = 0.075 moles
If 2 moles of Na react with 1 mole of F2
x moles of Na reacts with 0.075 moles of F2
x = 0.15
Hence Na is the limiting reactant
Mass of NaF = 0.10 moles * 42 g/mol = 4.2 g
5) The equation of the reaction is;
Fe2O3 + 2Al → 2Fe + Al2O3
Number of moles of Fe2O3 = 8.00 g/160 g/mol = 0.05 moles
Number of moles of Al = 2.16 g/27 g/mol = 0.08 moles
If 1 mole of Fe2O3 reacts with 2 mole of Al
x moles of Fe2O3 reacts with 0.08 moles of Al
x = 0.04 moles
Hence, Fe2O3 is the limiting reactant
1 mole of Fe2O3 yileds 2 moles of Fe
0.05 moles yileds 0.05 moles * 2 moles/1 mole = 0.1 moles
Mass of Fe = 0.1 moles * 56 g/mol = 5.6 g
6) The equation of the reaction is;
2Al + 3Cl2 → 2AlCl3
Number of moles of Al = 13.5 g/27 g/mol = 0.5 moles
Num ber of moles of Cl2 = 42.6 g /71 g/mol = 0.6 moles
If 2 moles of Al reacts with 3 moles of Cl2
x moles of Al reacts with 0.6 moles of Cl2
x = 0.4 moles
Al is the limiting reactant
Mass of AlCl3 = 0.4 moles * 133 g/mol = 53.2 g
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David has two yellow powders, Powder 1 and Powder 2. He collected data on some properties of these powders. His data are summarized in the table below. Which property CANNOT be used to determine whether the two powders are the same substance? Answer choices - a. mass b. density c. burns in air d. dissolves in water
Answers
The property that cannot be used to determine whether the two powders are the same substance is (d) dissolves in water.
The reason is that the ability to dissolve in water is not a unique property that can be used to identify a specific substance. Many different substances can dissolve in water, and the fact that both powders can dissolve in water does not necessarily mean they are the same substance.
On the other hand, properties such as mass, density, and the ability to burn in air can provide more specific information about the nature of the substance. Mass is a fundamental property that can be measured accurately, and if the two powders have the same mass, it suggests they may be the same substance. Density is a derived property that can also be measured and compared, providing information about the compactness of the material. The ability to burn in air indicates a chemical reactivity that can be used to distinguish between different substances.
Therefore, while properties like mass, density, and burning in air can provide valuable information for identifying substances, the property of dissolving in water alone is not sufficient to determine whether the two powders are the same substance.
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Isomers are molecules with the same molecular formula, but different structural formulae.
How many isomers are there in C7H16?
A.6
B.7
C.8
D.9
Answers
Answer:
D 9 is the answer
Explanation:
Hope it helps you
Please mark as brainliest answerAn object with a mass of 8.2 g raises the level of water in a graduated cylinder from 25.1 mL to 28.3 mL. What is the density of the object? g/mL
Answers
Answer:
The density is 2.5625g/mL. Hope this helped! :)
Explanation:
M= 8.2g D=M/V
V= 28.3-25.1=3.2mL
D=8.2g/3.2mL
D= 2.5625g/mL
Which of the following are characteristics of a temperate broadleaf forest? (Select all that apply.)
They contain mainly coniferous trees.
They experience all four seasons.
They can be found along the Atlantic coast of the United States.
They are very dry and receive little to no rainfall.
Answers
Answer:
They can be found along the Atlantic coast of the United States.
They experience all four seasons.
Explanation:
The characteristic of temperate broadleaf forests are they can be found along the Atlantic coast of the United States and experience all four seasons.
What is temperate broadleaf forest?As the name suggested that temperate broadleaf forests are those forests in which temperature througout the year is moderate and leaf of the tress are broad in shape.
As in that forest temperature is mild but that forest will experience all four seasons.Quality of soil of this forest is rich in minerals.Tress which are mostly present in this forests are oak, maple, beech, hickory, etc which are having broad leaves.They are generally found in central China and eastern North America, means along the Atlantic coast of the United States.Hence they can be found along the Atlantic coast of the United States and experience all four seasons are the characteristics of this forest.
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What is the total number of sulfur atoms in Mg2(SO4)3
Answers
AnswerElement Symbol # of Atoms
Magnesium Mg 1
Oxygen O 4
Sulfur S 1
:
Explanation:
Nitrogen dioxide, a major air pollutant, can be produced by the combustion of nitrogen oxide as shown.
2NO + O2 Right arrow. 2NO2
In a plant, 1,500 kg of nitrogen oxide is consumed per day to produce 1,500 kg of nitrogen dioxide per day. What is the percent yield?
Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100..
21.7%
32.6%
43.5%
65.2%
Answers
The percent yield for the production of nitrogen dioxide can be calculated using the formula: Percent yield = (actual yield / theoretical yield) x 100. In this case, the actual yield is given as 1,500 kg of nitrogen dioxide per day, and the theoretical yield can be determined based on the stoichiometry of the reaction.
From the balanced equation, we can see that the stoichiometric ratio between nitrogen oxide (NO) and nitrogen dioxide (NO2) is 2:2. Therefore, for every 2 moles of nitrogen oxide consumed, 2 moles of nitrogen dioxide are produced.
To calculate the theoretical yield, we need to convert the given mass of nitrogen oxide to moles. The molar mass of nitrogen oxide (NO) is 30 g/mol, so 1,500 kg is equal to 50,000 moles. Since the stoichiometric ratio is 2:2, the theoretical yield of nitrogen dioxide is also 50,000 moles.
Now we can calculate the percent yield:
Percent yield = (1,500 kg / 50,000 moles) x 100 = 3%
Therefore, the percent yield for the production of nitrogen dioxide is 3%. None of the given answer options match this result, so it seems there might be an error in the provided choices.
The given chemical equation represents the combustion of nitrogen oxide to produce nitrogen dioxide. According to the stoichiometry of the reaction, 2 moles of nitrogen oxide react with 1 mole of oxygen gas (O2) to produce 2 moles of nitrogen dioxide (NO2).
In the plant, it is stated that 1,500 kg of nitrogen oxide is consumed per day to produce an equal amount (1,500 kg) of nitrogen dioxide per day. To determine the percent yield, we need to compare the actual yield (1,500 kg) to the theoretical yield.
To calculate the theoretical yield, we need to convert the given mass of nitrogen oxide to moles. The molar mass of nitrogen oxide is calculated to be 30 g/mol. By dividing the mass of nitrogen oxide (1,500 kg) by its molar mass (30 g/mol), we find that there are 50,000 moles of nitrogen oxide consumed.
Since the stoichiometry of the reaction tells us that the ratio between nitrogen oxide and nitrogen dioxide is 2:2, the theoretical yield of nitrogen dioxide is also 50,000 moles.
Finally, we can calculate the percent yield using the formula: Percent yield = (actual yield / theoretical yield) x 100. Substituting the values, we get (1,500 kg / 50,000 moles) x 100 = 3%.
Therefore, the percent yield for the production of nitrogen dioxide in the given plant is 3%, which does not match any of the provided answer options.
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When ammonium chloride is dissolved in water, the beaker gets cold. Which type of reaction does this describe
O exothermic
O endothermic
O both exothermic and endothermic
O neither exothermic nor endothermic
Answers
Answer:
B
Explanation:
i think with exothermic reactions heat is released
this is what i looked up
hope this helps i took chem last year and think this is what i learned
Considering the definition of exothermic and endothermic reactions, the correct answer is second option: the reaction is endothermic.
Energy and chemical reactionsEnergy is the ability to do work or to produce heat.
Remembering that chemical reactions involve a reorganization of atoms between substances with breaking or formation of chemical bonds, this formation or breaking of chemical bonds is accompanied by changes in the energy of the system.
Exothermic reactionsChemical reactions that release heat are called exothermic. That is, an exothermic reaction is one where energy flows out of the system.
So, at room temperature, the heat released by a chemical reaction is enough to cause a rise in temperature.
Endothermic reactionsAn endothermic reaction is one that requires heat to take place. In other words, a chemical reaction is endothermic when it absorbs energy from the environment.
In this case, the heat is transferred from the outside to the inside of the system. By absorbing heat, the effect of an endothermic reaction is to lower the temperature.
This caseWhen ammonium chloride is dissolved in water, the beaker gets cold. That means the system is absorbing heat from the surrounding and the temperature does down.
So, the correct answer is second option: the reaction is endothermic.
Learn more about endothermic and exothermic reactions:
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