There was 1/3 of a box of cereal left four brothers shared it evenly write an equation to represent this problem

Answers

Answer 1

Answer:

1/12

Step-by-step explanation:

It is given that :

Amount of cereal left = 1/3 of a box

Number of people amongst whom the box of cereal is to be divided equally = 4

Therefore, an equation representing this problem is :

\($\frac{1/3}{4} = x$\)

where x = is the amount of the share each brother gets.

Therefore solving the equation, we get :

\($\frac{1/3}{4} = x$\)

\($\frac{1}{3} \times \frac{1}{4} = x$\)

\($\frac{1}{12}=x$\)

So, each brother got 1/12th of the cereal left.


Related Questions

3
5
+
2
3
=
whats the answer

Answers

Answer:

19/15 is the answer

A road is 8/9 of a mile long. A crew needs to replace 4/5 of the road how long is the section that needs to be repaved

Answers

Answer:

4/45

Step-by-step explanation:

8 - 4

9   5

=  8 × 5 - 4 × 9

       9 × 5   5 × 9

=  40 - 36

       45   45

=  40 – 36

            45

=  4

      45

8/9 - 4/5

= 4/45

What is Field variant vs invariant?

Answers

A field variant changes value with space or time transformation while an invariant field remains the same.

Field variant and invariant are terms used in mathematics and physics to describe how certain quantities or properties change or remain constant within a specific context.

A field variant is a quantity or property that changes when the system's parameters, such as location or time, are altered. For example, the temperature in a room may vary from one point to another, so it would be considered a field variant. In physics, electric and magnetic fields are often considered field variants, as their strength and direction can change depending on the observer's position.

On the other hand, a field invariant is a quantity or property that remains constant regardless of the system's parameters. In mathematics, a scalar quantity is often invariant, such as the length of a vector or the magnitude of a force. In physics, an example of a field invariant is the speed of light in a vacuum, which remains constant at approximately 299,792 kilometers per second, irrespective of the observer's position or motion.

In summary, field variants are properties that change with respect to a specific context, while field invariants remain constant. Understanding these concepts is essential for solving problems in mathematics, physics, and various scientific fields.

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When we subtract a velocity vector from another velocity vector, the result is:
A. an acceleration.
B. another velocity.
C. a scalar.
D. a displacement.

Answers

When we subtract a velocity vector from another velocity vector, the result is B. another velocity.

When we subtract a velocity vector from another velocity vector, we are essentially finding the difference between the two velocities. This difference is also a velocity vector, but in a different direction and with a different magnitude. Therefore, the answer is another velocity, option B.

It is important to note that acceleration is a change in velocity, not the result of subtracting one velocity from another. Scalar refers to a quantity with only magnitude, whereas velocity is a vector quantity with both magnitude and direction. Displacement refers to the change in position of an object and is not directly related to subtracting velocity vectors.

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Calculate the given quantity if
u = i + j − 2k v = 3i − 2j + k w = j − 5k
(a) 2u + 3v
(b) | u |
(c) u · v
(d) u × v
(e) | v × w |
(f) u · (v × w)
(g) The angle between u and v (rounded to the nearest degree)

Answers

The solutions for given vectors are: (a) 7i - 5j - 5k, (b) sqrt(6), (c) -1, (d) 7i - 7j - 7k, (e) 17, (f) -7i - 13j + 7k, (g) 91 degrees.

(a) 2u + 3v = 2(i + j - 2k) + 3(3i - 2j + k) = (2+9)i + (2-6)j + (-4+3)k = 11i - 4j - k

(b) |u| = sqrt(i^2 + j^2 + (-2k)^2) = sqrt(1+1+4) = sqrt(6)

(c) u · v = (i + j - 2k) · (3i - 2j + k) = 3i^2 - 2ij + ik + 3ij - 2j^2 - jk - 6k = 3 - 2j - 2k

(d) u × v = det(i j k; 1 1 -2; 3 -2 1) = i(2-5) - j(1+6) + k(-2+9) = -3i - 7j + 7k

(e) |v × w| = |(-2i - 16j - 13k)| = sqrt((-2)^2 + (-16)^2 + (-13)^2) = sqrt(484) = 22

(f) u · (v × w) = (i + j - 2k) · (-2i - 16j - 13k) = -2i^2 - 16ij - 13ik + 2ij + 16j^2 - 26jk - 4k = -2 - 10k

(g) The angle between u and v can be found using the dot product formula: cos(theta) = (u · v) / (|u||v|). Plugging in the values from parts (c) and (b), we get cos(theta) = (-1/3) / (sqrt(6) * sqrt(14)). Using a calculator, we find that theta is approximately 110 degrees.

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If an additional worker can produce an additional 20 units of output which can be sold for $4 per unit, what is the maximum wage that this perfectly competitive firm should pay to hire this worker?.

Answers

The maximum wage that this perfectly competitive firm should pay to hire this worker = $80

The options for this question

A) $80 minus the firm's profit markup

B) It depends on what the going wage rate is in the labor market.

C) $80

D) There is insufficient information to answer the question.

now, we need to find the maximum wage that this perfectly competitive firm should pay to hire this worker

given that

the additional worker can produce an additional 20 units of output and that can be sold for$4 per unit

maximum wage = additional units × sold per unit

                          = 20 × 4 = 80

the maximum wage = $80

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Please check the attached picture, please answer thoroughly!

Please check the attached picture, please answer thoroughly!

Answers

The selection depends on individual needs, preferences, and the intended use of the tiny house.

a) To find the amount of space inside each house, we need to calculate the volume for each design.

House on the left:

Volume = length x width x height = 2.5 m x 18 m x 2.8 m = 126 m³

Triangular house:

Volume of a triangular prism = (base area x height) / 2

Base area = (1/2) x base x height = (1/2) x 4 m x 10 m = 20 m²

Volume = (20 m² x 7 m) / 2 = 70 m³

b) When comparing the environmental impacts of each house, several factors need to be considered:

Positive impacts:

1. Material usage: Tiny houses use fewer materials, reducing resource consumption and waste generation.

2. Energy efficiency: Smaller living spaces require less energy for heating, cooling, and lighting, leading to lower energy consumption.

3. Land utilization: Tiny houses can be built on smaller plots of land, preserving green spaces and reducing urban sprawl.

Negative impacts:

1. Construction materials: Although tiny houses use less material overall, the environmental impact depends on the types of materials used. Sustainable and eco-friendly materials should be prioritized.

2. Water and waste management: Adequate provisions for water supply and waste disposal should be implemented to minimize environmental impacts.

3. Transportation: The transportation of tiny houses to their locations can contribute to carbon emissions if not done efficiently.

c) The choice of design for a tiny house depends on personal preferences and priorities. However, considering the provided information:

The house on the left offers a larger interior space of 126 m³, providing more room for living and storage. It may be suitable for individuals or couples who desire more space and functionality within their tiny house.

The triangular house has a smaller interior volume of 70 m³ but offers a unique design and aesthetic appeal. It may be preferred by individuals who prioritize a distinctive architectural style or who are looking for a minimalist and cozy living space.

Ultimately, the selection depends on individual needs, preferences, and the intended use of the tiny house. Factors such as lifestyle, desired amenities, and personal values regarding sustainability and resource conservation should be considered when making the final decision.

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Trichloroethylene (TCE, C₂HC13) is a well-known pollutant in soils and groundwater in many places, including Mountain View, CA. One major concern is that TCE volatilizing into the air in houses from the surrounding soil can cause unhealthful indoor concentrations. This so-called "vapor intrusion" is a common problem in this region. One report states that shallow groundwater concentrations of TCE of 110 ppm have been measured. The healthful standard for airborne TCE is 25 ppm (long-term exposure), and 200 ppm (short-term exposure)
Let's consider a one-story bungalow with area Ah =10 m x 10 m (about 1000 sq ft) and a ceiling h = 4 m high, and the vapor comes in only through the floor. In order to maintain the house at acceptable levels of TCE, we will use a fan to ventilate the house.
(a) If the groundwater is in equilibrium with air in your house, does this air exceed either health standard? The dimensionless Henry's Law Constant for TCE at 20°C is HT=0.4.
(b) The flux of TCE through the floor of your house can be given by FT = k(c+ - CT) where k is a measured constant with value 106 m/s that depends on things like the type of walls in your house, the porosity of the soil, etc.; ct is the equilibrium air concentration of TCE (from part a); and CT is the concentration of TCE in the air in the house. The normal strategy for remediating vapor intrusion is to install fans in the house that ventilate the house with outside air with a throughput of Q, in units of m³/hour. Assume that the outside ambient air has a TCE concentration of ca ("a" is for ambient). Write a budget equation for TCE, i.e. dct/dt =< stuff >. You do NOT have to integrate this equation!
(c) Using the budget equation from (b), what is the equation for the characteristic time 7 for TCE to build up in the house from zero to unhealthful (long-term exposure) if there is no ventilation? Then substitute numbers to compute a value for T. Is a large or small value of 7 indicative of a significant TCE problem? (d) Assuming we want to keep CT below 20 ppm, compute the minimum value of Q. Compare your answer to Q = 40 cfm (cubic feet per minute), which is the residential requirement by law.

Answers

(a) Yes, the air in the house would exceed the long-term health standard if the groundwater is in equilibrium with the air in the house.

(b) The budget equation for TCE is dct/dt = k(c+ - CT) - Q(ca - CT).

(c) The characteristic time t for TCE to build up in the house from zero to unhealthful (long-term exposure) if there is no ventilation is given by t = Ahk/Q. For the given values, t = 1.4 years. A large value of t indicates a significant TCE problem.

(d) The minimum value of Q to keep CT below 20 ppm is 160 cfm. This is more than the residential requirement of 40 cfm.

(a) The Henry's Law constant for TCE is 0.4, which means that the concentration of TCE in air at equilibrium with water is 40% of the concentration in water. The groundwater concentration is 110 ppm, so the equilibrium air concentration would be 44 ppm. This exceeds the long-term health standard of 25 ppm.

(b) The flux of TCE through the floor is given by FT = k(c+ - CT), where k is a measured constant, c+ is the concentration of TCE in the groundwater, and CT is the concentration of TCE in the air in the house. The normal strategy for remediating vapor intrusion is to install fans in the house that ventilate the house with outside air. The outside ambient air has a concentration of ca. The budget equation for TCE is dct/dt = k(c+ - CT) - Q(ca - CT), where dct/dt is the rate of change of the concentration of TCE in the house, k is the flux constant, c+ is the concentration of TCE in the groundwater, CT is the concentration of TCE in the air in the house, Q is the ventilation rate, and ca is the concentration of TCE in the outside air.

(c) The characteristic time t for TCE to build up in the house from zero to unhealthful (long-term exposure) if there is no ventilation is given by t = Ahk/Q, where Ah is the area of the house, k is the flux constant, and Q is the ventilation rate. For the given values, t = 1.4 years. A large value of t indicates a significant TCE problem.

(d) The minimum value of Q to keep CT below 20 ppm is 160 cfm. This is more than the residential requirement of 40 cfm. The difference is due to the fact that the groundwater concentration is much higher than the ambient air concentration.

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Write an equation of a line parallel to y = 2x - 1 that passes through the point (-3, 1)

Answers

The equation of the parallel line to y = 2x - 1, that passes through (-3, 1) is: y = 2x + 7.

How to Write the Equation of Parallel Lines?

Two lines that are parallel to each other would always have the same slope (m). In the slope-intercept form of the equation that represents a line, y = mx + b, the slope of the line is represented as "m", while the y-intercept is represented as b.

Given:

A point (-3, 1)

Equation, y = 2x - 1. The slope (m) = 2. Since parallel lines have the same slope (m), therefore, the line that passes through (-3, 1) also have a slope (m) = 2.

Substitute (x, y) = (-3, 1) and m = 2 into y = mx + b:

1 = 2(-3) + b

1 = -6 + b

1 + 6 = b

b = 7

To write the equation of the parallel line to y = 2x - 1, substitute m = 2 and b = 7 into y = mx + b:

y = 2x + 7.

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Given a set of data with mean of 12 and variance of 84. When each of the data is added with p and multiply with q, the new mean is 51 and the new variance is 756. Find the value of p and of q.​

Answers

Applying statistical concepts, it is found that the values are:

p = -11.37q = 81

When a constant is added to each data in a variable:

The mean is incremented by this constant.The variance remains constant.

When a constant is multiplied to each data in a variable:

The mean is multiplied by this constant.The variance is multiplied by the square of this constant

Hence, mean of 12, added with p and multiplied with q, for a mean of 51:

\((12 + p)q = 51\)

Variance of 84, after the operations, 756:

\(84\sqrt{q} =756\)

\(\sqrt{q} = \frac{756}{84}\)

\(\sqrt{q} = 9\)

\((\sqrt{q})^2 = 9^2\)

\(q = 81\)

For p:

\((12 + p)q = 51\)

\((12 + p)81 = 51\)

\(12 + p = \frac{51}{81}\)

\(12 + p = 0.63\)

\(p = -11.37\)

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Find the area of the square

Find the area of the square

Answers

Answer:

144

Step-by-step explanation:

225-81 because with pythagorean thorem both sides should equal the C value or the bigger square.

If the area of square 3 is 80 cm^2 and the area of square 2 is 100 cm^2, what is the area of square 1?
(please show work, it's a part of my study guide)

If the area of square 3 is 80 cm^2 and the area of square 2 is 100 cm^2, what is the area of square 1?(please

Answers

Answer:

1,025cm

Step-by-step explanation:

According to the Pythagoras theorem:

          a^2 + b^2 = c^2

a^2 = (Length of one side of square 3)^2

As, the are of a square = length of one side of the square^2,

then a^2 = area of square 3 = 80cm^2

and b^2 = area of square 2 = 100cm^2

Then, c^2 = a^2 + b^2 = 80 + 100 = 180cm^2

as c^2 ia also equal to the area of square 1,

Area of square 1 = 180cm^2

There are 12 finalists in a singing competition. The top four singers receive prizes. How many ways can the singers finish first through fourth?

Answers

See below for solution
There are 12 finalists in a singing competition. The top four singers receive prizes. How many ways can

Answer:665,280

Step-by-step explanation:

Formula for Permutations,

Consider the random process X(t) = B cos(at + θ), where a and B are constants, and θ is a uniformly distributed random variable on (0, 2phi) (14 points) a. Compute the mean and the autocorrelation function Rx, (t1, t₂) b. Is it a wide-sense stationary process? c. Compute the power spectral density Sx, (f) d. How much power is contained in X(t)?

Answers

a. Compute the mean and the autocorrelation function Rx (t1, t2):

The mean of a random process X(t) is given by:

\(\[\mu_X = E[X(t)] = E[B \cos (at + \theta)] = 0\]\)

since the expected value of the uniformly distributed random variable θ on (0, 2\pi) is 0.

The autocorrelation function Rx (t1, t2) of X(t) is given by:

\(\[R_X(t_1, t_2) = E[X(t_1)X(t_2)]\]\)

Substituting the expression for X(t) into the autocorrelation function:

\(\[R_X(t_1, t_2) = E[(B \cos(at_1 + \theta))(B \cos(at_2 + \theta))]\]\)

Expanding and applying trigonometric identities:

\(\[R_X(t_1, t_2) = \frac{B^2}{2} \cos(a t_1) \cos(a t_2) + \frac{B^2}{2} \sin(a t_1) \sin(a t_2)\]\)

The autocorrelation function is periodic with period T = \(\frac{2\pi}{a}.\)

b. Is it a wide-sense stationary process?

To determine if the process is wide-sense stationary, we need to check if the mean and autocorrelation function are time-invariant.

As we found earlier, the mean of X(t) is 0, which is constant.

The autocorrelation function depends on the time differences t1 and t2 but not on the absolute values of t1 and t2. Therefore, the autocorrelation function is time-invariant.

Since both the mean and autocorrelation function are time-invariant, the process is wide-sense stationary.

c. Compute the power spectral density Sx(f):

The power spectral density (PSD) of X(t) is the Fourier transform of the autocorrelation function Rx (t1, t2):

\(\[S_X(f) = \int_{-\infty}^{\infty} R_X(t_1, t_2) e^{-j2\pi ft_2} dt_2\]\)

Substituting the expression for the autocorrelation function:

\(\[S_X(f) = \int_{-\infty}^{\infty} \left(\frac{B^2}{2} \cos(a t_1) \cos(a t_2) + \frac{B^2}{2} \sin(a t_1) \sin(a t_2)\right) e^{-j2\pi ft_2} dt_2\]\)

Simplifying the integral:

\(\[S_X(f) = \frac{B^2}{2} \cos(a t_1) \int_{-\infty}^{\infty} \cos(a t_2) e^{-j2\pi ft_2} dt_2 + \frac{B^2}{2} \sin(a t_1) \int_{-\infty}^{\infty} \sin(a t_2) e^{-j2\pi ft_2} dt_2\]\)

Using the Fourier transform properties, we can evaluate the integrals:

\(\[S_X(f) = \frac{B^2}{2} \cos(a t_1) \delta(f - a) + \frac{B^2}{2} \sin(a t_1) \delta(f + a)\]\)

where δ(f) is the Dirac delta function.

d. How much power is contained in X(t)?

The power contained in a random process is given by integrating its power spectral density over all frequencies:

\(\[P_X = \int_{-\infty}^{\infty} S_X(f) df\]\)

Substituting the expression for the power spectral density:

\(\[P_X = \int_{-\infty}^{\infty} \left(\frac{B^2}{2} \cos(a t_1) \delta(f - a) + \frac{B^2}{2} \sin(a t_1) \delta(f + a)\right) df\]\)

Simplifying the integral:

\(\[P_X = \frac{B^2}{2} \cos(a t_1) + \frac{B^2}{2} \sin(a t_1)\]\)

Therefore, the power contained in X(t) is given by:

\(\[P_X = \frac{B^2}{2} (\cos(a t_1) + \sin(a t_1))\]\)

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A company manufactures a special type of sensor, and packs them in boxes of 4 for shipment. Then a new design increases the weight of each sensor by 9 grams. The new package of 4 sensors weighs 76 grams. How much did each sensor weigh originally?

Answers

As the firm develops a specific sort of sensor and ships them in boxes of four, each sensor weighed 10 grams at first.

What is equation?

In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign. A mathematical phrase with two equal sides separated by an equal sign is called an equation. An example of an equation is 4 + 6 = 10.

Here,

Let's call the original weight of each sensor "w". The total weight of 4 sensors would be 4w.

With the new design, each sensor weighs 9 grams more, so each sensor weighs w + 9 grams. The total weight of 4 sensors is 76 grams, so we can write an equation:

4(w + 9) = 76

Expanding the left-hand side and solving for w, we have:

4w + 36 = 76

4w = 40

w = 10

So each sensor originally weighed 10 grams as company manufactures a special type of sensor, and packs them in boxes of 4 for shipment.

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(1 ÷ 2 3 ⁄ 4 ) + (1 ÷ 3 1 ⁄ 2 ) = _____.

Answers

Answer:

50/77

Step-by-step explanation:

(1÷2 3/4)+(1÷3 1/2)

2 3/4 is same as 11/44

1/2 is same as 7/2

so to divide fraction you have to flip the second number and multiply

so 1 times 4/11=4/11

and 1 times 2/7=2/7

4/11 +2/7=28/77+22/77=50/77

A company needs to package 2,400 pencils. A box in the shape of a rectangular prism can hold 60 pencils. A cylindrical container can hold 80 pencils. Each box costs the company $0. 50, while each cylindrical container costs $0. 75. Which packaging should the company use to minimize cost? Explain. The rectangular prism boxes should be used because they will cost the company $2. 50 less than using the cylindrical containers. The cylindrical containers should be used because they will cost the company $2. 50 less than using the rectangular boxes. The rectangular prism boxes should be used because they will cost the company $5. 00 less than using the cylindrical containers. The cylindrical containers should be used because they will cost the company $5. 00 less than using the rectangular boxes.

Answers

The true statement is (a) The rectangular prism boxes should be used because they will cost the company $2. 50 less than using the cylindrical containers.

The given parameters are:

\(Pencils = 2400\) --- the pencils needed

The number of pencils the prism can hold is:

\(Prism =60\)

Divide the number of pencils needed by the number of pencils in 1 rectangular prism, to calculate the number of prisms needed (n1)

\(n_1 = \frac{Pencils}{Prism}\)

So, we have:

\(n_1 = \frac{2400}{60}\)

\(n_1 = 40\)

A rectangular prism costs $0.50.

So, the total cost is:

\(Total\ cost = 40 \times 0.50\)

\(Total\ cost = \$20\)

The number of pencils the cylinder can hold is:

\(Cylinder=80\)

Divide the number of pencils needed by the number of pencils in 1 cylinder box, to calculate the number of cylinders needed (n2)

\(n_2 = \frac{Pencils}{Cylinder}\)

So, we have:

\(n_2 = \frac{2400}{80}\)

\(n_2 = 30\)

A cylinder costs $0.75.

So, the total cost is:

\(Total\ cost = 30 \times 0.75\)

\(Total\ cost = $22.5\)

By comparison, the rectangular prism costs $2.5 less than the cylinder

Hence, the true statement is (a)

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enter the sum in the place -value chart? i ready

enter the sum in the place -value chart? i ready

Answers

Answer:

1.93

Step-by-step explanation:

  1

1.57

0.36

--------

1.93

Pls need help solving this.

Pls need help solving this.

Answers

Answer:

Step-by-step explanation:

Given: ABC is equilateral triangle.

AD = DB   & BE = EC   & CF = FA ------------(IV)

Proof:

  D & F are midpoint of the sides AB and AC

  DF = \(\frac{1}{2}BC\)            {Midpoint theorem}    

DF = BE     ----------------(I)

D & E are midpoint of the sides AB and BC

DE = \(\frac{1}{2}AC\)               {Midpoint theorem}      

DE = FA ----------------(II)

E & F are midpoint of the sides BC and AC

\(EF = \frac{1}{2}AB\)                  {Midpoint theorem}

EF = AD   ---------------(III)

From (I) ; (II) ; (III) ; (IV) ,

DF =  DE = EF

DEF is an  equilateral triangle.

The Point class represents x,y coordinates in a Cartesian plane. Which line of code appears completes this operator which transforms a Point by dx and dy? (Members written inline for this problem.) class Point { int x_{0}, y_{0};public: Point(int x, int y): x_{x}, y_{y} {} int x() const { return x_; } int y() const { return y_; }};Point operator+(int dx, int dy) { return _________________________;}

Answers

The correct line of code that completes this operator which transforms a Point by dx and dy is shown below: Point operator+(int dx, int dy) { return Point(x_+dx,y_+dy);}Note that the function operator+ takes two arguments: an integer dx and an integer dy.

The function returns a point, which is created by adding dx to x and dy to y.The completed code is shown below:class Point { int x_{0}, y_{0};public: Point(int x, int y): x_{x}, y_{y} {} int x() const { return x_; } int y() const { return y_; }};Point operator+(int dx, int dy) { return Point(x_+dx,y_+dy);}Therefore, the correct answer is: `Point(x_+dx,y_+dy)`

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A beverage distributor has a facility that bottles beer. Beer bottles are supposed to be filled to 12 oz but there are slight variations. As part of quality control, they randomly sample bottles of beer and measure how many ounces they contain. In the most recent sample, the found an average fill of 12.01 oz with a standard deviation of 0.89.
If one of the bottles of sampled beer was filled to 10.98 oz, what is its associated zscore?
Is this bottle an outlier?

Answers

The associated z score for filling to 10.98 oz. is -1.16.

Z score

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (x - μ) / σ

where x is the raw score, μ is the mean and σ is the standard deviation.

Given that μ = 12.01, σ = 0.89, hence:

For x = 10.98:

z = (10.98 - 12.01)/0.89 = -1.16

The associated z score for filling to 10.98 oz. is -1.16.

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Quadrilateral JKLM was dilated according to the rule DO, 1/2 (x,y) 1/2 x , 1/2, y to create the image quadrilateral J’k’L’M

Answers

The image quadrilateral J'k'L'M' is obtained by dilating quadrilateral JKLM according to the rule DO, where the x-coordinate of each vertex is halved and the y-coordinate is multiplied by 1/2.

A dilation is a transformation that changes the size of a figure while preserving its shape. In this case, the dilation rule DO states that the x-coordinate of each vertex is halved, and the y-coordinate is multiplied by 1/2.

Let's consider the coordinates of the vertices of quadrilateral JKLM: J(x₁, y₁), K(x₂, y₂), L(x₃, y₃), and M(x₄, y₄). Applying the dilation rule, we get the coordinates of the corresponding vertices of quadrilateral J'k'L'M':

J'(1/2x₁, 1/2y₁), k'(1/2x₂, 1/2y₂), L'(1/2x₃, 1/2y₃), and M'(1/2x₄, 1/2y₄).

Thus, each vertex of the original quadrilateral is transformed by halving the x-coordinate and multiplying the y-coordinate by 1/2. This results in the image quadrilateral J'k'L'M'.

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Find the arc length of AB if the
circumference of this circle is 187.

Find the arc length of AB if thecircumference of this circle is 187.

Answers

Answer:

π

Step-by-step explanation:

a circle contains 360° in total, so given it's circumference (lets say C),

the length of an arc with angle α is (α/360)*C
for our exanple, the length of arc AB, will be (20/360)*C
as C is given to be 18π cm, we can calculate:

Length(AB) = (20/360)*18π = π

Given the function f (x) = 3 (x – 5) + 8, which of the following represents f-1 (x)?

Answers

Given:

\(f(x)=3(x-5)+8\)

To find:

The inverse \(f^{-1}(x)\) of given function

Solution:

We have,

\(f(x)=3(x-5)+8\)

\(f(x)=3x-15+8\)

\(f(x)=3x-7\)

Put f(x)=y.

\(y=3x-7\)

Interchange x and y.

\(x=3y-7\)

Isolate y on one side.

\(x+7=3y\)

\(\dfrac{x+7}{3}=y\)

\(y=\dfrac{x+7}{3}\)

Put \(y=f^{-1}(x)\).

\(f^{-1}(x)=\dfrac{x+7}{3}\)

Therefore, the required inverse function is \(f^{-1}(x)=\dfrac{x+7}{3}\).

The inverse function of f(x) is \(f^{-1}(x) = 5 + \frac{x - 8}{3}\)

The function is given as:

\(f(x) = 3(x - 5) + 8\)

Replace f(x) with y

\(y = 3(x - 5) + 8\)

Swap the positions of x and y

\(x = 3(y - 5) + 8\)

Subtract 8 from both sides

\(x - 8= 3(y - 5)\)

Divide both sides by 3

\(\frac{x - 8}{3} = y - 5\)

Add 5 to both sides

\(5 + \frac{x - 8}{3} = y\)

Rewrite as:

\(y = 5 + \frac{x - 8}{3}\)

Replace y with the inverse function

\(f^{-1}(x) = 5 + \frac{x - 8}{3}\)

Hence, the inverse function of f(x) is \(f^{-1}(x) = 5 + \frac{x - 8}{3}\)

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x^2+6x-19=0 pls helpppp

Answers

Answer:

Step-by-step explanation:

Since this is not factorable, let's just complete the square:

\(x^2+6x=19\\x^2+6x+9=28\\(x+3)^2=28\\x+3=\sqrt{28}\\x=2\sqrt{7}-3\)

Rachel’s dog had 13 puppies. She gave away 5 pups. How many puppies did Rachel have left.

Answers

Answer:

8 puppies

Step-by-step explanation:

13-5=8

Answer: she had 8 pups left

Explanation: If Rachel's dog had 13 pups all you need to do is subtract 5 from 13 which is 8.

Hope this helps-

A pet store receives 7 boxes of car food. Each box has 48 cans. The store wants to put the cans in equal stacks of 8 cans. Draw a bar model to help you find how many stacks can be formed

Answers

We can form a total of 42 stacks of 8 cans each from the 7 boxes of cat food received by the pet store.

Now, We can use a bar model to represent the total number of cans and the number of stacks that can be formed.

First, let's find the total number of cans:

7 boxes x 48 cans/box = 336 cans

Now, let's use a bar model to represent this total:

| 336 cans of food  |

Next, we want to find how many stacks of 8 cans we can form. We can use a separate bar model to represent the size of each stack:

| 42 stacks of 8 cans each |

Hence, The number of stacks that can be formed, we need to divide the total number of cans by the number of cans in each stack:

336 cans ÷ 8 cans/stack = 42 stacks

So the final bar model looks like this:

| 336 cans of food  | = | 42 stacks of 8 cans each |

Therefore, we can form a total of 42 stacks of 8 cans each from the 7 boxes of cat food received by the pet store.

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In the parallelogram below, find the length of the segment GM.

In the parallelogram below, find the length of the segment GM.

Answers

Segment GM = 10, because GM is parallel to FE
The person above me is right ;)

Need in deed classrooms participate in great service learning projects! One classroom took 254 photos of their Saving Honeybees project. Another classroom took 15 times as many pictures of their Advocacy Project for Homeless Pets. How many photos did the Advocacy Project for Homeless Pets classroom take? Show or explain your work

Answers

Answer:

To solve the problem, we can use multiplication. We know that one classroom took 254 photos and the other classroom took 15 times as many pictures. So, we can write an equation to represent the situation:

Number of photos taken by Advocacy Project for Homeless Pets classroom = 254 x 15

We can then solve this equation using multiplication.

254 x 15 = 3810

Therefore, the Advocacy Project for Homeless Pets classroom took 3,810 photos.

given tannen's perspective on gender differences in communication, what would you expect to find regarding salary negotiation and gender

Answers

Given tannen's perspective on gender differences in communication,  Men far more than women negotiate for higher starting salaries because salary is a sign of status. So, correct option is C.

Based on Tannen's perspective on gender differences in communication, it is likely that you would find that men negotiate for higher starting salaries far more than women because salary is a sign of status.

Tannen argues that men are socialized to use language as a way to establish and maintain their status in society, and negotiating for a higher salary is one way for men to assert their status.

Women, on the other hand, are socialized to use language as a way to build and maintain relationships, and negotiating for a higher salary may be perceived as aggressive or confrontational, which goes against societal expectations for women's communication style.

Therefore, option (c) is the most likely answer.

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Complete question is:

Given tannen's perspective on gender differences in communication, what would you expect to find regarding salary negotiation and gender

answer choices:

a. Women negotiate for higher starting salaries far more than men because they wish to prove their worth

b. Men and women negotiate for higher starting salaries about equally

c. Men far more than women negotiate for higher starting salaries because salary is a sign of status

d. None of the above is true

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