The vertical distance is
. The horizontal distance is
. So the slope can be represented by the ratio
. The ordered pair for the red point on the line is
. If we substitute the numbers from the ordered pair in for x and y in the ratio, it will equal
please help ill give brainly
.

Answer:

a question with a single correct answer: non statistical

data that consists of numbers: numerical

a question that can have a variety of answers: statistical

Step-by-step explanation:

-

Answer:

b

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

We get that the radius is 3 ft and the length is 29 ft so the volume is

the approximate value is:

Answer:

True

Step-by-step explanation:

The left side  22  is equal to the right side  22 , which means that the given statement is always true.

Step-by-step explanation:

If we want to prove that x is equal to seven, we should first solve the equation for x so:

2x + 8 = 5x - 13

We should first add 13 on both sides and subtract 2x from both sides:

2x + 8 + 13 - 2x = 5x - 13 + 13 - 2x

21 = 3x

We can then divide both sides by 3 to get:

x = 7

a) To maximize its net savings, the company should use the new machine for 7 years.  b) The net savings during the first year of use of the machine are $405 (rounded off to the nearest dollar).  c) The net savings over the period determined in part a are $1,833.33 (rounded off to the nearest cent).

Step-by-step explanation: a) To determine for how many years should the company use the new machine to maximize its net savings, we need to find the value of x that maximizes the difference between the savings and the costs.To do this, we need to first calculate the net savings, N(x), which is given by:S'(x) - C'(x) = 175 - x² - (x² + 11x) = -2x² - 11x + 175To find the maximum value of N(x), we need to find the critical values, which are the values of x that make N'(x) = 0:N'(x) = -4x - 11 = 0 ⇒ x = -11/4The critical value x = -11/4 is not a valid solution because x represents the number of years of operation of the machine, which cannot be negative. (i.e., not use it at all).However, this answer does not make sense because the company would not introduce a new machine that it does not intend to use. Therefore, we need to examine the concavity of N(x) to see if there is a local maximum in the feasible interval.

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Using the Baye's Theorem,

the probability that the coin flipped ( 10 times) was the biased coin is 0.3..

We have given that

Two coins are available, one is fair and other one biased.

let us consider two events

F : a fair coin is flipped

B : a biased coin is flipped

Probability that biased coin comes up heads , P(H| biased) = 0.8

Probability that biased coin comes up tails, P(T|biased) = 0.2

Probability that fair coin comes up heads, P(H|F) = 1/2

Probability that fair coin comes up tails, P(T|F) = 1/2

One coin is selected at random and flips 10 times.

Results of 10 time flips are { H,T,T,H,H,T,H,H,T,H}

If flipped coin is biased ,

P(getting the 10 flips with biased coin)

= 0.8×0.2×0.2×0.8×0.8×0.2×0.8×0.8×0.2×0.8

= 0.86×0.24

P(getting the 10 flips with fair coin) = 0.5¹⁰

Using the Baye's Theorem,

P(A|B) = P(B|A)P(A)/P(B)

F and B both are independent events so P(FnB)

= 0

Probability (biased coin is used)= P(F) ×P(getting the 10 flips with biased coin) / [ P(F) ×P(getting the 10 flips with biased coin) + P(F) ×P(getting the 10 flips with fair coin)]

= 0.5 ×0.86×0.24 /(0.5 ×0.86×0.24 + 0.5 × 0.5¹⁰) = 0.3

Hence, the required probability is 0.3 ( round nearest tenth).

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Answer:

305.5 divided by 1/100= 3.055

When we have a normal model for the sampling distribution, we cannot say that a sample mean or sample proportion is approximately 2 standard errors (ses) away from the population mean or the true proportion.

Instead, we can say that 95% of the sample proportions fall within two standard errors of the population proportion. Similar to this, the percentage of sample proportions decreases as the standard error distance decreases and increases as the standard error distance increases.

Therefore, the standard error distance will be greater than 2 standard errors (ses) if 99% of the sample proportions are within a given standard error distance of the population proportion.

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The critical points of the function are (0, 0) and (3/4, -9/4), To classify the critical points, we need to examine the second partial derivatives of f(x, y) at each point

To find the critical points of the function f(x, y) = 8x^3 + y^2 + 6xy, we need to find the values of (x, y) where the partial derivatives with respect to x and y are equal to zero.

Taking the partial derivative with respect to x, we have:

∂f/∂x = 24x^2 + 6y = 0.

Taking the partial derivative with respect to y, we have:

∂f/∂y = 2y + 6x = 0.

Solving these two equations simultaneously, we get:

24x^2 + 6y = 0,

2y + 6x = 0.

From the second equation, we can solve for y in terms of x:

Y = -3x.

Substituting this into the first equation:

24x^2 + 6(-3x) = 0,

24x^2 – 18x = 0,

6x(4x – 3) = 0.

Therefore, we have two possibilities for x:

1. x = 0,

2. 4x – 3 = 0, which gives x = ¾.

Substituting these values back into y = -3x, we get the corresponding y-values:

1. x = 0 ⇒ y = 0,

2. x = ¾ ⇒ y = -9/4.

Hence, the critical points of the function are (0, 0) and (3/4, -9/4).

To classify the critical points, we need to examine the second partial derivatives of f(x, y) at each point. However, since the original function does not provide any information about the second partial derivatives, further analysis is required to classify the critical points.

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The equation of the osculating plane is 24x + 12√10(y-π) - 3z - 6π√10 = 0.

Given curve,  x=5sin(3t), y=t, z=5cos(3t); (0, π,-5).

To find the normal plane equation, the unit normal vector of the curve at the point must first be found. The unit tangent and unit binormal vectors are both derived from the unit tangent vector.

To calculate the tangent vector, the following steps are taken:

Equation of the curve is given as,

x=5sin(3t),

y=t,

z=5cos(3t).

Differentiating above equation with respect to t, we get;

dx/dt = 15 cos(3t)

dy/dt = 1

dz/dt = -15 sin(3t)

The unit tangent vector T is given by,

T = 1/√(dx/dt² + dy/dt² + dz/dt²) (dx/dt i + dy/dt j + dz/dt k)

Substituting the given values, we get

T = (3√10/10) i + (1/√10) j - (3/√10) k

Since we have to find the normal vector, we will differentiate the unit tangent vector,T, to get the unit normal vector N.

Let's differentiate T to obtain N:

dn/dt = 1/√(dx/dt² + dy/dt² + dz/dt²) [d²x/dt² i + d²y/dt² j + d²z/dt² k] + {(-1/2)(2t)(2t')/√(dx/dt² + dy/dt² + dz/dt²)³} [dx/dt i + dy/dt j + dz/dt k]

On substituting, we get,

N = (-9/√10) i + (3√10/10) j + (9/√10) k

Therefore, the normal plane equation is given by,(-9/√10)(x) + (3√10/10)(y-π) + (9/√10)(z+5) = 0.

To find the osculating plane equation, the coordinates of the point of tangency (P) and the principal normal vector, N, are required.

The equation of the osculating plane is then written as follows:

xT + yN = c,

where c is a constant value that is calculated by substituting the coordinates of P into the equation.Let us calculate the value of P and N,

To find the value of P, we substitute t=π in the given curve,

Thus,

x(π) = 5sin(3π) = 0,y(π) = π,z(π) = 5cos(3π) = -5

Therefore, the point of tangency P is (0, π, -5).

From the above derivation, we know that the unit normal vector N is(-9/√10) i + (3√10/10) j + (9/√10) k

Therefore, the unit principal normal vector is given by,

B = T x N= [(3√10/10) i + (1/√10) j - (3/√10) k] x [- (9/√10) i + (3√10/10) j + (9/√10) k]

= [(3√10/10) (9/√10) + (3/√10) (3/√10)] i + [(9/√10) (1/√10) - (3√10/10) (- 3/√10)] j + [(1/√10) (- 3/√10) - (3√10/10) (3√10/10)] k

= (24/√10) i + (12√10/10) j - (3/√10) k

The osculating plane equation is given by,

xT + yB = c

Now substituting x=0, y=π and z=-5 in above equation, we get

c = π(12√10/10) = (6π√10/5)

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The conditional probability that the outcome of the coin toss was heads can be calculated using Bayes' theorem. The conditional probability that the outcome of the toss was heads given that a white ball was selected is 26/63.

Let's denote H as the event that the outcome of the coin toss was heads, and W as the event that a white ball was selected. We want to find P(H|W), the probability of the coin toss being heads given that a white ball was selected.

According to Bayes' theorem, we have:

P(H|W) = P(W|H) * P(H) / P(W)

P(W|H) is the probability of selecting a white ball given that the outcome of the coin toss was headed. Since the first mug is chosen in this case, which contains two white balls out of a total of nine balls, P(W|H) = 2/9.

P(H) is the probability of the coin toss being heads, which is 1/2 since the coin is fair.

P(W) is the probability of selecting a white ball, regardless of the outcome of the coin toss. There are a total of seven white balls out of thirteen balls (two from the first mug and five from the second mug), so P(W) = 7/13.

Therefore, substituting these values into Bayes' theorem:

P(H|W) = (2/9) * (1/2) / (7/13)

Simplifying this expression:

P(H|W) = 26/63

Therefore, the conditional probability that the outcome of the toss was heads given that a white ball was selected is 26/63.

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The empirical method is the right answer.

Empirical probability is calculated by dividing the number of times an event was seen in your data by the entire sample size. An event's relative frequency is strongly connected to an empirical probability, also known as an experimental probability.

Empirical probability bases its estimation of the likelihood that a specific result will recur on the number of instances of that outcome within a sample set. In short, the empirical method uses relative frequencies to determine probabilities.

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Answer:

3

Step-by-step explanation:

Answer:1.5

Step-by-step explanation:

to answer this you need to create a triangle reasonable and esaily readable

do rise over run so 3/2 or 6/4 or 9/6 I think u get the idea

the answer is 3/2 in fraction in simplest form and 1.5 in integer form

PLS give me brainliest

Answer:

Since there are 320 students, and Preston expects 0.5% of them to be from Australia, the expected count of students from Australia is 0.005 (320) =1.6

The expected count students from Australia is 1.6.

Step-by-step explanation:

The expected count of students from Australia in Preston's group is equal to 1.6.

A goodness-of-fit test can be defined as a statistical tool that is used to test if sample data fits into a set of observations or distribution from a given population.

This ultimately implies that, a goodness-of-fit test helps to determine whether on not sample data represents the data that are expected in an actual population.

Given the followin data:

Popuation = 320 students.

Expected percent (Preston's group) = 0.5% = 0.005.

Expect count = 0.005 × 320

Expect count = 1.6.

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Answer:

7

Step-by-step explanation:

The output is 'y'. The input would be 'x'.

\(y=x+3\\\\y=4+3\\\\y=7\)

The output should be 7.

Hope this helps.

The output for the function y=x + 3 at input x = 4  will be y = 7.

The expression that established the relationship between the dependent variable and independent variable is referred to as a function. In the function as the value of the independent variable varies the value of the dependent variable also varies.

Given the function is  y=x + 3. the value of the output at input x = 4 will be calculated as:-

y = x + 3

Put x = 4 in the function.

y = 4 + 3

y = 7

Therefore, the output for the function y=x + 3 at input x = 4  will be y = 7.

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Answer:

The second one

Step-by-step explanation:

It is the only one that was moved but without turning, which is what translating a figure is.

Answer:

That's wrong, its C

Step-by-step explanation:

Answer:

I think it might be the last answer

Step-by-step explanation:

sorry just tryna help ok dokie

Answer:

yaaa last one

Step-by-step explanation:

The equation in function form is f(x)=-4x+80.

What is linear function?

A linear function is a function which forms a straight line in a graph. It is generally a polynomial function whose degree is utmost 1 or 0.

We can find the equation in function form as shown below:

We have given two points (5,60) and (10,40)

Slope of line

m = (40-60)/ (10-5)

m=-20/5

m=-4

Equation in slope intercept form

(y-y1) =m(x-x1)

(y-60) =-4(x-5)

y-60=-4x+20

y=-4x+20+60

y=-4x+80

y=f(x)

f(x)=-4x+80

Hence, the equation in function form is f(x)=-4x+80.

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Answer/Step-by-step explanation:

Common ratio of a sequence can be gotten by dividing any of the consecutive term in a sequence, by the term before it.

Thus,

For the sequence, \( 3, 9, 27. . . \) : \( a_1 = 3 \)

\( r = \frac{9}{3} = 3 \)

For the sequence, \( 8, 4, 2, 1. . . \) : \( a_1 = 8 \)

\( r = \frac{4}{8} = \frac{1}{2} \)

For the sequence, \( -16, 64, -256 . . \) : \( a_1 = -16 \)

\( r = \frac{64}{-16} = -4 \)

Therefore, the future value of a three-year uneven cash flow given below, using an 11% discount rate is $1,238.82.

To calculate the future value of a three-year uneven cash flow given below, using an 11% discount rate, we need to use the formula;

Future value of uneven cash flow = cash flow at year 1/(1+discount rate)¹ + cash flow at year 2/(1+discount rate)² + cash flow at year 3/(1+discount rate)³ + cash flow at year 4/(1+discount rate)⁴

Given the cash flows;

Year 0: $0

Year 1: $600

Year 2: $500

Year 3: $400

Then the Future value of uneven cash flow

= $600/(1+0.11)¹ + $500/(1+0.11)² + $400/(1+0.11)³

= $600/1.11 + $500/1.23 + $400/1.36

=$540.54 + $405.28 + $293.00

=$1,238.82

Therefore, the future value of a three-year uneven cash flow given below, using an 11% discount rate is $1,238.82.

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SOLUTION

Let's look at the graphical solution of the pair of simultaneous equations

From the graph, we can see that the equations have at least one solution, which are 2.556, and -0.333. Hence, it is said to be consistent.

Now, since the solutions intersect only at one place, it means that it has exactly one solution. If a consistent equation has exactly one solution, it is said to be independent.

Therefore, the systems of equations are consistent and independent

Answer:

3

Step-by-step explanation:

44x^2 + 20x + 4
44x^2 is a term
20x is a term
4 is a term

Answer:

3 terms

Step-by-step explanation:

There are 3 terms

Terms are separated with addition or subtraction signs.

Hope this helps and goodluck!

Answer:

approximately 43 - 44 minutes exact

Answer:

It would take you 2917 hours.

Step-by-step explanation:

Do 777,777,777 divided by 266,560.

I hope this helped at all.

Answer:

We could use 'd' as a variable to represent distance. And since distance is the most important thing in this question, the most important variable would be 'd'.

Is this what you were asking?

I hope I could help. (๑•～•)

The probability that an endure all battery selected at random will last more than 610 hours is 0.3%

What is the Z score?

A Z-score is a metric that quantifies how closely a value relates to the mean of a set of values. Standard deviations from the mean are used to measure Z-score. If a Z-score is 0, it indicates that the data point's score is identical to the mean score.

Z score is used to determine by how many standard deviations the raw score is above or below the mean, The z score is given by:

\(z = \frac{x - \mu}{\sigma}\)

where,

x = raw score

μ = mean

σ = standard deviation

Given that μ = 500, σ = 40, for x > 610:

z = (610 - 500) / 40

= 2.75

From the normal distribution table, P(z > 2.75) = 1 - P(z < 2.75) = 1 - 0.9970 = 0.0030 = 0.3%

Hence, the probability that an endure all battery selected at random will last more than 610 hours is 0.3%

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We have:

ab = bc (hypothetical)

so the triangle ABC is isosceles at B

we have: bd is the height of the triangle ABC, so BD is perpendicular to AB

Consider the triangle ABD and the right triangle ACD have:

AB = BC (hypothesis)

BD is the common edge

So the triangle ABD = triangle ACD (hypotenuse - acute angle)

hence the angle ABD = angle ACD

The probability that a claim amount is less than or equal to 4, given that it follows a gamma distribution with a mean of 6 and variance of 12, can be calculated using the cumulative distribution function (CDF) of the gamma distribution.

The gamma distribution is a continuous probability distribution with two parameters: shape parameter (k) and scale parameter (θ). In this case, we are given the mean and variance of the gamma distribution, which can be related to the shape and scale parameters as follows:

Mean (μ) = kθ

Variance (σ²) = kθ²

From the given information, we have μ = 6 and σ² = 12. To find the parameters k and θ, we solve the above equations simultaneously:

6 = kθ

12 = kθ²

Dividing the second equation by the first equation, we get:

2 = θ

Substituting this value back into the first equation, we find:

6 = k * 2

k = 3

So, the parameters for the gamma distribution are k = 3 and θ = 2.

Now, we can use the CDF of the gamma distribution to calculate the probability that a claim amount is less than or equal to 4:

P(x ≤ 4) = CDF(4; k, θ)

By evaluating this expression using the values of k and θ we obtained, we can find the desired probability.

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