The value of pie upto 35 decimal places is given below: 3.1415926......

Answer:

y = 35x - 517.

Step-by-step explanation:

y=35x−7

This line has a slope of 35so we can write a line parallel to it as

y - y1 = 35(x - x1) where (x1, y1) is a point on the line.

We are given this point (15, 8), so:

y - 8 = 35(x - 15)

y = 35x - 525 + 8

y = 35x - 517  is the required equation.

It aids in comprehending measurements when the data is scattered, standard deviation is significant. The standard deviation of the data will be higher the more evenly dispersed the data is.

Although the standard deviation is a frequently used statistic, it rarely receives the attention it merits. Although the mean and median are frequently mentioned in the news, they are rarely accompanied by any indication of how diverse the underlying data set was, so you only get a partial picture. In actuality, you might be overlooking the most captivating aspect of the tale.

What is Standard deviation?

A statistic known as the standard deviation is used to describe how volatile or dispersed a group of numerical values is. While a big standard deviation denotes that the values are scattered across a wider range, a low standard deviation indicates that the values tend to be close to the set mean.

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The equation of the line with slope m and y-intercept b is given by:

In this case the slope is 5 and the y-intercept is -2; then we have that the equation of the line is:

Now that we have the equation of the line we can use it to find points on the line, we do that by given values to x (whichever values we want) and use the equation to determine its corresponding y value.

If x=0, then we have:

Hence, the line passes through the point (0,-2).

If x=1, then we have:

Hence, the line passes through the point (1,3).

Now that we have two points on the line we graph them on the plane:

Finally, we join the points with a straight line. Therefore, the graph of the line is:

True, The range of a linear transformation defined by the matrix transformation t(x) = Ax is equal to the column space of matrix A.


The range of a linear transformation defined by the matrix transformation t(x) = ax is equal to the column space of matrix A (col A).

The range of a linear transformation is the set of all possible output values. In this case, the matrix A represents the transformation, and the column space of matrix A represents the span of the columns of A. The column space of matrix A is the set of all possible linear combinations of the columns of A.

To prove that the range of the linear transformation t(x) = Ax is equal to the column space of matrix A, we can show that every vector in the column space of A can be obtained as an output of the transformation t(x) = Ax. Additionally, we can show that every output of the transformation t(x) = Ax belongs to the column space of A.


Therefore, it is true that the range of a linear transformation defined by the matrix transformation t(x) = Ax is equal to the column space of matrix A.

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Option fourth ''Table B, because the given condition is that the student is taking a foreign language" is correct.

It is defined as the frequency that can be evaluated by the two-way frequency table. Usually, we can obtain this frequency by dividing the frequency that is not in the total frequency cell by the total frequency.

We have two tables given in the question.

The conditional relative frequency tables show the results of a survey asking students whether they are taking a foreign language or not.

The condition is: "Assuming a student is taking a foreign language"

Table B can be used to answer the above statement.

Thus, option fourth ''Table B, because the given condition is that the student is taking a foreign language" is correct.

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Answer:

Option b: Table A, because the given condition is that the student is taking a foreign language.

Step-by-step explanation:

on ed

Sorry for bad handwriting

if i was helpful Brainliests my answer ^_^

Given a quadrilateral ABCD, with the sides AB and DC parallel and equal in length. Let us denote angle BAD as ∠α and angle ADC as ∠β. Now, we have to find the values of the variables x and y such that ABCD is a parallelogram.

Parallelogram has a pair of parallel sides. So, we have AB ∥ CD. It is given that ∠α = ∠β and AB = CD. So, by angle-angle-side rule, the two triangles ABD and DCA are congruent.

In triangle ABD, we have:∠DAB = 180° - ∠α = 180° - ∠β (as ∠α = ∠β)⇒ ∠DAB + ∠CDA = 180° (linear pair of angles)⇒ ∠CDA = ∠β.In triangle DCA, we have:∠CDA = ∠β (as obtained above)⇒ ∠CAD = ∠α (as ∠α = ∠β)⇒ ∠BDC = 180° - ∠α = 180° - ∠β (linear pair of angles)⇒ ∠BDC = ∠DAB.In quadrilateral ABCD, the adjacent angles are supplementary. So, we have:∠BDC + ∠BCD = 180° (adjacent angles are supplementary)⇒ ∠DAB + ∠BCD = 180° (as ∠BDC = ∠DAB)⇒ ∠BCD = 180° - ∠DAB.In triangle ACD, we have:∠C = ∠C (common)⇒ ∠CAD + ∠BCD = 180° (angles of a triangle add up to 180°)⇒ ∠α + (180° - ∠DAB) = 180°⇒ ∠α + ∠β = 180°.

Now, we can solve for x and y.In triangle ABD, we have:AB = BD⇒ 3x = 21 - x⇒ 4x = 21⇒ x = 21/4.In triangle DCA, we have:CD = DA⇒ 3y = 22 - y⇒ 4y = 22⇒ y = 11/2. Therefore, the value of x is 21/4 and the value of y is 11/2.

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Looking at this figure, we can see it has 4 sides, so it is a quadrilateral.

All sides have different sizes, and there are no parallel sides.

So the only description we can use is quadrilateral.

Therefore the only option that applies is B.

The  critical value that should be used in constructing the confidence interval is 1.764≤μ≤2.636

The given parameters to help us understand this are

The sample size = 19

The sample mean is 1.4

The sample standard deviation is 0.7

The confidence level = 90% = 0.90

The level of significance  = 0.10

The degree of freedom

Df= n-1

The critical value of t using TINV(0.10.11) is

Critₓ = α/2 d.f

t= (0.5,11) = ±1.76

The confidence interval μ = 1.4 ± [(1.796)(0.70)]/√19

Therefore this is equal to 0.76≤μ≤0.04

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When m and n are integers such that 6<m<n, the value of n is 18.

In mathematics, multiples are the results of multiplying a given number by an integer. Manifold is the basic definition of multiplicity. A multiple is defined in mathematics as the product of one integer multiplied by another number. A multiple of a number is just the product of that number and another non-zero whole number. For instance, 12 is the sum of 2 and 6. 2 and 6 are both non-zero whole numbers.

Here,

We know this because statement 2 tells us that 36 is a multiple of N.

So, let's first list all pairs of values that satisfy statement 2 (as well as the given information):

i) M = 12 and N = 36

ii) M = 18 and N = 36

iii) M = 12 and N = 18

That's it!!

Among these three possible pairs of values, only one pair satisfies statement 1: M = 12 and N = 18

Since it must be the case that M = 12 and N = 18, the target question is N = 18

The value of n is 18 when m and n are integers such that 6<m<n.

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Answer: in2

Step-by-step explanation:

answerd

Answer:

So, the prime factors of 6 are written as 2 × 3, where 2 and 3 are prime numbers. It is possible to find the exact number of factors with the help of prime factorisation. The prime factor of the 6 is 2 x 3. The exponent in the prime factorisation is 1 and 1.

:-))

Answer:

Factors of 6: 1, 2, 3, 6. Prime factorization: 2 x 3.

Step-by-step explanation:

The standard deviation of this binomial distribution is 4

The given parameters are:

The standard deviation is calculated using:

\(\sigma = \sqrt{np(1 - p)\)

So, we have:

\(\sigma = \sqrt{100 * 20\% * (1 - 20\%)\)

Evaluate

\(\sigma = 4\)

Hence, the standard deviation of this binomial distribution is 4

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Answer:

inbox I think maybe I can help

Answer:

5m

Step-by-step explanation:

there are 5 m with each a coefficient of one

Answer:

the answer is 10

Step-by-step explanation:

plz mark brainliest

Answer:

-80

Step-by-step explanation:

Pemdas method.

Answer:

I have given two pictures for some visual clarity.

Hopefully my answer will help you.

12) line TQ and line QT are same because both the lines have the same points Q and T and we know that only one line can pass through two points. Hence, the statement is true.

13) Ray JK and ray JL are not the same ray because, although the two rays have a common vertices J they have two different points K and L due to which there exists two different rays that pass through points J and K and through points J and L. Hence the above statement is false.

14) Intersecting lines are coplanar since they always intersect on the same plane. The statement is true.

15) Obviously, four points are coplanar if they exist and lie on the same plane. The statement is true.

16) No, a plane containing two points of a line doesn't contains the entire line because a line doesn't have any end as it keeps on extending in two directions on the plane it lies. Two points can only contain a part of the line also known as line segment. The statement is false.

17) No, two distinct lines can't intersect on more than two one point. If the lines intersect at more than one point then they will become coincident lines(lines which lie on each other).

As the statement says that the lines are distinct, therefore the two lines can't intersect on more than two points. The statement is false.

The probability distribution of X is 0.5, 0.25, 0.25, and 0.125. Mean value ∑ X × P (X) = 1.875. Standard Deviation of X = 1.0533

a) For a fair coin,

P(H) = P(T) = 0.5

Outcome  X                            Probability

T                  1                                  0.5

HT              2                       0.5×0.5 = 0.25

HHT          3                       0.5×0.5×0.5 = 0.125

HHHT          4                           0.5×0.5×0.5×0.5 = 0.0625

HHHH          4                           0.5×0.5×0.5×0.5 = 0.0625

So, probability distribution of X is

X P(X)

1 0.5

2 0.25

3 0.125

4 0.0625+0.0625 = 0.125

b)

X     P(X)    X×P(X)         X2×P(X)

1     0.5     0.5          0.5

2     0.25      0.5               1

3     0.125    0.375         1.125

4     0.125       0.5            2

sum 1     E(X) = 1.87

c) Variance = E(X²) - E(X)²

= 4.625 - 1.875²

= 1.1094

Standard Deviation of X = √ Variance

= √1.1094

= 1.0533

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Answer:

a) Expected value = 50b.

b) Probability = 0.4c.

c) Probability that the game would take longer than 40 minutes is 0.2.

Let's discuss it further below.

In this question, we are given that the time required to play a certain game is uniformly distributed between 25 and 45 minutes. We are asked to find the expected value and variance of the time to complete the game, the probability of finishing within 33 minutes, and the probability that the game would take longer than 40 minutes.

a) To find the expected value and variance of the time to complete the game, we can use the following formulas:

Expected value = (minimum value + maximum value) / 2Variance = [(maximum value - minimum value)²] / 12

Using these formulas, we can calculate:

Expected value = (25 + 45) / 2 = 35Variance = [(45 - 25)²] / 12 = 50b.

b) To find the probability of finishing within 33 minutes, we can use the formula for a uniform distribution:

Probability = (x - minimum value) / (maximum value - minimum value)

Plugging in the values we know, we get:

Probability = (33 - 25) / (45 - 25) = 0.4c.

c) To find the probability that the game would take longer than 40 minutes, we can use the same formula as in part b, but with a different value for x:

Probability = (45 - 40) / (45 - 25) = 0.2

Therefore, the probability that the game would take longer than 40 minutes is 0.2.

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Answer: 6.75 cc

Step-by-step explanation:

The c is equal to half of the definite integral of the function over the interval [0, 2].

To determine c such that f(c) is the average value of the function on the interval [0, 2], we can use the formula for the average value of a function:

avg = 1/(b-a) * ∫(a to b) f(x) dx

In this case, a = 0 and b = 2, so the formula becomes:

avg = 1/2 * ∫(0 to 2) f(x) dx

We want to find the value of c such that f(c) = avg, so we can set these two expressions equal to each other and solve for c:

f(c) = avg
f(c) = 1/2 * ∫(0 to 2) f(x) dx

We can then use calculus to solve for c by finding the derivative of both sides with respect to c and setting them equal to each other:

f'(c) = 1/2 * (f(2) - f(0))

Solving for c gives us:

c = (1/2) * ∫(0 to 2) f(x) dx

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Answer:

Wrong values are plotted in the question statement graph.

Please find correct graph.

Step-by-step explanation:

Given that:

\(y =x+3\) and \(-1<x<5\)

i.e. we can put a value of x in the equation which is greater than -1 and lesser than 5.

OR

we can say, the points where x = -1 and x = 5 will not be included in the graph (they will be shown as hollow circle).

Now, let us put the values one by one:

x = -1, y = -1 + 3 =2

x = 0, y = 0 + 3 = 3

x = 1, y = 1 + 3 = 4

x = 2, y = 2 + 3 = 5

x = 3, y = 3 + 3 = 6

x = 4, y = 4 + 3 = 7

x = 5, y = 5 + 3 = 8

Therefore, the table of values become:

\(\begin{center}\begin{tabular}{ c c } x & y\\ -1 & 2\\ 0 & 3 \\ 1 & 4 \\ 2 & 5 \\ 3 & 6 \\ 4 & 7 \\5 & 8\\\end{tabular}\end{center}\)

Points (-1, 2) and (5, 8) will not be included in the graph.

Please find attached corrected graph.

Answer:

338.5

Step-by-step explanation:

5(7.3×9+2)

5(65.7×2)

5×67.7

338.5

Answer:

Step-by-step explanation:

__________________________________________________________

\(5\cdot\left(\left(3.14+4.16\right)\cdot9+2\right)\) = \(?\)

\(5\cdot\left(\left(7.3\right)\cdot9+2\right)\) = \(?\)

\(5\cdot\left(65.7+2\right)\) = \(?\)

\(5\cdot\left(67.7\right)\) = \(?\)

\(338.5\)

__________________________________________________________

Hope this helps! <3

__________________________________________________________

Answer:

5.6km

Step-by-step explanation:

1km = 1000 meters

5,600 meters = 5.6km

5600 divided by 1000 = 5.6km

So, Chen walked 5.6km today.