The three states of matter most common on Earth are solids, liquids, and gases. Which sequence the states order from least particle motion to most?

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question we have

mass = 5 × 50

We have the final answer as

Hope this helps you

The mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur .

The molecular formula of Aluminum Sulfate is \(Al_2(SO_4)_3.\) In one molecule of aluminum sulfate, there are 3 sulfur atoms. To calculate the mass of aluminum sulfate, follow the steps below:

Step 1: Calculate the molar mass of aluminum sulfate using the periodic table.Al = 27.0 g/molS = 32.1 g/molO = 16.0 g/mol

(2 × Al) + (3 × S) + (12 × O) = molar mass of \(Al_2(SO_4)_3.\) = 342.2 g/mol

Step 2: Find the number of moles of sulfur in the given number of atoms of sulfur.2\(2.837*10^{26\) atoms of sulfur × 1 mol S/\(6.022 * 10^{23\)atoms S = 0.0470 mol S

Step 3: Use the molar ratio of sulfur to aluminum sulfate to calculate the number of moles of aluminum sulfate.1 mol \(Al_2(SO_4)_3.\) / 3 mol S = 0.333 mol\(Al_2(SO_4)_3.\) per mol S0.0470 mol S × 0.333 mol \(Al_2(SO_4)_3.\)/mol S = 0.0157 mol \(Al_2(SO_4)_3.\)

Step 4: Calculate the mass of aluminum sulfate.0.0157 mol \(Al_2(SO_4)_3.\) × 342.2 g/mol\(Al_2(SO_4)_3.\)= 5.373 g\(Al_2(SO_4)_3.\)

Therefore, the mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur.

Know more about  aluminum sulfate   here:

https://brainly.com/question/28299913

#SPJ8

Answer: Shown below

Explanation:

CaCl2=calcium chloride

Mg(NO3)2=Magnesium nitrate

ZaCl2=Zinc Chloride

NH2Cl=Chloramine

AgNO2=Silver nitrate

NaCl= Sodium chloride

KI=Potassium iodide

PbSO4=Lead(II) Sulfate

n82CO3=Sodium carbonate

KNO3=Potassium nitrate

N82SO4=Sodium Sulfate.

I hope this helped please give Brainliest!

The name of the compounds and the involved ion are as follows;

Ionic compound is any of a large group of chemical compounds consisting of oppositely charged ions, wherein electron transfer, or ionic bonding, holds the atoms together.

Ionic compounds, when in an aqueous solution, dissociates into its respective ions. This question gives the chemical formula of certain compounds. For example, the sodium ions attract chloride ions and the chloride ion attracts sodium ions. The result is a three-dimensional structure of alternate Na⁺ and Cl⁻ ions.

The names of the chemical compound and the ionic elements that make them up are given in the main answer part.

Learn more about ionic compounds at: https://brainly.com/question/9167977

#SPJ1

Answer:

Ka = 4.70x10⁻⁴M

Explanation:

The general dissociation of a weak acid, HX, is:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

And Ka is written as:

Ka = [H⁺] [X⁻] / [HX]

Where [] represents the molar concentration in equilibrium of each specie.

The equilibrium is reached when X of HX is dissociate in X H⁺ and X X⁻, that is:

[HX] = 0.0129M - X

[H⁺] = X

[X⁻] = X

As pH = -log [H⁺]:

10^-pH = [H⁺] = X  = 2.239x10⁻³M

Solving:

[HX] = 0.0129M - 2.239x10⁻³M = 0.01066M

[H⁺] = 2.239x10⁻³M

[X⁻] = 2.239x10⁻³M

Ka = [H⁺] [X⁻] / [HX]

Ka = [2.239x10⁻³M] [2.239x10⁻³M] / [0.01066M]

KH2PO4 is a more suitable choice as a buffer because it has a greater buffering capacity due to the presence of the weak acid and its conjugate base.

KHPo4 is not considered an effective buffer compared to KH2PO4 due to its limited buffering capacity. The effectiveness of a buffer is determined by the concentration and dissociation properties of its conjugate acid-base pair.

KH2PO4 is a salt composed of the weak acid H2PO4- and its conjugate base HPO4^2-. In an aqueous solution, KH2PO4 can dissociate to release H+ ions from the H2PO4- component, which acts as a weak acid, and the HPO4^2- component can accept H+ ions, acting as a weak base. This allows KH2PO4 to effectively resist changes in pH when small amounts of acid or base are added to the solution.

On the other hand, KHPo4 consists of the strong acid H3PO4 and the weak base HPO4^2-. H3PO4 fully dissociates in water, providing a large concentration of H+ ions, making it difficult for the HPO4^2- to effectively act as a base and maintain pH stability.

Therefore, KH2PO4 is a more suitable choice as a buffer because it has a greater buffering capacity due to the presence of the weak acid and its conjugate base.

For more question on conjugate

https://brainly.com/question/14684465

#SPJ8

Answer:

I don't understand the question

Explanation:

what is your name

To titrate 30.00 ml of a 0.1000 M \(NaOH\) solution, one needs about 0.6126 g of monoprotic \(KHP\).

1. To calculate the amount of \(NaOH\) needed to make a 0.1 M solution, we first need to calculate the number of moles of \(NaOH\) needed.

Molarity = moles of solute / liters of solution
0.1 M = x moles / 0.5 L
x = 0.05 moles

Now we can calculate the mass of \(NaOH\) needed:
Mass = moles x molecular weight

Mass = 0.05 moles x 40.3 g/mol
Mass = 2.015 g

Therefore, approximately 2.015 g of \(NaOH\) should be dissolved in 500 ml of distilled water to produce a solution with a molarity near 0.1 M.

2. We can use the equation:
Moles of \(NaOH\) = moles of \(KHP\)

Molarity x volume (in liters) of \(NaOH\) = moles of \(KHP\)
0.1000 M x 0.03000 L = moles of \(KHP\)

moles of \(KHP\) = 0.003
Now we can calculate the mass of \(KHP\) needed:

Mass = moles x molecular weight
Mass = 0.003 moles x 204.2 g/mol

Mass = 0.6126 g
Therefore, approximately 0.6126 g of monoprotic \(KHP\) is needed to titrate 30.00 ml of a 0.1000 M \(NaOH\) solution.

For more question on monoprotic

https://brainly.com/question/28556909

#SPJ11

The frequency of the photon is 3.57 * 10^14 Hz. the energy in joules is 2.4 * 10^-19 J while the energy in kJ/mol is 3.9 * 10^-40 kJ/mol.

The energy of the photon can be obtained by the use of an adaptation of the Plank equation. Let us now use;

E = hc/λ

E = energy

h = Plank Constant

c = Speed of light

λ = wavelength

a)

c = λf

f = c/λ

Substituting values;

f = 3 * 10^8/839.6 * 10^-9

f = 3.57 * 10^14 Hz

b)

E = 6.6 * 10^-34 * 3 * 10^8/ 839.6 * 10^-9

E = 2.4 * 10^-19 J

c)

Energy in kJ/mole

Substituting values;

2.4 * 10^-19 J * 10^3/6.02 * 10^23

= 3.9 * 10^-40 kJ/mol

Learn more about photon:https://brainly.com/question/20912241

#SPJ1

Answer:

the l sign means the substance in the chemical equation is a liquid. (hope this helped : D )

9. The specific heat capacity of the metal is approximately 0.47 J/g°C, 10. The specific heat of the metal is approximately 0.52 J/g°C.

9-To determine the specific heat capacity of the metal, we can use the formula:

q = mmetal × cmetal × ΔTmetal + mwater × cwater × ΔTwater

where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

cmetal = q/(mmetal × ΔTmetal)

q = mwater × cwater × ΔTwater = (250.0 g) × (4.184 J/g°C) × (27.2°C - 24.3°C) = 3111.8 J

mmetal = 125.0 g

ΔTmetal = 27.2°C - 100.0°C = -72.8°C

cmetal = 3111.8 J/(125.0 g × -72.8°C) ≈ 0.47 J/g°C

10- To solve for the specific heat of the metal, we need to account for the heat capacity of the calorimeter as well. The heat transferred from the metal to the water is given by:

q = (mmetal × cmetal + Ccalorimeter) × ΔT + mwater × cwater × ΔT

cmetal = (q - Ccalorimeter × ΔT)/(mmetal × ΔT)

q = (1000.0 g) × (4.184 J/g°C) × (26.5°C - 24.9°C) = 1253.44 J

Ccalorimeter = 1101 J/°C

mmetal = 750.0 g

ΔT = 26.5°C - 100.0°C = -73.5°C

cmetal = (1253.44 J - 1101 J/°C × -73.5°C)/(750.0 g × -73.5°C) ≈ 0.52 J/g°C

learn more about specific heat capacity here:

https://brainly.com/question/29766819

#SPJ1

Answer:

C = 107.97 mol/L

Explanation:

Given data:

Volume of solution = 1.38 mL (1.38 mL× 1 L /1000 mL = 0.00138 L)

Mass of ammonium sulfite = 17.36 g

Concentration of solution =?

Solution:

We will calculate the number of moles of ammonium sulfite.

Number of moles = mass/molar mass

Number of moles = 17.36 g / 116.15 g/mol

Number of moles = 0.149 mol

Concentration:

C = n/V

C = concentration

n = number of moles of solute

v = volume in L

C = 0.149 mol / 0.00138 L

C = 107.97 mol/L

The final solution has a strength of 2%.

Let the initial volume of solution = x unit^3

The solution is initially by 20%

Amount of solute = x*20/100

                             = x/5 unit^3

Now,  

We first diluted by 1:5

1 part of initial solution is diluted with 4 parts of diluent

For 'x' unit^3 solution,

Diluent added = 4x unit^3

Total volume of solution becomes = x+4x

                                                          = 5x unit^3

Now,

We diluted by 1:2

1 part of solution is diluted with 1 part of diluent

5x unit^3 of solution is diluted with 5x unit^3 of diluent

Final solution = 5x + 5x = 10x unit^3

Final strength = (Amount of Solute/Final solution)*100%

                       = (x/5/10x)*100%

                       = x/50x*100%

                       = 2%  

The final strength of final solution is 2%

Learn more about Diluted Solution at: https://brainly.com/question/14528274

The difference between the numbers,

(2.260×104)−(8.098×103) = 598.539.

Subtraction is a mathematic operation. Which is used to remove terms or objects in an expression.

Given:

Two numbers,

(2.260×104) and (8.098×103).

First, we simplify the numbers,

(2.260×104) = 235.04

And  (8.098×103) = 833.579.

The difference between the numbers,

(2.260×104)−(8.098×103) = 833.579 - 235.04.

(2.260×104)−(8.098×103) = 598.539

Therefore, then value is 598.539.

To learn more about the subtraction;

https://brainly.com/question/2346316

#SPJ1

Based on the description of the potential energy diagram provided, the diagram made by the student appears to be correct.

The potential energy diagram represents the energy changes that occur during a chemical reaction. In an endothermic reaction, the products have higher potential energy than the reactants, meaning energy is absorbed from the surroundings.

The curve line on the graph indicates the energy changes throughout the reaction pathway. It starts at a higher level, representing the initial potential energy of the reactants. As the reaction progresses, the potential energy decreases, indicating the formation of products with lower potential energy.

The broken horizontal line from point X on the y-axis to the point where the curve begins represents the activation energy (Ea) of the reaction. Activation energy is the energy barrier that must be overcome for the reactants to convert into products.

Point X on the y-axis indicates the potential energy of the reactants at the start of the reaction, and the broken line shows the energy required to initiate the reaction.

The broken horizontal line from point Y on the y-axis to the point where the curve ends represents the potential energy of the products. Point Y represents the potential energy of the products at the end of the reaction.

Overall, the student's diagram correctly represents an endothermic reaction, showing the potential energy changes, the activation energy, and the final potential energy of the products. The curve line starts at a higher level (representing the higher potential energy of the reactants) and ends at a slightly lower level (representing the lower potential energy of the products).

For more such questions on potential energy diagram visit;

https://brainly.com/question/23343697

#SPJ8

Answer:

See below

Explanation:

From the graph: initial temp = -10 ° C

    melting occurs at 0 ° C   (constant temp process)

     at '2'   the ice is melting.....going from a solid to a liquid at a constant temperature  

Answer: KE = 8.6917248 J

I'm not for sure but I am pretty positive this is the answer

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

For more such questions on molecules

https://brainly.com/question/1351818

#SPJ8

The balanced equations are Cd (g) + S\(_8\) (g) → CdS (g), K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\). and a Na +  HOH → NaOH + H\(_2\). Cd (g) + S\(_8\) (g) → CdS (g) is combination reaction.

An equation per a chemical reaction is said to be balanced if both the reactants plus the products have the same number of atoms and total charge for each component of the reaction. In other words, both sides between the reaction have an equal balance of mass and charge. The balanced equations are Cd (g) + S\(_8\) (g) → CdS (g), K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\). and a Na +  HOH → NaOH + H\(_2\).

Cd (g) + S\(_8\) (g) → CdS (g) = combination reaction

K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\)  = decomposition reaction

Na +  HOH → NaOH + H\(_2\) = Hydration reaction

To know more about balanced equation, here:

https://brainly.com/question/7181548

#SPJ1

The mass of nitrogen dioxide present in 3.45 moles is equal to 158.73 g.

A mole can be defined as a scientific unit that is used to determine the huge number of quantities of molecules, atoms, ions, etc. The mass of the 1 mole of an element is called atomic mass and the mass of one mole of any compound is called molar mass.

The number of particles in 1 mole was found to be equal to 6.023 × 10 ²³ per mole which is known as Avogadro’s constant.

Given, the number of moles of nitrogen dioxide = 3.45 mol

The molar mass of NO₂ = 46.01 g/mol

It means that 1 mole of NO₂  has mass = 46.01 g

Then 3.45 moles of  NO₂ will have mass = 3.45 × 46.01 = 158.73 g

Learn more about the mole, here:

brainly.com/question/26416088

#SPJ1

The correct answer from the given four options is B: The equilibrium will shift to the left if sulfur trioxide is added to the system.

In chemistry, equilibrium refers to the state of a reversible reaction where the forward and reverse reactions occur at the same rate. In other words, the concentrations of reactants and products remain constant over time, and there is no net change in the amount of each substance. At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction, and the system is said to be in a dynamic state. Equilibrium is an important concept in many areas of chemistry, including acid-base reactions, solubility, and chemical kinetics.

Learn more about equilibrium here:

https://brainly.com/question/30807709

#SPJ1

At equilibrium, the HI concentration is 2.92 mol/L.

For the process H2(g)+CO2(g)updownarrow H2O+CO. at 1660 °C, the equilibrium constant KP is 4. In a 5 liter flask, 0.8 moles each of H2 and CO2 are first injected. Reactions occur in the following order with relation to H2: 1. In experiments 1 and 2, the reaction rate doubles when the initial concentration of H2 is doubled while the initial concentration of Cl2 is held constant.

H2(g) + I2(g) ⇌ 2HI(g)

c = [HI]² / [H2][I2]

At the specified temperature, c = 53.3, hence the following can be written:

53.3 = [HI]^2 / (0.400 mol/L) × (0.400 mol/L)

or, [HI]² = 53.3 × 0.16

or, [HI]² = 8.528

or, [HI] = sqrt(8.528) mol/L

or, [HI] = 2.92 mol/L

As a result, 2.92 mol/L of HI are present at equilibrium.

To know more about concentration visit:-

https://brainly.com/question/10725862

#SPJ1

The number that is the same as the exponentiation given as follows: 2.5 × 10-³ is 0.0025.

Exponentiation is the process of calculating a power by multiplying together a number of equal factors, where the exponent specifies the number of factors to multiply.

For example, if 10 is multiplied three times, then it can be written as "10 raised to 3" which means 10³. In this case, 10 is the base, and 3 is the exponent.

Therefore, a number 0.0025 can be written in exponentiation as 2.5 × 10-³ by counting the number of zeros forward.

Learn more about exponentiation at: https://brainly.com/question/28596571

#SPJ1

The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.

To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.

The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.

Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol

Now, let's calculate the percent composition of each element in CuBr₂:

Percent composition of copper (Cu):

Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%

Percent composition of bromine (Br):

Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%

Therefore, the percent composition of CuBr₂ is approximately:

- Copper (Cu): 28.46%

- Bromine (Br): 71.54%

These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.

for more such questions on composition

https://brainly.com/question/28250237

#SPJ8

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.

Answer: The equation is \(_{29}^{63}\textrm{Cu}\rightarrow _{30}^{63}\textrm{Zn}+_{-1}^0e\)

Explanation:

Neutron capture is a process where a neutron is converted into a proton and an electron. The released particle is known as beta particle and it carries a charge of -1 units and has a mass of 0 units. It is also known as an electron. The general equation for this process is:

\(_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+ _{-1}^0\e\)

The nuclear equation for the formation of zinc via neutron capture of copper follows:

\(_{29}^{63}\textrm{Cu}\rightarrow _{30}^{63}\textrm{Zn}+_{-1}^0e\)

Answer:

limiting reagent is 02

mass of CO2 is 11g

Explanation:

the limiting reagent is the reagent which is consumed completely

no of mole of CH2 = m in g / molar mass

= 46.0/(12+2)

= 3.285 moles.

no of mole of O2 = 32/32

= 1 mole

from the reaction

1 mole of CH2 ==> 2 mol of O2

3.285 mol ==> 1/2 mol

3.285 mol ==> 0.5 mol

:. since O2 has the lowest mol , it's the limiting reagent

the limiting reagent mol will be used to find the no of mole of CH2

2 mol of O2==> 1 mol of CO2

0.5 mol ==> 0.5/2

0.25 mole of CO2

mass = 0.25 * ( 12+32)

= 11g

you can support by rating brainly it's very much appreciated ✅

(a) Electroless deposition is a type of electrochemical deposition that does not require electrons - X.

(b) Increasing metal ion concentration increases the deposition current density on the electrodeposited structures - X.

(c) The standard reaction Gibbs energy change for water electrolysis is negative, not positive, and generates 1.23V during electrolysis under standard conditions - X.

(d) When the system is under mass transport limitation, the electrodeposited structures are normally dense and uniform - O.

(e)  If you deposit metal A on metal B with a huge lattice misfit between them, the deposition process follows the island growth mechanism rather than the layer-by-layer growth mechanism - O.

(f) To make an AxBy alloy from metals A and B with standard reduction potentials of 1.0V and -1.0V, respectively, you need to apply a potential between -1.0V and 1.0V, depending on the desired stoichiometry - O.

(g) The length of metal nanowires made using AAO templated electrodeposition can be controlled by the anodization time and the thickness of the AAO template - O.

(h) The membrane electrolyte for PEMFC should only allow for ionic movement, not electronic movement  - O.

(i) The fuel cell electric vehicle generates less CO2 than traditional vehicles but still produces some CO2 during operation  - O.

(j) The organic leveler used in the electrodeposition process interacts with the substrate or growing deposits through chemical bonding rather than van der Waals interaction  - O.

To learn more about the electrodeposition, follow the link:

https://brainly.com/question/29899263

#SPJ1

Consider the equation : 2NOCl(g) --> 2NO(g) + Cl₂(g) , the relative rate for NO is Δ[NO] = 2Δ[Cl₂].

The chemical equation is as follows :

2NOCl(g) --> 2NO(g) + Cl₂(g)

The Rate = change in the concentration of the species or the change in the time.

The rate law for the equation is as :

The rate law = k[NO] [ Cl₂]²

The rate law  for the chemical reaction is the expression that will provides the relationship in between the reaction rate and the concentrations of the reactants that is participating in it.

The relative rate for NO is :

Δ[NO] = 2Δ[Cl₂].

To learn more about rate here

https://brainly.com/question/29000078

#SPJ4

It is the 4th scenario is the dependent event. There are 7 gold tokens and 4 silver tokens in a cup. The first student randomly draws a gold token and keeps it. A second student randomly draws a gold token from the cup.

The fouth scenario is a dependent event because the probability of the second student drawing a gold token is affected by the outcome of the first student's draw.

If the first student draws a gold token, then there are only 6 gold tokens left in the cup, the probability changes. but  if the first student does not draw a gold token, then there are 7 gold tokens left in the cup, the probability will remain the same

Find more exercises on dependent events;

https://brainly.com/question/11473170

#SPJ1