The three gorges dam is rated at 22.5 gwe maximum output. if its generating efficiency is 90% and its head is 81 m, what is the rate of flow (in kg/s) of water through its turbines at maximum output? use e for exponent; for e.g. 3x10^8 should be written as 3e8.

Water pressure principles is known to  state that the amount of Fluid pressure is said to be perpendicular to the surface on which it it exert or works on.

Note that  principle is shown by a vessel that is said to be having flat sides and has water. The pressure exerted by the weight of the water is therefore known to be perpendicular to the walls of the storage.

A water butt is known to be a container that is made and also used to store a lot of rainwater.

Note that Water pressure principles is known to  state that the amount of Fluid pressure is said to be perpendicular to the surface on which it it exert or works on.

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The key ideas explored in Ai Weiwei's Colored Vases are appropriation, transformation, and cultural heritage.

In his Colored Vases series, Ai Weiwei took Han Dynasty vases and dipped them in industrial paint, transforming them from ancient artifacts into contemporary works of art. Through this act of appropriation, Weiwei highlights the importance of cultural heritage and its evolution over time. By transforming these vases, Weiwei also comments on the commodification of art and the value placed on objects in contemporary society. Through the use of bright, industrial colors, Weiwei brings attention to the cultural differences between East and West and how they are perceived. Overall, the Colored Vases series is a thought-provoking exploration of culture, appropriation, and transformation in contemporary art.

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The entropy changes in the system when there are constant specific heats and variable specific heats are found out to be

a) ASsys= 2.20 kJ/K

b) ASsys= 1.56 kJ/K respectively.

(a) Constant Specific Heat

To solve the problem, use the following formula:

ASsys = Cv ln(T₂/T₁)+R ln(V₂/V₁)

ASsys = [Cv ln(T₂/T₁)] + [R ln(V₂/V₁)]

where: ASsys= system entropy change

R = 0.287 kJ/kg.K

Cv = 0.717 kJ/kg.K

T₁ = 17 + 273 = 290 K (initial temperature)

P₁ = 120 kPa (constant pressure)

P₂ = 120 kPa (constant pressure)

V₁ = 300 L

= 0.3 m³ (initial volume)

V₂ = V₁ [since V is constant]

= 0.3 m³

T₂ = T₁ + q/Cp

where q= amount of heat added

Cp= specific heat of air at constant pressure

From the given data,

Q= P x V

= 120 kPa x 0.3 m³

= 36 kJ

Q/Δt = 200 W

= 200 J/s

Cp= 1.005 kJ/kg.K

[Table A-2, at 17°C, for air]

T₂ = (q/Cp) Δt + T₁

= (200/1.005) x 900 + 290

= 692 K

Now apply the formula for system entropy change.

ASsys = Cv ln(T₂/T₁)+R ln(V₂/V₁)

= 0.717 x ln(692/290) + 0.287 x ln(0.3/0.3)

= 2.20 kJ/K

(b) Variable Specific Heat

To solve the problem, use the following formula:

ASsys = ∫(Cp/T)dT- R ln(V₂/V₁)

whereASsys= system entropy change

ΔT= T₂ - T₁

= (692-290)

= 402 K

R= 0.287 kJ/kg.K

V₁ = V₂

= 0.3 m³

Using the data from Table A-2, Cps and T can be tabulated as:

Cp (kJ/kg.K)T (K)1.0052731.005284.16 (Note: T₂)1.005692

Apply the trapezoidal rule for the integral to get:

ASsys = ∫(Cp/T)dT- R ln(V₂/V₁)

= 0.287[(1.005273/290) + (1.005284.16/273) + (1.005692/692)]- 0.287 ln(0.3/0.3)

= 1.56 kJ/K

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The correct answer is The correct answer is d. EVJ cable type is available in sizes ranging from 18 AWG to 500 kcmil and is rated for extra hard usage.

Additionally, it has thermoset insulation, which provides excellent resistance to high temperatures and chemicals. The thermoset insulation ensures that the cable can withstand the harsh environments of electric vehicle applications, where exposure to heat and chemicals is common.EVJ cable type is commonly used in electric vehicle charging stations, battery management systems, and other applications where high power is required. The range of sizes available makes it a versatile cable that can accommodate different power requirements. The extra hard usage rating ensures that the cable can withstand the rough handling that is typical in electric vehicle charging stations.

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When you have a single cell selected and click the insert button instead of the button arrow, excel inserts a single cell, automatically moving cells down and to the right to create space for the new cell to be inserted.

This is done to ensure that any existing data in the adjacent cells to the right or below the cell being inserted is not deleted. Excel also provides an option to shift cells left, right, up, or down when a new cell or cells are inserted.

To insert a single cell in Excel, you can follow the steps below:

Select the cell that is immediately below or to the right of where you want to insert the new cell. This ensures that the data in the adjacent cells is not overwritten when the new cell is inserted.

Click on the Insert button on the Home tab in the ribbon. Alternatively, you can right-click the selected cell and choose Insert from the context menu. This opens the Insert dialog box. Select the option for how you want to shift the cells.If you want to insert a new cell above the selected cell and shift the cells down, select the option Shift cells down.

Click OK to insert the new cell, and Excel will shift the cells accordingly. Excel also provides options to insert multiple cells, rows, or columns. These options are available on the Insert button dropdown. You can also use keyboard shortcuts to insert cells, rows, or columns in Excel.

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Field engineers are engineers who work mostly on-site in various environments (such as factories and construction sites).

Thus, The tasks of a field engineer often involve equipment inspection and installation, supervision of crews or workers on the job site, research, and project status reporting.

Engineers on the ground will ensure that everything operates as intended and that engineering specifications are being met.

Field engineers are engineers who work mostly on-site in various environments (such as factories and construction sites). Only a small portion of their time is spent in an office.

Thus, Field engineers are engineers who work mostly on-site in various environments (such as factories and construction sites).

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Answer:

For most uses you'll want your water heated to 120 F(49 C) In this example you'd need a demand water heater that produces a temperature rise and it will take about 2 hours

Universal joints do not allow the drive shaft to change angles in response to rear axle movements, as stated by Technician A. Technician B is correct.

The  primary purpose of universal joints is to maintain a constant drive shaft length while accommodating changes in angles. Universal joints, also known as U-joints, are mechanical couplings used in drivetrain systems. They are typically employed in applications where there is a need to transmit rotational motion between two shafts that are not aligned in a straight line. The design of universal joints allows them to accommodate changes in angles between the input and output shafts while maintaining a consistent shaft length. As the rear axle moves, the angles between the transmission and the axle may change due to suspension travel or other factors. The universal joints allow the drive shaft to flex and rotate at varying angles without affecting its length. This flexibility helps to prevent binding or excessive stress on the drive shaft, ensuring smooth power transmission and allowing for efficient operation of the drivetrain system.

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how am I going to do this, I have a friend that might be able to help I will check

Answer:

Definitely not

Explanation:

You should have 1-2 feet of extra ladder on a flat surface so 1 foot on an adjacent floor is a no no

Answer:

b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.

Explanation:

An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.

It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.

Answer:

Ra = 3,000 lb

Ma = 26,125 lb-ft

Explanation:

Solution:-

- We are given a cantilever horizontal beam with a span of 20 ft subjected to distributed loads.

- We will use the following conventions and define our coordinate system:

- Denote positive direction ( + ) directed "vertically upward" and "anticlockwise".

- Denote negative direction ( - ) directed "vertically downward" and "clockwise".  

- We will denote a reaction force ( Ra ) and reaction moment ( Ma ) exerted by the wall support at point A on the beam in positive directions, respectively. These reactions are consequence of the distributed load acting on the horizontal beam.

-  First step is to analyze the distributed load. We will make 4 sections of the distributed loads and write down the shapes of each distributions as follows:

     Section                    Load ( Lb/ft)                     Distribution

           1                               750                             Rectangular

           2                              750                         Right angle triangle

           3                              450                         Right angle triangle

           4                              450                             Rectangular

- We will proceed with load-transformation. In load transformation we convert the distributed load into a " point load "  and determine the "location of transformed load " using distribution pattern of each section.

- We will now determine the point load and location of each point load for the respective section from point ( A ) as follows:

       Section 1:

                        P1 = Load_1 * distribution span_1

        From above table, Load_1 = 750 lb/ft.

        Distribution is rectangular, spanning L1 = 3ft

                         P1 = ( 750 lb/ft ) * ( 3ft )

                         P1 = 4500 lb

         For rectangular distributions, the point load acts at the geometric center of the distribution pattern; hence, center of rectangle x1 = 3ft from point A.  

          Section 2:

                        P2 = Load_2 * distribution span_2*0.5

        From above table, Load_2 = 750 lb/ft.

        Distribution is right angle triangle, spanning ( L2 )

                         P2 = 0.5* ( 750 lb/ft ) * ( L2 )

                         P2 = 375*L2 lb

         For rectangular distributions, the point load acts at the geometric center of the distribution pattern; hence, center of right angle triangle is x2 = 6ft + L2/3 from point A.              

          Section 3:

                         P3 = Load_3 * distribution span_2*0.5

        From above table, Load_3 = 450 lb/ft.

        Distribution is right angle triangle, spanning ( L3 )

                         P3 = 0.5* ( 450 lb/ft ) * ( L3 )

                         P3 = 375*L3 lb

         For rectangular distributions, the point load acts at the geometric center of the distribution pattern; hence, center of right angle triangle is x3 = 6ft + L2 + 2*L3/3 from point A.              

- Before we proceed further, we need to determine the spanning lengths of right angle triangles for distributed loads for sections 2 and 3. From the given figure we can form two equations as follows:

                       L2 + L3 = 9 ft    .... Eq 1

- The second equation can be determined by the concept of similar triangles to relate L2 and L3 as follows:

                       L2 = L3* ( 750 / 450 )

                       L2 = 5*L3 / 3   ... Eq 2

- Solve the two equations simultaneously for L2 and L3, we get:

                       L2 = 4.625 ft, L3 = 4.375 ft

- The corresponding point loads and locations are as such:

                      P2 = 1734.375 lb , x2 = 7.5416667 ft

                      P3 = 984.375 lb , x3 = 13.541667 ft

Note: The division of 750 lb/ft and 450 ft/lb loads in section 2 and section 3 can be mistaken to be equal and setting L2 = L3 = 4.5 ft. Remember to take care of such situations.

        Section 4:

                        P4 = Load_4 * distribution span_4

        From above table, Load_4 = 450 lb/ft.

        Distribution is rectangular, spanning L4 = 5ft

                         P4 = ( 450 lb/ft ) * ( 5ft )

                         P4 = 2,250 lb

         For rectangular distributions, the point load acts at the geometric center of the distribution pattern; hence, center of rectangle x4 = 6ft + 9ft + L4/2 = 17.5 ft from point A.  

- Second step: Apply the static equilibrium conditions on the horizontal beam.

       Force Balance: Sum of forces in vertical direction = 0

                   ∑ \(F_y,net = 0 = R_A + P3 + P4 - P1 - P2\)

                    \(R_A = 4,500 + 1,734.375 - 984.375 -2,250\\\\R_A = 3,000 Lb\)

      Moment Balance: Sum of moments about A = 0

      ∑ \(M_n_e_t = 0 = M_A + P3*x3 + P4*x4 - P1*x1 - P2*x2\)

                      \(M_A = -(984.375)*(13.541667) - (2250)*(17.5) + (4500)*(3) + (1734.375)*\\(7.54166667)\\\\M_A = -26,125 Lb.ft\)

Answer: The reaction force at point A is directed vertically upward ( Ra = 3,000 Lb ) and the reactive moment is directed clockwise at point A ( Ma = 26,125 Lb-ft ).

Answer:

Construction, the techniques and industry involved in the assembly and ... Early building materials were perishable, such as leaves, branches, and animal hides. ... The well-developed masonry technology of Mesopotamia was used to build large ... although its precise description is unknown; the concealed faces of stones

Explanation:

Advanced distillation technologies

2.1. Heat integrated distillation column (HIDC) ...

2.2. Membrane distillation (MD) ...

2.3. Cyclic distillation. ...

2.4. Cryogenic distillation. ...

2.5. Reactive distillation column.

Answer:

The first one.

Explanation:

The first one without a doubt

this is perfect.........

The min function with a resolution of 0.01 ft, the values of R and L required to minimize the total cost of the fence and the corresponding minimum cost can be determined.

To find the values of R and L that minimize the total cost, we need to set up the optimization problem. We have the following equations:

1. Area constraint equation: L * 2R + (πR²)/2 = 1600

2. Cost function: Cost = 2L * $30 + πR * $40

Using the min function with a resolution of 0.01 ft, we can find the values of R and L that minimize the cost function while satisfying the area constraint equation. The min function will calculate these values by iterating through different combinations of R and L within the specified resolution and finding the minimum cost.

Once we have the values of R and L that minimize the cost, we can substitute them back into the cost function to compute the minimum cost of the fence.

The specific numerical calculations require implementation in a programming language or mathematical software that supports optimization functions and can solve equations and minimize functions.

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Answer:

hello your question has some missing part attached below is the complete question

answer : steady state temperature = 419.713k ≈ 218.7⁰c

              Time required to reach a junction ≈ 5 secs

Explanation:

The detailed solution of the given problem is attached below but the solution to the subsequent problem from which the question you asked is referenced to( problem 1 ), is not attached because it was not part of the question you asked

This prompt is about Prince George's Wood Innovation Design Center. The building was erected as a model to highlight the possibilities of wood innovation and a departure from conventional concrete and steel architecture and building engineering models.

The Wood Innovation Design Centre (WIDC) is a meeting space for researchers, educators, and design professionals who are brainstorming new ways to use wood. The bottom floors of the building are dedicated to Integrated Wood Design instruction.

The Wood Innovation and Design Centre is located in Prince George, British Columbia. Michael Green Architecture ("Wood Innovation and Design Centre" n.p.) designed the 97-foot-tall, eight-story (six-story includes mezzanine and penthouse) structure.

The building's sleek, contemporary box shape is purposefully simple. Its simplicity serves as a canvas for the beauty of the numerous kinds of wood and their features, which include Douglas-fir, western red cedar, hemlock, pine, and spruce from British Columbia's sustainable forests.

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To write a program that accepts an integer between 100 and 10,000,000 and then determines whether the number entered is a palindrome or not, follow the steps given below: Step 1: Declare a variable num and intialize it with 0.Step 2: Take input from the user and store it in the variable num. Step 3: Declare two variables i and j and initialize them with 0.Step 4: Declare a variable flag and initialize it with 1.

Step 5: Declare an array arr of size 10,000,000 and intialize it with 0.Step 6: Store each digit of num in the array arr in reverse order using the while loop.Step 7: Now, traverse the array arr using the for loop and compare the ith and jth element of the array.

Step 8: If ith and jth element of the array are not same, then the number is not a palindrome and the flag is set to 0.Step 9: If ith and jth element of the array are same, then the loop continues and the flag is set to 1.Step 10: At last, if the flag is 1, then print the number is a palindrome else print the number is not a palindrome.Below is the C++ implementation of the above approach:```
#include
using namespace std;
int main()
{
   int num, i = 0, j = 0, flag = 1, arr[10000000] = {0};
   cin >> num;
   while (num != 0)
   {
       arr[i] = num % 10;
       i++;
       num /= 10;
   }
   j = i - 1;
   for (i = 0; i < j; i++, j--)
   {
       if (arr[i] != arr[j])
       {
           flag = 0;
           break;
       }
   }
   if (flag == 1)
       cout << "The number is a palindrome";
   else
       cout << "The number is not a palindrome";
   return 0;
}
```

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Answer:

Mass flow rate = 15.96kg/s

Explanation:

From

P1V1=mRT1

V1=RT1/P1

V1=0.0492m³/kg

M=A(U)/V1

Where u is the velocity

A=πd²/4

M=π(0.2²)/4×25/0.0492

M=15.96kg/s

Physical Effects of Metals

Metals are lustrous, malleable, ductile, good conductors of heat and electricity. Other effects include: State: Metals are solids at room temperature with the peculiarity of mercury, which is liquid at room temperature (Gallium is liquid on hot days).

Metals are typically very good conductors, meaning they let current flow easily. Fabrics that do not let current flow easily are called insulators. Most nonmetal fabrics such as plastic, wood and rubber are insulators.

Metals have a high melting point and are usually a solid at room temperature. They are also flexible. This means that they can be easily stretched. Finally, metals are suitable conductors of heat and electricity.

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In comparison to summary feedback, relative feedback filters out within-subject variation and provides more reliable information. Summary feedback refers to the information provided to learners after completing a task, often detailing their performance in relation to the specific objectives.

While this type of feedback can be useful, it may not always account for individual differences in learning styles, abilities, or other factors that can influence performance.

On the other hand, relative feedback compares an individual's performance to that of their peers or a reference group. By doing so, it can highlight the relative strengths and weaknesses of a learner, making it easier for them to understand where they stand in relation to others. This comparison can also help to eliminate within-subject variation, as it takes into account the performance of the entire group rather than focusing solely on an individual's results. As a result, relative feedback provides a more reliable and accurate reflection of a learner's performance and progress.

Furthermore, relative feedback can be motivational, as it encourages learners to strive for improvement by understanding their position in relation to their peers. This type of feedback can foster a healthy sense of competition and drive learners to develop their skills further. In summary, relative feedback offers a more reliable and informative assessment of a learner's performance compared to summary feedback, as it accounts for individual differences and within-subject variation by placing the focus on relative performance rather than isolated results.

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It appears that the country has a problem with infrastructure and public facilities maintenance.

The updating of water and sewer systems, road and bridge closures, and public parks full of litter and decaying facilities suggest that there is a lack of attention to and investment in the maintenance and improvement of these critical elements of the country's infrastructure.

This can lead to a number of problems, including health and safety risks, environmental degradation, and reduced quality of life for citizens. In addition, outdated and decaying infrastructure can also have a negative impact on the economy, as it may limit the ability of businesses and individuals to transport goods and travel effectively. To address these issues, the country may need to allocate more resources to infrastructure and public facility maintenance and improvement.

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Answer:

substance B

Explanation:

Answer:

i would say C

Explanation:

Answer:

c

Explanation:

ye