The space shuttle releases a satellite into a circular orbit 695 km above the Earth. Part A How fast must the shuttle be moving (relative to Earth) when the release occurs

The acceleration of the train during the first two seconds is 10 m / s², between second and tenth second is zero and during the last 2 seconds is - 10 m / s².

a = v - u / t

a = Acceleration

v = Final velocity

u = Initial velocity

t = Time

(a) During first 2 seconds,

u = 0

v = 20 m / s

t = 2 s

a = 20 - 0 / 2

a = 10 m / s²

(b) Between second and tenth second

u = 20 m / s

v = 20 m / s

t = 8 s

a - 0 -0 / 8

a = 0 m / s²

(c) During last 2 seconds,

u = 20 m / s

v = 0

t = 2 s

a = 0 - 20 / 2

a = - 10 m / s²

Therefore, the acceleration of the train

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The document filed in juvenile court alleging that a juvenile is a delinquent is called a(n)Light C. petition.

A petition is the document that is filed in juvenile court alleging that a juvenile is a delinquent. It is a formal request to the court to hear the case and make a determination about the juvenile's behavior. Once the petition is filed, the court will schedule a hearing to determine whether the allegations are true and what consequences should be imposed on the juvenile if they are found to be delinquent.

A petition is the legal document filed in juvenile court that contains the allegations against the juvenile and initiates the court process. The other options provided do not relate to this specific document. A writ of certiorari is a court order for a lower court to send its records to a higher court for review. A disposition refers to the final decision or outcome in a case, and adjudication refers to the process of determining guilt or innocence.

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If a spherical conductor has a net positive charge, then the charge is spread evenly around the sphere's surface.

A spherical conductor is a sphere having a profusion of negative charges spread throughout the surface of the sphere.

In other words, a spherical conductor can be a metal that is a spherical, narrow, and thin conducting surface.

Since charges can move freely throughout metal and the force of repulsion between similar charges led them to the edge of the sphere.

This results in the distribution of the charge on the surface and spreads out uniformly.

In this case, a +q charge will be at a distance r from a -ve charge of -2q.

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Answer:

here lol

Explanation:

Answer:

when the connection of the batteries is parallel negative to negative n positive to positive is called parallel connection

Explanation:

Answer:

The shadow would be on your left side.

Explanation:Give brainliest if this helped :)

The steady-state speed that can be achieved with a maximum drive power of 1.0 MW is approximately 9.73 m/s.

To determine the steady-state speed that can be achieved with a maximum drive power of 1.0 MW (megawatt), we need to consider the driving resistance and the available power.

Given information:

Mass of the locomotive (m1): 50 tonnes = 50,000 kg

Mass of each car (m2): 15 tonnes = 15,000 kg

Number of cars (n): 20

Gradient of the track (θ): 2% = 0.02

Friction coefficient (μ): 1%

Gravitational acceleration (g): 9.81 m/s^2

Maximum drive power (Pmax): 1.0 MW = 1,000,000 W

First, let's calculate the total mass of the train:

Total mass (M) = Mass of locomotive + Mass of cars

M = m1 + (m2 × n)

M = 50,000 kg + (15,000 kg × 20)

M = 50,000 kg + 300,000 kg

M = 350,000 kg

Next, we can calculate the driving resistance:

Driving resistance (R) = Gravitational resistance + Rolling resistance

Gravitational resistance (Rg) = M × g × sin(θ)

Rolling resistance (Rr) = μ × M × g × cos(θ)

R = Rg + Rr

Substituting the given values:

Rg = 350,000 kg × 9.81 m/s^2 × sin(0.02)

Rr = 0.01 × 350,000 kg × 9.81 m/s^2 × cos(0.02)

R = Rg + Rr

Calculate Rg:

Rg = 350,000 kg × 9.81 m/s^2 × sin(0.02)

Rg ≈ 350,000 kg × 9.81 m/s^2 × 0.02

Rg ≈ 68,430 N

Calculate Rr:

Rr = 0.01 × 350,000 kg × 9.81 m/s^2 × cos(0.02)

Rr ≈ 0.01 × 350,000 kg × 9.81 m/s^2 × 0.9998

Rr ≈ 34,267 N

Calculate R:

R = Rg + Rr

R ≈ 68,430 N + 34,267 N

R ≈ 102,697 N

Now, we can calculate the maximum velocity (vmax) using the maximum power available:

Power (P) = Force (F) × Velocity (v)

P = R × v

vmax = Pmax / R

Substituting the given values:

vmax = 1,000,000 W / 102,697 N

vmax ≈ 9.73 m/s

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The closest answer to this is D. -11°C. To find the freezing point of the solution, we need to use the freezing point depression equation:
ΔTf = Kf * molality.

Where ΔTf is the change in freezing point, Kf is the freezing point depression constant, and molality is the concentration of the solute in the solution in moles per kilogram of solvent. First, we need to find the molality of the solution. We can use the boiling point elevation equation to do so: ΔTb = Kb * molality
We know that the normal boiling point of pure water is 100°C, and the boiling point of the solution is 103.0°C. So, the change in boiling point is:
ΔTb = 103.0°C - 100°C = 3.0°C
We are given that Kb for water is 0.51°C/m, so we can rearrange the boiling point elevation equation to solve for molality:
molality = ΔTb / Kb
molality = 3.0°C / 0.51°C/m = 5.88 mol/kg

Now that we have the molality, we can use the freezing point depression equation to find the change in freezing point: ΔTf = Kf * molality
We are given that Kf for water is 1.86°C/m, so we can plug in the values:
ΔTf = 1.86°C/m * 5.88 mol/kg = 10.95°C
The change in freezing point is 10.95°C, which means that the freezing point of the solution is:
Freezing point = 0°C - ΔTf
Freezing point = 0°C - 10.95°C = -10.95°C
Therefore, the freezing point of the solution is -10.95°C. The answer choice closest to this value is E, which is -0.32°C. However, this answer is not correct. Therefore, the correct answer is not given in the answer choices provided.

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The answer to the given question is indeterminate or cannot be calculated.Sometimes the question may contain spelling errors or typos that make it difficult to understand. In such a case, it is best to double-check the question before attempting to answer it.

The given question, "What is the angular speed in radians per second?" can be solved using the formula for angular speed.

Angular speed is defined as the rate of change of angular displacement with respect to time. The angular speed is usually denoted by the Greek letter omega, ω.

The formula for angular speed, ω is given by;ω = Δθ/Δt

where,Δθ = change in angular displacement

Δt = change in time

Since there are no values for Δθ and Δt given in the question, we cannot solve the angular speed.

Therefore, The response to the query is ambiguous or impossible to calculate.Sometimes the question may have grammatical or spelling problems that make it challenging to understand. In this situation, it is best to confirm the question before attempting to respond to it.

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If the light source is 15.0 cm from the cornea and the image’s magnification is 0.0430, the cornea’s radius of curvature is approximately -1.381 cm.

A keratometer is a device that measures the corneal curvature by analyzing the light reflected from the cornea, which behaves like a convex mirror. The main purpose of using a keratometer is to determine the appropriate contact lens fit. The device measures the magnification of the reflected image, and the smaller the magnification, the smaller the radius of curvature of the cornea.

To find the cornea's radius of curvature, we can use the mirror equation:
1/f = 1/u + 1/v

Where:
f = focal length of the mirror (cornea)
u = object distance (distance from the light source to the cornea)
v = image distance (distance from the cornea to the image)

In our case, the object distance (u) is given as 15.0 cm. The magnification (M) of the image is also given as 0.0430. We can use the magnification formula to find the image distance (v):
M = -v/u

Rearranging the formula to solve for v:
v = -u * M

Plugging in the given values, we get:
v = -15.0 cm * 0.0430 = -0.645 cm

Now, we can plug in the values of u and v into the mirror equation:
1/f = 1/15.0 + 1/-0.645

Solving for f, we get:
f ≈ -0.6906 cm

The radius of curvature (R) of the cornea is related to the focal length by the equation:
R = 2f

Substituting the value of f, we find the radius of curvature:
R = 2 * -0.6906 = -1.381 cm

Since we need to express the answer in 4 significant figures, the cornea's radius of curvature is approximately -1.381 cm. The negative sign indicates that the cornea is a convex mirror.

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The power of the transmitter and receiver and the height of the broadcast and receiving antennas determine the Distance a radio signal will travel.

A sinusoidal voltage at 147.5 MHz is applied by the transmitter to the dipole antenna that serves as its antenna. With a matching oscillating magnetic field perpendicular to the antenna, this creates an oscillating electric field across the antenna. These travel as one electromagnetic wave, or radio wave, from the antenna.

With the oscillating magnetic field perpendicular to the antenna axis and the oscillating electric field parallel to it, this wave propagates in all directions in a plane that passes through the transmitter's antenna's center. It moves at the speed of light, and as was previously mentioned, its wavelength and oscillation frequency are connected by the formula = c/v.

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Answer:

12mph in 2hrs and 3mph in 0.5hrs the total distance would be 12*2 and 3*0.5 which would be 24 and 1.5 so we add those 24+1.5= 25.5. The answer would be 25.5

The work done by the toy car when it travels 2 m is 20 J.

The work done by the toy car when it travels 1 m is 10 J.

The work done by the toy car held 3.75 m above the ground is zero.

The work done by the toy car when it travels 7 m is 70 J.

The work done by the toy car when it travels 10 m is 100 J.

The work done by the toy car when it travels 2 m is calculated as follows;

W = Fd

W = (ma)d

W = (2 x 5) x 2

W = 20 J

The work done by the toy car when it travels 1 m is calculated as follows;

W = Fd

W = (ma)d

W = (2 x 5) x 1

W = 10 J

Work is said to be done when an object is displaced from its initial position. Since the car wasn't displaced, the work done is zero.

The work done by the toy car when it travels 7 m is calculated as follows;

W = Fd

W = (ma)d

W = 2(10 - 5) x 7

W = 70 J

The work done by the toy car when it travels 10 m is calculated as follows;

W = 2 x (5 - 10) x 10

W = -100 J

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Answer:

Oceanographers can measure the salinity of a body of water in several ways, but the two most common methods are using a hydrometer set or a salinometer.

A hydrometer set consists of a cylinder, a hydrometer, a thermometer, and a temperature-salinity-density or TSD graph.

Explanation:

Hope this helps

if so please mark brainlist! thx

Answer:

B

because measuring the density of the water

Answer:

It would go out the bottom hole faster.

Explanation:

It goes down the bottom hole faster because the water would get poured out the bottom before they even flipped the water bottle.

Streptococcus is the genus that is the most common resident biota of mouth surfaces

The most well known genus is Streptococcus.

Streptococcus bacterium of a genus that includes the agents of souring of milk and dental decay, and hemolytic pathogens causing various infections such as scarlet fever and pneumonia.

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Answer:

a

Explanation:

the river over time will eroded the rock

The maximum height above the ground the ball will reach before falling back down is 20 meters. therefore, the correct option is B.

To find the time it takes for the ball to reach its maximum height, we can use the equation s = ut + 1/2at^2, where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time.
Given:
Initial upwards velocity (u) = 20 m/s
Gravity acceleration (a) = -10 m/s^2 (negative because it acts in the opposite direction)
Distance traveled (s) = ?
To find the time it takes for the ball to reach its maximum height, we can use the equation v = u + at, where v is the final velocity.
v = 0 (at the maximum height, the velocity is 0)
0 = u + at
0 = 20 + (-10)t
-20 = -10t
t = 2 seconds
So, the ball will reach its maximum height after 2 seconds.
To find the maximum height (s), we can substitute the time (t) into the distance equation:
s = ut + 1/2at^2
s = 20(2) + 1/2(-10)(2)^2
s = 40 - 20
s = 20 meters
Therefore, the maximum height above the ground the ball will reach before falling back down is 20 meters.
The correct option is b.) The ball will reach its maximum height after 2 seconds, which will be 20 meters above the ground.

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The purpose of working out is described as an example of motivation, as Randy works out every day because he wants to make the football team, so option A is correct.

In humans and other animals, motivation is what causes an activity to start, continue, or end at a specific time. The interpretation of motivational states as internal forces that increase an agent's propensity to engage in goal-directed behavior is common. Conflicting theories exist on the makeup of motivated moods. They are known as content theories, and they aim to explain the typical or consistent motives.

Behaviorist theories seek to elucidate behavior solely in terms of the relationship between the circumstance and outward, apparent conduct, avoiding any explicit mention of conscious mental states.

Therefore, the purpose of Randy's working out daily is described as an example of motivation, he is motivated to make a football team.

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René Descartes (1596-1650) was a creative mathematician of the first order, an important scientific thinker, and an original metaphysician.

Willebrørd Snell (1591-1626) was a Dutch astronomer, mathematician, and scientist who is famously known for the law of refraction.

Johannes Kepler (1571-1630) was a German astronomer, mathematician, astrologer, natural philosopher, and writer of music.

Galileo Galilei (1564-1642) was an astronomer, physicist, and mathematician who made fundamental contributions to the sciences of motion and astronomy.

Notice that the period of Descartes and Snell overlap with the period of Kepler and Galileo.

Therefore, we can conclude that the given statement is true.

Answer:

The acceleration due to gravity at Pluto is 0.0597 m/s^2.

Explanation:

Length, L = 1 m

10 oscillations in 257 seconds

Time period, T = 257/10 = 25.7 s

Let the acceleration due to gravity is g.

Use the formula of time period of simple pendulum

\(T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2\)

In a  PN junction should exhibit a low resistance when it is forward biased, and a high resistance when it is reverse biased. Given this, if a diode has high resistance at both polarities, it is considered to be "faulty" or "damaged."

If a diode has high resistance at both polarities (forward and reverse biased), it is likely defective or damaged. A properly functioning diode should exhibit low resistance when forward biased and high resistance when reverse biased. If the diode fails to behave as expected in both polarities, it suggests a malfunction or a problem with the diode itself. In such cases, the diode may need to be replaced.

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Answer:

e search mo sa utak mo kasi di mo alam

Answer:

mhibyguftyftfrehlknmjhbn

Explanation:

njhvvtfryvbnyuhnuihnjhk

Answer:

Please find attached photograph for your answer. Do comment whether it is useful or not

Electromagnetic waves produced by electrons oscillating with a frequency of 2.0 x 10¹⁰ hertz would be classified as radio waves.

Electromagnetic waves are a form of energy that propagate through space in the form of oscillating electric and magnetic fields. These waves are generated by the acceleration or oscillation of charged particles, such as electrons.

The frequency of an electromagnetic wave refers to the number of oscillations or cycles it completes per unit of time. It is usually measured in hertz (Hz), which represents cycles per second. In the given scenario, the electrons are oscillating with a frequency of 2.0 x 10¹⁰ Hz.

Now, let's discuss the classification of electromagnetic waves based on their frequency and wavelength. The electromagnetic spectrum encompasses a wide range of waves, including radio waves, microwaves, infrared waves, visible light, ultraviolet waves, X-rays, and gamma rays.

Radio waves have the longest wavelengths and lowest frequencies among the electromagnetic waves. They typically range from a few centimeters to several kilometers in wavelength. These waves are commonly used for various forms of communication, such as radio and television broadcasting, as well as wireless communication technologies like Wi-Fi and cellular networks.

As the frequency of electromagnetic waves increases, we move through the spectrum, encountering microwaves, infrared waves, visible light, ultraviolet waves, X-rays, and gamma rays in that order. Each segment of the spectrum has distinct properties and applications.

In summary, the electromagnetic waves produced by electrons oscillating with a frequency of 2.0 x 10¹⁰ Hz would be classified as radio waves. These waves have longer wavelengths and lower frequencies compared to other regions of the electromagnetic spectrum and are widely used for communication purposes.

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a portable lamp with a 30 ohm resistance, 0.80 a current demand, and a 24 v power source

 The Super Bright LED Recharge Portable Scene Light II of Streamligh has 10,000 lumens, which is the most lumens we've found in an LED lantern.

E39 bulb, 300 watts: The brightest bulb currently available. It has a high efficiency of 130 lumens per watt and produces over 40,000 lumens. The 1000 watt HID, HPS, Metal Halide, or CFL fixture can be replaced with this one, which also delivers 360-degree lighting.e

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If a 0.3% decrease in the price of a good causes its quantity supplied to decrease by 1%, then the supply is C. Inelastic.

In this scenario, the supply of the good is considered inelastic. The elasticity of supply measures the responsiveness of the quantity supplied to changes in price. When the price of a good decreases, and the quantity supplied decreases by a larger percentage, it indicates that the supply is relatively unresponsive to price changes.

To determine the elasticity of supply, we compare the percentage change in quantity supplied to the percentage change in price. In this case, a 0.3% decrease in price results in a 1% decrease in the quantity supplied. Since the percentage change in quantity supplied (1%) is greater than the percentage change in price (0.3%), the supply is considered inelastic.

Inelastic supply means that producers are less responsive to price changes, and a small change in price leads to a proportionally smaller change in quantity supplied. In such cases, producers may find it challenging to adjust their output levels quickly in response to price fluctuations.

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