The rod ABCD is made of an aluminum for which E = 70 GPa. Take P = 100 kN.
For the loading shown, determine the deformation of point B.
Answers
The deformation of point B is approximately 0.002229 mm under the given loading.
To determine the deformation of point B in the aluminum rod under the given loading, we can use the formula for axial deformation due to an axial load:
ΔL = PL/(AE)
where ΔL is the deformation, P is the axial load, L is the length of the rod, A is the cross-sectional area of the rod, and E is the elastic modulus of the material.
In this case, we know that the load P is 100 kN, the elastic modulus E is 70 GPa, and the cross-sectional area A of the rod is given in the diagram as 500 mm^2. To find the length of the rod, we can use the Pythagorean theorem to find the length of segment BD:
BD^2 = AB^2 + AD^2
BD^2 = (500 mm)^2 + (600 mm)^2
BD = 781.02 mm
Therefore, the length of the rod is approximately 781.02 mm. Substituting the known values into the formula for axial deformation, we get:
ΔL = \(\frac{(100 kN)(781.02 mm)}{(500 mm^2)(70 GPa)}\)
ΔL = 0.002229 mm
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Related Questions
a 220 g , 34.0-cm-diameter turntable rotates on frictionless bearings at 59.0 rpm . a 25.0 g block sits at the center of the turntable. a compressed spring shoots the block radically outward along a frictionless groove in the surface of the turntable.
Answers
The turntable's rotation angular velocity when the block reaches the outer edge is 5.578 rads⁻¹
The inertial moment of the turntable block = \(\frac{1}{2} mr^{2}\)
The inertial moment of the block = \(mr^{2}\)
According to the law of conservation of angular momentum, the total angular momentum of the system when the block is seated at the center and when the block is at the outside edge must be the same since no external torque operates on the system.
Additionally,
ω= 2\(\pi\)f, where f represents rpm, can be used to determine
ω= 2π×63/60 = 6.597
So, I*ω = I' * ω'
\([\frac{1}{2} 0.23 *(0.5)^{2} + 0.021* (0)^{2} ]6.597= [\frac{1}{2} 0.23 *(0.5)^{2} + 0.021* (0.5)^{2} ]\)*ω'
ω' = 5.578 rads⁻¹
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If the same force is applied to an object with a small mass,it will have a blank accelertaion
Answers
If the same force is applied to an object with a small mass, it will experience a greater acceleration due to less inertia and the ease with which it can be accelerated. In contrast, an object with a larger mass will require more force to achieve the same acceleration.
According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. Mathematically, we can express this relationship as:
acceleration = force / mass
Therefore, if the same force is applied to an object with a small mass, it will experience a greater acceleration compared to an object with a larger mass. This is because the smaller mass results in less inertia, meaning it requires less force to cause a given acceleration. In other words, a smaller mass will accelerate more easily when the same force is applied to it. For example, if you apply the same force to a baseball and a bowling ball, the baseball will accelerate much more quickly because it has a smaller mass than the bowling ball. Conversely, if you apply the same force to a truck and a car, the car will accelerate more quickly because it has a smaller mass than the truck.
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Can someone buy me
it will make my day
Answers
Answer:
how much?
Explanation:
Somebody help!?
13. The graph below represents the speed of a car vs. time. Circle the letter(s) with the lowest acceleration.
What is the acceleration? How do you know?
Answers
Answer:
acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
Explanation:
Calculating acceleration involves dividing velocity by time — or in terms of SI units, dividing the meter per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .
Who conducted the experiment that showed that atoms were mostly made up of empty space?.
Answers
Rutherford conducted the experiment that showed that atoms were mostly made up of empty space.
Rutherford done an experiment in which he allowed alpha particle to bombard on gold foil . Which shows that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.
The observations made by Rutherford led him to conclude that: A major fraction of the α-particles bombarded towards the gold sheet passed through the sheet without any deflection, and hence most of the space in an atom is empty.
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the term ________ refers to an object's ability to take different forms.
Answers
The term "flexibility" refers to an object's ability to take different forms. High degree of flexibility is found in objects made by flexible materials.
Flexibility is a property that describes the ability of an object or material to bend, stretch, or change shape without breaking or losing its structural integrity. It is a measure of how easily an object can be deformed under the influence of external forces.
The flexibility of an object is determined by its composition, structure, and physical properties. Objects that are made of flexible materials, such as rubber or certain types of plastics, have a high degree of flexibility. They can be bent, twisted, or stretched without permanently deforming or breaking. In contrast, objects made of rigid materials, like metal or glass, have lower flexibility and are less prone to deformation.
Flexibility is an important characteristic in various fields, including engineering, materials science, and biomechanics. It allows for the design of structures and materials that can withstand different forces, adapt to different environments, and perform specific functions effectively.
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the drawing shows an exaggerated view of a rifle that has been"sighted in" for a 91.4-meter target. If the muzzle speed of thebullet is v0 = 427 m/s, what are the two possible anglesθ1 and θ2 between the rifle barreland the horizontal such that the bullet will hit the target? One ofthese angles is so large that it is never used in target shooting.(HInt: the following trigonometric identity may be useful: 2 sinθ cos θ = sin 2 θ.)
Answers
The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.
Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.
It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).
Here, t is the time of flight of the bullet and g is the acceleration due to gravity.
As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.
On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.
Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.
Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.
Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.
Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.
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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.
Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.
It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).
Here, t is the time of flight of the bullet and g is the acceleration due to gravity.
As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.
On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.
Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.
Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.
Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.
Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.
As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.
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A perfectly inelastic demand curve Multiple Choice graphs as a line parallel to the vertical axis. has a price elasticity coefficient greater than unity. has a price elasticity coefficient of unity throughout. graphs as a line parallel to the horizontal axis.
Answers
A perfectly inelastic demand curve graphs as a line parallel to the vertical axis.
How does a perfectly inelastic demand curve graph?A perfectly inelastic demand curve is a type of demand curve where the quantity demanded remains constant regardless of changes in price. In other words, the demand is completely unresponsive to price changes. When graphed, a perfectly inelastic demand curve appears as a vertical line parallel to the vertical axis.
This means that no matter how much the price of a product or service changes, the quantity demanded by consumers remains the same. The price elasticity of demand coefficient for a perfectly inelastic demand curve is zero because there is no change in quantity demanded relative to price changes.
A perfectly inelastic demand curve is often seen in the case of essential goods or products with no close substitutes, where consumers are willing to pay any price to obtain the item. Examples may include life-saving medications or specific medical treatments.
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fraction that occurs in gases and liquids is called what
plzz help meeeee
Answers
Answer:
it is called fluid friction.
It is estimated that a driver takes, on average, 1.5 seconds from seeing on obstacle to react by applying the brakes to stop or swerving. How far will a car, moving at 26 miles per hour in a residential neighborhood, travel (in feet) before a driver reacts to an obtacle? (round distance to one decimal place) feet
Answers
Answer:
The car was 132 feet far before the driver reacts to an obstacle.
Step-by-step explanation:
Given,
The speed of car = 60 miles per hour,
Also, time taken by the car to reacting the
obstacle =1.5 seconds = 3600 = 2100 hours
(1 hour = 3600 seconds )
We know that,
Distance = Speed × Time,
Hence, the distance of car from the obstacle before reacting the obstacle
= 60 × 2100
60
2400
# miles
Since, 1 mile = 5280 feet
= # miles = $280 = 132 feet
Therefore, the car would 132 feet far from the obstacle.
Energy from the sun drives the _ of the water from the ocean surface. As the air moves up the west side of the mountain, the water vapor cools and undergoes _ . The force of gravity causes the _ of the water from the cloud. Choices for the _ are condensation, evaporation, precipitation
Answers
Answer: The air is full of water, as water vapor, even if you can't see it. Condensation is the process of water vapor turning back into liquid water, with the best example being those big, fluffy clouds floating over your head. And when the water droplets in clouds combine, they become heavy enough to form raindrops to rain down onto your head.
Explanation:
cuales son las características de un generador eléctrico?
Answers
Answer:
Los generadores eléctricos funcionan según el principio de inducción electromagnética. Una bobina conductora (una bobina de cobre enrollada firmemente sobre un núcleo de metal) se hace girar rápidamente entre los polos de un imán tipo herradura. La bobina conductora junto con su núcleo se conoce como armadura.
you ran out of gas and are trying to push your car to a gas station, once you get the car moving, what force opposes your push?
Answers
The moves your car forward is the effect of static friction. The power needed to move the tires, which would in turn pushes the vehicle backward against the road, comes from the engine.
What is force example?Force is the term used to describe a body's tendency to alter or alter its state as a result of an external cause. When force is applied, the body could also alter its size, shape, and direction. hitting a football, pushing and pulling on the door, or kneading dough are a few examples.
What causes force?A push in pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on all of the materials. The force is no longer felt by the two surfaces when the interaction ends.
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A balloon is inflated by blowing air into it. Explain what would happen if an inflated balloon was put in a freezer.
Answers
Answer:
The air was blew into the balloon, which means that it was above room temperature. The space between particles is warm are far apart, so the air in the balloon is fully spaced out.
If you were to place the balloon inside of a freezer, then the space between the particles would close in and cause the balloon to shrink, similar to the picture below.
I hope this helped & Good Luck <3!!
PLEASE HELP!!!!!!!!!!!
Answers
Answer:B is the right answer because you the object dose not stay still unlike the other answers
Explanation:
Help meeeeeeeeeeeeee
Answers
When is the best time to take a resting heart break
A. One hour after eating a meal.
B. Just before going to bed at night.
C. One hour after vigorous exercise.
D. Just after waking in the morning.
Answers
Answer:
I believe D
Explanation:
You need to have a more accurate reading and you want to test it multiple times throughout the week though to get a base resting rate.
I hope this is correct good luck!
Using the formula for the resonant frequency, find the resonant frequency of a lcr circuit with l = 1 mh, c = 560 pf?
Answers
For LCR circuit, the Resonant frequency is 212.68kHz.
Given LCR circuit has L= 1 mH, C= 560pf
f=1/{2*22\7*√[1×10^(-3)H]*√[56*10^(-12)F]
f=212.68kHz
About Resonance frequency:
Equation f = 1 / [2π×√(LC)] can be used to calculate the resonant frequency of the RLC circuit, where:
f is the resonant frequency.L is the inductor's inductance.C is the capacitor's capacitance.The frequency at which the transfer function reaches its highest value is known as the resonant frequency of an electrical system. Consequently, the greatest output for a given input can be obtained. It has been demonstrated that resonance occurs when the values of the capacitive and inductive impedances are equal.
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Deon is running at a velocity of 5.4 meters per second. Deon has a total mass of 95 kilograms—including his helmet, uniform, and pads. If Deon runs directly into Chuck, who has a total mass of 120 kilograms and is standing still, what is the momentum of the Deon-Chuck system after the collision? Assume momentum is conserved.
Answers
The law of conservation of momentum states that the momentum of a system is equal and conserved before and after collision. Therefore, the final momentum of the system is 513 kgm/s.
What is the law of conservation of momentum?The law of conservation of momentum states that, for two or more bodies which are present in an isolated system that are acting upon each other, their total momentum remains constant in the system unless an external force is applied on them. The expression for conservation of momentum is:
m₁ u₁ + m₂u₂ = m₁v₁ + m₂v₂
where, m₁ = mass of one object,
m₂ = mass of another object,
u₁ and u₂ are the initial velocities of objects,
v₁ and v₂ are the final velocities of objects.
Here, m₁ = 95kg, m₂ = 120kg
u₁ = 5.4m/s, u₂ = 0m/s (at rest)
m₁ u₁ + m₂u₂ = m₁v₁ + m₂v₂
95 × 5.4 + 120 × 0 = 95 × v₁ + 120 × v₂
513 + 0 = 95 × v₁ + 120 × v₂
Momentum before collision = Momentum after collision
Therefore, the momentum after collision is 513 kgm/s.
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a crate is sliding down an inclined ramp at a constant speed of 0.55 m/s. the vector sum of all the forces acting on this crate must point:
Answers
Answer:
The net force on the object is zero
Explanation:
An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".
Choose the correct term to complete each blank.
It is (Harder/easier) to push an empty wheelbarrow than one filled with dirt. Because the dirt-filled wheelbarrow has more (Force/Speed/Mass) than the empty one, it requires more (Force/Inertia/Acceleration) to push at the same speed. A wheelbarrow containing grass clippings will require (More/Less/The Same) force to push at the same speed than a dirt-filled one because the grass clippings have less mass than dirt. Either wheelbarrow will require more force to push it uphill than downhill due to the effect of
(Friction/Inertia)
Answers
Explanation:
It is (Harder/easier) to push an empty wheelbarrow than one filled with dirt. Because the dirt-filled wheelbarrow has more (Force/Speed/Mass) than the empty one, it requires more (Force/Inertia/Acceleration) to push at the same speed. A wheelbarrow containing grass clippings will require (More/Less/The Same) force to push at the same speed than a dirt-filled one because the grass clippings have less mass than dirt. Either wheelbarrow will require more force to push it uphill than downhill due to the effect of (Friction/Inertia)
An object of mass 10 kg, initially at rest, experiences a constant horizontal acceleration of 4 m/s2 due to the action of a resultant force applied for 20 s. Determine the total amount of energy transfer by work, in kj.
Answers
So, the total energy value that has been transferred by work is 32 kJ.
IntroductionHi ! In this question, I will help you. Work is the amount of force exerted to cause an object to move a certain distance from its starting point. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :
\( \boxed{\sf{\bold{W = F \times s}}} \)
With the following condition :
W = work (J)F = force (N)s = shift or displacement (m)Now, because in this question, the "s" is not directly known, whereas it is known that the initial velocity is zero, the object has an acceleration, and is moving in certain time intervals. Then, use this formula to find the value of "s" !
\( \boxed{\sf{\bold{s = \frac{1}{2} \times a \times t^2}}} \)
With the following condition :
s = shift or displacement (m)a = acceleration (m/s²)t = interval of the time (s)Problem SolvingWe know that :
a = acceleration = 4 m/s²t = interval of the time = 20 sm = mass = 10 kgWhat was asked :
W = work = ... kJStep by Step :
Calculate value of force by multiple m and a\( \sf{F = m \times a} \)
\( \sf{F = 10 \times 4} \)
\( \sf{\bold{F = 40 \: N}} \)
Calculate value of shift or displacement\( \sf{s = \frac{1}{2} \times a \times t^2} \)
\( \sf{s = \frac{1}{\cancel 2} \times \cancel 4 \:_2 \times 20^2} \)
\( \sf{s = 2 \times 400} \)
\( \sf{\bold{s = 800 \: m}} \)
Last, calculate the value of work\( \sf{W = F \times s} \)
\( \sf{W = 40 \times 800} \)
\( \boxed{\sf{W = 32,000 \: J = 32 \: kJ}} \)
So, the total energy value that has been transferred by work is 32 kJ.
Physics mcq please be sure
Answers
Answer:
1. c 2.d
Explanation:
we did this in middle school
what would happen to tidal ranges if the moon were farther away from the earth?
Answers
If the moon were farther away from the earth, tidal ranges would be smaller. This is because the gravitational pull of the moon is what creates tides on earth.
As the moon gets farther away, its gravitational pull on the earth decreases, resulting in weaker tides. Conversely, if the moon were closer to the earth, tidal ranges would be larger. This is because the gravitational pull of the moon would be stronger, causing more dramatic tides.
If the moon were farther away from the Earth, the tidal ranges would be smaller. This is because the gravitational pull of the moon, which significantly influences the tides, would be weaker at a greater distance from the Earth. Consequently, the difference between high and low tides would decrease.
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A doctor specializes in surgery involving the lungs and heart. For which level of organization is this doctor specialized? A.atoms
B. cells
C. organs
D. tissues
Answers
Answer:
C
Explanation:
The lungs and heart are organs
For horizontally-launched projectiles, which of the following describes acceleration in both directions with a⃗ x=0 and a⃗ y=−9.8 m/s2.
A. Acceleration is −9.8 m/s2
in both directions.
B. Acceleration is constant in both directions.
C. Acceleration is equal in both directions.
D. Acceleration is zero in both directions.
Answers
The motion of projectiles shows that acceleration is constant in both directions; option B.
What is projectile motion?Projectile motion refers to the motion of projectiles in a curved path or parabola under the influence of gravity.
Projectiles are objects which are launched into the air and allowed to fall freely under the effect of the gravitational force of the earth.
For a horizontally-launched projectile with acceleration in the x-axis or x-direction equal to zero and acceleration u=in the y-axis equal to -9.8 m/s², the object is moving with a constant acceleration in both directions.
In conclusion, the motion of objects which are being launched into the air and allowed to fall freely under the effect of the gravitational force of the earth is known as projectile motion. Projectiles move with constant acceleration in both the x and y directions.
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С
A rocket of mass 1000 kg is travelling through the atmosphere.
The force due to its engine is 1200 N, and the drag force and friction equal 400 N.
The resultant force is 800 N. Calculate its acceleration.
Show your working and give the units. Use the equation:
force
acceleration =
mass
Answers
Answer:
a = 0.8 [m/s²]
Explanation:
To solve this problem we must use Newton's second law which tells us that the resulting force on a body is equal to the product of mass by acceleration, in this way we come to the following equation:
∑F = m*a
where:
F = forces applied [N]
m = mass = 1000 [kg]
a = acceleration [m/s²]
Now using Newton's second law.
\(1200 - 400 = 1000*a\\800 = 1000 *a\\a=0.8[m/s^{2} ]\)
What hanging mass will stretch a 2.9-m-long, 0.48-mm-diameter steel wire by 1.4 mm? The Young's modulus of steel is 20 x 1010 N/m² Express your answer in kilograms. IVE ΑΣΦΑ ➜ ? m 51.67 10 1 kg
Answers
The hanging mass will be 0.101 kg.
The formula for calculating the mass of a hanging wire is given as;
m = (π/4) * [(ρL² /Y) * ΔL + L * Δρ]
where; m is the mass of the hanging weight,
ρ is the density of the wire,
L is the length of the wire,
Y is Young's modulus of the wire,
ΔL is the extension of the wire and
Δρ is the change in the density of the wire.
In this case,
ρ = 7.86 x 10³ kg/m³L
= 2.9 mD
= 0.48 mm
= 0.48 x 10⁻³ m
= 4.8 x 10⁻⁴ mY
= 2.0 x 10¹¹ N/m²ΔL
= 1.4 x 10⁻³ m
Let US calculate the mass of the wire;
A = (π/4) * D²A
= (π/4) * (4.8 x 10⁻⁴)²A
= 1.80955737 x 10⁻⁷ m²ρL
= 7.86 x 10³ kg/m³ * 2.9m
= 22.794 kg Y
= 2.0 x 10¹¹ N/m²m_wire
= ρLA / Lm_wire
= 7.86 x 10³ kg/m³ * 1.80955737 x 10⁻⁷ m² / 2.9m
= 4.9091761 x 10⁻⁴ kg
Let's calculate the mass of the hanging weight using the mass formula.
m = (π/4) * [(ρL² /Y) * ΔL + L * Δρ]
m = (π/4) * [(7.86 x 10³ * 2.9² / 2.0 x 10¹¹) * 1.4 x 10⁻³ + 2.9 * 4.8 x 10⁻⁴]
m = 0.100615775 kg
Therefore, the hanging mass will be 0.101 kg.
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1. What three particles are found in an atom?
Answers
Answer:
Protons, Electrons, and neutrons
Answer:
protons electrons neutrons
Explanation:
in a photoelectric effect experiment, light of frequency f and intensity i results in a current for v > 0 of i. if the intensity i is doubled, the current i...
Answers
In a photoelectric effect experiment, light with frequency f and intensity i results in a current for v > 0 of i. If the intensity i is doubled, the main answer is that the current i will also double.
The photoelectric effect is the emission of electrons from a material when light shines on it.
The intensity of light is directly proportional to the number of photons striking the material.
When the intensity is doubled, the number of incident photons also doubles, which increases the number of emitted electrons and ultimately, the current.
Summary: In a photoelectric effect experiment, if the intensity i is doubled, the current i will also double due to the direct proportionality between intensity and emitted electrons.
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