The respiration rate of a goldfish is measured. The goldfish is then placed in cold water and the respiration rate is measured again

The molality of the toluene is 1.46 mol/kg.

The molality of a solution is its molal concentration. Molal concentration is denoted by m. It is the mol of solute dissolves in 1 Kg solvent.

The depression at freezing point is directly proportional to the molality of the solution. The equation we use for this type of problem is:

ΔT=iKm \(f_m\)

Where,  ΔT \(f_m\) is depression at freezing point, i is Van't hoff factor, m is molality and \(K_f\) is the freezing point depression constant.

Toluene is a non-electrolyte and so the value of i for this is 1.

Depression at a freezing point is given as -13.\(0^0\) and the \(K_f\) is given as 5.12. So, we could calculate the molality of the solution using the equation written above.

Let's plug in the values in the equation:

ΔT=iKm\(f_m\)

-7.51 =1 x5. 12 xm

m = \(\frac{7.51}{5. 12}\)

m = 1.46 m

It means the molality of the solution is 1.46 mol/kg.

Hence, the molality of the solution is 1.46 mol/kg.

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The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.

The electrochemical cell is the cell that is capable of generating the electrical energy from the chemical reactions or by the use of the electrical energy to cause the chemical reaction. The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.  

There are the two types of the electrochemical cells is as follows : the galvanic called the electrolytic cells. the galvanic cell is also called as the voltaic cell.

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When the waters are extremely oligotrophic  the carbon-14 method of determining primary productivity preferred over the oxygen bottle method

The light/dark bottle is a method for comparing dissolved oxygen concentrations before and after primary production. Bottles containing seawater tests with phytoplankton are brooded for a foreordained timeframe under light and dim circumstances.

To quantify complete essential efficiency, analysts frequently utilize the light-dim jug method. Since oxygen is produced during photosynthesis and used in respiration, this method uses changes in the concentration of dissolved oxygen to measure both processes.

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Answer:

Explanation:

Here, we want to get the name for the given chemical formula

Looking at the formula, we look at the names of the element

The names are sodium and fluorine

We write the name of the metal element first, then the non-metal atom

Thus, we have it as

Answer:

40.38 grams

Explanation:

The overall change in entropy for the process is approximately -0.251 J/K.

The change in entropy can be calculated using the formula:

ΔS = nCp ln(T2/T1) + nR ln(V2/V1)

where:

n = 0.13 moles (number of moles of helium in the balloon)

Cp = 5/2R (specific heat capacity of helium gas at constant pressure)

R = 8.314 J/(mol*K) (gas constant)

T1 = 298 K (initial temperature of the helium gas)

T2 = 291 K (final temperature of the helium gas)

V1 = 3.0 L (initial volume of the balloon)

V2 = 3.5 L (final volume of the balloon)

Plugging in the values, we get:

ΔS = (0.13 mol * 5/2 * 8.314 J/(molK)) ln(291 K/298 K) + (0.13 mol * 8.314 J/(molK)) ln(3.5 L/3.0 L)

ΔS = -0.296 J/K + 0.045 J/K

ΔS = -0.251 J/K

Therefore, the overall change in entropy for the process is approximately -0.251 J/K.

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In a galvanic cell, the reaction proceeds towards the production of products.  ΔG starts < 0, becomes more negative

Option B is correct .

As the reaction proceeds, the Gibbs free energy (ΔG) reduces, and the following are true:  ΔG starts < 0, becomes more negative.

When the reaction in a galvanic cell proceeds towards the production of products, the Gibbs free energy starts with a negative value, and it becomes even more negative.

The Gibbs free energy (ΔG) is a measure of the available energy in a system that can be used to do work. It measures the difference between the free energy of the final state and the initial state.The Gibbs free energy change of a system is dependent on the enthalpy and entropy change. If the enthalpy change is negative (exothermic), and the entropy change is positive (disorderly), the Gibbs free energy change is negative, and the reaction is spontaneous.

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Answer:

if my calculation are correct, it's 295 grams

Explanation:

because liters converted to grams is .1=100 so if you take 2.95 times 100, it equals 295

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

Moles of AlPO_4

Moles of Al3+=57.5µmol

Both students have correctly prepared a 1.0 M aqueous solution of potassium phosphate.

To determine which student has correctly prepared a 1.0 M aqueous solution of potassium phosphate (K₃PO₄), we need to compare their procedures.

Jennifer filled a 1.0 liter volumetric flask to calibration line having with water and then weighs out 212.3 g of potassium phosphate to add to the flask.

Joe, on the other hand, weighs out 212.3 g of the potassium phosphate as well as adds it to a 1.0 liter volumetric flask. He then fills the flask to the calibration line with water.

To determine the correct preparation method, we need to consider the molar mass of potassium phosphate (K₃PO₄), which we calculated previously as 212.27 g/mol.

Comparing the two methods;

Jennifer uses the correct amount of potassium phosphate (212.3 g), which corresponds to approximately 1 mole of K₃PO₄.

Joe also uses the correct amount of potassium phosphate (212.3 g), which corresponds to approximately 1 mole of K₃PO₄.

Both students have used the correct amount of potassium phosphate, which matches the molar mass of K₃PO₄. Therefore, both students have correctly prepared a 1.0 M aqueous solution of potassium phosphate.

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--The given question is incomplete, the complete question is

"An experiment in chm 2045 requires students to prepare a 1.0 M aqueous solution of potassium phosphate. Jennifer fills a 1.0 liter volumetric flask to the calibration line with water. She then weighs out 212.3 g of potassium phosphate and adds it to the volumetric flask. Joe weighs out 212.3 g of potassium phosphate and adds it to a 1.0 liter volumetric flask. He then fills the volumetric flask to the calibration line with water. Which student has correctly prepared a 1.0 M aqueous solution of potassium phosphate?"--

Answer:

6.336 mg

Explanation:

.4055 x (1/2)^6 = .006336 gm

Answer:

gold

Explanation:

1. the Earth's core products light to me. I like it. cuz it give.me light.

2. I learned that the fusion from these resources.

The statement "Nuclear fusion begins when a large, unstable nucleus is bombarded with a smaller particle" does not provide more information about nuclear fusion.

Nuclear fusion is a process in which two atomic nuclei come together to form a heavier nucleus. This process releases a tremendous amount of energy. The fusion process occurs at extremely high temperatures and pressures, similar to those found in the core of stars.

The other statements provide important information about the source of energy in our Sun, the environmental advantages of nuclear fusion over fossil fuel combustion, and the role of nuclear fusion in the formation of elements in the periodic table.

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Image transcribed:

4 ¹H --->1 ⁴He + energy-    

Nuclear fusion, like the example here, produces huge amounts of energy. Consider the statements below. Which ONE statement DOES NOT provide more information about nuclear fusion?

Nuclear fusion is the source of energy in our Sun.

Nuclear fusion when used as an energy source does not produce particulate matter pollution like fossil fuel combustion.

Nuclear fusion begins when a large, unstable nucleus is bombarded with a smaller particle.

Nuclear fusion is responsible for the formation of the elements we classify in the periodic table.

The chemical equation for the synthesis of CH3 CH3 'N CH3 by reductive amination of an appropriate aldehyde or ketone can be written as follows:

CH3CHO + CH3NH2 + NaBH4 → CH3 CH3 'N CH3 + NaOH + BH3

To synthesize the amine CH3 CH3 'N CH3 by reductive amination of an appropriate aldehyde or ketone, the following steps should be followed:

Step 1: Find an appropriate aldehyde or ketone for reductive amination, in this case, CH3CHO can be used. It is suitable as it contains a carbonyl group (-CHO) that can be easily reduced to an amine.

Step 2: Use an appropriate reducing agent to reduce the carbonyl group. Sodium borohydride (NaBH4) is an excellent reducing agent in this case. Sodium borohydride reduces the carbonyl group to an alcohol group (CHO -> CH2OH).

Step 3: React the alcohol group with an amine. To synthesize CH3 CH3 'N CH3, methylamine (CH3NH2) can be used as the reactant. The reaction of an alcohol group with an amine is known as reductive amination. Reductive amination converts the alcohol group into an amine.

Step 4: Purify the synthesized amine. Distillation is the best technique for purifying the synthesized amine. Distillation separates the synthesized amine from other impurities, including the reactants.

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Answer:

Both

Explanation:

The combined gas law is also known as the general gas law.

From the ideal gas law we assume that n = 1;

So;

              PV  = nRT

 and then;

                  \(\frac{P_{1}V_{1} }{T_{1} }\)  = \(\frac{P_{2}V_{2} }{T_{2} }\)

   If we cross multiply;

                P₁V₁T₂   = P₂V₂T₁

  So;

         T₁ = \(T_{2} \frac{P_{1}V_{1} }{P_{2} V_{2} }\)

Also;

         V₂  = \(V_{1} \frac{P_{1} T_{2} }{P_{2} T_{1} }\)

So from the choices both are correct

Answer:

The enthalpy of reaction is -185 kJ

Explanation:

To get the reaction:

 H₂(g) + Cl₂(g) → 2 HCl(g)

you must follow the following steps:

1)  Reactive molecules must break their bonds to obtain their atoms.

H₂(g) → 2 H(g)

Cl₂(g) → 2 Cl(g)

Bond energy (or enthalpy) is the energy required to break one mole of bonds of a gaseous substance. In the case of diatomic molecules with a single bond, it corresponds to the energy necessary to dissociate 1 mole of said substance in the atoms that form it.

Whenever you want to break links you must supply energy, so the link enthalpy will have positive values; while when a mole of bonds is formed energy is released and the bond enthalpy of this process will be negative.

In this case you will then have:

H₂(g) → 2 H(g)           ΔH=436 kJ/mol

Cl₂(g) → 2 Cl(g)         ΔH=243 kJ/mol

So the total energy needed to break all the bonds is:

ΔH=1 mol*436 kJ/mol +1 mol* 243 kJ/mol= 679 kJ

2) The atoms that were obtained in the break of the bonds must be combined to obtain the product.

2 H (g) + 2 Cl (g) → 2 HCl (g)

Being the single bond energy for one mole of 431 kJ H-Cl bonds and considering that two moles of H-Cl bonds are formed, the ΔH is:

ΔH = -2 moles* (432 kJ/mol) = -864 kJ

As mentioned, when a mole of bonds is formed energy is released, the bond enthalpy of this process will be negative.  So the formation of HCl is negative.

Hess's law states that the energy change in an overall chemical reaction is equal to the sum of the energy changes in the individual reactions comprising it. So:

ΔHtotal= -864 kJ + 679 kJ

ΔHtotal= -185 kJ

The enthalpy of reaction is -185 kJ

When bonds are created in the products of exothermic processes, more energy is produced than is required to break the bonds between the reactants. The reaction mixtures' temperature rises during this process.

the power needed to dissolve the link in the already-existing reactants, raising their level of activation. Activation energy is the substance needed to accomplish this.

Heat and/or light energy must be absorbed in order to break a bond. Some chemical bonds are broken and new ones are established during a reaction.

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The patient recieves 2.4 g Tigan in 2 days

In finding the conversion units, we can multiply and eliminate the same units so that we can get the desired quantity or unit.

In this case, it is expected that the number of Tigan is known in 2 days, so we just need to multiply the numbers that are known

\(\tt =300\dfrac{mg}{capsules}\times \dfrac{1~capsules}{dose}\times 4.0\dfrac{doses}{day}\times 2.0~days\\\\=300\times 1\times 4.0\times 2.0~mg=2400~mg=\boxed{\bold{2.4~g}}\)

Answer:

5 A1C13(aq) + 3 MnCl2(aq) + 3 KCl(aq) + 8 H20(1)

Explanation:

the products are on the right side of the arrow

Heat of vaporization is the amount of heat energy required to convert a substance from its liquid state to its gaseous state at a constant temperature and pressure. It is a measure of the strength of the intermolecular forces holding the molecules together in the liquid phase.

Heat of vaporization:

Heat of vaporization is the amount of heat energy required to convert a substance from its liquid state to its gaseous state at a constant temperature and pressure. It is a measure of the strength of the intermolecular forces holding the molecules together in the liquid phase.

When a substance is heated, the added energy increases the kinetic energy of the molecules, causing them to move faster. As the temperature rises, the average kinetic energy of the molecules increases, and eventually, the molecules have enough energy to overcome the intermolecular forces and escape from the liquid phase, forming a gas.

The heat of vaporization is specific to each substance and is typically expressed in units of joules per gram (J/g) or calories per gram (cal/g). It is an important property in various applications, such as in the design of cooling systems, understanding phase changes, and calculating energy requirements for processes involving vaporization.

Fact:

The heat of vaporization for water is approximately 40.7 kilojoules per mole (kJ/mol) at its boiling point of 100 degrees Celsius.

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The heat of vaporization is the amount of heat required to convert one gram of a substance from its liquid state to its gaseous state without any change in temperature. It is denoted by delta Hvap.

This is a measure of the energy that is required to overcome the intermolecular forces that hold a liquid together and break the bonds between the molecules to form a gas.Heat of vaporization is the amount of heat required to convert one gram of a substance from its liquid state to its gaseous state without any change in temperature.

There are many interesting phenomena where the heat of vaporisation can be seen. For instance, heat is continuously added to liquid water when it boils on a hob in order to overcome the intermolecular interactions and turn it into water vapour. Similar to how sweat evaporates from our skin, the heat that is removed from us as the sweat changes from a liquid to a gas cools us down.

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Benefits of using micro-scale techniques is that they offer a high level of precision and control in scientific experimentation. By using micro-scale techniques, researchers can manipulate small amounts of materials and samples, allowing them to perform experiments with a greater degree of accuracy and repeatability.

This can be especially useful in fields such as biology and chemistry, where even small variations in experimental conditions can have a significant impact on the results.Benefits of using micro-scale techniques is that they can reduce the cost and time required for experimentation. By using smaller samples and less reagents, researchers can save money on materials and reduce the time required for experiments to be completed. In addition, micro-scale techniques can be more environmentally friendly, as they require less waste and energy to produce.

Benefits of micro-scale techniques could include examples of specific applications in various scientific fields, such as microfluidics for drug discovery or microscale electrophoresis for DNA analysis. It could also discuss how micro-scale techniques are advancing research in areas such as nanotechnology and biomedicine, and how they are helping to solve some of the world's most pressing scientific challenges. Overall, the benefits of using micro-scale techniques are numerous and varied, and they are likely to continue to play an important role in scientific experimentation for years to come.

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For Co³⁺, the equation that shows how the cation acts as an acid is given as follows:  Co³⁺ + + H₂O → [HCoO₂]⁺ + [H]⁺

Co³⁺ + + H₂O → [HCoO₂]⁺ + [H]⁺

In the above chemical equation, Co³⁺ is the cation that acts as an acid. It reacts with water to form the hydrated cation [HCoO₂]⁺ and [H]⁺ ions as shown in the equation. The [HCoO₂]⁺  is also known as hydrated cobalt (III) cation. The reaction is an acid-base reaction in which the Co³⁺ ion donates a proton to the water molecule, making it act as an acid.

In the above chemical equation, the phases of the reactants and products are given as follows:

Co³⁺ (aq) + H₂O (l) → [HCoO₂]⁺ (aq) + H⁺ (aq), where, "aq" denotes the aqueous phase and "l" denotes the liquid phase.

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Answer:

A. Distance = 18 m

    time = 2 hr

    speed = 9 m/hr

Explanation:

Speed is the same thing as velocity.

Velocity = distance/time

18m/2hr = 9m/hr

For choice B, the numbers are right, but the units are mixed (minutes were changed to hours)

True because you can be precise with the same measurements but they can be not the correct area so

it should be TRUE

Explanation:

green is dominate and theres a G in each box that makes it all Green

it is A it got to be A)-4k

Explanation: