The procedure for a reaction directs you to use 0.035 mol of the liquid ester, methyl benzoate (M.W. 136.15, d1.094 g/mL ), in your reaction. How many mL of methyl benzoate would you need to measure in a graduated cylinder in order to have the required number of mols ([0.035 mol) ? Enter your answer using one decimal places (6.8), include zeroes, as needed. Include the correct areviation for the appropriate unit Answer:

Answer:

Physical changes are those in which the shape, size, or state of the matter changes, but the substance is still essentially the same. Chemical changes are those where one or more substances are combined to produce a new substance.

Explanation:

For example, chopping up a carrot or ice melting into water are both physical changes. Chemical changes are those where one or more substances are combined to produce a new substance. At the end of a chemical change, you have a new substance. Burning a piece of paper would be a chemical change, as would baking a cake. Ozone is an invisible gas made of 3 oxygen atoms.

Answer:

protons and neutrons are the answer

Answer:

a) Y³⁺ > Eu²⁺ > Fr⁺ > Sr²⁺

b) Sr > Fr > Eu > Y

Explanation:

Y is the least reactive metal because it does not react with any of the other solutions.

Sr is the most reactive metal because it reacts with all of the other solutions.  

Sr + 2Fr⁺ ⟶Sr²⁺ + 2Fr

3Sr + 2Y³⁺ ⟶ 2Sr²⁺ + 2Y

Sr + Eu²⁺ ⟶ Sr²⁺ + Eu

Fr is more reactive than Eu because it reacts with Eu(NO₃)₂.

2Fr + Eu²⁺ ⟶ 2Fr⁺ + Eu

The order of reactivity is

Sr > Fr > Eu > Y

b) Reducing agents

In each of the above reactions. the more reactive metal is acting as a reducing agent — it is donating electrons to the cation of the other metal.

Thus, the order of activity of reducing agents is

Sr > Fr > Eu > Y

a) Oxidizing agents

The metal cations are the oxidizing agents.

The order of reactivity of the oxidizing agents is the reverse order of the reducing agents

Y³⁺ > Eu²⁺ > Fr⁺ > Sr²⁺

c) Standard reduction potential table

See the image below.

When the nuclide strontium-80 decays by electron capture, the name of the product nuclide is Zirconium-80, and the symbol for the product nuclide is 80Zr.

In atomic physics, electron capture is a phenomenon that occurs when an electron merges with a nucleus and a neutrino to generate a neutron. The process takes place inside the nucleus, and it is one of the mechanisms for radioactive decay of atoms.

The process of electron capture takes place when the nuclide is not in the lowest energy state. This occurs mostly in atomic nuclei with a large neutron-to-proton ratio, such as isotopes of polonium, tin, and iodine. Nuclide strontium-80 is a nuclide that has 38 protons and 42 neutrons.

When this nuclide decays by electron capture, it results in the formation of a product nuclide. The product nuclide is Zirconium-80, which has 40 protons and 40 neutrons.

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The smallest angle, measured from the reflecting planes, at which constructive interference of an X-ray beam is observed is approximately 27.2 degrees.

To determine the smallest angle of constructive interference, we can use Bragg's Law, which states that constructive interference occurs when the path difference between two waves is equal to an integer multiple of the wavelength. The formula is given as:

2d sin(θ) = nλ

Where:

d is the distance between the reflecting planes (0.541 nm)

θ is the angle between the incident X-ray beam and the planes (the desired angle)

n is the order of the interference (we are considering the first-order, so n = 1)

λ is the wavelength of the X-ray beam (0.0649 nm)

Rearranging the formula, we get:

sin(θ) = (nλ) / (2d)

θ = arcsin((nλ) / (2d))

Plugging in the values, we have:

θ = arcsin((1 * 0.0649 nm) / (2 * 0.541 nm))

θ ≈ 27.2 degrees

Therefore, the smallest angle at which constructive interference is observed is approximately 27.2 degrees.

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The statement that is incorrect about ionic compounds is: "ionic bonds involve the sharing of electrons by metals and nonmetals."

Ionic bonds are not formed by the sharing of electrons, but rather by the transfer of electrons from a metal to a nonmetal. The metal loses one or more electrons to form a positive ion (cation), and the nonmetal gains those electrons to form a negative ion (anion). The attraction between these opposite charges forms the ionic bond and holds the ionic compound together.

All the other statements are correct:

Ionic compounds include table salt (NaCl), calcium carbonate (CaCO3), and sodium bicarbonate (NaHCO3).

Ions are formed when ionic solids dissolve in water.

Between metals and nonmetals, ionic bonds form.

The attraction of positive and negative ions holds ionic compounds together.

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Answer:

D. lysosome

Explanation:

hope it helps :D

sorry if its wrong :/

Answer:

Frequency = Velocity / Wavelength

or

f = v / λ

The new pH of the buffer solution after adding 0.0020 mol of HCl to 0.250 L of the solution is 9.10.

First, we need to calculate the initial concentrations of the base and its conjugate acid in the buffer solution:

\(K_a = \frac{[H^+][B^-]}{[BH^+]}\)

Since we know the pH of the buffer solution, we can use the following equation to calculate the concentration of H+ ions:

\(\begin{aligned}\mathrm{pH} &= -\log{[\mathrm{H}^+]} \\\mathrm{H}^+ &= 10^{-\mathrm{pH}} \\\mathrm{H}^+ &= 10^{-8.94} = 1.23 \times 10^{-9} \ \mathrm{mol/L}\end{aligned}\)

Since the buffer contains equal concentrations of base and its conjugate acid, we can assume that [B-] = [BH+]. Let x be the concentration of both species:

\(\frac{x^2}{(0.455L + 0.228L)} &= 1.23 \times 10^{-9} \\\)

\(x^2 &= 7.07 \times 10^{-10} \\\)

\(x &= 8.41 \times 10^{-6} \ \mathrm{mol/L}\)

Now, we need to calculate the new concentrations of the buffer species after adding 0.0020 mol of HCl to 0.250 L of the buffer solution:

\(\mathrm{BH^+} + \mathrm{H^+} \rightarrow \mathrm{B^-} + \mathrm{H_2O}\)

Initial concentration of \(\mathrm{BH^+} = 8.41 \times 10^{-6} \ \mathrm{mol/L}\)

Concentration of H+ added = 0.0020 mol / 0.250 L = 0.0080 mol/L

Assuming that the volume change upon adding the acid is negligible, we can use an ICE table to calculate the new concentrations:

\([BH$^+$] & [H$^+$] & [B$^-$]\)

\(& $8.41\times10^{-6}$ M & 0.0080 M & $8.41\times10^{-6}$ M \\)

\(-0.0080$ M & $-0.0080$ M & $+0.0080$ M\)

\(8.41\times10^{-6}$ M & 0 & $8.41\times10^{-6}$ M $+0.0080$ M\)

Final concentration of \(BH$^+$ = $8.41\times10^{-6}-0.0080=-0.00799$ M\)

(Note that the negative value indicates that the concentration of BH+ is now effectively zero.)

Final concentration of \(B$^-$ = $8.41\times10^{-6}+0.0080=0.0080$ M\)

To calculate the new pH, we can use the Henderson-Hasselbalch equation:

\($pK_a = -\log(K_a) = -\log(7.07\times10^{-10}) = 9.15$\)

\($pH = 9.15 + \log\left(\frac{0.0080}{8.41\times10^{-6}}\right) = 9.10$\)

Therefore, the new pH after adding 0.0020 mol of HCl to 0.250 L of the buffer solution is 9.10.

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Answer:

here u go! ................

Answer:

Hope this is ok :))

Explanation:

The equation that represents a single replacement reaction given the various options is 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

A single replacement reaction, also known as single displacement reaction is a reaction in which elements higher in the electro-chemical series displace or replace elements lower in the electro-chemical series displace from a solution.

The following example illustrates single replacement reaction:

A + BC -> AC + B

From the above reaction, we can see that A has replace/displace B to from AC.

With the above information, we can determine the equation that represents single replacement reaction. Details below:

Equation from the questions:

From the above, we can see that only 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) conform to single replacement reaction.

Thus, the correct answer to the question is: 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

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The mole fraction of ethylene glycol is 0.203.

The mole fraction represents the number of moles of a specific component divided by the total number of moles present in the given solution.

It is a method of expressing the concentration of a solution

Mole fraction can be represented by x. Let a solution consists of components A and B then, the mole fraction is

\(Mole fraction of solute, n_A = \frac{n_A}{n_A+n_B}\)

\(Mole fraction of solvent, n_B = \frac{n_A}{n_A+n_B}\)

The molar mass of ethylene glycol = 62 g

Given the mass of ethylene glycol = 2.109 x 10³ g

The molar mass of water = 18 g

Given the mass of water= 2.40×10³ g

No moles of ethylene glycol,  \(n_A\) = \(\frac{2.109 \times 10^3 g}{62 g}\)

                                                =34.02

No of moles of water, \(n_B\) = \(\frac{2.40 \times 10^3 g}{18 g}\) = 133.33

Mole fraction of ethylene glycol = \(x = \frac{n_A}{n_A +n_B}\)  = \(\frac{34.02}{34.02+133.33} = \frac{34.02}{167.35}\)

                                                      =  0.203

Hence, The mole fraction of ethylene glycol is 0.203

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Answer:

The fly cells must be compared with human cells

Explanation:

Dr. Gracia's aim is the development of a potential cancer treatment. Remember that the treatment is meant for human beings.

Usually, the pre-clinical trials of the treatment is carried out on other organisms and the success rate is evaluated before trial on humans.

If protein W has been effective on flies, its effect on human cells should also be diligently compared before conclusions are drawn regarding the therapeutic effects of protein W.

For the sample of n sludge specimens is selected and the conclusion and the pH of each one is determined.

A) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

B) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

C) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

D) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

E) The null hypothesis is rejected. Sufficient evidence is present for the fact that the true average pH is less than 7.0.

The null hypothesis in inferential statistics is that two possibilities are always equal. It shows that the underlying assumption is that the observed difference is just the result of chance. It is possible to estimate the probability of the null hypothesis is correct using statistical tests.

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Answer:

Mg  

Explanation:

The standard reduction potentials are

                                              E°/V

Au³⁺(aq ) + 3e⁻  ⟶  Au(s);     1.42

Hg²⁺(aq)  + 2e⁻  ⟶  Hg(l);     0.85

Ag⁺(aq)    +   e⁻  ⟶  Ag(s);    0.80

Cu²⁺(aq)   + 2e⁻ ⟶  Cu(s);   0.34

Mg2+(aq) + 2e- ⟶  Mg(s);   -2.38

The more negative the standard reduction potential, the stronger the metal is as a reducing agent.

Mg is the only metal with a standard reduction potential lower than that of Cu, so

Only Mg will react spontaneously with Cu²⁺.

Answer:

B. Mg

Explanation:

Answer:

3 sig figs

Explanation:

Answer: If both parents are heterozygous for freckles, then they each have a genotype of Ff. This means that each parent has one dominant allele for freckles and one recessive allele for no freckles. When these two parents mate, their offspring will have a genotype that is a combination of the genotypes of the two parents.

Explanation:

There are four possible combinations of genotypes that the offspring could have: FF, Ff, ff, and Ff. The first three genotypes are possible because each parent has a 50% chance of passing on each of their two alleles to their offspring. The fourth genotype, Ff, is possible because the offspring could inherit one F allele from one parent and one f allele from the other parent.

The genotype ratios for the offspring of these two heterozygous parents would be 1:2:1. This means that there is a 25% chance that an offspring will have the genotype FF, a 50% chance that it will have the genotype Ff, and a 25% chance that it will have the genotype ff.

The phenotype ratios for the offspring of these two heterozygous parents would be 3:1. This means that 75% of the offspring will have freckles, and 25% of the offspring will not have freckles. This is because the genotypes FF and Ff both result in the freckles phenotype, while the genotype ff results in the no freckles phenotype

(a) distance measured with metre rule or tape rule

    time measured with stopwatch/ stop clock/ timer

    Average speed = total distance / time

(b) (i) decrease in speed

    (ii) Change in speed = a * t

        4.5 m/s

hope this helps......

Answer:

Distancia = 925 metros.

Explanation:

Dados los siguientes datos;

Tiempo = 50 segundos

Velocidad = 18.5 m/s

Para encontrar la distancia recorrida;

Matemáticamente, la distancia viene dada por la fórmula;

\( Distancia = velocidad * tiempo \)

Sustituyendo en la fórmula, tenemos;

\( Distancia = 18.5 * 50 \)

Distancia = 925 m.

Por tanto, el cuerpo recorrió una distancia de 925 metros.

Formation of ammonium acetate and water occurs when aqueous solutions of ammonia and vinegar are mixed, the

Ammonia, which has the chemical formula NH₃, is a weak base, while vinegar, which is a solution of acetic acid (CH₃COOH) in water, is an acid. When the two solutions are mixed, a neutralization reaction occurs, in which the ammonium ion (NH⁴⁺) from ammonia combines with the acetate ion (C₂H₃O²⁻) from vinegar to form ammonium acetate (NH₄C₂H₃O₂) and water (H₂O).

The balanced chemical equation for the reaction is,

NH₃(aq) + CH₃COOH(aq) → NH₄C₂H₃O₂(aq) + H₂O(l)

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Explanation

As temperatures rise, glaciers melt faster than they accumulate new snow. As these ice sheets and glaciers melt, the water eventually runs into the ocean, causing sea level to rise. Icebergs and frozen seawater also melt in warm temperatures but are not significant contributors to sea level rise.

When glaciers collapse and pieces of glacial ice fall into the ocean, they are called icebergs. Because the water from melting glaciers is held on land, the runoff greatly raises the volume of water in the ocean, causing a rise in sea level.

The enormous ice sheets that are present in Greenland and Antarctica are also referred to as glaciers. Glaciers melt more quickly as temperatures rise than they can store new snow. As these glaciers and ice sheets melt, the water eventually enters the ocean, raising the sea level.

Changes in the amount of sea ice can impede the regular flow of the ocean, which can impact the climate globally. The polar regions are the most vulnerable regions on Earth to climate change because even a slight temperature increase can cause larger warming over time.

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Answer: It's the circulatory system

Explanation:

Answer:

na + B2 = t

Explanation:

Answer:

2NaN3→ 2Na + 3N2 is the balanced equation

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The visual indicator that enough of a drying agent , such as anhydrous MgSO4 or CaCl2 has been added to properly dry an organic solution is that the drying agent will move freely like a powder around the solution .

Because the anhydrous form is hygroscopic ( readily absorbs water from the air ).

What is the work of anhydrous magnesium sulphate ?

Magnesium sulphate is frequently used in the laboratory as an indicator, especially after aqueous work-up . aqueous work-up is a common technique in the lab to get rid of residual impurities after completion of a reaction . for this the organic reaction is cooled to room temperature and mixed with water .specific impurities will then diffuse into the aqueous phase and can be separated with a separatory funnel .

unfortunately some residual water will stay in the organic phase and this can have negative impact for characterization of compound . therefore Magnesium sulphate is added ,which is able to catch the residual water in its crystal lattice .after filtration of the solid magnesium sulfate ,the water is reduced to non-significant amount and the compound ready for further investigation.

Similarly , calcium chloride is strongly hygroscopic ( absorbs water from the environment ) , so it removes moisture from the air ,making it dryer . this results in water  in the substance to be dried to evaporate into the drier air and this cycle repeats until the system reaches an equilibrium.

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Answer:

A. The largest value is 7 and the smallest value is 1. Find the difference. 7 - 1 = 6.

Explanation:

The period 2 elements which have atomic numbers 3-10 are Lithium (Li) and fluorine (F). The period 3 elements which have atomic number 1 - 18 are Sodium (Na) and Argon (Ar). The Period 3 elements have the highest electron affinities than period 2 elements.

The term element is defined as a substance that cannot be broken down into a simpler substance. They are differentiate by a unique atomic number.

The term atomic radius is defined as the distance from the atom's nucleus to the outermost shell of the electron cloud. The atomic radius decreases along with a period and increases down a group.

1 element which have atomic numbers 1, 3, 11, and 19 are alkali metals. Members of group 18 have eight valence electrons in their orbit.

Thus, The period 2 elements which have atomic numbers 3-10 are Lithium (Li) and fluorine (F).

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LEAST TO MOST POLAR- hexane,diethyl ether,acetone,n-propanol,water ,methanol

Considering the problem  we can say that the kids are compared to be more polar or smaller molecular weight compounds. The more polar compounds interact with silica more just as the kids bus stopped at every point and reached the destination late. Whereas, the adult bus is compared to be less polar compounds or high molecular weight which interacts less and reaches the destination faster.

Thus more polar compounds reaches the destination late whereas less polar compound reaches first.

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Answer: Polonium, Tellurium, Selenium, Sulfur

Explanation:

In our periodic trend, we know the ionization energy increases as we go left --> right and bottom --> top. In this example, in Group 16, sulfur is above the other 3.

The azide ion, Nsubscript3 superscript1-, is a symmetrical ion

Five valence electrons make up nitrogen.

The ion has a total of 16 valence electrons (5 * 3 + 1), making it symmetrical.

We will use all 16 of the valence electrons if we give three pairs of electrons to the two terminal N atoms to complete their octets. However, there are only 4 shared valence electrons on the core nitrogen atom.

1. N atoms can have two double bonds placed between them.

2. The central N atom can create a single bond and a triple bond with the right and left N atoms, respectively.

3. The central N atom has the ability to create single and triple bonds with the left and right N atoms, respectively.

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