The potential of the electric field produced by point charge at any point (x,y,z) is given by V=3x2+5, where x, y are in metres and V is in volts. The intensity of the electric field at (−2,1,0) is:
A) +17Vm^-1
B) -17m^-1
C) +12 Vm^-1
D) -12 Vm^-1
Answers
V = 3 x 2 + 5 gives the potential of the electric field created by a point charge at any point (x, y, z), where x and y are measured in meters and V is measured in volts. At (2, 1, 0), the electric field has a strength of +12 Vm-1. Here the correct answer is option C.
The electric field E at any point in space is given by the negative gradient of the potential V at that point. That is,
E = -∇V
where ∇ is the gradient operator.
In this case, the potential is given by V = 3x^2 + 5, so the gradient of V is
∇V = ( ∂V/∂x, ∂V/∂y, ∂V/∂z )
= ( 6x, 0, 0 )
Evaluating this at the point (-2, 1, 0) gives
E = (6x, 0, 0)
= (-12, 0, 0)
The magnitude of the electric field intensity is given by
|E| = √(Ex^2 + Ey^2 + Ez^2)
= √((-12)^2 + 0^2 + 0^2)
= 12 Vm^-1
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Related Questions
Which term is defined as "energy that moves from high to low along many pathways"? circuit board parallel switch electrical current series
Answers
The terminology which connotes energy that moves from high to low along many pathways is: electrical current.
What is an electrical current?An electrical current can be defined as a form of energy that is typically transmitted from high to low level, along several pathways (conducting paths) in an electric circuit.
This ultimately implies that, an electrical current refers to a terminology which connotes energy that moves from high to low along many pathways
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Answer:
circuit board
Explanation:
i took the test
A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.
Answers
Given:
The initial height of the ball, h=1.6 m
The initial speed of the ball, u=14 m/s
To find:
a) The time of flight of the ball.
b) The range of the ball.
Explanation:
As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.
Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.
The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.
a)
From the equation of motion,
\(h=u_yt+\frac{1}{2}gt^2\)Where g is the acceleration due to gravity and t is the time of flight of the ball.
On substituting the known values,
\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)b)
The range of the ball is given by,
\(R=u_xt\)On substituting the known values,
\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)Final answer:
a) The time of flight of the ball is 0.57 s
b) The range of the ball is 7.98 m
A water wave approaches a wall with a small hole in it. The wave is blocked by the wall, except for the part that goes through the hole. The waves coming out of the hole begin to spread out as the new source of wavefronts. This is an example of what property?
a Interference
b Amplitude
c Collision
d Diffraction
Answers
Answer:
diffraction
Explanation:
took da test
which model would be classified as a physical model
Answers
Answer:
Model will be classified as a physical model since it is demonstrating a model in real life.
Explanation:
Answer:
Marshmallow answer
Explanation:
S
6
Electric Pencil
Sharpener:
Moving electrons cause the
blades to spin.
Game Controller:
The gamer manually
manipulates the joystick and
the movements are translated
into electrical impulses that
travel to the gaming system
through the wires.
→>
Answers
An electric pencil sharpener is a small motorized appliance for sharpening or refreshing the points on lead pencils.
An electric pencil sharpener is a small motorized equipment for polishing or fresh the factors on lead pencils. Within the hollow, a small electric powered motor turns a blade meeting at high velocity. The blades shave wooden and lead from the pencil's cease, bringing it to some extent.
The old-fashioned pencil sharpeners which are established to the wall and cranked through a manage are an instance of a compound system that is composed simple machines: the wheel and axle and a wedge.
You could sharpen colored pencils in an electric sharpener, however make certain to be very mild with your pencils and often easy your sharpener to put off any wax increase. If performed improperly, sharpening your colored pencils in an electric sharpener can harm each your pencils and your sharpener.
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The experimenter had observed that some colors of birthday balloons seem to be harder to inflate than others. She ran this experiment to determine whether balloons of different colors are similar in terms of the time taken for inflation to a diameter of 7 inches. Four colors were selected from a single manufacturer. An assistant blew up the balloons and the experimenter recorded the times (to the nearest 1/10 second) with a stop watch. Questions for all the following cases: Please identify: Independent variable and number of level? Dependent variable? Study design (i.e., between or within-subject design)? Confounding variable (if any)? Violation of Validity (if measureable)?
Answers
Case: The effect of balloon color on inflation time.
Independent variable: Balloon color (categorical) with four levels (e.g., red, blue, green, yellow).
Dependent variable: Time taken for inflation to a diameter of 7 inches (continuous, measured in seconds).
Study design: Within-subject design (the same group of participants inflating balloons of different colors).
Confounding variable: Possible confounding variables could be the size or material of the balloons, as these factors might affect the inflation time. To control for this, it would be important to ensure that all balloons used in the experiment are of the same size and material.
Violation of Validity: A violation of validity could occur if the measurement of inflation time is not accurate or consistent (e.g., if the stopwatch used is unreliable or if the experimenter's recording of times is inconsistent). Ensuring proper measurement procedures and equipment would help mitigate this violation.
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A box is sliding with a speed of 4.50 m/s4.50 m/s on a horizontal surface when, at point PP, it encounters a rough section. On the rough section, the coefficient of friction is not constant, but starts at 0.1000.100 at PP and increases linearly with distance past PP, reaching a value of 0.6000.600 at 12.5 m12.5 m past point PP.A) Use the work-energy theorem to find how far this box slides before stopping.B) What is the coefficient of friction at the stopping point?C) How far would the box have slid if the friction coefficient didn't increase, but instead had the constant value of 0.1000.100?
Answers
(A) This box glides, then slides up to 4.74 m before stopping . (B) The friction coefficient at the point of halting is 0.537. (C) The box would have slid 101.25 meters before coming to a stop if the coefficient of friction had stayed unchanged.
To solve this problem, we can use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:
Net work = ΔK.E.
We can break the motion of the box into two parts: before and after the rough section. Before the rough section, the box is moving with a constant velocity, so the net work done on it is zero. After the rough section, the box slows down and comes to a stop, so the net work done on it is equal to its initial kinetic energy:
Net work = -K.E.
(A) To find how far the box slides before stopping, we need to find the distance over which the box is acted upon by the increasing frictional force. Let's call this distance x.
W (friction) = ∫₀ˣ F f(x') dx'
here,
F f(x') is frictional force at a distance x' from point P.
Since the coefficient of friction increases linearly with distance, we can express F f(x') as:
F f(x') = μ₀ + (μ f - μ₀) * (x'/x f)
here,
μ₀ is initial coefficient of friction at point P,
μ f is final coefficient of friction at distance x f = 12.5 m, and
x' ranges from 0 to x.
Reserving expression of F f(x') into the integral for W (friction):-
W (friction) = μ₀ * x + (μ f - μ₀) * (x²/2x f)
Express initial kinetic energy as:-
K.E. = (1/2) * m * v²
here,
m is mass of the box and
v is its initial velocity of 4.50 m/s.
Setting the net work equal to the change in kinetic energy:-
= μ₀ * x + (μ f - μ₀) * (x²/2x f)
= (1/2) * m * v²
= x² - 2x f * [(μ f - μ₀)/μ₀] * x - 2x f * (K.E./(μ₀ * m))
= 0
Putting given values of μ₀, μ f, x f, m, and v:-
x = 4.74 m
Therefore, the box slides for a distance of 4.74 m before coming to a stop.
(B) To find the coefficient of friction at the stopping point, we can use the same equation we derived earlier for W (friction) and solve for μ f:-
= W (friction)
= μ₀ * x + (μ f - μ₀) * (x²/2x f)
= -K.E.
= μ f
= (2 * K.E. + μ₀ * x * (μ f - μ₀)/x f) / x²
Putting given values of K.E., μ₀, μ f, x f, and x:-
μ f = 0.537
Therefore, the coefficient of friction at the stopping point is 0.537.
(C) If the coefficient of friction remained constant at μ₀ = 0.1000, then we can simplify the equation we derived for x by setting μ f = μ₀:
= μ₀ * x + (μ₀ - μ₀) * (x²/2x f)
= (1/2) * m * v²
Simplifying the second term:-
μ₀ * x = (1/2) * m * v²
Solving for x:-
x = (m * v²) / [2 * μ₀ * W (friction)]
here,
W (friction) is work done by friction.
To find W (friction), we can integrate the frictional force over the entire distance traveled by the box:-
= W (friction)
= ∫₀ˣ F f(x') dx'
here,
F f(x') is constant frictional force of μ₀.
Reserving this expression for W friction into the equation for x:-
x = (m * v²) / (2 * μ₀ * F f * x)
here,
F f is constant frictional force of μ₀.
Simplifying:-
x = (m * v²) / (2 * μ₀ * F f)
Putting given values of m, v, μ₀, and F f:-
x = 101.25 m
Therefore, if the coefficient of friction had remained constant at μ₀ = 0.1000, the box would have slid for a distance of 101.25 m before coming to a stop.
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Hello people ~
Which of the following options are correct?
If a conductor has a potential V 4- 0 and there are no charges anywhere else outside, then _____
(a) there must not be charges on the surface or inside itself.
(b) there cannot be any charge in the body of the conductor.
(c) there must be charges only on the surface.
(d) there must be charges inside the surface.
Answers
The charge would be in equilibrium so there would be no charge in the body of the conductor.
Answer:
(b) there cannot be any charge in the body of the conductor
Answer:
B
Explanation:
Note the line that there is no charges anywhere else outside means the charge is placed in equilibrium position.
Hence there cannot be any charge in the body of conductor
The force acting on a tugboat is described by the vector(6 newtons,–3 newtons). What is the direction of the force in degrees, to thenearest tenth of a degree?
Answers
In order to calculate the direction of the vector, first let's draw its components:
since the horizontal component is positive and the vertical component is negative, the vector is pointing to the 4th quadrant.
To calculate the angle, we can use the arc tangent as follows:
\(\begin{gathered} \tan (\theta)=\frac{-3}{6} \\ \tan (\theta)=-0.5 \\ \theta=\tan ^{-1}(-0.5) \\ \theta=-26.56\degree \end{gathered}\)Rounding to nearest tenth, the direction is -26.6°.
30POINTS!!!!The solar wind is made up of electrically charged particles. They do not cause harm on Earth. They are too weak.
True
or
False
Answers
Answer:
true
Explanation:
the explanation is we would have been roasted if they weren't to weak
Volume of a cylinder with a diameter of 1.55 cm and a height of 1.34 cm
Answers
Answer:
2.53 cm³
Explanation:
Volume of cylinder = πr²h; where h is the height and r is the radius and
π = 3.14 approx.
Volume = 3.14 * (1.55/2)² * 1.34 = 2.53 cm³
I divided 1.55 by 2 because we were given the diameter and not radius. Diameter = radius / 2
The speed an
object travels in a
specific
DIRECTION
Is this speed velocity or acceleration
Answers
hope this helps :)
A 5.0 Newton force is applied to the right of a 6.0 kg object to move across a smooth surface. The coefficient of friction is zero. a. Draw and label all of the forces acting on the object b. Calculate the acceleration of the object
Answers
Answer:
\(0.833\ \text{m/s}^2\)
Explanation:
m = Mass of block = 6 kg
F = Force on block = 5 N
\(\mu\) = Coefficient of friction = 0
a = Acceleration of the block
From Newton's second law we have
\(F=ma\\\Rightarrow a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{5}{6}\\\Rightarrow a=0.833\ \text{m/s}^2\)
The acceleration of the block is \(0.833\ \text{m/s}^2\)
9. Thermal energy (heat) is defined as
A. the sum of all the kinetic energies of all the particles in an object
B. the average of all the kinetic energies of all the particles in an object
C. the sum of all the numbers of particles in an object
D. the average number of particles in an object
Answers
Answer:
The correct answer is A. Thermal energy (heat) is defined as the sum of all the kinetic energies of all the particles in an object.
. what is the pressure 8 meters below the surface of a lake filled with freshwater with respect to the surface? what is the absolute pressure?
Answers
absolute pressure: 80000 Pa
gauge pressure: 195000 Pa
The amount of force delivered perpendicularly to an object's surface per unit area is known as pressure. It is represented by the letter "p" or "P." Pressure should be written with a lowercase p, according to the IUPAC. But many people use the capital P. The use of P vs p relies on the field in which one is working, the proximity of other symbols denoting quantities like power and momentum, as well as writing style.
Pressure is expressed in a variety of units. Some of these are the result of dividing a unit of force by a unit of area; the old measure of pressure, the pound-force per square inch (psi), is equivalent to one newton per square meter (N/m2), as is the SI unit of pressure, the pascal (Pa).
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A doll sets on the a table 3 meters high weighing 1.5kg. What is the gravitational potential energy?
A-4.5 joules
B-19.6 joules
C-14.7 joules
D-44.1 joules
Answers
Answer:
Explanation:
A - 4.5
estimate what earth's rotational acceleration would be in rad/s2 if the length of a day increased from 24 h to 48 h during the next 100 years.
Answers
The orbital speed is \(7.272\times10^{-5}\).
We need to calculate the initial and final angular speed.
The distance the body travels in relation to the number of rotations or revolutions per unit of time is determined using the angular speed formula.
The speed of an object determines how swiftly or slowly it moves. The orbital speed of an item in rotation is known as its angular speed.
\(w_{o}=\frac{2\pi}{t}=\frac{2\pi}{24\times60\times60}=7.272\times10^{-5\)
The final angular speed is
\(w_{f} =2w_{o}\)
So, the angular acceleration is,
Angular acceleration is the term used to describe the temporal pace at which angular velocity varies.
\(\alpha=\frac{w_{f} -w_{o} }{t}=\frac{w_{o} }{t}\)
On solving we get,
\(\alpha=2.306\times10^{-14} \frac{rad}{s^2}\)
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What is Stefan Boltzmann Law?
Answers
The radiation emitted from an area A of a black body at absolute temperature T is directly proportional to the fourth power of the temperature, according to Stefan Boltzmann's equation.
Mathematically, u/A = σ T⁴
where,
σ is Stefans's constant(5.67 × 10⁻⁸ W/m²k⁴)
According to the equation above, a body that is not a black body receives less radiation and consequently emits less of it.
For such a body, u = e σ A T⁴
where,
e is emissivity(value lies between 0 and 1)
With the surrounding temperature T₀, energy radiated by an area per unit time.
Δu = u - u₀ = e σ A (T⁴ - T₀⁴)
The blackbody's temperature and the quantity of power it emits per unit area are related by Stefan Boltzmann's law. The total energy emitted or radiated by a black body per unit surface area across all wavelengths and per unit time is directly proportional to the fourth power of the black body's thermodynamic temperature, according to the law.
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Blocks A (mass 3.50 kg) and B (mass 10.00 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block A is moving toward it at 9.00 m/s. The blocks are equipped with ideal spring bumpers. The collision is head-on, so all motion before and after the collision is along a straight line. Let +x be the direction of the initial motion of A. Find the maximum energy stored in the spring bumpers and the velocity of each block at the time of the collision
Answers
The total energy that can be stored in the spring bumpers is 43.8 J, or KE = 43.8.
What is the formula for energy capacity?The battery's power capacity is the amount of energy it can hold. Its power is commonly stated in Watt-hours (the symbol Wh) (the symbol Wh). A Watt-hour is equal to the voltage (V) and current (Amps) that a battery can produce for a specific period of time (generally in hours). Voltage * Amps * hours = Wh.
Block A's momentum before to the impact can be calculated using the formula p1 = m1v1 = (3.50 kg)(9.00 m/s) = 31.5 kgm/s.
Block B's initial momentum is p2 = m2v2 = 0, indicating that it is at rest.
Prior to the collision, the system's total momentum was equal to 31.5 kgm/p1 + p2.
\(p1 + p2 = (m1 + m2)v\)
\(31.5 kgm/s = (3.50 kg + 10.00 kg) * v\)
\(31.5 kgm/s = 13.50 kg * v\)
\(v = 31.5 kg*m/s / 13.50 kg = 2.33 m/s\)
The kinetic energy of block A before the collision is given by KE1 = (\(1/2)m1v1^2 = (1/2)(3.50 kg)(9.00 m/s)^2 = 141.8\) J
The kinetic energy of block B before the collision is KE2 = \((1/2)m2v2^2 = 0\)
The total kinetic energy before the collision is KE1 + KE2 = 141.8 J
\(ΔKE = KEf - KEi = (1/2)(m1 + m2)v^2 - KE1 - KE2\)
\(ΔKE = (1/2)(3.50 kg + 10.00 kg)(2.33 m/s)^2 - 141.8 J - 0\)
ΔKE = 43.8 J\(31.5 kgm/s = 13.50 kg * v\)
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The temperature at Furnace Creek in Death Valley reached 136°F (331 K) on July 10, 1913. What i the peed of ound in air at thi temperature?
Answers
The speed of sound in air at the temperature of 136°F (331 K) = 365.71 m/s
The speed of soundThe speed of sound in air depends on temperature, so the higher the temperature, the greater the value of the speed of sound.
The equation for determining the speed of sound with a change in temperature is:
v = v₀ + 0.6(∆T)
where:
v = the final sound velocity (m/s)
v₀ = the initial sound velocity (m/s)
∆T = temperature change (°C)
Note: The speed of sound in air at 0°C is 331 m/s.
We have ∆T = 136°F ⇒ 57.85°C
So,
v = 331 + 0.6 (57.85)
= 365.71 m/s
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how does a wheel involve physics
Answers
Suppose you rapidly stir some raw eggs with an eggbeater. The temperature of the eggs will A) increase. B) decrease. C) remain unchanged.
Answers
If you rapidly stir some raw eggs with an eggbeater, the temperature of the eggs will remain unchanged.
Humans and human ancestors have scavenged and eaten animal eggs for millions of years.
Humans in Southeast Asia had domesticated chickens and harvested their eggs for food by 1500 BCE.
The most widely consumed eggs are those of fowl, especially chickens. Eggs of other birds, including ostriches and other ratites, are eaten regularly but much less commonly than those of chickens.
People may also eat the eggs of reptiles, amphibians, and fish. Fish eggs consumed as food are known as roe or caviar.
The act of stirring will not generate any heat or cooling effect, and the temperature of the raw eggs will remain the same.
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Suppose a 200mm focal length telephoto lens is being used to photograph mountains 9.5km away.
a) What is image distance, in meters, for this lens?
b) What is the image height, in centimeters, of a 950m high cliff on one of the mountains?
Answers
a) The image distance for this lens is approximately 0.20004 meters.
b) The image height of the 950m high cliff is approximately 2 centimeters.
a) To find the image distance (v) for a 200mm focal length (f) telephoto lens photographing mountains 9.5km away (object distance, u = 9,500m), we can use the thin lens formula:
1/f = 1/u + 1/v
Rearrange the formula to solve for v:
1/v = 1/f - 1/u
1/v = 1/0.2 - 1/9500 ≈ 4.9989
v ≈ 1/4.9989 ≈ 0.20004 meters
So, the image distance for this lens is approximately 0.20004 meters.
b) To calculate the image height (h') of a 950m high cliff (object height, h), we first find the magnification (M) using the formula:
M = -v/u
M = -0.20004/-9500 ≈ 0.00002105
Now, to find the image height, we multiply the magnification by the object height:
h' = M * h
h' = 0.00002105 * 950 ≈ 0.02 meters or 2 centimeters
Therefore, the image height of the 950m high cliff is approximately 2 centimeters.
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A motorcycle travels at a constant 20 m/s for 10 s. How far has it traveled?
Answers
d =200 m
Explanation:Hi there !
Velocity formula
v = d/t => d = v×t
d = distance
t = time
d = 20m/s×10s = 200 m
Good luck !
what is the surface charge density on the inner surface of the conducting shell?express your answer in terms of some or all of the variables q , a , b , and appropriate constants.
Answers
The surface charge density on the inner surface of the conducting shell can be expressed as: σ = q / (4πb^2), or σ = εq / (4πb^2).
To find the surface charge density on the inner surface of the conducting shell, we can use the formula:
σ = Q / A
where σ is the surface charge density, Q is the charge enclosed by the surface, and A is the area of the surface.
In this case, the charge enclosed by the surface is the charge q, since the conducting shell is neutral and does not contribute to the charge. The area of the inner surface of the shell is 4πb^2. Therefore, we have:
σ = q / (4πb^2)
Alternatively, we can use the fact that the electric field just outside the inner surface of the shell is E = q / (4πεb^2), where ε is the permittivity of free space. The electric field just inside the inner surface of the shell is zero, since the electric field inside a conductor is zero. Therefore, the charge density on the inner surface of the shell is given by:
σ = εE = εq / (4πb^2)
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A fan operating at 260V with a current being supplied at 13A. What is the effective resistance at which it is being operated?
Answers
Answer:
20 ohms
Explanation:
Resistance=Potential difference÷Electric current
X=260÷13
X=20
The acceleration of a car is – 0.75 ms 2. If its initial velocity is 12.0 ms"!, what is its
velocity 2.5 seconds later?
Answers
Using first equation of kinematics
\(\\ \rm\hookrightarrow v=u+at\)
\(\\ \rm\hookrightarrow v=12+(-0.75)(2.5)\)
\(\\ \rm\hookrightarrow v=12-1.9\)
\(\\ \rm\hookrightarrow v=10.9m/s\)
what current will pass through your bodi if you touch the two terminals of a 9.0 v battery with your two hands
Answers
The current passing through your body when touching a 9.0 V battery with both hands depends on your body's resistance, and can typically range from 0.1 mA to 9 mA.
Ohm's Law states that current (I) equals voltage (V) divided by resistance (R). The human body's resistance can vary significantly, ranging from 1,000 ohms (when wet) to 100,000 ohms (when dry). Using the formula I = V/R, we can calculate the current. For example, if the resistance is 10,000 ohms (a relatively common value), the current would be:
I = 9.0 V / 10,000 ohms = 0.0009 A, or 0.9 mA (milliamps)
Thus, the current passing through your body when touching a 9.0 V battery with both hands depends on your body's resistance, and can typically range from 0.1 mA to 9 mA.
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which of the following statements is true of gravitational force but cannot describe electric force? responses the magnitude of gravitational force is inversely proportional to the square of the distance between objects. the magnitude of gravitational force is inversely proportional to the square of the distance between objects. gravitational force can be both attractive and repulsive. gravitational force can be both attractive and repulsive. the influence of gravitational force dominates over extremely large scales in the universe. the influence of gravitational force dominates over extremely large scales in the universe. gravitational force is considered a fundamental force.
Answers
The statement "the influence of gravitational force dominates over extremely large scales in the universe" is true of gravitational force but cannot describe electric force.
When it comes to gravitational force, the adage "the influence of gravitational force dominates over extremely large scales in the universe" is accurate, but it cannot apply to the electric force. The main force in the cosmos at vast dimensions is gravity, which controls the motion of planets, stars, and galaxies. Although both gravitational and electric forces obey the inverse square law.
The behaviour of charged particles on lower dimensions, such as within atoms and molecules, is mainly governed by electric forces, which are usually much weaker than gravitational forces. In addition, while both forces can be appealing, gravitational forces are always attractive, whereas electric forces can also be repulsive between entities with similar charges. Last but not least, there are four basic forces: gravity, the strong nuclear force, the weak nuclear force, and the electric force. The strong nuclear force is one of these four factors.
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How can you use fields to describe the force between two distant electric charges?
Answers
Electric field lines can be used to describe the force between two distant electric charges.
The electric field is a property of space that describes the force experienced by a charged particle placed in that space. When an electric charge is present in space, it creates an electric field around it that is responsible for the force experienced by other charged particles placed in that field. The force experienced by the charged particles is proportional to the strength of the electric field, which decreases with distance. The strength of the electric field is described by electric field lines, which are imaginary lines that show the direction of the force that would be experienced by a small positive test charge placed at any point in the field.
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