Answer:
\( |d| = \sqrt{ {(x_{2} -x_{1})}^{2} + {(y_{2} -y_{1})}^{2} + {(z_{2} -z_{1})}^{2}} \\ = \sqrt{ {(6 - 2)}^{2} + {(3 - 0)}^{2} +{(5 - 8)}^{2} } \\ = \sqrt{16 + 9 + 9} \\ = \sqrt{34} \)
The position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.
What is Distance between two points?The distance formula states that the distance between two points in xyz-space is the square root of the sum of the squares of the differences between corresponding coordinates A( \(x_{1}\) , \(y_{1}\) , \(z_{1}\) ) and B( \(x_{2}\) , \(y_{2}\) ,\(z_{2}\)),
AB² = (\(x_{2}\) - \(x_{1}\))² + (\(y_{2}\) - \(y_{1}\))² + ( \(z_{2}\) - \(z_{1}\) )²
In reality, the Pythagorean Theorem is nothing more than the distance formula. Draw a right triangle using the segment AB as its hypotenuse in order to get the distance AB between points A( \(x_{1}\) , \(y_{1}\) ) and B( \(x_{2}\) , \(y_{2}\) ).
Given that in the question two points are A(2,3,5) and B(6,0,8), so the distance between them is
AB² = (\(x_{2}\) - \(x_{1}\))² + (\(y_{2}\) - \(y_{1}\))² + ( \(z_{2}\) - \(z_{1}\) )²
AB² = 4² + 3² + 3²
AB² = 34
AB = 5.83 m
Position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.
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Which example best describes Newton's third law of motion?
F
When a glass slid across a table, it spilled water when it stopped suddenly.
G
An engine used less work to move a lighter car than when it moved a heavier car.
H When a passenger stepped from a boat to the shore, the boat moved away from the shore .
The best example of Newton's third law of motion is, When a passenger stepped from a boat to the shore, the boat moved away from the shore. Thus, option C is correct.
Sir Issac Newton gives three laws of motion. The first law states that an object remains at rest or in continuous motion unless an external force acted on it. The second law stated that the force is directly proportional to the acceleration of the object. Newton's third law states that, for every action, there is an equal and opposite reaction.
From the given, Newton's third law is applicable, When a passenger stepped from a boat to the shore, the boat moved away from the shore. This shows the action and reaction of the boat and shore.
Thus, the ideal solution is option C.
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Question 6 of 10
How would you change the distance between two charged particles to
increase the electric force between them by a factor of 16?
A. Reduce the distance by a factor of 4.
B. Increase the distance by a factor of 4.
C. Reduce the distance by a factor of 16.
D. Increase the distance by a factor of 16.
SUBMIT
Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.
Thus, When charged things interact with other objects, there is an electric force present in the system.
The electric force between them is appealing because positive charges are attracted to negative charges. For two positive charges or two negative charges, the electric force is repellent.
A typical illustration of this is what happens when two balloons are rubbed on a blanket. When you rub the balloons against the blanket, electrons from the blanket transfer to the balloons, leaving the blanket positively charged and the balloons negatively charged.
Thus, Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.
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A boy throws an arrow at an original speed of 2m / s to create an angle 0 referring to the balloon at a distance of 3m from the departure point. Calculate the angle 0 and the height of the arrow. Let g = 10m / s2.
Calculate the horizontal component of the velocity. The horizontal component of the velocity is given by:
v_x = v * cos(theta)
where v is the original speed of the arrow and theta is the angle of projection.In this case, v = 2 m/s and theta is unknown. Solving for theta, we get:
theta = arccos(v_x / v)
theta = arccos(2 / 2) = 45 degrees
Calculate the vertical component of the velocity. The vertical component of the velocity is given by:
v_y = v * sin(theta)
In this case, v = 2 m/s and theta = 45 degrees. Solving for v_y, we get:
v_y = 2 * sin(45 degrees) = 1.414 m/s
Calculate the time of flight. The time of flight is given by:
t = 2 * v_y / g
In this case, v_y = 1.414 m/s and g = 10 m/s^2. Solving for t, we get:
t = 2 * 1.414 / 10 = 0.283 seconds
Calculate the height of the arrow. The height of the arrow is given by:
y = v_y * t - 0.5 * g * t^2
In this case, v_y = 1.414 m/s, t = 0.283 seconds, and g = 10 m/s^2. Solving for y, we get:
y = 1.414 * 0.283 - 0.5 * 10 * 0.283^2 = 0.303 meters
Therefore, the angle of projection is 45 degrees and the height of the arrow is 0.303 meters.
A 540 W electric heater is designed to operate at 120 V. What current does it draw?
The electric heater draws a current of 4.5 amps.
Using Ohm's Law, we can calculate the current drawn by the electric heater. Ohm's Law states that the current (I) flowing through a conductor is equal to the voltage (V) applied to the conductor divided by its resistance (R):
I = V/RIn this case, the voltage (V) is 120 V and the power (P) of the electric heater is 540 W. We can use the formula P = VI, where P is the power in watts, V is the voltage in volts, and I is the current in amperes. Solving for I, we get:
I = P/VI = 540 W / 120 VI = 4.5 ATherefore, the electric heater draws a current of 4.5 amperes (A) when operated at 120 volts (V).
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A bullet traveling at 5.0 x10^2 meters per is brought to rest by an impulse of 50 Newton*seconds. Find the mass of the bullet.
The bullet stops moving on hitting on a surface. Hence, the impulse here is equal to the momentum. Therefore, the mass of the bullet is 0.1 Kg.
What is impulse?Impulse in physics is the change in momentum. It is the product of the force and change in time.
hence, impulse = f. dt
When the bullet is travelling with a velocity of 500 m/s it has a momentum. When it brought to rest, momentum become zero. Thus, the momentum is equal to the impulse here.
Therefore, f.dt = m. v
f.dt = 50 N s
v = 500 m/s
m = 50 N s/500 m/s = 0.1 Kg
Therefore, the mass of the bullet is 0.1 Kg.
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Why do people do drugs?
People use drugs for many reasons: they want to feel good, stop feeling bad, or perform better in school or at work, or they are curious because others are doing it and they want to fit in. The last reason is very common among teens.Drugs excite the parts of the brain that make you feel good. But after you take a drug for a while, the feel-good parts of your brain get used to it. Then you need to take more of the drug to get the same good feeling. Soon, your brain and body must have the drug just to feel normal. You feel sick, awful, anxious, and irritable without the drug. You no longer have the good feelings that you had when you first used the drug. This is true if you use illegal drugs or if you misuse prescription drugs. Misuse includes taking a drug differently than how your doctor tells you to (taking more or crushing pills to "shoot up" or snort), taking someone else’s prescription, or taking it just to get “high.”
if you stand three feet in front of a plane mirror, how far away would you see yourself in the mirror
a. 1.5ft
b. 3.0ft
c. 6.0ft
d. 12ft
Answer:
6 ft
Explanation:
A plane mirror shows you at the actual distance from the mirror, so if a person stood right next to the mirror, he/she will see your image at a distance of 3 feet but since you are at a distance of 3 ft away from the mirror and the image formed is 3 ft inside the mirror
The image will be at a distance of 6 feet from you
A 135 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 63.7 kg person stands on the platform at a distance of 1.05 m from the center, and a 30.1 kg dog sits on the platform near the person 1.33 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis.
Answer:
the moment of inertia is 380.14 kg-m^2
Explanation:
The computation of the moment of inertia is as follows:
The net moment of inertia is
= MR^2 ÷ 2 + m_p d_p^2 + m_d d_d^2
= 135 × 1.95^2 ÷2 + 63.7 × 1.05^2 + 30.1 × 1.33^2
= 380.14 kg-m^2
hence, the moment of inertia is 380.14 kg-m^2
We simply applied the above formula so that the correct value could come
And, the same is to be considered
What is motion please explain with diagram
Answer:
An object in a motion when it is continuously changing its position based on a reference point and observed by a person or a device.
This will be my last question, What type of electricity, do you get from friction?
Answer: you get static electricity. U can shock others easily with this thing u could play pranks but i suggest not to ;-;
Explanation:
How will the motion of the arrow change after it leaves the bow?
The string moves to the right, as it restores its original position with the median plane of the bow. As a result, the string "pulls" on the arrow with a force F2. 2. The tip of the arrow T moves slightly to the left.
pls thank me and brainliest me
You check in at the airport and have your luggage weighed. It comes to 25kg. The airport is at sea level and you take off and climb to 30,000 ft. How much less does your luggage now weigh?
mass of earth = 5.98 × 10 ^24
radius of earth = 6.37 × 10^ 6
Answer:
0.705 kg less
Explanation:
Altitude at sea level = 0 ft
Altitude after climbing = 30,000 ft = 30,000 x 0.3048 = 9,144 m
Weight = W = mg
Change in weight = ΔW = (M-luggage) × (g-sea level - g-altitude)
g at sea level:
g1 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth)²
g at altitude of 30,000 ft:
g2 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth + Altitude)²
Gravitational constant = 6.674 × 10^-11 m^3 kg^-1 s^-2
g1 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6)^2
g1 ≈ 9.8358 m/s^2
g2 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6 + 9,144)^2
g2 ≈ 9.8076 m/s^2
ΔW = (M-luggage) × (g1 - g2)
= 25 kg × (9.8358 - 9.8076)
≈ 0.705 kg
Therefore, your luggage would weigh approximately 0.705 kg less when you climb to 30,000 ft compared to its weight at the airport.
Can't guarantee this is right, but I checked the numbers a few times and this is the best I can do!
EXPLORING WORK AND ENERGY OBJECTIVES: - Measure the force required to move a mass over a certain distance using different methods. - Compare the force required to move different masses over different time intervals. MATERIALS: - clamps - cord, 1.00 m - spring balance (labeled in diagram as Force Meter) - inclined plane - masking tape - meterstick - set of hooked masses - stopwatch PROCEDURE 1 1. At one edge of the lab table, place a tape mark to represent a starting point. From this mark, measure exactly 0.50 m and 1.00 m. Place a tape mark at each measured distance. 2. Securely attach a 1.00 kg mass to one end of the cord and the spring balance to the other end. The balance will measure the force required to move the mass through different displacements. 3. Place the mass on the table top at the starting point. Hold the balance parallel to the tabletop so that the cord is taut between the balance and the mass. Carefully pull the mass at constant speed along the surface of the table to the 0.50 m mark (this may require a bit of practicel). As you pull, observe the force measured on the balance. If your balance is marked in grams or kilograms, convert to newtons so as to stay consistent with units. 4. Record the force and distance using the appropriate SI units. 5. Repeat steps 3 and 4 for a distance of 1.00 m. 6. Repeat entire procedure for a 0.2 kg mass. A. Did you exert the same force on the 1 kg mass as you did on the 0.2 kg mass to move them an equal distance? Why or why not? B. Did it require more force to move the mass 1.00 m than to move the same mass 0.50 m ? Why or why not? C. What force did you pull against? Explain
The force exerted on the 1 kg mass and the 0.2 kg mass to move them an equal distance would not be the same because the force required to move a mass depends on the mass being moved. The force required to move an object is given by the equation F = m * a, where F is the force, m is the mass, and a is the acceleration. Since the acceleration is constant in this experiment, the force required to move the 0.2 kg mass will be less than the force required to move the 1 kg mass.
How exploring work and energy?B. Yes, it would require more force to move the mass 1.00 m than to move the same mass 0.50 m. This is because the work done on an object is given by the equation W = F * d, where W is the work done, F is the force, and d is the distance. Since the force required to move the mass is constant, the work done would be proportional to the distance moved.
C. The force that was pulled against is the force of friction between the mass and the surface of the table. This force acts in the opposite direction to the applied force and must be overcome in order to move the mass. The magnitude of the force of friction depends on the mass, the coefficient of friction between the two surfaces, and the normal force acting on the mass.
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A motorcycle, travelling cast, starts from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 s.Calculate a) Its acceleration b) Its final velocity c) At what time the motorcycle had covered half the total distance d) What distance the motorcycle had covered in half the total time.
The motorcycle had covered a distance of 16 meters in half the total time.
a) To calculate the acceleration, we can use the formula:
a = (v - u) / t
where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.
Given:
u = 0 m/s (initial velocity)
v = ? (final velocity)
t = 4 s (time)
s = 64 m (distance)
Using the equation of motion:
s = ut + 1/2at^2
We can rearrange the equation to solve for acceleration:
a = 2s / t^2
a = 2(64) / (4)^2
a = 128 / 16
a = 8 m/s^2
Therefore, the acceleration of the motorcycle is 8 m/s^2.
b) To find the final velocity, we can use the formula:
v = u + at
v = 0 + (8)(4)
v = 32 m/s
Therefore, the final velocity of the motorcycle is 32 m/s.
c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:
s = ut + 1/2at^2
32 = 0 + 1/2(8)t^2
16 = 4t^2
t^2 = 4
t = 2 s
Therefore, the motorcycle had covered half the total distance at 2 seconds.
d) To calculate the distance covered in half the total time, we use the formula:
s = ut + 1/2at^2
s = 0 + 1/2(8)(2)^2
s = 0 + 1/2(8)(4)
s = 0 + 16
s = 16 m
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Describe the life cycle of a star before it collapses into a black hole.
Describe the life cycle of a star before it becomes a black dwarf.
What is the likely outcome of our sun? *
The sun will supernova and become a black hole.
The sun will swell, encompassing the inner planets and collapses into a dwarf star.
The sun will become a pulsar.
How Do You Know?
P.S. the how do you know is only for the last question
1) describe the life cycle of a star before it collapses into a black hole.
1) describe the life cycle of a star before it collapses into a black hole.ans: A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. Over time, the hydrogen gas in the nebula is pulled together by gravity and it begins to spin. As the gas spins faster, it heats up and becomes as a protostar. Eventually the temperature reaches 15,000,000 degrees and nuclear fusion occurs in the cloud's core. The cloud begins to glow brightly, contracts a little, and becomes stable. It is now a main sequence star and will remain in this stage, shining for millions to billions of years to come. This is the stage our Sun is at right now.
2) describe the life cycle of a star before it becomes a dwarf.
ans: The life cycle of a low mass star (left oval) and a high mass star (right oval). ... As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf.
3) what is the likely outcome of our sun?
ans: All stars die, and eventually — in about 5 billion years — our sun will, too. Once its supply of hydrogen is exhausted, the final, dramatic stages of its life will unfold, as our host star expands to become a red giant and then tears its body to pieces to condense into a white dwarf.
energy is the energy of moving engine parts.
Mechanical
Electrical
Chemical
Answer:
mechanical energy is being used
Define "increased productivity" in terms of the number of tasks and the amount of time.
Answer:
The greater the amount of output for a given unit of input, the higher the overall productivity. Businesses generally aim to improve productivity over time to maintain competitiveness and increase the business's profitability. Individuals are familiar with the idea of productivity in their own lives.
If an arrow is fired from a bow with a perfectly horizontal velocity of 60 m/s and the arrow
was 2 m above the ground when it was released, how far will the arrow fly horizontally before it strikes the ground?
Explanation:
This problem is solved by determining how long it takes the arrow to fall to the ground in exactly the same manner as if the arrow was dropped with no horizontal velocity. The time required for the arrow to fall to the ground will be the same time that the arrow flies horizontally at 60.0 m/s, so
d=1/2at^2
solved for t=√2d/a
t=√(2)(2.00m)/9.80m/s^2 =0.639s
The time required for the fall is multiplied by the horizontal velocity to get the horizontal distance.
d(horizontal)=v(horizontal)×time=60.0m×0.639s =38.3m
The arrow will fly 37.8 meters in the horizontal direction before it strikes the ground.
What is projectile motion?Projectile motion is a form of motion experienced by an object or particle that is projected near Earth's surface and moves along a curved path under the action of gravity only.
Given is an arrow fired perfectly along the horizontal direction with velocity of 60 m/s. The arrow was 2 m above the ground when it was released.
initial horizontal velocity = u[H] = 60 m/s
initial vertical velocity = u[V] = 0 m/s
Horizontal acceleration = a[H] = 0 m/s²
Vertical acceleration = a[V] = 9.8 m/s²
Vertical distance = S[V] = 2 m
Using second equation of motion for vertical direction to calculate time taken to reach the ground.
S[V] = u[V] × t + 1/2 a[V] × t²
S[V] = 1/2 × a[V] × t²
2 = 1/2 x 9.8 x t²
4/9.8 = t²
t² = 0.4081
t = 0.63 seconds
Horizontal distance covered = S[H] = u[H] x t
S[H] = 60 X 0.63 = 37.8 meters
Therefore, the arrow will fly 37.8 meters in the horizontal direction before it strikes the ground.
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What precise meaning do you attach to the statement r = (24.0 ± 0.3) mm, where r is the radius of a tube.
The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.
Accurate findings are desired when any quantity is being measured. Closeness of the measurements to a particular value is referred to as accuracy (like the theoretical value). It is not insignificant that measurements can contain inaccuracies; as a result, the outcome frequently includes a margin error. The sentence above displays the radius's measured value along with its margin of error.
In other words, the aforementioned statement represents a quantity's numerical value along with its tolerance, or the only permissible (and conceivable) values to ensure that the measurement is accurate. The information provided above demonstrates that the range of the tube's radius within which we are certain is from 23.7 to 24.3.
These are all valid radius values, along with all others within this interval. By increasing the number of trials in a measurement, the value for the upper and lower bounds of the error can be decreased.
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I need help, please!
Answer:
can u send pictures again it's unclear.
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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If humans are exposed to radiation, this can cause a change in their DNA base sequence. What is the term given to this?
The term used to indicate different DNA nucleotide changes in humans exposed to radiation is called a mutation.
What is a mutation?A mutation is any DNA nucleotide change or modification that occurs in the genome of a given organism.
Mutations may be caused by physical agents (e.g., UV radiation) or chemical agents.
In conclusion, the term used to indicate different DNA nucleotide changes in humans exposed to radiation is called a mutation.
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During the middle of a family picnic, Barry Allen received a message that his friends Bruce and Hal
to be saved. Barry promised his wife Iris that he would be back in exactly 5 minutes. From that that picnic
location, Barry runs at a speed of 600 m/s for 2 minutes at a heading of 35° north of west to save Bruce.
He then changed his heading to 30° west of north, slows down to 400 m/s and runs for 1 minute to save
Hal. (The changes in speed are essentially instantaneous and not part of solving this problem).
(aPray a physical representation of the displacement during Barry's full trip.
The kinematics of the uniform motion and the addition of vectors allow finding the results are:
The Barry's initial trajectory is 94.30 10³ m with n angles of θ = 138.8º The return trajectory and speed are v = 785.9 m / s, with an angle of 41.2º to the South of the East
Vectors are quantities that have modulus and direction, so they must be added using vector algebra.
A simple method to perform this addition in the algebraic method which has several parts:
Vectors are decomposed into a coordinate system The components are added The resulting vector is constructed
Indicate that Barry's velocity is constant, let's find using the uniform motion thatthe distance traveled in ad case
v = \(\frac{\Delta d}{t}\)
Δd = v t
Where v is the average velocity, Δd the displacement and t the time
We look for the first distance traveled at speed v₁ = 600 m / s for a time
t₁ = 2 min = 120 s
Δd₁ = v₁ t₁
Δd₁ = 600 120
Δd₁ = 72 10³ m
Now we look for the second distance traveled for the velocity v₂ = 400 m/s
time t₂ = 1 min = 60 s
Δd₂ = v₂ t₂
Δd₂ = 400 60
Δd₂ = 24 103 m
In the attached we can see a diagram of the different Barry trajectories and the coordinate system for the decomposition,
We must be careful all the angles must be measured counterclockwise from the positive side of the axis ax (East)
Let's use trigonometry for each distance
Route 1
cos (180 -35) = \(\frac{x_1}{\Delta d_1}\)
sin 145 = \(\frac{y_1}{\Delta d1}\)
x₁ = Δd₁ cos 125
y₁ = Δd₁ sin 125
x₁ = 72 103 are 145 = -58.98 103 m
y₁ = 72 103 sin 155 = 41.30 10³ m
Route 2
cos (90+ 30) = \(\frac{x_2}{\Delta d_2}\)
sin (120) = \(\frac{y_2}{\Delta d_2}\)
x₂ = Δd₂ cos 120
y₂ = Δd₂ sin 120
x₂ = 24 103 cos 120 = -12 10³ m
y₂ = 24 103 sin 120 = 20,78 10³ m
The component of the resultant vector are
Rₓ = x₁ + x₂
R_y = y₁ + y₂
Rx = - (58.98 + 12) 10³ = -70.98 10³ m
Ry = (41.30 + 20.78) 10³ m = 62.08 10³ m
We construct the resulting vector
Let's use the Pythagoras' Theorem for the module
R = \(\sqrt{R_x^2 +R_y^2}\)
R = \(\sqrt{70.98^2 + 62.08^2}\) 10³
R = 94.30 10³ m
We use trigonometry for the angle
tan θ ’= \(\frac{R_y}{R_x}\)
θ '= tan⁻¹ \(\frac{R_y}{R_x}\)
θ '= tan⁻¹ \(\frac{62.08}{70.98}\)
θ ’= 41.2º
Since the offset in the x axis is negative and the displacement in the y axis is positive, this vector is in the second quadrant, to be written with respect to the positive side of the x axis in a counterclockwise direction
θ = 180 - θ'
θ = 180 -41.2
θ = 138.8º
Finally, let's calculate the speed for the way back, since the total of the trajectory must be 5 min and on the outward trip I spend 3 min, for the return there is a time of t₃ = 2 min = 120 s.
The average speed of the trip should be
v = \(\frac{\Delta R}{t_3}\)
v = \(\frac{94.30}{120} \ 10^3\)
v = 785.9 m / s
in the opposite direction, that is, the angle must be
41.2º to the South of the East
In conclusion, using the kinematics of the uniform motion and the addition of vectors, results are:
To find the initial Barry trajectory is 94.30 10³ m with n angles of 138.8º The return trajectory and speed is v = 785.9 m / s, with an angle of 41.2º to the South of the East
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At what distance from a 0.100 C
charge will the electric field be
10000 N/C?
(Unit = m)
Answer:
Explanation:
\(F = k \frac{Q}{r^{2}} \\10000 = 8.99 * 10^{9} * \frac{0.1}{r^{2}} => r^{2} = 8.99 * 10^{5} * 0.1 = 89900 => r = 299.83 m = 300 m\)
Answer:
The answer would be 299.83
Explanation:
Trust
Which graph uses bars to show data that are broken into intervals?
O A. Scatter plot
O B. Bar graph
O C. Box-and-whisker plot
O D. Histogram
Answer:
A. scatter plot?
Explanation:
I dont really know if I'm right... sorry.
A sample of vegetable oil with density 913 kg/m3 is found to have a mass of 0.0365 kg. Find the volume of this sample
The volume of the vegetable oil is 0.00003998 m³.
The density of vegetable oil,
ρ = 913 kg/m³
The mass of vegetable oil,
m = 0.0365 kg
To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.
The formula for density is:
ρ = m/V
where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:
V = m/ρSubstituting the given values of mass and density in the above formula,
We get:
V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)
Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.
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An object of mass 6 kg. is resting on a horizontal surface. A horizontal force
of 15 N is constantly applied on the object. The object moves a distance of
100m in 10 seconds.
(a) How much work does the applied force do?
(b) What is the kinetic energy of the block after 10 seconds?
(c) What is the magnitude and direction of the frictional force (if there is
any)?
(d) How much energy is lost during motion?
Answer:
a) The work done by the applied force is 1500 joules.
b) The kinetic energy of the block after 10 seconds is 1200 joules.
c) The magnitude of the force of friction is 3 newtons and its direction is against motion.
d) 300 joules of energy are lost during motion.
Explanation:
a) Since the object has a constant mass, on which a constant horizontal force is exerted. The work done by the force (\(W\)), measured in joules, is defined by the following expression:
\(W = F\cdot \Delta x\) (1)
Where:
\(F\) - Force, measured in newtons.
\(\Delta x\) - Distance, measured in meters.
If we know that \(F = 15\,N\) and \(\Delta x = 100\,m\), then the work done by the force exerted on the object is:
\(W = (15\,N)\cdot (100\,m)\)
\(W = 1500\,J\)
The work done by the applied force is 1500 joules.
b) At first we need to calculate the net acceleration of the object (\(a\)), measured in meters per square second. By assuming a constant acceleration, we use the following kinematic formula:
\(\Delta x = v_{o}\cdot t +\frac{1}{2}\cdot a\cdot t^{2}\) (2)
Where \(v_{o}\) is the initial velocity of the object, measured in meters per second.
We clear the acceleration within the equation above:
\(\frac{1}{2}\cdot a \cdot t^{2} = \Delta x-v_{o}\cdot t\)
\(a = \frac{2\cdot (\Delta x - v_{o}\cdot t)}{t^{2}}\)
If we know that \(\Delta x = 100\,m\), \(v_{o} = 0\,\frac{m}{s}\) and \(t = 10\,s\), then the net acceleration experimented by the object is:
\(a = \frac{2\cdot \left[100\,m-\left(0\,\frac{m}{s} \right)\cdot (10\,s)\right]}{(10\,s)^{2}}\)
\(a = 2\,\frac{m}{s^{2}}\)
By the 2nd Newton's Law, we construct the following equation of equilibrium under the consideration of a friction force acting against the motion of the object:
\(\Sigma F = F - f = m\cdot a\) (3)
Where:
\(F\) - External force exerted on the object, measured in newtons.
\(f\) - Kinetic friction force, measured in newtons.
If we know that \(F = 15\,N\), \(m = 6\,kg\) and \(a = 2\,\frac{m}{s^{2}}\), the kinetic friction force is:
\(f = F-m\cdot a\)
\(f = 15\,N-(6\,kg)\cdot \left(2\,\frac{m}{s^{2}} \right)\)
\(f = 3\,N\)
The work done by friction (\(W'\)), measured in joules, is:
\(W' = f\cdot \Delta x\) (4)
\(W' = (3\,N) \cdot (100\,m)\)
\(W' = 300\,J\)
And the net work experimented by the object is:
\(\Delta W = 1500\,J - 300\,J\)
\(\Delta W = 1200\,J\)
By the Work-Energy Theorem we understand that change in translational kinetic energy (\(\Delta K\)), measured in joules, is equal to the change in net work. That is:
\(\Delta K = \Delta W\) (5)
If we know that \(\Delta W = 1200\,J\), then the change in translational kinetic energy is:
\(\Delta K = 1200\,J\)
The kinetic energy of the block after 10 seconds is 1200 joules.
c) The magnitude of the force of friction is 3 newtons and its direction is against motion.
d) The energy lost by the object is equal to the work done by the force of friction. Therefore, 300 joules of energy are lost during motion.
A ball is projected with an initial velocity 50m/s at an angle 30 degree from the top of a tower 55m high.calculate the total time the ball was on the air and the maximum horizontal distance
Time of flight = 1.6 s
Horizontal distance = 64 m
What is a projectile motion?Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.
For the given case,
h = vt + ¹/₂gt²
h = height of tower
v = initial velocity
t = time of flight
55 = 50sin30t + ¹/₂9.8t²
55 = 25t + 4.9t²
4.9t² + 25t - 55 = 0
t = 1.6 s
X = vₓt
X = horizontal distance
vₓ = horizontal velocity
t = time of flight
X = (50 x cos30) x 1.6
X = 64 m
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Darrel wakes up and notices there are water droplets on his window. He is confused about why there are water droplets because it did not rain last night. Which of the following statements best explains why there are water droplets on the window?
Answer:
You didn't put any options but there are water droplets on the window due to dew-condensation.
Explanation:
I learned this in class.
Answer:
its C or D
Explanation:
The energy from the sun caused water to heat up and evaporate.
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