The period of a sound wave coming from an instrument is 0. 002 seconds. What is the frequency of the sound?.

To find the average speed in meters per second, we need to convert both the distance and time to the same units. Since 540 km is equal to 540000 meters and 4.5 hours is equal to 16200 seconds, we can calculate the average speed as:

Average speed = distance / time = 540000 meters / 16200 seconds = 33.333 meters/second.

Explanation:

The equation 2y = 8 sin (4πt) is a general equation for a particle vibrating in simple harmonic motion. The amplitude of the oscillations is given by the coefficient of the sine term, which is 8 in this equation. Therefore, the amplitude of the particle vibrating in simple harmonic motion is 8 cm.

The angular frequency is given by the coefficient of the variable t, which is 4π in this equation. Therefore, the angular frequency of the particle vibrating in simple harmonic motion is 4π rad/s.

Therefore, the answer is (b) 4 cm and 4π rad.

When water at 0 °C is heated, it actually decreases in volume until it reaches 4 °C due to the anomalous expansion behavior of water.

When water at 0 °C is heated, it actually decreases in volume until it reaches 4 °C.

This behavior is due to the anomalous expansion of water. Most substances contract as they cool and expand as they are heated. However, water behaves differently. As water is cooled from its maximum density at 4 °C, it contracts and its volume decreases. This contraction continues until it reaches 0 °C.

Once water reaches its freezing point at 0 °C, it undergoes a phase transition from a liquid to a solid state (ice). During this phase transition, the water molecules rearrange themselves into a crystalline structure, which results in an increase in volume and a decrease in density. Therefore, as water freezes, it expands and its volume increases.

When water at 0 °C is heated, it actually decreases in volume until it reaches 4 °C due to the anomalous expansion behavior of water.

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AP Physics 1 is a college-level introductory physics course designed to give high school students an understanding of the fundamental principles of physics.

The course covers topics such as mechanics, waves, thermodynamics, electricity, and magnetism. Students in AP Physics 1 learn to think critically and solve problems using scientific inquiry, experimentation, and analysis. The course is structured to provide students with hands-on laboratory experience and to develop their skills in using math and quantitative analysis to explain physical phenomena. At the end of the course, students take an exam that can qualify them for college credit and demonstrate their mastery of the concepts and skills covered in the course.

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Answer: Cross-cutting features are always younger than the surrounding rock.

When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

The options include:

1. An unconformity is created when lava pours out on Earth’s surface.

2. Faults are the result of volcanic activity.

3. Intrusions and extrusions are sedimentary formations.

4. Cross-cutting features are always younger than the surrounding rock.

5. When material erodes before sediment is deposited on it, a geologic gap results.

The law of superposition simply states that when there is a layers of rocks, we would see that the younger layers will lie and be on top of the layers that are older.

Other tools that can help scientist with relative dating are:

• Cross-cutting features are always younger than the surrounding rock.

• When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

It's on Edge

Answer:

It is cause by radiation that's the answer

Explanation: the heat project sun rays towards the popcorn which causes it to pop

The final equilibrium temperature (in °C) of the system when ice and water vapor are combined can be calculated using the principle of energy conservation and the specific heat capacities of ice and water.

To determine the final temperature, we can apply the equation:

(m₁ * c₁ * ΔT₁) + (m₂ * c₂ * ΔT₂) = 0

Where:

- m₁ is the mass of ice (22.0 kg)

- c₁ is the specific heat capacity of ice (2.09 J/g·°C)

- ΔT₁ is the change in temperature of ice (final temperature - 0.00 °C)

- m₂ is the mass of water vapor (4.80 kg)

- c₂ is the specific heat capacity of water (4.18 J/g·°C)

- ΔT₂ is the change in temperature of water (final temperature - 100.0 °C)

Solving for the final temperature, we find:

(22.0 kg * 2.09 J/g·°C * ΔT₁) + (4.80 kg * 4.18 J/g·°C * ΔT₂) = 0

Substituting the given values, we can solve for ΔT₁ and ΔT₂. Once we have those values, we can find the final temperature by adding ΔT₁ to 0.00 °C.

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Yes carbon dioxide is needed for photosynthesis while cellular respiration needs oxygen and dispurses carbon dioxide

An audience member covers her ears during a loud concert shows evidence that matter can reflect waves.

An audience member covers her ears during a loud concert is an event that provides evidence that matter can reflect waves because a sound is heard again and again due to the reflection of waves. This repetition of sound is due to the property of reflection of sound waves.

So we can conclude that an audience member covers her ears during a loud concert shows evidence that matter can reflect waves.

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Answer:

A laser beam bounces off a series of mirrors

Explanation:

Answer:

Explanation:

The mass of the car doesn't matter because On a flat curve the mass of the car does not affect the speed at which it can stay on the curve. You would need the mass if you were solving the the centripetal force acting on the car, but not the acceleration.

\(a=\frac{v^2}{r}\) and filling in

\(a=\frac{(8.5)^2}{48.0}\) and we need 2 significant digits in our answer. That means that

a = 1.5 m/sec²

Answer:

Protostars

Explanation:

Answer:

10 m^3 /s

Explanation:

1 m  X  2 m  X  5 m /s = 10 m^3/s

Answer:

Reasd through the explanartion first :)

Explanation:

Initial velocity, u = 30 m/s

Final velocity, v = 100 m/s

Acceleration, a = 40 m/s²

Distance traveled, s = ?

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

So, putting all the values, we get

⇒ v² - u² = 2as

⇒ (100)² - (30)² = 2 × 40 × s

⇒ 10000 - 900 = 80s

⇒ 9100 = 80s

⇒ 9100/80 = s

⇒ s = 113.75 m.

(a) The free body diagram for representing all the forces acting on an object.

(b) The force Mr. Seifert is applying to the box to move it forward to the RIGHT is 105 N.

A free body diagram is a graphical illustration of all the forces acting on an object.

The force applied by Mr Seifert is calculated by applying Newton's second law of motion as follows;

F - Ff = ma

where;

The given parameters include;

mass of the cardboard = 40 kg

force of friction = 25 N

acceleration of the cardboard = 2 m/s²

The force applied by Mr Seifert is calculated as follows;

F = Ff + ma

F = 25 N  +    (40 kg x 2 m/s²)

F = 105 N

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Answer:

Approximately \(5.11 \times 10^{-19}\; {\rm J}\).

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: \(R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}\).

Look up the speed of light in vacuum: \(c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}\).

Look up Planck's constant: \(h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}\).

Apply the Rydberg formula to find the wavelength \(\lambda\) (in vacuum) of the photon in question:

\(\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}\).

The frequency of that photon would be:

\(\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}\).

Combine this expression with the Rydberg formula to find the frequency of this photon:

\(\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}\).

Apply the Einstein-Planck equation to find the energy of this photon:

\(\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}\).

(Rounded to three significant figures.)

\(\\ \rm\Rrightarrow Work\:done=Force(Distance)\)

\(\\ \rm\Rrightarrow Work\:done=20(20)=400J\)

Option D

The change in the potential energy of the ball is equal to 0J. Therefore, option (A) is correct.

Work can be described as the energy used when a force is exerted to move an object through a specific displacement. The work done can be defined as it depends upon both the force on the object and the displacement by the object.

The displacement in a straight line in the direction of the applied force over a distance 'd'.

W= F × d

Where 'F' is the exerted force and 'd' is the displacement by the object.

The change in the potential energy or kinetic energy is equal to the work done.

The change in the potential energy  = mgh₂ - mgh₁

The ball roll over the surface, h₂ = h₁

Therefore, the change in the potential energy is equal to zero.

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To calculate the radiation pressure on a highly polished metal surface, the most appropriate approximation to use is the small-angle approximation.

Radiation pressure refers to the pressure produced when electromagnetic radiation is absorbed or reflected by a surface. A highly polished metal surface is highly reflective, and therefore is expected to produce high radiation pressure.

The small-angle approximation is the assumption that the angle of incidence is small enough such that the sine of the angle is equal to the angle itself. This approximation is particularly useful in situations where the angle of incidence is small relative to 1 radian or less. This approximation can be used to calculate radiation pressure on highly polished metal surfaces because the angle of incidence is usually small (typically less than 1 radian), and therefore can be approximated using the small-angle approximation.

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If you increase the frequency of a sound wave four times, the speed will increase four times. The correct option is A.

Particles that are vibrating make up sound waves. These collide with other particles, causing them to vibrate, which allows the sound to escape the source.

Your ear drums vibrate as a result of air vibrations, which allows you to perceive sound. This vibration is transformed into messages, which proceed to your brain via a nerve.

When sound is produced, air molecules shake and collide, causing vibrations to travel between air molecules. The sound is transmitted by the vibrating particles, which also cause the ear drum to vibrate.

A sound wave's frequency can be increased four times without increasing its speed.

Thus, the correct option is A.

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Answer:

\huge{\underline{\underline{.........Answer.........}}}

.........Answer.........

Given:-

u = 0.3 m/s

v = 5.5 m/s

t = 5 seconds

Explanation:-

Case-1

Acceleration = ?

From the first law of motion.

v = u + atv=u+at

a = \frac{v - u}{t}a=

t

v−u

a = \frac{5.5 - 0.3}{5}a=

5

5.5−0.3

a = \frac{5.2}{5}a=

5

5.2

a = 1.04a=1.04

\boxed{\boxed{a = 1.04 m/s^2}}

a=1.04m/s

2

So,the acceleration produced is 1.04 m/s^2.

Case-2

Distance travelled = ?.

From second equation of motion.

s = ut + \frac{1}{2} a {t}^{2}s=ut+

2

1

at

2

s = 0.3 \times 10 + \frac{1}{2} \times1.04 \times 100s=0.3×10+

2

1

×1.04×100

s = 3 + \frac{1}{2} \times 104s=3+

2

1

×104

s = 3 + 52s=3+52

s = 55 \: meterss=55meters

\boxed{\boxed{s = 55 meters}}

s=55meters

So,the distance travelled is 55 meters.

Explanation:

This is just example for your question

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Looking at the graph and its missing parts, we can identify the following items to fill each box:

A. Population Size.

Since the population size is a dependent variable in relation to time, we should use it in the vertical axis.

B. Slow growth when population is small.

In the first part of the graph, the population is small and also grows slowly.

C. Faster and faster growth as population becomes larger.

In the final part of the graph, the population is big and also grows fast.

D. Time

Since the time usually is an independent variable, we should use it on the horizontal axis.

Answer:

Explanation: A ball is thrown into the air at an angle of 50 degrees with a horizontal, and initial velocity of 12m/s. (i) we to find the total time of the flight, and (ii) maximum height that the ball reaches

(i) Total flight time:

To find the total time, we much keep in mind that it is the time that the bill would take to reach the same height level as its starting height, the equation that will be used is as follows:

By setting equation (1) equal to zero and solving for the "t" , the total flight time can be solved, it can be done as follows:

(ii) Maximum height of the ball:

The maximum height that the ball can reach would be attained in half of the total flight time, therefore we need to simply find the y(t) at half of the total flight time, this is done as follows:

Answer:

A reference frame is that frame to which the qualities of an object are related:

For instance - an object may described by - mass, speed, acceleration, size,  etc,

It is important to remember that Newton's Laws of motion do not hold in accelerated reference frames -

Einstein's laws of special relativity are only true in frames that move with contant speed to one another

Answer: Acceleration is 0.25m/s^2

Explanation:

The box with the changing data shows that the acceleration is constant at 4.90 m/s2, but i thought g = 9.80 m/s2.

The acceleration due to gravity (g) is different from the acceleration of the object itself. Although g is usually taken to be 9.8 m/s2, it can vary depending on the object's location and height above the Earth's surface. As a result, a falling object can experience acceleration greater than, less than, or equal to g when air resistance is taken into account or not

In the given scenario, the box is not necessarily in free fall; it could be undergoing linear motion along a surface. Furthermore, the box could be in free fall, but with air resistance affecting its motion. In this situation, the box's acceleration would be less than g.The box's acceleration may have been determined using an accelerometer or a ticker tape. Regardless, the acceleration indicates the rate at which the box's velocity is changing, which may or may not be equal to g.

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Answer:bight

Explanation:

64°F is equivalent to 17.78°C.

A temperature unit developed from the SI (International System of Units) is Celsius (symbol: °C).

Prior to the adoption of the metric system, Fahrenheit (symbol: °F) was a commonly used measurement of temperature.

To convert Fahrenheit (°F) to Celsius (°C) we have to first subtract 32 from Fahrenheit and then multiply it by .5556 or 5/9.

We have to convert 64 degrees Fahrenheit (°F) to Celsius (°C),

We can use the following formula:

°C = (°F - 32) x 5/9

As per the given information,

°F = 64

By placing the value 99.3 for °F, we get:

°C = (64 - 32) x 5/9

°C= 32 x 5/9

°C = 160/9

°C = 17.78 (rounded to two decimal places)

Therefore, 64°F is equivalent to 17.78°C.

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Question :-   What is 64°F in °C?

Answer:

are in equal size or act in same direction

Balanced forces are the forces which are equal in size. Balanced force has a net force which is equal to zero, and these do not cause a change in motion. Thus, the correct option is C.

Balanced forces are those which are opposite in direction and equal in the size. Balanced forces are considered to be in the state of equilibrium. When the forces are balanced and there is no change in direction. Combined forces which are balanced are always equal to zero. These forces are equal and hence do not cause any change in the motion of an object.

Examples of balanced forces include resting against a wall, lying down, aircraft in a steady-flight, floating in water, and standing in the ground.

Therefore, the correct option is C.

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The southern highlands of Mars are more heavily cratered than the northern low plains. Based on the age and elevation differences between the southern highlands and the northern low plains on Mars, the southern highlands are more heavily cratered.

The heavily cratered nature of the southern highlands compared to the northern low plains on Mars can be inferred based on the following factors:

Age: Cratering is a geological process that occurs over time as meteoroids and asteroids impact the planetary surface. Older regions tend to have more craters, indicating a longer exposure to impacts. The southern highlands of Mars are believed to be much older than the northern low plains, which suggests that they have had more time to accumulate craters.

Elevation: The southern highlands are generally at a higher elevation compared to the northern low plains. Higher elevation regions are more likely to be exposed to impacts because they present a larger target area for incoming projectiles. Therefore, the increased elevation of the southern highlands contributes to their higher cratering rate.

In conclusion, based on the age and elevation differences between the southern highlands and the northern low plains on Mars, we can infer that the southern highlands are more heavily cratered. The longer exposure time and higher elevation make the southern highlands more susceptible to impact events, resulting in a greater number of craters compared to the northern low plains.

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