The pendulum shown in the figure sweeps out an angle of =22.7∘ during its motion. How far does the pendulum bob (the ball at the end of the rope) travel in one complete cycle of motion if its length is =32.7 cm?

Answers

Answer 1

In order to allow it to freely swing, a weight is suspended from a pivot like a pendulum. the pendulum bob (the ball at the end of the rope) travel in one complete cycle is 17.8285 cm cycle.

The restoring force from gravity will cause a pendulum to accelerate back towards its equilibrium position when it is sideways moved from its resting, equilibrium position. The pendulum swings back and forth about the equilibrium position after being freed due to the restoring force acting on its mass.

In case the arc swept (and not the displacement from vertical)

At 22.7°, the length of the arc is 22.7°/360° circumference.

Circumference: 2r/22.5cm = 141.37cm

22.7°/360°×141.37cm = 8.914cm

The arc's measurement is 8.914 cm.

Returning to the beginning is a part of one cycle:

2.8914 divided by 17.8285 cm cycle

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Related Questions

A train accelerates at a constant rate of 1 m/s2. It passes through a 24.5 m wide level crossing in a time of 2 s. After the train leaves the crossing, how much time is required until its speed reaches 31 m/s?.

Answers

A train accelerates at a constant rate of 1 m/s², then the velocity of the train after time t₁ will be equal to 15.25 m/s.

What is Velocity?

Velocity is really the direction speed of an item in motion as a measure of the rate at which its location is changing as seen through a particular point of view and as determined by a specific unit of time. A key idea in kinematics, the area of classical physics that studies how bodies move, is velocity.

Acceleration, a = 1 m/s²

Distance, d = 24.5 m

Time, t = 2 s

Velocity, v₂ = 31 m/s

By the equation of motion,

v = u + at

v = v₁

t = t₁

v = v₁ - 4.2      (1)

24.5 = u(2) + 1/2(1)(2²)

u = 11.25 m/s

v₁ = u + 4

v₁ = 11.25 + 4

v₁ = 15.25 m/s.

Therefore, the velocity of the train after time t₁ is 15.25 m/s.

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An ammeter has azero offset error This fault will affect

Answers

Answer:

An ammeter has a zero offset error. This fault will affect. neither the precision nor the accuracy of the readings. only the precision of the readings.

The accuracy of the present measurement will be impacted by an ammeter's zero offset inaccuracy, but the precision of the measurement will not change.

What is resistance?

Resistance is the obstruction of electrons in an electrically conducting material.

                                                                                         

voltage = current ×resistance

How accurate measurement or reading is may be determined by its accuracy. The measurements will be off because of zero inaccuracy.

Thus, The precision of the measurement would not alter if an ammeter made a mistake with its zero offsets, but the accuracy of the current measurement would be decreased.

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If earth is squeezed into the size of moon, what will be the weight of a person of 50 kg mass on the surface of earth? [Mass of Earth = 4 x 1024 kg. Radius of Moon = 1.7 × 103 km]​

Answers

Answer:

4618.9N

Explanation:

We need to start of by calculating the Gravitational Force (acceleration) of the Earth (IF it was the same size as the moon) which is showed as follows:

\(g = \frac{GM}{r^2}\) where g is the gravitational acceleration, G is the gravitational constant (6.673 × \(10^{-11}\) Nm^2kg^-2), M is the mass of the planet, r is the radius of the planet.

Substituting the values as given in the question,

\(g = \frac{6.673 * 10^{-11} * 4 * 10^{24}}{(1.7*1000 * 1000)^2}\\\\= \frac{26.69200 * 10^{13}}{2890000000000}\\\\\\= 92.3598615917 N/kg\)

Hence, the gravitational force is 92.4N/kg (or m/s^2).

Considering this,

50 * 92.4 = 4618.89N ≈ 4618.9N

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One car is traveling north at 80 km/h. A second car is traveling south at 80 km/h. Both cars have the same velocity
True
False

Answers

True because it is the same amount and same speed but just different directions and people

Answer: True

Explanation:

1. Alexandra and Rachel are on a train that sounds a whistle at a constant frequency as
it leaves the train station. Compared to the sound emitted by the whistle, the sound that
the passengers standing on the platform hear has a frequency that is
a. lower, because the sound-wave fronts reach the platform at a frequency
lower than the frequency at which they are produced
b. lower, because the sound waves travel more slowly in the still air above the
platform than in the rushing air near the train
c. higher, because the sound-wave fronts reach the platform at a frequency
higher than the frequency at which they are produced
d. higher, because the sound waves travel faster in the still air above the
platform than in the rushing air near the train

Answers

Answer: the answer would be C trust me i took the test if its not that its b

hope that helps

Explanation: i took the test

answer:

a) lower because the sound-wave fronts reach the platform at a frequency lower than the frequency at which they are produced

explanation :3

If the train is leaving the train station, then the people who are standing on the platform would hear a sound with a lower frequency since the train is moving further away. ^^

A ball is throw at an angle of 30 degrees off the horizontal, with an initial velocity of 28 m/s. what is the maximum height the ball will reach?​

Answers

\({\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{Angle \ of \ projection = 30^{\circ} }\)

\(\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ of \ projectile = 28 \: m/s^{-1} }\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{Height_{\:(max)}\: reached\: by \:the \:projectile }\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\\)

As we know that,

\(\\\)

\(\dashrightarrow\:\: \sf{ H = \dfrac{u^2\;sin^2\theta}{2\;g} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{H = \dfrac{(28)^2\;sin^2 30^{\circ}}{2\;(9.8)} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{H = \dfrac{784 \times \;sin^230^{\circ}}{19.6} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{ H = \dfrac{784}{19.6}\times sin^2 30^{\circ}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{ H = \dfrac{784}{19.6}\times \bigg(\dfrac{1}{2}\bigg)^2 }\)

\(\\\)

\(\dashrightarrow\:\: \sf{ H = \dfrac{784}{19.6}\times \dfrac{1}{4} }\)

\(\\\)

\(\dashrightarrow\:\: {\boxed{\sf{H=10\:m }}}\)

if an 80kg object has 632 J of PE, how high is it

Answers

The object is on 81 cm high.

What is potential energy?

The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.

Given that: an 80kg object has 632 J of Potential energy.

Let the height is h: then,

mgh = PE

80 kg × 9.8× m/s^2 × h = 632 Joule

h = 0.81 m = 81 cm.

The object is on 81 cm high.

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PROBLEMS Q2/ In the cct shown in Figure, find: 1) Rt 2) Ibe Iaf​

PROBLEMS Q2/ In the cct shown in Figure, find: 1) Rt 2) Ibe Iaf

Answers

The circuit consists of a series of number of pairs of parallel and series

arranged resistors.

Correct responses:

\(R_T\) = 12 Ω\(I_{BE}\) = 0.5 A\(I_{A_F}\) = 2 A

Methods used for calculations to obtain the above responses

The total resistance can be calculated as follows;

Resistance between point C to D and from D to E are in series, therefore;

We have;

\(R_{CD}\) = 5 Ω and \(R_{DE}\) = 9 Ω are parallel

Therefore;

\(R_{TCE} = \mathbf{ \dfrac{1}{\dfrac{1}{R_{CE}} + \dfrac{1}{R_{CD} +R_{DE}} }}\)

\(R_{TCE} = \dfrac{1}{\dfrac{1}{14} + \dfrac{1}{5+9} } = 7\)

\(R_{TCE}\) = 7 Ω

\(R_{BC}\) = 11 Ω is in series with \(R_{CE}\) both of which are parallel to \(R_{BE}\) = 18 Ω

\(R_{TBE} = \mathbf{\dfrac{1}{\dfrac{1}{R_{BE}} + \dfrac{1}{R_{BC} + R_{TCE}} }}\)

Therefore;

\(R_{TBE} = \mathbf{\dfrac{1}{\dfrac{1}{18} + \dfrac{1}{11 + 7} }} = 9\)

\(R_{TBE}\) = 9 Ω

\(R_{TAE} = \mathbf{\dfrac{1}{\dfrac{1}{R_{AE}} + \dfrac{1}{R_{AB} + R_{TBE}} }}\)

Therefore;

\(R_{TAE} = \dfrac{1}{\dfrac{1}{22} + \dfrac{1}{13 + 9} } = 11\)

\(R_{TAE}\) = 11 Ω

\(R_T = \mathbf{R_{TAE} + R_{A_F}}\)

Therefore;

\(R_T\) = 11 Ω + 1 Ω = 12 Ω

The current in the circuit, I, is therefore;

\(\displaystyle I = \frac{24 \ v}{12 \ \Omega} = \mathbf{2 \ A}\)

By current divider rule, due to the equality of the parallel resistances we have;

Current through AB, \(I_{AB}\) = \(\frac{1}{2} \times 2 \ A\) = 1 A

Similarly;

Current through BE, \(\mathbf{I_{BE}}\) = \(\frac{1}{2}\) × 1 A = 0.5 A

Current through \(\mathbf{I_{A_F}}\) = The circuit current, I = 2 A

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explain why a wrecking ball can destroy a building, but a yo-yo cant. Use the term kinetic energy in your explanation.

Answers

released weight increases in velocity.

momentum increases as force increases.

momentum= mass x velocity

the wrecking ball has a bigger mass and weight.

the mass of the weight of the wrecking ball is constant, the velocity of the weight as it swings must be increased if momentum is going to be increased.

The kinetic energy of a body determines it's level of impact on the object in which it comes in contact with. Hence, the much larger kinetic energy exhibited by a wrecking ball compared to a yo-yo means that is has a much larger impact on a building than a yo-yo.

Kinetic Energy = 0.5mv²

The kinetic energy of a body is a factor of it's velocity and mass as they are directly proportional.

The wrecking ball has a very large mass which is thousands of times larger than that of a yo-yo. Also, the velocity at which a wrecking ball is launched is higher than the velocity of a yo-yo.

This means that the kinetic energy of a wrecking ball is much higher than that of yo-yo. Hence, having much greater impact on a building compared to a yo-yo.

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what is the relationship between work and mechanical advantage

Answers

Answer:
Mechanical efficiency: the comparison of the machine's work output with it's work input
Mechanical advantage: the number of times that the machine multiplies the force


Explained:
what is the relationship between work and mechanical advantage

Bella is taking an adventurous trip through the jungle. First, she trekked for 1 hour into the thick jungle at an average speed of 6 km/h. next, she took a boat to cross a lake which rode her at an average speed of 20 km/h for 0.5 hours. for the lost part of her trip, she hiked for 2 hours at an average speed of 4 km/h. find the total distance on her trip.

Answers

The total distance of Bella's trip through the jungle is 24 kilometers.

To find the total distance of Bella's trip, we need to calculate the distance traveled during each leg of her journey and then sum them up.

Let's calculate the distance traveled in each segment:

Trekking in the thick jungle:

Bella trekked for 1 hour at an average speed of 6 km/h.

Distance = Speed × Time

Distance = 6 km/h × 1 hour

Distance = 6 km

Crossing the lake by boat:

Bella rode a boat at an average speed of 20 km/h for 0.5 hours.

Distance = Speed × Time

Distance = 20 km/h × 0.5 hour

Distance = 10 km

Hiking for the remaining part:

Bella hiked for 2 hours at an average speed of 4 km/h.

Distance = Speed × Time

Distance = 4 km/h × 2 hours

Distance = 8 km

Now, let's calculate the total distance:

Total distance = Distance of trekking + Distance of crossing the lake + Distance of hiking

Total distance = 6 km + 10 km + 8 km

Total distance = 24 km

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Weight is best defined as _____. A the amount of space an object takes up B the speed of an object C the force of gravity on an object D the amount of energy in an object

Answers

Weight is best defined as C) the force of gravity on an object.

A short tennis player hits a ball that is


r meters from their elbow with an angular acceleration

αalpha. A tall tennis player hits a ball with the same angular acceleration where the ball is
2, r from their elbow .

Answers

The tangential acceleration of the short player's ball is twice the tangential acceleration of the tall player's ball.

How does the acceleration affect the ball?

The ball of the shorter player experiences twofold of the ball of the taller player's tangential acceleration. The reason behind this is that the magnitude of the tangential acceleration correlates directly with the radius of the circle.

The ball belonging to the smaller player is positioned nearer to the elbow, resulting in a decreased radius. It can be deduced from this statement that the ball of the short player experiences twice the magnitude of tangential acceleration compared to the ball of the tall player.

The answer is: ashort = 2atall

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The Complete Question

A short tennis player hits a ball that is r meters from their elbow with an angular acceleration a. A tall tennis player hits a ball with the same angular acceleration where the ball is 2r from their elbow. How does the tangential acceleration of the short player's ball Ashort compare with the tall player's ball a tall? Choose 1 answer: ashort 2atall ashort Otall ashort 1 atall 2

how does mass relates to latent heat?​

Answers

The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

What is latent heat?​

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?

Answers

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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Question 3 of 25The pitch of a sound is most closely associated with theof the wave.A. wavelengthO B. amplitudeO C. speedO D. frequencySUBMIT

Question 3 of 25The pitch of a sound is most closely associated with theof the wave.A. wavelengthO B.

Answers

The pitch of a sound can be determined in sounds that have a distinguished frequency. Therefore, it depends on the frequency.

Answer:

The pitch of a sound is most closely associated with the frequency of the wave

What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 550 nm

Answers

Answer:

The expression for destructive interference in thin films allows to find the result for the smallest thickness of the films is:

         t = 2.03 10⁻⁸ mm

Explanation:

Given parameters

Incident wavelength lamo = 535 nm

Refractive index of the film n = 1.32

To find

The minimum thickness for destructive interference

The interference phenomenon occurs when the path of two rays scattered by an obstacle have different optical paths. In the case of thin films we must take into account:

The reflected wave has a phase change of 180º when it goes from a medium with a lower refractive index to a medium with a higher index.

Inside the film medium the wavelength is modulated by the refractive index.

                 

In the attachment we see an outline of these events and the expression for destructive interference remains.

               2 n t = m λ₀

Where n is the refractive index, t the thickness of the film, λ₀ the wavelength in the vacuum and m an integer indicating the order of interference.  

             t =  

The first destructive interference occurs for m = 1, let's calculate.

       t =    

       t = 202.65 nm

Let's reduce this amount to millimeters.

        t = 202.65 nm  

        t = 2,027 10⁻⁸ mm

In conclusion, using the expression for destructive interference in thin films we can find the result for the smallest thickness of the films is:

         t = 2.03 10⁻⁸ mm

1. True or False: All aspects of health are equally important. A problem in one area can affect
other areas.
A true
B false

Answers

This is true so the answer would be A

A map suggests that Atlanta is 730 miles in a direction 5.00° north of east from Dallas. The same map shows that Chicago is 560 miles in a direction 21.0° west of north from Atlanta. The figure below shows the location of these three cities. Modeling the Earth as flat, use this information to find the displacement from Dallas to Chicago. Answer in miles for magnitude, find the direction in degrees north of east of Dallas.

Answers

The magnitude of the displacement is 1,097.7 mi, and the angle is 89.9°

How to find the magnitude and direction in degrees of the displacement?

To find the displacement from Dallas to Chicago, we can break down the vectors representing the distances and directions into their x and y components. Since the Earth is modeled as flat, we can use basic trigonometry to calculate the components.

Let's start by considering the vector from Dallas to Atlanta. The magnitude of this vector is given as 730 miles, and the direction is 5.00° north of east. To calculate the x and y components, we can use the following equations:

x = magnitude_DA * cos(angle_DA)y = magnitude_DA * sin(angle_DA)

Substituting the values:

x = 730 * cos(5.00°)

y = 730 * sin(5.00°)

Similarly, for the vector from Atlanta to Chicago, with a magnitude of 560 miles and a direction 21.0° west of north:

x = magnitude_AC * sin(angle_AC)

y = magnitude_AC * cos(angle_AC)

Substituting the values:

x = 560 * sin(21.0°)

y = 560 * cos(21.0°)

To find the displacement from Dallas to Chicago, we can sum the x and y components:

x_displacement = x_component_DA + x_component_ACy_displacement = y_component_DA + y_component_AC

Now, we can calculate the magnitude and direction of the displacement using these x and y components:

magnitude_displacement = √(x_displacement² + y_displacement²)

angle_displacement = atan(y_displacement / x_displacement)

Finally, we can substitute the calculated values and solve for the magnitude and direction:

magnitude_displacement = √((730 * cos(5.00°) + 560 * sin(21.0°))² + (730 * sin(5.00°) + 560 * cos(21.0°))²) = 1,097.7 miangle_displacement = atan((730 * sin(5.00°) + 560 * cos(21.0°)) / (730 * cos(5.00°) + 560 * sin(21.0°))) = 89.9°

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How does the force of gravity change as the mass of one object doubles?

Answers

If the mass of one of the objects is doubled, then the force of gravity between them is doubled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

The force of gravity changes as the mass of one object doubles. As the mass of one object is doubled then the force between the objects also gets doubled.

What is Force?

Force is an influence which can change the motion of an object through the application of an external force. A force can cause an object with the mass to change its velocity, that is the object undergo acceleration.

Force is directly proportional to the mass of the object and the acceleration of the object. If we double the mass of one of the objects, then we double the strength of the force. If we double the masses of both the objects, then we quadruple the strength of force.

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The way in which one atom interacts with another atom is mostly influenced by the configuration of the
A. electrons farthest from the nucleus.
B. protons in the center of the nucleus.
C. electrons closest to the nucleus.
D. protons on the outer edge of the nucleus.

Answers

The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

Option A.

What is atom?

An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).

The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.

Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

The remaining options do not fit the empty space properly, and they include;

protons in the center of the nucleus.electrons closest to the nucleus.protons on the outer edge of the nucleus.

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A 750 kg race car accelerates to the right. The engine applies a force of
+7000 N to the car. The total friction on the car in the opposite
direction is -200 N.
Find the net force on the car then use 'Fnet = m a' to find the
acceleration.
O a
b
Oc
Od
12.4 m/s2
10.5 m/s2
8.0 m/s2
9.1 m/s2

Answers

Refer to the photo taken.
Answer: Option D, 9.1 m/s^2
A 750 kg race car accelerates to the right. The engine applies a force of+7000 N to the car. The total

Which of the following is true about the International Space Station?
A
It is on the surface of Mars.

B
It is the size of ten football fields.

C
It was built from separate parts sent to space.

D
It was a partnership between the US and Soviet Union.

Answers

Answer: It was built from separate parts sent to space.

Answer:

c because first is totally wrong and second one is about two football fields and d is also totally wrong because it is a partnership of at least 10 countrie so.i think č is correct answer.

when a force of 400m is applied on a body at an angle to the horizontal direction of displacements the body covers a distance of 8m calculate the work done​

Answers

The work done​  to the horizontal direction of displacements the body is 3200 joule.

What is work done?

A force must be applied and there must be movement in the force's direction for a work to be completed scientifically.

With that said, we may state that Work is the product of the force's component acting in the displacement's direction and its magnitude.

Applied force = 400 N

Displacement in the direction of force = 8 m

Hence, work done = 400 ×  Joule = 3200 joule.

Therefore, the work done​  to the horizontal direction of displacements the body is 3200 joule.

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What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m

Answers

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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If an automobile with a velocity of 4.0 m/s accelerates at a rate of 4.0 m/s2
for 2.5 s, what is the final velocity?

Answers

Answer:

V=u+at

=4+4*2.5

=14m/s

Explanation:

Initial velocity =4m/s

acceleration =4m/(second) squared

time =2.5 seconds

v=u+at

v=4+4*2.5

v=14m/s

compare and contrast speed and velocity.​

Answers

Speed is the time rate of an object moving from one place to another, while velocity is the rate and direction of the object's movement. They are very similar but they don't mean the same thing.

Given the information in the velocity vs. time graph, what is the displacement of the object after 1 second?


_____ m


After 3 seconds?


_____ m


After 5 seconds?


_____ m


Thank you!!!

Given the information in the velocity vs. time graph, what is the displacement of the object after 1

Answers

The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

What is displacement?

The displacement of an object is the change in the position of the object.

displacement of the object after 1 second

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

displacement of the object after 3 second

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

displacement of the object after 5 second

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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A spring has a force constant of 440.0 N/m.
(a) Determine the potential energy stored in the spring when the spring is stretched 4.15 cm from equilibrium.
(b) Determine the potential energy stored in the spring when the spring is stretched 2.96 cm from equilibrium.
(c) Determine the potential energy stored in the spring when the spring is unstretched.

Answers

Following are the answer:

The potential energy stored in the spring when it is stretched 4.15 cm from equilibrium is 0.0424 J.The potential energy stored in the spring when it is stretched 2.96 cm from equilibrium is 0.0207 J.The potential energy stored in the spring is zero.

What is potential energy?

Potential energy is the energy possessed by an object due to its position or configuration relative to other objects. It is the energy that an object has stored in it as a result of its position or state. An object's potential energy is often associated with its ability to do work, which can be released when the object is allowed to move or change its position.

(a) The potential energy stored in a spring stretched by a distance x from its equilibrium position can be calculated using the formula:

\(U = (1/2) k x^2\)

where k is the spring constant.

Substituting the given values, we get:

\(U = (1/2) (440.0 N/m) (0.0415 m)^2U = 0.0424 J\)

Therefore, the potential energy stored in the spring when it is stretched 4.15 cm from equilibrium is 0.0424 J.

(b) Using the same formula as in part (a), but with x = 0.0296 m, we get:

\(U = (1/2) (440.0 N/m) (0.0296 m)^2U = 0.0207 J\)

Therefore, the potential energy stored in the spring when it is stretched 2.96 cm from equilibrium is 0.0207 J.

(c) When the spring is unstretched, its potential energy is zero, since there is no displacement from equilibrium. So the potential energy stored in the spring is zero.

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What are spooky rays? How were they discovered? How are they related to visible light?​

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What are spooky rays? :Spooky rays are Halloween; Spooky mystic background light beams rays.

How was spooky rays discovered; In 1895,a German Engineer Wilhelm ntgen, was experimenting with making cathode rays .His device was blacked out.But he noticed a piece of cardboard painted with barium platinocyanide flouresced when it was placed near the cathode ray tube.

How are they related to visible light?: This occurs when two particles are inextricably linked.

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