The number of moles of a substance can be converted into
molecules by:
a Dividing them by Avogadro's number
b Multiplying them by their molar mass
C Dividing them by their molar mass
d Multiplying them by Avogadro's number

Answer:

If there are more products than reactants, that means the reaction has shifted towards the left, which is the backward direction. If there are more reactants than products, that means the reaction has shifted towards the right, which is the forward direction.

Answer:

Explanation:

The best way to explain this is to use an example

\(I\frac{125}{53} + e \frac{0}{-1} ====> Te\frac{125}{52}\)

You have to understand what happened. A electron was shot into the nucleus of the Iodine. That electron change the entire composition of the nucleus resulting in 52 protons. The mass remained the same (125) but the nucleus was altered. The chemical became 125 52 Tellurium.  But what is important is that it takes a tremendous amount of energy to disrupt a nucleus, and a new chemical is born from that disruption.

The carbon in Compound 3 matches the carbon in Compound 4a with an asterisk is C2. Therefore, option B is correct.

Alpha-cadinol is a cadinane sesquiterpenoid that has a hydroxy group at position 10. It acts as a fungicide and a plant metabolite.

This compound is synthesized in two main steps. In the first step, compound 1 undergoes nucleophilic addition to compound 2. Then, the product compound 3 formed will undergo intramolecular aldol condensation. This cyclic product further undergoes dehydration and forms two isomers compound 4a and compound 4b. The compound 4a only is converted to alpha-cadinol.

In the conversion of compound 3 to compound 4a, carbon 2 containing acidic hydrogen will deprotonate and attack the carbonyl of the 5-carbon ring. Therefore, the asterisk is carbon 2.

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Answer:

i think option a is correct answer because when there is low temperature then the kinetic enegry will be very less and the atoms moves very slowly.

Answer:

A. very, very slowly

Explanation:

A is the answer because atoms will move faster in hot gas than in cold gas.

A brother is bragging about doing a bench press of 4000 grams at the gym. 4000 grams is equal to 8.818 pounds.

The bench press or chest press is training or weight training to strengthen your arm and chest muscles. It is done by laying down on a bench and pushing and pulling up the bars with weight.

It is a common weight-lifting exercise in gyms. Trainers use accordingly weight on the basis of the trainee's weight and strength that is doing the bench press, and the weight is measured differently in different countries. Eight-pound is not a very big amount.

In America, weight is measured in pounds, one kg is 1000 grams and

1 gram is 0.00220462

4000 x 0.00220462

4000 grams will be 8.818 pounds.

Thus, 4000 grams is equal to 8.818 pounds.

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The final temperature of the mixture given that 25 g of water at 25 °C is mixed with 25 g of water at 65 °C, is 45 °C

The final temperature of the mixture can be obtained by calculating the equilibrium temperature of the mixture. This is shown below:

Heat loss by warm water = Heat gain by cold water

MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)

Cancel out C

Mᵥᵥ(Tᵥᵥ - Tₑ) = M(Tₑ - T)

25× (65 - Tₑ) = 25 × (Tₑ - 25)

Cancel out 25

65 - Tₑ = Tₑ - 25

Collect like terms

65 + 25 = Tₑ + Tₑ

90 = 2Tₑ

Divide both side by 2

Tₑ = 90 / 2

Tₑ = 45 °C

Thus, we can conclude that the final temperature the mixture is 45 °C

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The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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Answer:

69

Explanation:

Answer:

The waters' temp increased

Explanation:

The temperature of the water in the swimming pool has increased due to the heat from the Sun. As a result, the particles in the water are moving faster and have a higher kinetic energy than in the morning.

The type of isomerism shown is structural isomerism and the molecular formula of the compounds are as follows:

Isomers are molecules that have the same molecular formula but differ in the arrangement or spatial orientation of atoms within the molecule. In simpler terms, isomers are compounds that have the same chemical formula but different structures.

Isomerism arises due to the different ways in which atoms can be connected or arranged within a molecule.

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Answer:

4.67 liters of SO2 with sig figs

Explanation:

To do this reaction, we first must find the limiting agent.
in this problem, 5 liters of H2S are reacted with 7 liters of O2, and each two moles of H2S corresponds to 3 moles of O2. Assuming ideal behavior, 1 liter of H2S has the same number of moles as 1 liter of O2 has. So, 2 liters of H2S react with 3 liters of O2. To find the limiting reagent, focus on one reagent and calculate how much of the other reagents would be needed to fully consume that one reagent.
Focus on H2S:
5 liters of H2S would require 7.5 liters of O2 (since each 2 liters of H2S requires 3 liters of O2)

Focus on O2:
7 liters of O2 would require 14/3, or 4.666... liters of H2S.

Since we don't have 7.5 liters of O2 (we only have 7 liters) to react with all 5 liters of H2S, we would say that O2 is the limiting reagent, and that we have 7 liters of it.

Next, figure out how much product can be produced per mole of that limiting reagent. 3 moles of O2 and 2 moles of H2S turns into 2 moles of SO2 and 2 moles of H2O. Thus, the ratio of O2 to SO2 is 3:2
We have 7 liters of O2, and since the ratio of O2 to SO2 is 3:2, we can set up the equation:
7:x = 3:2 where x is the number of liters of SO2
cross multiply (or solve with another method) to get:
x = 14/3, or 4.666... liters of SO2

It is an amine, and it has less polar nitrogen-hydrogen and oxygen-hydrogen bonds.

A compound's boiling point is a physical characteristic. These intramolecular linkages between the molecules that make up a chemical affect these physical characteristics.

Alcohols and amino acids have the same kind of intermolecular linkages. The hydrogen bond is the name of this kind of bond.

The electrical attraction between a hydrogen atom from one molecule and an electronegative atom from a nearby molecule is known as a hydrogen bond.

The strength of the bond is in the following order: H.....F > H.....O > H......N

The H....N hydrogen bonds exist in amines, whereas the H....O hydrogen bonds exist in alcohols.

Consequently, the alcohol's hydrogen bonds are stronger and it will impart a higher boiling point on the compound.

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Answer:uses world like

Explanation:

To ensure data traceability and accessibility is to complete a study beginning-to-end on a closed system or platform.

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The solubility of the salts is affected by the temperature changes. 1. NaCl is least affected by temperature. 2. supersaturated. 3. 60 grams KBr. 4. Ethanol has both polar and non-polar groups. 5. Mixing and shaking.

A KBr solution with 90 gm solute in 100 grams of water at 50 degrees is classified as supersaturated. 60 grams of KBr are needed to make a saturated solution in 100 gm of water at 30 degrees.

Ethanol is a general solvent due to the presence of both the polar and the non-Polar groups. As a result, it is easier to dissolve both polar molecules and non-Polar molecules. The dissolving rate can be increased by mixing or shaking the solution. Also, the sugar dissolves faster in hot than cold tea.

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Answer:

positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Answer:

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Answer:

0.20 g/L

Explanation:

Step 1: Calculate the molar mass of the gas (M)

At T = 350 °C = 623 K and P = 1 atm (we will assume this data), the density (ρ) of the gas is 0.087 g/L. We can calculate the molar mass of the gas using the following expression.

ρ = P × M/R × T

M = ρ × R × T/P

M = 0.087 g/L × (0.0821 atm.L/mol.K) × 623 K/1 atm = 4.5 g/mol

Step 2: Calculate the density of the gas at STP

At standard temperature (T = 273.15 K) and standard pressure (P = 1 atm), the density of the gas is:

ρ = P × M/R × T

ρ = 1 atm × 4.5 g/mol /(0.0821 atm.L/mol.K) × 273.15 K = 0.20 g/L

The mass of ammonia formed if it were to be the only product would be 17 grams.

Nitrogen gas reacts with hydrogen gas to form ammonia gas according to the following balanced equation:

\(N_2 + 3H_2 --- > 2NH_3\)

From the balanced equation of the reaction, the mole ratio of nitrogen to hydrogen gas is 1:3.

Recall that, mole = mass/molar mass

Thus, 14.01 g of nitrogen gas would be:

   14.01/28.02 = 0.5 mol

5.02 g of hydrogen gas would be:

   5.02/1.01 = 5.0 mol

Since the mole ratio from the balanced equation is 1:3, 0.5 mol nitrogen should require 1.5 mol hydrogen. In other words, 5.0 mol hydrogen is excess while 0.5 mol nitrogen is the limiting reactant.

The mole ratio of nitrogen to the ammonia produced is 1:2. Thus, the equivalent mol of ammonia gas produced would be:

0.5 x 2 = 1 mol

Mass of 1 mol ammonia = 1 x 17

                                        = 17 grams

Thus, the mass of ammonia gas that will be formed from 14.01 g sample of nitrogen gas and 5.02 sample of hydrogen gas would be 17 grams.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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The correct answer is the radioactive decay.

Let us understand this.

For example, alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus).

Another example of nuclear fission is radioactive decay process in which the nucleus of an atom splits into smaller parts and huge amount of energy is released.

Hence, the correct process is radioactive decay.

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Answer:

sorry if I get this wrong I think it is C

Explanation:

Answer:Cellular respiration is not the same as breathing, but they are closely related

Explanation: When you breathe in, you take in the oxygen your cells need for cellular respiration. When you breathe out, you get rid of carbon dioxide that your cells produce during cellular respiration.

To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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(a)  The mass percent of HCl in the solution is approximately 36.1%.

(b)  The molality of HCl in the solution is approximately 15.5 mol/kg.

(c)  The mole fraction of HCl in the solution is approximately 0.218.

(a) To calculate the mass percent of HCl, we need to determine the mass of HCl in a given volume of the solution.

Given: Concentration of HCl = 11.8 M

Density of the solution = 1.190 g/mL

First, we need to calculate the mass of the solution. Since density is mass per unit volume, the mass of 1 mL of the solution is 1.190 g.

Next, we need to calculate the mass of HCl in 1 mL of the solution. Since the concentration is given in moles per liter (M), and the molar mass of HCl is 36.46 g/mol, we can calculate the mass of HCl in 1 mL as follows:

Mass of HCl = concentration × volume × molar mass

          = 11.8 mol/L × 0.001 L × 36.46 g/mol

          = 0.430 g

Now, we can calculate the mass percent of HCl using the following formula:

Mass percent = (mass of solute ÷ mass of solution) × 100

           = (0.430 g ÷ 1.190 g) × 100

           ≈ 36.1%

(b) The molality of HCl is calculated by dividing the moles of solute (HCl) by the mass of the solvent (water) in kilograms.

Since the density of the solution is given as 1.190 g/mL, the mass of 1 mL of the solution is 1.190 g. However, we need to consider the density of the solvent (water) to calculate the mass of water in the solution.

Assuming the density of water is 1 g/mL, the mass of water in 1 mL of the solution is (1.190 g - 0.430 g) = 0.760 g.

To calculate the molality of HCl, we need to convert the mass of water to kilograms:

Mass of water (kg) = 0.760 g ÷ 1000 = 0.000760 kg

The molality (m) is calculated using the formula:

Molality = (moles of solute ÷ mass of solvent in kg)

        = (11.8 mol/L × 0.001 L) ÷ 0.000760 kg

        ≈ 15.5 mol/kg

(c) The mole fraction (X) of HCl is calculated by dividing the moles of HCl by the total moles of all components in the solution.

To calculate the mole fraction, we need to consider the volume of the solution and convert it to liters.

Given: Concentration of HCl = 11.8 M

Volume of the solution = 1 mL

Volume of the solution (L) = 1 mL ÷ 1000 = 0.001 L

To calculate the mole fraction of HCl, we need to calculate the moles of HCl and the moles of water (solvent) in the solution.

Moles of HCl = concentration × volume

            = 11.8 mol/L × 0.001 L

            = 0.0118 mol

Moles of water = mass of water ÷ molar mass of water

             = 0.760 g ÷ 18.015 g/mol (molar mass of water)

             = 0.0422 mol

Total moles in the solution = moles of HCl + moles of water

                           = 0.0118 mol + 0.0422 mol

                           = 0.054 mol

Mole fraction of HCl = moles of HCl ÷ total moles

                   = 0.0118 mol ÷ 0.054 mol

                   ≈ 0.218

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evaporation because the water is coming out of the water into the air

Diatomic: Composed of two atoms. Polar: A bond with a negative end and a positive end. Nonpolar: A bond in which neither atom takes more than its share of electrons. Metallic: A type of bond that allows valence electrons to move freely among ions. Electronegativity: Determines what type of bond will form.

The ability of an atom or functional group to draw electrons to itself is known as electronegativity in chemistry.

Diatomic molecules consist only of two atoms, whether they are from the same or distinct chemical elements.

Since charges fluctuate, a momentary dipole moment occurs in a so-called nonpolar molecule at any given time if the charge arrangement is spherically symmetric when averaged across time.

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Answer:

N - 1s²2s²2p³

Explanation:

Nitrogen is located in the p-block of the periodic table (groups 13-18) and is on the 2nd period.

The 2nd period tells us the principal energy level (a quantum number) is n = 2. Therefore, it must have already filled up the 1s sublevel.

The groups 13-18 on period 2 tells us that the 2s sublevel is also filled.

Nitrogen is located in Group 15. That means that there are 3 electrons that have filled the 2p sublevel, out of a possible 6.

Therefore, our electron configuration is 1s²2s²2p³

2p³ (Shorthand Config)

[He] 2s²2p³ (Noble Gas Config)

Answer:

A

Explanation:

on edge

Drift nets are a problem because when they are lost in the sea, they may continue to kill many animals.

This is referred to as a fishing technique where nets, called drift nets, hang vertically in the water column and are arranged to drift with the tide or current  without being anchored to the bottom.

In a situation whereby they are lost or left,  they may continue to kill many animals in what is referred to as ghost fishing which may lead to overexploitation and a disruption in the ecosystem thereby making it the correct choice.

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When a chocolate bar is solid, it is able to smell it.  It is also important to note that a substance 's molecules cannot be in two distinct phases at the a time.

In general, it is not possible for a the molecules of the chocolate  to be in two distinct phases at the same time.

It must be noted that smelling a solid, such as a chocolate bar, however, mean  the release  of loose molecules from the solid,   which may then move   through the air and   reach our olfactory receptors in our nose, allowing us to sense the fragrance.

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Answer:

Therefore we can say that the total number of electrons present in $ p - $ orbital of chlorine atoms is eleven.

Explanation: