The net work done in accelerating a solid cylindrical wheel from rest to an angular speed of 5050 rev/ min is W=590. J. If the radius of the wheel is 1.10m, what is its mass?

The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:

k = Q / (A * ΔT * L) = Rth * (A * ΔT)

Reorganizing this equation gives:

Rth = k / (A * ΔT)

The given information in the problem is:

Rate of heat flow (Q) = 14.0 watts

Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C

Temperature difference (ΔT) = 28°C

Substituting these values into the equation, we have:

k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK

So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.

The power needed to boil the water is divided by the element's power output, and the result is multiplied by 100 to get the efficiency of the kettle as a percentage. The answer is 79 %.

We are informed that

Electric kettle power is 1 kW.

Electric kettle voltage is 230 V.

The time it takes the kettle to bring the water to boiling point is 7.5 minutes.

1 kg = mass of water.

Heat generated equals V x I x t + Pt.

generated heat = 1000 W x 7.5 x 60

Heat absorbed equals (100 - 15) x 1 x 4200 = 4200 x 85

Efficiency is determined by multiplying the heat produced by the heat absorbed by 100.

= 4.2 x 85 x 10^3 / 4.5 x 10^5 x 100

= 357 / 4.5 = 79 %

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Answer:

Heat, which is the exchange of energy between a system and its surroundings, occurs in three major ways: conduction, convection and radiation.

Which has higher heat capacity oil or water?

For both the hot plate and the microwave, olive oil will heat up faster than water because the heat capacity of oil is lower than the heat capacity of water. Water requires more energy per gram of liquid to change its temperature.

when I search I found this answer I hope it can help you answer your question.

As the fish goes deeper, the volume of air in the swim bladder increases.

Buoyant force is calculated using the following formula;

F = ρVg

where;

The volume of the fluid displaced is calculated as follows;

V = Ah

where;

Thus, we can conclude that as the fish goes deeper, the volume of air in the swim bladder increases.

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Answer:

L = 239.2 J.s

Explanation:

The angular momentum of the rod is given by the following formula:

L = mvr

where,

L = Angular Momentum = ?

m = mass = 13.1 kg

r = radius of circle of rotation = length of rod = 2.15 m

v = linear speed of rod = r(angular speed of rod) = (2.15 m)(3.95 rad/s)

v = 8.5 m/s

Therefore,

L = (13.1 kg)(8.5 m/s)(2.15 m)

L = 239.2 J.s

The angular momentum of the thin rod will be L = 239.2 J.s

Whenever any object has rotational motion then its angular momentum will be the product of the linear velocity of the object and the radius of the circle of rotation of the object.

The angular momentum of the rod is given by the following formula:

\(L= MVr\)

where,

L = Angular Momentum = ?

m = mass = 13.1 kg

r = radius of circle of rotation = length of rod = 2.15 m

w=3.95 rad/s

Now the angular momentum will be calculated as:

\(L= MVr\)

The linear velocity will be

\(V=wr=3.95\times 2.15=8.5\ \frac{m}{s}\)

Now put the value in the formula we get:

\(L=13.1\times 8.5\times 2.15=239.2\ J\)

\(L=239.2\ J\)

Hence the angular momentum of the thin rod will be L = 239.2 J.s

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Answer:    

2 : A large storm

Explanation: I hope this helps

Answer:

A.Radio waves

Explanation:

The magnitude of the displacement of the vector A is determined as 6.2 units.

The magnitude of the displacement of the vector is calculated as follows;

| A | = √[ (x₂ - x₁ )²  +  (y₂ - y₁ )² +  (z₂ - z₁ )²]

where;

The magnitude of vector A is calculated as;

| A | = √[ (2 - 0 )²  +  (3 - 0 )² +  (5 - 0 )²]

| A | = √ (4 + 9 + 25)

| A | = √ ( 38)

| A | = 6.2 units

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The complete question is below;

If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2). find the magnitude of the displacement of vector A.

The  magnitude of the total displacement of her trip is 2.2 miles.

The magnitude of the total displacement of her trip is calculated as follows;

Total east journey = 0.8 mi + 1.2 mi = 2 mi

Resultant displacement = √(y² + x²)

Resultant displacement = √(0.9² + 2²)

Resultant displacement = 2.2 mi

Thus, the  magnitude of the total displacement of her trip is 2.2 miles.

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Answer:

I think it's A

Explanation:

he shouldn't have changed the amount of sugar, because the whole point is to see which temperature dissolves sugar more quickly.

I'll assume you mean the hill is 150 m along its slope, since that's the direction the ball rolls.

The distance x it rolls after time t is

x = (2.5 m/s) t + 1/2 (6.3 m/s²) t²

Set x = 150 m and solve for t :

150 m = (2.5 m/s) t + 1/2 (6.3 m/s²) t²

(3.15 m/s²) t² + (2.5 m/s) t - 150 m = 0

t = 1/2 [(-2.5 m/s) + √((2.5 m/s)² - 4 * (3.15 m/s²) * (-150 m))]

(Use the quadratic formula, and take the positive root)

t ≈ 6.52 s

Okay, let's convert all the lengths to the same unit to compare:

(a) 100 m = 100 meters

(b) 104 μm = 104 micrometers = 104 × 10^-6 meters = 0.000104 meters

(c) 107 nm = 107 nanometers = 107 × 10^-9 meters = 0.000000000997 meters

(d) 102 mm = 102 millimeters = 102 × 10^-3 meters = 0.0102 meters

The longest length is:

(a) 100 m = 100 meters

The answer is option (a).

Answer: 100 m

Explanation:

1 μm = \(10^{-6}\) m = 0,000001 m

1 nm = \(10^{-9}\) m = 0,000000001 m

1 mm = \(10^{-3}\) m = 0,001 m

∴ 100 m es la mayor longitud

The magnitude of the electrical field would be 1.5x10^3 N/C.

The electrostatic force experienced by a charged particle in an electric field is given by the formula:

F = qE

Where F is the electrostatic force, q is the charge of the particle, and E is the electric field strength.

In this case, the electrostatic force acting on the particle is 3.0x10^-6 N and the charge of the particle is -2.0x10^-9 C. So we have:

3.0x10^-6 N = (-2.0x10^-9 C)E

Solving for E, we get:

E = (3.0x10^-6 N) / (-2.0x10^-9 C)

E = -1.5x10^3 N/C

Since the electric field is a vector quantity, its magnitude is always positive. Therefore, the magnitude of the electric field in this case is:

|E| = 1.5x10^3 N/C

So the magnitude of the electric field is 1.5x10^3 N/C, directed downward.

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Answer:

Vx = 35.31 [km/h]

Vy = 18.77 [km/h]

Explanation:

In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.

\(v_{x} = 40*cos(28)\\V_{x} = 35.31 [km/h]\)

In order to find the vertical component, we must use the sine function of the angle.

\(V_{y}=40*sin(28)\\V_{y} = 18.77 [km/h]\)

Overall probability of this particular event happening are 2/5 and 1/4, respectively. You get 2/20 when you add them all together. Justify with 1/10.

The justification for probability serves as the basic foundation for density of a reference substance. For instance, this same theoretically chance of receiving a head while tossing a coin is 12.

The possibility is typically defined as the proportion of positive outcomes to all alternatives in the sample space. Probability and plausibility, as well as its homophones in these other language skills, are words that have their roots in medieval knowledge and Cicero. They are typically used to denote opinions that are plausible or widely accepted.

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The bullet stops moving on hitting on a surface. Hence, the impulse here is equal to the momentum. Therefore, the mass of the bullet is 0.1 Kg.

Impulse in physics is the change in momentum. It is the product of the force and change in time.

hence, impulse = f. dt

When the bullet is travelling with  a velocity of 500 m/s it has a momentum. When it brought to rest, momentum become zero. Thus, the momentum is equal to the impulse here.

Therefore, f.dt = m. v

f.dt = 50 N s

v = 500 m/s

m = 50 N s/500 m/s = 0.1 Kg

Therefore, the mass of the bullet is 0.1 Kg.

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(a) The amplitude of the wave is determined as 8 cm.

(b) The period of the wave motion is  20 s and the frequency of the wave is 0.05 Hz

(c) The wavelength of the wave is 500 cm.

(a) The amplitude of the wave is the maximum displacement of the wave.

from the graph, amplitude of the wave = 8 cm

(b) The period of the wave motion is calculated as;

T = 20 s

The frequency of the wave = 1/T = 1/20 s = 0.05 Hz

(c) The wavelength of the wave is calculated by applying the following wave formula.

λ = v / f

λ = 25 cm/s / 0.05 Hz

λ = 500 cm

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:The sun provides the light to see the moon, while the earth casts a shadow on the moon but on full moons there is no shadow from the earth on the moon, and the moon is the thing affected by all of this

Explanation:

umm actually is 10 points

Magnetism is the result of the "spin" of the electron and most of these cancel each other out in larger bodies thus most things not being magnetic.

Answer:

b) 0.48m is the right answer.

Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Answer:

proportional tax is.the answer.

Explanation:

because both girls tax is equal.

Answer:

84.1 m

Explanation:

Given :

The distance from the ship to submarine :

20 + y

Using Pythagoras :

Tan θ = opposite / Adjacent

Tan θ = 20 / 12

12 tan θ = 20

θ = tan^-1(20/12)

20

θ = 59.036°

The angle phi;

n1sinθ1 = n2sin θ

Sin 59.036 = 1.33 * sin phi

Sin phi = sinsin(59.04) ÷1.33

0.8574907 = 1.33 * sin phi

Sin phi = 0.8574907 / 1.33

Sin phi = 0.6447298

phi = sin(0.6447298

Phi = 40.15°

From Pythagoras :

y = 76tan40.15°

y = 76 * 0.8435707

y = 64.11

20 + y

20 + 64.11 = 84.11

Answer:

The final speed of electron=\(5.93\times 10^6m/s\)

Explanation:

We are given that

Initial velocity, u=0

Potential, V=100 V

We have to find the final speed.

Mass of electron, \(m=9.1\times 10^{-31} kg\)

Charge on electron, q=\(1.6\times 10^{-19}C\)

We know that

\(qV=\frac{1}{2}mv^2-\frac{1}{2}mu^2\)

Using the formula

\(1.6\times 10^{-19}\times 100=\frac{1}{2}\times 9.1\times 10^{-31} v^2-0\)

\(v^2=\frac{2\times 1.6\times 10^{-19}\times 100}{9.1\times 10^{-31}}\)

\(v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 100}{9.1\times 10^{-31}}}\)

\(v=5.93\times 10^6m/s\)

Hence, the final speed of electron=\(5.93\times 10^6m/s\)

Answer: 1.348 meters

Explanation: Although the sign is missing from the location of the 4.00 kg object, it is assumed to be positive. The net moment of all the objects about the center of mass must be zero. Let the center of mass be on the y axis at a point  c . Adding the four moments together, we get:

(2.00)(3.00−c)+(3.00)(2.50−c)+(2.50)(0−c)+(4.00)(0.500−c)=0

6.00−2.00c+7.50−3.00c+0−2.50c+2.00−4.00c=0

11.5c=15.50

c=  1.348 metres

The center of mass is on the y axis at  y  = 1.348 metres.

The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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