The map below shows major ocean currents in the North Atlantic and North Pacific Oceans. In general, currents flowing toward the
Equator bring cooler waters to some regions, while currents flowing away from the Equator bring warmer waters to other regions.
North
British
Isles
Askan
North Atlantic
Azor
U.S.A
California
Gulf Stream
Loop
n
Canbean
North Equatorial
North Equatorial CC
North Fuatorial
Equator
South Equatorial
Not
South Equatorial
Image courtesy of NOAA
Judging from the map, which region probably has cooler summers than it would without the effect of a nearby ocean current?
A the Central U.S.
B. the British Isles
C. the U.S. East Coast
D. the US West Coast

The Map Below Shows Major Ocean Currents In The North Atlantic And North Pacific Oceans. In General,

Answers

Answer 1

Answer:

d

Explanation:

Answer 2

the US West Coast region probably has cooler summers than it would without the effect of a nearby ocean current.

what is ocean current ?

ocean current can be defined as the horizontal movement of seawater which is produced by gravity, wind, and water density, it play an major role in the determination of climates of coastal regions.

The movement of ocean water is continuous which can be up three types such as Waves, Tides, Currents

The streams of water which flow continuously on the ocean surface in specific directions are called ocean currents, it affect the temperature of ocean water as Warm ocean currents increase the temperature whereas Cold ocean currents decrease the temperature.

The magnitude of the ocean currents is about  few centimeters per second to as much as 4 metres per second and the intensity of the ocean currents generally decreases with increasing depth.

There are two types of ocean currents such as Warm Ocean Currents

and Cold Ocean Currents

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Related Questions

During a high Reynolds number experiment, the total drag force acting on a spherical body of diameter D = 12 cm subjected to airflow at 1 atm and 5°C is measured to be 5.2 N. The pressure drag acting on the body is calculated by integrating the pressure distribution (measured by the use of pressure sensors throughout the surface) to be 4.9 N. Determine the friction drag coefficient of the sphere, and whether the flow is in turbulence.

Answers

The total drag force acting on a sphere with a diameter of 12 cm and exposed to airflow at 1 atm and 5°C is therefore measured to be 5.2 N. Therefore, the friction drag coefficient is 0.0115.

When determining whether a flow pattern is laminar or turbulent while passing through a pipe, Reynolds number, a dimensionless quantity, is used. The relationship between inertial and viscous forces is what determines the Reynolds number. Friction is caused by surface irregularity, according to observations made at the microscopic level. Variety of Friction Friction can be divided into two categories, which are as follows: internal rubbing

Cdf = 0.2*0.3/5.2

Cdf = 0.06/5.2

Cdf = 0.0115

when 5.2/0.3 = 0.2

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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.​

Answers

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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A Ferris wheel rotates three times each minute. It carries each car around a circle with the diameter of 19.0m. What force, magnitude (in N) and direction (in degrees), does the seat exert on a 35.0-kg child when the rider is halfway between the top and the bottom?

Answers

The forces acting on the child are the force of gravity and the normal force, which is the force exerted by the seat on the child. the force exerted by the seat on the child has a magnitude is Fn = 342.5N. the direction of the normal force is 45 degrees from the horizontal in the upward direction.

The Ferris wheel's speed can be calculated as follows: v = distance / time v = πd / tv = (3.14 * 19.0 m) / 1 min v = 60.66 m/min

The acceleration of the Ferris wheel can be calculated as follows: a = (v²) / ra = (60.66 m/min)² / (19.0 m / 2)a = 194.6 m/min²

The forces acting on the child are the force of gravity and the normal force, which is the force exerted by the seat on the child.

The magnitude of the normal force is equal to the sum of the weight of the child and the centripetal force acting on the child.

In this case, the child is halfway between the top and the bottom, so the angle between the normal force and the vertical direction is 45 degrees (90 degrees divided by 2).

As a result, the force exerted by the seat on the child has a magnitude of:

Fn = Fg + Fcf = maFn = (35.0 kg) * (9.8 m/s²) + (35.0 kg) * (194.6 m/min²)Fn = 342.5 N

The direction of the normal force is perpendicular to the seat, which is horizontal.

Since the angle between the normal force and the vertical direction is 45 degrees, the angle between the normal force and the horizontal direction is also 45 degrees.

Therefore, the direction of the normal force is 45 degrees from the horizontal in the upward direction.

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HELP: I’ve been stuck on this problem for a while now.

HELP: Ive been stuck on this problem for a while now.

Answers

Answer:

a.work done=force *displacement

=500N*46m

=23000 Joule

b.power=work done/time taken

=23000/25

=920 watt

c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)

=60kg*9.8m/s*14m

=8232 joule

Explanation:

How is biochar produced?

Answers

Answer:

Biochar is produced by heating biomass in the total or partial absence of oxygen. Pyrolysis is the most common technology employed to produce biochar, and also occurs in the early stages of the combustion and gasification processes. Besides biochar, bio-oil and gas can be collected from modern pyrolysers.

A billiard ball of mass 0.500 kg moves at a velocity of 2.20m/s [fwd] when it collides elastically with asecond ball, of mass 0.350 kg. The second ball is initially moving at 1.50m/s [fwd]. Determine theobtained velocity of both balls after the collision.

Answers

Given:

The mass of the 1st ball, m₁=0.500 kg

The velocity of the 1st ball before the collision, u₁=2.20 m/s

The mass of the 2nd ball, m₂=0.350 kg

The speed of the second ball before the collision, u₂=1.50 m/a

To find:

The velocities of the balls after the collision.

Explanation:

In an elastic collision, both momentum and the kinetic energies of the balls are conserved.

The velocities of the balls after the collision are given by,

\(\begin{gathered} v_1=\frac{m_1-m_2}{m_1+m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\text{ }\to\text{ \lparen i\rparen} \\ v_2=\frac{2m_1}{m_1+m_2}u_1+\frac{m_2-m_1}{m_1+m_2}u_2\text{ }\to\text{ \lparen ii\rparen} \end{gathered}\)

Where v₁ is the velocity of the 1st ball and v₂ is the velocity of the 2nd ball.

On substituting the known values in equation (i),

\(\begin{gathered} v_1=\frac{0.500-0.350}{0.500+0.350}\times2.20+\frac{2\times0.350}{0.500+0.350}\times1.50 \\ =1.62\text{ m/s} \end{gathered}\)

On substituting the known values in the equation (ii),

\(\begin{gathered} v_1=\frac{2\times0.500}{0.500+0.350}\times2.20+\frac{0.350-0.500}{0.500+0.350}\times1.50 \\ =2.32\text{ m/s} \end{gathered}\)

Final answer:

The velocity of the 1st ball is 1.62 m/s after the collision.

The velocity of the 2nd ball after the collision is 2.32 m/s.

A box slides on a level floor. It is slowing with a constant
acceleration of magnitude 2.0 m/s2
. What is the coefficient of
kinetic friction between the box and the floor?

Answers

Answer:

Explanation:

We can use the following equations of motion to solve the problem:

v^2 = u^2 + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration, s is the distance travelled.

In this case, the box is slowing down, so the initial velocity u is greater than the final velocity v. We can use a negative sign to indicate that the acceleration is opposite to the initial velocity.

Let us assume that the mass of the box is m and the coefficient of kinetic friction is μ. The force of friction acting on the box is given by f = μmg, where g is the acceleration due to gravity.

Since the acceleration of the box is 2.0 m/s^2, we have

f = ma

μmg = m(-2.0)

μg = -2.0

μ = -2.0/g

Substituting g = 9.8 m/s^2, we get

μ = -0.204

Since the coefficient of friction cannot be negative, we take the absolute value and obtain:

μ = 0.204

Therefore, the coefficient of kinetic friction between the box and the floor is approximately 0.204.

A block of wood 3 cm on each
side has a mass of 27 g. What is the
density of the block? (Hint, don't
forget to find the volume of the
wood first using lx W h.)

Answers

Answer:

1g/cm3

Explanation:

volume of block is 3 cubed which is 27 cm3

we know density is m/v so d= 27g/27cm3

which is 1g/cm3

if my answer helps please mark as brainliest

Based on the naming rules for ions, which of the following is a negatively charged ion (not a polyatomic ion)?

chloride

chlorite

chlorine

chlorate

Answers

probably chlorate is the correct answer

IONS QUICK CHECK:

1. Based on the naming rules for ions, which of the following is a negatively charged ion (not a polyatomic ion)?

A. Chloride

2. When moving across a period from left to right in the periodic table, excluding transition elements, which trend occurs?

D. Valence electrons increase by one

3. Which information about an atom can a period number give you?

D. How many energy levels it has

4. Fluorine has 7 valence electrons. Which charge is its ion likely to have?|

D. 1-

5. Which two elements in the list would bond together based on their ionic charges?

A. Potassium and iodine

A wave takes 0.5 seconds to complete one cycle. Which characteristic of the wave does this description represent? A. period B. wavelength C. amplitude D. frequency​

Answers

Answer:

period

Explanation:

A wave takes 0.5 seconds to complete one cycle. It is called the time period of the wave. It is the time taken by the wave to complete one cycle.

The relation between the time period and the frequency is given by :

T = 1/f

Where

f is frequency of the wave

Hence, the correct option is (a) "period".

You hit a hockey puck and it slides across the ice at nearly a constant speed.Is a force keeping it in motion?Explain.

Answers

Answer:

Explanation:

When the puck is sliding on the ice, there is no force being exerted on the puck to keep it moving forward. Instead, inertia keeps the puck moving forward. Friction between the puck and the ice gradually slows the puck down. You hit a hockey puck and it slides across the ice at nearly a constant speed

At constant speed and varying position of the hockey puck, implies a change in the velocity of the hockey puck and net force is acting on it to keep it in motion.

According to Newton's second law of motion, the force applied to a an object is directly proportional to the product of mass and acceleration of the object.

F = ma

Acceleration is the change in the velocity of an object per change in time of motion.

At constant velocity, the acceleration of an object is zero.When acceleration of an object is zero, the force on the object is zero.A constant speed (magnitude only) and change in the direction of the object, implies a change in velocity of the object.at changing velocity, the acceleration on an object is positive, and hence net force acts on the object.

Thus, we can conclude that at constant speed and varying position of the hockey puck, implies a change in the velocity of the hockey puck and net force is acting on it to keep it in motion.

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A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C. At what temperature would the sphere begin to float in glycerine

Answers

A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C.

To determine the temperature at which the hollow glass sphere begins to float in glycerine, we need to calculate the density of glycerine at various temperatures and compare it to the density of the glass sphere.

The density of glycerine changes with temperature, so we need to use a density-temperature chart or equation to determine the density of glycerine at different temperatures.

Assuming the hollow glass sphere has a uniform wall thickness, we can calculate its volume by subtracting the volume of the hollow interior from the volume of the whole sphere

Volume of sphere = (4/3)π\(r^{3}\)

Volume of hollow interior = (4/3)π\((r-t)^{3}\)

Volume of glass wall = (4/3)π(\(r^{3}\) - \((r-t)^{3}\)), where t is the thickness of the glass wall.

From the density and volume of the glass sphere, we can determine its mass

Mass of glass sphere = Density of glass sphere x Volume of glass sphere

Next, we can use Archimedes' principle to determine the volume of glycerine displaced by the glass sphere when it is submerged in the glycerine

Volume of glycerine displaced = Mass of glass sphere / Density of glycerine at the given temperature

When the glass sphere floats, the volume of glycerine displaced will be equal to the volume of the glass sphere. Thus, we can set the two volumes equal to each other and solve for the temperature at which the density of glycerine matches the density of the glass sphere

Volume of glass sphere = Volume of glycerine displaced

(4/3)π\(r^{3}\) - (4/3)π\((r-t)^{3}\) = Mass of glass sphere / Density of glycerine at the given temperature

Hence, for the temperature requires knowing the radius and thickness of the glass sphere and the mass of the sphere.

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An airbys A380 airliner lands at 30 m/s. Partially loaded, its mass is 480000 kg. The engines apply reverse thrust for 12s to slow the plane to 25 m/s.How much thrust did the engines apply?

Answers

To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

A 0,9 -kg object attached to the end of a string swings in a vertical circle (radius = 75 cm). At the top of the circle the speed of the object is 6,5 m/s. What is the magnitude of the tension in the string at this position?

Answers

0.6 cm is the answer add it up and find the m/s hope this helps

A patient prescribed a metered dose inhaler will find it
A. works for lower (not upper) respiratory diseases only.
B. should be filled with medication in aerosol form only.
C. is filled with medication used to administer a fixed amount of medication per inhalation through the mouth.
D. should be filled with medication in powder form only.

Answers

Answer:The correct answer should be C. is filled with medication used to administer a fixed amount of medication per inhalation through the mouth.

Explanation:

Answer:

c. is filled with medication used to administer a fixed amount of medication per inhalation through the mouth.

Which of the following is an assumption rather than a prediction of Einstein's special theory of relativity?
A) length contraction B) time dilation C) No material object can reach or exceed the speed of light. D) the constancy of the speed of light E) the equivalence of mass and energy
the constancy of the speed of light

Answers

No material object can reach or exceed the speed of light is the assumption.

The Principle of Relativity : The states of changed physical systems are not affected, whether these changes of state be referred to the one or the other of two systems in uniform translatory motion relative to each otherThe Principle of Invariant Light Speed : Light is always propagated in empty space with a definite velocity c which is independent of the state of motion of the emitting body.In relative theory, reference frames play a vital role. It is used to measure a time of events by using a clock.An event is nothing but an occurrence that refers to a location in space corresponding to the reference frame. For instance, the explosion of a fire flower can be considered as an event.

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The Jamaican Bobsled Team is sliding down a hill in a toboggan at a rate of 5 m/s when he reaches an even steeper slope. If he accelerates at 2 m/s2 for the 5 m slope, how fast is he traveling when he reaches the bottom of the 5 m slope?

Answers

Answer:

6.71 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 5 m/s

Acceleration (a) = 2 m/s²

Distance (s) = 5 m

Final velocity (v) =.?

The final velocity at the bottom of the slope can be obtained as shown below:

v² = u² + 2as

v² = 5² + (2 × 2 ×5)

v² = 25 + 20

v² = 45

Take the square root of both side

v = √45

v = 6.71 m/s

Thus, the velocity of the Jamaican Bobsled Team when he reached the bottom of the slope is 6.71 m/s

A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertically up from the ground with an initial velocity of 0=40.0 m/s . At what height from the ground will the two objects first meet?

A small object begins a free-fall from a height of =81.5 m at 0=0 s . After =2.20 s , a second small

Answers

Answer:

33.2 m

Explanation:

For the first object:

y₀ = 81.5 m

v₀ = 0 m/s

a = -9.8 m/s²

t₀ = 0 s

y = y₀ + v₀ t + ½ at²

y = 81.5 − 4.9t²

For the second object:

y₀ = 0 m

v₀ = 40.0 m/s

a = -9.8 m/s²

t₀ = 2.20 s

y = y₀ + v₀ t + ½ at²

y = 40(t−2.2) − 4.9(t−2.2)²

When they meet:

81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²

81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)

81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716

81.5 = 61.56t − 111.716

193.216 = 61.56t

t = 3.139

The position at that time is:

y = 81.5 − 4.9(3.139)²

y = 33.2

A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.
a. How much work does he do on the wall? ____________
b. How much energy is used?__________
c. How much power is exerted?____________

Answers

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

What is force?

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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2. An object’s velocity is measured to be v (t) = αt−βt2, where α = 4.00 m/s2 and β = 2.00 m/s3. Calculate the average acceleration of the object from t = 0.0 s to t = 3.0 s

Answers

Hi there!

Given the values for α and β, we can plug these into the given equation:

\(v(t) = 4t - 2t^2\)

Begin by solving for the velocity at t = 0 and t = 3:

At t = 0:
\(v(0) = 4(0) - 2(0^2) = 0 \frac{m}{s}\)

At t = 3:
\(v(3) = 4(3) - 2(3^2) = 12 - 18 = -6 \frac{m}{s}\)

Acceleration is the SLOPE of the velocity graph (its derivative), so we can use the kinematic equation:

\(a = \frac{v_f - v_i}{\Delta t}\)

Plug in the knowns:

\(a = \frac{-6-0}{3 - 0} = \boxed{-2 \frac{m}{s^2}}\)

The decibel rules of thumb can be combined. (a) If a sound has intensity xdB, how many dB does a sound 100 times more intense have? (b) If another sound has intensity ydB, how many dB does a sound 4 times less intense have? (c) Combine what you know about (a) and (b): If a sound has intensity zdB, how many dB does a sound 25 times more intense have?

Answers

C i think hope this help

A boat travels 28 m while it reduces its velocity from 27.5 m/s to 14.5m/s. What is the boat’s acceleration while it travels that distance?

Answers

Answer:

9.75 m/s²

Explanation:

Given that,

v= 14.5 m/s

u = 27.5 m/s

s = 28 m

a = ?

v² = u² -2as [ minus sign due to deceleration]

14.5² = 27.5² - 2 × a × 28

210.25 - 756.25 = -56a

-56a = -546

a = 9.75 m/s²

La figuna 25 muestra las estructuras anatomicas de la pierna y el pie que intervienen cuando se levanta del suelo e talón de modo que a pie haga en efecto contacto con el suelo en un solo punto, mostrado como P an la figura Calcule las fuerzas que debenejercerce sobre el pie por el músculo de la pantorrilla y por los huesos de la pierna cuando una persona de 65kg se para de puntillas sobre un pie. Compare estas fuerzas con el peso de la persona Suponga que a=5.Ocm y b=15 cm

La figuna 25 muestra las estructuras anatomicas de la pierna y el pie que intervienen cuando se levanta

Answers

Answer:

Explanation:

T =  fuerza que debenejercerce sobre el pie por el músculo de la pantorrilla

F =  fuerza que debenejercerce sobre por los huesos de la pierna

ΣFy = 0

P - mg = 0

P = mg = 65(9.8) = 637 N

                  ΣM_T = 0

637(5 + 15) - F(15) = 0

                          F = 849.333333...

                          F = 850 N↓

           ΣM_F = 0

T(5) - 637(15) = 0

                  T = 1,911

                   T = 1900 N↑

a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its side at frequency f the maximum induced emf is

Answers

When a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its sides at frequency f the maximum induced emf is  2πBAf

What is a magnetic field?

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

The maximum induced emf is 2πBAf when a rectangular wire loop of area A is spun around one of its sides at frequency f, perpendicular to a uniform magnetic field B.

therefore the correct answer is option C

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Your question seems incomplete, the complete question is as follows

A rectangular loop of wire has area A. It is placed perpendicular to a uniform magnetic field B and then spun around one of its sides at frequency f. The maximum induced emf is:

A. BAf

B. 4πBAf

C. 2πBAf

D. 2BAf

A bicycle slows down uniformly from vi=8.40 [m/s] to rest over a distance of 115 [m]. Each wheel and tire has an overall diameter of 0.68 [m]. Determine the magnitude of the angular acceleration of the wheel. Give your answer in units of radians per second squared.

Answers

A bicycle slows down uniformly from vi=8.40 [m/s] to rest over a distance of 115 [m]. Each wheel and tire has an overall diameter of 0.68 [m]. The magnitude of the angular acceleration of the wheel is approximately 0.0757 rad/s².

To determine the magnitude of the angular acceleration of the wheel, we need to first calculate the change in angular velocity and the time taken to come to rest. Then we can use these values to find the angular acceleration.

Calculate the initial angular velocity:

The initial linear velocity of the bicycle wheel is given by the formula v = ω * r, where v is the linear velocity, ω is the angular velocity, and r is the radius of the wheel.

The radius of the wheel is half the diameter, so r = 0.68 m / 2 = 0.34 m.

Given the initial linear velocity vi = 8.40 m/s, we can calculate the initial angular velocity ωi:

vi = ωi * r

ωi = vi / r

Calculate the final angular velocity:

The final angular velocity of the wheel is 0 rad/s since it comes to rest.

ωf = 0 rad/s

Calculate the change in angular velocity:

The change in angular velocity (Δω) is given by the formula Δω = ωf - ωi.

Δω = 0 - ωi

Calculate the time taken to come to rest:

To calculate the time taken to come to rest, we can use the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given the initial velocity vi = 8.40 m/s, final velocity vf = 0 m/s, and distance d = 115 m, we can calculate the acceleration a:

vf = vi + at

0 = 8.40 + a * t

We also know that the distance traveled d is related to the initial and final velocities and the time by the formula d = (vi + vf) / 2 * t:

d = (vi + vf) / 2 * t

115 = (8.40 + 0) / 2 * t

From the two equations above, we can solve for the acceleration a and the time t.

Calculate the angular acceleration:

The angular acceleration (α) is given by the formula α = Δω / t.

α = Δω / t

Substitute the values for Δω and t and calculate the angular acceleration.

Therefore, the magnitude of the angular acceleration of the wheel is approximately 0.0757 rad/s².

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To win the game, a place kicker must kick a football from 30m from the goal, and the ball must clear the crossbar which is 3.05 m high. When kicked, the ball leaves the ground with the speed of 19 m/s at the angle of 37.2° from the horizontal. Acceleration of gravity is 9.8 m/s^2
How much vertical distance does the ball clear the crossbar?

Answers

Answer:

Explanation:

Ignore air resistance

The horizontal velocity is

vx =19cos37.2 = 15.134 m/s

The ball travels 30 m in a time of

30 / 15.134 = 1.982 s

In that time, the ball will be at an altitude of

s = vy₀t + ½at²

s = 19sin37.2(1.982) + ½(-9.8)1.982² = 3.5137... m

so the ball clears the bar by

h = 3.5137 - 3.05 = 0.4637... = 0.46 m

For an experiment to produce useful data, what must happen?

A. It must be performed by a famous scientist.

B. It must prove a hypothesis correct.

C. It must be published in a famous journal.

D. It must be repeated several times.

Answers

Answer: D

Explanation: It must be repeated several times. (You could have different results everytime. Kind of like a dice. If you only roll it once and get a 3, you will only think it rolls a 3 unless you roll it and get different results or unless you've seen a dice before.)

Determine the velocity (in m/s) of the object during the last six seconds. Include a numerical answer accurate to the second decimal place. If negative, include the - sign

Determine the velocity (in m/s) of the object during the last six seconds. Include a numerical answer

Answers

Answer:

0.33 m/s

Explanation:

The graph given is that of distance against time. The slope of such a graph gives the velocity of the object while travelling.

In this graph the change in distance for the last 6 seconds is given by;

The distance is : 10-8 = 2 m

The time in seconds is: 6 s

The velocity =  2/6 = 1/3 m/s

The velocity expressed in decimal form is : 0.33 m/s

We have 3 gears meshed with the following teeth. A – 20; B – 50; C – 30. Another set of gears have the following teeth. X – 20; Y – 25; Z – 30. Assuming gears A and X are running at the same rpm. Which statement is correct?

Answers

gear C and Z will run at the same RPM

RPM is not a unit, according to the International System of Units (SI). The word "revolution" is a semantic annotation rather than a unit, which explains this. RPM formula sign must be f for (rotational) frequency and or for angular velocity due to the measured physical quantity. s−1  or Hz is the basic SI-derived unit that corresponds. The radians per the second unit are used to express angular speed.

As a result, a disc rotating at 60 RPM  is considered to be rotating at either 2 rad/s or 1 Hz, where the former refers to angular velocity and the latter to the rate of revolutions per second.

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We have 3 gears meshed with the following teeth. A 20; B 50; C 30. Another set of gears have the following

Which game most represents a wave?

hide and seek
tic-tac-toe
poker
tipping over dominos

Answers

Answer:

Tipping over dominos

Explanation:

Because when tipping the dominos it carrys energy from one place to the other and it is a good repersenteive of a wave

We can compare tipping over dominos to wave because both involves the transfer of energy.

What is a wave?

A wave is a disturbance that transfers energy from one point to another without any permanent displacement of the particles of the medium.

What is tipping over dominos?

Tipping over dominos is delivery service that involves movement of energy from one place to another just like wave.

Thus, we can compare tipping over dominos to wave because both involves the transfer of energy.

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