The loaded car of a roller coaster has mass M = 320 kg. It goes over the highest hill with a speed v of 21.4 m/s. The radius of curvature R of the hill is [01] m. (a) What is the force (N) that the track must exert on the car? (positive is up) (b) What must be the force (N) that the car exerts on a 61 kg passenger?

(D) virtual and larger than the object.

Concave mirror is spherical mirror which has its reflecting surface bulging inwards

. The focal length of a mirror is the distance between the pole of the mirror and a point where all the reflected rays merge,The focal point and the centre of curvature of the concave mirror lie in front of the mirror

so,if an object is located between the focal point and a concave mirror we can use the ray diagram to check this,

.

, the image produced will be virtual , and longer than the object

so, the answer is

(D) virtual and larger than the object.

I hope this helps you

''The ability to use an applied force in order to make an object move'' is the  scientific definition of energy that relates it to work.

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less competition for pollinators with other species  

 Explanation: just took this test and got a 100

Answer:

less competition with other species

Explanation:

just took the test

The dependent, independent, and controlled variables​ are as follows:

1. Dependent - The effect of lime urea table salt and compost on the soil

2. Independent - The soil on which the elements are incorporated.

3. Controlled variable - The height of the plants.

The dependent variable is that which is tested in the experiment and in this experiment, Chandani is testing the effect of lime, urea, table salt, and compost on the soil.

The independent variable is the altered element in the experiment and for this experiment, this is the soil that receives different additives. Finally, the controlled variable is that which remains constant and that is the height of each plant that the researcher checks.

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There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

The density of a binary alloy can be calculated using the following equation:

ρ = w1ρ1 + w2ρ2

where,

ρ = density of the alloy

w1 and w2 = weight fractions of the two components (in this case, gold and silver)

ρ1 and ρ2 = densities of the pure components.

We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:

\(w_{Au}\) = 0.10

\(w_{Ag}\) = 0.90

We are also given the densities of pure gold and silver as:

ρ_Au = 19.32 g/\(cm^{3}\)

ρ_Ag = 10.49 g/\(cm^{3}\)

Now we can substitute these values into the density equation to find the density of the alloy:

ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag

ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))

ρ = 11.08 g/\(cm^{3}\)

Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.

To do this, we can use Avogadro's number and the atomic weights of gold and silver:

\(N_A\) = 6.022 × \(10^{23}\) atoms/mol

Aum = 196.97 g/mol

Agm = 107.87 g/mol

The number of gold atoms:

\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)

Substituting the values, we get:

\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol

\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)

Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

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None of the statements are true of all proteins. Here is a correct statement about proteins:

Proteins are large, complex molecules that perform a wide variety of functions in the body, such as catalyzing metabolic reactions, replicating DNA, responding to stimuli, and transporting molecules from one location to another. They are made up of chains of amino acids, which are linked together in a specific sequence determined by the genetic code. Protein structure and function is highly dependent on the specific sequence of amino acids in the protein, and proteins can take on a wide variety of shapes and sizes, ranging from small, globular proteins to large, fibrous proteins.

The magnitude of horizontal force, is 33.27 N.

Length of the uniform bar, L = 24 m

Mass of the uniform bar, m = 5 kg

Angle between the cord and the bar, θ₁ = 90°

Angle between the cord and the wall, θ₂ = 50°

For the horizontal equilibrium,

Hₓ = T sinθ₂

Hₓ = T x sin 50

Hₓ = 0.766 T

For the vertical equilibrium,

Hy + T cosθ₂ = mg

Hy + T cos 50 = 5 x 9.8

Hy + 0.642 T = 49 N

For rotational equilibrium,

mg (L/2) = T x L

So,

T = mg/2 = 5 x 9.8/2

T = 24.5 N

Therefore, the magnitude of horizontal force,

Hy = 49 - (0.642 x 24.5)

Hy = 49 - 15.73

Hy = 33.27 N

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Answer:

A:  magnitude and direction

B: Force that the field exerts on a test charge

C: its magnitude and direction is the same.

D: electrostatic machine

two rollers that are driven by a motor that generates a rotation

Explanation:

There are certainly significant challenges facing the US political system, and there is a need for reforms that can improve the functioning of government and promote public welfare. However, there is also an ongoing debate about the nature of these challenges and the best path forward to address them.

Critics of the US political system argue that several institutional failures have hindered the government's ability to address major public policy challenges. For example, some say that the US Congress has become increasingly dysfunctional. In contrast, others point to the role of money in politics, with the influence of wealthy donors and special interest groups limiting the ability of elected officials to act in the public interest.

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Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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when water in a metal pot is heated over a campfire. Primarily, by means of convection energy transfer is thermal energy moved from the fire to the bottom of the pot

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

Thermal energy can flow by different means such as conduction, convection, and radiation.

As given in the problem when water in a metal pot is heated over a campfire. The energy we receive around the campfire is mostly due to the effect of the radiation of the heat but the Primary means of energy transfer is thermal energy moved from the fire to the bottom of the pot because of the convection.

Thus, when water is heated in a metal pot over a campfire. Thermal energy is primarily transferred from the fire to the bottom of the pot through convection.

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The banking angle is the angle that the surface makes with the horizontal, or the angle of inclination.

v = √rg tanθ

tanθ=v²/rg  

The relation gives the angle of banking of the cyclist going round the curve. Here v is the speed of the cyclist, r is the radius of the curve, and g is the acceleration due to gravity.

The banking angle is the angle that the surface makes with the horizontal, or the angle of inclination. The normal force acting on the car while travelling through such a curving road has a horizontal component. The centripetal force needed to prevent skidding is provided by this component.

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The pilot's total velocity is 116.3 knots in the direction of 62.3⁰.

The pilot's total velocity is calculated by applying the principle of relative velocity.

The total velocity is also the resultant velocity and the magnitude of the pilot's total velocity is calculated by applying Pythagoras theorem as follows;

R = √ (V₁² + V₂²)

R =  √ (54² + 103²)

R = 116.3 knots

The direction of the velocity vector is calculated as follows;

tan θ = (103 knots) / (54 knots)

θ = tan⁻¹ (103/54)

θ = 62.3⁰

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Calculate the horizontal component of the velocity. The horizontal component of the velocity is given by:

v_x = v * cos(theta)

where v is the original speed of the arrow and theta is the angle of projection.In this case, v = 2 m/s and theta is unknown. Solving for theta, we get:

theta = arccos(v_x / v)

theta = arccos(2 / 2) = 45 degrees

Calculate the vertical component of the velocity. The vertical component of the velocity is given by:

v_y = v * sin(theta)

In this case, v = 2 m/s and theta = 45 degrees. Solving for v_y, we get:

v_y = 2 * sin(45 degrees) = 1.414 m/s

Calculate the time of flight. The time of flight is given by:

t = 2 * v_y / g

In this case, v_y = 1.414 m/s and g = 10 m/s^2. Solving for t, we get:

t = 2 * 1.414 / 10 = 0.283 seconds

Calculate the height of the arrow. The height of the arrow is given by:

y = v_y * t - 0.5 * g * t^2

In this case, v_y = 1.414 m/s, t = 0.283 seconds, and g = 10 m/s^2. Solving for y, we get:

y = 1.414 * 0.283 - 0.5 * 10 * 0.283^2 = 0.303 meters

Therefore, the angle of projection is 45 degrees and the height of the arrow is 0.303 meters.

Answer:

The processes of photosynthesis and respiration are interrelated because the products of such processes are used as reactants for one process. One product of photosynthesis is oxygen. This oxygen is used in the process of respiration as a reactant producing carbon dioxide which is used as a reactant for photosynthesis.

The ocean water contains different types of ions.

The increase in the salt concentration results in the higher density of the ocean water. This salt concentration in the ocean is the result of different ions present in it.

The water is mostly present in the oceans and in some parts it is in the form of running water in the rivers. The oceans are salty due to the presence of the dissolved ions.

The salty nature of the oceans is also due to the ions carried by the rain water and other form of running water on the surface of the Earth. The amount of salt present in the ocean water in a particular region varies as compared to the other.

This variation in the concentration of the salt in the water leads to the variation in the density of the ocean water because if the concentration of the salt is low, then less amount salt is present in unit volume and therefore it has less density whereas if the concentration of the salt is more, it will lead to the higher density of the ocean water.

Therefore, the correct statement about ocean is that it contains different ions that are responsible for its salinity.

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The units of G must be C. m³ / ( kg s² )

What is Newton's gravitational law?

Every particle in the universe is pulled to every other particle with a force that is directly proportional to the product of their masses and inversely proportional to their separation from one another, according to Newton's Law of Universal Gravitation.

In the equation above, the constant proportionality is the universal gravitational constant (G). Henry Cavendish conducted an experiment to determine G's precise value. The equation for G is G = 6.673 x 10-11 N m2/kg2.

The Universal Gravitational Law may explain everything, from how an apple falls off a tree to why the moon revolves around the earth. To understand the beauty of the universal gravitational law, watch the video.

F = Gravitational Force ( Newton )

G = Gravitational Constant ( 6.67 × 10⁻¹¹ Nm² / kg² )

m = Object's Mass ( kg )

R = Distance Between Objects ( m )

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Answer:

The angular displacement of the blade is 576,871.2 radians

Explanation:

Given;

angular speed of the Helicopters rotor blades, ω = 510 rpm (revolution per minute)

time of motion, t = 3 hours

The angular speed of the Helicopters rotor blades in radian per second is given as;

\(\omega = \frac{510 \ rev}{mins} *\frac{2 \pi \ rad}{1 \ rev} *\frac{1 \ min}{60 \ s}\\\\\omega = 53.414 \ rad/s\)

The angular displacement in radian is given as;

θ = ωt

where;

t is time in seconds

θ = (53.414)(3 x 60 x 60)\\

θ = 576,871.2 radians

Therefore, the angular displacement of the blade is 576,871.2 radians

Answer:

An ohmic conductor is defined as one which obeys ohm's law that is V ∝ I where is the voltage and is the current. There must be a linear graph. Silver is an example of an ohmic conductor as the graph for silver is a linear graph. Silver and copper are some examples of ohmic conductor

The heaviest liquid is mercury. In order to equalize the air pressure, it only climbs 76 cm. Water will rise to a 13.6 because it is 13.6 times lighter than mercury. By a factor of 13.6, mercury is 13.6 times denser than water.

Therefore, the barometer's height would be 13.6 times higher if water were employed in place of mercury. Since water expands when it freezes, the glass tube would be broken.

Because of its high density, mercury is frequently employed in barometers, allowing for a column height that is appropriate for measuring atmospheric pressure. For example, a mercury barometer would need to be 13.6 times taller than a water barometer to measure the same change in pressure.

This is the primary justification for using mercury in thermometers. Mercury will provide accurate readings in comparison to water since it lacks the condensation property that water possesses. Mercury can be used to measure both negative and positive temperatures, whereas water cannot be used to measure either.

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1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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a. The position of the sandbag at a time 0.245 s after its release is 39.706 m from the ground.

b. The magnitude of the velocity of the sandbag at a time 0.245 s after its release is 2.4 m/s.

c. The direction of the velocity of the sandbag at a time 0.245 s after its release is to the ground.

d. The position of the sandbag at a time 1.15 s after its release is 33.52 m from the ground.

e. The magnitude of the velocity of the sandbag at a time 1.15 s after its release is 11.27 m/s.

f. The direction of the velocity of the sandbag at a time 1.15 s after its release is to the ground.

According to the free-fall motion, when an object is released without an initial velocity from a certain height the object will experience acceleration due to the gravitational force of the earth. The non-uniform motion formula

v = u + at

d = (u × t) + 0.5at²

The formula for free-fall motion become

v = u + at                  ⇒ v = gt

d = (u × t) + 0.5at²   ⇒  d = 0.5gt²

When the sandbag is released by the balloon at h = 40.0 m, it moves in a free-fall motion.

At t = 0.245 s

At t = 1.15 s

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Answer: Newton's second law of motion

Explanation:

Answer:

it is no darker than any other part of the moon surface

Explanation:

The magnetic field at a point due to wires with distance r = C cm and carrying the current I is 2 mA is 0.29 T.

The magnetic field is produced over the magnet or current-carrying conductor. The Biot-Sarvat law is defined as the magnetic field produced due to the current-carrying conductor. The magnetic field is the vector quantity and the unit of the magnetic field is Tesla. It is the vector quantity.

Magnetic field, B = μ₀/2π (I/R), where  μ₀ is the permeability of the magnetic field, I is current, and R is the distance between two points.

B₁= μ₀/2π (I/R)

 = (1.26×10⁻⁶)×2×10⁻³/(2π×1.35m)

 = 0.29T

B₂ = 0.29T

The net magnetic field is B=B₁+B₂=0.58T.

Thus, the magnetic field is 0.29T. The left wire carries the current outward direction and the right wire carried the current inward direction and hence the direction magnetic field given by the right-hand thumb rule is inside.

B) By using the equation, F=q(v×B), where q is the charge, v is the velocity and B is the magnetic field. Path b is followed by a neutron as it is not deflected by a Magnetic field. The path a is the upward path followed by a negatively charged particle(electron) and Path C is the downward path followed by a positively charged particle(proton).

C) The circular conductor undergoes thermal expansion while it is a uniform magnetic field the direction of the current is a clockwise direction given by the Right-hand thumb rule.

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4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.

The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.

To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.

Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.

ΔE = 4×10^26 W

c = 3×10^8 m/s (speed of light)

Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².

Substituting the values, we have:

Δm = (4×10^26 W) / (3×10^8 m/s)²

Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.

This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.

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Answer:

Given :  A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.

the bus engine exerts a constant forward force F.

To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?

Solution:

V²  - U² = 2aS

V = Vf

U = 0

S = 120 m

=> Vf² - 0 = 2a(120)

=> Vf² = 240a

m = 760  kg

Force = F

F = ma

=> F =760 a

=> a = F/760

Vf² = 240F/760

Case 2  :When the bus is towing a 330-kg small car,

m = 760 + 330 = 1090 kg

a = F/1090

Vf²  = 2aS

=> 240F/760  = 2 (F/1090) S

=> S = 120 x 1090 /760

=> S = 172.1   m  

172.1   m   distance needed to reach same Vf

Explanation:

Given,

The length of the vector, A=27.6 m

The angle made by the vector in the counterclockwise direction from the y-axis, θ=-60.0°

The negative sign indicates that the angle is in the counterclockwise direction. The angles made in the clockwise direction is represented with the positive sign.

The y-component of the given vector is calculated as,

On substituting the known values,

Thus the y-component of the given vector is 13.8 m