The molar solubility of \(Al(OH)_3\) in 0.2 M \(Al(NO_3)_3\) is approximately \(2.68 * 10^-^1^1 M.\)
To determine the molar solubility of \(Al(OH)_3\) in 0.2 M \(Al(NO_3)_3\) , we must take into account the normal ion effect. The presence of \(Al^3^+\) ions from \(Al(NO_3)_3\) will affect the solubility of \(Al(OH)_3\).
The balanced equation for the dissolution of \(Al(OH)_3\) in water is:
\(Al(OH)_3(s)\)⇌ \(Al^3^+(aq) + 3OH^-(aq)\)
The solubility product expression for \(Al(OH)_3\) is
\(K_s_p\) = \([Al^3^+]. [OH^-]^3\)
The molar solubility can be established using an equilibrium table, the \(K_s_p\) of \(Al(OH)_3\) is \(2.0 * 10^-^3^2\)
So,
[\(Al^3^+\)] = 0 (from 0.2 M \(Al(NO_3)_3\))
[\(OH^-\)] = 0
At equilibrium:
\([Al^3^+]\) = x (change due to dissolution of \(Al(OH)_3\))
\([OH^-]\)= 3x (since the stoichiometric coefficient is 3 in the balanced equation)
Using the \(K_s_p\)expression:
\(K_s_p = [Al^3^+][OH^-]^3\)
\(2.0 * 10^-^3^2 = x * (3x)^3\\2.0 * 10^-^3^2 = 27x^4\)
\(x = \sqrt[3]{2.0 * 10^-32 / 27} \\x = 2.68 * 10^-^1^1\)
Therefore, the molar solubility of \(Al(OH)_3\) in 0.2 M \(Al(NO_3)_3\) is approximately \(2.68 * 10^-^1^1 M.\)
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Show how to carry out the transformation of benzene to chlorobenzene by going through a diazonium intermediate. At each step, either select the appropriate reagents or draw the correct product.
The reaction of chlorobenzene is
\(C_6H_6 + HNO_2 + HCl-- > C_6H_5N_2Cl + H_2O\\C_6H_5N_2Cl + CuCl + HCl-- > C_6H_5Cl + CuCl_2 + N_2\)
The transformation of benzene to chlorobenzene through a diazonium intermediate involves the following steps:
Step 1: Diazotization
Benzene is first converted to a diazonium salt using nitrous acid and hydrochloric acid (HCl) at low temperatures.
\(C_6H_6 + HNO_2 + HCl-- > C_6H_5N_2Cl + H_2O\)
Step 2: Replacement of Diazonium group with Chlorine
The diazonium salt is then treated with cuprous chloride (CuCl) in the presence of hydrochloric acid (HCl) to replace the diazonium group with a chlorine atom to form chlorobenzene.
\(C_6H_5N_2Cl + CuCl + HCl-- > C_6H_5Cl + CuCl_2 + N_2\)
The overall reaction is:
\(C_6H_6 + HNO_2 + HCl-- > C_6H_5N_2Cl + H_2O\\C_6H_5N_2Cl + CuCl + HCl-- > C_6H_5Cl + CuCl_2 + N_2\)
The final product is chlorobenzene, which is formed by the replacement of the diazonium group with a chlorine atom.
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What is the molarity of HCl found in a titration where 30 mL of HCl is titrated with 15 mL of 0.1 M NaOH
The molarity of HCl is found in a titration where 30 mL of HCl is titrated with 15 mL of 0.1 M NaOH is 0.05 M.
What is molarity?Molarity is the measure of the concentration of any solute per unit volume of the solution.
The reaction is \(\rm NaOH(aq)+HCl(aq) \rightarrow H2O(l)+NaCl(aq)\)
The ratio is 1:1
Step1- to calculate the equal moles of HCl
\(\dfrac{0.1\;mol\;NaOH}{ L} \times 15\;ml = 1.5\; mmol\)
Step2: Calculate the molar concentration
\(\dfrac{1.5 \; m mols\;HCl}{ 30\;ml\;HCl} = 0.05 \;M \;HCl\)
Thus, the molarity of HCl is 0.05 M.
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Elements K and L have 12 and 17 protons respectively. If
Khas 24 neutrons and L has 36, in a tabular form identify
the number of protons, neutrons and electrons
possessed by the ions of the two elements.
Given
Element K : 12 protons, 24 neutrons
Element L : 17 protons, 36 neutrons
Required
the number of protons, neutrons and electrons possessed by the ions of the two elements.
Solution
Element Knumber of protons=atomic number = 12
electron configuration : 1s² 2s² 2p⁶ 3s²
The element will release 2 electrons to make it stable, thus forming a cation with a +2 charge
number of protons = 12
number of electrons = 10
number of neutrons = 24
Element Lnumber of protons=atomic number = 17
electron configuration : 1s² 2s² 2p⁶ 3s²3p⁵
The element will gain 1 electrons to make it stable, thus forming a anionwith a -1 charge
number of protons = 17
number of electrons = 18
number of neutrons = 36
If we look at this problem, it looks like the numbers 24 and 36 are mass numbers, not the number of neutrons, so the possible elements are Mg and Cl, and the ions are Mg²⁺ and Cl⁻
What is hydrogenation?
Explanation:
Hydrogenation is a reduction reaction which results in an addition of hydrogen (usually as H2). If an organic compound is hydrogenated, it becomes more "saturated" with hydrogen atoms. The process typically requires the use of a catalyst, since hydrogenation only occurs spontaneously at high temperatures. The most common catalysts are nickel, platinum, or palladium.
Hydrogenation reduces the number of double and triple bonds in hydrocarbons, while dehydrogenation removes hydrogen atoms and increases the number of double and triple bonds
Methane, CH4, is burned with dry air. The molar analysis of the products on a dry basis is CO2, 9.7%; CO, 0.5%; 02, 2.95%; and N2, 86.85%. Determine (a) the air- fuel ratio on both a molar and a mass basis, (b) the percent theoretical air, (c) the dew point temperature of the products, in °F, if the products are cooled at 1 atm.
a) the air-fuel ratio on a molar basis is 9.52. the air-fuel ratio on a mass basis is 17.98. b) the percent theoretical air is 92.3%. c) the dew point temperature of the products is approximately 44 °F.
a) Calculation of air-fuel ratio (AFR) on molar basis:
First of all, we need to determine the stoichiometric equation for the combustion of methane. The stoichiometric equation of methane combustion with dry air can be written as follows:
CH₄ + 2(O₂ + 3.76N₂) → CO₂ + 2H₂O + 7.52N₂
The equation shows that for every mole of methane, 2 moles of oxygen (from air) and 7.52 moles of nitrogen are required for complete combustion. Therefore, the molar air-fuel ratio (AFR) can be calculated as:
AFRm = (moles of air) / (moles of fuel)
AFRm = (2 × 3.76 + 2) / 1
AFRm = 9.52
Hence, the air-fuel ratio on a molar basis is 9.52.
Calculation of air-fuel ratio (AFR) on mass basis:
The mass of dry air per mole of air is equal to the sum of the molar masses of the constituent gases of dry air, which are nitrogen (N₂) and oxygen (O₂). Therefore, the mass basis of air-fuel ratio can be calculated as:
AFRmass = (mass of air) / (mass of fuel)
AFRmass = [(2 × 28.02 + 3.76 × 28.02) g] / (16.04 g)
AFRmass = 17.98
Hence, the air-fuel ratio on a mass basis is 17.98.
b) Calculation of percent theoretical air:
The theoretical air requirement (TAR) is the minimum amount of air required to completely combust a unit mass of fuel. The percent theoretical air (%TAR) can be calculated as:
%TAR = (AFRactual / AFRstoichiometric) × 100
AFRstoichiometric = (2 × 3.76 + 2) / 1 = 9.52
Given, AFRactual = 86.85 / (9.7 + 0.5 + 2.95) = 8.78
%TAR = (8.78 / 9.52) × 100 = 92.3%
Therefore, the percent theoretical air is 92.3%.
c) Calculation of dew point temperature of the products:
The dew point temperature is the temperature at which the water vapor present in the products starts to condense into liquid water. It can be calculated from the water vapor partial pressure using a steam table. The water vapor partial pressure can be calculated as:
P(H₂O) = y(H₂O) × P(total)
y(H₂O) = (moles of water vapor) / (total moles of products)
y(H₂O) = 2 / (0.097 + 0.005 + 0.0295 + 0.8685) = 0.022
P(total) = P(CO₂) + P(CO) + P(O₂) + P(N₂) = 1 atm
Using a steam table at 1 atm, the dew point temperature of water vapor is found to be approximately 44 °F.
Therefore, the dew point temperature of the products is approximately 44 °F.
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What is the molarity of a solution made by mixing 112. 3 g Mg(OH)2 with enough water to make 1. 2 L?
We must first determine how many moles of Mg(OH)2 are in the solution in order to determine its molarity:
Compute Mg(OH)2's molar mass:
mol Mg = 24.31 g
O = 15.99 g/mol
H = 1.01 g/mol
Mg(OH)2 has a molar mass of 24.31 plus 2(15.99) plus 2(1.01), or 58.33 g/mol.
Determine how many moles of Mg(OH)2 there are:
Mass / molar mass = number of moles
1.925 moles are obtained by multiplying 112.3 g by 58.33 g/mol.
Determine the solution's molarity:
Molarity is equal to the moles of solute per litre of solution.
Molarity = 1.925 moles/1.2 litres = 1.60 M
As a result, the molarity of the solution created by combining 1.2 L of water with 112.3 g of Mg(OH)2 is 1.60 M.
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Use the periodic table to identify the element indicated by each electron configuration by typing in the chemical symbol for the element.
1s22s22p6:
Ne
1s22s22p63s23p3:
P
1s22s22p63s23p64s1:
K
1s22s22p63s23p64s23d8:
Ni
1s22s22p63s23p64s23d104p65s24d3:
Nb
Answer:
1s22s22p6: Ne 1s22s22p63s23p3: P 1s22s22p63s23p64s1: K 1s22s22p63s23p64s23d8: Ni 1s22s22p63s23p64s23d104p65s24d3: Nb
Answer:
1s22s22p6:
Ne
1s22s22p63s23p3:
P
1s22s22p63s23p64s1:
K
1s22s22p63s23p64s23d8:
Ni
1s22s22p63s23p64s23d104p65s24d3:
Nb
Explanation:
How could you test whether or not a substance is a fluid?
Classify each property according to whether it is displayed by metals or by nonmetals
a. low melting point b. shiny dull c. poor conductor d. ductile e. malleable f. brittle g. good conductor h. high melting point
a. low melting point: Nonmetals. b. shiny: Metals. c. poor conductor: Nonmetals. d. ductile: Metals. e. malleable: Metals. f. brittle: Nonmetals. g. good conductor: Metals. h. high melting point: Metals
a. Low melting point is generally displayed by nonmetals. Metals tend to have high melting points.
b. Metals are typically shiny due to their ability to reflect light.
c. Nonmetals are generally poor conductors of heat and electricity.
d. Metals are ductile, meaning they can be drawn into thin wires without breaking.
e. Metals are malleable, meaning they can be hammered into thin sheets or shapes without shattering.
f. Nonmetals are usually brittle, meaning they are prone to breaking or shattering when subjected to stress.
g. Metals are good conductors of heat and electricity.
h. Metals typically have high melting points compared to nonmetals.
It's important to note that these are general trends and not absolute characteristics for all metals or nonmetals. Some exceptions or variations may exist within specific elements or compounds.
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The chemical formula:N2 would represent what type of substance
Answer:
it would represent sodium
Considering the temperature vs. time graph below, how does the temperature at the beginning of a change of state
compare with the temperature at the end of the change?
The temperature is always lower.
The temperature is always the same.
The temperature is usually lower.
The temperature is usually higher.
calculate the molarity of a solution of 0.065 grams of nacl in enough ethanol (ch3ch2oh) to give 100 ml of solution.
The molarity of the solution of 0.065 grams of NaCl in enough ethanol \((CH_3CH_2OH)\) to give 100 ml of solution is 0.11 M.
The molarity of a solution is defined as the number of moles of solute per liter of solution. To calculate the molarity, we need to know the number of moles of solute present in the solution and the volume of the solution.
First, we need to find the number of moles of solute. We can do this by using the formula:
moles of solute = mass of solute / molar mass of solute
The molar mass of NaCl is 58.44 g/mol, so we can use this to calculate the number of moles of NaCl in 0.065 g of NaCl:
moles of NaCl = 0.065 g / 58.44 g/mol = 0.0011 mol
Next, we need to find the volume of the solution. We know that the solution has a volume of 100 ml. We will assume that the density of ethanol is close to the density of water which is 1g/ml, so we can assume that the volume of the solution is equal to the mass of the solution.
Finally, we can calculate the molarity of the solution:
molarity = moles of solute/liters of solution
molarity = 0.0011 mol / 0.1 L = 0.11 M
So the molarity of the solution is 0.11 M.
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guess what 2nd language i can speak:
A1. german
B2. french
C3. Sarcasum
Answer:
B2 French I hope I'm right
Answer:
English
Explanation:
I mean u typing in English lol
the hypothetical elementary reaction 2a b c has a rate constant of 0.049 m -1 s -1. what is the reaction velocity when the concentration of a is 42 mm?
The We are given a hypothetical elementary reaction 2A + B → C, with a rate constant (k) of 0.049 M^-1 s^-1, and the concentration of A as 42 mm We will determine the reaction velocity (v) when the concentration of A is 42 mm.
The Convert the concentration of A from mM to M. Since 1 M = 1000 mM, we have 42 mM = 42 / 1000 = 0.042 M
Write down the rate law for the elementary reaction. For the given elementary reaction, the rate law is v = k[A]^2[B]
Solve for the reaction velocity (v) We have the rate constant (k) and the concentration of A, but we don't have the concentration of B. Without the concentration of B, we cannot calculate the exact value of v. However, we can express v in terms of [B]. Substitute the given values for k and [A] v = (0.049 M^-1 s^-1) (0.042 M) ^2[B] v = (0.001764) [B]
v ≈ 8.64 x 10^-5 M^-1 s^-1[B] So, the reaction velocity (v) is approximately 8.64 x 10^-5 M^-1 s^-1 times the concentration of B ([B]).
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Which family does this element belong to? It is a silvery-white, soft metal
that tarnishes rapidly in air and reacts with water, is a relatively soft metal
Alkali Metals
Alkaline Earth Metals
Halogens
Noble gases
Answer:
Alkali metals
hope it helps
a.
Which of these statements about a column of the periodic table is true?
The elements have similar characteristics.
b. The elements have a wide range of characteristics.
C. The elements have the same atomic number.
d. The elements have the same atomic mass.
What is the chemical formula for acetic acid?
CH3COOH
Explanation:
hope I helped
if you get the answer right mark me as brainlyst
which of these is a chemical property of a substance?
A:density
B:color
C:melting point
D:reactivity
Answer:
The correct answer would be D, reactivity
Explanation:
Some examples of different types of chemical properties include toxicity, heat of combustion, acidity, flammability, and the many other types of reactivity. I hope this helps you! :)
whats the temperature outside in florida
Answer:
80 degrees
Explanation:
Under appropriate conditions, nitrogen and hydrogen undergo a combination reaction to yield ammonia: N2 (g) + 3H2 (g) → 2NH3 (g) A 9.3-g sample of hydrogen requires ________ g of N2 for a complete reaction.
Answer:
43 g N₂
Explanation:
To find the mass of N₂ required, you need to (1) convert grams H₂ to moles H₂ (via molar mass), then (2) convert moles H₂ to moles N₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles N₂ to grams N₂ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 2 sig figs to match the amount of sig figs of the given value.
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
Molar Mass (N₂): 2(14.009 g/mol)
Molar Mass (N₂): 28.018 g/mol
1 N₂(g) + 3 H₂(g) -----> 2 NH₃(g)
9.3 g H₂ 1 mole 1 mole N₂ 28.018 g
-------------- x ---------------- x -------------------- x ------------------ = 43 g N₂
2.016 g 3 moles H₂ 1 mole
The image shows energy flowing from coal, to a coal-fired power plant, to a power
tower, and finally to a radio. Match the types of energy as they are converted from
one type to the other in each stage of the process. HELPP PLS
The types of energy are correctly matched below:
Thermal energy: Coal-fire power plant
Electrical energy: power plant
Sound energy: Radio
Chemical/potential energy:Coal
What is energy conversion?Energy conversion is also known as energy transformation whereby a type of energy changes to another form of energy.
There are various types of energy which includes:
Thermal energy: A typical example of thermal energy is the coal-fire power plant which generates heat energy upon its performance and usage.Electrical energy: A typical example of the electrical energy is the power plant which has the ability to generate electricity.Sound energy: A typical example of the sound energy is the radio device which has the ability to generate sounds.Chemical/potential energy: A typical example of chemical energy is the coal.Learn more about energy here:
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Select the correct answer. What is the molar mass of BaBr2? A. 217. 2 g/mol B. 297. 1 g/mol C. 354. 5 g/mol D. 434. 4 g/mol.
Answer:
B. 297.1
Explanation:
To fond molar mass you just add the atomic
masses together however many ttimes they appear. Eg. BaBr2 would be 137.33 + 2(79.9)
Which of the following is not a possible sublevel?
a. 1s
b. 2p
c. 3f
d. 4d
Calculate the number of vanadium atoms in a 50.0 sample of vanadium oxide (V2O5)
how many grams are in 2.34 moles of Li?
Answer:
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Lithium, or 6.941 grams.
Thus, the answer would be 16.24194.
Explanation:
PLEASE HELP ME PLEASEEEE if you could just answer one of these questions that would be amazing!
A period of the life cycle during which positive nitrogen balance is most likely to occur is:__________
The period of the life cycle during which positive nitrogen balance is most likely to occur is childhood.
What is nitrogen balance?The term nitrogen balance refers to the fact that there is a balance between the intake and the loss of nitrogen. The intake of nitrogen occurs when a person takes in food that contain proteins which are a rich source of nitrogen in the body and helps in the process of the build up of the cells in the body.
The period of the life cycle during which positive nitrogen balance is most likely to occur is childhood.
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Psychoanalysis is a measure that does not assess nutritional status.
Nutritional status reflects the health of the person as a function of the nutrients in his/her diet. Through a clinical examination and dietary recall, we can figure out if the person is eating enough in terms of build and nourishment, 24-hour meal recall, social status, etc. Biochemical examinations are used to confirm the clinical findings or even discover malabsorption states. .
Psychoanalysis is diving deep into the mental status of the patient. Asking about how they feel, relevant past experiences, and current state is done. But this has nothing to do with the nutritional status of the person.
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is pH 6 a weak or strong acid?
Answer:
6 pH is a weak acid
Explanation:
Generally, a strong acid has a pH of about zero to 3.
The pH scale typically ranges from 1 to 14, with lower numbers representing acids, higher numbers, bases. Neutral liquids like water have a pH of 7.
(Please heart the answer if you find it helpful, it's a motivation for me to help more people)
How do the following changes affect the value of the equilibrium constant for a gas-phase exothermic reaction: Drag the appropriate items to their respective bins. Reset Help addition of a catalyst decrease in the temperature removal of a product decrease in the volume removal of a reactant Increase equilibrium constant Decrease equilibrium constant No effect on equilibrium constant
The following changes affect the value of the equilibrium constant for a gas-phase exothermic reaction:
Addition of a catalyst- Increase equilibrium constant
Decrease in the temperature - Decrease equilibrium constant
Removal of a product- No effect on equilibrium constant
Decrease in the volume- Decrease equilibrium constant
Removal of a reactant- Decrease equilibrium constant
Define exothermic process
An exothermic process in thermodynamics is a thermodynamic process or reaction that releases energy from the system to its surroundings, typically in the form of heat but occasionally in the form of light (such as a spark, flame, or flash), electricity (such as from a battery), or sound (such as the explosion produced by the burning of hydrogen).
The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant, K. The equilibrium constant is temperature-dependent and unaffected by the precise ratios of reactants to products, the presence of a catalyst, or the presence of inert substances. Additionally, it is unaffected by the volumes, pressures, and concentrations of the reactants and products.
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The main advantage of solar energy is:
It has very little pollution.
It is free.
It can be used all the time.
It is low in cost.
Answer:
I think ithe answer is it is free
hope this helps