the highest points you can score in a B.B game. true or false. (help a bestie out )

The reason galaxies that are distant from our galaxy move away from our galaxy more rapidly is more space expands between us and distant galaxies.

A galaxy is a group of millions of stars and their systems that are grouped due to gravitational forces.

According to the Big Bang theory, galaxies are expanding and separate among them.

In conclusion, the reason galaxies that are distant from our galaxy move away from our galaxy more rapidly is more space expands between us and distant galaxies.

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Answer:

the galaxies are moving as the universe keep expanding .

Explanation:

The final velocity of the model rocket when the engine cuts out is \(32.3 m/s.\)

We may solve for the model rocket's final velocity using the formula: work done (W) = change in kinetic energy (KE). We must first identify the work the model rocket engine has done. It is stated that 1500 J of work are applied.
\(W = 1500 J\)
Next, we need to find the change in kinetic energy of the model rocket. We know that it starts from rest and travels 35 meters with a mass of 0.80 kg.
\(ΔKE = 1/2 mv^2 - 0\)
\(ΔKE = 1/2 (0.80 kg) v^2\)
\(ΔKE = 0.40v^2\)
Now we can substitute these values into the equation:
\(1500 J = 0.40v^2\)
Solving for v, we get:
\(v = \sqrt{1500 J / 0.40(0.80 kg}\)
\(v = 32.3 m/s\)
Therefore, the model rocket is going 32.3 m/s when the engine cuts out.

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Answer:

13108.3N

Explanation:

Given parameters:

Acceleration = 0.785m/s²

Net force  = 1050N

Unknown:

Normal force acting on car  = ?

Solution:

The normal force on this car is the weight of the car;

   Normal force  = mg

where m is the mass of the car

           g is the acceleration due to gravity = 9.8m/s²

Now solve for the mass;

             Net force  = mass x acceleration

                1050  = mass x 0.785

                 mass  = \(\frac{1050}{0.785}\)   = 1337.6kg

So,

     Normal force  = 1337.6kg x 9.8m/s² = 13108.3N

13108 works as well for acellus

In the case of the bug and the car, both will experience the same force when they collide, based on Newton's second law of motion. But since the bug has less mass than the car, it will experience much greater acceleration.

This law states that the force acting on an object is equal to its mass multiplied by its acceleration, given by the formula:

So, as a result, the bug is quickly stopped by the force of the collision, while the car continues to move with little noticeable change in its speed.

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Answer: When you change lanes, follow these steps:

Turn on your signal.

Check your mirrors.

Check your blind spot by looking over your shoulder.

If it is safe, change lanes.

Turn off your signal after completing the lane change.

Explanation: urwellcome

Answer:

Turn on your turn signal, and check for cars behind and in front of you.

Explanation:

It is important to check for cars because you may crash and injure/die. So stay safe!

If the voltage of the battery is doubled, the compass needle would deflect by a greater angle than before.

If the voltage of the battery in the simple circuit is doubled, it would result in a stronger current flowing through the circuit. The increase in current would lead to a stronger magnetic field generated by the circuit.

When the switch is turned on, the flow of current through the wire creates a magnetic field around it. This magnetic field interacts with the magnetic compass, causing the needle to deflect. Doubling the voltage of the battery would increase the current flowing through the wire, thereby increasing the strength of the magnetic field generated by the circuit. As a result, the compass needle would experience a stronger magnetic force, leading to a larger deflection. If the voltage of the battery is doubled, the compass needle would deflect by a greater angle than before. Instead of the previous 5 degrees deflection to the west, the needle may deflect by a larger angle, depending on the exact relationship between the magnetic field strength and the angle of deflection.

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Answer:

\(0.5\; {\rm m}\).

Explanation:

The period \(T\) of a wave is the reciprocal of its frequency \(f\). In other words, \(T = (1/f)\). Since the frequency of the wave in this question is \(f = 10\; {\rm Hz} = 10\; {\rm s^{-1}}\), the period of this wave would be \(T = (1/f) = (1/10)\; {\rm s} = 0.1\; {\rm s}\).

The wavelength of a wave is the distance its wavefront travels in one period \(T\).

The period of this wave is \(T = 0.1\; {\rm s}\). At a speed of \(v = 5\; {\rm m\cdot s^{-1}}\), it would have travelled a distance of \(v\, T = (0.1\; {\rm s})\, (5\; {\rm m\cdot s^{-1}}) = 0.5\; {\rm m}\) within one period.

The equation of the motion of this object is  \(\mathbf{y = 3 cos \Big [ \dfrac{ \pi}{2}(t -2) \Big ] }\)

An oscillation in a waveform is a periodic set of vibrations an object in the medium produces.

From  the parameters given:

The angular velocity can be computed by using the formula:

\(\mathbf{\omega = \dfrac{2 \pi}{T}}\)

\(\mathbf{\omega = \dfrac{2 \pi}{4.0}}\)

The amplitude A from the oscillation is:

\(\mathbf{\Big|A \Big| = \Big|\dfrac{3 - (-3)}{2} \Big| = 3}\)

It implies that the vertical shift (D) is:

\(\mathbf{\dfrac{minimum + maximum}{2} = \dfrac{3+(-3)}{2} = 0}\)

However, by using the formula of the general form of a sinusoidal equation, we have:

\(\mathbf{y = A cos \Big [ \dfrac{2 \pi}{4}(t -2) \Big ] + 0}\)

\(\mathbf{y = 3 cos \Big [ \dfrac{ \pi}{2}(t -2) \Big ] }\)

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The momentum flow rate through the pipe carrying liquid ammonia is 1 × \(10^6\) kg·m/s.

The flow rate of momentum (Ṁ) through the pipe can be calculated by multiplying the mass flow rate (ṁ) by the velocity (v). The speed can be determined using the equation v = ṁ / (ρA), where ρ is the density of the liquid ammonia and A is the pipe's cross-sectional area.

Given:

ṁ = 100 kg/s

A = 0.01 m²

Assuming the density (ρ) of liquid ammonia is 700 kg/m³, we can calculate the velocity (v):

v = ṁ / (ρA)

v = 100 kg/s / (700 kg/m³ × 0.01 m²)

v = 10000 m/s

Now, we can calculate the flow rate of momentum (Ṁ):

Ṁ = ṁv

Ṁ = 100 kg/s × 10000 m/s

Ṁ = 1 × \(10^6\) kg·m/s

Therefore, the momentum flow rate through the pipe is 1 × \(10^6\) kg·m/s.

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Answer:

you calculate a specific type of run for example 100m and it takes 20 seconds to finish and calculate the time it takes them to finish

hope this helps

have a good day :)

Explanation:

You need th information about the time period she ran and the distance she covered in that time period to analyze her speed.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second.

The generally considered unit for speed is a meter per second.

Your friend wants to join the school track team and has asked for your help to determine how fast she can run the data of her time and the length of the distance she covered in that period of time because the only way to know how fast she runs is to analyze her speed by using the distance and the time.

Thus , you need information about the time period she ran and the distance she covered in that time period to analyze her speed.

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Answer:

The correct option is (c) "it bounces the light towards a focal point"

Explanation:

There are two types of spherical mirrors i.e. concave and convex.

A concave mirror is a type of spherical mirror that is curved inwards. For this type of mirror the rays of light are bounced back and converge to the focal point of the mirror.

So, the correct option is (c).

Answer:

c

Explanation:

a) Answer: On the equator, the Circle of Illumination divides the earth into two equal parts, with each part receiving 12 hours of daylight and 12 hours of darkness.

The equator receives an equal day and night (12 hours each) regardless of the day of the year due to the Circle of Illumination, which is a line that separates the day side of the earth from the night side of the earth. The Circle of Illumination separates the sunlit and dark sides of the earth. The earth's axis is at a 23.5-degree angle to the plane of its orbit around the sun, causing different latitudes to receive different amounts of sunlight throughout the year. On the equator, the Circle of Illumination divides the earth into two equal parts, with each part receiving 12 hours of daylight and 12 hours of darkness.

b)  Answer: The earth's axis is tilted at 23.5°, and during the December solstice, the North Pole is tilted away from the sun, causing the Arctic Circle and areas beyond it to experience a full day of daylight because the sun is above the horizon for 24 hours.

On December 22nd, between the latitudes of the Tropic of Cancer (23.5°N) and the Arctic Circle (66.5°N), 24 hours of daylight is experienced. This occurs because the earth's axis is tilted at 23.5°, and during the December solstice, the North Pole is tilted away from the sun, causing the Arctic Circle and areas beyond it to experience a full day of daylight because the sun is above the horizon for 24 hours.

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The magnitude spectrum versus frequency for the signal g(t) = exp(-10t)u(t) and the continuous magnitude transform, and to determine the number of points in the signal and the period, the provided MATLAB code can be used.

A. To plot the magnitude spectrum versus frequency for the signal g(t) = exp(-10t)u(t) for 0 ≤ t ≤ 1 with Δt = 0.01 and determine the number of points in the signal:

```matlab

% Define parameters

delta_t = 0.01; % Sampling interval

t = 0:delta_t:1; % Time vector

g = exp(-10*t).*(t >= 0); % Signal definition

% Pad with zeros

N_zeros = 450;

g_padded = [zeros(1, N_zeros), g, zeros(1, N_zeros)];

% Compute the Fourier Transform

G = fft(g_padded);

% Compute the magnitude spectrum

G_mag = abs(G);

% Determine the number of points in the signal

num_points = length(g_padded);

% Determine the period

T = num_points * delta_t;

% Determine the frequency vector

Fs = 1/delta_t; % Sampling frequency

f = (-Fs/2 : Fs/num_points : Fs/2 - Fs/num_points);

% Plot the magnitude spectrum versus frequency

plot(f, G_mag);

xlabel('Frequency');

ylabel('Magnitude Spectrum');

title('Magnitude Spectrum versus Frequency');

```

B. To plot the continuous magnitude transform given by G(f) = (10 + j2πf) / (1 - e^(-(10 + j2πf))) and utilize the same frequency separation:

```matlab

% Define frequency range

f = -Fs/2 : Fs/num_points : Fs/2 - Fs/num_points;

% Evaluate the expression for G(f)

G_continuous = (10 + 1j * 2 * pi * f) ./ (1 - exp(-(10 + 1j * 2 * pi * f)));

% Plot the continuous magnitude transform

plot(f, abs(G_continuous));

xlabel('Frequency');

ylabel('Magnitude');

title('Continuous Magnitude Transform');

```

C. To plot the magnitude spectrum versus frequency for the signal g(t) = sinc(πt) assuming Δt = 0.01 and determine the period T:

```matlab

% Define parameters

delta_t = 0.01; % Sampling interval

t = -1:delta_t:1; % Time vector

g = sinc(pi*t); % Signal definition

% Pad with zeros

N_zeros = 450;

g_padded = [zeros(1, N_zeros), g, zeros(1, N_zeros)];

% Compute the Fourier Transform

G = fft(g_padded);

% Compute the magnitude spectrum

G_mag = abs(G);

% Determine the number of points in the signal

num_points = length(g_padded);

% Determine the period

T = num_points * delta_t;

% Determine the frequency vector

Fs = 1/delta_t; % Sampling frequency

f = (-Fs/2 : Fs/num_points : Fs/2 - Fs/num_points);

% Plot the magnitude spectrum versus frequency

plot(f, G_mag);

xlabel('Frequency');

ylabel('Magnitude Spectrum');

title('Magnitude Spectrum versus Frequency');

```

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Answer:

Explanation:

In this problem we are required to find the potential energy possessed by the television

Given data

mass of television m = 15 kg

height  added above the ground, h= 1-0.3 = 0.7 m

acceleration due to gravity g = 9.81 m/s^2

apply the formula for potential energy we have

P.E= m*g*h

P.E = 15*9.81*0.7 = 103 Joules

The magnification of the image of Julitha Barber produced by the converging mirror is 0.0979

To find the magnification of the image, we need to use the formula:

magnification = -v/u,

where v is the distance of the image from the mirror, and u is the distance of the object from the mirror. Since the object is Julitha Barber standing at a distance of 553 m, we can take u as -553 m (negative because the object is on the same side as the mirror).
Now, we need to find the distance of the image from the mirror (v). For this, we can use the mirror formula: 1/v + 1/u = 1/f, where f is the focal length of the mirror, and is equal to half the radius of curvature (f = R/2). So, in this case, f = 1.20 × 102 m/2 = 60 m. Substituting the values in the formula, we get:
1/v + 1/-553 = 1/60
Solving for v, we get v = -54.12 m. (Note that the negative sign indicates that the image is virtual and upright.)
Now, we can use the magnification formula to find the magnification of the image:
magnification = -v/u = -(-55.6)/553 = 0.0979  (rounded to one decimal place)
Therefore, the magnification of the image of Julitha Barber produced by the converging mirror is 0.0.0979. This means that the image is 10 times smaller than the actual object and is virtual and upright.

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Answer:

Filiberto experimenta una deceleración de \(2\,\frac{m}{s^{2}}\).

Explanation:

(The problem was written in Spanish. Hence, explanation will be held in Spanish).

Asúmase que Filiberto se distrae por 2 segundos, puesto que un par equivale a dos, y que el vehículo experimenta un aceleración constante. La deceleración experimentada por el vehículo se deriva de la siguiente fórmula:

\(a = \frac{v-v_{o}}{\Delta t}\)

\(a = \frac{40\,\frac{m}{s}-90\,\frac{m}{s} }{2\,s}\)

\(a = -25\,\frac{m}{s^{2}}\)

Filiberto experimenta una deceleración de \(2\,\frac{m}{s^{2}}\).

Answer:

Explanation:

The strength of the force of friction depends on two factors: how hard the surfaces push together and the types of surfaces involved. What factors affect the gravitational force between two objects? Two factors affect the gravitational attraction between objects: mass and distance.

Answer: 11.025 meters.

Explanation:

Ok, we know that the initial velocity is only horizontal, so it does not affect the vertical problem.

Looking only at the vertical problem (because we want to know how high is the bridge) we have that:

The acceleration is the gravitational acceleration, g = 9.8m/s^2

A(t) = -9.8m/s^2

Where the negative sign is because this acceleration is downwards.

For the vertical velocity we integrate over time, as we do not have an initial vertical velocity, there is no constant of integration.

V(t) = (-9.8m/s^2)*t

For the position we integrate over time again, here the constant of integration is the initial vertical position, H, that is the height of the bridge.

P(t) = 0.5* (-9.8m/s^2)*t^2 + H.

Now we know that the ball hits the ground 1.5s after it was kicked, then:

p(1.5s) = 0m

With that we can find the value of H.

0 = 0.5* (-9.8m/s^2)*(1.5s)^2 + H.

H = 0.5*(9.8m/s^2)*(1.5s)^2 = 11.025m

The rate at which the current in the solenoid is changing at this instant is 4.4 A/s.

To determine the rate at which the current in the solenoid is changing, we can use Faraday's law of electromagnetic induction. According to Faraday's law, the induced electromotive force (emf) is equal to the negative rate of change of magnetic flux through a circuit. In this case, the solenoid acts as a circuit.

The induced electromotive force (emf) is given by:

emf = -dΦ/dt

Where:

emf is the induced electromotive force,

dΦ/dt is the rate of change of magnetic flux.

For a long solenoid, the magnetic flux (Φ) can be calculated as:

Φ = B * A

Where:

B is the magnetic field strength,

A is the area of the solenoid.

The magnetic field strength inside a solenoid is given by:

B = μ₀ * n * I

Where:

μ₀ is the permeability of free space (4π × 10^-7 T·m/A),

n is the number of turns per unit length (turns/m),

I is the current flowing through the solenoid.

Let's calculate the magnetic field strength (B) inside the solenoid:

B = μ₀ × n × I

 = (4π × 10^-7 T·m/A) × (800 turns/m) × I

 = (3.1831 × 10^-4) × I T

The area (A) of the solenoid can be calculated using the formula for the area of a circle:

A = π × r^2

Where:

r is the radius of the solenoid.

Let's calculate the area (A) of the solenoid:

A = π × r^2

 = π × (0.03 m)^2

 = 0.002827 m^2

Now, substitute the values of B and A into the formula for magnetic flux:

Φ = B × A

  = (3.1831 × 10^-4) × I T × 0.002827 m^2

  = 9.0 × 10^-7 × I Wb

Next, we differentiate the magnetic flux (Φ) with respect to time (t) to find the rate of change of magnetic flux:

dΦ/dt = d/dt (9.0 × 10^-7 × I)

       = 9.0 × 10^-7 × dI/dt Wb/s

Finally, we can equate the rate of change of magnetic flux (dΦ/dt) to the induced electromotive force (emf) given in the problem statement:

emf = -dΦ/dt

    = -9.0 × 10^-7 × dI/dt Wb/s

Given that the induced electromotive force (emf) is 4.0 μV/m = 4.0 × 10^-6 V/m, we can solve for the rate of change of current (dI/dt):

4.0 × 10^-6 V/m = -9.0 × 10^-7 × dI/dt

\(\frac{dI}{dt} = \frac{-(4.0) (10^-6 V/m)}{(9.0) (10^-7)} = -4.4 A/s\)

Therefore, the rate at which the current in the solenoid is changing at this instant is 4.4 A/s.

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Answer:

Radio waves, infrared, visible light, ultraviolet, X-rays, and gamma rays are examples of waves conveyed by simultaneous periodic fluctuations in electric and magnetic field intensity.

Explanation:

Hope this helps! Stay Safe and have a great day :)

Given that the elevation of Lake Havasu is 400 feet and Lake Tahoe is 6200 feet, we need to determine which lake has a lower concentration of oxygen gas.

Higher elevation generally corresponds to lower atmospheric pressure, which affects the availability of oxygen. Therefore, Lake Havasu, located at a lower elevation, is likely to have a higher concentration of oxygen gas compared to Lake Tahoe.

The concentration of oxygen gas in water is influenced by several factors, including atmospheric pressure and temperature. As elevation increases, atmospheric pressure decreases. Lower atmospheric pressure at higher elevations results in less oxygen dissolved in water compared to lower elevations.

Lake Tahoe, situated at an elevation of 6200 feet, experiences lower atmospheric pressure compared to Lake Havasu, which is at 400 feet. Therefore, Lake Havasu is expected to have a higher concentration of oxygen gas in its water compared to Lake Tahoe.

It's important to note that factors such as temperature, circulation patterns, and biological processes also influence oxygen concentration in lakes. However, given the same water temperatures, the difference in elevation between the two lakes suggests that Lake Havasu would likely have a relatively higher concentration of oxygen gas.

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Given:

The applied force is F = 23 N

The mass of the object is m = 7 kg

The object moves with a constant velocity of v = 6.1 m/s

The acceleration due to gravity is g = 10 m/s^2

Required: The coefficient of friction between the object and the surface.

Explanation:

The object moves at a constant velocity, so the acceleration will be zero.

The equation of motion can be written as

So, the applied force will be equal to the frictional force.

The coefficient of friction can be calculated as

On substituting the values, the coefficient of friction will be

Thus, the coefficient of friction is 0.33

Final Answer: The coefficient of friction between the object and the surface is 0.33.

Answer:

The building are not getting farther and farther away, road signs, exits, other cars

Explanation:

In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.

However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.

It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.

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The extra cost of fuel for driving 83 mph instead of 73 mph is $3.7671.

The speed of your automobile has a huge effect on fuel consumption. Traveling at 65 miles per hour (mph) instead of 55mph can consume almost 20% more fuel. As a general rule, for every mile per hour over 55 , you lose 2% in fuel economy.

If you take a 400-mile trip and your average speed is 83mph rather than the posted speed limit of 73mph, then the extra cost of the fuel is calculated as:

* **Fuel consumption at 83 mph:** 30 mpg * (1 - 2% * (83 - 55)) = 27.6 mpg

* **Fuel consumption at 73 mph:** 30 mpg * (1 - 2% * (73 - 55)) = 29 mpg

* **Extra fuel used:** 400 miles / 27.6 mpg - 400 miles / 29 mpg = 2.4 gallons

* **Extra cost of fuel:** $3.26/gallon * 2.4 gallons = $3.7671

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the electric field is more than the threshold value and the capacitor will experience dielectric breakdown.

1. Given values are,
side length of metal plates, a = 3 cm and b = 6 cm
distance between the plates, d = 2.36 cm
voltage, V = 110 V
dielectric constant of water, k = 80.4
dielectric constant of new material, k2 = 3.75
a) To calculate the capacitance of capacitor, the formula is, C=εA/d  ……………… (1)
where A = area of plate, ε = permittivity, and d = separation distance between two plates.
We know that the permittivity of vacuum is given as, ε0 = 8.854 x 10^-12 F/m
The capacitance of capacitor can be expressed as,
C1 = ε0 (kA/d) …………….. (2)
where, ε0 = permittivity of vacuum, k = dielectric constant and A = area of plate.
Substituting the given values in equation (2),
C1 = 8.854 x 10^-12 x 80.4 x (0.03 x 0.06)/0.0236
C1 = 0.000132 F
Therefore, the capacitance of capacitor is 0.000132 F.

b) To calculate the new capacitance, the formula is given as,
C2 = k2ε0A/d ……………… (3)
where k2 is the dielectric constant of new material.
Substituting the given values in equation (3),
C2 = 3.75 x 8.854 x 10^-12 x (0.03 x 0.06)/0.0236
C2 = 0.000263 F
Therefore, the new capacitance is 0.000263 F.

c) The new voltage can be calculated as,
V2 = V1(C1/C2) …………… (4)
Substituting the given values in equation (4),
V2 = 110 (0.000132/0.000263)
V2 = 55 V
Therefore, the new voltage is 55 V.

d) The charge on each plate is given as,
Q = CV ………….. (5)
Substituting the given values in equation (5),
Q = 0.000132 x 110
Q = 0.0145 C
Therefore, the charge on each plate is 0.0145 C.

2. Given values are,
capacitance, C = 3.23 µF
area of plate, A = 6.35 mm^2
separation distance between two plates, d = ?
new capacitance, C2 = 5.63 mF
new dielectric constant, k2 = ?
voltage, V = 110 V
electric field between two plates, E = 8.99 x 10^4 N/C
working voltage, Vw = 63 V

a) The separation distance between two plates can be calculated as,
C1/C2 = d2/d1  …………….. (6)
where d1 and d2 are the initial and final separation distance, respectively.
Substituting the given values in equation (6),
3.23 x 10^-6/5.63 x 10^-3 = d2/d1
d2 = 5.63 x 10^-3 x (d1/3.23 x 10^-6)
Area of plate, A = 6.35 mm^2 = 6.35 x 10^-6 m^2
The capacitance can be expressed as,
C = εA/d
d = εA/C
where ε = permittivity of dielectric material.
Therefore, substituting the given values in above equation,
d1 = ε x 6.35 x 10^-6/3.23 x 10^-6
d1 = 12.50 ε
Substituting the value of d1 in equation (6),
5.63 x 10^-3 = d2/12.50 ε
d2 = 70.38 ε
The separation distance between two plates is 70.38 ε.

b) The new dielectric constant can be calculated as,
C2 = k2ε0A/d2
k2 = C2d2/ε0A
Substituting the given values in above equation,
k2 = 5.63 x 10^-3 x 70.38 ε/(8.854 x 10^-12 x 6.35 x 10^-6)
k2 = 3.95
Therefore, the new dielectric constant is 3.95.

c) The new voltage can be calculated as,
V2 = V1(C1/C2)
Substituting the given values in above equation,
V2 = 110(3.23 x 10^-6/5.63 x 10^-3)
V2 = 0.063 V
Therefore, the new voltage is 0.063 V.

d) The electric field can be expressed as,
E = V/d
d = V/E
Substituting the given values in above equation,
d = 63/8.99 x 10^4
d = 7.01 x 10^-4 m
The voltage, V = 110 V > working voltage, Vw = 63 V

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