The highest ever recorded temperature on earth was 136°F in the US and the lowest was − ° 129 F in Antarctica. What is the difference of these temperatures recorded on Earth?

The set of all strings accepted by M is an infinite decidable subset of L.

Every infinite Turing-recognizable language has an infinite decidable subset.

Let's prove this theorem.

We must know the properties of the Turing recognizable language before the proof. A language is considered Turing recognizable if a Turing machine M accepts all strings in the language, and either rejects or loops forever on all strings not in the language. We can define that any language is infinite if it contains infinite strings.

Similarly, the set of all strings in the language is infinite if the language is infinite.

Let us suppose that L is an infinite Turing-recognizable language over the alphabet Σ. It implies that there exists a Turing machine M that accepts all the strings in L. We need to consider the following facts to prove that every infinite Turing-recognizable language has an infinite decidable subset:

If a Turing machine accepts an infinite number of strings in a language L, then it accepts at least one infinite subset of the language.

Suppose that a Turing machine accepts a language L, then the set of all strings accepted by the Turing machine is decidable.

Now, let's construct a new Turing machine M′ that works in the following manner:

In the first step, M' simulates M on the input w.

In this step, M' generates the strings of Σ* in some order.

In this step, for each string generated in step 2, M' runs M on that string. If M accepts that string, then M' outputs the string.

Suppose that there are only finite strings of L that are accepted by M. It implies that M has an infinite loop on all other strings not in L.

since M′ generates the strings of Σ* in some order, M′ will eventually simulate M on the string w for which M has an infinite loop.

Therefore, M′ will be in an infinite loop and will never halt.

So, the set of all strings accepted by M is infinite. We can say that the set of all strings accepted by M is an infinite decidable subset of L.

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Complete question :

Stephanie has six identical gift boxes to wrap. Each box is a cube that measures 6 inches on each side. She would like to wrap them all using the same gift wrapping paper. The roll of wrapping paper she has is 30 inches wide and 10 feet long.

Answer:

Left over = 2292 in²

Step-by-step explanation:

Given that :

Gift boxes are identical ;

Each gift box is a cube with side length, s = 6 inches

Area of gift box, Surface area of a cube = 6s²

Area = 6(6²) = 6 * 36 = 216 in²

Area of one gift box = 216 in²

6 gift boxes will be : 216 in² * 6 = 1296 in²

Allowing 2 inches to cover for overlap in each box : 2 inches * 6 = 12 in²

Dimension of wrapping paper = 30 inches by 10 feets

Recall :

1 Feet = 12 inches

Hence ; dimension of wrapping paper becomes :

30 inches by (10*12) inches

30 inches by 120 inches

Area of wrapping paper = 30 * 120 = 3600 in²

Total area of paper - area of gifbox - area of overlap

(3600 - 1296 - 12) in²

= 2292 in²

Leftover = 2292 in²

The largest possible solution is x + y =w = 4

Now, According to the question:

Suppose that the sum of the squares of two complex numbers x and y is 7 and the sum of the cubes is 10.

Now, One way to solve this problem is by substitution. We have

\(x^{2} +y^2 = (x+y)^2+2xy=7\)

and,

\(x^3+y^3=(x+y)(x^2-xy+y^2)=(7-xy)(x +y)=10\)

Hence observe that we can write :

x +y = w and xy = z

This reduces the equations to \(w^2-2z =7\) and w(7 - z) =10

Because we want the largest possible w, let's find an expression for z in terms of w.

\(w^2-7 =2z\) => \(z = \frac{w^2-7}{2}\)

Substituting, \(w^3-21w+20=0\)

which factorizes as (w-1) (w+5) (w-4) = 0

Hence, The largest possible solution is x + y =w = 4

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Answer:Exact Form:  x = ± √ 41 − 7

Decimal Form:

x = − 0.59687576 … , − 13.40312423 …

Step-by-step explanation:Use the formula  

in order to create a new term. Solve for  x  by using this term tocompletethe square.

Exact Form:  x = ± √ 41 − 7

Decimal Form:

x = − 0.59687576 … , − 13.40312423 …

Step-by-step explanation:

The cube has SIX sides ....each has area   x * x

  total area =   6    *  x*x   =   216     cm^2

                         6x^2 = 216

                              x^2 = 36

                               x = 6 cm

Volume =   x * x * x = 216 cm^3

C. When there is no outlier, the mean is the appropriate measure of center.

When there are no outliers in a dataset, the mean is a good measure of center because it takes into account the values of all the data points. The median is also a good measure of center, but it may not be the best choice if there are extreme values or outliers in the dataset, as it can be influenced by those values. However, when there are no outliers, both the mean and the median are appropriate measures of center.

Option A is not true because the mean is not skewed in one direction when there is no outlier. Skewness refers to the shape of the distribution, and it can be affected by outliers, but not by the absence of outliers.

Option B is not true because the median is not skewed in one direction when there is no outlier. Skewness refers to the shape of the distribution, and the median is not affected by the shape of the distribution, but by the position of the values.

Option D is not true because the median can be used as the measure of center even when there is no outlier. It is a robust measure of center that is not influenced by extreme values.

\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{16\% of 5000}}{\left( \cfrac{16}{100} \right)5000}\implies 800\)

Answer:

Step-by-step explanation:

216

Answer:

85% of 19 = 16.15

Step-by-step explanation:

If P(A) = 0.7, P(B) = 0.8, and P (A or B) = 0.9 the value of P (A and B) will be 0.6.

P(A) is the probability of event A happening.

P(A) = 0.7

P(B) is the probability of event B happening.

P(B) = 0.8

P (A or B) is the probability of either A or B happening.

P (A or B) = 0.9

P (A and B) is the probability of both A and B happening.

P (A and B) =?

The formula to find the value of P (A and B) is,

P (A and B) = P(A) + P(B) - P (A or B)

P (A and B) = 0.7 + 0.8 - 0.9

P (A and B) = 1.5 - 0.9

P (A and B) = 0.6.

Therefore, the value of P (A and B) is 0.6.

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Answer:

The random variable X is the number of activations that occur in the 55 minute time period.

Step-by-step explanation:

The random variable X represents the number of occurrences of an event in the time interval of interest. The time interval of interest is the fixed time period for which the probability of an event is being sought. In this case, the time interval of interest is 55 minutes. The random variable X is the number of activations that occur in the 55 minute time period.

In the given Poisson Distribution, the random variable X represents the number of activation in 55 minutes. Hence, the 4th option is the right choice.

A Poisson distribution is a probability distribution used in statistics to illustrate how many times an event is expected to occur over a certain time period. It is, in other words, a count distribution. Poisson distributions are frequently used to analyze independent events that occur at a consistent rate during a specified time frame. It was named after Siméon Denis Poisson, a French mathematician.

The Poisson distribution is a discrete function, which means that the variable may only take values from a (possibly endless) list. To put it another way, the variable cannot accept all values in any continuous range. The variable in the Poisson distribution may only take whole integer values (0, 1, 2, 3, etc.), no fractions or decimals.

In the question, we are informed that Raymond has a motion detector light that gets activated an average of 15 times every 2 hours during the night.

We are asked what the random variable X represents, to find the probability that the motion detector light will be activated exactly 8 times in 55 minutes during the night using the Poisson distribution.

The formula for the Poisson Distribution is given as,

\(P(X = x) = e^{-\lambda}\frac{\lambda^x}{x!}\)

where e is the Euler's number, x is the number of occurrence, and λ is the expected value.

The term X is the variable over which the distribution is defined.

Thus, in the given Poisson Distribution, the random variable X represents the number of activation in 55 minutes. Hence, the 4th option is the right choice.

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Refer to the attachment for the complete question.

Answer:

45/58.4

Step-by-step explanation:

Answer: part 1: 45/54.8.

Part 2: 55.2

Step-by-step explanation:

Edge

(a) Hypotheses:

H0: The proportion of individuals who exercise at least 100 minutes per week is the same for people living in condos and people not living in condos.

Ha: The proportion of individuals who exercise at least 100 minutes per week differs between people living in condos and people not living in condos.

In this scenario, the parameter of interest is the proportion of individuals who exercise at least 100 minutes per week. The null hypothesis assumes that the proportion is the same for both groups, while the alternative hypothesis suggests that there is a difference.

To test the hypotheses, we can use a hypothesis test for the difference in proportions. We would collect data on the number of individuals in each group who exercise at least 100 minutes per week and calculate the sample proportions. Then, we can perform a hypothesis test using the appropriate statistical test (e.g., a z-test for proportions) to determine if the difference is statistically significant.

If the p-value from the hypothesis test is less than the significance level (e.g., 0.05), we would reject the null hypothesis and conclude that there is evidence of a difference in the proportion of individuals who exercise at least 100 minutes per week between people living in condos and people not living in condos.

(b) Hypotheses:

H0: There is no difference in the proportion of babies born prematurely between mothers who smoked during pregnancy and mothers who did not smoke during pregnancy.

Ha: The proportion of babies born prematurely is different between mothers who smoked during pregnancy and mothers who did not smoke during pregnancy.

In this scenario, the parameter of interest is the proportion of babies born prematurely. The null hypothesis assumes that there is no difference in the proportion of premature births, while the alternative hypothesis suggests that there is a difference.

To test the hypotheses, we can again use a hypothesis test for the difference in proportions. We would collect data on the number of babies born prematurely and the total number of babies in each group (smoking vs. non-smoking mothers). Then, we can perform a hypothesis test using an appropriate statistical test (e.g., a z-test for proportions) to determine if the difference is statistically significant.

If the p-value from the hypothesis test is less than the chosen significance level (e.g., 0.05), we would reject the null hypothesis and conclude that there is evidence of a difference in the proportion of babies born prematurely between mothers who smoked during pregnancy and mothers who did not smoke during pregnancy.

(c) Hypotheses:

H0: There is no association between seeing a Nintendo ad and the amount of spending on Nintendo products in the next 48 hours.

Ha: There is an association between seeing a Nintendo ad and the amount of spending on Nintendo products in the next 48 hours.

In this scenario, the parameter of interest is the association between seeing a Nintendo ad (exposure) and the amount of spending on Nintendo products (outcome) within the next 48 hours. The null hypothesis assumes no association, while the alternative hypothesis suggests an association.

To test the hypotheses, we can use a hypothesis test for independence or association between two categorical variables. We would collect data on whether users saw a Nintendo ad and their corresponding expenditures on Nintendo products. Then, we can perform a statistical test such as the chi-square test or Fisher's exact test to determine if there is a significant association between the variables.

If the p-value from the hypothesis test is less than the chosen significance level (e.g., 0.05), we would reject the null hypothesis and conclude that there is evidence of an association between seeing a Nint…

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We can deduce that the 103rd derivative of cos 2x will have a sine function with a coefficient of (-2)¹⁰³⁻¹ = -2¹⁰²

The given derivative can be found by observing the pattern that occurs when taking the first few derivatives. The derivative D103 represents the 103rd derivative. We start by finding the first few derivatives and look for a pattern.

Let's take the derivative of cos 2x multiple times:

D(cos 2x) = -2sin 2x

D²(cos 2x) = -4cos 2x

D³(cos 2x) = 8sin 2x

D⁴(cos 2x) = 16cos 2x

D⁵(cos 2x) = -32sin 2x

From these calculations, we can observe that the pattern alternates between sine and cosine functions and multiplies the coefficient by a power of 2. Specifically, the exponent of sin 2x is the power of 2 in the sequence of coefficients, while the exponent of cos 2x is the power of 2 minus 1.

Applying this pattern, we can deduce that the 103rd derivative of cos 2x will have a sine function with a coefficient of (-2)¹⁰³⁻¹ = -2¹⁰². Therefore, the derivative D103(cos 2x) is -2¹⁰² × sin 2x.

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With all given given conditions the time of death is in between 6:15 A.M. and 7:15 A.M.

We'll use the given formula: t = -10 ln(T - 70) / (98.6 - 70), where t is the time elapsed since death and T is the body temperature. We have two temperature readings, and we'll find the elapsed time for each.

1. At 9:00 A.M., the temperature was 85.7°F:
t = -10 ln(85.7 - 70) / (98.6 - 70)
t = -10 ln(15.7) / 28.6
t ≈ 2.65 hours

2. At 11:00 A.M., the temperature was 82.8°F:
t = -10 ln(82.8 - 70) / (98.6 - 70)
t = -10 ln(12.8) / 28.6
t ≈ 3.66 hours

Since the temperature readings were taken at 9:00 A.M. and 11:00 A.M., we need to subtract the elapsed time from those times to estimate the time of death.

1. 9:00 A.M. - 2.65 hours ≈ 6:15 A.M.
2. 11:00 A.M. - 3.66 hours ≈ 7:15 A.M.

Based on these estimations, the person likely died between 6:15 A.M. and 7:15 A.M.

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The answer would be 4.6 x 10^-5

Hello there! :)

Numbers in scientific notation look like this:

____x10^-

The coefficient must be between 1 and 10:

4.6x10^-

Now,the exponent is how many units we move the decimal place.

The exponent for this number is negative because the number is small.

We move the decimal point 5 times to the left.

Therefore, 0.000046 in scientific notation looks like so:

4.6x10^-5

Hope it helps.

~A lonely teen who helps others with a smile

-Grace :-)

Good luck.

The predicted Diabetes Risk Score can be obtained using the given regression equation. So, the correct answer is (B) 132.44.

Diabetes Risk Score = Constant + Age × 0.166 + Weight × 0.532

Plugging in the values for Age and Weight, we get:

Diabetes Risk Score = 1.78 + 34 × 0.166 + 235 × 0.532

Diabetes Risk Score = 1.78 + 5.644 + 125.02

Diabetes Risk Score = 132.44

Therefore, the predicted Diabetes Risk Score for someone who was 34 years old and weighed 235 pounds is 132.44.

So, the correct answer is (B) 132.44.

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Answer:

A system of linear equations is a collection of two or more linear equations, and a solution to a system of linear equations consists of values of each of the unknown variables in the system that satisfies all of its equations, or makes them true.

Answer:

(0, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Systems

y + 5x = 1

5y - x = 5

Step 2: Rewrite Systems

y + 5x = 1

Step 3: Redefine Systems

y = 1 - 5x

5y - x = 5

Step 4: Solve for x

Substitution

Step 5: Solve for y

Answer:

(-2) + (3-7)

(-1) * (-2)

EVALUATE THE EXPRESSION  

Step-by-step explanation:

HELP ME ONN THIS QUESTION PLSSSZ

Answer:

8 hours

Step-by-step explanation:

2x4 = 8

Based on the information provided, it can be concluded Mashen earns R111.11 per hour.

The rate refers to the amount of money Mashen earns per hour. To find the amount he earns per hour, we use the formula amount earned per month/hours worked per month, which would result in the rate per hour.

Here is an example:

Total earned: 5000

Total hours: 40

5000 / 40 = 25 per hour

Based on this formula, let's now calculate the rate per hour for Meshen as it follows:

Total earned / total hours = rate per hour

R20000 / 180= R111.11 per hour

Therefore, Mashen earns R111.11 per hour.

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Answer:

answer is d

Step-by-step explanation:

pretty ez

Answer: 11

Step-by-step explanation:

Complementary angles mean both angles sum 90°, then:

(3x + 2)° + 5x° = 90°

3x° + 2° + 5x° = 90°

8x° + 2° = 90°

8x° = 88°

x = 11

Confirmation:

(3x + 2)°                                        5x°

(3(11) + 2)°                                      5(11)x°

(33 + 2)°                                         55x°

35°

                      35° + 55° = 90°

Total number of seats that remain unsold are 168.

What is statistics?

The branch of mathematics dealing with data collection, organization, analysis, interpretation and presentation.

Let's start by defining some variables to represent the unknowns in the problem:

From the problem, we know that:

We also know that the total revenue collected is $34,650:

27x + 45y = 34650

Now we can substitute y = 0.5x from the second equation into the third equation and simplify:

27x + 45(0.5x) = 34650

27x + 22.5x = 34650

49.5x = 34650

x = 700

So there were 700 $30-seats and 350 $50-seats.

The number of sold $30-seats is 0.9(30x) = 567, and the number of sold $50-seats is 0.9(50y) = 315.

Therefore, the total number of seats sold is 882, and the number of unsold seats is:

1050 - 882 = 168

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Answer:

12

Based on the given conditions, formulate:: 72/90/15

Cross out the common factor: 72/6

Cross out the common factor: 12

Work Shown:

\(-\frac{5}{4} \div \frac{1}{4}\\\\-\frac{5}{4} \times \frac{4}{1}\\\\-\frac{5\times4}{4\times1}\\\\-\frac{5}{1}\\\\-5\)

Whenever you divide fractions, you flip the second fraction and multiply. In this case, the '4's cancel.

Answer:

B

Step-by-step explanation: