HELPPPPPPP
What did a study by Strayer and Johnston (2001) regarding the effects of attention on driving conclude?
A.
Attention is not affected as long as one is using a hands-free phone.
B.
Driving and talking with friends in the car increases the chance of an accident.
C.
Driving and listening to the radio increases the chance of missing traffic signals.
D.
Driving and talking on any type of cell phone increases the chance of missing traffic signals.
Answer:
D.
Driving and talking on any type of cell phone increases the chance of missing traffic signals.
Explanation:
correct on edge2021
Answer:
the answer is d thank me later
Explanation:
Which of the following describes the correct order of energy conversions necessary to form electricity from solar panels?
Solar Heat Kinetic → Electric
Solar- Kinetic Heat → Electric
Solar 1 Heat → Electric
O Solar ->Electric
Answer:
hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9
A car is stationary. It accelerates at 0.8 ms^2 for 10 s and then at 0.4 ms^2 for a further 10 s. Use the equations of motion to deduce the car's final displacement. You will have to split the journey into two parts, since the acceleration changes after 10 s.
Answer:
The final displacement of the car is 140 meters.
Explanation:
The final displacement of the car (\(s\)), in meters, is the sum of the change in displacement associated with each part of the journey, which is derived from the following kinematic formulas:
\(s = s_{1} + s_{2}\) (1)
\(s_{1} = \frac{1}{2}\cdot a_{1}\cdot t_{1}^{2}\) (2)
\(v_{o,2} = a_{1}\cdot t_{1}\) (3)
\(s_{2} = v_{o,2} + \frac{1}{2}\cdot a_{2}\cdot t_{2}^{2}\) (4)
Where:
\(s_{1}\) - Traveled distance of the first part, in meters.
\(s_{2}\) - Traveled distance of the second part, in meters.
\(a_{1}\) - Acceleration in the first part, in meters per square second.
\(a_{2}\) - Acceleration in the second part, in meters per square second.
\(v_{o,2}\) - Initial speed of the car in the second part, in meters per second.
\(t_{1}\) - Time taken in the first part, in seconds.
\(t_{2}\) - Time taken in the second part, in seconds.
If we know that \(a_{1} = 0.8\,\frac{m}{s^{2}}\), \(t_{1} = 10\,s\), \(a_{2} = 0.4\,\frac{m}{s^{2}}\) and \(t_{2} = 10\,s\), then the distance traveled by the car is:
By (2):
\(s_{1} = \frac{1}{2}\cdot \left(0.8\,\frac{m}{s^{2}} \right)\cdot(10\,s)^{2}\)
\(s_{1} = 40\,m\)
By (3):
\(v_{o,2} = \left(0.8\,\frac{m}{s^{2}} \right)\cdot (10\,s)\)
\(v_{o,2} = 8\,\frac{m}{s}\)
By (4):
\(s_{2} = \left(8\,\frac{m}{s} \right)\cdot (10\,s) + \frac{1}{2}\cdot \left(0.4\,\frac{m}{s^{2}} \right)\cdot (10\,s)^{2}\)
\(s_{2} = 100\,m\)
By (1):
\(s = 140\,m\)
The final displacement of the car is 140 meters.
A high diver dives off a platform and strikes the water 1.857 seconds later. Ignoring air resistance, how fast is he traveling as he strikes the water in m/s?
Answer:
The (vertical) speed of the driver as he strikes the water is approximately 18.22 m/s
Explanation:
From the parameters given in the question, we have;
The time after which the driver strikes the water after he drives off a platform, t = 1.857 s
Let 'v' represent the vertical speed of the driver
We can find the vertical speed of the vehicle as it strikes the water as follows;
v = u + g·t
Where;
v = The final vertical velocity of the driver
u = The initial vertical speed of the driver = 0 m/s
g = The acceleration due to gravity ≈ 9.81 m/s²
t = The time of motion = 1.857 seconds
Therefore, we have;
v = 0 + 9.81 m/s² × 1.857 s = 18.21717 m/s
Therefore;
The vertical speed of the driver as he strikes the water, v ≈ 18.22 m/s
Gravity's role in the motion of stars, planets, & solar systems
Answer: The sun's gravity pulls the planet toward the sun, which changes the straight line of direction into a curve. This keeps the planet moving in an orbit around the sun. Because of the sun's gravitational pull, all the planets in our solar system orbit around it.
A bow is drawn so that it has 40 J of potential energy. When fired, the arrow will have a kinetic energy of: Select one: O a. 80) o b. 20) O 0.60) O d. 40)
When a bow is drawn and has 40 J of potential energy, the arrow's kinetic energy when fired will be:
Your answer: d. 40 J
Explanation:
Potential energy is the energy that an object possesses due to its position, configuration, or state of being. It is stored energy that has the potential to do work in the future. The amount of potential energy that an object has depends on its position or configuration relative to other objects or systems. For example, a bow that is pulled back has potential energy that can be released as kinetic energy when it is released.
Kinetic energy, on the other hand, is the energy that an object possesses due to its motion. It is the energy that an object possesses because it is in motion and is able to do work by causing a change in another object's motion or position. The amount of kinetic energy that an object has depends on its mass and its velocity. For example, a moving car has kinetic energy that can be transferred to another object if it collides with it.
When the bow is drawn, it stores potential energy. When fired, this potential energy is converted into kinetic energy for the arrow. In an ideal situation with no energy loss, the arrow's kinetic energy will be equal to the bow's potential energy. Therefore, the arrow will have a kinetic energy of 40 J.
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Where would you expect to find volcanic mountain ranges and why?
Answer:
Sixty percent of all active volcanoes occur at the boundaries between tectonic plates. Most volcanoes are found along a belt, called the “Ring of Fire” that encircles the Pacific Ocean. Some volcanoes, like those that form the Hawaiian Islands, occur in the interior of plates at areas called “hot spots.”
Explanation:
Volcanoes are found around tectonic plates because the convection currents move the plates. Where convection currents diverge near the Earth's crust, plates move apart. Where convection currents converge, plates move towards each other, plates converge and the plates move together, also known as ridge push, therefore mountains and volcanoes are formed
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A metal spoon is put in a cup of hot tea and then put it into the mouth. The spoon is not very hot, but the tea is much hotter. Why?
a car is driven 1.5 kilometers west in 2 minutes. what is the velocity in m/s?
A 0. 013 kg rubber stopper is attached to a 0. 93 m length of string. The stopper is swung in a horizontal circle, making one revolution in 1. 18 s. Find the centripetal acceleration of the rubber stopper
The centripetal acceleration of the rubber stopper is 0.34 N. The explanation is as follows.
What is a circular motion?An object’s position relative to the center of a circle is given by the position vector, r. As the object moves, the length of the vector remains constant, but the direction changes. Velocity is displacement over time. So, displacement would be Δr. Recall that average velocity is Δd/Δt, so for circular motion
Given,
m = 13g
T = ?
r = 0.93m
Calculations:
\(a=4\pi ^{2} r/T\)
\(a=4(3.14)^{2} (0.93m) / (1.18s)^2=26m/s^{2}\)
T= ma= (0.013kg) (26 m/\(s^{2}\))
T = 0.34 N
* Note for force in N, mass must be in kg.
What is centrifugal Force?If forces come in pairs, is there an “outwardforce” causing the stopper to stay out there at the end of the string? When a car turns left sharply, is there a force causing a passenger to move toward the door? NO! Newton’s first law says an object in motion continues… This outward motion is simply the inertia of the object and this “centrifugal force” is FICTITIOUS!
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The bearing of grids of an AB alignment is 100º 22', while the magnetic declination is 8º30' E. What are the true azimuth, magnetic azimuth, and grid azimuth of this alignment?
The true azimuth of the AB alignment is 91º 52' (east of north), the magnetic azimuth is 100º 22' (east of north), and the grid azimuth is 108º 52' (east of north).
To find the true azimuth, magnetic azimuth, and grid azimuth of the AB alignment, we need to consider the magnetic declination. The magnetic declination indicates the angle between true north and magnetic north at a specific location. In this case, the magnetic declination is 8º 30' E, which means that the magnetic north is 8º 30' east of the true north.
To calculate the true azimuth, we subtract the magnetic declination from the grid azimuth. The grid azimuth is given as 100º 22', so subtracting the magnetic declination of 8º 30' E gives us a true azimuth of 91º 52' (east of north).
The magnetic azimuth remains the same as the grid azimuth, which is 100º 22' (east of north).
The grid azimuth is calculated by adding the magnetic declination to the true azimuth. Since the magnetic declination is east, we add it to the true azimuth. Adding 8º 30' E to the true azimuth of 91º 52' gives us a grid azimuth of 108º 52' (east of north).
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5. A car travels at a steady speed of 80kmh-1. How far will it travel in 900 seconds?
Answer:
below
Explanation:
3600 seconds in an hour
900 sec / 3600 sec/hr = .25 hr
80 km /hr * .25 hr = 20 km
Part C
Just like in the diagram, when Earth was primarily liquid, it separated into layers. What prediction can you make about the
densities of Earth's different layers?
When the Earth was primarily liquid, it separated into layers. The density of Earth's different layers may be predicted. For instance, it is assumed that the outermost layer, or crust, is less dense than the inner layers.
The Earth's crust is mostly composed of silicates (such as quartz, feldspar, and mica) and rocks, which are less dense than the mantle, core, or outer core.
The mantle is composed of solid rock, which is denser than the Earth's crust.
The core is the most dense layer, and it is composed of a liquid outer core and a solid inner core.
Most of the Earth's layers are composed of different types of rock and minerals.
The layers were formed from the molten material that cooled and solidified.
The Earth's layers are divided into four groups, or spheres, that represent different levels of density.
The lithosphere is the outermost layer, which includes the crust and upper mantle.
The asthenosphere is the soft layer beneath the lithosphere.
The mantle is a solid layer that surrounds the core.
The core is the Earth's central layer, consisting of a liquid outer core and a solid inner core.
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State fourth law of Thermodynamics
Answer: The dissipative component of evolution is in a direction of steepest entropy ascent
Explanation:
According to our definition, every non-equilibrium state of a system or local subsystem for which entropy is well defined must be equipped with a metric in state space with respect to which the irreversible component of its time evolution is in the direction of the steepest entropy ascent permissible under the conservation constraints. We derive (nonlinear) expansions of Onsager reciprocity and fluctuation-dissipation relations to the far-non-equilibrium world inside the rate-controlled constrained-equilibrium approximation to demonstrate the force of the fourth law (also known as the quasi-equilibrium approximation).
An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s. The total momentum is
Answer:
See Explanation
Explanation:
m1(v1) + m2(v2)
Opposite turns the plus to subtraction.
80(8) - 120(4.0)
60 - 480 = 160 kg m/s to the right
An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s. The total momentum is 160 kg m/s.
What is momentum?Momentum is a fundamental concept in physics that describes the amount of motion an object has. It is defined as the product of an object's mass and its velocity. Mathematically, momentum (p) is given by:
p = m × v
where p is the momentum, m is the object's mass, and v is its velocity.
The units of momentum are kilogram-meters per second (kg m/s) in the SI system of units. The direction of momentum is the same as the direction of the object's velocity.
Momentum is a conserved quantity, meaning that the total momentum of an isolated system (a system that does not interact with its surroundings) remains constant. This is known as the law of conservation of momentum, and it has many practical applications in physics and engineering. For example, it can be used to analyze collisions between objects, such as in sports or automobile accidents.
Here in the Question,
To find the total momentum of the two players, we first need to calculate the individual momentum of each player, and then add them up.
The momentum (p) of an object is given by the product of its mass (m) and velocity (v):
p = m × v
For the first player with a mass of 80 kg and a velocity of 8 m/s, the momentum is:
p1 = 80 kg × 8 m/s = 640 kg m/s
For the second player with a mass of 120 kg and a velocity of -4.0 m/s (negative because he is traveling in the opposite direction), the momentum is:
p2 = 120 kg × (-4.0 m/s) = -480 kg m/s
The negative sign in front of the momentum for the second player indicates that his momentum is in the opposite direction of the first player.
To find the total momentum, we add the individual momenta:
total momentum = p1 + p2
= 640 kg m/s - 480 kg m/s
= 160 kg m/s
Therefore, the total momentum of the two players is 160 kg m/s.
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Which of the following statements best describes why the mass of a bowling ball would not change if it were transported from Earth to the Moon?
Answer:
On Earth, the acceleration due to gravity is 9.8 m/s/s. ... In other words, you weigh more on Earth; you would weigh less on the moon. For instance, if you take a 10 kg bowling ball to the moon, it would still have a mass of 10 kg. However, its weight would be much less because the moon's gravity is relatively weak.
Explanation:
How is the crest of a transverse wave similar to the compressions on a longitudinal wave
Answer:
In a longitudinal wave, the crest and trough of a transverse wave correspond respectively to the compression, and the rarefaction.
Explanation:
Calculate the mechanical advantage if a machine allows you to move a 60 newton rock by only exerting 15 newtons of force.
Answer:
4 Newtons
Explanation:
I think it's 4 because mechanical advantage = output force/input forceSo, it would be 60/15, which is 4 newtonsAnswer:
4
Explanation:
1. For each of the compounds listed below, write down how many atoms of each element is in one molecule of the compound. a) Hydrogen chloride (HCI) b) Sulfur dioxide (SO₂) c) Ammonia (NH₂) d) Carbon monoxide (CO) 2. For each of the compounds in question 1, draw a model of one molecule of the compound.
1.
a) Hydrogen chloride (HCl) - 1 hydrogen atom, 1 chlorine atom
b) Sulfur dioxide (SO₂) - 1 sulfur atom, 2 oxygen atoms
c) Ammonia (NH₃) - 1 nitrogen atom, 3 hydrogen atoms
d) Carbon monoxide (CO) - 1 carbon atom, 1 oxygen atom
2.
a) Hydrogen chloride (HCl) :
H
|
Cl--C--
|
H
b) Sulfur dioxide (SO₂) :
O
//
O=S
\\
O
c) Ammonia (NH₃) :
H
|
H--N--H
|
H
d) Carbon monoxide (CO) :
O
//
C=O
V02 Zone 90-100% MHR; =BPM
The south celestial pole appears on your meridian at an altitude of 30 degrees in the south. Where are you?
a. Latitude = 30 degrees south
b. Latitude = 60 degrees north
c. Latitude = 30 degrees north
d. Latitude = 60 degrees south
e. The south pole
The Based on the given information, we know that the south celestial pole appears on your meridian, Additionally, we know that it appears at an altitude of 30 degrees in the south. the south celestial pole appears 30 degrees above the horizon when it crosses the meridian.
The celestial poles are points in the sky around which all celestial objects appear to rotate. The north celestial pole is located directly above the Earth's North Pole, and the south celestial pole is located directly above the Earth's South Pole. Therefore, if the south celestial pole appears at an altitude of 30 degrees in the south, we can conclude that the observer is located in the southern hemisphere. Option a is the only latitude listed that is in the southern hemisphere, so the answer is a. The observer is located at a latitude of 30 degrees south. This means that the observer is in a location in the southern hemisphere where the south celestial pole appears 30 degrees above the horizon when it crosses the meridian.
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The hog-nosed bat is the smallest mammal on Earth: it is about the same size as a bumblebee and has an average mass of 2.0 g. Suppose a hog-nosed bat with this mass flies at 2.0 m/s when it detects a bug with a mass of 0.20g flying directly toward it at 8.0 m/s. What fraction of the total kinetic energy
dissipated when it swallows the bug?
Given
\(m_1 = 2g\\\\m_2 = 0.2g\\\\v_1 = 2m/s\\\\v_2 = -8m/s\)
The expression for a perfectly inelastic collision,
\(m_1v_1 + m_2v_2 = (m_1+m_2)v_f\)
Therefore,
\(v_f = \frac{m_1v_1 + m_2v_2}{(m_1+m_2)} \\\\v_f = \frac{(2*2)+(0.2*-8)}{2+0.2}\\\\v_f = 1.09m/s\)
Since the bat and the bug fly towards each other, and after some time the bat swallows the bug, it is said to be a condition of perfectly inelastic collision.
The kinetic energy of the bat before it swallows the bug is,
\(KE_b = \frac{1}{2}m_1v_1^2\\\\KE_b = \frac{1}{2}2*2^2\\\\KE_b = 4gm^2/s^2\)
The kinetic energy of the bat after it swallows the bug is,
\(KE_f = \frac{1}{2}(m_1+m_2)v_f^2\\\\KE_f = \frac{1}{2}(2+0.2)1.09^2\\\\KE_f = 1.3gm^2/s^2\)
The total dissipation in the kinetic energy of the bat is calculated as,
\(\delta KE = KE_b - KE_f\\\\\delta KE = 4 - 1.3\\\\\delta KE = 2.7 gm^2/s^2\)
The fraction of the dissipated kinetic energy of the bat is calculated as,
\(d = \frac{\delta KE}{KE_b}\\\\d = \frac{2.7}{4}\\\\d = 0.67\)
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Which statement best describes what happens when oil and water are stirred together?.
a certain aircraft has a liftoff speed of 129 km/h. (a) what minimum constant acceleration does the aircraft require if it is to be airborne after a takeoff run of 204 m?
To determine the minimum constant acceleration required for the aircraft to become airborne after a takeoff run of 204 m, we can use the following kinematic equation:
v^2 = u^2 + as
Where:v is the final velocity (liftoff speed) in m/s.u is the initial velocity (zero in this case) in m/s.a is the acceleration in m/s^2.s is the distance traveled in meters.First, we need to convert the liftoff speed from km/h to m/s:
129 km/h * (1000 m / 1 km) * (1 h / 3600 s) = 35.83 m/s
Now, we can rearrange the kinematic equation to solve for the acceleration:
a = (v^2 - u^2) / (2s)a = (35.83 m/s)^2 / (2 * 204 m)a ≈ 31.51 m/s^2
Therefore, the minimum constant acceleration required for the aircraft to become airborne after a takeoff run of 204 m is approximately 31.51 m/s^2.
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Which of the technologies could mostly like be found in a wearhouse
What is unusual about the behavior of water below the temperature of 4degree C? a. Within the range of 0 degree C to 4 degree C water contracts when the temperature decreases, whereas most substances expand. b. Within the range of 0 degree C to 4 degree C the specific heat of water is halved when the temperature decreases, whereas the specific heat of most substances is doubled. c. Within the range of 0 degree C to 4 degree C water expands when the temperature decreases, whereas most substances contract. d. Within the range of 0 degree C to 4 degree C the specific heat of water doubles when the temperature decreases, whereas the specific heat of most substances is halved.
The correct option is a. Within the range of 0 degree C to 4 degree C, water contracts when the temperature decreases, whereas most substances expand.
This property of water has important implications for the behavior of lakes and oceans in cold climates and temperature, as the contraction of water as it cools can cause it to sink to the bottom, which can in turn affect the circulation and mixing of water in these bodies.
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Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.
The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.
The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].
Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.
Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).
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What is the size and position of an image formed by a plane mirror?1) same size, closer to the mirror2) same size, same distance away from the mirror3) enlarged, closer to the mirror4) reduced, farther from the mirror
Answer:
2) same size, same distance away from the mirror
Explanation:
The image formed by a plane mirror has the same size and it is at the same distance of the object. It is also reversed from left to right. So, the size and position of an image formed by a plane mirror are
2) same size, the same distance away from the mirror
It takes Josh 8 seconds to slow down from 39 m/s to 21 m/s. Calculate his acceleration
a: acceleration
Δv: change in velocity
t: time
a = Δv/t = (21-39)/8 = -18/8 m/s^2 = -2.25 m/s^2
Which nutrient is easily broken down and converted to glucose for energy use in the body?
Answer:
Explanation:
The body uses three main nutrients to function— carbohydrate, protein, and fat. These nutrients are digested into simpler compounds. Carbohydrates are used for energy (glucose). Fats are used for energy after they are broken into fatty acids.
Answer:
its carbohydrates she didnt list the answer i did and i was the one asking the question well theirs the answer had to figure it out my self
Explanation: