the following equation uses a numbering system that is not decimal, hex or binary. what is the "base?" hint, try using trial and error. 235? 32? = 311?

Answer:

x=3

Step-by-step explanation:

The line of reflection would be at x=3. It’s like a mirror.  The reflection is backward, but the same distance from the line of reflection, so the line needs to be halfway between the two shapes.  Since C is at 4 and C’ is at 2, the line of reflection has to be at 3.

To construct a Deterministic Finite Accepted M such that L(M) = L(G), the language generated by grammar G = ({S, A, B}, {a, b}, S , {S -> abS, S -> A, A -> baB, B -> aA, B -> bb} ), the following steps should be followed:

Step 1: Eliminate the Null productions from the grammar by removing productions containing S. The grammar, after removing null production, becomes as follows.{S -> abS, S -> A, A -> baB, B -> aA, B -> bb}

Step 2: Eliminate the unit productions. The grammar is as follows. {S -> abS, S -> baB, S -> bb, A -> baB, B -> aA, B -> bb}

Step 3: Now we will convert the given grammar to an equivalent DFA by removing the left recursion. By removing the left recursion, we get the following productions. {S -> abS | baB | bb, A -> baB, B -> aA | bb}

Step 4: Draw the state diagram for the DFA using the following rules: State diagram for L(G) DFA 1. The start state is the initial state of the DFA. 2. The final state is the final state of the DFA. 3. Label the edges with symbols on which transitions are made. 4. A table for the transition function is created. The table for the transition function of L(G) DFA is given below:{Q, a} -> P{Q, b} -> R{P, a} -> R{P, b} -> Q{R, a} -> Q{R, b} -> R

Step 5: Construct the DFA using the state diagram and transition function. The DFA for the given language is shown below. The starting state is shown in green and the final state is shown in blue. DFA for L(G) -> ({Q, P, R}, {a, b}, Q, {Q, P}) Where, Q is the starting state P is the first intermediate state R is the second intermediate state.

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Answer:

(x−1)(x+5)

Step-by-step explanation:

Answer:

Step-by-step explanation:

x^2 + 4x - 5

(x + 5)(x - 1)

Answer:

13 1/3 mph

Step-by-step explanation:

If running 1 1/3 miles takes him 1/10 hour, 1 1/3 * 10 will be his mph

As a single price monopolist, the firm will produce the quantity where marginal revenue equals marginal cost. This quantity will be lower than the competitive equilibrium quantity, leading to a higher price for consumers and reduced output in the market.

As a single price monopolist, the firm faces a downward-sloping demand curve for its product. To maximize profits, the monopolist will choose the quantity where marginal revenue (MR) equals marginal cost (MC). However, since the monopolist cannot price discriminate, it must charge the same price to all consumers. In a perfectly competitive market, the price is equal to the marginal cost, and the quantity produced is determined by the intersection of the demand and supply curves. However, as a monopolist, the firm restricts output to achieve higher prices and maximize its profits. The monopolist's marginal revenue curve lies below the demand curve, reflecting the fact that it can only increase output by lowering the price for all units sold. As a result, the marginal revenue curve has a steeper slope than the demand curve. The quantity at which MR equals MC will be lower than the competitive equilibrium quantity. Therefore, as a single price monopolist, the firm will produce a quantity that is lower than the competitive equilibrium quantity, leading to higher prices for consumers and reduced output in the market.

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Answer:

x=2, y=1

Step-by-step explanation:

Add:

2x+4y=8

+10x-4y=16

------------------

12x=24

Divide by 12 on both sides:

x=2

Substitute x with 2 on either 2x+4y=8 or 10x-4y=16 it doesn't matter it will result in the same answer.

(I will do both of them to prove it but you only need to replace x with one of the equation)

For 2x+4y=8

2(2)+4y=8

4+4y=8

Subtract 4 on both sides

-4+4+4y=8-4

4y=4

Divide 4 on both sides:

y=1

For 10x-4y=16

10(2)-4y=16

20-4y=16

-20+20-4y=16-20

-4y=-4

Divide -4 on both sides:

y=1

The answer for both 2x + 4y = 8 and 10x – 4y = 16 are the same showing that it doesn't matter which equation you replace the number with it will still result you in the same answer

Hope this helps!

Answer:

y = 3x + 2 (the second choice)

Step-by-step explanation:

perpendicular means the negative reciprocal of x

x is -1/3

so a perpendicular line would have

3x

number next to the x is the slope which is

m

then use the point slope form formula

y - y1 = m (x - x1) with (1,5)

m is the slope

y - 5 = 3 (x - 1)

y - 5 = 3x - 3

y = 3x + 2

Answer:

AGE should be 35

Step-by-step explanation:

same as DGB

The economic order quantity is approximately 355 units, which corresponds to option D) 355 units.

To find the economic order quantity (EOQ), we can use the following formula:

EOQ = sqrt((2 * Annual Demand * Fixed Ordering Cost) / Carrying Cost per Unit)

Given information:

Annual Demand = 3,000 units

Fixed Ordering Cost = $30

Carrying Cost per Unit = $1.43

Substituting the values into the formula:

EOQ = sqrt((2 * 3,000 * 30) / 1.43)

EOQ = sqrt(180,000 / 1.43)

EOQ = sqrt(125,874.125)

EOQ ≈ 354.91

Rounding the EOQ to the nearest whole number, we get:

EOQ ≈ 355 units

Therefore, the economic order quantity is approximately 355 units, which corresponds to option D) 355 units.

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Answer:

B is the correct answer

Step-by-step explanation:

Coefficient is - 5 and constant is 2

Answer:

\( - 5x + 2 \\ coefficient = - 5 \\ constant = 2 \\ thank \: you\)

Answer:

d

Step-by-step explanation:

the ratio of height : shadow of statue is 15 : 20 = 3 : 4

the ratio of height : shadow of person will also be 3 : 4

jet height of person be h , then

\(\frac{h}{4}\) = \(\frac{3}{4}\) ( cross- multiply )

4h = 12 ( divide both sides by 4 )

h = 3

then the person is 3 feet tall

Answer:

d) 3 feet

Step-by-step explanation:

Answer:

H (13, -16)

Step-by-step explanation:

\(\boxed{\begin{minipage}{7.4 cm}\underline{Midpoint between two points}\\\\Midpoint $=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the endpoints.\\\end{minipage}}\)

Given:

Substitute the given endpoint G and midpoint M into the midpoint formula:

\(\implies M=\left(\dfrac{x_H+x_G}{2},\dfrac{y_H+y_G}{2}\right)\)

\(\implies (3, 4)=\left(\dfrac{x_H-7}{2},\dfrac{y_H+24}{2}\right)\)

x-value of endpoint H:

\(\implies 3=\dfrac{x_H-7}{2}\)

\(\implies 6=x_H-7\)

\(\implies x_H=13\)

y-value of endpoint H:

\(\implies 4=\dfrac{y_H+24}{2}\)

\(\implies8=y_H+24\)

\(\implies y_H=-16\)

Therefore, the coordinates of endpoint H are:

Answer: 13 -16

Step-by-step explanation: Edge 2023

The transformation that's illustrated in the diagram is translation.

It should be noted that transformation simply means the manipulation of that moves a shape from a space to another.

In this case, the transformation that's illustrated in the diagram is translation. This is the sliding of try shape across certain number of spaces.

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The height of Jeremy is 159 cm.

To find the height of Jeremy:

So,

Then, Jeremy = 135 + 24 = 159 cm.

Therefore, the height of Jeremy is 159 cm.

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Answer:

7 jshdbnskskslaksnbfbfje

Alex has $15.78 and Rick has $12.15 money.

According to the question,

We have the following information:

Alex had $3.63 more than Rick. Together they had $27.93.

Let's take the money Rick has to be $x.

Now, we have the following expression for the money Alex has:

3.63+x

Now, we have:

x+3.63+x = 27.93

2x+3.63 = 27.93

Subtracting 3.63 from both the sides:

2x = 27.93-3.63

2x = 24.3

Dividing by 2 on both the sides:

x = 24.3/2

x = $12.15

So, Rick has $12.15.

Now, the money Alex has:

3.63+12.15

$15.78

Hence, Alex has $15.78 and Rick has $12.15 money.

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a. To show that the area of region R is infinite, we can calculate the definite integral of the function y = 1 from x = 1 to x = ∞:

∫[1,∞] 1 dx.

Since this integral is improper, we need to take the limit as the upper bound approaches infinity:

lim (b→∞) ∫[1,b] 1 dx.

Evaluating the integral, we get:

lim (b→∞) [x] from 1 to b.

Taking the limit as b approaches infinity, we have:

lim (b→∞) (b - 1).

Since the limit diverges to infinity, the area of region R is infinite.

b. To find the volume of the solid generated by rotating region R around the x-axis, we can use an improper integral:

V = π ∫[1,∞] (1)^2 dx.

Again, since this integral is improper, we take the limit as the upper bound approaches infinity:

V = π lim (b→∞) ∫[1,b] (1)^2 dx.

Simplifying the integral, we get:

V = π lim (b→∞) [x] from 1 to b.

Taking the limit as b approaches infinity, we have:

V = π lim (b→∞) (b - 1).

Since the limit diverges to infinity, the volume of the solid generated by rotating region R around the x-axis is also infinite.

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Answer:

I need help on this to anyone please

Answer:

840 minutes

Step-by-step explanation:

We solve this question using the LCM Method

Find and list multiples of each number of minutes which is given in the quest as 140, 210 and 280 minutes until the first common multiple is found. This is the lowest common multiple.

Multiples of 140:

140, 280, 420, 560, 700, 840, 980, 1120

Multiples of 210:

210, 420, 630, 840, 1050, 1260

Multiples of 280:

280, 560, 840, 1120, 1400

Therefore,

LCM(140, 210, 280) = 840

Therefore, they would have to wait after their first break together to get together again after 840 minutes

Answer:

Since there are 57 varieties of juice and we can choose any number of each variety, we have 57 choices for each of the 6 cans we need to select. Therefore, the total number of ways to select 6 cans of juice is:

57 x 57 x 57 x 57 x 57 x 57 = 57^6

This can be calculated as:

57^6 = (3 x 19)^6 = 3^6 x 19^6 = 729 x 47,287,681

So there are 729 x 47,287,681 = 34,369,561,449 ways to select 6 cans of juice.

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Answer:  The two correct equations are:

A) 1/8 (x+16) = 76/8 (where x=Food Only)

C) x = 60 (where x=Food Only)

Step-by-step explanation:

Pick TWO that describe the situation (not necessarily solve):

A) 1/8 (x+16) = 76/8 (where x=Food Only)

B) 1/8 (x+16) = 76 (where x=Food Only)

C) x = 60 (where x=Food Only)

D) x = 60 (where x=Food + TIP)

E) 8 (x+16) = 76 (where x=Food Only)

Check Equation for Option A:

1/8 (x+16) = 76/8

1/8x + 16/8 = 76/8

Multiply by 8:

x + 16 = 76

Subtract 64 from both sides:

x = 76 - 16

x = 60 (Correct x=Food Only)

Check Equation for Option C:

x=60 (Correct x=Food Only)

Answer: 4

Step-by-step explanation:

Answer:75 mph

Step-by-step explanation:

48630 is large should the sample be if the margin of error is to be less than $4 .

What does the term "margin of error" mean?

Margin of Error  = Z*Stdev/sqrt(n)

4 <= 0.90* 33/sqrt(n)

n >= (0.90* 33/2)^4 = 48630.17 OR 48630

So, n should be atleast 48630 so that margin of error is within $4

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The probability that Juliana will take jazz on Saturday morning based on the decision tree given is 3%.

The probability that jazz is taken is:

= 1 - Probability of ballet

= 1 - 70%

= 30%

The probability that if jazz is taken, it will be taken on Wednesday is:

= Probability that jazz is taken on Wednesday night / Probability that Jazz is taken

= 27% / 30%

= 90%

The probability that Jazz is taken on Saturday morning is therefore:

= Probability that jazz is taken x (1 - Probability of Wednesday night)

= 0.3 x ( 1 - 90%)

= 3%

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The natural breaks, quantile, and equal interval classification schemes are methods used to categorize data for the purpose of creating thematic maps. Each scheme has its own approach and considerations: Natural Breaks, Quantile, Equal Interval.

Natural Breaks (Jenks): This classification scheme aims to identify natural groupings or breakpoints in the data. It seeks to minimize the variance within each group while maximizing the variance between groups. Natural breaks are determined by analyzing the distribution of the data and identifying points where significant gaps or changes occur. This method is useful for data that exhibits distinct clusters or patterns.

Quantile (Equal Count): The quantile classification scheme divides the data into equal-sized classes based on the number of data values. It ensures that an equal number of observations fall into each class. This approach is beneficial when the goal is to have an equal representation of data points in each category. Quantiles are useful for data that is evenly distributed and when maintaining an equal sample size in each class is important.

Equal Interval: In the equal interval classification scheme, the range of the data is divided into equal intervals, and data values are assigned to the corresponding interval. This method is straightforward and creates classes of equal width. It is useful when the range of values is important to represent accurately. However, it may not account for data distribution or variations in density.

In summary, the natural breaks scheme focuses on identifying natural groupings, the quantile scheme ensures an equal representation of data in each class, and the equal interval scheme creates classes of equal width based on the range of values. The choice of classification scheme depends on the nature of the data and the desired representation in the thematic map.

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False. The x86-64 bit architecture utilizes the full 64 bits for representing virtual address space, not just 48 bits.

The x86-64 bit architecture, also known as x64 or AMD64, extends the 32-bit x86 architecture to support 64-bit computing. One of the major advantages of this architecture is its ability to access a significantly larger virtual address space compared to its 32-bit predecessor. In x86-64, the virtual address space is indeed 64 bits wide, allowing for a theoretical capacity of 2^64 bytes, which is an enormous amount of memory.

The misconception that only 48 bits are used for representing the virtual address space may arise from the fact that current x86-64 implementations typically limit the practical addressable space to 48 bits. This is known as the "canonical address space" and allows for 256 terabytes of addressable memory. The remaining 16 bits are reserved for future expansion and are not utilized in most current systems. However, the full 64-bit address space is still available in the architecture and can be used if needed in future hardware implementations or specialized applications.

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The interval of convergence is (-1/2 , 1/2) .

Given,

f(x) = 1/1+4x²

Here,

f(x) = 1/1+4x²

=Σ\((4x^{2} )^{n}\)

n varies from 0 to infinity .

| (4x²)| < 1

So,

f(x) = 1/1 +  4x² = Σ\((4x^{2} )^{n}\)

f(x) =  1/1 +  4x² = Σ \(4^{n}\) \(x^{2n}\)

with |x²| < 1/4

-1/2 < x < 1/2

Thus the interval of convergence is (-1/2 , 1/2) .

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