The Excel function, RAND() generates a random number from
In the Sanotronics example, suppose director labor cost is $46,
parts cost is $95 and the 1st year demand is 10,000. What is the
profit value?
The Excel function, RAND() generates a random number from a normal distribution a uniform distribution a discrete distribution Question 2 (1 point) In Excel's IF function, the second argument is condi

\(\Huge \boxed{\mathfrak {ANSWER }}\)

\(\large \boldsymbol {} \displaystyle \frac{1}{5-\sqrt{2} } \cdot \frac{5+\sqrt{2} }{5+\sqrt{2} } =\frac{5+\sqrt{2} }{(5)^2-(\sqrt{2)}^2 } =\boxed{\frac{5+\sqrt{2} }{23} }\)

The function you seek to minimize is

()=3‾√4(3)2+(13−4)2

f

(

x

)

=

3

4

(

x

3

)

2

+

(

13

−

x

4

)

2

Then

′()=3‾√18−13−8=(3‾√18+18)−138

f

′

(

x

)

=

3

x

18

−

13

−

x

8

=

(

3

18

+

1

8

)

x

−

13

8

Note that ″()>0

f

″

(

x

)

>

0

so that the critical point at ′()=0

f

′

(

x

)

=

0

will be a minimum. The critical point is at

=1179+43‾√≈7.345m

x

=

117

9

+

4

3

≈

7.345

m

So that the amount used for the square will be 13−

13

−

x

, or

13−=524+33‾√≈5.655m

To use the normal approximation for a test of two proportions, n1 p1, n1 (1 - p1), n2 p2, and n2 (1 - p2) must all be greater than or equal to 5.

This is because the normal distribution assumes that the sample size is large enough to approximate the binomial distribution, and the rule of thumb is that each cell (n1 p1, n1 (1 - p1), n2 p2, and n2 (1 - p2)) should have at least 5 expected counts. If any of these cells have fewer than 5 expected counts, then the normal approximation is not reliable and a more appropriate test should be used. It is important to note that this is just a rule of thumb, and other factors such as the size of the effect and the desired level of significance should also be considered when deciding on a statistical test.

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Answer: 40

Step-by-step explanation: 50x0.8=40

Okay, maybe im wrong? But i dont see how its 4 thats more than half.

Rodger can do 46 pushups.

50 * 0.92 = 46

Edit: To better clarify, 0.92 is from 1.00 - 0.08.  

... 8 percent fewer than 100 percent is 92 percent; 1.00 - 0.08 = 0.92

Keep in mind that:

1.00 = 100%

0.08 = 8%

0.92 = 92%

After finding this you may multiply 50 * 0.92 to get 46.

Answer:

12 inches.

Step-by-step explanation:

You have to use the pythagorean formula. The measurements you stated form a right angle. Therefore, a^2 + b^2 = c^2. In this equation, we know c=13, and b=5. So therefore c^2 - b^2 = 144. We have to solve for a, so square root 144 to get 12.

Answer:12 in

Step-by-step explanation:

Answer:

B.

Step-by-step explanation:

C=3.14D

Circumference is equal to pi multiplied by the diameter, so 50 times 3.14 is equal to 157. 157 is closest to 160.

Answer:

B

Step-by-step explanation:

the actual circumference is 157.08 but it asks you to pick the closest one, which is 160. hope this helps!

Answer:

(2, –3) is a solution to the system of linear equations.

Step-by-step explanation:

Given: Equations:

3x - y = 9 --------(1),

4x + y = 5 --------(2),

Add Equation (1) + Equation (2),

3x + 4x = 9 + 5

7x = 14  ( Combine like terms )

x = 2   ( Divide both sides by 7 ),

From equation 1:

3(2) - y = 9

6 - y = 9

-y = 9 - 6    ( Subtraction 6 on both sides )

-y = 3

y = - 3     ( Multiplying -1 on both sides )

Given:

The graph of \(y = ax^2+c\) contains the point (2, 14).

To find:

The point which lies on the graph of \(y = a(x-2)^2+c\).

Solution:

Consider the given equations are

\(y_1 = ax^2+c\)     ...(i)

\(y_2 = a(x-2)^2+c\)      ...(ii)

The translation is defined as

\(g(x)=f(x+a)\)

where, a is horizontal shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

From equation (i) and (ii), it is clear that a=-2. So, graph of \(y = ax^2+c\) shifts 2 units right to get the graph of \(y = a(x-2)^2+c\).

It means each point on \(y = ax^2+c\) shifts 2 units right.

\((x,y)\to (x+2,y)\)

(2, 14) lies on \(y = ax^2+c\).

\((2,14)\to (2+2,14)\)

\((2,14)\to (4,14)\)

Therefore, (4,14)  must be lies on \(y = a(x-2)^2+c\).

Answer:

x³ + 11x² + 18x

Step-by-step explanation:

(x² + 2x)(x + 9)

Step 1: Distribute x²+2x into x + 9.

x³ + 2x² + 9x² + 18x

Step 2: Combine like terms.

x³ + 11x² + 18x

The area of this rectangle is x³ + 11x² + 18x.

Answer:

Area= height x width = (x + 9) (x^2 + 2x) = x^3 + 2x^2 + 9x^2 + 18x = x^3 + 11 x^2 + 18x

Step-by-step explanation:

The height is (x + 9) and the width is (x^2 + 2x) and the the area of the rectangle is equal to: Area= height x width = (x + 9) (x^2 + 2x) = x^3 + 2x^2 + 9x^2 + 18x = x^3 + 11 x^2 + 18x

The first error that Holden made in his proof is option (B) Holden only established some of the necessary conditions for a congruence criterion.

Congruence of triangles is a relationship between two triangles where they have exactly the same shape and size. When two triangles are congruent, all their corresponding sides and angles are equal in measure.

Holden's proof contains an error because he only established the congruence of one pair of corresponding sides in the two triangles. However, to prove the congruence of two triangles, all corresponding sides and angles must be shown to be congruent using a congruence criterion such as SSS or SAS. Therefore, Holden's proof is incomplete and does not provide sufficient evidence to conclude that the two triangles are congruent.

Therefore, the correct option is (B) Holden only established some of the necessary conditions for a congruence criterion.

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The given question is incomplete, the complete question is:

Holden tried to prove that △FGH≅△FIH

1 IH≅GH

Given

2 FH≅FH

Line segments are congruent to themselves.

3 △FGH≅△FIH

Side-side congruence

What is the first error Holden made in his proof?

(A) Holden used an invalid reason to justify the congruence of a pair of sides or angles.

(B) Holden only established some of the necessary conditions for a congruence criterion.

(C) Holden established all necessary conditions, but then used an inappropriate congruence criterion.

(D) Holden used a criterion that does not guarantee congruence.

Answer:

40.21 m is the circle's cirumference.

Answer:

9.4 is your answer, i need to write more and i dont know why

To find the joint probability distribution function f(u, v) of two random variables U and V, follow these steps:
1. Identify the support: Determine the range of values that the random variables U and V can take. The support is the set of all possible (u, v) pairs for which f(u, v) > 0.
2. Define the joint probability function: Using the support, create an equation that describes the probability of each (u, v) pair occurring. The equation should satisfy the conditions of a valid probability distribution function. That is, f(u, v) ≥ 0 for all (u, v) pairs in the support, and the sum (for discrete variables) or integral (for continuous variables) of f(u, v) over the entire support should be equal to 1.
3. Calculate probabilities: Use the defined joint probability distribution function f(u, v) to compute the probabilities of events involving U and V.

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The value of side length w is 13.75 .

Given right angled triangle,

Perpendicular = w

Hypotenuse = 17

Angle of triangle = 54°

So,

According to the trigonometric ratios,

tanФ = p/b

cosФ = b/h

sinФ = p/h

By using sinФ,

sinФ = p/h

sin 54° =  w/ 17

0.809 = w/17

w = 13.75 .

Thus after correction w will be 13.75

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Answer:

2x(x + 3)

Step-by-step explanation:

2x² + 6x ← factor out 2x from each term

= 2x(x + 3)

Answer:

∠1 = 56

Step-by-step explanation:

To find ∠1 we need to

∠1 + ∠2 = ∠ABD

∠1 + 17 = 75

∠1 = 75 -17

∠1 = 56

Answer:

c

Step-by-step explanation:

Here is the complete question

Samantha invested $660 into an account that paid 3.5% interest compounded annually. Samantha did not make any additional deposits or withdrawals

What is the total amount of interest paid by this investment at the end of five years?

A- $115.50

B-$783.87

C-$123.87

$2,755.50

Interst = future value - amount invested

amount invested = $660

Future value = A( 1 + r)^n

FV = Future value  

P = Present value  

R = interest rate  

N = number of years  

$660 x ( 1.035)^5 = $783.87

Interest = $783.87 - $660 = $123.87

$

The statement would no longer be true if you did not flip the signs.

Example: 1 < x < 2 multiplied by (-1) equals -2 < x < -1, because you can't have a number that is greater than -1, and less than -2 at the same time.

Answer:

24 tiles^2

Step-by-step explanation:

Length = 6

width = 4

Area = Length x width

        = 6 x 4

        = 24 tiles^2

Adjust the parameters as needed, such as the step size (h) and the final x-value (xn), and run the code to obtain the solution for y(x).

The resulting plot will show the solution curve.

To solve the given set of differential equations using the Runge-Kutta method in MATLAB, we need to convert the second-order differential equations into a system of first-order differential equations.

Let's define new variables:

y = y(x)

z = dz/dx

Now, we have the following system of first-order differential equations:

dy/dx = z (1)

dz/dx = -k/(2y) (2)

To apply the Runge-Kutta method, we need to discretize the domain of x. Let's assume a step size h for the discretization. We'll start at x = 0 and proceed until x = infinite.

The general formula for the fourth-order Runge-Kutta method is as follows:

k₁ = h f(xn, yn, zn)

k₂ = h f(xn + h/2, yn + k₁/2, zn + l₁/2)

k₃ = h f(xn + h/2, yn + k₂/2, zn + l₂/2)

k₄ = h f(xn + h, yn + k₃, zn + l₃)

yn+1 = yn + (k₁ + 2k₂ + 2k₃ + k₄)/6

zn+1 = zn + (l₁ + 2l₂ + 2l₃ + l₄)/6

where f(x, y, z) represents the right-hand side of equations (1) and (2).

We can now write the MATLAB code to solve the differential equations using the Runge-Kutta method:

function [x, y, z] = rungeKuttaMethod()

   % Parameters

   k = 1;              % Constant k

   h = 0.01;           % Step size

   x0 = 0;             % Initial x

   xn = 10;            % Final x (adjust as needed)

   n = (xn - x0) / h;  % Number of steps

   % Initialize arrays

   x = zeros(1, n+1);

   y = zeros(1, n+1);

   z = zeros(1, n+1);

   % Initial conditions

   x(1) = x0;

   y(1) = 0;

   z(1) = 0;

   % Runge-Kutta method

   for i = 1:n

       k1 = h * f(x(i), y(i), z(i));

       l1 = h * g(x(i), y(i));

       k2 = h * f(x(i) + h/2, y(i) + k1/2, z(i) + l1/2);

       l2 = h * g(x(i) + h/2, y(i) + k1/2);

       k3 = h * f(x(i) + h/2, y(i) + k2/2, z(i) + l2/2);

       l3 = h * g(x(i) + h/2, y(i) + k2/2);

       k4 = h * f(x(i) + h, y(i) + k3, z(i) + l3);

       l4 = h * g(x(i) + h, y(i) + k3);

       y(i+1) = y(i) + (k1 + 2*k2 + 2*k3 + k4) / 6;

       z(i+1) = z(i) + (l1 + 2*l2 + 2*l3 + l4) / 6;

       x(i+1) = x(i) + h;

   end

   % Plotting

   plot(x, y);

   xlabel('x');

   ylabel('y');

   title('Solution y(x)');

end

function dydx = f(x, y, z)

   dydx = z;

end

function dzdx = g(x, y)

   dzdx = -k / (2*y);

end

% Call the function to solve the differential equations

[x, y, z] = rungeKuttaMethod();

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The solution for this system of equation will be \(x=4, y=-3.\)

We will solve the given system of equation by the method of substitution. Now we label the equations as  \(2x+y=5....(i)\) and \(-3x-5y=3....(ii)\).

Now from equation \((i)\) we will find the value of \(y\) which is \(5-2x\). Then we will substitute the value of \(y\) in equation \((ii)\).

So, \(-3x-5\times(5-2x)=3\)

⇒ \(-3x-25+10x=3\)

⇒ \(7x-25=3\)

⇒ \(7x=28\)

\(\therefore x =\frac{28}{7}=4....(iii)\)

Now we will take the value of \(x\) from equation equation \((iii)\) and substitute in equation \((i)\) to get the value of \(y\).

So, \((2 \times 4)+y=5\)

⇒ \(8+y=5\)

⇒ \(y=8-5\)

\(\therefore y=3\)

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All intermediate P^-1P terms equal the identity matrix (I), and they cancel each other out: A^100 = PD^100P^-1 So, the statement is true.

To determine if this statement is true or false. Let's proceed step by step:

1. We are given A = PDP^-1, where A, P, and D are square matrices, and D is a diagonal matrix.

2. We need to find A^100, which means A multiplied by itself 100 times. Using the given equation, we can compute A^100 as follows: A^100 = (PDP^-1)^100

Now, we can use the property (AB)^n = A^nB^n for diagonalizable matrices: A^100 = (PDP^-1)^100 = PD^100P^-100

Since D is a diagonal matrix, it is easy to compute its power:

D^100 = diag(d1^100, d2^100, ..., dn^100)

We know that the product of inverse matrices equals the identity matrix: P^-1P = I

Therefore, we can rewrite the expression for A^100: A^100

= PD^100P^-100

= PD^100(P^-1P)P^-99

= PD^100IP^-99

= PD^100P^-1P^-98 ... P^-1

Notice that all intermediate P^-1P terms equal the identity matrix (I), and they cancel each other out: A^100 = PD^100P^-1 So, the statement is true.

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Answer:

Answered below

Step-by-step explanation:

Slope = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

You need 2 coordinates from your graph as long as the line you have is completely straight. You have 2 points it is (0,3) & (8,0)

So your y2 is 0

y1 is 3

So your x2 is 8

x1 is 0

Plug in and solve (keep in mind you should be expecting a negative slope since your line is sloping downwards as you advance to the right.

m = (0-3)/(8-0)

m = -3/8

m = slope = -3/8x = -0.375x

Slope is given as a number followed by value x

Answer:

(-2,6,-6)IS THE SLOPE

Answer:

72 degrees

Step-by-step explanation:

180-108=72

where I got 180: a supplementary angle is 180 degrees

The area of the largest possible inscribed triangle with one side as a diameter of the circle is 72 square centimeters.

The largest possible inscribed triangle with one side as a diameter of the circle has a right angle.
To find the area of the inscribed triangle, we need to calculate the length of the base and the height. Since the diameter of the circle is the base of the triangle, it has a length of 2 times the radius, which is 12 cm.
The height of the triangle is equal to the radius of the circle, which is 6 cm.
To calculate the area of the triangle, we use the formula:
Area = 1/2 * base * height

= 1/2 * 12 cm * 6 cm

= 72 square cm
Therefore, the area of the largest possible inscribed triangle with one side as a diameter of the circle is 72 square centimeters.

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The best-fit line to represent the black data points is the blue line.

The plot of absorbance vs. concentration shows 8 data points with 3 lines drawn to represent the data. In order to determine the best-fit line, we need to evaluate the lines based on how well they represent the data points.

(a) The red line is the middle line and goes through 1 data point, with 3 data points above it and 4 data points below it. This line has a slope that is between the slopes of the other two lines. However, it doesn't go through many of the data points and the slope is not consistent with the majority of the data points.

(b) The green line is the top line and touches 3 of the data points, with the rest of the data points below it. This line has a steeper slope compared to the red line, but it doesn't touch many of the data points and has a significant deviation from the majority of the data points.

(c) The blue line is the bottom line and has 2 data points below it and 6 data points above it. This line has a slope that is more consistent with the majority of the data points, and it has the least deviation from the data points compared to the other two lines.

In mathematical terms, the blue line has the least sum of squared residuals, meaning it has the smallest difference between the observed values and the predicted values.

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