To obtain the corresponding expression for the magnetic field in a plane wave propagating in a nonmagnetic medium, we can use Maxwell's equations. Specifically, Faraday's law of electromagnetic induction relates the electric field (E) to the magnetic field (B) as follows:
∇ × E = -∂B/∂t
Given the electric field expression E = 225e^(-30x) cos(2π × 10^8 t - 40x) [V/m], we can apply Faraday's law to find the corresponding magnetic field expression.
Taking the curl of both sides of the equation, we have:
∇ × (∇ × E) = ∇ × (-∂B/∂t)
Using vector calculus identities, we can simplify the left side of the equation:
∇ × (∇ × E) = ∇(∇ ⋅ E) - ∇²E
Since the electric field does not have any dependence on y or z, the derivatives with respect to y and z are zero. Therefore, the expression simplifies further:
∇ × (∇ × E) = (0, ∂(∂E/∂x)/∂z - ∂²E/∂x², 0)
Now, equating this to -∂B/∂t, we have:
(0, ∂(∂E/∂x)/∂z - ∂²E/∂x², 0) = -∂B/∂t
To find the expression for the magnetic field (B), we need to solve this equation. However, this involves differentiating the given electric field expression twice with respect to x, which can be quite involved.
The resulting expression for the magnetic field will depend on the specific values and derivatives involved in the electric field expression. To obtain the complete expression for the magnetic field, we would need to carry out the necessary differentiations and simplifications.
The corresponding expression for the magnetic field in a plane wave propagating in a nonmagnetic medium can be obtained by applying Faraday's law of electromagnetic induction. However, in this case, the given electric field expression is quite complex and involves derivatives, making it difficult to provide a direct answer without performing the necessary calculations.
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For an Ac signal with peak voltage Vp equal to 60V, the same power would be delivered to a load with a dc voltage of
Answer:
30√2 ≈ 42.426 volts
Explanation:
The RMS value of the signal is the DC equivalent. For a sine wave, the mean of the square is half the square of the peak value. Then the Root-Mean-Square is ...
RMS = √((Vp)^2/2) = Vp/√2
For Vp = 60 volts, the equivalent DC voltage is ...
V = (60 volts)/√2 = 30√2 volts ≈ 42.426 volts
The starting device usually used on single phase, fractional horsepower motors requiring low starting torque is the
The starting device usually used on single-phase, fractional horsepower motors requiring low starting torque is the current relay.
How tons cutting-edge relay is wanted energized?This is the minimal cutting-edge, the relay expects to float thru the now shorted contacts whilst the relay is became on (forty mA). The load may be much less than that too however relay won't stay sufficient for range of cycles of operation referred to withinside the information sheet. The minimum running voltage to your precise relay is 3. seventy-five V.
A cutting-edge relay is a kind of electromagnetic transfer used as a part of the manipulating structures for electric equipment. These relays are generally used as sensors (cutting-edge sensor/tracking relays) to screen cutting-edge float inside the business and different safety-touchy equipment current beginning relays are used on single-phase, fractional horsepower cars requiring low beginning torque.Read more about the torque:
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A thin-walled pressure vessel is constructed by rolling a 6 mm thick steel sheet into a cylindrical shape, welding the seam along line A-B, and capping the ends. The vessel is subjected to an internal pressure of 1.25 MPa. What is the normal stress normal to line A-B?
Answer:
41.015
Explanation:
Solution
Given that:
Th first step to take is to find the longitudinal stress in the cylinder
σl = PD/4t
P = the pressure
D = the diameter
t = the thickness
Thus,
σl = 1.25 * ^ 6 * 0.45 / 4 * 6 * 10 ^ ⁻3
=23.475Mpa
Now. we find the hoop stress in the cylinder∠
σh = PD/2t
σh = 1.25 * ^ 6 * 0.45/ 2 * 6 * 10 ^ ⁻3
σh =46.875 Mpa
Then
we find the normal stress in the line of the 30° angle with the longitudinal axis stated below:
σab = σh + σl/2 + ( σh - σl/2) cos 2θ + t sin 2θ
So,
σab =46.875 + 23.4375/2 + ( 46.875 - 23.4375/2) cos 2(30°) + 0
σab= 41.015
Therefore the normal stress to line A-B is 41.015
Pinewood Studios was a part of a construction boom in
Pinewood Studios played a significant role in the construction boom that occurred in the UK during the 20th century.
The studio complex, located in Buckinghamshire, was established in 1936 and quickly became one of the most important production hubs for the British film industry.
As demand for film and television production increased, Pinewood expanded to include additional soundstages, backlots, and post-production facilities.
The studio's success also led to the growth of related industries, such as visual effects and prop manufacturing, in the surrounding area.
Today, Pinewood is known for hosting major film franchises like James Bond and Star Wars, and continues to be a vital part of the UK's creative economy. Its legacy as a symbol of British filmmaking excellence is sure to endure for years to come.
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Chọn dữ liệu phù hợp và biểu diễn chúng dưới dạng biểu đồ, từ đó cho biết 3 yếu tố
mà người dùng xem xét nhiều nhất khi mua một chiếc tablet.
Answer:
Please explain it in English so that i can help you or you need someone who can speak Vietnam help you
in which order are the transformations being applied here? if the reflection is applied first, if the shear is applied first, type s5a2
To establish the order of transformations used in the transformation given by the notation "s5a2," we must carefully examine the notation. The symbol "s5a2" denotes a pair of transformations.
The first transformation, indicated by the letter "s," is shear. The subscript 5 denotes that this shear is applied in a certain direction along a line 5 units distant from the origin. The second change, indicated by the letter "a," is an expansion or dilatation. The subscript 2 denotes that this enlargement's scale factor is 2. As a result, according to the notation "s5a2," shear is used first, followed by expansion. As a result, the right transformation order is: Shear along a 5 unit line away from the origin. To establish the order of transformations used in the transformation given by the notation "s5a2," we must carefully examine the notation. The symbol "s5a2" denotes a pair of transformations.
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why is it difficult to dissolve cellulose in solvent that dissolve petroleum based polymers
The crystallinity of cellulose as well as its polar qualities makes it less difficult to dissolve. It has a three-dimensional hydrogen bond (H-bond) arrangement with the hydroxyl group connected to each polymer chain. On the other hand, Hydrocarbon polymers are nonpolar, and nonpolar solvents are used to dissolve them.
What exactly is cellulose?Cellulose is an organic molecule with the formula n that is a polysaccharide made up of a linear chain of hundreds to thousands of β linked D-glucose units. Cellulose is a structural component of the major cell wall of green plants, many algae, and oomycetes.
Cellulose is the principal component present in plant cell walls and aids in the plant's stiffness and strength. Although cellulose cannot be digested by humans, it is an essential source of fiber in the diet. Cellulose is utilized in the production of clothing and paper.
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Describe the extent of their own responsibility. When to act on their own innitiative to find , clarify and evaluate information , and to whom they should report if they have problems they cannot resolve in the work place
Answer:
whatsthe question choices
The cold drawn AISI 1040 steel bar with 25-mm width and 10-mm thick has a 6- mm diameter thru hole in the center of the plate. The plate is subjected to a completely reversed axial load that fluctuates from 12kN to 28kN. Use notch sensitivity of 0.83.
Required:
a. Estimate the fatigue factor of safety based on yielding criteria.
b. Estimate the fatigue factor of safety based on Goodman and Morrow criteria.
Answer:
A) ( N ) = 1.54
B) N ( Goodman ) = 1.133, N ( Morrow) = 1.35
Explanation:
width of steel bar = 25-mm
thickness of steel bar = 10-mm
diameter = 6-mm
load on plate = between 12 kN AND 28 kN
notch sensitivity = 0.83
A ) Fatigue factor of safety based on yielding criteria
= δa + δm = \(\frac{Syt}{n}\) = 91.03 + 227.58 = 490 / N
therefore Fatigue number of safety ( N ) = 1.54
δa (amplitude stress ) = kf ( Fa/A) = 2.162 * ( 8*10^3 / 190 ) = 91.03 MPa
A = area of steel bar = 190 mm^2 , Fa = amplitude load = 8 KN , kf = 2.162
δm (mean stress ) = kf ( Fm/A ) = (2.162 * 20*10^3 )/ 190 = 227.58 MPa
Fm = mean load = 20 *10^3
B) Fatigue factor of safety based on Goodman and Morrow criteria
δa / Se + δm / Sut = 1 / N
= 91.03 / 183.15 + 227.58 / 590 = 1 /N
Hence N = 1.133 ( based on Goodman criteria )
note : Se = endurance limit (calculated) = 183.15 , Sut = 590
applying Morrow criteria
N = 1 / ( δa/Se) + (δm/ δf )
= 1 / ( 91.03 / 183.15 ) + (227.58 / 935 )
= 1.35
which type of energy transformed into thermal energy in a toaster
Answer:
Electrical energy
Each of the following problems describes an algorithm implemented on a computer satisfying the axioms (13.5) and (13.7). For each one, state whether the algorithm is backward stable, stable but not backward stable, or unstable, and prove it or at least give a reasonably convincing argument. Be sure to follow the definitions as given in the text. (d) Data: x∈C. Solution: 0, computed as x⊖x. (Again, a real machine may do better than our definitions based on (13.7).) (e) Data: none. Solution: e, computed by summing ∑
k=0
[infinity]
1/k! from left to right using ⊗ and Θ, stopping when a summand is reached of magnitude <ϵ
machine
(f) Data: none. Solution: e, computed by the same algorithm as above except with the series summed from right to left. (g) Data: none. Solution: π, computed by doing an exhaustive search to find the smallest floating point number x in the interval [3,4] such that s(x)⊗ s(x
′
)≤0. Here s(x) is an algorithm that calculates sin(x) stably in the given interval, and x
′
denotes the next floating point number after x in the floating point system.
(d) The algorithm is backward stable.
(e) The algorithm is unstable.
(f) The algorithm is unstable.
(g) The algorithm is stable but not backward stable.
(d) The algorithm for computing 0 is backward stable because regardless of the input x, the computed solution x⊖x is always equal to 0. Any small perturbation in x will not affect the result.
(e) The algorithm for computing e by summing the series from left to right is unstable. It relies on accumulating small values of 1/k! until a summand with magnitude less than ϵ is reached. However, the accumulation of floating-point numbers can introduce rounding errors, and the order of summation can affect the result, leading to potentially large errors.
(f) The algorithm for computing e by summing the series from right to left is also unstable. The accumulation of floating-point numbers and the order of summation can introduce errors, resulting in potentially different results compared to the algorithm in (e).
(g) The algorithm for computing π using an exhaustive search is stable but not backward stable. It relies on finding the smallest floating-point number x in the interval [3,4] such that the product of sin(x) and sin(x') is less than or equal to 0. While the algorithm is stable in the sense that small perturbations in the input will not drastically change the result, it is not backward stable because the computed solution does not closely reflect the exact mathematical solution of π.
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Select the appropriate SDLC process model to develop the VHROM system.
Software application life cycle simply means the application of standard practices to software applications building.
This is an incomplete information. Therefore, an overview of the software application life cycle will be given. It's the process of planning, creating, testing, and deployment of an information system.
Software application life cycle is divided into six steps which are planing requirements, designing, building, documentation, testing, deployment, and maintenance.
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An air conditioner operates exactly as a refrigerator; it removes heat from a cold place (a bedroom, for example) and conveys it to a warmer place (usually the outside). Quantities of practical importance in understanding the efficiency of air conditioners are the rate of heat removal and the electric power input to the unit (i.e., the electric energy consumed per unit time). Find an expression for the coefficient of performance KKK of an air conditioner that has a rate of heat removal HHH and a power consumption PPP .
The expression for coefficient of heat performance is; K = H/P
We are given the expressions;
Coefficient of performance = K
Rate of heat removal = H
Power consumption = P
Formula for coefficient of performance is usually;
K = Q/W
However, the rate of heat removal H can be further expressed as;
H = Q/T
Where;
Q is heat removed
T is time
Similarly, for power consumption, it can also be expressed as;
P = W/T
Where;
W is workdone
T is time taken
Thus, Q = HT and W = PT
Finally;
K = HT/PT
K = H/P
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The fuel reduction zone, "Reduced Fuel Zone", is the remaining __________ and will depend on the steepness of your property and the vegetation.
Select one: a. 70 feet (or to property line) b. 450 feet (or to property line) c. 60 feet (or to property line) d. 30 feet (or to property line)
The fuel reduction zone, "Reduced Fuel Zone", is the remaining 30 feet (or to property line) and will depend on the steepness of your property and the vegetation. The correct answer is option d. 30 feet (or to property line).
Reduced Fuel Zones (RFZs) are areas of vegetation and fuel that have been managed or modified to reduce their flammability and to create fuel breaks. The objective is to remove or minimize the fuel load, as well as the continuity and distribution of fuel throughout the landscape.RFZs assist firefighters in controlling fires, particularly those that are moving rapidly, because they allow for a reduction in the fire's intensity, speed, and potential to spread. In fire suppression operations, RFZs are frequently used as safety zones for firefighters and as areas where strategic fire control operations, such as burning operations, can be conducted to bring the fire under control.In conclusion, the Reduced Fuel Zone (RFZ) is the remaining 30 feet (or to property line) and will depend on the steepness of your property and the vegetation.
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two technicians are discussing pulse train signals. technician a says a fuel injector pulse on a hybrid engine is an example of a pulse train signal. technician b says that an ignition module pulse on a hybrid engine is an example of a pulse train signal. which technician is correct?
Both Technician A and Technician B are correct as there statement fuel injector pulse on a hybrid engine is an example of a pulse train signal" and "an ignition module pulse on a hybrid engine is an example of a pulse train signal" are correct.
A hybrid vehicle is one that draws its power from two or more different sources, such as submarines that operate on batteries when submerged and diesel when they are surfaced. Hydraulic hybrids that use pressurised fluid are another way to store energy.
To maximise both fuel and energy efficiency, hybrid powertrains are made to switch between different power sources. For instance, in hybrid electric vehicles, the combustion engine is better at maintaining high speed while the electric motor is more effective at producing torque, or turning power. The three main advantages of hybridization are increased efficiency, lower emissions, and lower operating costs when compared to non-hybrid vehicles.
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what is the effect of distance between a dipole and a ground plane on the input impedance of the dipole
The distance of a dipole antenna's feed point from the ground plane has an impact. The relationship between the real part of the impedance and the fractional height above ground for the desired resonant frequency is shown in the chart at left.
What is dipole antenna?The simplest and most common type of antenna in radio and telecommunications is the dipole antenna, also known as a doublet. The term "dipole" refers to any of a group of antennas with a radiating structure supporting a line current that is so energized that it only has one node at each end and produces radiation patterns that resemble those of an elementary electric dipole.
A dipole antenna typically consists of two identical conductive components, such as metal wires or rods. Between the two halves of the antenna, the driving current from the transmitter is applied, or, for receiving antennas, the output signal to the receiver is taken. One of the conductors is connected to each side of the feedline to the transmitter or receiver.
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Estimate the maximum expected thermal conductivity for a Cermet that contains 58 vol% titanium carbide (TiC) particles in a cobalt matrix. Assume thermal conductivities of 27 and 69 W/m-K for TiC and Co respectively.
Answer:
The right answer is "36.32 W/mk".
Explanation:
According to the question,
TiC = 76%
or,
= 0.76
CO = 24%
or,
= 0.24
Thermal conductivity of TiC,
= 26 W/mk
Thermal conductivity of CO,
= 69 W/mk
On applying the rule, we get
⇒ \("K" \ of \ Cermet=(K)_{TiC} (V_f)_{TiC}+(K)_{CO} (V_m)_{CO}\)
On putting the given values, we get
⇒ \(=(26)(0.76)+(69)(0.24)\)
⇒ \(=19.76+16.56\)
⇒ \(=36.32 \ W/mk\)
A composite wall has a 6-cm layer of fiberglass insulation [K =
0.038 W/(m-°C)] sandwiched between two 2 cm thick white pine boards
[K = 0.10 W/(m-°C)]. Calculate the heat flux per unit area through
Answer:
Explanation:To calculate the heat flux per unit area through the composite wall, we can use the concept of thermal resistance and Fourier's law of heat conduction. The formula for calculating the heat flux (q) is:
q = (T1 - T2) / R_total
Where:
T1 is the temperature on one side of the wall
T2 is the temperature on the other side of the wall
R_total is the total thermal resistance of the composite wall
The thermal resistance of each layer can be calculated using the formula:
R = thickness / thermal conductivity
Let's calculate the heat flux per unit area step by step:
Calculate the thermal resistance of each layer:
R_fiberglass = 0.06 m / 0.038 W/(m-°C) = 1.58 (m²·°C)/W
R_pine = 0.02 m / 0.10 W/(m-°C) = 0.20 (m²·°C)/W
Calculate the total thermal resistance of the composite wall:
R_total = R_fiberglass + R_pine + R_fiberglass = 1.58 (m²·°C)/W + 0.20 (m²·°C)/W + 1.58 (m²·°C)/W = 3.36 (m²·°C)/W
Determine the temperature difference between the two sides of the wall.
Assume T1 = 100 °C and T2 = 20 °C.
(T1 - T2) = 100 °C - 20 °C = 80 °C
Calculate the heat flux per unit area:
q = (T1 - T2) / R_total = 80 °C / 3.36 (m²·°C)/W ≈ 23.81 (W/m²)
Therefore, the heat flux per unit area through the composite wall is approximately 23.81 W/m².
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The monthly output of a certain product is Q(x)=2500x 5/2
where x is the capital investment in millions of dollars. Find dQ/dx, which can be used to estimate the effect on the output if an additional capital investment of $1 million is made. dQ/dx=
The monthly output of a certain product can be given by the function
\(`Q(x) = 2500x^(5/2)`\)
where x is the capital investment in millions of dollars.
differentiate the function Q(x) with respect to x.
\(dQ/dx = d/dx(2500x^(5/2))\)
Using the power rule of differentiation, we have:
\(dQ/dx = (5/2) * 2500 * x^(5/2 - 1)dQ/dx
= 6250x^(3/2) `dQ/dx
= 6250x^(3/2)`\)
which gives us the effect on the output if an additional capital investment of $1 million is made.
Note: To estimate the effect on the output if an additional capital investment of $1 million is made, we substitute x with x+1 in the expression for `dQ/dx`. This gives us the new output and the increase in output due to the additional investment.
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An exothermic reaction releases 146 kJ of heat energy and 3 mol of gas at 298 K and 1 bar pressure. Which of the following statements is correct?
A) ΔU=-138.57 kJ and ΔH=-138.57 kJ
B) ΔU=-153.43 kJ and ΔH=-153.43 kJ
C) ΔU=-138.57 kJ and ΔH=-146.00 kJ
D) ΔU=-153.43 kJ and ΔH=-146.00 kJ
Answer:
D) ΔU = -153.43 kJ and ΔH = -146.00 kJ
Explanation:
Given;
heat energy released by the exothermic reaction, ΔH = -146 kJ
number of gas mol, n = 3 mol
temperature of the gas, T = 298 K
Apply first law of thermodynamic
Change in the internal energy of the system, ΔU;
ΔU = ΔH- nRT
where;
R is gas constant = 8.314 J/mol.K
ΔU = -146kJ - (3 x 8.314 x 298)
ΔU = -146kJ - 7433 J
ΔU = -146kJ - 7.433 kJ
ΔU = -153.43 kJ
Therefore, the enthalpy change of the reaction ΔH is -146 kJ and change in the internal energy of the system is -153.43 kJ
D) ΔU = -153.43 kJ and ΔH = -146.00 kJ
A(n) _____ provides a portable source of light when working on a vehicle.
Answer:
flashlight???
Explanation:
For each function , sketch the Bode asymptotic magnitude and asymptotic phase plots.
a. G(s)= 1/s(s+2)(s+4)
b. G(s)= (s+5)/(s+2)(s+4)
c. G(s)= (s+3)(s+5)/s(s+2)(s+4)
Answer:
attached below
Explanation:
a) G(s) = 1 / s( s+2)(s + 4 )
Bode asymptotic magnitude and asymptotic phase plots
attached below
b) G(s) = (s+5)/(s+2)(s+4)
phase angles = tan^-1 w/s , -tan^-1 w/s , tan^-1 w/4
attached below
c) G(s)= (s+3)(s+5)/s(s+2)(s+4)
solution attached below
1. The upper specification limit is 27 The lower specification limit is 10
The standard deviationof the process is 2.6
Determine the process capability, Cp
Round your answer to 2 decimal places, if applicable.
QUESTION 122. A process design meets K = 3 sigma levels.
The process was originally centered.
If the mean of the process shifts up towards the upper specification limit by 0.81 standard deviations.
What is the expected dropout per 1,000 opportunities on the upper end?
Round your answer to the nearest whole unit, if applicable
The process capability, Cp, is calculated by dividing the difference between the upper and lower specification limits by six times the standard deviation of the process. In this case, the Cp value cannot be determined as the standard deviation of the process is given but not the process mean or target value.
Process capability, Cp, is a measure of how well a process can meet the specifications. It is calculated by dividing the difference between the upper and lower specification limits by six times the standard deviation of the process. In this case, the upper specification limit is 27, and the lower specification limit is 10. However, the process mean or target value is not provided, which is necessary to calculate Cp accurately. Without the process mean, we cannot determine the process capability.
Regarding the expected dropout per 1,000 opportunities on the upper end, it is calculated based on the shift in the process mean. Since the process was originally centered and the mean shifts up towards the upper specification limit by 0.81 standard deviations, it implies that the process mean moves closer to the upper limit. This shift indicates an increased likelihood of values exceeding the upper limit. To calculate the expected dropout per 1,000 opportunities on the upper end, we need to consider the process capability index, Cpk, which takes into account the mean shift. However, since the necessary information to calculate Cpk (such as the mean, standard deviation, and process specifications) is not provided, we cannot determine the expected dropout accurately.
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PLEASE HELP I NEED THIS ASP!!
Answer:
up up down down
Explanation:
left right left right b a select start
Using a small cube as a representative volume of material, illustrate graphically all the six independent components of strains that determine the state of strain in the volume of material that is enclosed by the cube. Indicate in your schematics, the change in shape produced by each of the normal strain and shear strain components.
Answer:
Attached below
Explanation:
Attached below is the schematic diagram of a small cube representing volume of material and all the six independent components of strains that will determine the state of strain
Note : Attached below is a free hand diagram of the cube indicating the six independent components of strains and a screen shot of the change in shape produced by each of the normal strain and shear strain components
( drawn with online tools )
A 280 km long pipeline connects two pumping stations. It is desired to pump 0.56 m3/s of oil through a 0.62 m diameter line, the discharge station is 250 m lower in elevation than the upstream station, and the discharge pressure is to be maintained at 300 kPa. The oil has a dynamic viscosity of 3.645 x 10-3 Pa·s and a density of 810 kg/m3. The pipe is constructed of commercial steel and the inlet pressure may be taken as 1 atmosphere. Considering the mechanical-energy friction loss Ff, determine the power required to pump the oil if the power efficiency is 70%. Develop a sketch of the piping system considered.
Ignore energy losses due to contraction, expansion & 90° bends!!!
A heavy train requires nearly a mile to come to a complete stop because it has a lot of
Answer:
Friction
Explanation:
Heavy objects take an extended way to get to a full halt, so they have a lot of friction.
An item with high weight is forced down to something like a surface of stronger power than an item with small weight and, as a result, there is a greater pressure between the base of the large weight than the one between ground and the small one.
Answer:
friction
Explanation: It has a lot of mass so it will interact with the railroad. When you interact with the railroad, it is called friction. That will make the train slower.
Hope this helps! Stay Safe!
Air flows through a pipe at a rate of 200 L/s. The pipe consists of two sections of diameters 20 cm and 10 cm with a smooth reducing section that connects them. The pressure difference between the two pipe sections is measured by a water manometer. Neglecting frictional effects, if the inlet temperature of air is at 25oC, due to the compression of the air at neck of the pipe contraction, the outlet temperature is measured at 30oC, determine the differential height of water between the two pipe sections. Take the air density at 25oC and 35oC as 1.20 kg/m3 and 1.19 kg/m3 respectively.
The differential height between the two pipe sections is 0.05m
What is Differential HeightThe differential height of water between the two pipe sections can be calculated using the following equation:
h = (Q²*(ρ₂-ρ₁)/(A*g)) * (P₂-P₁)
where
h = differential height of water (m)
Q = volumetric flow rate (L/s)
ρ = density of air (kg/m3)
A = cross sectional area of pipe (m2)
g = gravitational acceleration (9.81 m/s2)
P = pressure (Pa)
Substituting the given values in the equation we get,
h = (200*(1.19-1.20)/(π*(0.1)2*9.81)) * (30-25)
h = 0.05 m
Hence, the differential height of water between the two pipe sections is 0.05 m.
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T/F. a clamp-on ammeter is designed to measure only alternating current
True, a clamp-on ammeter is designed to measure only alternating current.
It is FLASE to state that a clamp-on ammeter is designed to measure only alternating current.
Why is this so ?A clamp-on ammeter,also known as a clamp meter or current clamp, is designed to measure both alternating current (AC)and direct current (DC).
It is a versatile instrument commonly used by electricians and technicians to measure electrical currents without the need to disconnect the circuit.
The clamp-on ammeter clamps around a conductor,allowing it to measure the current flowing through the conductor, whether it is AC or DC.
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A clamp-on ammeter is designed to measure only alternating currents.
True or False?
_____is a slow wireless technology used to connect devices within a radius of about 30 feet
Answer:
Bluetooth is a slow wireless technology used to connect devices within a radius of about 30 feet. While Bluetooth technology is amazing, there are lots of bugs involved with Bluetooth devices, and there is still lots to be discovered in this area of tech.