The diagram shows a triangle. 37° 65° 6р What is the value of p? p =​

The best measure of variability is the standard deviation.

Player A is the most consistent, with an IQR of 1.5.

Standard deviation is defined as the square root of the variance is used to calculate the standard deviation, a statistic that expresses how widely distributed a dataset is in relation to its mean.

The table shows the number of goals made by two hockey players.

Player A:

2, 3, 1, 3, 2, 2, 1, 3, 6

Using  a statistics calculator, we have:

Mean = 2.56

S.D. = 1.51

Player B:

1, 4, 5, 1, 2, 4, 5, 5, 11

S.D. = 3.03

The best measure of variability is the standard deviation.

Player A is the most consistent, with an IQR of 1.5.

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The upper cumulative probability to get the probability that the proportion of successes falls between 0.52 and 0.59. For the upper bound of 0.59, the z-score is (0.59 - 0.55) / 0.034, which is approximately 1.18.

To calculate the probability that the proportion of successes in the sample will be between 0.52 and 0.59, we can use the normal approximation to the binomial distribution. The formula for the standard deviation of the sample proportion is given by: Standard Deviation = sqrt(p * (1-p) / n)

where p is the probability of success in the population (0.55 in this case) and n is the sample size (200 in this case). We can then use this standard deviation to calculate the z-scores for the lower and upper bounds of the desired range.

Next, we need to look up the corresponding cumulative probabilities in the standard normal distribution table for each z-score. Finally, we subtract the lower cumulative probability from the upper cumulative probability to get the probability that the proportion of successes falls between 0.52 and 0.59.

To calculate the probability that the proportion of successes in the sample falls between 0.52 and 0.59, we first need to calculate the standard deviation of the sample proportion using the formula mentioned earlier:

Standard Deviation = sqrt(p * (1-p) / n)

Standard Deviation = sqrt(0.55 * (1-0.55) / 200)

Using this formula, we can find the standard deviation to be approximately 0.034.

Next, we calculate the z-scores for the lower and upper bounds of the desired range using the formula: Z = (x - μ) / σ

For the lower bound of 0.52, the z-score is (0.52 - 0.55) / 0.034, which is approximately -0.88. For the upper bound of 0.59, the z-score is (0.59 - 0.55) / 0.034, which is approximately 1.18.

We then use these z-scores to find the corresponding cumulative probabilities in the standard normal distribution table. Let's denote the cumulative probabilities as P1 for the lower bound and P2 for the upper bound.

Finally, we calculate the probability that the proportion of successes falls between 0.52 and 0.59 by subtracting P1 from P2: Probability = P2 - P1

This probability represents the likelihood that the proportion of successes in a sample of 200 items falls within the specified range.

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Answer:

68,5*4=274 nên cái ao đó là hình vuông

Step-by-step explanat

4*a là chu vi hình vuông

Answer:

It's 18.

Step-by-step explanation:

17 plus 18 plus 19 equals 54, and the middle number is 18.

Answer:

$10.16

Step-by-step explanation:

Total Cost = Cost of Lunch + Beverage + Tip's Amount + Sales Tax.

Cost of lunch + Beverage = 6.5 + 1.5 = $8

Tip:

8* 20/100 = $1.6

Sales tax:

8* 7/100 = $0.56

Cost of Lunch + Beverage + Tip's Amount + Sales Tax = Total Cost

$8 + $1.6 + $0.56 = $10.16

hope it helps :)

mark brainliest!!!

-2x+24 is equivalent to expression -3(2x-8)+4x.

Option B is the correct answer.

We have,

First, simplify the expression inside the parentheses:

-3(2x-8) = -6x + 24

Then substitute this into the original expression:

-3(2x-8)+4x = -6x + 24 + 4x = -2x + 24

Therefore,

The equivalent expression is -2x+24.

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Answer:

3n - 1

Step-by-step explanation:

2+(n-1)3

=> 2 + 3*n -3*1

=> 2 + 3n - 3

=> 3n - 1

Hope you understand!!

The domain model class diagram is used to illustrate the domain models in object-oriented development. It provides an overview of a system's domain models, the major concepts, and their relationships.

These diagrams are used to give an understanding of the software system's requirements and to guide the system's design process.150 words:What is a domain model class diagram?A domain model class diagram is a type of UML diagram that is used to represent the domain models in object-oriented development.

This diagram is used to depict an overview of a system's domain models, the major concepts, and their relationships. A domain model is a visual representation of the system's domain, which includes the concepts, activities, and relationships between the concepts and activities.

A domain model class diagram can be used to capture the user's requirements and translate them into a software system.The domain model class diagram consists of classes, attributes, associations, and operations. Classes are the fundamental building blocks of the system and define the system's concepts.

Attributes are the properties of the classes, while operations are the actions that can be performed on the classes. Associations are the relationships between the classes, and they define how the classes are connected to one another.

The domain model class diagram provides a clear and concise representation of the system's domain and enables designers and developers to build software systems that meet the user's needs.

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Step-by-step explanation:

Give the slope between the points (-5,-2)(-2,-7)

slope = change in y / change in x

slope = (-2 - (-7)) / (-5 - (-2))

slope = ( -2 + 7) / ( -5 + 2)

slope = 5/-3

slope = -5/3 or -1.667

a) The amount of water in the pool after 2 hours can be calculated using the equation.

Water in pool = 10L/hour × 2 hours = 20L.

b) The pool will be 80L when the equation is satisfied: 80L = 10L/hour × Time.

Solving for Time, we find Time = 8 hours.

c) Part b) is linear.

a) To calculate the amount of water in the pool after 2 hours, we can use the equation:

Water in pool = Water filling rate × Time

Since the pool gets filled up with 10L of water per hour, we can substitute the values:

Water in pool = 10 L/hour × 2 hours = 20L

Therefore, after 2 hours, there will be 20 liters of water in the pool.

b) To determine the number of hours it takes for the pool to reach 80 liters, we can set up the equation:

Water in pool = Water filling rate × Time

We want the water in the pool to be 80 liters, so the equation becomes:

80L = 10 L/hour × Time

Dividing both sides by 10 L/hour, we get:

Time = 80L / 10 L/hour = 8 hours

Therefore, it will take 8 hours for the pool to contain 80 liters of water.

c) Part b) is linear.

The equation Water in pool = Water filling rate × Time represents a linear relationship because the amount of water in the pool increases linearly with respect to time.

Each hour, the pool fills up with a constant rate of 10 liters, leading to a proportional increase in the total volume of water in the pool.

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There are option (b) 12 integers between 1000 and 1999 that have distinct odd digits.

To find the number of integers between 1000 and 7400 that have distinct odd digits, we can break down the problem into smaller parts. First, we can count the number of integers between 1000 and 1999 that have distinct odd digits. We can then count the number of integers between 2000 and 2999, and so on, until we count the number of integers between 7000 and 7400.

Let's focus on the first part of the problem, which is finding the number of integers between 1000 and 1999 that have distinct odd digits. To do this, we can use the following steps:

Using the multiplication principle, we can multiply the number of choices we have for each digit to find the total number of integers between 1000 and 1999 that have distinct odd digits. This gives us:

4 x 3 x 2 x 1 = 24/2 = 12

Therefore, we find that the answer to the problem is (b) 12 integers.

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The rate of change of y with respect to x is given by dy/dx = xy - (3/2)x²y.

To find the rate of change of y with respect to x, we need to differentiate the given equation. The rate of change can be determined by taking the derivative of both sides of the equation with respect to x.

First, let's differentiate each term separately using the rules of differentiation.

Differentiating x²y with respect to x gives us 2xy using the product rule.

To differentiate 5, we know that a constant has a derivative of 0.

Differentiating 2ln(y) with respect to x requires the chain rule. The derivative of ln(y) with respect to y is 1/y, and then we multiply by dy/dx. So, the derivative of 2ln(y) is 2/y * dy/dx.

Differentiating x³ gives us 3x² using the power rule.

Now, we can rewrite the equation with its derivatives:

2xy - 2/y * dy/dx = 3x²

To solve for dy/dx, we can isolate it on one side of the equation. Rearranging the equation, we get:

2xy = 2/y * dy/dx + 3x²

To isolate dy/dx, we move the term 2/y * dy/dx to the other side:

2xy - 2/y * dy/dx = 3x²

2xy = 2/y * dy/dx + 3x²

2/y * dy/dx = 2xy - 3x²

Now, we can solve for dy/dx by multiplying both sides by y/2:

dy/dx = (2xy - 3x²) * (y/2)

Simplifying further, we have:

dy/dx = xy - (3/2)x²y

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Answer:

Scroll Down Below...

Step-by-step explanation:

To decide by virtue of what many age it will love trio person engaged in private ownership of business, we can use the rule of 72 for plain interest. The rule of 72 states that you can approximate the number of age it takes for an expenditure to double by separating 72 apiece annual interest. In this case, we ask about by virtue of what long it takes to trio person engaged in private ownership of business, so we'll separate 72 for one interest (5%).72 / 5 = 14.4According to the rule of 72, it would take nearly 14.4 age to double person engaged in private ownership of business at a 5% annual interest. Since we be going to trio person engaged in private ownership of business, we need to double it two times.14.4 age x 2 = 28.8 ageTherefore, it would take nearly 28.8 age to trio person engaged in private ownership of business at a 5% natural interest.In Spanish:Para determinar cuántos años tomará triplicar el money, podemos utilizar la regla del 72 para el interés plain. La regla del 72 establece que puedes aproximar el número de años que se tarda en duplicar una inversión dividiendo 72 entre la tasa de interés anual. En este caso, queremos weapon cuánto tiempo tomará triplicar el money, así que dividiremos 72 entre la tasa de interés (5%).72 / 5 = 14.4Según la regla del 72, tomaría aproximadamente 14.4 años duplicar el money a una tasa de interés anual del 5%. Como queremos triplicar el money, necesitamos duplicarlo do veces.14.4 años x 2 = 28.8 añosPor lo tanto, tomaría aproximadamente 28.8 años triplicar el money a una tasa de interés natural del 5%. La respuesta correcta es 28.8 años.

The correct match is:1. Domain (all real numbers): Range = {3, 4, 5, 6}2. Domain = Range = (all real numbers)3. Domain = (all real numbers), Range = {3}4. Domain = {2}

1. the range set of E= ((3, 3), (4, 4), (5, 5), (6, 6)) : Domain (all real numbers), Range = {3, 4, 5, 6}

2. the range and domain of F = {(x, y) l x+y=10) : Domain = Range = (all real numbers)

3. the range and domain of P = ((x, y) ly=3] : Domain = (all real numbers), Range = {3}

4. the domain set of C= {(2, 5), (2, 6), (2, 7)) : Domain = {2}

E = ((3, 3), (4, 4), (5, 5), (6, 6))

range sets where range is the set of all y-values ​​in the specified set of points is.

range = {3, 4, 5, 6}

range and domain of F = {(x, y) | x + y = 10}

where range is all A set of y-values.

area = {y | y = 10 - x}

and the domain is the set of all x values ​​that satisfy the equation x + y = 10.

domain = {x | x is a real number}

P = ((x,y) | y = 3] range and region

range is given directly as y = 3. Therefore range is {3}.

Also, no constraint is specified on x, so the domain can be any real number.

domain = (all real numbers)

domain of C = {(2, 5), (2, 6), (2, 7)}

where domain is the set of all x values A set of specified points.

domain = {2}

matches option:

E range set = ((3, 3), (4, 4), (5, 5), (6, 6))

matches less ( 3, 4, 5, 6)

F = {(x, y) | range and range = ((x,y) | y = 3]

match: range = {3}, range = (all real numbers)

domain set for C = {(2, 5), (2, 6 ), (2, 7)}

Matches: (2)

So the match is:

(3 , 4, 5, 6)

range = range = (all real numbers)

range = {3}, range = (all real numbers)

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The interval containing the middle 95% of the simulation data is approximately 0.3426 to 0.5374.

To create an interval containing the middle 95% of the data based on the simulation results, we can use the concept of confidence intervals. Since the simulation was repeated 100 times, we can calculate the proportion of tails in each set of 100 flips and then find the range that contains the middle 95% of these proportions.

Let's calculate the interval:

Calculate the proportion of tails in each set of 100 flips:

Proportion of tails = 44/100 = 0.44

Calculate the standard deviation of the proportions:

Standard deviation = sqrt[(0.44 * (1 - 0.44)) / 100] ≈ 0.0497

Calculate the margin of error:

Margin of error = 1.96 * standard deviation ≈ 1.96 * 0.0497 ≈ 0.0974

Calculate the lower and upper bounds of the interval:

Lower bound = proportion of tails - margin of error ≈ 0.44 - 0.0974 ≈ 0.3426

Upper bound = proportion of tails + margin of error ≈ 0.44 + 0.0974 ≈ 0.5374

Therefore, the interval containing the middle 95% of the simulation data is approximately 0.3426 to 0.5374.

Now, we can compare the observed proportion of 44 tails in 100 flips with the simulation results. If the observed proportion falls within the margin of error or within the calculated interval, then it can be considered consistent with the simulation results. If the observed proportion falls outside the interval, it suggests a deviation from the expected result.

Since the observed proportion of 44 tails in 100 flips is 0.44, and the proportion falls within the interval of 0.3426 to 0.5374, we can conclude that the observed proportion is within the margin of error of the simulation results. This means that the result of 44 tails in 100 flips is reasonably likely to occur with a fair coin based on the simulation.

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The number of edges that the prism has is

When a plane intersects a prism, the shape formed is known as the cross section. The cross section of the prism will have the same form as the base if it is divided by a plane that runs horizontally and parallel to the base.

A prism is a 3-dimensional object with two congruent and parallel bases (which are polyggonal) connected by rectangular lateral faces. The number of edges of a prism is equal to the sum of the number of edges of the two bases and the number of lateral faces.

Each base of the prism has n edges, so the two bases together have 2n edges. The number of lateral faces of the prism is equal to the number of edges of one of its bases, so there are n lateral faces. Each lateral face has 4 edges, so the total number of edges of the lateral faces is 4n.

Therefore, the total number of edges of the prism is equal to the sum of the number of edges of the two bases (2n) and the number of lateral faces (4n), which is 2n + 4n = 6n.

In conclusion, the cross section of a prism is an n-sided polygon and the prism has n + 2 edges.

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Answer:

Step-by-step explanation:

first we add them altogether:

0.25+0.17+0.21+0.03 = 0.66

than we subtact the 0.66 from the whole (1) =

1-0.66= 0.34

So, in response to the above question, we can state that They gathered a total equation of s + 2s = 3s shells.

A mathematical equation links two statements and utilises the equals sign (=) to indicate equality. In algebra, an equation is a mathematical assertion that proves the equality of two mathematical. For examples, in the equation 3x + 5 = 14, because equal sign separates the numbers by a gap. A mathematical formula may be used to determine how the two sentences on either side of a letter relate to one another. The emblem and the particular piece of software are usually identical. like, for instance, 2x - 4 = 2.

In the case where Anna gathered s shells and her brother gathered twice as many, the brother gathered 2s shells.

They gathered a total of s + 2s = 3s shells.

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The domain and range are the set of x and values of the function are in the table.

the function as a table,

Input (x) | Output (y)

-3         |        -4

-1          |         2

0         |         0

-3         |         5

2         |         4

What is the domain and range?

The domain and range are fundamental concepts in mathematics that are used to describe the input and output values of a function or relation.

The domain of a function refers to the set of all possible input values, or x-values, for which the function is defined.

The range of a function refers to the set of all possible output values, or y-values.

To find the domain and range of functions and represent them in different formats.

To find the domain and range of a function:

The domain refers to the set of all possible input values (x-values) for the function.

The range refers to the set of all possible output values (y-values) for the function.

To represent the function as a table, you would list the input-output pairs. For example:

Input (x) | Output (y)

-3         |        -4

-1          |         2

0         |         0

-3         |         5

2         |         4

To represent the function as a mapping, you would indicate the correspondence between the input and output values.

For example:

-3     ->   -4

-1     ->     2

0     ->     0

-3    ->     5

2     ->     4

To represent the function as a graph, The x-values would be on the horizontal axis, and the y-values would be on the vertical axis.

The points (-3, -4), (-1, 2), (0, 0), (-3, 5), and (2, 4) would be plotted accordingly.

Hence, The domain and range are the set of x and values of the function are in the table.

the function as a table,

Input (x) | Output (y)

-3         |        -4

-1          |         2

0         |         0

-3         |         5

2         |         4

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Answer: Answer is 6.11

Step-by-step explanation:

Lets solve this equation (2x-1)+4x+(12x+5)=114

step 1: we first add x variables

          ie. 2x + 4x + 12x = 18x

step 2: we add numbers

          ie. -1 + 5 = 4

step 3: now we arrange LHS part

         ie.  18x + 4 = 114

step 4: now move this 4 to right hand side and simplify them

         ie. 18x = 114 - 4 = 110

step 5: now we divide 110 by 18 to get the value of x

         ie. x = 110/18 = 6.11

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Answer:

Richard is older

Step-by-step explanation:

We can set up an inequality for both statements.

Let r equal Richard's age and s equal Sylvia's age.

"I am older than my wife."

Since Richard is speaking, the inequality would look like this:

r > s

This means Richard is older than Sylvia.

"I am younger than my husband."

Since Sylvia is speaking, the inequality would look like this:

s < r

This means that Sylvia is younger than Richard.

We can flip one inequality to "see" them from the same perspective.

Let's use s < r

To make it so that we can see the relationship from Richard's perspective, flip the entire inequality.

s < r

to

r > s

The inequality from the first quote is identical to this one!

Therefore, Richard is older than Sylvia.

Given the expression: (3.2+0.2)2+12​

To get the value of the expression, do the following:

1. add 3.2 and 0.2

2. multiply 3.4 by 2

3. add 6.8 and 12

So, the value of the expression = 18.8

The  correct relation symbol

1. LN < RN

2.  LR > LN

3. RN > LN

4. m∠L < m∠N

5. m∠N = m∠R

To determine the correct relation symbols in the given situations, we need to compare the given values in the triangle ∆LRN.

A. In ∆LRN, m∠L = 61° and m∠R = 48°.

LN < RN: The measure of ∠L is greater than the measure of ∠R. By the angle-side relationship, this indicates that the side opposite ∠L (LN) is shorter than the side opposite ∠R (RN). Therefore, LN < RN.

LR > LN: The sum of the measures of ∠L and ∠R is greater than 180° (61° + 48° = 109°), indicating that ∆LRN is an obtuse triangle. In an obtuse triangle, the longest side is the one opposite the obtuse angle, which is LR. Therefore, LR > LN.

RN > LN: In a triangle, the length of any side is greater than the length of the side opposite the smaller angle. Since ∠L is greater than ∠R, the side opposite ∠L (LN) is shorter than the side opposite ∠R (RN). Therefore, RN > LN.

B. In ∆LRN, LN = 8cm, RN = 12cm, and LR = 15cm.

m∠L < m∠N: In a triangle, the measure of any angle is larger than the measure of the angle opposite the shorter side. Since LN is the shortest side, the angle opposite LN (∠L) will have a smaller measure than the angle opposite the longer side, which is ∠N. Therefore, m∠L < m∠N.

m∠N = m∠R: In an isosceles triangle, the angles opposite the equal sides are congruent. Since LR = LN, it indicates that ∆LRN is an isosceles triangle, and therefore, m∠N = m∠R.

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Answer:

The second choice

Step-by-step explanation:

Answer: Felipe's work!

Step-by-step explanation:

Answer:

19/3 (6 1/3)

Step-by-step explanation:

Answer:

11.78097

Step-by-step explanation:

When the value of n nickles plus d dimes is c cents, n in terms of d and c will be n = c - d.

It should be noted that an expression is simply used to show the relationship that can be illustrated based on the data.

In this case, we want to calculate the value of n nickles plus d dimes is c cents, what is n in terms of d and c.

This will be:

c = n + d

Therefore, to get n will be calculated thus:

Subtract d from both sides.

c - d = n + d - d

n = c - d

Therefore, when the value of n nickles plus d dimes is c cents, n in terms of d and c will be n = c - d.

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The procedure that should be conducted to directly address this research question is the one sample proportion z test. This is because the research question is about the proportion of ring-tailed lemurs that are left hand dominant, which is a categorical variable. The sample size is greater than 30, so the central limit theorem can be applied and the distribution of the sample proportion can be assumed to be approximately normal. Therefore, a one sample proportion z test can be used to test whether the proportion of left hand dominant ring-tailed lemurs is greater than 0.5.

The one sample proportion z test is a statistical test used to determine whether a sample proportion is significantly different from a hypothesized population proportion. This test requires a categorical variable and a sample size greater than 30 in order to apply the central limit theorem and assume normality of the distribution of the sample proportion. The test statistic is calculated by subtracting the hypothesized population proportion from the sample proportion and dividing by the standard error of the sample proportion.

To directly address the research question of whether more than half of all ring-tailed lemurs are left hand dominant, a one sample proportion z test should be conducted. This test is appropriate for a categorical variable with a sample size greater than 30 and assumes normality of the distribution of the sample proportion. The test will determine whether the proportion of left hand dominant ring-tailed lemurs is significantly different from 0.5, which is the null hypothesis.

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