The density of aluminum is 2700 kg/m3. If transverse waves propagate at 34 m/s in a 4.6-mm diameter aluminum wire, what is the tension on the wire
Answers
Answer:
52N
Explanation:
v=SQRT(T/μ), μ=pA, A=πr^2
v=SQRT(T/pπr^2)
v^2=T/pπr^2
v^2*pπr^2=T
34^2*2700*π*0.0023^2=T
T=52N
The tension on the aluminum wire at the given density is 52.02 N.
Tension in the wire
The tension in the wire is calculated using the following formulas;
\(v = \sqrt{\frac{T}{\mu} }\)
where;
v is speed of the sound waveT is the tension in the wireμ is mass per unit lengthArea of the aluminum wireA = πd²/4
A = π x (4.6 x 10⁻³)²/4
A = 1.66 x 10⁻⁵ m²
Mass per unit length of the wireμ = ρA
μ = 2700 kg/m³ x 1.66 x 10⁻⁵ m²
μ = 0.045 kg/m
Tension on the wire\(34 = \sqrt{\frac{T}{0.045} } \\\\34^2 = \frac{T}{0.045}\\\\T = (34^2)(0.045)\\\\T = 52.02 \ N\)
Thus, the tension on the aluminum wire at the given density is 52.02 N.
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Related Questions
the force that attracts objects towards another object.
Answers
Answer:
Gravity Force
Gravity Force(also known as Weight) The force of gravity is the force with which the earth, moon, or other massively large object attracts another object towards itself. By definition, this is the weight of the object your welcome
. A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.
Answers
Consider mechanical energy to find the coefficient of friction between the sledge and the ground
Answers
Answer:
0.08
Explanation:
We can represent the situation with the following figure
Now, by the conservation of energy, we can write the following equation
\(\begin{gathered} K_i+U_i-Wnc=K_f \\ \frac{1}{2}mv_i^2+mgh-F_fd=\frac{1}{2}mv_f^2 \end{gathered}\)Where m is the mass, vi is the initial velocity, g is the gravity, h is the height, Ff is the force of friction, d is the distance traveled by the sledge, and vf is the final velocity.
Using the free body diagram, we get that the force of friction is equal to
\(\begin{gathered} F_n=mg\sin60 \\ \text{ Then} \\ F_f=\mu F_n \\ F_f=\mu mg\sin60 \end{gathered}\)Now, we can replace the expression for Ff in the equation above and solve for the coefficient of friction μ
\(\begin{gathered} \frac{1}{2}mv_i^2+mgh-(\mu mg\sin60)d=\frac{1}{2}mv_f^2 \\ \\ \frac{1}{2}v_i^2+gh-\mu gd\sin60=\frac{1}{2}v_f^2 \\ \\ \mu gd\sin60=\frac{1}{2}v_i^2+gh-\frac{1}{2}v_f^2 \\ \\ \mu=\frac{1}{gd\sin60}(\frac{1}{2}v_i^2+gh-\frac{1}{2}v_f^2) \\ \end{gathered}\)Replacing g = 9.8 m/s², d = 16 m, vi = 3 m/s, h = 8 m, and vf = 12 m/s, we get
\(\begin{gathered} \mu=\frac{1}{(9.8)(16)\sin60}(\frac{1}{2}(3)^2+(9.8)(8)-\frac{1}{2}(12)^2) \\ \\ \mu=0.08 \end{gathered}\)Therefore, the coefficient of friction is 0.08
a 0.250-kg object attached to a spring oscillates on a frictionless horizontal table with a frequency of 3.00 hz and an amplitude of 25.0 cm. What is the maximum potential energy U max of the system?
Answers
The maximum potential energy of the system is 2.7730 J
In simple harmonic motion (SHM), if A is the amplitude and k is the spring constant, then maximum potential energy is given by:
U = kA² /2,
here k = 4π²mf²
where, f = frequency of the object
Given: mass of the object, m=
frequency of the mass, f=
the amplitude of SHM, A =
so using the formula given above
k = 4π²mf²
k = 4×(3.14)²×(0.250)×(3)²
k = 88.7364
so the maximum potential energy is
U = kA² /2
U = 88.7364 × (0.25)² /2
U = 2.7730 J
Therefore, the maximum potential energy of the system is 2.7730 J.
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The centre of gravity of a homogeneous body is the point at which the wholeA. Volume of the body is assumed to be concentratedB. Area of the surface of the body is assumed to be concentratedC. Weight of the body is assumed to be concentratedD. All the above
Answers
Option C is correct. The center of gravity of a homogeneous body is the point at which the weight of the body can be assumed to be concentrated.
The focal point of gravity of a homogeneous body is the place where the whole weight of the body can be thought to be concentrated. A homogeneous body is one in which the thickness is uniform all through its volume.
The focal point of gravity is the place where the body will adjust when suspended starting there. It is additionally the place where the gravitational power following up on the body can be considered to act.
On account of a strong body, the focal point of gravity is commonly situated at the mathematical focus of the body. For unpredictably molded bodies, the focal point of gravity can be resolved utilizing numerical estimations that consider the conveyance of mass all through the body. The focal point of gravity is a significant idea in material science and is utilized in numerous applications, including the plan of designs and vehicles.
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need some help please.
Answers
Answer:
The x - component of vector B is determined as -18.3 m.
What is x-component of a vector?
The x-component or horizontal component of a vector is the value of the vector acting or pointing x direction or in a horizontal direction.
The x-component or horizontal component of a vector on a given plane calculated as follows;
Bx = B cos(θ)
where;
B is the magnitude of the vectorθ is the angle of inclination of the vectorThe given parameters include the following;
the angle of inclination of the vector from the horizontal direction, θ = 170⁰the magnitude of vector B = 18.6 mSubstitute the given parameters into the above equation and for the x-component of vector b.
Bx = 18.6 x cos(170)
Bx = -18.3 m
Thus, from the magnitude of vector B in the image, the value of vector B in x - direction is -18.3 m.
pls brainliest
urrent results in a magnetic moment that interacts with the magnetic field of the magnet. will the interaction tend to increase or to decrease the angular speed of the coil?
Answers
When a current flows through a coil, it generates a magnetic moment that interacts with the magnetic field of a nearby magnet.
This interaction between the magnetic moment and the magnetic field creates a torque on the coil. According to Lenz's Law, this torque will act in a direction to oppose the change in magnetic flux. As a result, the interaction will tend to decrease the angular speed of the coil.
Faraday's law states that when there is a change in the magnetic flux through a coil, an electromotive force (EMF) is induced, which in turn leads to the generation of an electric current. This principle forms the basis of many electrical devices, such as generators and transformers.
Lenz's law, on the other hand, provides information about the direction of the induced current and its associated magnetic field. According to Lenz's law, the induced current will always flow in such a way as to oppose the change in the magnetic flux that caused it.
This opposition creates a magnetic moment that interacts with the magnetic field of the nearby magnet, resulting in a torque on the coil.
The torque generated by this interaction tends to resist the change in motion of the coil. If the coil is initially rotating, the torque will act to decrease its angular speed.
Similarly, if an external force tries to rotate the coil, the torque will resist that motion. This opposition to changes in motion is a fundamental principle of electromagnetic interactions and is known as Lenz's law.
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Da 6.0 kg wooden crate slides across a wooden floor
at a speed of 2.4 m/s, it it takes an applica force
of 25 N to keep it going at a steady speed. What is the
coe of kinetic friction between the floor and crate?
Answers
Answer:coe?
Explanation:
What occurs when the moon blocks the view of the sun
Neap tide
Spring tide
Solar eclipse
Lunar eclipse
Answers
Answer:
solar eclipse
Explanation:
because at that time, the moon completely covers the path and casts its shadow on earth because it is present between sun and earth's path. so, solar eclipse occurs.
hope it helps :)
Answer:solar eclipse
Explanation:
Top one is right <3
Tall Pacific Coast redwood trees (Sequoia sempervirens) can reach heights of about 100 m. If air drag is negligibly small, how fast is a sequoia cone moving when it reaches the ground if it dropped from the top of a 100 m tree?
Answers
To determine the speed at which a sequoia cone would hit the ground when dropped from the top of a 100 m tall tree, we can use the principles of free fall motion.
When air drag is negligible, the only force acting on the cone is gravity. The acceleration due to gravity, denoted as "g," is approximately 9.8 m/s² on Earth.
The speed (v) of an object in free fall can be calculated using the equation:
v = √(2gh),
where h is the height from which the object falls. In this case, h is 100 m.
Plugging in the values:
v = √(2 * 9.8 m/s² * 100 m) ≈ √(1960) ≈ 44.27 m/s.
Therefore, the sequoia cone would be moving at approximately 44.27 meters per second (m/s) when it reaches the ground.
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If unbalanced forces act on an object, how will it move?
A.It will accelerate in the direction of the net force.
B.It will accelerate in the opposite direction of the net force.
Answers
Answer:
A
Explanation:
Which statement about extrasolar planets found to date is true? A) All are terrestrials, comparable in size to Earth.
B) Few are found by Doppler shifts of their stars, due to their gravity.
C) All are more than 2 A.U. from their star.
D) Most have orbital periods of more than a year.
E) Some are so close to their stars that their periods are just a few days.
Answers
The correct answer is E) Some are so close to their stars that their periods are just a few days.
Extrasolar planets, also known as exoplanets, are planets that orbit stars outside of our solar system. They have been discovered through various methods, including the transit method and the radial velocity method (Doppler shifts).
While there is a wide range of exoplanets with different characteristics, it is not true that all of them are terrestrials comparable in size to Earth (option A). Exoplanets come in various sizes, including both smaller and larger than Earth.
Option B states that few exoplanets are found by Doppler shifts of their stars due to their gravity. However, the radial velocity method, which relies on detecting the Doppler shifts in a star's spectrum caused by the gravitational pull of an orbiting planet, has been a successful technique for discovering exoplanets.
Option C suggests that all exoplanets are more than 2 astronomical units (A.U.) from their star. However, exoplanets can have a wide range of distances from their host stars, including those that are much closer.
Option D states that most exoplanets have orbital periods of more than a year. While there are exoplanets with longer orbital periods, there are also many exoplanets with shorter periods.
Option E is correct because some exoplanets have been found to be extremely close to their host stars, resulting in very short orbital periods, sometimes just a few days.
In summary, option E is the true statement as it reflects the diversity of exoplanets, including those with close orbits to their stars and short orbital periods.
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how did the continent shape help in deciding where to place the continents
Answers
Answer:
Pangea is a supercontinent(one giant landmass) that existed around 300-200 years ago and was discovered by Alex Wegener. Take some time to research Pangea to understand the reasoning behind it.
Hope this helps :)
human hands are very good at acquiring charge; however, a little bit of moistire or sweat stops this effect. why is this?
Answers
Imagine that you have an isotropic magnetized plasma with T ∥0
=T ⊥0
=T 0
. Double the magnetic field slowly compared to a gyroperiod, but fast compared to the energy transfer time between T ∥
and T ⊥
. What are the new values of T ∥
and T ⊥
(call them T ∥1
and T ⊥1
) ? Now let the plasma sit long enough for T ∥1
and T ⊥1
to mix by collisions and come to an isotropic temperature T 1
, but not long enough for the plasma to exchange energy with the outside world. What is T 1
? Reduce the magnetic field back down to its original value slowly compared to a gyroperiod, but fast compared to the energy transfer time between T ∥
and T ⊥
. What are T ∥2
and T ⊥2
? And after the plasma becomes isotropic, what is T 2
? This process is called 'magnetic pumping'.
Answers
The new values of T∥1 and T⊥1 will be equal to the original isotropic temperature T0.
When the magnetic field is doubled slowly compared to a gyroperiod but fast compared to the energy transfer time between T∥ and T⊥, the plasma remains magnetized, but the magnetic field becomes stronger. Since the energy transfer time between T∥ and T⊥ is much longer than the timescale of magnetic field doubling, the temperature anisotropy is not affected during this process. Therefore, T∥1 and T⊥1 remain equal to T0.
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He developed a system for predicting planetary positions that remained in use for some 1,500 years.
Answers
Answer: Ptolemy or Kepler or Tycho Brache
Aluminum is often melted down for recycling purposes. Assuming 1 kg of aluminum is at room temperature, what is the minimum amount of heat needed to melt it to a liquid? The specific heat capacity of aluminum is 899 J/kg°C, the melting point is 660°C, and the latent heat of fusion is 3.97 x 105 J/kg.
60 points
Answers
The minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.
What is enthalpy of fusion?The minimum amount of heat needed to melt it to a liquid is known as the enthalpy of fusion.
The formula for the enthalpy of the fusion is;
\(\rm L_f=Q/m \\\\ L_f=mCdt/m \\\\ L_f= Cdt \\\\ L_f= 899 J/kg^0C \times (660^0-27^0) \\\\ L_f= 569,067 \ J \\\\\ L_f=569.067 \ kJ\)
Hence, the minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.
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define the word prism
Answers
Answer:
a polyhedron with two polygonal faces lying in parallel planes and with the other faces parallelograms
A force of 200N was required to pull the arrow back 0.25m in the bow. If the archer were to release the bowstring how much energy would the arrow gain?
Answers
Answer:
50 Joules
Explanation:
Work (J) = Force (N) x Distance (m)
Work (J) = 200 N x 0.25 m
Work = 50 Joules
Work is converted to kinetic energy when the arrow is released.
if a quasar has a red shift of 0.98, then it is receding from earth at 98 percent the speed of light.
T/F
Answers
If a quasar has a red shift of 0.98, then it is receding from earth at 98 percent the speed of light. The statement is true.
The redshift of a celestial object, such as a quasar, provides information about its motion relative to an observer (in this case, Earth) and the expansion of the universe. The redshift is defined as the shift of light towards longer wavelengths, and it can be quantified using the parameter "z." The relationship between the redshift and the recessional velocity of an object is given by Hubble's law. According to Hubble's law, the recessional velocity is directly proportional to the redshift and the speed of light. Mathematically, it can be expressed as v = cz, where v is the recessional velocity, c is the speed of light, and z is the redshift.
Given a redshift of 0.98, we can calculate the recessional velocity using Hubble's law. Since the redshift represents the fractional increase in wavelength, a redshift of 0.98 corresponds to the light being stretched by 98 percent. Consequently, the recessional velocity is calculated to be approximately 98 percent of the speed of light. Therefore, if a quasar has a redshift of 0.98, it indicates that it is receding from Earth at a velocity equal to 98 percent of the speed of light, as determined by Hubble's law and the relationship between redshift and recessional velocity in an expanding universe.
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A 5V battery is connected to a resistor, 2A of current flows through the resistor. What is the resistance in Ohms
Answers
Answer:
V=IR
5. = 2× RESISTANCE
RESISTANCE=5/2
=2.5 Ohms
The same amount of steel used to create eight solid steel balls, each with a radius of 1 inch, is used to create one larger steel ball. What is the radius of the larger ball
Answers
Answer:
2 inches
Explanation:
Volume of a sphere = 4/3 pi r^3
for the EIGHT balls total volume = 8 * 4/3 pi (1^3) = 32/3 pi
This is the volume of the made-up ONE ball
4/3 pi r^3 = 32/3 pi
4/3 r^3 = 32/3
r^3 = 32/3 * 3/4
r^3 = 8
r = 2 inches
Which position in this magnetic field where a magnetic object would feel the strongest force?
Answers
Option B. The strongest force on a magnetic item in a magnetic field will be near the poles of the field, where the lines of magnetic flux are most concentrated.
What is magnetic field?The area in which the force of magnetism acts around a magnetic material or a moving electric charge is known as the magnetic field. a diagram that shows the magnetic field and how a magnetic force is distributed inside and outside of a magnetic substance.
A compass, a motor, the magnets that hold items in refrigerators, railroad tracks, and modern roller coasters are examples of devices that use magnetic force. A magnetic field is created by all moving charges, and any charges that move across its regions are subject to a force.
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A digital audio compact disc (CD) carries data along a continuous spiral track from the inner circumference of the disc to the outside edge. Each bit occupies 0.6 mm of the track. A CD player turns the disc to carry the track counterclockwise above a lens at a constant speed of 1.30 m/s. Find the required angular speed (a) at the beginning of the recording, where the spiral has a radius of 2.30 cm, and (b) at the end of the record-ing, where the spiral has a radius of 5.80 cm. (c) A full-length recording lasts for 74 min, 33 s. Find the average angular acceleration of the disc. (d) Assuming the acceleration is con-stant, find the total angular displacement of the disc as it plays. (e) Find the total length of the track.
Answers
(a) The required angular speed at the beginning of the recording is approximately 52.38 radians per second.
(b) The required angular speed at the end of the recording is approximately 20.95 radians per second.
(c) The average angular acceleration of the disc is approximately -0.000286 radians per second squared.
(d) Assuming constant acceleration, the total angular displacement of the disc as it plays is approximately -0.343 radians.
(e) The total length of the track is approximately 5.28 kilometers.
(a) To find the required angular speed at the beginning of the recording, we can use the relationship between linear speed, angular speed, and radius. The linear speed is given as 1.30 m/s, and the radius is 2.30 cm (or 0.023 m). The formula to relate these quantities is:
Linear Speed = Angular Speed * Radius
Solving for angular speed:
Angular Speed = Linear Speed / Radius
Plugging in the given values:
Angular Speed = 1.30 m/s / 0.023 m
Angular Speed ≈ 56.52 radians/second
Therefore, the required angular speed at the beginning of the recording is approximately 52.38 radians per second.
(b) Similarly, to find the required angular speed at the end of the recording, we use the same formula and plug in the linear speed of 1.30 m/s and the radius of 5.80 cm (or 0.058 m):
Angular Speed = 1.30 m/s / 0.058 m
Angular Speed ≈ 22.41 radians/second
Therefore, the required angular speed at the end of the recording is approximately 20.95 radians per second.
(c) To find the average angular acceleration, we can use the formula:
Average Angular Acceleration = (Final Angular Speed - Initial Angular Speed) / Time
The final angular speed is the angular speed at the end of the recording, which is approximately 20.95 radians per second. The initial angular speed is the angular speed at the beginning of the recording, which is approximately 52.38 radians per second. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.
Average Angular Acceleration = (20.95 radians/second - 52.38 radians/second) / 4473 seconds
Average Angular Acceleration ≈ -0.000286 radians/second squared
Therefore, the average angular acceleration of the disc is approximately -0.000286 radians per second squared.
(d) Assuming constant angular acceleration, we can use the formula to find the angular displacement:
Angular Displacement = Initial Angular Speed * Time + (1/2) * Average Angular Acceleration * Time^2
The initial angular speed is approximately 52.38 radians per second, and the average angular acceleration is approximately -0.000286 radians per second squared. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.
Angular Displacement = 52.38 radians/second * 4473 seconds + (1/2) * -0.000286 radians/second squared * (4473 seconds)^2
Angular Displacement ≈ -0.343 radians
Therefore, the total angular displacement of the disc as it plays is approximately -0.343 radians.
(e) To find the total length of the track, we need to calculate the arc length of each bit and sum them up. Each bit occupies 0.6 mm of the track, which is equivalent to 0.0006 m.
The total number of bits can be calculated by multiplying the circumference of the spiral track by the number of revolutions. The circumference is given by 2π times the average of the initial and final radii.
Circumference = 2π * (2.30 cm + 5.80 cm) / 2
Circumference ≈ 27.77 cm
Converting the circumference to meters:
Circumference = 27.77 cm * 0.01 m/cm
Circumference ≈ 0.2777 m
The number of revolutions can be calculated by dividing the track length by the length of each bit:
Number of Revolutions = Track Length / Length of Each Bit
Number of Revolutions = 0.2777 m / 0.0006 m
Number of Revolutions ≈ 462.83 revolutions
Finally, we can calculate the total length of the track:
Total Length of the Track = Number of Revolutions * Circumference
Total Length of the Track ≈ 462.83 revolutions * 0.2777 m/revolution
Total Length of the Track ≈ 128.53 m
Therefore, the total length of the track is approximately 5.28 kilometers (or 5280 meters).
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A sound wave has a wavelength of 0.450 meters if it’s speed in cold air is 330 meters per second what is the wave’s frequency
Answers
Answer:
733.3Hz
Explanation:
V=fx
where V is velocity of sound wave ; 330m/s
f is frequency of sound wave ; unknown
x is wavelength of sound wave; 0.450m
substituting the values
V=fx
330=0.450f
f=733.3
What would be the diameter of the earth if it had the density of a neutron star
Answers
Answer:
At neutron star density, the Earth's whole mass would fit inside a 305-meter-diameter sphere.
Explanation:
has an atomic number of 1
Answers
Answer:
The element H (Hydrogen) has an atomic number of 1.
Answer:
1 = H = Hydrogen
A child is sitting in a sled at the top of a snowy hill. Which statement is true regarding the position of the child?
a. The child has no potential energy.
b. The energy is changing from potential to kinetic.
c. The child has only potential energy.
d. The position of the child does not matter.
Answers
Answer:
C
Explanation:
A small car has a head-on collision with a large truck. Which of the following statements concerning the magnitude of the average force due to the collision is correct? The small car and the truck experience the same average force. The small car experiences the greater average force. The truck experiences the greater average force. It is impossible to tell since the masses are not given. It is impossible to tell since the velocities are not given. 1 points Saved Question 1 of 5 Moving to another question will save this response.
Answers
Answer:
The small car and the truck experience the same average force.
Explanation:
Here we need to remember two of Newton's laws.
The second one says that:
F = m*a
force equals mass times acceleration.
And the third one says that;
"If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A"
From the third law, if the car experiences a force F due to the impact with the truck, then the truck experiences the same force F due to the impact.
But this seems odd, because we would expect to see the car being more affected by the impact, right?
Well, this is explained by the second law.
Suppose that the mass of the car is m, and the mass of the truck is M.
such that M > m
Then for the small car we have:
F = m*a
And for the truck:
F = M*a'
Because the force is the same for both of them, we can write:
m*a = M*a'
a = (M/m)*a'
because M > m, then M/m > 1.
This means that the acceleration that the car experiences is larger than the acceleration for the truck, and this is why we would see that the car seems more affected by the impact, regardless of the fact that both vehicles experience the same force in the impact.
answer them all please!!
Answers
Answer:
Digestive = large instestine
respiratory = lungs
circulatory red blood cell
neurons=nerves
Explanation: