The colour observed hrainbow during on the lower side of a a sunny rainy day is​

The mass of nickel is 36.5g metal.

Ni+2AgNO3 → Ni(NO3)2+2Ag

21.5g Ni / 58.69g = 0.366mol Ni

Ag = 107.87

N i= 58.69

But, 2molAg per 1 mol Ni, so, change in mass is more like...

Twice as many moles Ag as Ni, and then the mass relationship is 107.87g Ag / 58.69, but due to the 2Ag: 1Ni mol ratio, the change in mass is like:

107.87(2) / 58.69 = 3.68 times increase

So, the final mass of Ag is 3.68x, and the change in mass of Ni is x

36.5=(21.5-x)+(3.68x)

Solve for x

x=5.597

3.68x=g Ag

3.68(5.597)=20.59

21.5 - x = g Ni after reaction

21.5 - 5.597 = 15.903g Ni

20.59g Ag + 15.903g Ni = 36.5g metal

The mass of nickel is 36.5g metal.

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The enthalpy change for the process MgSO₄ + NaOH → Mg(OH) + Na₂SO₄ is 132.065 J/mol.

Total volume of the solution:

= 50 + 50

= 100mL

Mass of the solution (water) = 100mL × 1gm/mL = 100gm

Heat absorbed by the solution

= 100gm ×  4.18 J/°C/gm ×  (29.3-23.2)

=2549.8 J

Heat absorbed by the calorimeter:

= 15J/°C ×  (29.3-23.2) = 91.5 J

Total heat absorbed:

= 2549.8 J + 91.5 J

= 2641.3 J

Moles of MgSO4 =1.00M/0.05 L = 20mol

Enthalpy of reaction per mole of MgSo4 reacted = 2641.3 J ÷ 20mole

= 132.065 J/mol

Thus, enthalpy change for the process  MgSO₄ + NaOH → Mg(OH) + Na₂SO₄ is 132.065 J/mol.

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Answer: 0.3 moles NH3

Explanation:

Percent Yield can be calculated as the actual yield divided by the theoretical yield times 100.

Percent Yield can be defined as the actual yield divided by the theoretical yield times 100. There are so many reasons why the actual yield of a chemical reaction may be less than the theoretical yield of the reaction. This yield is the percent ratio of experimental yield to the theoretical yield. It is calculated as experimental yield divided by theoretical yield multiplied by 100%. If the experimental and theoretical yield are having the same value, the percent yield is 100% of the reaction. It indicates how much product is left-over and help you formulate a plan to create less waste during the chemical reactions.

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Complete question is,

How to calculate the percent yield for the reaction ?

Answer:

207g

Explanation:

Given compound:

            Ca(ClO₃)₂

The equivalent mass can be derived by summing the molar masses of each atom

  Molar mass of Ca = 40

                            Cl  = 35.5

                            O  = 16

Now solve;

 Molar mass  = 40 + 2(35.5 + 3(16)) = 207g

Soil erosion is basically the soil being deteriorated by the gradual impact of water or wind to it, being a very mechanical situation, where water or wind will hit the soil, detaching some particles and making the soil weaker. The main cause will be hits from water or wind. Deforestation will have a huge impact on erosion, since the soil where trees are taken down is more likely to receive impacts from wind or water, if the trees were left in their place, they would be used as a "shield" for the soil

The principal organic product formed on reaction of benzyl bromide with each of the following reagents is as follows:

a. Sodium ethoxide: benzyl alcohol

b. Potassium tert-butoxide: tert-butyl benzyl ether

c. Sodium azide: No reaction occurs between benzyl bromide and sodium azide.

d. Sodium hydrogen sulfide: benzenesulfinic acid

e. Sodium iodide (in acetone): No reaction occurs between benzyl bromide and sodium iodide in acetone.

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It is solubility which is the maximum amount of solute that may dissolve in a known volume of solvent at a specific temperature. The value of Ksp for Ni₃(PO₄)₂ is 3.27 × 10⁻¹⁶.

The equilibrium constant for the dissolution of a solid substance into an aqueous solution is the solubility product constant. Ksp is used to represent it. A type of equilibrium constant, the solubility product's value changes with temperature.

The dissociation of  Ni₃(PO₄)₂ is:

Ni₃(PO₄)₂ → 3Ni²⁺ + 2PO₄³⁻

The expression for the solubility product constant (Ksp) is:

Ksp = [Ni²⁺]³[PO₄³⁻]²

Solubility = 8.0 × 10⁻⁴ m

Ksp = [8.0 × 10⁻⁴ ]³[8.0 × 10⁻⁴ ]²

Ksp = 3.27 × 10⁻¹⁶

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The quantity of heat released when when 15.7 g of benzene in the liquid phase at 50.0 °c is converted to solid benzene at 2.0 °c. molar mass of benzene is 11.37708 KJ.

Energy = nCp,liquid(T,bp - T₁) + nΔH + nCp,gas(T₂ - T,bp)

where

n is the number of moles

T,bp is the boiling point of benzene at 80.1°C

Cp,liquid = 134.8 J/mol·°C

Cp,gas = 82.44 J/mol·°C

ΔH = 87.1 J/mol

Energy = (3.12 moles)(134.8 J/mol·°C)(80.1°C - 75.1°C) + (3.12 moles)(87.1 J/mol) + (3.12 moles)(82.44 J/mol·°C)(115.1°C - 80.1°C)

Energy = 11,377.08 J

It smells pleasant and is quite combustible. Benzene swiftly disappears into the atmosphere. Its vapor can descend into low-lying locations since it is heavier than air. Benzene floats on top of water and barely slightly dissolves in it.

One of the fundamental petrochemicals, benzoene is a component of crude oil that occurs naturally. Benzene is categorized as an aromatic hydrocarbon because of the cyclic continuous pi bonds that exist between the carbon atoms. PhH is a common abbreviation. The stench near gas stations is partly caused by benzene, a colorless, extremely combustible chemical that has a sweet scent.

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Heptane is limiting while oxygen is in excess. The mass of carbon dioxide produced would be 9,223.62 grams, while excess oxygen would measure 14,461.12 grams

From the equation of the reaction:

C7H16 + 11O2 --> 7CO2 + 8H2O

Mole ratio of C7H16 to O2 = 1:11

Mole of 3000 g heptane = 3000/100.21

                                           = 29.94 moles

Mole of 25000 g O2 = 25000/32

                                    = 781.25 moles

Thus, O2 is in excess and heptane is limiting.

Mole ratio of heptane and CO2 = 1:7

equivalent mole of CO2 = 29.94 x 7 = 209.58 moles

Mass of 209.58 moles CO2 = 209.58 x 44.01

                                               = 9223.62 grams

Excess mole of O2 = 781.25 - (29.94x11)

                                = 781.25 - 329.34 = 451.91 moles

Mass of 451.91 moles of O2 = 451.91 x 32

                                              = 14,461.12 grams excess oxygen.

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The each of the four quantum numbers and property of orbitals or electrons each describes are :

1) Principle quantum number : the principle denoted by, n. the principle quantum number describes the energy level of electrons. like 3d subshell , n= 3

2) angular quantum number : angular quantum number describes the shape of the sub shell. example , l = 0,1,2,3.....    s,p,d,f

3) magnetic quantum number , ml : describes the orientation of the orbitals. for l = 1 . ml = -1 0 +1

4) spin quantum number ms:  describes the spin of the electrons. there are two possible value of spin quantum number . ms = + 1/2 for up and ms = - 1/2 for down spin.

Thus, The each of the four quantum numbers and property of orbitals or electrons each describes are :

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The molar concentration of Al(OH)₃ in the solution is 1.61 M.

we need to calculate the number of moles of Al(OH)3 in the solution:

Number of moles of Al(OH)₃ = mass of Al(OH)3 / molar mass of Al(OH)3

Molar mass of Al(OH)₃ = (1 x atomic mass of Al) + (3 x atomic mass of O) + (3 x atomic mass of H)

Molar mass of Al(OH)₃ = (1 x 26.98 g/mol) + (3 x 16.00 g/mol) + (3 x 1.01 g/mol) = 78.00 g/mol

Number of moles of Al(OH)₃ = 62.7 g / 78.00 g/mol = 0.804 moles

Next, we need to calculate the volume of the solution in liters:

Volume of solution = 500.0 mL = 500.0 mL x (1 L/1000 mL) = 0.500 L

Finally, we can calculate the molar concentration of Al(OH)₃

Molarity = moles of solute/volume of solution in liters

Molarity = 0.804 moles / 0.500 L = 1.61 M

Therefore, the molar concentration of Al(OH)₃ in the solution is 1.61 M.

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The statement "Throwing overweight and underweight balls will help the pitcher gain strength in their arm" is an inaccurate explanation for this training.

Overweight and underweight balls balls may help a pitcher generate more velocity, but they will not necessarily make them more accurate which in fact, throwing weighted balls can be detrimental to a pitcher's accuracy because the ball has a different center of gravity than a standard regulation ball. This can cause the ball to travel in unexpected directions when the pitcher releases it. Furthermore, throwing weighted balls can also lead to arm fatigue, which can in turn lead to a decrease in accuracy. Therefore, while weighted balls can be used to increase velocity, they will not necessarily make a pitcher more accurate.

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complete question: A standard baseball has of a mass of 145 grams. Your school's star pitcher is preparing for his senior season and anticipating being signed to play with a college team. As a tool to gain velocity, the coach has him on a training schedule using weighted balls. The standard program involves throwing regulation balls (145 g) as well as overweight and underweight balls. Which statement is an inaccurate explanation for this training?

A) Weighted balls will increase the pitcher's velocity.

B) Training with overweight and underweight balls will help the pitcher gain control of the ball.

C) Throwing weighted balls will help the pitcher increase the speed at which they can throw the ball.

D) Throwing overweight and underweight balls will help the pitcher gain strength in their arm.

Europeans wanted to trade things for rubber and oil with Africa

Answer:

200Joules

Explanation:

W=Fd                                                                                                                                         W=10×20                                                                                                                             W=200J

Answer:

HFusion*mass + Spec.Heat*mass*ΔT + HVap*mass

80cal/g*50.0g + 1.00cal/g°C*50.0g*(100°C-0°C) + 540cal/g*50g

3.60x10⁵cal

Explanation:

Using the HFusion we can find the heat needed to convert the ice to liquid water.

With specific heat capacity we can find the heat needed to increase the temperature of water from 0 to 100°C.

With HVap we can find the heat to convert the liquid water into steam.

The equations are:

Computing the values:

36000cal =

The Combustion is the the limiting reactant.

What is combustion ?

The generation of heat and light in the form of flame together with a chemical reaction that often entails the presence of oxygen. When a substance interacts with oxygen, a chemical reaction known as combustion occurs that generates heat. Among them are ethane, wood, and propane. The word for these compounds is exhaust. The majority of the exhaust is produced by chemical processes involving fuel and oxygen.

What is reaction ?

In a chemical reaction, one or more chemicals change into one or more other substances. For instance, the reaction between iron and oxygen results in rust. Sodium acetate, carbon dioxide, and water are the end products of the reaction between vinegar and baking soda.

Therefore, the Combustion is the the limiting reactant.

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Answer:

One Hectometer is 10,000 centimeters. So multiply your hectometer by 10,000, and that's your conversion. Your answer is 590.

The percent yield of norborneol is approximately 82.2%.

To calculate the percent yield, we use the formula: percent yield = (actual yield / theoretical yield) * 100%.

First, we need to determine the theoretical yield, which is the amount of norborneol that would be produced if the reaction proceeded with 100% efficiency.

The balanced equation for the hydration reaction of norbornene to norborneol is not provided, so we cannot determine the stoichiometry of the reaction.

Assuming the reaction proceeds according to a 1:1 stoichiometry, the theoretical yield of norborneol would be equal to the amount of norbornene used in the reaction (1.245 grams).

Now, we can calculate the percent yield using the actual yield (1.0230 grams) and the theoretical yield (1.245 grams): percent yield = (1.0230 / 1.245) * 100% ≈ 82.2%.

Therefore, the percent yield of norborneol from the hydration reaction is approximately 82.2%.

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Answer:

12?

Explanation:

Answer:

8

Explanation:

haploid is half

The atomic number of this atom is 3.

Atomic Number =Number of Protons .

Here protons=3, Neutrons=4 and Electrons=3. So, The atomic number of this atom is 3.

The charge number of an atomic nucleus is the chemical element's atomic number, also known as nuclear charge number (symbol Z). This is equivalent to the proton number (np), or the number of protons present in the nucleus of each atom of that element, for conventional nuclei.

Ordinary chemical elements can be uniquely identified by their atomic number. The atomic number and the number of electrons are both equal in a regular, uncharged atom.

The atomic mass number A of a regular atom is calculated by adding its neutron number N and neutron number Z. Since the mass of electrons is negligible for many uses, protons and neutrons have roughly equal masses, thus the mass defect of a nucleon.

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Answer:

3 electrons

Explanation:

Nitrate needs 3 electrons to achieve a stable electron configuration

Three is the answer. it needs three to complete its shell

To determine the number of moles of Cl in a 27.8-gram sample of CFCl3, we need to use the molar mass of CFCl3 and the molar mass of Cl to calculate the moles of Cl present.

The molar mass of \(CFCl_3\) (chlorofluorocarbon-11 or CFC-11) can be calculated by summing the atomic masses of its constituent elements. Carbon (C) has a molar mass of approximately 12.01 g/mol, fluorine (F) has a molar mass of about 19.00 g/mol, and chlorine (Cl) has a molar mass of around 35.45 g/mol.

The molar mass of \(CFCl_3\) is thus:

(1 × molar mass of C) + (1 × molar mass of F) + (3 × molar mass of Cl)

= (1 × 12.01 g/mol) + (1 × 19.00 g/mol) + (3 × 35.45 g/mol)

= 12.01 g/mol + 19.00 g/mol + 106.35 g/mol

≈ 137.36 g/mol

Now we can use the molar mass of Cl (35.45 g/mol) to calculate the moles of Cl in the given 27.8-gram sample of \(CFCl_3\) using the formula:

moles of Cl = mass of sample (g) / molar mass of Cl (g/mol)

Substituting the values, we have:

moles of Cl = 27.8 g / 35.45 g/mol

≈ 0.784 mol

Therefore, there are approximately 0.784 moles of Cl in the 27.8-gram sample of \(CFCl_3\).

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Answer:

There is no conductivity because covalent solutes will not disassociate into ions when placed into a solution. Without ions, you can not conduct electricity. Hence the term "non-electrolyte"

Answer:

52.165 inches

Explanation:

hope it help

Answer:

52.2 inches

Explanation:

Answer:

Stamens

Explanation:

Answer:

The correct answer is quantitative data.

Explanation:

The value of data in the form of numbers of counts where each set of data exhibits a specific numerical value associated with it is termed as quantitative data. This information refers to any quantifiable knowledge, which can be used for statistical analysis and mathematical calculations so that decisions of real-life can be taken based on the mathematical outcomes. The quantitative data is used to find the solutions of the queries like how often, how much, or how many.  

In the given case, a botanist measured the growth of the plant for two weeks, and the outcome came in the form of numerical value. Thus, the knowledge she collected is known as quantitative data.  

Answer:

0.342 moles

145 moles

0.0239 moles

0.498 moles

Explanation:

To solve this you only need to follow this rule:

N = n x Na. For solving this questions, you just need to divide this values for Avogadro's Coasting, and it's done. Hope it helped!

The acid dissociation constant (Ka) for a monoprotic acid with a percent ionization of 1.45% in a 0.143 M solution is to be determined, expressed to three significant figures.

The percent ionization of an acid is defined as the percentage of the initial concentration of the acid that has dissociated into ions in solution. To calculate the Ka of the acid, we can use the equation for percent ionization:

\(\%Ionization =\frac{concentration\,of\,H+\,ions}{initial\,concentration\,of\, acid} \times 100\)

Since the acid is monoprotic, we can assume that the initial concentration of H+ ions is equal to the initial concentration of the acid. Therefore, we can rewrite the equation as:

\(\%Ionization =\frac{concentration\,of\,H+\,ions}{concentration\,of\, acid} \times 100\)

Substituting the given values, we get:

\(1.45\%=\frac{concentration\,of\,H+\,ions}{0.143M} \times 100\)

Solving for the concentration of H+ ions, we get:

Concentration of \(H+ ions = 1.45\% \times \frac{0.143 M}{100} = 0.00208 M\)

Now, we can use the equation for Ka:

\(Ka = \frac{[H+][A-] }{[HA]}\)

where [H+] is the concentration of H+ ions, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the undissociated acid. Since the acid is monoprotic, the concentrations of the conjugate base and undissociated acid are equal. Therefore:

\(Ka = \frac{ [H+]^2}{[HA]}\)

Substituting the values we have calculated, we get:

\(Ka = \frac{ (0.00208 M)^2}{(0.143 M - 0.00208 M)} = 1.23 \times x^{-5}\)

Therefore, the Ka for the monoprotic acid is \(1.23\times 10^{-5}\), expressed to three significant figures.

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