The circular concrete culvert rolls with an angular velocity of ω=0.44rad/s when the man is at the Part A position shown. At this instant the center of gravity of the culvert and the man is located at point G, and the radius of gyration about G is k G
​ =3.7ft. Determine the angular acceleration of the culvert. The combined weight of the culvert and the man is 50016 . (Figure 1) Assume that the culvert rolls without slipping, and the man does not move within the culvert. Express your answer to three significant figures and include the appropriate units.

The angular momentum of a 1kg rock held in place by against the inside wall of the rotating drum can be calculated using the formula L = mvr⊥, where L is the angular momentum, m is the mass, v is the linear velocity and r⊥ is the perpendicular radius from the axis of rotation to the line of motion of the rock. In this case, r⊥ is equal to the radius of the drum, which is 0.2 meters. The linear velocity can be found by multiplying the angular velocity by the radius, i.e. v = ωr. The angular velocity can be obtained by dividing 2π by the period of rotation, i.e. ω = 2π/T. Therefore, the angular momentum of the rock is:

If the period of rotation is 15 seconds, then the angular momentum of the rock is:

In physics, momentum or center is a quantity related to the speed and mass of an object.

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Answer:

GPEb=67.86% of initial GPE at point a

Explanation:

It depends on how massive the ball is, but I can still give an answer comparing original GPE at point A to new GPE at B

GPEa=m*9.8*140

GPEa=1372(m)

GPEb=m*9.8*95

GPEb=931(m)

GPEb=0.6786*GPEa

Answer:

1. wisest

2. more delicious

3. majestic (not sure about this one)

4. industrious

5. happiest

Answer:

the projection of a vector quantity, as force or velocity, along an axis.

Explanation:

Answer: To the right

Explanation:

8n is more strength then 6n periodt pooh ✨

When two children fight over a toy. One pulls with a force of 8N to the right. The other pulls with a force of 6N to the left then the net force on the toy would be 2 N to the right.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = ma

As given in the problem, two children fight over a toy. One pulls with a force of 8N to the right. The other pulls with a force of 6N to the left.

Net force = 8 - 6

                = 2 Newtons

Thus, the net force of the toy comes out to be 2 Newtons.

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3.if time=45mins,D=4km,2700secs,4000m then. S=d/t S=1.4m/s

Answer:

m = 100 kg

Explanation:

F = ma

120 = m × 1.2

m = 120 ÷ 1.2

m = 100 kg

Answer:

9.75 x 10^4 J

Explanation:

Work done, W = 9.75 x 10^4 J

According to the work energy theorem, the change in kinetic energy is equal to the work done by all the forces.

So, here work done is 9.75 x 10^4 J so the change in kinetic energy is 9.75 x 10^4 J.

Answer:

Explanation:

To calculate the height of the table in this scenario, we can use the equations of motion. Let's define the variables first:

Initial velocity (u) = 2.50 m/s (given)

Time taken to reach the floor (t) = 0.391 s (given)

Acceleration due to gravity (g) = 9.8 m/s² (assuming the ball falls freely near the surface of the Earth)

Now, we can use the kinematic equation:

h = u * t + (1/2) * g * t²

Plugging in the given values, we have:

h = (2.50 m/s) * (0.391 s) + (1/2) * (9.8 m/s²) * (0.391 s)²

Simplifying the equation:

h = 0.97875 m + 0.07511 m

h = 1.05386 m

Therefore, the height of the table is approximately 1.05386 meters.

Answer:

The time it will take for the driver to reach Ottawa is 3 hours 32 minutes and 45 seconds

Explanation:

The given parameters are;

Speed of the car = 120 km/h

Distance from Toronto to Ottawa = 425.5 km

The formula for speed is given as follows;

Speed = Distance/Time

Therefore, to find the time duration it takes from Toronto to Ottawa, we have;

Time duration = Distance from Toronto to Ottawa/(Speed of the car)

The time duration = 425.5/120 = 3.54583 hours = 212.75 min = 12765 seconds

The time it takes from Toronto to Ottawa while driving at 425.5 km/h = 12765 seconds.

Answer:

The object will continue to move with a constant velocity.

Explanation:

Hope this helps you :)

Answer: 1.5 × 10^-17

Explanation:

Given the following :

Frequency(f) = 2.2 × 10^16 Hz

Planck's constant(h) = 6.63 × 10^-34

The energy of a photon 'E' is given as the product of frequency and the planck's constant

E = hf

E = (6.63 × 10^-34) × (2.2 × 10^16)

E = 6.63 × 2.2 × 10^(-34 +16)

E = 14.586 × 10^-18

E = 1.4586 × 10^-17

E = 1.5 × 10-17 (2 S. F)

Answer:

C. 1.5 × 10–16 J

Explanation:

In a merry-go-round rotating at constant angular speed, two children Ana and Bobby are riding at different points A and B, respectively.

The linear velocity of a point on a rotating object depends on its distance from the center of rotation and the angular velocity of the object. The farther a point is from the center of rotation, the greater its linear velocity.

Therefore, the child riding at the outermost point, which is Bobby in this case, will have a greater magnitude of linear velocity compared to the child riding at the innermost point, which is Ana.

Thus, option (b) is correct - Bobby has the greater magnitude of linear velocity. This concept is important in understanding centripetal force and its effects on objects in circular motion.

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Answer:

lm.ao i was stuck too when i was on that

Explanation:

what u need to know sis?

speed, being a scalar quantity, is the rate at which an object covers distance. The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. On the other hand, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes.

Answer:

Explanation:

Answer:

because it helps to neutralize acid in our body.

Answer:

the answer is 4m/s = 3600 w

Answer:

direct current (DC) and alternating current (AC)

I'm not weather the answer is right or wrong....

Answer: 11 m/s

vinitial=2 m/s

time=3 s

acceleration = 3 m/s^2

vfinal = ?

The key here is that it is a constant acceleration, so we can use the constant acceleration equations. The easiest one to use would be:

vfinal=vinitial + a*t

We need vfinal, so algebraically we are ready to put in numbers into the equation:

vfinal=vinitial + a*t = 2 m/s + (3 m/s^2)*(3 s ) = 11 m/s is the final velocity

The ball's final velocity is 11 m/s

From one of equations of kinematics for linear motion

We have that

v = u + at

Where v is the final velocity

u is the initial velocity

a is the acceleration

and t is the time

From the given information in the question

u = 2 m/s

t = 3 secs

a = 3 m/s²

Putting these parameters into the above formula

v = u + at

We get

v = 2 + (3×3)

v = 2 + 9

v = 11 m/s

Hence, the ball's final velocity is 11 m/s

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457280.13 8 J change in gravitational potential energy is needed.

where

m = 68 kj

H = 2574 ft

where = 32 5 ft

a )if Gravitational potential energy is zero at see level .

then at strating

point,

Equation

G. P . E ( Ui ) = mgh

Change in G PE ;

AU = UJ - Vi

= mgy- mgh = mg ( H-h)

= 68 x9.81 [2574 - 325 0.3048

AU = 457280' 138 Joules

at top

GPE ( Uf ) = mgy

P . E = 0

GPF = Gravitational potential Energy .

at Top ape = 0

b)then change in GPE ;

ΔU = U(top) - Vata

= 0 - [-mg ( 4-h )]

= mg ( H-h j

= 68 * 9 . 81 [ 257 4 - 325 ) 0.3048

ΔU = 45 7280 . 13 8 J.

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Explanation:

hope it helps thanks

pls mark me as brainliest

Answer:

Meteorites Contain Magnesium-26

Brainliest Please!

The metalcore is the central component of any metal that is covered by wires. Metalcore is found in the X denoted area.

A solenoid is a coil of wire that conducts an electric current. A solenoid is an electromagnet made out of a wire or helical coil.

When an electric current is sent through the coil, it produces a magnetic field. A solenoid is a coil that generates a magnetic field when an electric current passes through it.

When a conductive wire is used to build a loop, a solenoid is formed.

Hence the metalcore is found in the given X area.

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Answer: b

Explanation:

edge

To solve this problem, we need to use conservation of energy. The spring has elastic potential energy due to being stretched, which will be transferred into kinetic energy as the glider moves.

At the release point, all of the potential energy will be converted into kinetic energy, so we can use the equation \(KE = 0.5mv^2 to solve for v.\)

We can also use the force required to hold the spring at 0.350 m to calculate the spring constant, k, using Hooke's Law (F = -kx).

Once we have k, we can calculate the maximum displacement of the glider (x = -0.100 m)

Use conservation of energy to solve for v. The correct answer is C) 2.87 m/s.

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A 70 kg person does a bungee jump from a bridge and falls straight down. The y-component of acceleration of the jumper is 1.6 m/s².

Given that,

Spring constant k is 80 N/m

Natural length of the bungee cord is 20 m

Total length of the bungee cord is 25 m

From Newton's second law of motion we know that, F = ma

By drawing a free body diagram we get,

Fe - W = m*a

where, Fe is elastic force, it can be written as k*Δx

k is the spring constant

Δx is the change in length of the cord

W is weight of the body acting downwards (mg)

Fe - W = m*a

k Δx - mg = ma

a = k/m (Δx) - g

a = k/m (x₁-x₀) - g

a = 80/70 (25-20) - 9.8

a = 11.43 - 9.8 = 1.6 m/s²

Thus, the acceleration of the jumper is 1.6 m/s².

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If the lens of our eyes were concave, we would not be able to see. We would be blind. This is because our eyes form a visual image on the same side of the lens at the object being viewed. Thus, a concave lens would result in the visual image focusing in front of the eye, not the retina inside the eye. This would mean that no signals would be sent to the brain, and vision would not be possible.

The momentum of the system before the collision 255 g⋅m/s.

In this case, the mass of the first cart is 250 grams, the velocity of the first cart is 0.42 m/s, the mass of the second cart is 500 grams, and the velocity of the second cart is 0.30 m/s.

The momentum of the first cart is:

momentum = 250 g × 0.42 m/s = 105 g⋅m/s

The momentum of the second cart is:

total momentum = 105 g⋅m/s + 150 g⋅m/s = 255 g⋅m/s

Therefore, the total momentum of the system before the collision is 255 g⋅m/s.

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The block would accelerate down the inclined plane. The force applied is greater than the maximum force of static friction. The correct answer is (B).

Angle of inclination of plane, θ = 30, Coefficient of static friction, µs = 0.2, Coefficient of kinetic friction, µk = 0.2The block is stationary, A block (A) remains stationary on the inclined plane, which implies that the force of static friction fsmax acting upwards balances the force of gravity mgsinθ acting downwards.

Using the formula of maximum force of static friction, we get; fsmax = µs x mg cosθ = 0.2 x mg x cos 30 ......(1)Also, the maximum force of static friction, in this case, is less than the force of gravity acting downwards. Hence, the block will slide down the incline.

On substituting the values in eq. (1), we get; fsmax = (0.2) (9.8) (0.866) ≈ 1.69 N. The force of gravity acting on the block will be; Fg = mg sinθ = 0.5mg N. Since the force applied, Fapp is greater than fsmax, the block will accelerate down the plane. So, the correct answer is (B).

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I think it's 3

Explanation:

trust me bro