The chemical formula for phosphorus trichloride is PCl3. In one to two sentences, explain how you would build or draw a model of phosphorus trichloride. Include a description of the parts of the model.

Answer:

True

Explanation:

the independent variable would be like if the psychologist is experimenting the impact of sleep deprivation, sleep deprivation would be the independent variable that is being manipulated or changing its level systematically in the experiment.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The  equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)

A physical quantity that has both directions and magnitude is referred to as a vector quantity.

A lowercase letter with a "hat" circumflex, such as "û," is used to denote a vector with a magnitude equal to one. This type of vector is known as a unit vector.

According to the final position of the vector as shown in the figure, The final x co-ordinate is 4 and  the final y co-ordinate is 2.

the  equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)

Learn more about vector here:

https://brainly.com/question/24256726

#SPJ1

The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

Know more about Kinematic equation here:

https://brainly.com/question/24458315

#SPJ8

Explanation:

Equation for resistity

\(p(t)= p(0) \times (1 + a \times (change \: in \: temp))\)

\( = 0.02 \times {10}^{ - 6} \times (1 + 0.004 \times 60)\)

\( = 2.48 \times {10}^{ - 8} ohm \: m\)

\(r = (p \times l) \div a\)

\( = (2.48 \times {10}^{ - 8} \times 1200) \div \: 5 \times {10}^{ - 6} \)

\( = 5.952 \: ohms\)

a. I've attached a plot of the surface. Each face is parameterized by

• \(\mathbf s_1(x,y)=x\,\mathbf i+y\,\mathbf j\) with \(0\le x\le2\) and \(0\le y\le6-x\);

• \(\mathbf s_2(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf k\) with \(0\le u\le2\) and \(0\le v\le\frac\pi2\);

• \(\mathbf s_3(y,z)=y\,\mathbf j+z\,\mathbf k\) with \(0\le y\le 6\) and \(0\le z\le2\);

• \(\mathbf s_4(u,v)=u\cos v\,\mathbf i+(6-u\cos v)\,\mathbf j+u\sin v\,\mathbf k\) with \(0\le u\le2\) and \(0\le v\le\frac\pi2\); and

• \(\mathbf s_5(u,y)=2\cos u\,\mathbf i+y\,\mathbf j+2\sin u\,\mathbf k\) with \(0\le u\le\frac\pi2\) and \(0\le y\le6-2\cos u\).

b. Assuming you want outward flux, first compute the outward-facing normal vectors for each face.

\(\mathbf n_1=\dfrac{\partial\mathbf s_1}{\partial y}\times\dfrac{\partial\mathbf s_1}{\partial x}=-\mathbf k\)

\(\mathbf n_2=\dfrac{\partial\mathbf s_2}{\partial u}\times\dfrac{\partial\mathbf s_2}{\partial v}=-u\,\mathbf j\)

\(\mathbf n_3=\dfrac{\partial\mathbf s_3}{\partial z}\times\dfrac{\partial\mathbf s_3}{\partial y}=-\mathbf i\)

\(\mathbf n_4=\dfrac{\partial\mathbf s_4}{\partial v}\times\dfrac{\partial\mathbf s_4}{\partial u}=u\,\mathbf i+u\,\mathbf j\)

\(\mathbf n_5=\dfrac{\partial\mathbf s_5}{\partial y}\times\dfrac{\partial\mathbf s_5}{\partial u}=2\cos u\,\mathbf i+2\sin u\,\mathbf k\)

Then integrate the dot product of f with each normal vector over the corresponding face.

\(\displaystyle\iint_{S_1}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\int_0^2\int_0^{6-x}f(x,y,0)\cdot\mathbf n_1\,\mathrm dy\,\mathrm dx\)

\(=\displaystyle\int_0^2\int_0^{6-x}0\,\mathrm dy\,\mathrm dx=0\)

\(\displaystyle\iint_{S_2}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\int_0^2\int_0^{\frac\pi2}\mathbf f(u\cos v,0,u\sin v)\cdot\mathbf n_2\,\mathrm dv\,\mathrm du\)

\(\displaystyle=\int_0^2\int_0^{\frac\pi2}-u^2(2\sin v+\cos v)\,\mathrm dv\,\mathrm du=-8\)

\(\displaystyle\iint_{S_3}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\int_0^2\int_0^6\mathbf f(0,y,z)\cdot\mathbf n_3\,\mathrm dy\,\mathrm dz\)

\(=\displaystyle\int_0^2\int_0^60\,\mathrm dy\,\mathrm dz=0\)

\(\displaystyle\iint_{S_4}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\int_0^2\int_0^{\frac\pi2}\mathbf f(u\cos v,6-u\cos v,u\sin v)\cdot\mathbf n_4\,\mathrm dv\,\mathrm du\)

\(=\displaystyle\int_0^2\int_0^{\frac\pi2}-u^2(2\sin v+\cos v)\,\mathrm dv\,\mathrm du=\frac{40}3+6\pi\)

\(\displaystyle\iint_{S_5}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\int_0^{\frac\pi2}\int_0^{6-2\cos u}\mathbf f(2\cos u,y,2\sin u)\cdot\mathbf n_5\,\mathrm dy\,\mathrm du\)

\(=\displaystyle\int_0^{\frac\pi2}\int_0^{6-2\cos u}12\,\mathrm dy\,\mathrm du=36\pi-24\)

c. You can get the total flux by summing all the fluxes found in part b; you end up with 42π - 56/3.

Alternatively, since S is closed, we can find the total flux by applying the divergence theorem.

\(\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_R\mathrm{div}\mathbf f(x,y,z)\,\mathrm dV\)

where R is the interior of S. We have

\(\mathrm{div}\mathbf f(x,y,z)=\dfrac{\partial(3x)}{\partial x}+\dfrac{\partial(x+y+2z)}{\partial y}+\dfrac{\partial(3z)}{\partial z}=7\)

The integral is easily computed in cylindrical coordinates:

\(\begin{cases}x(r,t)=r\cos t\\y(r,t)=6-r\cos t\\z(r,t)=r\sin t\end{cases},0\le r\le 2,0\le t\le\dfrac\pi2\)

\(\displaystyle\int_0^2\int_0^{\frac\pi2}\int_0^{6-r\cos t}7r\,\mathrm dy\,\mathrm dt\,\mathrm dr=42\pi-\frac{56}3\)

as expected.

Given:

The intensity of unpolarized incident light is

It passes first through a polarizing filter with its axis vertical

The second polarising filter is at an angle of,

from the vertical

To find:

What light intensity emerges from the second filter ?

Explanation:

According to the Malus law, the emergent light intensity is,

Hence, the required intensity is

The correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

Energy balance refers to the way in balance is achieved when intake of energy is equal to energy expended.

Energy refers to the impetus behind all motion and all activity. If is also the capacity to do work. Energy is measured in a unit dimensioned in mass × distance²/time² (ML²/T²) or the equivalent.

So therefore, the correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

Learn more about energy balance:

https://brainly.com/question/26103866

#SPJ1

Ans: 62.5

Explanation: \(F{net}\) = m x a

                    1N = 1kg x 1m/ \(s{2}\)

Answer:

a.75cm

Explanation:

Explanation:

\(thank \: you\)

The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W

First, we shall determine the work done in pushing the cart. Details below:

Wd = Fd

Wd = 20 × 3.5

Wd = 70 J

Finally, we shall determine the power used in pushing the cart. Details below:

P = Wd / t

P = 70 / 2

P = 35 W

Thus, we can conclude that the power used is 35 W

Learn more about power:

https://brainly.com/question/30817666

#SPJ1

the answer is c because

Cold water sinks because it is more dense than warm water.

Warm water rises because it is less dense than cold water.

Answer:

D and C

Explanation:

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

Question Parameters:

Ladakh is 800 mb.

assuming that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level pressure we need to add,

Ps=800+350

Ps= 1150 mb

For more information on Pressure visit

https://brainly.com/question/25688500

When the right kidney is obstructed, the nephrons in the left kidney increase in size to compensate. This statement is true.

When the right kidney is obstructed because of any reason, the nephrons of the left kidney increase in size to compensate.

Nephrons are basically the basic building blocks of the kidney. Nephron's help in filtering the fluid of the body.

Normally when both the Kidneys work efficiently then both the Kidneys have normal size.

But a one of the kidney is obstructed then the nephron size of the Other kidney increases in order to compensate the loss for the lack of use of nephrons of the obstructed kidney.

To know more about Kidneys, visit,

https://brainly.com/question/28063794

#SPJ4

The velocity of Bob at 11 seconds is 4.27 m/s.

The velocity of Bob at 11 seconds is calculated by applying average velocity formula as shown below.

v = ( total displacement ) / ( total time )

v = ( X₃ + X₁₁ ) / ( 3 + 11 )

where;

4 = ( 9 + 11u ) / ( 14 )

where;

The velocity of Bob at 11 seconds is calculated as;

4 = ( 9 + 11u ) / 14

9 + 11u = 56

11u = 56 - 9

11u = 47

u = 47 / 11

u = 4.27 m/s

Learn more about average velocity here: https://brainly.com/question/24445340

#SPJ1

Answer:

It is gaining potential energy

Answer: it could also be gravitational potential energy

This is because as it rises in the air it will gain more energy to fall back down

The most denser among the given materials is gold and the least dense one is helium. The order of density from least to most dense is helium, carbon dioxide, water, lead and gold.

Density of a substance is the measure of its mass per unit volume. It describes how  closely packed its particles. density depends on the bond type, temperature and pressure.

The density of helium is very low and it is the lightest element after hydrogen. It density is about 0.00017 g/ml. Density of carbon dioxide is 0.0019 g/ml and the density of water is 1 g/ml.

Gold is a denser metal and its density is about 19.3 g/ml and that of lead is 11.3 g/ml. Hence, the order of density from least to most dense is He < carbon dioxide< water< lead < gold.

To find more on density, refer here:

https://brainly.com/question/15164682

#SPJ1

Answer:

this is about momentum p=mv

A, the elephant has more mass

The rotational velocity of the centrifuge is \(\sqrt{5}\) rad/s.

Centripetal force is defined as the force that acts on a body moving in circular path which is directed towards the centre of the circular path.

Here,

The rotational acceleration attained by the astronauts, a' = 100 m/s²

The radius of the centrifuge, r = 20 m

From the equation of circular motion,

       a' = rω²

So,  ω² = a'/r

      ω² = 100/20

      ω² = 5

Rotational velocity, ω = \(\sqrt{5}\) rad/s

Hence,

The rotational velocity of the centrifuge, ω is \(\sqrt{5}\) rad/s

To learn more about Centripetal forces, click:

https://brainly.com/question/1869806

#SPJ9

Answer:

It looks like a total of 9 meters

Explanation:

the dot on the graph for 1910 sits JUST below the mark for 10 meters

Answer:

C

Explanation:

edge 2020... Using elimination it's the only one that makes sense.

The statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.

The gravitational force is a force that attracts all mass-bearing objects. The gravitational force is referred to as attractive because it always strives to pull masses together rather than pushing them apart.

As we know, the gravitational force is given by:

\(\rm F = \dfrac{Gm_1m_2}{r^2}\)

Where, G is the gravitational constant.

m1 and m2 are masses.

r is the distance between the masses.

From the data given in the table, shows that:

The gravitational force is indirectly proportional to the square of the distance.

Thus, the statement third "an increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass" is correct.

Learn more about the gravitational force here:

https://brainly.com/question/12528243

#SPJ2

Answer:

a reaction between an acid and a base

Explanation:

Answer:

The answer is A. A reaction between an acid and a base

Explanation:

Answer:

Gravity.

Explanation:

Gravity causes the child on a sled to slide down the hill.

Hope this helps!

Answer:

natural convection

............

Answer:

The distance of the father from the center is  \(d_f = \frac{1}{2} \ m\)

Explanation:

From the question we are told that

    The distance of the son from the center is  \(d_s = 2 \ m\)

Let the mass of the son be  \(m_s\)

     then the mass of the father is  \(m_f = 4m_s\)

Now for the teeter-totter to be balanced the torque due to the weight of the father must be equal to the torque due to the weight the son, this is mathematically represented as

         \(\tau_s = \tau_f\)

Where  \(\tau_s\) is the torque of the son which is mathematically represented as

        \(\tau_ s = m_s * d_s * g\)

while \(\tau_f\) is the torque of the father which is mathematically represented as

        \(\tau_f = m_f * d_f * g\)

=>    \(\tau_f = 4 m_s * d_f * g\)

 So

         \(4 m_s * d_f * g = m_s * d_s * g\)

substituting values

        \(4 * d_f * = 2\)

 =>    \(d_f = \frac{1}{2} \ m\)      

The minimum width of the screen is 34 cm.

For a diffraction grating, dsinθ = mλ where d = grating spacing = 1/5640 lines per cm = 1/5640 cm per line = 1/5640 × 10⁻² m per line, θ = angle between principal maximum and the center axis of the grating, m = order of maxima = 1 (since we require the position of the principal maximum) and λ = wavelength = 455 nm = 455 × 10⁻⁹ m

So, sinθ = mλ/d

Also tanθ = L/D where θ = angle between principal maximum and the center axis of the grating, L = distance between central maximum and principal maximum and D = distance between grating and screen = 0.661 m.

For small angles sinθ ≈ tanθ

So, mλ/d = L/D

making L subject of the formula, we have

L = mλD/d

L = 1 × 455 × 10⁻⁹ m × 0.661 m ÷  1/5640 × 10⁻² m per line

L = 1 × 455 × 10⁻⁹ m × 0.661 m  × 5640 × 10² line per m

L = 1696258.2 × 10⁻⁷ m

L = 0.16963 m

L ≅ 0.17 m

So, for centers of all the principal maxima formed on either side of the central maximum fall on the screen, the minimum width of the screen is w = 2L.

So, w = 2 × 0.17 m

w = 0.34 m

w = 34 cm

So for the centers of all the principal maxima formed on either side of the central maximum fall on the screen, the minimum width of the screen is 34 cm.

Learn more about diffraction grating here:

https://brainly.com/question/15712101

The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

The electric potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.

In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.

To find the capacitance value, we can use the formula:

C = Q / V

where Q is the charge stored in the capacitor and V is the voltage across the capacitor.

Substituting the given values, we get:

C = 9.40 x 10^-10 / 50.0

= 1.88 x 10^-11 F

Now we can use the formula for electric potential energy to find the energy stored in the capacitor:

U = (1/2) * 1.88 x 10^-11 * (50.0)^2

= 4.70 x 10^-8 J

Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

Know more about  electric potential energy here:

https://brainly.com/question/14306881

#SPJ11  

Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores

Explanation:

(a) A 1 000 kg car is pulling a 300 kg trailer, together the car and trailer move forward with an acceleration of 2. 15 m/s² the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

To determine the net force on the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

The total mass of the car and trailer combined is the sum of their individual masses: 1,000 kg + 300 kg = 1,300 kg.

The acceleration of the car and trailer system is given as 2.15 m/s².

Using Newton's second law:

Net force = mass × acceleration

Net force = 1,300 kg × 2.15 m/s²

Net force ≈ 2,795 N

Therefore, the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

This net force is responsible for accelerating the combined mass of the car and trailer in the forward direction. It represents the sum of all external forces acting on the system, such as the force exerted by the car's engine and the tension in the connection between the car and trailer.

For more such information on: force

https://brainly.com/question/12970081

#SPJ11