the alpha particles in rutherford’s experiments were used to —

The reaction rate with mass of the tablet being 1000 mg and volume of water 0.200 L is

(i) If Reaction time is 34.5 sec – 145 mg / L / sec is the reaction rate

(ii) If Reaction time is 28.9 sec – 173 mg / L / sec is the reaction rate

(iii) If Reaction time is 23.1 sec – 216 mg / L / sec is the reaction rate

Given that, Mass of tablet = 1000 mg

                  Volume of water = 0.200 L

We need to find the reaction rate

We know that, Reaction rate =  \(\frac{mass of tablet / volume of water}{reaction time}\)

(i) Reaction rate if reaction time is 34.5 sec = \(\frac{1000 / 0.200}{34.5}\) = 145 mg / L / sec

(ii) Reaction rate if reaction time is 28.9 sec = \(\frac{1000/0.200}{28.9}\) = 173 mg / L / sec

(iii) Reaction rate if reaction time is 23.1 sec = \(\frac{1000/0.200}{23.1}\) = 216 mg / L / sec

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The given reaction is already balanced, that is to say tha the number of atoms in the reactants matches the number of atoms in the products. In the reaction, we can see the relationship between CaC2 and H2O. For each mole of CaC2 two moles of H2O react.

So, if 4.8 moles of CaC2 are consumed the moles of H2O needed will be:

Mol of H2O = Mol of CaC2 x 2

Mol of H2O = 4.8 x 2 = 9.6 mol of H2O

Now, to calculate the grams of H2O we will use the following equation and the mass molar of H2O.

Mass molar of H2O =18.01 g/mol

So, if 4.8 moles of CaC2 are consumed in this reaction, 172.9 g of H2O are needed

Answer:

Answer: hunting deer

Explanation:

since the extraction of resources to the withdrawing of materials from the enviroment for human use, including fossil fuels ( oil, gas, and coal), rocks and minerals, bimass via deforestation and fishing and hunting, and water.

The amount of gas dissolved in solution tends to increase as the temperature decreases.

The ideal gas law describes the relationship between the amount of gas, temperature, pressure, and volume of an ideal gas. It states that the product of the pressure and volume of a gas is directly proportional to the number of gas molecules present (measured in moles), the temperature of the gas (measured in Kelvin), and a constant known as the gas constant (R). This can be expressed mathematically as PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is gas constant, and T is the temperature in Kelvin.

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Answer: Increase

Explanation:

The equilibrium constant is  12.5.

The equilibrium constant of a chemical response is the price of its response quotient at chemical equilibrium, a kingdom approached by means of a dynamic chemical device after enough time has elapsed at which its composition has no measurable tendency towards in addition trade.

The equilibrium consistent of a chemical response is the price of its response quotient at chemical equilibrium, a kingdom approached by a dynamic chemical device after enough time has elapsed at which its composition has no measurable tendency in the direction of further trade.

Calculation:-

CH₄ + H₂O --------->  CO + 2H₂

[CO] = 10⁻² mol/L

     = 0.01 mol/l

[H₂] = 5 × 10⁻¹ mol/l = 0.5 mol/l

[H₂O] = 10⁻² mol/l = 0.01 mol/l

[CH₄] = 10⁻² mol/l = 0.01 mol/l

K = [CO][H₂]³/[CH₄][H₂O]

  = (0.01) × (0.5)³/(0.01)×(0.01)

Kc = 12.5

Equillibirium constant =  12.5

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The decrease in concentration (ΔO₂) of O₂ each year, given that for every two CO₂ produced, three O₂ are required from the atmosphere, can be calculated using the equation:

ΔO₂ = (3/2) * ΔCO₂

Where:

ΔO₂ represents the decrease in concentration of O₂

ΔCO₂ represents the increase in concentration of CO₂

According to the given information, for every two CO₂ produced, three O₂ are required. This ratio of 3 O₂ to 2 CO₂ can be used to determine the change in concentration.

Therefore, the decrease in concentration of O₂ each year is equal to (3/2) times the increase in concentration of CO₂.

It's important to note that the units of concentration should match, such as parts per million (ppm), for both CO₂ and O₂. The resulting decrease in concentration of O₂ (ΔO₂) will also be in ppm.

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Answer:

On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them.

Answer:

um lets say its weight and force

Explanation:

it consist of pulling an individual object or living being to pull in a sub planet or lets say it pulls you from a land that doesn't make u float

0-gravity= to floating experience so yeah

To select four species that can be identified as molecules from the given list, you should look for species that are composed of two or more atoms chemically bonded together. The correct options are:

1. CO (Carbon monoxide) - A molecule consisting of one carbon atom and one oxygen atom bonded together.
2. CO2 (Carbon dioxide) - A molecule consisting of one carbon atom and two oxygen atoms bonded together.
3. O2 (Oxygen) - A diatomic molecule consisting of two oxygen atoms bonded together.
4. CH3OH (Methanol) - A molecule consisting of one carbon, four hydrogen, and one oxygen atom bonded together.

Your answer: Four species that can be identified as molecules from the list are CO, CO2, O2, and CH3OH.

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The name of the process shown in the diagram is of filtration which is a separation technique.

Filtration is defined as a process by which solid particles which are present in liquid or gaseous medium are allowed to be removed using a filter medium which retains the particles but allows the liquid to pass through.

The requirements for filtration are a filter medium ,fluid containing particles , a mechanical device usually a filter and a driving force.The filter media is classified depending on the pore size of particles which are to be filtered.

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Answer:

Straight chains, branched chain and rings.

Explanation:

Hope this helps :)

Answer/Explanation:

Carbon based molecules tend to form in chain like patterns. So, carbon molecules could/would form a chain that branches out, a chain that travels in a straight or constant direction, and a chain that connects into a loop style.

This experiment aims to observe the temperature changes during the phase changes of water and formulate hypotheses based on the observations.

The purpose of suspending the thermometer in the ice is to measure the temperature of the ice. It should not touch the bottom of the beaker because the bottom may be warmer than the ice, which could give an inaccurate reading.

It is important to record the states in the beaker (solid ice, melting ice, liquid water, boiling water, steam) because the temperature remains constant during the phase changes. The states indicate the changes in the internal energy of the system, which is not reflected in the temperature.

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Answer:

98.8g (3 s.f.)

Explanation:

Use the mole = mass/mr equation to find the moles of CaO, then use the molar ratio to find the moles of Fe2O3, which is the same as CaO, (assuming the ratio is 1:1, as you haven't stated it clearly in the question). Then use the equation and input to find Mass, which is 98.8g to 3 s.f.

To calculate the work done on the gas, we can use the formula:

Work (W) = -PΔV

Where:

W is the work done on the gas,

P is the constant external pressure, and

ΔV is the change in volume of the gas.

Given:

Initial volume (V1) = 4.65 L

Final volume (V2) = 6.21 L

External pressure (P) = 2.33 atm

First, we need to calculate the change in volume (ΔV):

ΔV = V2 - V1

ΔV = 6.21 L - 4.65 L

ΔV = 1.56 L

Now, we can substitute the values into the formula to calculate the work done on the gas:

W = -PΔV

W = -(2.33 atm) * (1.56 L)

Since we need the answer in joules, we need to convert atm·L to joules. The conversion factor is 101.325 J = 1 L·atm.

W = - (2.33 atm) * (1.56 L) * (101.325 J / 1 L·atm)

W = - 375.75 J

Therefore, the work done on the gas is approximately -375.75 joules. The negative sign indicates that work is done on the gas, as the volume increases under constant external pressure.

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Answer: a. 1.11 atm, 0.43 mol

Explanation:

Answer:

1. 500 cm = 5 m

2. 1000 g = 1 kg

3. 455 L = 45, 500 cL

4. 0.865 m = 0.00865 m or 8.65 * 10^-3 n

5. 33.5 cm = 335 mm

6. 0.0198 m = 19800 micrometers

7. 57.65 cg = 5.765 * 10^8 nanograms

8. 1000 L = 1 kl

9. 99 degrees F = 37.222 degrees C

Explanation:

1.  One meter = 100 centimeters

500 centimeters/ 100 centimeters = 5 meters

2. One kilogram = 1000 grams.

1000 grams/1000 grams = 1 kilogram

3. One Liter = 100 centiliters

455 liters * 100 centiliters = 45, 500 centiliters

4. One meter = 100 centimeters

0.865 centimeters/100 centimeters = 0.00865 meters

5. One centimeter = 10 millimeters

33.5 centimeters * 10 millimeters = 335 millimeters

6. One meter = 1.0 * 10^6 micrometers

0.0198 meters * 1 * 10^6 micrometers = 19800 micrometers.

7. One centigram = 1.0 * 10^7 nanograms

57.65 centigrams * 1 * 10^7 nanograms = 5.765 * 10^8 nanograms.

8. One kiloliter = 1000 L

1000 L/ 1000 L = 1 kiloliter

9. The formula for finding Celsius is 5/9(f - 32)

So 5/9(99 - 32) = x

5/9(67) = x

x = 335/9 or 37.222 degrees Celsius.

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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368.39 grams of Cu will be produced by 2.9 moles of Mn, rounded to 2 decimal places.

To determine the number of grams of Cu produced by 2.9 moles of Mn, it is needed to use the stoichiometry of the balanced chemical equation. By comparing the coefficients of Mn and Cu in the equation, we can establish a mole-to-mole ratio.

According to the balanced equation:

1 mole of Mn reacts to produce 2 moles of Cu

Follow these steps:
1. Identify the balanced equation: Mn(s) + 2 CuCl(aq) → 2 Cu(s) + MnCl2
2. Determine the molar ratio between Mn and Cu: 1 Mn : 2 Cu
3. Calculate the moles of Cu produced using the molar ratio: 2.9 moles Mn × (2 moles Cu / 1 mole Mn) = 5.8 moles Cu
4. Convert moles of Cu to grams: 5.8 moles Cu × (63.55 g Cu / 1 mole Cu) = 368.39 g Cu
5. Round the answer to 2 decimal places: 368.39 g Cu ≈ 368.39 g Cu

Similarly, 368.39 grams of Cu will be produced by 2.9 moles of Mn, rounded to 2 decimal places.

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Answer: c. Shared equally between two atoms

Electrons are shared equally because the atoms have the same electronegativity.

Answer:

Mitochondria are the working organelles that keep the cell full of energy. In a plant cell, chloroplast makes sugar during the process of photosynthesis converting light energy into chemical energy stored in glucose.

Explanation:

got that from google hope it works

Answer:

2NaI + Cl2 -> I2 + 2NaCl

Balanced.

To indicate the distance that corresponds to the bond length of the N₂ molecule, we need to know the bond length of the N₂  molecule. The bond length of a molecule refers to the distance between the nuclei of two bonded atoms.

The bond length of N₂  is approximately 109.76 picometers (pm). Therefore, to indicate the bond length of N₂   on the horizontal axis, we can place an X at 109.76 pm.

It's important to note that bond lengths can vary slightly depending on the specific conditions of a given experiment or calculation. However, the bond length of N₂  at standard conditions is well established, and 109.76 pm is a commonly accepted value.

Knowing the bond length of a molecule is important in understanding the nature of the chemical bond between two atoms. The bond length is related to the strength of the bond, with shorter bond lengths indicating stronger bonds. The bond length of N₂ , for example, is relatively short, indicating a strong bond between the two nitrogen atoms.

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The volume of a 0.92 M barium acetate solution that contains 75.0 g of barium acetate is 319 mL.

To calculate the volume in milliliters of a 0.92M barium acetate solution that contains 75.0 g of barium acetate, follow these steps:
Determine the molar mass of barium acetate, Ba(C₂H₃O2)₂.
Ba: 137.33 g/mol
C₂H₃O₂: 2 * (2 * 12.01 g/mol + 3 * 1.01 g/mol + 2 * 16.00 g/mol) = 2 * 59.04 g/mol
Total molar mass: 137.33 g/mol + 2 * 59.04 g/mol = 255.41 g/mol
Then, calculate the moles of barium acetate in 75.0 g.
moles = mass / molar mass
moles = 75.0 g / 255.41 g/mol = 0.2937 mol
Use the molarity formula to find the volume in liters.
M = moles / volume (L)
0.92M = 0.2937 mol / volume (L)
Volume (L) = 0.2937 mol / 0.92M = 0.3192 L
Convert the volume from liters to milliliters.
Volume (mL) = 0.3192 L * 1000 mL/L = 319 mL (rounded to 3 significant digits)

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Answer:

\(82\)

Answer:

\(\boxed {\boxed {\sf 72 \ electrons}}\)

Explanation:

Lead (Pb) has 82 protons, or positively charged particles. If this was a neutral atom of lead, then there would also be 82 electrons, or negatively charge particles to balance each other out and create an overall charge of 0.

However, we are given an ion of lead (Pb⁴⁺) which means the electrons and protons are not equal.

This is a 4+ ion. Since it is more positive, there must be fewer electrons than protons. In this case, it is 4 fewer electrons.

There must be 78 electrons.

ANSWER

The formula of strontium oxide is SrO

EXPLANATION

Strontium oxide is formed when strontium reacts with oxygen

Below is the reaction between strontium and oxygen

Hence, the formula of strontium oxide is SrO

Answer:

2 atm

Explanation:

Different symbols have different meanings in chemistry. For example, the symbol Δ = adding energy to the reactants.

To identify whether the reactants combine with a specific pressure, we have to use the symbol atm, in such a case 2 atm.

Hope that helps!

"Hypotonic solution," refers to a solution with the highest water concentration due to its lower solute concentration compared to the other options, leading to water influx into cells.

A hypotonic solution would be most likely to have the highest water concentration. In a hypotonic solution, the solute concentration is lower than that inside the cell or compared to another solution. As a result, water tends to move into the cell or the solution to equalize the concentration.

When a cell is placed in a hypotonic solution, water molecules will move into the cell through the process of osmosis. This influx of water increases the water concentration inside the cell, leading to cell swelling or even bursting in extreme cases.

Compared to hypertonic and isotonic solutions, a hypotonic solution has a lower solute concentration, allowing for a higher concentration of water molecules. This results in a higher water concentration in the solution. It's important to note that the concept of tonicity is related to the relative solute concentrations between two solutions and their effect on cell osmosis. In this case, a hypotonic solution is characterized by a higher water concentration compared to the other options.

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Answer:

107.8682U is the molar mass of ag

Answer: pic

Explanation:

plz

Answer:

4. matter is neither created nor destroyed

Explanation:

The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical reactions. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

in this question, we are given with the pressure at initial point i.e. 15 psi that undergoes compression from 470ml of volume to 260 ml.

We are asked to determine the final pressure after the compression.

For that we'd consider the Boyle's law that states that, for a gas in an iso-thermic system Pressure is inversely proportional to the Volume.

which means with the increase in Pressure, Volume of gas will reduce.

At constant Temperature, product of Pressure and Volume will be constant.

PV =  constant.

for same system at different pressure volume condition, we can say that-

\(P_{1}V_{1} = P_{2}V_{2}\)

\(P_{1} = 15psi\\ V_{1} = 470ml\\ V_{2} = 260ml\)

(15)(470) / (260) = \(P_{2}\)

Final Pressure = 27.11 psi

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