The ABC Corporation manufactures and sells two products: T1 and T2. 20XX budget for the company is given below:

Projected Sales Units Price T1 60,000 $165 T2 40,000 $250

Inventories in Units January 1, 20XX December 31, 20XX T1 20,000 25,000 T2 8,000 9,000

The following direct materials are used in the two products: Amount used per unit Direct Material Unit T1 T2 A pound 4 5 B pound 2 3 C each 0 1

Anticipated Inventories Direct Material Purchase Price January 1, 2012 December 31, 2012 A $12 32,000 lb. 36,000 lb. B $5 29,000 lb. 32,000 lb. C $3 6,000 units 7,000 units

Projected direct manufacturing labor requirements and rates for 20XX are as follows: Hours per Unit Rate per Hour T1 2 $12 T2 3 $16

4

Manufacturing overhead is allocated at the rate of $20 per direct manufacturing labor-hour. Marketing and distribution costs are projected to be $100,000 and $ 300,000, respectively.

a. What is the total expected revenue (in dollars) for 20XX? b. What is the expected production level (in units) both for T1 and T2? c. What is the total direct material purchases (in dollars) for each type of direct material? d. What is the total direct manufacturing labor cost (in dollars)? e. What is the total overhead cost (in dollars)? f. What is the total cost of goods sold (in dollars)? g. What is the total expected operating income (in dollars) for 20XX?

Answer:

A) slip(s1) = (1800 - 1750) / 1800 = 0.0277

B) 1800 rpm, 1350 rpm,  900 rpm, 450 rpm

Explanation:

Given data

frequency = 60 Hz,  

Line - line rms = 440 - V

3 phase induction-motor drive

number of poles = 4

Full-load rated speed = 1750

rated torque = 40 Nm

A) The plot of torque-speed characteristics for the following values of the frequency f : 60 Hz, 45 Hz, 30 Hz, and 15 Hz is attached below

first we calculate the rated speed:

Ns = \(\frac{120f}{p}\)

f = 60 Hz .  p (number of poles) = 4

Ns\(_{1}\) = \(\frac{120(60)}{4}\) = 1800

full loaded rated value = 1750.

slip(s1) = (1800 - 1750) / 1800 = 0.0277

considering a linearly condition the slip is low

\(\frac{T1}{T2} = \frac{S1}{S2} * \frac{F2}{F1}\)

S1 = 0.0277

f1 = 60 Hz

hence s2 = 0.018 therefore Ns2 = 1500

B) The speeds of operation at : 60 Hz, 45 Hz, 30 Hz, 15 Hz

for 60 Hz :

Ns = \(\frac{120f}{p}\) = (120*60) / 4 = 1800 rpm

for 45 Hz:

Ns = 120(f) / p = (120*45) / 4 = 5400 /4 = 1350 rpm

for 30 Hz:

Ns = 120(f) / p = (120*30) / 4 = 3600 / 4 = 900 rpm

for 15 Hz:

Ns = 120(f) / p = (120*15) / 4 = 1800 / 4 = 450 rpm

Answer:

7.5 feet

Explanation:

45 divided by 6 is 7.5

Answer:

7.5 feet

Explanation:

45 divided by 6 is 7.5

Answer:

(0, 0.04)

Explanation: Given that At time t = 0, a particle is at rest in the x‐y plane at the coordinates (x0, y0) = (6, 0) in. If the particle is then subjected to the acceleration components ax = 0.5 − 0.35t in./sec^2 and ay = 0.15t − 0.02t^2 in./sec^2.

differentiate ax and ay twice. That is, second derivatives to get the position

dax/dt =  − 0.35

d^2ax/dt^2 = 0

and

day/dt = 0.15 − 0.04t

d^2ay/dt^2 = 0.04

the coordinate of the particle after t = 6 sec will be (0, 0.04)

the graph will be linear

l

l

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Answer:

Deburring Tool

Explanation:

A deburring tool is used in order to debur the PVC pipes. They are mostly used for the plastic pipes.

After the PVC pipes are cut, there are burrs on the pipe surface. To remove these burrs, a deburring tool is used. It removes the burrs form the edges of the PVC pipes that results from grinding, cutting, milling, drilling, etc.

The deburring tools are made from high speed steels.

To calculate IP subnetworks with minimum waste of IP addresses, you can use Variable Length Subnet Masking (VLSM) technique. VLSM allows for the allocation of different subnet sizes within a larger network.

To demonstrate the calculation of IP subnetworks with minimum waste of IP addresses, let's consider the following example: Suppose we have been allocated the IP range 192.168.0.0/24 (subnet mask: 255.255.255.0) and we need to create subnets with varying sizes. We will use the VLSM technique to achieve this. First, identify the subnets with the largest required number of hosts. Let's say we need a subnet with 60 hosts, a subnet with 30 hosts, and a subnet with 10 hosts Subnet with 60 hosts: Subnet mask: 255.255.255.192 (/26) Network address: 192.168.0.0/26 Available IP range: 192.168.0.1 - 192.168.0.62 Subnet with 30 hosts: Subnet mask: 255.255.255.224 (/27) Network address: 192.168.0.64/27 Available IP range: 192.168.0.65 - 192.168.0.94 Subnet with 10 hosts: Subnet mask: 255.255.255.240 (/28) Network address: 192.168.0.96/28 Available IP range: 192.168.0.97 - 192.168.0.110 By using VLSM, we have effectively utilized the IP range 192.168.0.0/24 with minimum waste of IP addresses. Each subnet is allocated with the required number of hosts, optimizing the utilization of the IP space. Note: This is just an example, and the actual subnet sizes and IP ranges may vary based on your specific requirements. The table provided above illustrates how the IP range can be subdivided into subnets with different subnet masks and available IP ranges.

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No, the southbound interface in SDN is not responsible for providing a uniform means for application developers and network managers to access SDN services and perform network management tasks.

The statement is false because the southbound interface in Software-Defined Networking (SDN) is not responsible for providing a uniform means for application developers and network managers to access SDN services and perform network management tasks.

The southbound interface is the interface between the SDN controller and the network devices (switches, routers) and is responsible for transmitting control instructions and forwarding policies from the controller to the network devices. It is focused on communication and control between the controller and the network infrastructure.

The northbound interface, on the other hand, is responsible for providing a uniform means for application developers and network managers to access SDN services and perform network management tasks by allowing them to interact with the SDN controller.

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Answer:

900 psig

Explanation:

The angle of attack of a wing directly controls the C) distribution of pressures acting on the wing.

When the angle of attack of a wing is increased, the air moving over the curved upper surface of the wing must travel a greater distance and faster than the air moving beneath the wing's flat lower surface. This creates an area of lower air pressure above the wing and an area of higher air pressure beneath the wing, resulting in lift. The greater the angle of attack, the greater the lift produced.

However, if the angle of attack is too great, the airflow over the wing may separate, causing a loss of lift and potentially leading to a stall. Therefore, proper control of the angle of attack is crucial for safe and efficient flight.

Option C is answer.

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Answer:

t5g5gtttttttttttttttttttttttttttttttttttttttttttt

Explanation:gt555555555555555555555555555555555555555555555555

Answer:

dawbkjbjwwjhjfbfjewfaekfhawkjndwkja

Explanation: dum*as*

Answer:

John should detail his Scrum Master.

Explanation:

The Team Lead or Scrum Master coordinates the tasks of individual team members and supports the progress of the team. The Scrum Master usually receives instructions from the Product Owner and then ensures that the tasks are performed accordingly.  She also coaches the Development Team and works with the Product Owner to carry out daily development activities.  She also drives the Scrum Values and Principles, ensuring that the team members understand and practice them.

The development of empires in Mesopotamia had a significant impact on the region and the world as a whole. Mesopotamia was the cradle of civilization and the place where the first empires emerged. These empires were characterized by their highly organized and centralized systems of government, sophisticated legal codes, and complex economies.

The development of empires in Mesopotamia had several important impacts, including the spread of civilization, the advancement of technology, and the growth of trade and commerce. Mesopotamia was a melting pot of cultures, and the empires that emerged there played a vital role in the spread of civilization. They established trade routes that spanned the ancient world, and their technological innovations, such as the wheel and irrigation systems, had a lasting impact on human history. The development of empires in Mesopotamia also had a profound impact on the way we think about government and society.
These empires were characterized by strong central authority, and their legal codes and administrative systems set the standard for the rest of the world. In conclusion, the development of empires in Mesopotamia was a significant turning point in human history. It played a crucial role in the spread of civilization, the advancement of technology, and the growth of trade and commerce.

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The fact that Eli plans to set up a recycling program made him choose D. The material he chose is renewable and is much better for the environment.

It should be noted that recycling simply means the process of collecting and processing materials that can be turned into another product.

Therefore, the material he chose is renewable and is much better for the environment and thus influenced his decision.

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Note that Option B - ∀x P(x) ∨¬P(x) is a valid sentence.

Option B is known as the law of the excluded middle, which states that for any proposition P, either P is true or its negation, ¬P, is true. This law holds for all values of x, so the statement ∀x P(x) ∨¬P(x) is always true.

An argument is valid if and only if it is required that if all of the premises are true, then the conclusion must be true; it is impossible that all of the premises are true and the conclusion is false. An invalid argument is one that is not legitimate.

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Answer:

a. The time required for the tank to empty halfway is presented as follows;

\(t_1 = \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \left (\sqrt{2} -1 \right)\)

b. The time it takes for the tank to empty the remaining half is presented as follows;

\(t_2 = { \dfrac{ D_0^2 }{D} \cdot\sqrt{\dfrac{H}{g} }\)

The total time 't', is presented as follows;

\(t = \sqrt{2} \cdot \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} }\)

Explanation:

a. The diameter of the tank = D₀

The height of the tank = H

The diameter of the orifice at the bottom = D

The equation for the flow through an orifice is given as follows;

v = √(2·g·h)

Therefore, we have;

\(\dfrac{P_1}{\gamma} + z_1 + \dfrac{v_1}{2 \cdot g} = \dfrac{P_2}{\gamma} + z_2 + \dfrac{v_2}{2 \cdot g}\)

\(\left( \dfrac{P_1}{\gamma} -\dfrac{P_2}{\gamma} \right) + (z_1 - z_2) + \dfrac{v_1}{2 \cdot g} = \dfrac{v_2}{2 \cdot g}\)

Where;

P₁ = P₂ = The atmospheric pressure

z₁ - z₂ = dh (The height of eater in the tank)

A₁·v₁ = A₂·v₂

v₂ = (A₁/A₂)·v₁

A₁ = π·D₀²/4

A₂ = π·D²/4

A₁/A₂ = D₀²/(D²) = v₂/v₁

v₂ = (D₀²/(D²))·v₁ = √(2·g·h)

The time, 'dt', it takes for the water to drop by a level, dh, is given as follows;

dt = dh/v₁ = (v₂/v₁)/v₂·dh = (D₀²/(D²))/v₂·dh = (D₀²/(D²))/√(2·g·h)·dh

We have;

\(dt = \dfrac{D_0^2}{D} \cdot\dfrac{1}{\sqrt{2\cdot g \cdot h} } dh\)

The time for the tank to drop halfway is given as follows;

\(\int\limits^{t_1}_0 {} \, dt = \int\limits^h_{\frac{h}{2} } { \dfrac{D_0^2}{D} \cdot\dfrac{1}{\sqrt{2\cdot g \cdot h} } } \, dh\)

\(t_1 =\left[{ \dfrac{D_0^2}{D\cdot \sqrt{2\cdot g} } \cdot\dfrac{h^{-\frac{1}{2} +1}}{-\frac{1}{2} +1 } \right]_{\frac{H}{2} }^{H} =\left[ { \dfrac{D_0^2 \cdot 2\cdot \sqrt{h} }{D\cdot \sqrt{2\cdot g} } \right]_{\frac{H}{2} }^{H} = { \dfrac{2 \cdot D_0^2 }{D\cdot \sqrt{2\cdot g} } \cdot \left(\sqrt{H} - \sqrt{\dfrac{H}{2} } \right)\)

\(t_1 = { \dfrac{2 \cdot D_0^2 }{D^2\cdot \sqrt{2\cdot g} } \cdot \left(\sqrt{H} - \sqrt{\dfrac{H}{2} } \right) = { \dfrac{\sqrt{2} \cdot D_0^2 }{D^2\cdot \sqrt{ g} } \cdot \left(\sqrt{H} - \sqrt{\dfrac{H}{2} } \right)\)

\(t_1 = { \dfrac{\sqrt{2} \cdot D_0^2 }{D^2\cdot \sqrt{ g} } \cdot \left(\sqrt{H} - \sqrt{\dfrac{H}{2} } \right) = { \dfrac{D_0^2 }{D^2\cdot \sqrt{ g} } \cdot \left(\sqrt{2 \cdot H} - \sqrt{{H} } \right) =\dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \left (\sqrt{2} -1 \right)\)The time required for the tank to empty halfway, t₁, is given as follows;

\(t_1 = \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \left (\sqrt{2} -1 \right)\)

(b) The time it takes for the tank to empty completely, t₂, is given as follows;

\(\int\limits^{t_2}_0 {} \, dt = \int\limits^{\frac{h}{2} }_{0 } { \dfrac{D_0^2}{D} \cdot\dfrac{1}{\sqrt{2\cdot g \cdot h} } } \, dh\)

\(t_2 =\left[{ \dfrac{D_0^2}{D\cdot \sqrt{2\cdot g} } \cdot\dfrac{h^{-\frac{1}{2} +1}}{-\frac{1}{2} +1 } \right]_{0}^{\frac{H}{2} } =\left[ { \dfrac{D_0^2 \cdot 2\cdot \sqrt{h} }{D\cdot \sqrt{2\cdot g} } \right]_{0 }^{\frac{H}{2} } = { \dfrac{2 \cdot D_0^2 }{D\cdot \sqrt{2\cdot g} } \cdot \left( \sqrt{\dfrac{H}{2} } -0\right)\)

\(t_2 = { \dfrac{ D_0^2 }{D} \cdot\sqrt{\dfrac{H}{g} }\)

The time it takes for the tank to empty the remaining half, t₂, is presented as follows;

\(t_2 = { \dfrac{ D_0^2 }{D} \cdot\sqrt{\dfrac{H}{g} }\)

The total time, t, to empty the tank is given as follows;

\(t = t_1 + t_2 = \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \left (\sqrt{2} -1 \right) + t_2 = { \dfrac{ D_0^2 }{D} \cdot\sqrt{\dfrac{H}{g} } = \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} } \cdot \sqrt{2}\)

\(t = \sqrt{2} \cdot \dfrac{D_0^2 }{D^2 } \cdot \sqrt{ \dfrac{H}{g} }\)

The correct option is a: Consumers can buy books online from a foreign country and have them shipped directly to their homes.

This example illustrates how the Internet affects place utility by allowing consumers to access products from different locations easily and conveniently. The Internet has revolutionized the concept of place utility by connecting consumers with sellers from all over the world.

In this case, the ability to buy books from a foreign country and have them shipped directly to one's home demonstrates how the Internet has made products and services more accessible and convenient to consumers. This increased accessibility and convenience lead to a higher level of place utility, which ultimately enhances the overall customer experience.

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Answer: True

Explanation:

The number of threads in 16 inches of the rod is 176 threads

Given that:

1 threaded rod= 11 threads per inch

Therefore, to find the number of threads in 16 inches of the rod,

We would have to multiply and this is given below:

16 * 11= 176 threads

This answer is gotten because a threaded rod has 11 threads per inch and when there are 16 inches of rod, to find the number of inches, you would have to multiply the values together.

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The circuit breaker may have a maximum rating of 20–25.Any breaker between the aforementioned ratings will therefore be adequate.

Motor rating will be translated from horsepower (hp) to watts (W).

Circuit breakers are typically installed for electric circuits 20% to 25% more than the circuit's Rated Current, whereas overload relays are typically installed for electric circuits 20% to 25% more than the circuit's Running Current.

Therefore, the rated current of the motor will be multiplied by 1.2 1.25 Step by Step to get the maximum capacity of the circuit breaker. Explanation:

1 horsepower is 745.7 watts, so 30 horsepower is 22371 watts.

Assuming 208V phase to phase voltage and unity power factor (cos=1)

Rated Power (watt) equals 3. V.I. cos

If 208V is the voltage from the phase to the neutral, then use the following formula:

Rated Power (watt) equals 3. V.I. cos.

62.169A is the rated current.

So,

62.169A is the rated current.

Therefore, the needed maximum rating for a circuit breaker is: 20–25 percent of the rated current = 62,17*1.2 62,17*1.25 = 74.6–77,7A

Any breaker between the aforementioned ratings will therefore be adequate.  

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In scientific notation, a number x between 0 and 10 times a power of 10⁻ i.e., x10ⁿ⁻is produced by the calculator. For example, 53476 is represented as 5.3476*10⁴. This is often given by the calculator as 5.3476*E⁴

It is comparable to engineering notation. In this case, x is in the range of 0 to 1000, and the exponent n is the biggest multiple of 3 such that 10ⁿ is less than the integer. As a result, the responses are in the form x10ⁿ. For example, 53.476*10³ is used to symbolize the number. This makes it easy to add prefixes like micro, mili, mega, or kilo in front of the unit right away. The significand has exactly one digit before the decimal point in scientific notation. Therefore, 1.34 must be the significand. As a result, the exponent is 10⁵

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False. Fire extinguishing equipment cannot be frozen according to Ref. 213/91.

According to Ref. 213/91, fire extinguishing equipment cannot be frozen. Fire extinguishers are essential safety devices designed to combat fires effectively. They contain pressurized agents that are specifically formulated to extinguish different types of fires. Freezing temperatures can significantly impair the functionality of fire extinguishers and render them ineffective in emergency situations.

When fire extinguishing equipment freezes, several issues can arise. First, the contents of the extinguisher may expand as they freeze, potentially leading to ruptures or leaks in the container. This can cause the extinguisher to malfunction or become hazardous when used. Second, freezing temperatures can affect the performance of the extinguishing agent itself. Certain agents, such as water-based solutions, can solidify or lose their effectiveness when exposed to extreme cold.

It is crucial to store fire extinguishers in suitable environments that are above freezing temperatures. This ensures that the equipment remains in optimal condition and is ready for immediate use during emergencies. Regular inspections and maintenance are also essential to identify any signs of damage or deterioration that may compromise the functionality of fire extinguishers.

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Answer:

a

Explanation:

The cable type that comes in two different modes, single mode and multimode is the fiber optic cable.

Fiber optic cables are made up of thin strands of glass or plastic fibers that transmit data through light waves. The two modes of fiber optic cables are single mode and multimode.

Single mode fiber optic cables have a small core, typically 9 microns, and only allow one mode of light to travel through them.

As a result, these cables are well suited for long-distance transmission because they have low attenuation and a narrow bandwidth. Single mode cables are used in telecommunications and cable TV networks

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Answer:

Hello your question is incomplete attached below is the complete question

answer :

I) P = t/R * 492.85

II) The final equation : PR / t  + 4M/πR3 =  б e

Explanation:

attached below is a detailed solution to the given problem

i) P = t/R * 492.85

ii) Final equation : PR / t  + 4M/πR3 = б e

\(V_{F}\) (Volume Fraction) will be 0.14436 and Tensile strength weill be 620.222 MPa.

What is Tensile strength?

Tensile strength is a material's ability to withstand a pulling (tensile) force and refers to a material's breaking strength when a force capable of breaking many strands of the material simultaneously is applied at a constant rate of extension/load. It is typically expressed in units of force per cross-sectional area.

Tensile strength is the amount of load or stress that a material can withstand before stretching and breaking. Tensile strength, as the name implies, is a material's resistance to tension caused by mechanical loads applied to the material. One of the most important and widely measured properties of structural materials is their ability to resist breaking under tensile stress.

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The shape of a bridge is determined by the material it's made of. Bridges are made from different materials such as wood, steel, stone, and reinforced concrete.

Stone bridge: A stone bridge is built from stone blocks or stones that are cut and fitted together. The shape of a stone bridge is typically arched or curved. This is because stone is a very heavy and dense material that can withstand a lot of pressure. The arched shape of the stone bridge helps distribute the weight of the bridge evenly across the supporting pillars.

Steel bridge: A steel bridge is made from steel beams or trusses. The shape of a steel bridge is typically angular and geometric. This is because steel is a very strong material that can be easily molded and shaped into different shapes. The angular shape of the steel bridge helps distribute the weight of the bridge evenly across the supporting pillars. The shape also helps provide stability and prevent the bridge from swaying or moving in high winds.

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The force of attraction between a cation with a valence of +1 and an anion with a valence of -1 can be calculated using Coulomb's law. the force of attraction between a cation with a valence of +1 and an anion with a valence of -1, separated by a distance of 1.9 nm, is approximately 4.74 x 10^8 N.

What is Coulomb's law?

Coulomb's law is a fundamental law in electromagnetism that describes the interaction between electrically charged particles. It states that the force of interaction between two point charges is directly proportional to the magnitude of the charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as:

F = k * (q1 * q2) / r^2

The force of attraction between a cation with a valence of +1 and an anion with a valence of -1 can be calculated using Coulomb's law. Coulomb's law states that the force of attraction between two charged particles is proportional to the product of their charges and inversely proportional to the square of the distance between them.

The equation for the force of attraction between two charged particles (q1 and q2) separated by a distance of r is given by:

F = k * (q1 * q2) / r^2

where k is the Coulomb's constant (8.987551787 x 10^9 N * m^2 / C^2).

For a cation with a valence of +1 and an anion with a valence of -1, the force of attraction can be calculated as follows:

q1 = +1, q2 = -1, r = 1.9 x 10^-9 m

F = k * (q1 * q2) / r^2

= 8.987551787 x 10^9 N * m^2 / C^2 * (1 * -1) / (1.9 x 10^-9 m)^2

= 4.74 x 10^8 N

So, the force of attraction between a cation with a valence of +1 and an anion with a valence of -1, separated by a distance of 1.9 nm, is approximately 4.74 x 10^8 N.

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The range of values of v0 will depend on the range R and the angle of the initial velocity vector θ.

Initial velocity is the velocity of an object at the beginning of its motion. It is the speed and direction of an object at the start of its motion. It can be determined by measuring the displacement of the object from its starting point as a function of time. Initial velocity is often used to describe the speed of a projectile, such as a ball thrown into the air, or the speed of a moving object, such as a vehicle.

The range of values of v0 can be determined by using the equation for range, R = v0² sin (2θ) / g, where θ is the angle of the initial velocity vector v0, g is the acceleration due to gravity and R is the range of the projectile.

Assuming the points B and C are at the same height, the range of values of v0 can be determined by solving the equation for v0.

R = v0² sin (2θ) / g

v0 = √(Rg / sin (2θ))

Therefore, the range of values of v0 will depend on the range R and the angle of the initial velocity vector θ.

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