Suppose you add two vectors a and b. what angle between them produces the result with the greatest magnitude?

To determine the position u of the mass at any time t, we can use the equation of motion for a mass-spring system without damping:n m * u''(t) + k * u(t) = 0

m = 2 lb / (32.2 ft/s^2) = 0.062 lb·s^2/ft

The spring constant k can be determined using Hooke's law:

k = F / x

where F is the force exerted by the mass and x is the displacement. In this case, the force F is the weight of the mass, and the displacement x is 6 in:

k = (2 lb) / (6 in) = (2 lb) / (6 in) * (1 ft/12 in) = 0.111 lb/ft

The equation of motion now becomes:

0.062 * u''(t) + 0.111 * u(t) = 0

To solve this second-order linear homogeneous differential equation, we assume a solution of the form u(t) = A * cos(ωt + φ).

Substituting this assumed solution into the equation of motion, we get:

-0.062 * A * ω^2 * cos(ωt + φ) + 0.111 * A * cos(ωt + φ) = 0

-0.062 * ω^2 + 0.111 = 0

Solving for ω, we get:

ω = sqrt(0.111 / 0.062) = 2.258 rad/s

From ω, we can determine the frequency f and period T:

f = ω / (2π) = 2.258 / (2π) ≈ 0.359 Hz

T = 1 / f ≈ 2.786 s

The amplitude A is determined by the initial conditions. When the mass is pulled down an additional 3 in (0.25 ft) and released, it reaches its maximum displacement, so A = 0.25 ft.

Therefore, the position u of the mass at any time t is given by:

u(t) = 0.25 * cos(2.258t)

To draw the graph of u(t), plot the position u on the y-axis and time t on the x-axis, using the equation u(t) = 0.25 * cos(2.258t). The graph will be a cosine wave with an amplitude of 0.25 ft.

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Earth is larger than Mars. Additionally, Mars' circumference is around half that of the Earth's. Therefore, around 6.5 planets the size of Mars could fit inside the Earth if it were cracked open like an egg.

Not only is Mars smaller than Earth, but it is also less dense. This indicates that the gravitational force of gravity on Mars' surface is just 38% as powerful as that of gravity on Earth.

Therefore, 8.7 × 1016 N of gravitational force pulls the Earth and Mars together. The two planets are 5.5 × 1010 meters apart. The mass of the Earth is 6.0 × 1024 kg.

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Answer:

Workdone = 40 Nm

Explanation:

Force = 20 Newton

Distance = 2 meters

To find the work done;

Mathematically, work done is given by the formula;

Workdone = force * distance

Workdone = 20 * 2

Substituting into the formula, we have;

Workdone = 40 Nm

Answer:

33.3m

Explanation:

Recall that for a regular wave, the relationship between, wavelength, frequency  and velocity (speed) is given by :

v = fλ,

where:

v = velocity (speed) of the wave = 50m/s

f = frequency of the wave = 1.5 Hz

λ = wavelength (we are asked to find this)

simply substitute the given values into the equation:

v = fλ

50 = 1.5 λ,

λ = 50/1.5

λ = 33.3m

The weight of the log is 980N

The force of gravity acting on an object is its weight, which is equal to its mass times the acceleration of gravity, or w = mg. The newton is the SI unit for weight since it is a force.

The weight of a 100 kg log can be calculated using the equation w = mg,

where m is the mass of the log (100 kg) and g is the acceleration due to gravity (9.8 m/s^2).

So, w = (100 kg)(9.8 m/s^2) = 980 N.

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Answer:

64

Explanation:

bc yes

The resistance of 80.0 centimeters of constantan wire, whose diameter of the cross-section is 0.457 millimeters is 2.39, then the resistivity of constantan would be 4.89 ×10⁻⁵ Ohm meters⁻¹.

Resistance is the obstruction of electrons in an electrically conducting material.

The mathematical relation for variation in resistance with length is given,

R = ρ*L/A

As given in the problem resistance of 80.0 centimeters of constantan wire, whose diameter of the cross-section is 0.457 millimeters is 2.39,

Area of the constantan wire = π/4 ×(0.000457)²

                                              = 16.4 ×10⁻⁶ meter²

R = ρ*L/A

2.39 = ρ*0.8/ 16.4 ×10⁻⁶

ρ = 2.39×16.4 ×10⁻⁶ / 0.8

   =4.89 ×10⁻⁵

Thus, the resistivity of constantan​ would be 4.89 ×10⁻⁵ Ohm m⁻¹.

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The change in the momentum was found to be 16,000 kgm/s

Change in momentum ?

Situations involving impulse and momentum are all around us, whether we notice it or not. Before we begin evaluating these daily instances, we'll go over the fundamental ideas of impulse and momentum.

In physics, an impulse (Ft) is a force (F) operating over a certain time (t) that results in a change in momentum (p) of an object. The impulse-momentum theorem is the equation of impulse with the change in momentum.

the change in the momentum was Δp=mxΔv

Δp=2000x8

Δp=16,000 kgm/s

therefore the change in momentum was found to be 16,000kgm/s

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Answer:

c

Explanation:

on edg

Electric Current:

Electric current is the flow of charge through a given circuit per unit time. Electric current is one of the components needed to calculate the electric power that a device needs to operate and do work. Electric current is measured in amperes (A), which is equal to:

            1A = 1 C/ s

Recall that the coulomb (C) is the unit for charge while the second (s) is the unit for time

Given: I = 3.5

A is the current

Δt =30 s is the time interval

                     A =ΔQ/ΔT

Net charge = 100C

Electricity is produced when an electric current runs through a circuit.

How does electric current work?

A current of electricity is a steady flow of electrons. When electrons move from one place to another, round a circuit, they carry electrical energy from place to place like marching ants carrying leaves. Instead of carrying leaves, electrons carry a tiny amount of electric charge.

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Answer:Mutual respect. Mutual trust. Mutual affection.

Explanation:

The factor that will directly affect the magnetic force produced by an electromagnetic is (option A) Number of turns in the wire, amount of current.

When a current goes through a wire, it creates a magnetic field around that wire. The strength of the magnetic field is determined by the amount of current that flows through the wire and the number of turns in the wire.

The more turns  in the wire and  how high the current  will determine how strong the magnetic field produce by the Electromagnets will be.

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100 mph

Explanation:

Chetan is going 100 mph he hauling

Atoms of the pair of elements that will form ionic bonds in a compound are : C.) I and F.

Ionic bonds are a type of linkage created by electrostatic attraction between ions with opposing charges in chemical compounds.

Iodine has electronegativity of 2.66 and Fluorine has electronegativity of 3.98, which is a difference of 1.32. This large difference in electronegativity makes it favorable for Iodine to lose an electron and for Fluorine to gain an electron, forming ionic bond in compound.

The formation of ionic bonds occurs between atoms with large difference in electronegativity, where one atom loses electrons and other gains electrons to achieve  stable electron configuration.

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Given that a 10-pound sack of potatoes falls from an airplane. As the velocity of the falling sack increases, so does the air resistance on it. When the air resistance equals 10 pounds, the acceleration of the sack will be zero.

Let’s consider the forces acting on the 10-pound sack of potatoes:1. Gravitational force acting on the sack is given as Fg = mg where m = 10 pounds (mass) and g = 32.2 ft/s² (acceleration due to gravity)Thus, Fg = 10 × 32.2 = 322 lb2. Air resistance increases as the velocity of the falling sack increases, eventually reaches a point where it balances the gravitational force. This point is called terminal velocity.Terminal velocity is defined as the maximum velocity attainable by an object as it falls through a fluid, in this case, air. At terminal velocity, the net force acting on the object is zero since the gravitational force is balanced by the air resistance.3. At terminal velocity, the acceleration of the sack will be zero as the net force is zero. Thus, the acceleration of the sack when the air resistance equals 10 pounds is zero.Therefore, the acceleration of the sack will be zero when the air resistance equals 10 pounds.

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Answer: Is in the image

The mass of the child is 45.9 kg. Therefore, the answer is option D.

Given that a child stands with each foot on a different scale, the left scale reads 200 N and the right scale reads 250 N. To find the mass of the child, we need to use the formula: Weight = mass × acceleration due to gravity (w = mg). The acceleration due to gravity is 9.8 m/s². Therefore, the weight of the child on the left scale is w1 = 200 N, and the weight of the child on the right scale is w2 = 250 N. We can use these two weights to calculate the mass of the child. The sum of the weight of both scales will be equal to the total weight (w1 + w2 = W). Therefore, the total weight of the child is:

W = 200 N + 250 N= 450 N

We have the total weight of the child, and now we can calculate the mass of the child by dividing the weight by the acceleration due to gravity. Therefore, the mass of the child is:

m = W/g

= 450 N / 9.8 m/s²

= 45.92 kg

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Answer:

l think that the answer is 10.hope this helps . Can you mark me the brainest pliz.lt's LAURA RAYS AMIRA.

Answer:

Explanation:

700-40 = 760

760/10 = 76

It will take her 76 days to finish the book

Answer:

63 J

Explanation:

Efficiency = work out / work in

0.84 = W / 75 J

W = 63 J

The net force on the rope is the sum of all the forces acting on it. It can be either zero if all the forces cancel each other out or non-zero if there is a resultant force.

The determine the direction of the net force on the rope, we need to identify all the forces acting on it. If the rope is being pulled by two equal forces in opposite directions, the net force will be zero, and the rope will remain stationary. However, if the forces acting on the rope are not equal, the net force will be in the direction of the stronger force.
The direction of the rope's movement depends on the direction of the net force acting on it. If the net force is towards the left, the rope will move to the left, and if it is towards the right, the rope will move to the right. In summary, the net force on the rope is determined by adding all the forces acting on it, and the direction of the rope's movement depends on the direction of the net force. If the net force is towards the left, the rope will move to the left, and if it is towards the right, the rope will move to the right.

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Answer:

a seismometer records ground movement, and a seismometer is the output.

Explanation:

a seismometer has a moving pen, that when the ground shakes, it moves the pen to create a seismograph.

Answer:

the twenty-fourth, and last, letter of the Greek alphabet (Ω, ω), transliterated as ‘o’ or ‘ō.’.

Explanation:

Answer:

Work out the change in velocity for you given time.

Calculate the change in time for the period you are considering.

Divide the change in velocity by the change in time.

can increase the velocity of the object, decrease the velocity of the object, or change the direction of the velocity of the object.

Explanation:

hope this helped have a great day!

The fractional change in the frequency of the whistling sound heard by the person as the bullet crosses is a decrease from the actual frequency to approximately 391.13 Hz.

The fractional change in the frequency of the whistling sound heard by the person as the bullet passes by can be determined using the Doppler effect formula. The formula for the apparent frequency, or the frequency heard by the person, is:

f' = f x (v + v_observer) / (v + v_source)

Where:
- f' is the apparent frequency
- f is the actual frequency of the whistling sound
- v_observer is the velocity of the observer (person)
- v_source is the velocity of the source (bullet)
- v is the speed of sound in air

In this case, the bullet is passing by the person, so the observer's velocity (v_observer) is zero. The speed of sound in air (v) is typically around 343 m/s.

Using the given information:
- The bullet's speed (v_source) is 220 m/s
- The speed of sound in air (v) is 343 m/s

We can substitute these values into the formula:

f' = f x (0 + 220) / (220 + 343)

Simplifying further:

f' = f x 220 / 563

Now, let's assume the actual frequency of the whistling sound is f = 1000 Hz. Substituting this value:

f' = 1000 x 220 / 563

Simplifying further:

f' ≈ 391.13 Hz

So, the apparent frequency of the whistling sound heard by the person as the bullet crosses is approximately 391.13 Hz.

In conclusion, the fractional change in the frequency of the whistling sound heard by the person as the bullet crosses is a decrease from the actual frequency to approximately 391.13 Hz.

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Solution :

Crust

In the field of geology, the crust may be defined as the outermost solid shell of a planet. It forms the topmost outer hard layer of the earth surface. Earth has three layers. They are the crust, mantle and the core.

When we go deeper and deeper inside the earth's crust, the temperature rise. In the crust, on the surface of the earth, the temperature is normal and is atmospheric. As we go deep down the core, the temperature rise and it is highest at the core where all the rock and the iron is in the form of the molten lava.

According to the Geologist, beneath the earth's crust, for every mile we go inside the temperature rises by 15 degree Fahrenheit.

Answer:

1314362.5 gm     or   1314.3625 kg

Explanation:

A cube has all three dimension =

  55 * 55 * 55 = 166375  cm^3

166 375 *   7.9 g/ cm^3 = 1314362.5 gm

However, for a convex mirror, the focal length is negative, so the correct answer is: -0.25 m (option b)

A spherical mirror that forms only virtual images has a negative focal length. The relationship between focal length (f) and radius of curvature (R) for a spherical mirror is given by:

1/f = 1/R - 1/d

where d is the distance between the object and the mirror. Since the mirror forms only virtual images, the distance between the object and the mirror is negative.

Substituting R = 0.50 m and d = -∞ (since the mirror forms only virtual images), we get:

1/f = 1/0.50 - 1/(-∞)

Since 1/(-∞) = 0, we have:

1/f = 2

Therefore, f = 1/2 = 0.5 m.

Since the focal length is negative, the correct answer is (b) -0.25 m.

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F₂ = 1.723 x 10⁸ N

Given

Area of small piston : 0.004 m²

Area of large piston : 3.5 m²

Force 225 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

225/0.004 m² = F₂/3.5² m²

F₂ = 1.723 x 10⁸ N