Sue and Jenny kick a soccer ball at exactly the same time. Sue’s foot exerts a force of 75.9 N to the north. Jenny’s foot exerts a force o 105.8 N to the east. What is the magnitude of the resultant force on the ball?

Answer:

6.0×10⁻²¹ J

Explanation:

KE = 3/2 kT,

where KE is average kinetic energy per molecule,

k is the Boltzmann constant,

and T is absolute temperature.

KE = 3/2 (1.38×10⁻²³ J/K) (18 + 273.15) K

KE = 6.0×10⁻²¹ J

Answer:

The answer is 6.0×10⁻²¹ J , because KE = 3/2 kT,  where KE is average kinetic energy per molecule,  k is the Boltzmann constant,  and T is the absolute temperature.

KE = 3/2 (1.38×10⁻²³ J/K) (18 + 273.15) K

KE = 6.0×10⁻²¹ J

When an object is moved closer to the concave mirror, then

a)magnitude of image distance increases.

b)the image height become larger.

In concave mirror, we know that when an object is placed at the focus, its image will formed in enlarged size at infinity, it means height of image is large as compared to height of object. Here the scenario is same when object is placed at the center of curvature, object formed at the center of curvature of mirror in opposite direction of object. When object is moved closer to mirror from the center of curvature, image starts moving away from the mirror.

Image will formed below the positive y-axis and nature of image will be inverted and size of image starts increasing when it moves closer to mirror.

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Answer:

A. When one bulb burns out, all the other lights stay lit.

Answer: C.. all bulbs go out.

Explanation:

Sources of mineral resources are most commonly magma, sediments, or hydrothermal fluids.

Examples of mineral resources are iron, diamond, gold, silver, copper, aluminum, granite, marble, clay, salt, rare earths or fossil fuels.

What are mineral resources?

A mineral resource is a concentration of natural solid inorganic or fossilized organic matter, including metals, coal and minerals, in sufficient quantity and quality to have reasonable prospects for economic exploitation. This definition has a broader scope than mineral reserves that are likely to be economically recovered based on consideration of technical, economic, and legal concerns.

Mineral resources means minerals, naturally occurring solid inorganic substances, or naturally occurring solid fossilized organic substances (including base metals, precious metals, coal and industrial minerals), in or on the earth's crust, such Means concentrated or occurring in form and quantity and in its grade or quality. There are reasonable prospects for economic development. The location, quantity, grade, geological features and continuity of Mineral Resources are known, estimated or interpreted on the basis of specific geological evidence and knowledge.

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Answer:

Workdone = 465766038 Joules.

Explanation:

Given the following data;

Mass = 1167

Initial velocity = 10m/s

Final velocity =28m/s

To find the workdone;

We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.

Mathematically, it is given by the equation;

W = Kf - Ki

W = ½MVf² - ½MVi²

Substituting into the equation

W = ½(1167)*28² - ½(1167)*10²

W = ½ * 1361889* 784 - ½ * 1361889 * 100

W = 533860488 - 68094450

Workdone = 465766038 Joules.

Answer:

In series

Explanation:

Ammeter is used in electric circuits to measure the amount electric current that passes through the circuit.

Now, as a rule, this ammeter is always connected in series with the wires in the circuit where the current is being measured so that sufficient current can pass through it.

Answer:

Mass, m = 816.33kg

Explanation:

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, \( Weight, W = mg\)

Where;

Making mass, m the subject of formula, we have;

\( Mass, m = \frac {W}{g} \)

Given the following data;

Weight = 8000N

We know acceleration due to gravity is equal to 9.8 m/s²

Substituting into the equation, we have;

\( Mass, m = \frac {8000}{9.8} \)

Mass, m = 816.33kg

Therefore, the mass of the elevator is 816.33kg.

Answer:

B f

Explanation: hop it helps

The drift velocity (v) of charge carriers in a conductor is given by the following equation: v = I / (n \(\times\) A \(\times\) q).

v = I / (n \(\times\) A \(\times\) q)

where:

v is the drift velocity, measured in meters per second (m/s)

I is the current flowing through the conductor, measured in amperes (A)

n is the number of charge carriers per unit volume of the conductor, measured in per cubic meter (\(m^(-3)\))

A is the cross-sectional area of the conductor, measured in square meters (m^2)

q is the charge of a single carrier, such as an electron, measured in coulombs (C)

This equation relates the drift velocity of the charge carriers to the current flowing through the conductor, the number of charge carriers per unit volume, the cross-sectional area of the conductor, and the charge of a single carrier. The drift velocity represents the average velocity of the charge carriers as they move through the conductor in response to an applied electric field.

The number of charge carriers per unit volume (n) depends on the material of the conductor and the temperature. In metals, the charge carriers are typically electrons, and the number density is on the order of 10^28 to 10^29 electrons per cubic meter.

The cross-sectional area (A) of the conductor is the area of the cross-section of the conductor perpendicular to the direction of the current flow, and is a measure of the amount of material available for the charge carriers to move through.

The charge of a single carrier (q) is typically the charge of an electron, which is approximately 1.6 x \(10^{-19\) coulombs.

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Answer:

a. 24 m³, 7.0×10⁴ Pa

Explanation:

Use Bernoulli's equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₃ + ½ ρ v₃² + ρgh₃

Given or assumed:

P₁ = 0 Pa

v₁ ≈ 0 m/s

h₁ = 10 m

P₃ = 0 Pa

h₃ = 2 m

ρ = 1000 kg/m³

g = 9.8 m/s²

Substituting and simplifying:

ρg (10) = ½ ρ v₃² + ρg (2)

10g = ½ v₃² + 2g

(Notice this is simply an energy balance.)

Solving for v₃:

v₃ = √(16g)

v₃ = 12.5 m/s

Volumetric flow rate is velocity times area:

Q = v₃ A₃

Q = (12.5 m/s) (0.0160 m²)

Q = 0.200 m³/s

After 2 minutes, the volume discharged is:

V = (0.200 m³/s) (120 s)

V = 24.0 m³

Using Bernoulli's principle again:

P₂ + ½ ρ v₂² + ρgh₂ = P₃ + ½ ρ v₃² + ρgh₃

Since h₂ = h₃ and P₃ = 0:

P₂ + ½ ρ v₂² = ½ ρ v₃²

P₂ = ½ ρ (v₃² − v₂²)

Since volumetric flow is constant (mass is conserved):

Q = Q

v₂ A₂ = v₃ A₃

v₂ = v₃ A₃ / A₂

Substituting:

P₂ = ½ ρ (v₃² − (v₃ A₃ / A₂)²)

P₂ = ½ ρ v₃² (1 − (A₃ / A₂)²)

P₂ = ½ (1000 kg/m³) (12.5 m/s)² (1 − (0.0160 / 0.0480)²)

P₂ = 69,700 Pa

P₂ ≈ 7.0×10⁴ Pa

Answer:

Define local action and polarization.How do they make their cell defective?​

Explanation:

Local action is a principle in physics that describes how a particle or object interacts with another object that is nearby, without the need to consider transients that occur over long distances. This means that the influence of one object on another rapidly decreases as the distance between them increases. Local action is a fundamental assumption in quantum physics and general relativity, and it is essential for understanding many physical phenomena.

Polarization is a phenomenon that occurs when a transverse wave, such as an electromagnetic wave, oscillates in a specific plane. This means that the direction of the wave's electric field changes with time, but always remains in the same plane. Polarization is important in many applications, such as optics, where the polarization of light can be used to control the intensity and direction of light. Furthermore, polarization is fundamental in particle physics, where subatomic particles have an intrinsic polarization that can be measured in experiments.

Answer:

In terms of both price and availability, the Birkin bag is as elusive as it is exclusive. For more than two decades, the bag has been the most sought item in the handbag industry. For such a modest bag, that's a lot of staying power (in looks alone, the design itself takes some 18 hours and is done by a single craftsman).

Of course, it's likely that the bag's rarity is what keeps it at the top of every want list. It is difficult, for example, to stroll into a Hermès store and buy a bag –– even if you could afford to pay the minimum price of $10,000. No, you have to be on an elite list to receive a Birkin.

Explanation:

There are alot more things like the Birkin Bag that use the same marketing skills and it works for alot of companies.

Answer:

The period of a wave or an oscillating system is the time it takes for the system to complete one full cycle of its motion. In physics and engineering, the period of a wave is a fundamental concept used to describe the behavior of periodic signals and systems. The period can be used to calculate other parameters of the wave, such as its frequency, wavelength, and velocity.

In this case, the oscillator completes 30 cycles in 15 seconds, meaning it completes a cycle every 15 seconds / 30 cycles = 0.5 seconds. So the period of the oscillator is 0.5 seconds. The frequency of the oscillator can then be calculated as the reciprocal of its period, which is 1 / 0.5 seconds = 2 Hz.

In conclusion, the period of an oscillator is an important parameter that describes its behavior, and it is directly related to other parameters such as frequency, wavelength, and velocity.

The formula s = (1/2)gt2 = 0.5 * 9.80665 * 82 = 313.8 m can be used to calculate the free fall distance. If you are aware of how high the object is.

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The period of the race car's motion around the circular racetrack is approximately 0.01664 seconds.

The period of motion is the time it takes for an object to complete one full revolution or cycle. In this case, the race car is moving in a circular path, and we can calculate the period using the formula \(T = 2\pi r/v\), where T is the period, r is the radius of the circular path tangential velocity, and v is the velocity of the race car.

First, we need to convert the radius from millimeters to meters:

T is the period of motion,

R is the radius of the racetrack, and

v is the velocity of the race car.

Given that the radius of the racetrack is 265 mm (0.265 m) and the velocity of the race car is 40.0 m/s, we can substitute these values into the formula:

\(T = (2 * \pi * 0.265 m) / 40.0 m/s.\)

Simplifying the equation:

T = 0.01664 s.

Therefore, the period of motion for the race car is tangential velocity approximately 0.01664 s seconds. This means that it takes approximately0.01664 s seconds for the race car to complete one full lap around the circular racetrack.

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Answer:

Im not 100% sure so don't completly rely on these answer s

#1 is B

#2 ia B

#3 is A

#4 is A

#5 is A

and i think #6 is A

im 100% sure that 3 and 4 are A tho  

Explanation:

Answer:

Option a

Explanation:

Given that the car speeds up at a steady 1.3 m/s2, and the magnitude of the centripetal acceleration is equal to the tangential acceleration. We can use the following equations in order to determine the time required to attain the magnitude of centripetal acceleration equal to tangential acceleration.  

The centripetal acceleration of an object moving in a circle is given by the formula;\(a_c = v^2/r\) Where v is the speed of the object and r is the radius of the circle.

Therefore, t = 5.7/1.3

= 4.385 seconds. So, the time after which the magnitude of the centripetal acceleration is equal to the tangential acceleration is 4.385 seconds (rounded to 2 decimal places).

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Answer: An eclipse of the Sun occurs at only full Moon

Explanation:

A series RC circuit contains a 0.01 microfarad capacitor and a 2,000-ohm resistor and has a frequency of 500 Hz. The impedance of the series RC circuit is approximately 1416 ohms.

The impedance Z of a series RC circuit can be calculated using the formula:

Z = sqrt(R^2 + (1/ωC)^2)

where R is the resistance, C is the capacitance, and ω is the angular frequency.

Given that the capacitance of the circuit is 0.01 microfarads and the resistance is 2,000 ohms, we can calculate the angular frequency as:

ω = 2πf = 2π(500 Hz) = 1000π rad/s

Substituting the values into the formula, we get:

Z = sqrt((2000 Ω)^2 + (1/(1000π rad/s * 0.01 μF))^2)

= sqrt(4,000,000 + 10^12/(π^2))

≈ 1416 Ω

Therefore, the impedance of the series RC circuit is approximately 1416 ohms.

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Friction affects the work done by machines by reducing the mechanical advantage of that machine.

MA = \(F_{o}\) / \(F_{i}\)

MA = Mechanical advantage

\(F_{o}\) = Output force

\(F_{i}\) = Input force

Mechanical advantage is the ratio of output force to input force in a system.

According to law of conservation of energy, input energy is equal to output energy. It is true in the machines also but some of the output energy is not necessarily asked of the machine. That energy which is not useful is heat produced due to friction.

Therefore, friction affects the work done by machines by reducing the mechanical advantage of that machine.

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According to the relaxed power, the far point in meter unit is 0.28 meters.

We need to know about the relaxed power of the eye to solve this problem. Relaxed power can be defined as the ability of the optical device to see. It can be represented by a dioptre unit. The relaxed power formula is

P = 1/di + 1/do

where P is power of the eye, di is distance between eye lens and image and do is distance between eye lens and image.

From question above, the given parameters are

P = 53.6 d

di = 2 cm = 0.02 m

By substituting the given parameters, we can calculate the far point

P = 1/di + 1/do

53.6 = 1/0.02 + 1/do

1/do = 53.6 - 50

1/do = 3.6

do = 1/3.6

do = 0.28 m

Hence, the far point in meter unit is 0.28 meters.

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i need help with this too:( if u found out the answer lmk

Answer:

Some stars in space can come to life causing humans to be amazed but at thesame time in great/critical danger.

Answer:

I’m glad you asked!

Explanation:

So let’s just say it is Fiction.Science fiction is perfect because it is with space and science,but it is fiction.

Science fiction!

If the predator in the Lotka-Volterra models feeds on several different prey items, the outcomes would likely be different compared to a scenario where it feeds on a single prey item.

In the Lotka-Volterra models, the interaction between predators and prey is typically represented by a set of differential equations. When a predator feeds on several different prey items, it introduces additional complexities to the model. Here are a few reasons why the outcomes would likely be different:

Prey Interactions: Different prey items may have different population dynamics and interactions with each other. Some prey may compete for resources, while others may have a mutually beneficial relationship. These interactions can affect the predator's ability to obtain food and impact the population dynamics of both the predator and prey species.

Predator Behavior: A predator feeding on multiple prey items may exhibit different foraging behaviors. It could switch between prey types based on availability or preference. This dynamic foraging behavior can influence the predation pressure on each prey species and lead to different population dynamics.

Resource Partitioning: When a predator consumes multiple prey items, there may be resource partitioning among the prey species. Each prey species may have different resource requirements, leading to variations in their population sizes and dynamics. This partitioning can create niche differentiation and affect the overall stability and dynamics of the predator-prey system.

Trophic Cascades: The presence of multiple prey items can introduce the possibility of trophic cascades, where changes in one prey population can indirectly affect the other prey species and subsequently impact the predator. For example, if the predator's primary prey becomes scarce, it may switch to another prey item, which could lead to population fluctuations and indirect effects throughout the ecosystem.

In summary, when the predator in the Lotka-Volterra models feeds on multiple prey items, the outcomes can be different due to complex prey interactions, predator behavior, resource partitioning, and the potential for trophic cascades. These additional factors introduce more variables and dynamics into the model, leading to different population sizes and interactions between the predator and prey species.

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Answer:

No. Because undefined amounts of energy are also released in deformation of the objects, heat released, etc.

Increase the frequency of the incident light. The photoelectric effect occurs when light of a sufficient frequency strikes a metal and frees electrons from the metal's surface. The energy of the incident photons must be greater than the energy required to remove the electrons, known as the work function. Thus, increasing the frequency of the incident light will result in higher energy photons, increasing the likelihood of electron ejection in the photoelectric effect.

The kinetic energy of the photoelectrons that are released will grow as the light amplitude increases, according to the wave model of light, yet the measured current will increase as the frequency increases. In contrast to expectations, studies revealed that raising the light's frequency and amplitude raised the current and the photoelectrons' kinetic energy, respectively.

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Answer:

90.0

Explanation:

Because 78.8329 + 3.179=83.0119

83.0119 + 6.5263=89.5382 rounded up is 90.0000

Hope this helps have a awsome afternoon:)

Answer:

See below

Explanation:

Potential Energy = mgh

Where m = mass, g = acceleration due to gravity and h = height

So, Height is directly proportional to potential energy. Such that

If, Height is increased, Potential Energy is increased and vice versa.

Answer:

\( \boxed{\sf Time \ taken = 10 \ seconds} \)

Given:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Acceleration (a) = 2 m/s²

To Find:

Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s²

Explanation:

\(\sf From \ equation \ of \ motion:\)

\( \boxed{ \bold{v = u + at}}\)

Substituting values of v, u & a in the equation:

\( \sf \implies 30 = 10 + 2t\)

Substract 10 from both sides:

\( \sf \implies 30 - 10 = (10 - 10) + 2t\)

\( \sf \implies 20 = 2t\)

20 = 2t is equivalent to 2t = 20:

\( \sf \implies 2t = 20\)

Dividing both sides by 2:

\( \sf \implies \frac{ \cancel{2}t}{ \cancel{2}} = \frac{20}{2} \)

\( \sf \implies t = \frac{10 \times \cancel{2}}{ \cancel{2}} \)

\( \sf \implies t = 10 \: s\)

So,

Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s² = 10 seconds