sponges have specialized cells, called , which provide structure and support. group of answer choices amoebocytes spicules ostia choanocytes

elastic cartilage has the function which was designed to absorb compressive shock.

what is elastic cartilage ?

Elastic cartilage is histologically similar to hyaline cartilage, but it contains a dense matrix of yellow elastic fibres. Under a microscope, these fibres form dark bundles. The elastic fibres require specific staining since they seem the same as hyaline cartilage when stained with haematoxylin and eosin (H&E). Verhoeff van Geison stains are used (which give the elastic fibres a black colour), but other stains such as aldehyde fuchsin stains, Weigert's elastic stains, and orcein stains can also be used. These fibres give elastic cartilage its flexibility, allowing it to endure repeated bending. One or more chondrocytes, similar to hyaline, are found between the gaps (or lacunea) in the fibres. Chondrocytes account for only 2% of the tissue's volume.

elastic cartilage has the function which was designed to absorb compressive shock.

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The pH meter can distinguish between smaller differences in pH than pH strips can is the reason that explains why using a pH meter would improve the accuracy of her data.

A pH meter is a scientific instrument that measures the hydrogen-ion activity in water-based solutions, indicating its acidity or alkalinity expressed as pH.

pH strips are pieces of paper that change color depending on the pH – the acidity or alkalinity – of a liquid.  pH strips are a cheap and relatively accurate way of measuring the pH of any liquid.

The difference in electrical potential relates to the acidity or pH of the solution. The pH meter is used in many applications ranging from laboratory experimentation to quality control.

If you work in applications where low resolution and accuracy are sufficient, then pH strips are a great way to easily and cheaply measure pH in solutions.

However, if you need high resolution and extremely accurate results, pH meters are the best option, and worth the investment.

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Answer:

I dont know the exact answer but if it helps i think you count the number of letters in the first dna strand and then count the amount of letters are different from the bottom strand then turn it into a percentage.

Explanation:

Answer:

Explanation:

2 because it's going upward.

Answer:

D.5

Explanation:

The degree of the polynomial 3x^5 - 6x^2 + 5x is 5, so the answer is option D.

A polynomial is a type of algebraic expression that consists of variables, coefficients, and exponents.

There can be one or more terms in a polynomial, and the degree of the polynomial is determined by the highest power of the variable present in it.

For example, the polynomial 3x^2 + 4x + 5 has a degree of 2 since the highest power of the variable (x) is 2. In the given polynomial 3x^5 - 6x^2 + 5x, the highest power of the variable is 5, which means that the degree of the polynomial is 5.

Hence, the correct answer is option D.

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Answer:

Active transport occurs when molecules are moved across a semi-permeable membrane and UP (against) a concentration gradient.

Active transport occurs when molecules are moved across a semi-permeable membrane and up a concentration gradient.

Active transport may be defined as a transport that occurs against the concentration gradient and is mediated by carrier proteins.

This type of transport requires metabolic energy to move ions or molecules against or up of the concentration gradient.  

Therefore, the correct answer to this question is Up.

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The original cell density of the sample was 540 cells/mL. This was calculated based on the dilution factor and the number of colonies that grew on the plate.

To calculate the original cell density, we need to consider the dilution factor and the number of colonies that grew on the plate.

First, we determine the dilution factor. The original sample was diluted 1:100 (0.1 mL into 9.9 mL), resulting in a dilution factor of 1/100 or 0.01.

Next, we calculate the number of cells in the diluted sample. Since 0.1 mL of the diluted sample was spread on the plate and 54 colonies grew, we can assume that each colony represents one cell from the original sample.

Therefore, the number of cells in the diluted sample is 54 cells.

To find the original cell density, we divide the number of cells in the diluted sample by the dilution factor:

Original cell density = (Number of cells in diluted sample) / (Dilution factor)

                           = 54 cells / 0.01

                           = 540 cells/mL.

Thus, the original cell density of the sample is 540 cells/mL.

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Exponential growth occurs when a population increases at a constant rate per unit time.

This means that the population grows by the same percentage over each time interval. For example, if a population of 100 individuals grows by 10% each year, it will increase by 10 individuals in the first year, 11 individuals in the second year, and so on. This type of growth is often seen in populations of organisms, as well as in financial investments and other situations where growth is compounded over time.

In mathematical terms, exponential growth can be represented by the equation y = a(1 + r)^t, where y is the final population size, a is the initial population size, r is the growth rate, and t is the time interval. By plugging in different values for these variables, we can calculate the population size at any given time and see how it changes over time. Overall, exponential growth is an important concept in many fields, including biology, economics, and finance, and understanding how it works can help us make better predictions and decisions about the future.

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During the cardiac cycle, the heart undergoes sequential pressure changes and volume changes, facilitated by coordinated valve activity, resulting in the generation of distinct heart sounds.

The mechanical events of the cardiac cycle consist of pressure changes, volume changes, valve activity, and heart sound.

These events can be grouped into two phases: diastole and systole.

The cardiac cycle refers to the series of events that occur during one heartbeat.

This process lasts approximately 0.8 seconds and is divided into two phases, namely diastole and systole.

During diastole, the heart muscle relaxes and fills with blood.

The following events occur during diastole: The aortic and pulmonary valves are closed. The mitral and tricuspid valves are open.

Blood flows from the atria into the ventricles. The volume of the ventricles increases.

The pressure in the atria is greater than the pressure in the ventricles. This causes blood to flow through the mitral and tricuspid valves into the ventricles.

The ventricles contract during systole, and the following events occur: The mitral and tricuspid valves are closed.

The aortic and pulmonary valves are open. Blood is forced out of the ventricles into the arteries.

The volume of the ventricles decreases. The pressure in the ventricles is greater than the pressure in the arteries.  This causes blood to flow through the aortic and pulmonary valves into the arteries.

Heart sounds are created by the closing of the heart valves.

The first heart sound is created by the closure of the mitral and tricuspid valves, and the second heart sound is created by the closure of the aortic and pulmonary valves.

The mechanical events of the cardiac cycle are essential for the proper functioning of the heart and the circulatory system as a whole.

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Answer:

The weather change as the earth warms because since,20th century due to human activities, particularly fossil-fuel burning which increases heat- trapping greenhouse gas levels in Earth's atmosphere.

Answer: Temperature and PH

Explanation:

Enzyme activity can be affected by a variety of factors, such as temperature, pH, and concentration. Enzymes work best within specific temperature and pH ranges, and sub-optimal conditions can cause an enzyme to lose its ability to bind to a substrate.

Hope it helps!

Answer:

she is not prepared because she brought unnesasery things

Explanation:

Answer:

ariana needs to wear tight fitting clothes and tie her hair back to avoid getting chemical on them or catching on fire. she needs goggles to properly protect her eyes. she also needs close toed shoes to protect her feet

Explanation:

Answer:

I think it's " C and D" not to sure about "C" but one of the answers is definitely " D"

Explanation:

Evolution by natural selection refers to the mechanism that is responsible for species’ survival, diversification, and extinction. The two requirements that are fundamental to the process of natural selection include; differential survival and reproduction and heritability of phenotypic variation.

The heritability of traits that allow individuals to survive and reproduce can lead to differential survival of individuals that possess them, which results in a change in the frequency of these traits within a population over time. This process is known as natural selection.The correct answer to the question is option B: II, IV, and V. Natural selection requires several factors to bring about evolution. The three requirements for evolution by natural selection are differential survival and reproduction, variation in phenotype, and heritability of phenotypic variation. Sexual reproduction also influences evolution, but it is not a requirement for natural selection.

Natural selection and evolution occur in the following way: there is a variation in a trait, the variation leads to differential survival, and over time, the trait becomes more or less frequent. When the frequency of a trait changes due to natural selection, it leads to evolution. Hence, options II, IV, and V are requirements for evolution by natural selection.

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The correct answer is "All of the Above". All four indicators (dental development, epiphyseal fusion, pubic symphysis morphology, and all of the above) are age indicators for adults.

Age indicators for adults:

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Answer:

high energy

Explanation:

 There are two factors involved in cellular respiration. They are Nicotinamide adenine dinucleotide (NAD+) and flavin adenine dinucleotide (FAD+). They both are in charge of accepting the high-energy electrons and carry them to the electron transport chain. There they used to synthesize ATP molecules.

Inguinal hernias can currently be repaired laparoscopically using five different methods: reduction of the sac with or without closure of the ring, transabdominal preperitoneal (TAPP), transabdominal totally extraperitoneal (eTEP), intra-peritoneal onlay mesh (IPOM), and totally extraperitoneal (TEP) repair. According to our view, surgeons who are interested in a laparoscopic approach should be proficient in all procedures in order to meet the demands of all patients and be able to switch to a different technique as needed.

The eTEP procedure is a tool that hernia surgeons can use. In comparison to the traditional TEP procedure, this technique will be simpler for residents and surgeons with less expertise to learn. It can extend the extraperitoneal approach's standard indications to individuals with challenging body habits, a close umbilicus-pubis distance, and histories of pelvic surgery. The indications for the conventional TEP procedure can be broadened to more difficult instances as the surgeon's skill grows.

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Answer:

(i) Sprouting is the natural process by which seeds or spores germinate and put out shoots, and already established plants produce new leaves or buds or other newly developing parts experience further growth.

(ii) It makes up much of your bones and teeth and plays a role in heart health, muscle function and nerve signaling

Rhythm Salsa resulted from the development of a muscle cell culture technique.

To obtain a cell culture, it is necessary to disaggregate the original tissue, which can be by mechanical force or enzymatic process. These cells are grown in an adherent layer in a single layer (monolayer) or in organoid format (3D culture) or in suspension.

With this information we can conclude that rhythm Salsa resulted from the development of a muscle cell culture technique.

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Answer:

Darwin's theory.

Explanation:

The researcher who conducted an investigation on a blood disease carried by birds found out that the organism is unicellular and has a nucleus, cell wall, and the ability to produce spores. Based on this information, the organism belongs to the Kingdom Fungi.

The kingdom Fungi consists of unicellular and multicellular organisms that lack chlorophyll and reproduce asexually and sexually by forming spores. They are heterotrophic organisms, which means they depend on other organisms for their food. Fungi cells have a cell wall made up of chitin, which provides strength and rigidity to the cell wall. The cytoplasm of the fungal cells contains many specialized organelles, including nuclei, ribosomes, mitochondria, and Golgi bodies that carry out various metabolic activities.

The researcher's findings suggest that the organism is a unicellular fungus with a nucleus, cell wall, and the ability to produce spores. Spores play a crucial role in the fungal life cycle, as they allow the organism to reproduce and spread to new habitats. These spores can be transported by wind, water, or other organisms to colonize new areas.

In conclusion, based on the researcher's investigation, the organism she isolated from the blood of an infected bird belongs to the Kingdom Fungi.

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In the absence of the Na+/K+-ATPase activity, cotransport by secondary active transport and maintenance of the electrochemical gradient does not occur (Option D).

Na+/K+-ATPase is a primary active transporter that moves sodium and potassium ions across the plasma membrane against their concentration gradients.

ATP hydrolysis supplies the energy needed to move the ions against the concentration gradient.

The sodium concentration is lower inside the cell than outside, and the potassium concentration is higher inside the cell than outside.

The Na+/K+-ATPase maintains the sodium and potassium concentration gradients by transporting three sodium ions out of the cell for every two potassium ions it transports into the cell. This helps to maintain the electrochemical gradient for the ions across the plasma membrane, which is important for a variety of cell functions.

In the absence of the Na+/K+-ATPase activity, the maintenance of the electrochemical gradient does not occur, which makes it difficult for the cell to maintain homeostasis. In addition, secondary active transport, also known as cotransport, relies on the energy of the electrochemical gradient to move molecules across the membrane, so it would also be affected.

Hence, the correct answer is Option D.

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Answer:cell walls, cell membrane, mitochondria and nucleus

hope this helps(:

Explanation:

The examples provided, a, b, and c, all demonstrate different mechanisms of repair or replacement of damaged cells in the body.

a. A scrape being healed: When you experience a scrape or a minor injury, the body initiates a healing process. Specialized cells called platelets form a clot to stop bleeding, and immune cells migrate to the site of injury to clean it up and prevent infection. Fibroblasts then produce collagen, a protein that forms the framework for new tissue growth.  New blood vessels, called capillaries, form to bring oxygen and nutrients to the healing area.

Over time, new skin cells, or epithelial cells, multiply and migrate to cover the wound, eventually closing it completely. This process is known as epithelialization and is an example of cell replacement.

b. Scars forming where a cut once belonged: In some cases, when the injury is deeper or more severe, the body's repair mechanism involves the formation of scar tissue. Scar tissue is composed of collagen fibers that help bridge the gap left by the injury.

While scar tissue is not identical to the original tissue, it provides a functional substitute, helping to restore the structural integrity of the damaged area. Scarring occurs when the body's healing response goes beyond the normal repair process and produces excess collagen.

c. Skin flaking off your arm in the winter: The shedding or flaking of skin is a natural process called desquamation. It involves the removal of dead skin cells from the outermost layer of the epidermis. Skin cells have a lifespan and constantly undergo a cycle of renewal.

New skin cells are generated at the bottom layer of the epidermis and gradually move upward as they mature. As they reach the surface, they become flattened, lose their nuclei, and eventually slough off. This shedding helps to remove old and damaged cells and allows for the replacement of fresh, healthy cells.

In summary, a scrape being healed involves the replacement of damaged cells through a series of processes, while scars forming indicate the formation of collagen-rich tissue to repair deeper injuries. Skin flaking off represents the natural shedding of dead skin cells and the continuous renewal of the epidermis.

These examples illustrate different ways in which the body repairs or replaces damaged cells to maintain its overall health and functionality.

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The Question was Incomplete, Find the full content below :

Which examples show repair or replacement of damaged cells? a. A scrape being healed. b. Scars forming where a cut once belonged. c. Skin flaking off your arm in the winter.

Answer:

A:

Explanation:

The shape of the leaf is feathery with a rough texture

Answer:

Green, feathery leaves with a rough texture

Explanation:

got it right on my quiz

The correct answer is option (C) thus endosymbiosis is an explanation for the origin of mitochondria.

The term "endosymbiont" refers to the symbiont in endosymbiosis, which occurs when the symbiont resides inside the body of its host. The partnership between Rhizobium and plant legumes is an illustration of endosymbiosis. The endosymbiont that lives inside the roots of legumes is called rhizobium. The main driving force behind eukaryotic cell evolution is endosymbiosis. Recent research on the evolution of algae has revealed that endosymbiosis has taken place multiple times and has produced a variety of eukaryotic cells. Molecular mechanisms for the induction of endosymbiosis between various protists are unknown, despite the significance of this phenomenon.

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The origin of mitochondria can be explained via endosymbiosis, which is option (C) in the correct response.

The symbiont in endosymbiosis, which takes place when the symbiont resides inside the body of its host, is referred to as a "endosymbiont." An example of endosymbiosis is the relationship between Rhizobium and plant legumes. Rhizobium is the name of the endosymbiont that resides inside the roots of legumes. Endosymbiosis is the primary mechanism guiding eukaryotic cell evolution. Endosymbiosis has occurred several times and has resulted in the production of a diversity of eukaryotic cells, according to recent studies on the development of algae. Despite the importance of this phenomena, the molecular mechanisms for the induction of endosymbiosis across different protists are unknown.

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DNA polymerase I is the enzyme that eliminates RNA primers and substitutes dNTPs for them during DNA replication. Here option E is the correct answer.

DNA polymerase I is a type of enzyme involved in DNA replication. It has multiple functions, including the removal of RNA primers that are necessary for the initiation of DNA replication. Once the RNA primers have been removed, DNA polymerase I replace them with DNA nucleotides (dNTPs), thus completing the synthesis of the DNA strand.

Other enzymes involved in DNA replication include DNA helicase, which unwinds the double-stranded DNA, and primase, which synthesizes RNA primers. DNA ligase, on the other hand, seals any breaks or gaps that may be present in the DNA strand after replication.

Understanding the roles and functions of these enzymes is crucial in understanding the DNA replication process, and can help researchers develop new methods for manipulating DNA sequences for various purposes, such as gene therapy or genetic engineering.

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Complete question:

The enzyme that removes RNA primers and replaces them with dNTPs during DNA replication is called:

A - DNA ligase.

B - Primase.

C - Reverse transcriptase.

D - Helicase.

E - DNA polymerase i.