Answer:
look at the picture, i wrote in french but o think yoi could understand
-2r - r + 8 combine the like terms to create an equivalent expression
Hey there!
-2r - r + 8
= -2r - 1r + 8
COMBINE the LIKE TERMS
= (-2r - r) + 8
= -3r + 8
Therefore, your answer is most likely:
-3r + 8
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
WILL MARK BRAINLIEST!! PLEASE HELP ASAP.
1. If a scooter travels 36 miles on just 3 gallons of gas, how far will it travel on 16 gallons of gas?
2. A babysitter earns $28.50 for 2 hours of work. If she gets paid $99.75, then how many hours did she work?
3. A moose travels 4.5 kilometers in 5 hours. How far will it travel in 60 hours?
4. If 3 cm. of silver chain costs $9.60, then how much chain will $22.40 buy?
5. If a train ticket costs $145.50 to travel 50 miles, how far will $552.90 allow you to travel?
6. If $239.85 buys 369 liters of oil, then how much oil will $1.95 buy?
7. If you travel 220 miles in 66 hours, how far will you travel in just 3 hours?
8. If a gallon of aviation fuel costs $17.50, then how much will 8.2 gallons cost?
9. A snail crawls 7 cm in 2 minutes. At this rate, how far will it travel in 13 minutes?
10. If 17 kg of fertilizer covers 4 acres, how many kg will be needed to cover 244 acres?
11. How much will 4.4 gallons cost if 1 gallon costs $2.85?
12. Lunchmeat costs $2.50 for 5 oz. How much lunch meat will $32.50 buy?
(PLEASE EXPLAIN HOW YOU GOT THE ANSWER PLSS)
Answer:
you bad
Step-by-step explanation:
ferfrfvrgb rg bg bb
Question 10(Multiple Choice Worth 1 points)
(03.05 MC)
Look at the cups shown below (images are not drawn to scale):
A cone is shown with width 2 inches and height 3 inches, and a cylinder is shown with width 2 inches and height 7 inches.
How many more cubic inches of juice will cup B hold than cup A when both are completely full? Round your answer to the nearest tenth.
18.8 cubic inches
21.9 cubic inches
25.1 cubic inches
32.6 cubic inches
Cup B will hold approximately 18.8 cubic inches more volume juice than Cup A when both are completely full.
To answer this question, we first need to find the volume of each cup. We are given the dimensions of a cone (Cup A) and a cylinder (Cup B). The formula for the volume of a cone is (1/3)πr^2h, and the formula for the volume of a cylinder is πr^2h.
STEP 1. For Cup A (cone):
- Radius (r) = width/2 = 2/2 = 1 inch
- Height (h) = 3 inches
- Volume = (1/3)π(1)^2(3) = π cubic inches
STEP 2. For Cup B (cylinder):
- Radius (r) = width/2 = 2/2 = 1 inch
- Height (h) = 7 inches
- Volume = π(1)^2(7) = 7π cubic inches
Now, we need to find the difference in volume between Cup B and Cup A:
Difference in volume = Volume of Cup B - Volume of Cup A
= 7π - π
= 6π cubic inches
≈ 18.85 cubic inches
Rounding to the nearest tenth, the difference is approximately 18.8 cubic inches.
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pls help asap :(!!!!!!!
The midpoints of the segment is (4, -3.5).
What is Section Formula?The coordinates of the point A(x, y) which divides the line segment joining the points P(a , b) and Q(c , d) internally in the ratio m : n are given by the formula: P ( x , y ) = ( a x n + c x m / (m+n) , bn + dn / (m+n))
Given:
Points (-4, -7) and (12, -6).
So, the ratio is line is m:n = 1:1
let (x, y) be the midpoint.
Now, using section formula
x = (-4 x 1 + 12 x 1)/ (1+1)
x= (-4 +12) /2
x= 8/2
x= 4
and, y = (-7 x 1 -6 x 1)/ 2
y = -7-6/2
y = -13/2
y = -3.5
Hence, the midpoints are (4, -3.5).
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What is the probability that the test will fail to decide
is true when in reality =72. 5?
Determined by various factors such as sample size, statistical significance, and the chosen level of confidence. the probability that the test will fail to decide that the true value is 72.5 when it is indeed 72.5.
In order to calculate the probability of a Type II error, one would need to know the specific details of the test being used, such as the sample size, the statistical power of the test, and the chosen level of significance.
In general, the probability of a Type II error increases as the sample size decreases and the level of significance decreases. This means that if the test being used is not sufficiently powered or if the level of confidence is too low, there is a higher probability of failing to detect a true effect.
If the test is not able to accurately determine if the statement is true or not when the actual value is 72.5, then there is a possibility that a Type II error has occurred. The probability of this error depends on the specific details of the test being used and cannot be determined without further information.
The probability of a test failing to decide a certain hypothesis is true, when it is actually true, can be determined using the concept of Type II error or false negative rate. In statistical hypothesis testing, Type II error (β) refers to the probability of failing to reject a false null hypothesis. These factors influence the power of the test, which is the probability of correctly rejecting the null hypothesis when it is false. The power of the test (1 - β) is complementary to the probability of making a Type II error.
In this case, the null hypothesis (H0) could be that the value is not equal to 72.5,
while the alternative hypothesis (H1) states that the value is equal to 72.5.
The probability you are looking for is the Type II error rate when the true value is 72.5.
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Alex is adding baseball cards to sleeves in his binder. He filled 2 7 of his binder the first day. On the second day he filled 4 7 . How much of his binder did Alex fill in those two days
Answer:
Alex filled 6 7 of his binder.
Step-by-step explanation:
Identify the slope of the line y−1=−6(x−3).
Answer:
The slope of the line is -5
bob thinks the inverse of y=2x-5 is y =5x-2 identify his error and find the correct inverse
Answer:
yea he is wrong
Step-by-step explanation:
He is wrong because you cant not just switch the variable. If you move the variable the value will change.
Question 1(Multiple Choice Worth 2 points)
(Circle Graphs MC)
The circle graph describes the distribution of preferred transportation methods from a sample of 400 randomly selected San Francisco residents.
circle graph titled San Francisco Residents' Transportation with five sections labeled walk 40 percent, bicycle 8 percent, streetcar 15 percent, bus 10 percent, and cable car 27 percent
Which of the following conclusions can we draw from the circle graph?
Together, Streetcar and Cable Car are the preferred transportation for 168 residents.
Together, Walk and Streetcar are the preferred transportation for 55 residents.
Bus is the preferred transportation for 45 residents.
Bicycle is the preferred transportation for 50 residents.
Question 2(Multiple Choice Worth 2 points)
(Appropriate Measures MC)
The box plot represents the number of tickets sold for a school dance.
A horizontal line labeled Number of Tickets sold that starts at 8, with tick marks every one unit up to 30. The graph is titled Tickets Sold for A Dance. The box extends from 17 to 21 on the number line. A line in the box is at 19. The lines outside the box end at 10 and 27.
Which of the following is the appropriate measure of center for the data, and what is its value?
The mean is the best measure of center, and it equals 19.
The median is the best measure of center, and it equals 4.
The median is the best measure of center, and it equals 19.
The mean is the best measure of center, and it equals 4.
Question 3(Multiple Choice Worth 2 points)
(Comparing Data LC)
The histograms display the frequency of temperatures in two different locations in a 30-day period.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80 to 89, at 6 above 90 to 99, at 4 above 100 to 109, and at 2 above 110 to 119. The graph is titled Temps in Desert Landing.
When comparing the data, which measure of center should be used to determine which location typically has the cooler temperature?
Median, because Desert Landing is symmetric
Mean, because Sunny Town is skewed
Mean, because Desert Landing is symmetric
Median, because Sunny Town is skewed
Question 4(Multiple Choice Worth 2 points)
(Appropriate Measures MC)
A charity needs to report its typical donations received. The following is a list of the donations from one week. A histogram is provided to display the data.
10, 11, 35, 39, 40, 42, 42, 45, 49, 49, 51, 51, 52, 53, 53, 54, 56, 59
A graph titled Donations to Charity in Dollars. The x-axis is labeled 10 to 19, 20 to 29, 30 to 39, 40 to 49, and 50 to 59. The y-axis is labeled Frequency. There is a shaded bar up to 2 above 10 to 19, up to 2 above 30 to 39, up to 6 above 40 to 49, and up to 8 above 50 to 59. There is no shaded bar above 20 to 29.
Which measure of variability should the charity use to accurately represent the data? Explain your answer.
The range of 13 is the most accurate to use, since the data is skewed.
The IQR of 49 is the most accurate to use to show that they need more money.
The range of 49 is the most accurate to use to show that they have plenty of money.
The IQR of 13 is the most accurate to use, since the data is skewed.
Question 5(Multiple Choice Worth 2 points)
(Making Predictions MC)
A recent conference had 900 people in attendance. In one exhibit room of 80 people, there were 65 teachers and 15 principals. What prediction can you make about the number of principals in attendance at the conference?
There were about 820 principals in attendance.
There were about 731 principals in attendance.
There were about 208 principals in attendance.
There were about 169 principals in attendance.
Question 6(Multiple Choice Worth 2 points)
(Creating Graphical Representations LC)
A teacher was interested in the subject that students preferred in a particular school. He gathered data from a random sample of 100 students in the school and wanted to create an appropriate graphical representation for the data.
Which graphical representation would be best for his data?
Stem-and-leaf plot
Histogram
Circle graph
Box plot
Answer 1: Together, Streetcar and Cable Car are the preferred transportation for 168 residents.
How to solveThe circle graph shows the percentage of residents who prefer each transportation method, and the total sample size is 400.
For streetcar, (15/100) x 400 = 60 residents prefer it, and for cable car, (27/100) x 400 = 108 residents prefer it.
Together, Streetcar and Cable Car are the preferred transportation for 60 + 108 = 168 residents.
Answer 2: The median is the best measure of center, and it equals 19.
The box plot shows the distribution of the number of tickets sold for a school dance.
The median is the middle value of the data when arranged in order, and it is represented by the line in the box. In this case, the median is 19. The mean, on the other hand, can be influenced by extreme values, and we cannot determine it from the box plot alone.
Answer 3: Median, because Sunny Town is skewed.
When comparing the data, we need to consider the measure of center that is less affected by extreme values, and that is the median.
The median is the middle value of the data when arranged in order. The histogram for Sunny Town is skewed to the right, which means that there are some very high values that are affecting the mean.
Therefore, the median is the better measure of center to determine which location typically has the cooler temperature.
Answer 4: The IQR of 13 is the most accurate to use, since the data is skewed.
The histogram shows the frequency of donations received by a charity, and the data is skewed to the right.
The IQR (Interquartile Range) is the difference between the third quartile (Q3) and the first quartile (Q1), which represents the middle 50% of the data.
The IQR is less sensitive to extreme values and is a better measure of variability for skewed data. In this case, the IQR is 49 - 42 = 7, which is the most accurate measure of variability to use.
Answer 5: There were about 15 principals in attendance.
In the exhibit room, out of 80 people, 15 are principals.
We can assume that the proportion of principals in the exhibit room is the same as the proportion of principals in the conference.
Therefore, the estimated number of principals in the conference is (15/80) x 900 = 168.75, which is approximately 169.
Answer 6: Histogram
The teacher wants to represent the subject preferences of 100 students. A histogram would be the best graphical representation to use because it shows the frequency distribution of a continuous variable, which in this case could be the number of students who prefer each subject.
A stem-and-leaf plot is used for small datasets, and a box plot is used to display the distribution of a continuous variable across categories. A circle graph is more appropriate for displaying categorical data, such as the percentage of students who prefer each subject.
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what are type of petty cash book ?
Answer:
columnar petty cash book & imprest petty cash book
Step-by-step explanation:
how do I find the value of variable and the measure of the angles
1) Since the sum of interior angles yields 180º, no matter which type of triangle it is.
2) Then we can write
3x+12 +x +6x +8 = 180
10x +20 = 180º
10x = 180-20
10x = 160
x= 16
2.2 Let's find out the measurement of each angle
m∠ A= x Plug into that the value of x
m∠ A = 16º
m∠B= 3x+12 Plug into that the value of x
m∠B = 3(16) +12
m∠B = 48+12
m∠B =60
3) Then the answers are:
x = 16
m∠ A = 16º
m∠B =60
Please help! I don't understand!
Answer: I think it would be 15 inches but don't trust me I'm bad at math
Step-by-step explanation:
Answer:
I think it's 15 inches
Step-by-step explanation:
16-1
find a general solution to the given differential equation. z''+z'-9z=0
The general solution to the given differential equation is z(t) = C1*\(e^{(3t)}\) + C2*\(e^{(-3t)}\)
The given differential equation is a second-order linear homogeneous differential equation, which can be written as:
z'' + z' - 9z = 0
To find the general solution, we first need to solve the characteristic equation:
\(r^2\) + r - 9 = 0
By factoring or using the quadratic formula, we find the roots r1 and r2:
r1 = 3
r2 = -3
Since we have two distinct real roots, the general solution of the differential equation is:
z(t) = C1 * \(e^{(r1t)}\) + C2 * \(e^{(r2t)}\)
z(t) = C1 * \(e^{(3t)}\) + C2 * \(e^{(-3t)}\)
where C1 and C2 are arbitrary constants determined by initial conditions.
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Let A= [ 2 3
-1 1]
and B= [ 2 9
-3 k ]
.What value(s) of k , if any , will make AB = BA ? Select the correct choice below and. if necessary fill in the answer box within your choice. A. k = D (Use a comma to separate answers as needed.) B. No value of k will make AB = BA
The correct answer is option B. No value of k will make AB = BA
To check whether AB = BA, we need to multiply the matrices AB and BA and see if they are equal.
AB = [ 2 3-1 1] [ 2 9-3 k ]
[ 1 0 2 ] [ 0 0 1 ]
= [ 4 + 3(0) - 2k 18 - 9(0) - 3k ]
[ 0 + 0 + 2 0 + 0 + 1 ]
= [ 4 - 2k 18 - 3k ]
[ 2 1 ]
BA = [ 2 9-3 k ] [ 2 3-1 1]
[ 0 0 1 ] [ 1 0 2 ]
= [ 4 + 27 - 6k 6 - 3k - 3 ]
[ 1 0 ]
= [ 31 - 6k 3 - 3k ]
[ 1 0 ]
For AB = BA, we need to have
4 - 2k = 31 - 6k and 18 - 3k = 3 - 3k
Solving the first equation gives k = 9, and substituting k = 9 into the second equation gives 15 = 0, which is not true. Therefore, there is no value of k that makes AB = BA.
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The population of the state of Calisota is 48.2 million in 2013 , and 49.9 million in 2017. If this growth rate holds , what will the population be in 2024 , to the nearest tenth of a million ?
The population be in 2024 , to the nearest tenth of a million is 397.5
What will the population be in 2024?We find the difference (subtract) between the original population and the population at Time 1, divide by the initial population, then multiply by 100 to obtain the Population Growth (PG).Population after n years equals P x (1+R/100)n if growth is constant at R% per year. 3. If the population is declining at a constant rate of R% annually, the population after n years will be equal to P x (1-R/100)n.
Population after n years equals
P x (1+R/100)n
48.2 * (1 - 49.9)7
397.5
The population be in 2024 , to the nearest tenth of a million is 397.5
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select all answers that are true.
The correct trigonometry expression are
sin 48 = a/c
tan 42 b/a
sin 42 = b/c
cos 48 = b/c
How to determine the correct expressionsThe correct expression is worked using SOH CAH TOA
Sin = opposite / hypotenuse - SOH
Cos = adjacent / hypotenuse - CAH
Tan = opposite / adjacent - TOA
The right angle triangle is labelled as follows
for angle 48
opposite = a
adjacent = b
hypotenuse = c
for angle 42
opposite = b
adjacent = a
hypotenuse = c
This help us to get the expressions as required
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limh→0 (e^(2+h) - e2)/h =
A 0
B 1
C 2e
D e2
E 2e2
As h approaches 0, the limit becomes: e(²+0) = e²
The answer is D, e².
The given expression is lim(h→0) (e(2+h) - e²)/h. To find the limit, we can apply L'Hopital's Rule since we have an indeterminate form of the type 0/0. L'Hopital's Rule states that if lim(f(x)/g(x)) as x→a is indeterminate, then it is equal to lim(f'(x)/g'(x)) as x→a, provided the limit exists.
Here, f(h) = e^(²+h) - e^² and g(h) = h. Let's find their derivatives:
f'(h) = d(e(²+h) - e^²)/dh = e^(²+h)
g'(h) = dh/dh = 1
Now, applying L'Hopital's Rule:
lim(h→0) (e(²+h) - e²)/h = lim(h→0) (e²+h))/1
As h approaches 0, the limit becomes:
e(²+0) = e²
So, the answer is D, e².
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Evaluate the expression.
Answer:
5
Step-by-step explanation:
3^2 x ( 2 + 3)/ (2+1) x 3
3^2 x 5/3 x 3
9 x 5/ 3x 3
45/9
=5
Anais goes to the store to get granola bars 1 pack of 100 granola bars is $8.67.
Another pack of granola bars is 50 granola bars for $5.48. Which is the better buy?
The better option is to buy the Granola bar.
What is a unit value?
When the expenditures or value of production of an item is divided by the quantity, the result is known as a unit value. The unit value of a set of homogeneous products is the total value of the purchases/sales divided by the sum of the quantities.
To determine which is the better buy, you need to compare the price per granola bar for each option. To do this, you can divide the price of each pack by the number of granola bars it contains.
For the first pack of 100 granola bars, the price per granola bar is $8.67 / 100 granola bars = $0.09 per granola bar.
For the second pack of 50 granola bars, the price per granola bar is $5.48 / 50 granola bars = $0.11 per granola bar.
Since the price per granola bar is lower for the first pack, it is the better buy. You would save money by purchasing the first pack of 100 granola bars instead of the second pack of 50 granola bars.
Hence, the better option is to buy the Granola bar.
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Which statements could he include in his explanation? select two options. the domain of both functions is all real numbers. the domain of f(x) is x > 5. the domain of g(x) is x > 5. the range of f(x) is y > 0. the range of g(x) is y > 0.
The correct option is 'The domain of both functions is all real numbers'.
According to statement
Here, functions are f(x) = 5x and g(x) =5x
Since the domain of f(x) is, D= { x : x belongs to all real numbers.}
Therefore, Domain of f(x) is all real numbers.
Since f(x) and g(x) have the same value,
Therefore, Domain of g(x) is also the set of real numbers.
Now, range of f(x) is , R= { 5x : x belongs to all real numbers.}
Therefore, Range of f(x) is all real numbers.
Range of g(x) is also all real numbers.
So, we can say by the above explanation, only option (1) is correct.
DISCLAIMER: The question was incomplete. Please find the full content below.
QUESTION
Keshawn is asked to compare and contrast the domain and range for the two functions.
f(x) = 5x
g(x) = 5x
Which statements could he include in his explanation? Check all that apply.
1. The domain of both functions is all real numbers.
2. The domain of f(x) is x > 5.
3. The domain of g(x) is x > 5.
4. The range of both functions is y > 5.
5. The range of f(x) is y > 0.
6. The range of g(x) is y > 0.
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2x + 3y = 16
4x - 3y =-4
a parallelogram has exactly 1 pair of parallel sides. T/F
The given statement "a parallelogram has exactly 1 pair of parallel sides. " is false because a parallelogram has two pairs of parallel sides.
This is one of the defining characteristics of a parallelogram. Opposite sides of a parallelogram are parallel and congruent, meaning they have the same length. The parallel sides are formed by the pairs of opposite sides that do not intersect. This property gives the parallelogram its unique shape and symmetry. If a quadrilateral has only one pair of parallel sides, it would not be classified as a parallelogram.
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Why are we here what is the purpose?
Answer:
We are here because we need help with a particular course or question
Step-by-step explanation:
Our goal is to try our best and explain to others to their understanding (and win titles)
BOOM!!!
Abc is an equilateral triangle. abuvwxyz is a regular octagon and bcmno is a regular pentagon. the triangle is outside both the octagon and the pentagon, but shares a side with each. if the perimeter of buvwxyzacmno is 160, then what's the perimeter of abc?
The perimeter of ABC is 30 because the length of each side of ABC is one-third of the sum of the side lengths of the regular octagon and pentagon.
Given, ABC is an equilateral triangle, and abuvwxyz is a regular octagon, and bcmno is a regular pentagon. It's given that the triangle is outside both the octagon and the pentagon but shares a side with each. Let's call the side that ABC shares with the octagon, and pentagon as x.
The perimeter of the octagon is equal to the product of the number of sides and the length of each side of a regular octagon, so the perimeter of the octagon is 8x. Similarly, the perimeter of the pentagon is 5x.
Now, we are given that the perimeter of the whole figure is 160. Therefore,
AB + BC + AC + pentagon perimeter + octagon perimeter = 160
AB + BC + AC + 8x + 5x = 160
AB + BC + AC + 13x = 160
Since ABC is an equilateral triangle, all sides of the triangle are equal. Therefore, we can express each side of ABC as (1/3)(AB + BC + AC), so
AB + BC + AC = 3 (side length of ABC)
Substituting the above equation in the previous equation, we get
3 (side length of ABC) + 13x = 160
3 (side length of ABC) = 160 - 13x
side length of ABC = (160 - 13x) / 3
As ABC is an equilateral triangle, all sides of the triangle are equal, so we can say that each side of ABC is (160 - 13x) / 9.
We are given that the perimeter of ABC is 30. So,
3 (side length of ABC) = 30
(160 - 13x) / 3 = 30
160 - 13x = 90
13x = 70
x = 5.4
Therefore, the length of each side of ABC is (160 - 13x) / 9 = (160 - 13(5.4)) / 9 = 10.
Hence, the perimeter of ABC is 3 × 10 = 30.
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A map of a highway has a scale of 2 inches=45 miles. The length of the highway on the map is 8 inches. There are 17 rest stops equally spaced on the highway, including one at each end. You are making a new map with a scale of 1 inch=30 miles. How far apart are the rest stops on the new map?
There are 0.375 inches far apart are the rest stops on the new map.
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
A map of a highway has a scale of 2 inches=45 miles.
The length of the highway on the map is 8 inches. There are 17 rest stops equally spaced on the highway, including one at each end.
Since, A map of a highway has a scale of 2 inches = 45 miles.
Hence, For 8 inches,
⇒ 45 × 8 / 2
⇒ 180 miles
Since, There are 2 stope at the end.
Hence, There are 16 gaps from each stop.
Since, 1 inch = 30 miles
Hence, 180 miles = 180/30 inches
= 6 inches
Thus, We get;
Distance the rest stops on the new map is,
⇒ 6 / 16 = 0.375 inches
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4. In your own words describe the difference between the natural breaks, quantile, and equal interval classification schemes that can be used to make a thematic map. Refer to lecture and homework 8.
The natural breaks, quantile, and equal interval classification schemes are methods used to categorize data for the purpose of creating thematic maps. Each scheme has its own approach and considerations: Natural Breaks, Quantile, Equal Interval.
Natural Breaks (Jenks): This classification scheme aims to identify natural groupings or breakpoints in the data. It seeks to minimize the variance within each group while maximizing the variance between groups. Natural breaks are determined by analyzing the distribution of the data and identifying points where significant gaps or changes occur. This method is useful for data that exhibits distinct clusters or patterns.
Quantile (Equal Count): The quantile classification scheme divides the data into equal-sized classes based on the number of data values. It ensures that an equal number of observations fall into each class. This approach is beneficial when the goal is to have an equal representation of data points in each category. Quantiles are useful for data that is evenly distributed and when maintaining an equal sample size in each class is important.
Equal Interval: In the equal interval classification scheme, the range of the data is divided into equal intervals, and data values are assigned to the corresponding interval. This method is straightforward and creates classes of equal width. It is useful when the range of values is important to represent accurately. However, it may not account for data distribution or variations in density.
In summary, the natural breaks scheme focuses on identifying natural groupings, the quantile scheme ensures an equal representation of data in each class, and the equal interval scheme creates classes of equal width based on the range of values. The choice of classification scheme depends on the nature of the data and the desired representation in the thematic map.
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Divide (10x^3 + 19x^2 + x - 7) by (5x + 2)
Answer:
2x² + 3x - 1 - 5/(5x +2)
Step-by-step explanation:
2x² + 3x - 1
__________________
5x + 2 | 10x³ + 19x² + x - 7
| -10x³ - 4x²
| 15x² + x
| - 15x² - 6x
| - 5x - 7
| 5x +2
| - 5
2x² + 3x - 1 - 5/(5x +2)
Candice won the lottery for 30000 dollars.However 20% of her money has to go to the state for taxes.How much money will she receive after paying taxes?
Answer:
She will receive $24,000 after paying taxes
Step-by-step explanation:
This question can be solved using a rule of three.
20% of her money has to go to the state for taxes. So she will receive 100-20 = 80%. $30000 is 100% = 1. How much is 80% = 0.8?
$30000 - 1
$x - 0.8
x = 30000*0.8
x = 24000
She will receive $24,000 after paying taxes
Kaj just started a running plan where she runs 8 miles the first week and then increases the number of miles she runs by 5% each week. If she keeps up this plan for 23 weeks, how many total miles would Kaj have run, to the nearest whole number?
Answer: 118
Step-by-step explanation: mere guess
Answer: 331
Step-by-step explanation:
When we are given a linear function, how is one way we can graph it