Solve for a.
√7a-10 - √2a+5=0


What is the root? If there is no root, choose none.

-1
1
3
none

The surface integral in terms of ρ and θ ∫∫S.((6y - 5)e^(x^2))

To evaluate ∬s.curl F•nds using Stokes' Theorem, we first need to find the curl of the vector field F and then compute the surface integral over the given surface S.

Given vector field F = (6yz)i + (5x)j + (yz(e^(x^2)))k, let's find its curl:

∇ × F = ∂/∂x (yz(e^(x^2))) - ∂/∂y (5x) + ∂/∂z (6yz)

Taking the partial derivatives, we get:

∇ × F = (0 - 0) i + (0 - 0) j + (6y - 5)e^(x^2)

Now, let's parametrize the surface S, which is the portion of the paraboloid z = (1/4)x^2 + y^2 for 0 ≤ z ≤ 4. We can use cylindrical coordinates for this parametrization:

r(θ, ρ) = ρcos(θ)i + ρsin(θ)j + ((1/4)(ρcos(θ))^2 + (ρsin(θ))^2)k

where 0 ≤ θ ≤ 2π and 0 ≤ ρ ≤ 2.

Next, we need to find the normal vector n to the surface S. Since S is oriented upward, the normal vector points in the positive z-direction. We can normalize this vector to have unit length:

n = (∂r/∂θ) × (∂r/∂ρ)

Calculating the partial derivatives and taking the cross product, we have:

∂r/∂θ = -ρsin(θ)i + ρcos(θ)j

∂r/∂ρ = cos(θ)i + sin(θ)j + (1/2)(ρcos(θ))k

∂r/∂θ × ∂r/∂ρ = (-ρsin(θ)i + ρcos(θ)j) × (cos(θ)i + sin(θ)j + (1/2)(ρcos(θ))k)

Expanding the cross product, we get:

∂r/∂θ × ∂r/∂ρ = (ρcos(θ)(1/2)(ρcos(θ)) - (1/2)(ρcos(θ))(-ρsin(θ)))i

+ ((1/2)(ρcos(θ))sin(θ) - ρsin(θ)(1/2)(ρcos(θ)))j

+ (-ρsin(θ)cos(θ) + ρsin(θ)cos(θ))k

Simplifying further:

∂r/∂θ × ∂r/∂ρ = ρ^2cos(θ)i + ρ^2sin(θ)j

Now, we can calculate the surface integral using Stokes' Theorem:

∬s.curl F•nds = ∮c.F•dr

= ∫∫S.((∇ × F)•n) dS

Substituting the values we obtained earlier:

∫∫S.((∇ × F)•n) dS = ∫∫S.((6y - 5)e^(x^2))•(ρ^2cos(θ)i + ρ^2sin(θ)j) dS

We can now rewrite the surface integral in terms of ρ and θ:

∫∫S.((6y - 5)e^(x^2))

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Answer:

6610

Step-by-step explanation:

We have tan(X) = opposite/ adjacent

tan(QBP) = PQ/BQ

tan(35) = PQ/BQ    ---eq(1)

tan(QAP) = PQ/AQ

tan(20) = \(\frac{PQ}{AB +BQ}\)

\(=\frac{1}{\frac{AB+BQ}{PQ} } \\\\=\frac{1}{\frac{AB}{PQ} +\frac{BQ}{PQ} } \\\\= \frac{1}{\frac{230}{PQ} + tan(35)} \;\;\;(from\;eq(1))\\\\= \frac{1}{\frac{230 + PQ tan(35)}{PQ} } \\\\= \frac{PQ}{230+PQ tan(35)}\)

230*tan(20) + PQ*tan(20)*tan(35) = PQ

⇒ 230 tan(20) = PQ - PQ*tan(20)*tan(35)

⇒ 230 tan(20) = PQ[1 - tan(20)*tan(35)]

\(PQ = \frac{230 tan(20)}{1 - tan(20)tan(35)}\)

\(= \frac{230*0.36}{1 - 0.36*0.7}\\\\= \frac{82.8}{1-0.25} \\\\=\frac{82.8}{0.75} \\\\= 110.4\)

PQ = 110.4

≈110

Height above sea level = 6500 + PQ

6500 + 110

= 6610

3 x 3 = 9

Y x y = y^2

3y x 3y = 9y^2

Answer:

9y²

Step-by-step explanation:

\(=3y*3y\\\\=(3y)^{2} \\\\=9y^{2}\)

Answer:

2x2x2 x11

Step-by-step explanation:

Answer:

The prime factorization of 88 is 2, 2, 2, and 11.

Answer:

1. y= 1/3x+2

2.y=-3/4x-5

Step-by-step explanation:

Answer:

4.5

Step-by-step explanation:

d=10-5.5

d= 4.5

we just need to minus 10 with 5.5 so that we can find d

The series of rigid motion transformations that map polygon A to Polygon A''' are;

A rigid transformation is a transformation in which the distance between all pairs of points on the pre-image is preserved following the transformation.

The series of rigid motion transformations that map polygon A to polygon A''' are;

Transformation from A to A'

Transformation from A' to A''

Transformation from A'' to A'''

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Given statement solution is :- a) The area of one semi-circle at one end is  58.09 square feet.

b) The area of the garden is 274.42 square feet.

c) The area in square metres is approximately 58.09 square feet.

The area of the garden is approximately 274.42 square feet, and the area in square meters is approximately 25.49 square meters.

a) To find the area of one semi-circle at one end, we need to calculate the area of a complete circle and then divide it by 2. The formula for the area of a circle is A = πr², where A represents the area and r is the radius.

Since the diameter of the semi-circle is equal to the width of the rectangular portion, which is 8.6 feet, the radius will be half of that, which is 8.6 / 2 = 4.3 feet.

Now we can calculate the area of the semi-circle:

A = (π * 4.3²) / 2

A ≈ 58.09 square feet

b) To find the area of the garden, we need to sum the area of the rectangular portion with the areas of the two semi-circles.

Area of the rectangular portion = length * width

Area of the rectangular portion = 18.4 feet * 8.6 feet

Area of the rectangular portion ≈ 158.24 square feet

Area of the two semi-circles = 2 * (area of one semi-circle)

Area of the two semi-circles ≈ 2 * 58.09 square feet

Area of the two semi-circles ≈ 116.18 square feet

Total area of the garden = area of the rectangular portion + area of the two semi-circles

Total area of the garden ≈ 158.24 square feet + 116.18 square feet

Total area of the garden ≈ 274.42 square feet

c) To convert the area from square feet to square meters, we need to know the conversion factor. Since 1 foot is approximately 0.3048 meters, we can use this conversion factor to convert the area.

Area in square meters = Total area of the garden * (0.3048)²

Area in square meters ≈ 274.42 square feet * 0.3048²

Area in square meters ≈ 25.49 square meters

Therefore, the area of one semi-circle at one end is approximately 58.09 square feet. The area of the garden is approximately 274.42 square feet, and the area in square meters is approximately 25.49 square meters.

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The x-intercepts of the graph are (-7, 0) and (4, 0)

A system of equations is a collection of two or more equations that have the same variables. A solution to a system of equations is a set of variable values that satisfy all of the equations at the same time.

Given y = x2 + 3x -28

Now we have to find the x-intercepts of the graph

When the graph passes through the x-axis then Y = 0

x2 + 3x – 28 = 0

x2 + 7x - 4x - 28 = 0

x(x + 7) - 4 ( x + 7) = 0

(x+7) (x- 4) = 0

X = -7 or 4

(-7, 0) and (4, 0)

Therefore the x-intercepts of the graph are (-7, 0) and (4, 0)

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The total surface area of the pyramid from the net is 286 square cm

To calculate the total surface area of a pyramid from its net, you need to add up the areas of all its faces.

The net of a pyramid is a two-dimensional representation of the pyramid, where the edges of the net represent the edges of the pyramid.

In this case, the nets are

Using the above as a guide, we have the following:

Area = 10 * 7 + 2 * (1/2 * 10 * 12.5 + 1/2 * 7 * 13)

Evaluate

Area = 286

Hence, the surface area is 286 square cm

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Answer:

1:2

Step-by-step explanation:

The ratio unsimplified of blue marbles to red and yellow is 3:6, but since both numbers in the ratio can be divided by 3, we can simplify the ratio to 1:2.

The mean, median, and mode of the data Lengths of Longest 3 Point Kick for NCAA Division 1-A Football  32 46 48 44 31 36 56 59 32 31 55 52 58 40 59 46 35 49 59 37 is :

Mean of the data set can be calculated as,

Mean = ∑xi/n

Here number of sample(n) = 20

So Mean,

(32+46+49+44+31+36+56+59+32+31+55+52+58+40+59+46+35+49+59+37)/20

= 905/20

= 45.25 or 45.3

Median can be calculated as,

Median = (n+1)/2 = (20+1)/2 th value = 10.5th value

Now we will sort the data from smallest to largest data value as follows

31,31,32,32,35,36,37,40,44,46,46,48,49,52,55,56,58,59,59,59

So 10th value from the sorted data is 46 and 11th value is 46

So Median = (46+46)/2 = 46

Mode of the data set is 59 as this value is occuring most of the times in the data set.

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\( \huge \pink{ \underline \mathfrak{ \green{Answer}}} \: \\ \\ \: \: \rightarrow \fbox{ a). \blue{ \: 54 \: }}\)

Step-by-step explanation:

\( \bf{Given} \: \colon 4w² + w-6, when \: \: w = -4 \\ \\ \tt \underline \red{Solution} \colon \\ \\ \rightarrow \: 4w {}^{2} + w \: - 6 \\ \\ \: put \: \: value \: \: of \: \: w \: \: in \: \: given \: \: equation \\ \\ \rightarrow \: 4( - 4) {}^{2} + \: (- 4 )\: - 6 \\ \\ \rightarrow \: 4(16) \: - 4 \: - 6 \\ \\ \rightarrow \: 64 \: - 10 \\ \\ \bf \rightarrow54\)

The area of the shaded triangle in the given diagram is determined as: 11.5 cm²

Area of a triangle = 0.5 × base × height.

To find the area of the shaded triangle, find the areas of triangle 1, 2, and 3, then subtract their sum from the area of the rectangle (see image in the attachment).

Note: one square grid = 1 by 1 cm.

Area of triangle 1:

Base = 5 cm

Height = 2 cm

Area of triangle 1 = 1/2(5)(2) = 5 cm²

Area of triangle 2:

Base = 4 cm

Height = 3 cm

Area of triangle 2 = 1/2(4)(3) = 6 cm²

Area of triangle 3:

Base = 5 cm

Height = 2 cm

Area of triangle 3 = 1/2(5)(1) = 2.5 cm²

Area of the Rectangle:

Length = 5 cm

Width = 5 cm

Area = (5)(5) = 25 cm²

Area of the shaded triangle = 25 - (5 + 6 + 2.5)

Area of the shaded triangle = 11.5 cm²

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Answer:

3

Step-by-step explanation:

The function that represents the Scooter Company's total profit is given by:

P(x) = -2x² + 250x - 2,000.

The profit function is calculated by the revenue function subtracted by the cost function, hence:

P(x) = R(x) - C(x).

In this problem, we have that:

Hence the profit function is:

P(x) = R(x) - C(x).

P(x) = 400x - 2x² - (150x + 2000).

P(x) = -2x² + 250x - 2,000.

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Part (a)

The cost is the initial cost plus the cost per slushie multiplied by the number of slushies sold.

\(C(x)=500+1.25x\)

Part (b)

The revenue is the number of slushies sold multiplied by the amount charged per slushie.

\(R(x)=3.50x\)

For given measurements, the perimeter of the quadrilateral is 30cm.

The length of a quadrilateral's border, or what remains after joining all four of its sides to form a single line segment, is referred to as the quadrilateral's perimeter. As a result, a quadrilateral's perimeter is measured in the same linear units as its sides, such as meters, inches, centimeters, etc.

This may be stated using a straightforward formula. For instance, the formula for a quadrilateral ABCD's perimeter may be written as,

AB + BC + CD + DA = The perimeter

perimeter of the quadrilateral = sum of all sides.

perimeter of the quadrilateral = 1 + 9 + 12 + 8

= 30 cm.  

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Using implicit differentiation dy/dx = -(2x + y)/(x + 2y) and d2y/dx² = -2(x² - 3xy - y²)/(x + 2y)³.

Implicit differentiation is the process of differentiating an equation in which it is not easy or possible to express y explicitly in terms of x.

Given the equation x² + xy + y² = 5,

we can differentiate both sides with respect to x using the chain rule as follows:

2x + (x(dy/dx) + y) + 2y(dy/dx) = 0

Simplifying this equation yields:

(x + 2y)dy/dx = -(2x + y)

Hence, dy/dx = -(2x + y)/(x + 2y)

Next, we need to find d^2y/dx^2 by differentiating the expression for dy/dx obtained above with respect to x, using the quotient rule.

That is:

d/dx(dy/dx) = d/dx[-(2x + y)/(x + 2y)](x + 2y)d^2y/dx² - (2x + y)(d/dx(x + 2y))

= -(2x + y)(d/dx(x + 2y)) + (x + 2y)(d/dx(2x + y))

Simplifying this equation yields:

d2y/dx² = -2(x² - 3xy - y²)/(x + 2y)³

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The volume of the rectangular prism box with the given dimensions is: 36.25 cubic inches.

Volume of a rectangular prism = (length)(width)(height)

Dimensions of the given rectangular prism box:

Volume of the rectangular prism box = (3.625)(2.5)(4) = 36.25 cubic inches.

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Answer:

f+6

f+6 =(f+6)

Answer:

The Pair Factors of 54 are (1, 54), (2, 27), (3, 18), and (6, 9) and its Prime Factors are 1, 2, 3, 6, 9, 18, 27, 54.

Step-by-step explanation:

hope this helped:)

brainliest for the brains........................

The Pair Factors of 54 are (1, 54), (2, 27), (3, 18), and (6, 9) and its Prime Factors are 1, 2, 3, 6, 9, 18, 27, 54.

Here, we have,

The factors of 54 are the numbers, that can divide 54 completely or evenly. When a pair of factors are multiplied together to produce the 54, then they are said to be pair factors. The factors divide the number completely. Hence, these factors cannot be a fraction.

Factors of 54: 1,2,3,6,9,18,27 and 54

Factor pairs of the number 54 are the whole numbers which are not a fraction or decimal number.

To find the factors of a number, 54, we will use the factorization method.

To find factors of 54, we have to divide 54 by all natural numbers from 1 to 54.

54 ÷ 1 = 54

54 ÷ 2 = 27

54 ÷ 3 = 18

54 ÷ 6 = 9

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A. The firm's short-run total cost curve can be calculated as TC = 2K + 4L. The short-run average cost curve function will be SAC = TC/Q, where Q is the output.

B. The firm's short-run marginal cost function is MC = 4/Q. The short-run total cost (STC) at 25 and 200 levels of output will be 800 and 2400 respectively. The short-run average cost (SAC) at 25 and 200 levels of output will be 32 and 12 respectively. The short-run marginal cost (SMC) at 25 and 200 levels of output will be 16 and 8 respectively.

C. The graph of the SAC and SMC curves is shown below.

SAC and SMC Graph

D. The SMC curve intersects the SAC curve at its lowest or minimum point because at this point, the SAC curve is at its most cost-efficient level, meaning that the firm's costs are minimized. This is because at this point, the marginal cost is lower than the average cost, meaning that the firm can produce additional units of output with a decreasing cost.

Answer:

75

Step-by-step explanation:

a^2+b^2=c^2

plug 21 and 72 for a and b respectively. Once plugged, c will equal 75.

Answer:

HELP ASAP THIS IS GEOMETRY

Step-by-step explanation:

HELP ME PLEASE will give brainliestHELP ASAP THIS IS GEOMETRYHELP ME PLEASE will give brainliestHELP ASAP THIS IS GEOMETRYHELP ME PLEASE will give brainliestHELP ASAP THIS IS GEOMETRYHELP ME PLEASE will give brainliestHELP ASAP THIS IS GEOMETRYHELP ME PLEASE will give brainliestHELP ASAP THIS IS GEOMETRYHELP ASAP THIS IS GEOMETRYHELP ASAP THIS IS GEOMETRYHELP ME PLEASE will give brainliestHELP ASAP THIS IS GEOMETRYHELP ME PLEASE will give brainliestHELP ASAP THIS IS GEOMETRYHELP ME PLEASE will give brainliestHELP ASAP THIS IS GEOMETRYHELP ASAP THIS IS GEOMETRY

Answer:

3.6 × 10^9

Step-by-step explanation:

When multipliying two numbers in scientific notation, the exponents in the factor of 10 will be added when the two expressions are multiplied.

Thus (1.2 ⋅ 10^28) ⋅ (3 ⋅ 10^−19) = ( 1.2 × 3 )

( 10^28 × 10^-19 ) = 3.6 × 10^(28-19) = 3.6 × 10^9

Answer:

x-intercept(s): (3,0)

y-intercept(s): (0,−6)

Step-by-step explanation:

The answer has one solution:

_______________________________

       →  x = 6 ; y = 7 ;  or, write as:  [6, 7].

_______________________________

Step-by-step explanation:

_______________________________

Given:

y = x + 1;

y = 2x – 5 ;

_______________________________

2x  – 5 = x + 1  ;  Solve for "x" ;

Subtract "x" ; and Subtract "1" ; from Each Side of the equation:

   2x  – x  – 5  – 1 = x  – x  +  1  –  1 ;

to get:  

   x   –  6  =  0  ;

Now, add "6" to Each Side of the equation;

       to isolate "x" on one side of the equation;

        and to solve for "x" :

    x   –  6   +  6 =  0  +  6  ;

to get:

       x  =  6 .

_______________________________

Now, let us solve for "y" ;  

We are given:  

  y =  x + 1  ;

Substitute our solved value for "x" ; which is:  "6" ; for "x" ; into this given equation; to obtain the value for "y" :

 y =  x + 1 ;

    =  6 + 1 ;

 y =  7 .

_______________________________

Let us check our answers by plugging the values for "x" and "y" ;

("6" ; and "7"; respectively);  into the second given equation; to see if these values for "x" and "y" ; hold true:

  Given:  y = 2x –  5 ;

        →  7 =? 2(6) –  5 ??  ;

        →  7 =? 2(6) –  5 ??  ;        

        →  7 =?  12   –  5 ??  ;

        →  7 =?   7 ?? ;

        →  Yes!

_______________________________

The answer has one solution:

       →  x = 6 ; y = 7 ;  or, write as:  [6, 7].

_______________________________

Hope this is helpful!  Best wishes!

_______________________________

Answer:

Step-by-step explanation:

\(y=(\frac{1}{g} )x\)

Constant up a proportionally is  \(\frac{1}{g}\).