Solid calcium phosphate and aqueous sulfuric acid solution react to give calcium sulfate, which comes out of solution as a solid. The other product is phosphoric acid, which remains in solution. Write an equilibrium equation for the reaction using complete formulas for the compounds with phase labels.

Answer:

n= 0.059 moles of gas

Explanation:

STEP-BY-STEP EXPLANATION:

Firstly, we need to define the ionic radius

The ionic radius is the distance between the nucleus and the electron in the outermost shell of an ion.

Recall, that the ionic radius decreases across the period and increases down the group

Given that the atomic number of Potassium is 19 and the atomic number of sodium is 11

The next thing is to write the electronic configuration of both elements

According to the electronic configuration of sodium and potassium, we will observe that sodium belongs to period 3 and potassium belongs to period 4

This implies that Sodium has 3 shells and potassium has 4 shells. Hence, the ionic radius of potassium is larger than the ionic radius of sodium.

PART B

The electronegativity difference explains which bond is more ionic. Due to the structure of potassium and sodium, potassium chloride (KCl) has a higher electronegativity and the size of potassium (K) is greater than sodium (Na) atom. Hence, (K is more electrostatic than Na).

Therefore, KCl has stronger bonding than NaCl

The nucleus contains protons and neutrons while the electron revolves around the shell.

Recall that, both sodium and potassium are alkali metals and have the same chemical properties

The electronegativity of Potassium = 0.82

The electronegativity of sodium = 0.93

The electronegativity of chlorine = 3.16

The electronegativity difference of Nacl = 3.16 - 0.93

The electronegativity difference of NaCl = 2.23

The electronegativity difference of KCl = 3.16 - 0.82

The electronegativity difference of KCl = 2.34

Hence, the electronegativity difference of KCl is higher than the NaCl

NaCl has stronger bonding than KCl due to greater lattice energy

The decrease in the size of atom results in an increase in lattice energy. The size of a sodium atom is small compared to the size of a potassium atom because sodium has three shells and potassium has 4 shells. A decrease in the size of an atom leads to an increase in lattice energy. Hence, stronger bonding is a function of lattice energy.

Therefore, NaCl has stronger bonding than KCl

Answer:

15 mL of O₂.

Explanation:

The balanced equation for the reaction is given below:

2H₂O —> 2H₂ + O₂

From the balanced equation above,

2 mL of H₂O reacted to produce 2 mL of H₂ and 1 mL of O₂.

Next, we shall determine the volume of H₂O needed to produce 30 mL of H₂. This can be obtained as follow:

From the balanced equation above,

2 mL of H₂O reacted to produce 2 mL of H₂.

Therefore, 30 mL of H₂O will also react to produce 30 mL of H₂.

Thus, 30 mL of H₂O is needed for the reaction.

Finally, we shall determine the volume of O₂ produced from the reaction. This can be obtained as follow:

From the balanced equation above,

2 mL of H₂O reacted to produce 1 mL of O₂.

Therefore, 30 mL of H₂O will react to produce = (30 × 1)/2 = 30/2 = 15 mL of O₂.

Thus, 15 mL of O₂ were produced from the reaction.

Answer:

When myocytes (aka muscle cells) are triggered at a certain point for awhile it can cause strain and pain throughout the muscle.

Answer:

Explanafgr7tfgt4ttion:

As combustion always result into the formation of water, the other type of reactions that may result into formation of water are Acid-Base Neutralization Reactions and Hydrogen and Oxygen Reaction.

Acid-Base Neutralization Reactions:

A neutralisation reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products.

H⁺ ions and OH⁻ ions combine to generate water during a neutralisation reaction. Acid-base neutralisation is the most common type of neutralisation reaction.

Example: Formation of Sodium Chloride (Common Salt):

HCl + NaOH → NaCl + H₂O

Hydrogen and Oxygen Reaction:

Water vapour is created when hydrogen gas (H₂) and oxygen gas (O₂) are combined directly. This reaction produces a lot of heat and releases a lot of energy.

Example: 2 H₂ + O₂ → 2 H₂O

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Answer:

5l NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

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Answer:

c

Explanation:

chemicals can be found in every part of our lives

By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.

Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.

STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).

First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we have STP conditions, we can substitute the values:

(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).

Simplifying the equation:

2.5 = n × 22.4149.

Solving for n (the number of moles):

n = 2.5 / 22.4149 ≈ 0.1116 moles.

Next, we can calculate the number of molecules using Avogadro's number:

Number of molecules = n × N_A.

Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).

Number of molecules ≈ 6.72 × 10^22 molecules.

Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

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Answer

Ions

Explanation

Answer:

b did the test

Explanation:

did the test

A balanced chemical equation obeys the law of conservation of mass. The reaction of HCl with Ca(OH)₂ is a weak base - strong acid reaction. The products formed are CaCl₂ and H₂O. The correct option is D.

A chemical equation in which the number of reactants and products on both sides of the equation are equal is defined as the balanced chemical equation. The coefficients are the numbers which are added to balance the chemical equation.

The balanced equation for the reaction of HCl with Ca(OH)₂ is given as:

Ca (OH)₂ (s) + 2HCl (aq) → CaCl₂ (aq) + 2H₂O (l)

Here one mole of Ca (OH)₂ reacts with two moles of HCl and gives one mole of CaCl₂ and two moles of H₂O respectively. Here Ca (OH)₂ is a white precipitate and HCl is a aqueous solution.

Thus the correct option is D.

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Answer:

Orbiter

Explanation:

Space shuttles are made out of three main parts: rocket boosters, a fuel tank, and orbiter (the part that resembles an airplane

Answer:

Explanation:

Calculate the pOH for a solution that has a hydroxide ion, (OH-) concentration of 5.02 X 10-4 M.

Calculate the pH.

Note: the answers should have three significant figures

Answer:

cold or ice?

Explanation:

have a good day.

Answer:

potassium and calcium

Answer:

The correct option is b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)

Explanation:

The relation between Kc and Kp is given by the following equation:

\(Kp = Kc (RT)^{dn}\)

where R is the gas constant (0,082 L.atm/K.mol), T is the temperature (in K) and dn is the change in moles.

The change in moles (dn) is calculated as:

dn = moles of products - moles reactants

If dn=0, RT= 1 ⇒ Kc=Kp

We calculate dn for each reaction from the estequiometrial coefficients of products and reactants as follows:

a) 4 NH₃(g) + 3 O₂(g) ⇌ 2 N₂(g) + 6 H₂O(g)

dn= (2+6) - (4+3) = 1 ⇒ Kc ≠ Kp

b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)

dn = (1+1) - (1+1)= 0 ⇒ Kc = Kp

c) 2 N₂(g) + O₂(g) ⇌ 2 N₂O(g)

dn= 2 - (2+1) = -1 ⇒ Kc ≠ Kp

d) 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g)

dn = 2 - (2+1) = -1 ⇒ Kc ≠ Kp

The reaction in which Kc=Kp is b), because reactants and products have the same number of moles.

Answer:

80.2L

Explanation:

Given parameters:

Initial volume of oxygen = 47.2L

Initial pressure of oxygen = 1240torr

Final pressure  = 730torr

Unknown:

Final volume  = ?

Solution:

To solve this problem, we apply the Boyle's law proposed by Robert Boyle. It states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

             P₁V₁ = P₂V₂

P and V are pressure and volume

1 and 2 are initial and final states

              1240 x 47.2  = 730 x V₂  

                  V₂  = 80.2L

Answer:

A botfly that lays an egg in the skin of an animal when the larvae hatches from the egg, it burrows deep into the skin. The animal that may become sick from having the larvae under its skin is called Mutualism.

Explanation:

The animal is the host while the botfly is the parasite. A mutualism in which one mutualistic partner removes parasites, as well as dead or diseased skin from another, in return receiving a steady supply of food is called Pollination. Nearly all pollination services involve a mutualism that has evolved over millions of years. Another example is reproduction.

The empirical formula of the compound is C10H15N5O15S.

To determine the empirical formula of the compound, we need to calculate the mass of each element in the compound and then find the ratios of the elements.

Let's start with the combustion analysis:

Mass of CO2 produced = 1.53 g

Mass of H2O produced = 0.940 g

Using the molar masses of CO2 (44.01 g/mol) and H2O (18.02 g/mol), we can calculate the moles of carbon and hydrogen in the compound:

Moles of carbon = 1.53 g / 44.01 g/mol = 0.0348 mol

Moles of hydrogen = 0.940 g / 18.02 g/mol = 0.0521 mol

Next, let's consider the reaction with SO3:

Mass of compound = 6.37 g

Mass of SO3 produced = 6.53 g

Using the molar mass of SO3 (80.06 g/mol), we can calculate the moles of sulfur in the compound:

Moles of sulfur = 6.53 g / 80.06 g/mol = 0.0816 mol

Finally, let's consider the reaction with HNO3:

Mass of compound = 8.43 g

Mass of HNO3 produced = 3.40 g

Using the molar mass of HNO3 (63.01 g/mol), we can calculate the moles of nitrogen in the compound:

Moles of nitrogen = 3.40 g / 63.01 g/mol = 0.054 mol

We also know that the total mass of the compound is 2.72 g + 6.37 g + 8.43 g = 17.52 g.

Now we can find the empirical formula of the compound by dividing the moles of each element by the smallest number of moles. The smallest number of moles is 0.0348 mol, which corresponds to the carbon atoms in the compound.

Empirical formula = C1H1.5N0.5O1.5S0.1

To get whole number subscripts, we can multiply all the subscripts by 10:

Empirical formula = C10H15N5O15S

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Answer:

approximately 251.55 grams of AuCl3 would contain 5.0 x 10^23 molecules.

The amount of SO₂(g) in the reaction vessel has a lower value compared to its value at the original equilibrium. Option d is correct choice.

Injecting pure O₂(g) into the reaction vessel at a constant temperature will cause the system to shift towards the right side of the equation in order to consume the added O₂. This means that the amount of SO₂(g) in the reaction vessel will decrease, while the amount of SO₃(g) and O₂(g) will increase.

Since the reaction is exothermic, adding O₂(g) will not change the equilibrium constant (Keq) of the reaction, so (A) is not affected. However, the amount of O₂(g) in the reaction vessel will increase, so (C) has a higher value compared to its value at the original equilibrium.

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--The complete question is, 2SO(g) <-> 2SO₂(g) + O₂(g)

After the eq. represented above is established, some pure O₂(g) is injected into the reaction vessel at a constant temperature. After equilibrium is reestablished, which of the following has a lower value compared to its value at the original equilibrium?

A. Keq for the reaction

B. The amount of SO₃(g) in the reaction vessel

C. The amount of O₂(g) in the reaction vessel.

D. The amount of SO₂(g) in the reaction vessel.--

Answer: how old are you

Explanation:

Your answer should be -selective breeding

\(hope that helps\)

Answer:

6.02 X 1023 atoms of oxygen.

Explanation:

One mole of atoms of oxygen has a mass of 16 g, as 16 is the atomic weight of oxygen, and contains 6.02 X 1023 atoms of oxygen.

the number of oxygen atoms an oxygen molecule has is two oxygen atoms

While either glucose and fructose circles are in this state, only the fructose rings are still in equilibrium with only an extended chain form.

The major source of energy for the body's cells is glucose, which is present in the blood as sugar. The body can make glucose from those other molecules or it can get it from the food we eat. Glucose is transported to the cells by the circulation. One hormone that controls blood glucose levels is insulin.

Some foods that are naturally high in pure glucose include sweet maize, syrup, agave syrup, dried apricots, fruits, and fruit juices. when included in a well-balanced food and consumed in moderation.

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