Sliding contacts- X X - X X X www A rectangular coil of N turns with length a and width b rotates at frequency f in a uniform magnetic field B. The coil is connected to co-rotating cylinders, against which metal brushes slide to make contact. 1. Calculate the mathematical expression of the induced voltage. 2. Design a loop with values a and b that will produce 120 V with f = 60 Hz. Use a uniform magnetic field of 0.5 T

Technical practice incorporates build-time identification of security vulnerabilities in the code is  Penetration testing.

A penetration test, sometimes referred to as a pen test or ethical hacking, is a legitimate simulated cyberattack on a computer system that is carried out to analyze the system's security. This is distinct from a vulnerability assessment.

In order to identify and illustrate the financial effects of a system's vulnerabilities, penetration testers employ the same tools, strategies, and procedures as attackers. Reconnaissance, scanning, vulnerability assessment, exploitation, and reporting are the five stages of a penetration test.

Penetration testing is a technical activity that includes build-time discovery of security vulnerabilities in the code.

Penetration tests are essential to an organization's security because they teach staff members how to respond to any kind of intrusion from a malicious party. Pen tests are a method of determining whether a company's security procedures are actually effective.

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Answer:

eye protection safety gloves and rubber shoes and a safe ground

Explanation:

The model that predicts the duration of a contest as a function of the value of the resource is called the "Tullock's rent-seeking model".

This model was introduced by Gordon Tullock in 1967 and is widely used in political science and economics to understand how individuals and organizations compete for resources. In this model, individuals invest time and resources in order to win a contest, with the winner taking the entire prize. The duration of the contest is determined by the number of participants and the value of the prize, with larger prizes leading to longer contests. The model has been used to analyze a wide range of phenomena, from political lobbying to sports competitions.

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Saturated water at 250℃ is introduced into a throttling valve and exits the valve at 0.2321 MPa, the quality of water at the exit of the throttling valve is approximately 0.1157 or 11.57%.

To determine the quality (x) of water at the exit of the throttling valve, we can use the steam tables to find the properties of saturated water at 250°C and then use the pressure at the exit to determine the quality.

Given:

Initial state: Saturated water at 250°C

Exit pressure (P₂) = 0.2321 MPa

Steps to solve:

1. Find the specific enthalpy (h₁) and specific entropy (s₁) of saturated water at 250°C from steam tables.

2. Use the exit pressure (P₂) to find the specific enthalpy (h₂) of saturated water at that pressure from steam tables.

3. Calculate the quality (x) using the formula:

\(\[ x = \frac{h_1 - h_2}{h_{fg}} \]\)

Where \(\( h_{fg} \)\) is the specific enthalpy of vaporization (latent heat of vaporization) at the given temperature.

Let's perform the calculations:

1. From steam tables, at 250°C:

\(\( h_1 = 2796.7 \, \text{kJ/kg} \)\)

\(\( s_1 = 5.8435 \, \text{kJ/kg} \cdot \text{K} \)\)

2. From steam tables, at \(\( P = 0.2321 \, \text{MPa} \)\):

\(\( h_2 = 2507.6 \, \text{kJ/kg} \)\)

3. Find \(\( h_{fg} \)\) at 250°C:

\(\( h_{fg} = h_{\text{g}} - h_{\text{f}} \)\)

From steam tables:

\(\( h_{\text{g}} = 2676.5 \, \text{kJ/kg} \)\)

\(\( h_{\text{f}} = 100.09 \, \text{kJ/kg} \)\)

Therefore,

\(\( h_{fg} = 2676.5 \, \text{kJ/kg} - 100.09 \, \text{kJ/kg} \\\\= 2576.41 \, \text{kJ/kg} \)\)

Now, plug the values into the formula for quality:

\(\[ x = \frac{2796.7 \, \text{kJ/kg} - 2507.6 \, \text{kJ/kg}}{2576.41 \, \text{kJ/kg}} \]\)

Calculate:

\(\[ x \approx 0.1157 \]\)

Thus, the quality of water at the exit of the throttling valve is approximately 0.1157 or 11.57%.

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One of the oldest examples of a corbeled arch bridge was indeed built by the Mycenaeans, which is named as Arkadiko Bridge.

One of the oldest examples of a corbeled arch bridge built by the Mycenaeans is the Arkadiko Bridge, located in Greece. It is believed to have been built during the 13th century BC and is still standing today. The bridge was constructed using a corbeled arch technique, which involves gradually cantilevering each layer of stones until they meet in the middle to form an arch. The Arkadiko Bridge is considered a remarkable engineering feat and a testament to the advanced construction techniques of the Mycenaean civilization.

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Answer:

Explanation: 2 is thy answer

Answer:

A

Explanation:

Answer:

A) Engineers must clearly determine exactly what needs to be solved or designed.

Explanation:

Note hat you use the delete operator only on pointers that were created with the new operator. (Option C).

The delete operator is used to remove a specified property from an object. If the deletion is successful, it will return true; otherwise, it will return false.

In C++, the delete operator is used to deallocate memory that was previously allocated using the new operator. When you create a new object using the new operator, it allocates memory for the object on the heap. When you are finished with the object and no longer need it, you should use the delete operator to deallocate the memory and free it up for other objects.

It is important to only use the delete operator on pointers that were created with the new operator. If you use the delete operator on a pointer that was not created with the new operator, it can cause problems such as memory leaks or undefined behavior.

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A) Sewage Factor: It represents the proportion of water inflow that is expected to be discharged as sewage. It is used in the design of sewer systems to estimate the quantity of sewage flow that will be generated.

B) Connection Factor: It represents the percentage of buildings or properties that are expected to connect to a sewer system. It is used in the design of sewer systems to estimate the total number of connections that will be made to the system.

C) Infiltration Coefficient: It represents the rate at which water enters a sewer system through cracks, joints, and other defects in pipes. It is used in the design of sewer systems to estimate the volume of infiltration that will occur during wet weather conditions.

D) Design Period: It is the length of time for which a particular engineering project is designed to function effectively. For example, in the case of water supply systems, the design period may be 20-30 years, during which the system is expected to meet the water demand requirements of the users.

E) Drop Manhole: It is a type of manhole that is constructed at a location where the sewer pipe changes direction from a horizontal to a vertical alignment. The purpose of a drop manhole is to reduce the velocity of the sewage flow and prevent damage to the downstream sewer structures.

F) Self Cleansing Velocity: It is the minimum velocity required in a sewer pipe to prevent the deposition of solids and ensure the self-cleansing of the pipe. A value of twice the average velocity is commonly used as the self-cleansing velocity.

The factors that affect water demand include population size, economic activity, climate, lifestyle, and water pricing policies. Changes in any of these factors can influence the level of water demand in a given area. For example, an increase in population size or economic activity can lead to a higher demand for water, while the implementation of water conservation measures can reduce water demand.

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Sorry sir i don't know the answer

Answer:

E = 132.69 sin(ωt -11.56)

i(t) = 6.64 sin (ωt +48.44) A

Explanation:

given data

e1 = 80 sin ωt volts                       80 < 0

e2 = 60 sin (ωt + π/2) volts          60 < 90

e3 = 100 sin (ωt – π/3) volts        100 < -60

solution

resultant will be  = e2 + e2 + e3

E =  80 < 0 + 60 < 90 + 100 < -60

\(\bar E\) = 80 + j60 + 50 - j50\(\sqrt{3}\)

\(\bar E\) = 130 + (-j26.60)

\(\bar E\) = 132.69  that is less than -11.56

so

E = 132.69 sin(ωt -11.56)

and

as we have given the impedance

z = (10-j17.3)Ω

z = 19.982 < -60

and

i(t) = \(\frac{132.69}{19.982}\) sin(ωt -11.56 + 60)  

i(t) = 6.64 sin (ωt +48.44) A

The student can have multiple advisors; each advisor can have different roles.

To accommodate the change in requirements so that a student can have more than one advisor, the student record should be modified to include additional fields for additional advisors and roles. Each advisor can then be assigned a different role. These roles could include primary advisor, secondary advisor, or any other role the student chooses. In addition, the student should be able to assign different advisors to different courses they are taking to receive tailored advice and guidance. The student's record should be updated to reflect the changes and the additional advisors and roles should be clearly displayed. This will help the student keep track of all of their advisors and the roles they play.

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The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.

Answer:

The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.

Explanation:

Answer:

The voltage to be measured is applied between the two spheres and the distance or spacing S between them gives a measure of the sparkover voltage. ... In the case of a.c. peak value and d.c. voltage measurements, the applied voltage is uniformly increased until sparkover occurs in the gap.

Answer:

given

i=100mph

to=65 F

find thd p

p=i*f

p= 65*100=6500

Answer:

Hello your question is incomplete attached below is the complete question

answer :

I) P = t/R * 492.85

II) The final equation : PR / t  + 4M/πR3 =  б e

Explanation:

attached below is a detailed solution to the given problem

i) P = t/R * 492.85

ii) Final equation : PR / t  + 4M/πR3 = б e

Answer:

The specific enthalpy of the exit stream is 63.267 Btu per pound-mass.

Explanation:

This case represents a mixing chamber, a steady state device where two streams of the same fluid (cold and hot streams) are mixed with negigible changes in kinetic and gravitational potential energy and likewise in heat work interactions with surroundings. By Principle of Mass Conservation and First Law of Thermodynamics we have the following Mass and Energy Balances:

Mass Balance

\(3\cdot \dot m_{in} - \dot m_{out} = 0\) (1)

Where:

\(\dot m_{in}\) - Mass flow of the hot stream, in pounds-mass per second.

\(\dot m_{out}\) - Mass flow of the resulting stream, in pounds-mass per second.

Energy Balance

\(2\cdot \dot m_{in}\cdot h_{c}+\dot m_{in}\cdot h_{H}-\dot m_{out}\cdot h_{out} = 0\) (2)

Where:

\(h_{c}\) - Specific enthalpy of the cold stream, in BTU per pound-mass.

\(h_{h}\) - Specific enthalpy of the hot stream, in BTU per pound-mass.

\(h_{out}\) - Specific enthalpy of the resulting stream, in BTU per pound-mass.

By applying (1) in (2) we eliminate \(\dot m_{in}\) and clear \(h_{h}\):

\(h_{out} = \frac{2\cdot h_{c}+h_{h}}{3}\)

From Property Charts of the Refrigerant 134a, we have the following information:

Cold fluid (Subcooled liquid)

\(p = 100\,psia\)

\(T = 30\,^{\circ}F\)

\(h_{c} \approx 37.870\,\frac{Btu}{lbm}\)

Hot fluid (Superheated steam)

\(p = 100\,psia\)

\(T = 80\,^{\circ}F\)

\(h_{h} = 114.06\,\frac{Btu}{lbm}\)

If we know that \(h_{c} \approx 37.870\,\frac{Btu}{lbm}\) and \(h_{h} = 114.06\,\frac{Btu}{lbm}\), then the specific enthalpy of the resulting stream is:

\(h_{out} = 63.267\,\frac{Btu}{lbm}\)

The specific enthalpy of the exit stream is 63.267 Btu per pound-mass.

Answer:

A motor burnout is formed when a hermetic motor burns while in use.

Answer:

A) 0.0614 inches

b) The standard steel paper clip should float on water

Explanation:

The maximum diameter that the rod can have before it will sink

we can calculate this using this formula :

D = \((\frac{8\alpha }{\pi y } )^{\frac{1}{2} }\) ----- 1

∝ = value of surface tension of water at 60⁰f  = 5.03×10^−3  lb/ft

y = 490 Ib/ft^3

input the given values into equation 1 above

D = \((\frac{8*(5.3*10^{-3}) }{\pi *490 } )^{\frac{1}{2} }\)

   = 5.11 * 10^-3 ft   convert to inches

   = 5.11 *10^-3 ( 12 in/ 1 ft ) = 0.0614 inches

B) The diameter of a standard paper Cliphas = 0.036 inches

and the diameter of the rod = 0.0614. Hence the standard steel paper clip should float on water

In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

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Answer:

The value of \(\mathbf{BOD_5 \ at \ 15^0 \ C \ is \simeq 130.14 \ mg/L}\)

Explanation:

From the given information:

To find the BOD5 (in mg/L) at 15° C; we need to know the ultimate carbonaceous BOD and the reaction rate coefficient at  15° C.

So, to start with the calculation of the ultimate carbonaceous BOD by using the formula:

\(BOD_t = L_o (1-e^{-k*t})\)

where;

\(BOD _t\) = Biochemical oxygen demand at t days

\(L_o\) = the ultimate carbonaceous

∴

\(150= L_o (1-e^{-0.20*5})\)

\(L_o =\dfrac{150}{ (1-e^{-0.20*5})}\)

\(L_o =\dfrac{150}{ (1-0.3679)}\)

\(L_o =237.30 \ mg/L\)

Thus, the ultimate carbonaceous BOD = 237.30 mg/L

For the reaction rate coefficient; we use the formula:

\(k_{\tau} = k_{20} \times \theta^{\tau - 20}\)

where;

\(k_{\tau}\) = rate of the reaction constant at various temperature (T) = 15

\(k_{20}\) = rate of the reaction constant at standard laboratory = 0.20

\(\theta\) = constant = 1.047

∴

\(k_{15} =0.20 \times \theta^{15 - 20}\)

\(k_{15} =0.20 \times 1.047^{-5}\)

\(k_{15} =0.20 \times0.7948\)

\(k_{15} = 0.1590 / day\)

Thus, at 15° C, the reaction constant (k) = 0.1590 / day

Finally, the BOD5 (in mg/L) at 15° C can be calculated by using the formula:

\(BOD_t = L_o (1 - e^{-k*t})\)

\(BOD_t = 237.30 \times (1 - e^{-0.1590*5})\)

\(BOD_t = 237.30 \times (1 -0.45158)\)

\(BOD_t = 237.30 \times (0.54842)\)

\(\mathbf{BOD_5 \simeq 130.14 \ mg/L}\)

Answer:

\( \therefore \) The power output of the draw-works motor is 4.36 hp

Explanation:

Given that,

As the problem given, the cable is tied of the top on the oil rig and it wraps around the lower pulley and the top pulley. So, we will be using the formula below:

Differentiate it but with respect to the time. Therefore,

Thus,

Thus, the power output should be

\( P = Fv = \bigg(\frac{600}{2}\bigg) \cdot 8 = 2400 \ lb \cdot ft/s = \frac{2400}{550} = 4.36 \ hp \)

\( \therefore \) The power output of the draw-works motor is 4.36 hp

Answer:

is a relationship between multiple tasks or milestones. The dependency chain is created relative to the task or milestone positions in the work breakdown structure in the Gantt view. The type of dependency created is a finish-start dependency with zero lag.

Answer:

13.4 mm

Explanation:

Given data :

Load amplitude ( F )  = 22,000 N

factor of safety ( N )= 2.0

Take ( Fatigue limit stress amplitude for this alloy ) б = 310 MPa

calculate the minimum allowable bar diameter to ensure that fatigue failure will not occur

minimum allowable bar diameter = 13.4 * 10^-3 m ≈ 13.4 mm

attached below is a detailed solution

When an exception is thrown within a function and it is not caught within that function, the function is immediately exited and the calling function is checked for a try.

During the execution of a programme, when an exception—anomalous or exceptional conditions requiring special processing—occurs, exception handling—a process used in computing and computer programming—responds to the situation.

The specifics of how this is done vary depending on whether it is a hardware or software exception and how the software exception is implemented, but generally speaking, an exception interrupts the normal flow of execution and executes a pre-registered exception handler.

If provided, exception handling is made possible by specialised programming language constructs, hardware mechanisms such as interrupts, or operating system (OS) inter-process communication (IPC) features such as signals. Some exceptions, particularly those relating to hardware, may be handled so politely that execution can pick up where it left off.

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The approximate average power output is mathematically given as

P=1097.6w

Question Parameters:

Iowa with a 10 m2 swept area and 50 m hub height

Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

Generally, the equation for the average output power  is mathematically given as

\(P=0.5 \phi BAu^3*n\\\)

Where

B= Benz coefficient

n=0.8

Therefore

P=0.5*1*0.8*10*7^3*0.8

P=1097.6w

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Complete Question

What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 50 m hub height? Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2