Show the mechanism for the reaction conducted at −5 °C in CCl4.CCl4.
cyclohexene+bromine⟶dibromocyclohexanecyclohexene+bromine⟶dibromocyclohexane
Draw structures, including charges and electrons, and add curved arrows. Details count.
Step 1 Add three curved arrows to the first step.
Draw the step 1 products: 1 organic species and 1 inorganic species.

c. 276 mL of 1.58 M HCl.

To answer this question, we need to use the mole ratio between the two reactants: 1 mole of HCl for every 1 mole of NaHCO3.

In this case, we need 23.2 g of NaHCO3, which is equal to 0.273 moles (23.2 g / 84.02 g/mol).

Since we need 1 mole of HCl for every 1 mole of NaHCO3, we can calculate the number of moles of HCl needed with the following equation: 0.273 moles of NaHCO3 x 1 mole HCl/1 mole NaHCO3 = 0.273 moles of HCl.

Now we can use the molarity of HCl (1.58 M) to calculate the volume of HCl needed. 1.58 M HCl x 0.273 moles HCl/1 L HCl = 0.433 L HCl, or 433 mL of HCl. Therefore, the correct answer is c. 276 mL of 1.58 M HCl.

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Based on the information provided, we can infer that camk2 is also a kinase, since it belongs to the same gene family as camk1. Camk2 is likely to have a similar function as camk1, which is phosphorylating target proteins in the cytosol.

Gene families are groups of genes that share a common ancestry and have similar functions. Since camk1 and camk2 are in the same gene family, they are likely to have similar characteristics and functions. Camk1 is specifically mentioned as a kinase that phosphorylates target proteins in the cytosol.

Therefore, it is reasonable to infer that camk2, being in the same gene family, would also be a kinase and have a similar function of phosphorylating target proteins in the cytosol. In summary, camk2 is inferred to be a kinase that phosphorylates target proteins in the cytosol, similar to camk1.

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The neutralization reaction between iron(III) hydroxide (Fe(OH)₃) and hydrofluoric acid (HF) can be represented as follows:

Fe(OH)₃ + 3HF → FeF₃ + 3H₂O

The formula of the salt formed by this neutralization reaction is iron(III) fluoride (FeF₃).

A chemical reaction known as neutralization occurs when an acid and a base react with one another in a quantitative manner. When a chemical reaction takes place in water, neutralization ensures that the resulting solution does not include an excessive amount of hydrogen or hydroxide ions.

The acidity of the reactants will determine how much of a change there is in the pH of the solution after it has been neutralized.

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Answer:

92.37°C

Explanation:

Assuming the volume remains the same in both the states ( bicycle tire).

Then as per ideal gas equation

\(P_1/T_1 = P_2/T_2\)

where P1, P2 are pressure at two different states and T1, T2 are temperature at these two states

Given:

P1 = 1.34 atm, T1 = 33.0 ° C = 306K

P2 = 1.60 atm, T2 = ?

1.34/306 = 1.60/T_2

⇒ T2 = 1.60×306/1.34

= T2= 365.37K= 92.37°C

You would need to use 2.5 µL of the 2 M NaCl stock solution to make 500 µL of 100 mM NaCl solution

To make 500 µL of 100 mM NaCl solution, you need to have 5 x 10^-7 moles of NaCl. Given the concentration of your stock solution, the number of moles of NaCl in 10 mL of the solution can be calculated as follows:  you would need to use 2.5 µL of the 2 M NaCl stock solution to make 500 µL of 100 mM NaCl solution

moles of NaCl = \((2 M) x (10 mL) = 20 x 10^-3\) moles

To obtain \(5 x 10^-7\) moles of NaCl, you need to take \((5 x 10^-7 moles) / (20 x 10^-3 moles) x (10 mL) = 2.5 x 10^-6 mL = 2.5 µL\) of the stock solution.

Therefore, you would need to use 2.5 µL of the 2 M NaCl stock solution to make 500 µL of 100 mM NaCl solution.

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In the nitrate ion (NO3-), nitrogen and oxygen are held together by covalent bonds.

In the nitrate ion (NO3-), nitrogen and oxygen atoms are held together by covalent bonds. Covalent bonds are formed when atoms share electrons to achieve a stable electron configuration. In the case of the nitrate ion, the central nitrogen atom shares its electrons with three oxygen atoms, resulting in the formation of three covalent bonds. The covalent bonds allow for the sharing of electrons between the atoms, creating a stable and bonded nitrate ion structure.

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Answer:

5.6

Explanation:

Because of the gravity of the earth

The total interaction energy in units of eV/atom assuming λ = 4156 eV and R_0/rho = 12 is 150N eV/atom.

Given Potential for two inert gas (Xe) atoms at separation R :

U=λe^(-R/rho)-R^6/a^6

a) To calculate the potential energy of the two atoms at equilibrium separation R_0,

we have to put dU/dR = 0λ e^(-R_0/rho) = (6R_0^6)/(a^6)λ e^(-R_0/rho) = (6(12rho)^6)/(a^6)

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12)

The potential energy can be expressed as, U=λe^(-R_0/rho) = ((6(12rho)^6)/(a^6)) * e^(12) * e^(-12rho/rho)= ((6*12^6)/a^6) * e^(-11rho)

b) Given R_0 = 12rho, λ = (6(12rho)^6)/(a^6) * e^(12)

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12) = (6 * 12^6)/(a^6) * e^(12) * e^(-12) = (6 * 12^6)/(a^6)

Potential energy U = λe^(-R_0/rho) = (6 * 12^6)/(a^6) * e^(-11rho)c)

The total interaction energy in units of eV/ atom assuming λ = 4156 eV and R_0/rho = 12

Therefore, λ = (6(12rho)^6)/(a^6) * e^(12) = (6 * 12^6)/(a^6) * e^(12) * e^(-12) = (6 * 12^6)/(a^6)

Total energy (U) = (N/2)U = (N/2)λe^(-R_0/rho) = (N/2)(6 * 12^6)/(a^6) * e^(-11rho) = 150N eV/atom.

Therefore, the total interaction energy in units of eV/atom assuming λ = 4156 eV and R_0/rho = 12 is 150N eV/atom.

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Answer:

Explanation:

Multiply the coefficient 0.022414 by the number of moles to calculate the gas volume in cubic meters at the standard temperature and pressure. In our example, the volume of the nitrogen gas is 0.022414 x 2 = 0.044828 cubic meters or 44.828 liters.

Answer:

You will need a Kukushili pressure cooker for this experiment. This pressure cooker will allow you to compress the gases and observe its volume.

Answer:

0.000001 joule

Explanation:

brainlest?

The amount of a sample of 100 grams of a radioactive isotope that would remain after 732 days would be 14.0625 grams.

Given, the Half-life of the radioactive isotope = 273 days.Time elapsed = 732 days.Initial quantity or sample = 100 grams. Let's determine how many half-lives have passed since 732 days: Number of half-lives = (time elapsed) / (half-life)= 732 / 273 ≈ 2.683

Half-life #1: After the first half-life of 273 days, the sample will be halved. Therefore, after 273 days, the quantity remaining will be 1/2 * 100g = 50g

Half-life #2: After the second half-life of 273 days, the sample will be halved again. Therefore, after 546 days, the quantity remaining will be 1/2 * 50g = 25gHalf-life #3: After the third half-life of 273 days, the sample will be halved again.

Therefore, after 819 days, the quantity remaining will be 1/2 * 25g = 12.5gHowever, the time elapsed from 819 days to 732 days is 87 days. This time interval is less than the half-life. As a result, it is critical to calculate the amount that would be left over after 732 days using a different method. Let us consider the remaining amount from 819 days (12.5g) as the new initial quantity for the remaining 87 days. The half-life of the radioactive isotope is 273 days.

Therefore, the rate of decay for each day will be: Rate of decay per day = (1/2)^(1/273)≈ 0.002540401Therefore, the amount of the sample remaining after 87 days (or 0.3195 half-lives) can be calculated using the following formula: Q = Q0(0.5)^(t/h)where Q0 is the original quantity, Q is the remaining quantity after time t, and h is the half-life of the isotope. Q = 12.5g × (0.5)^(0.3195)Q ≈ 6.5625g

Therefore, the total amount of the sample remaining after 732 days can be found by adding up the amounts of the sample remaining from each half-life: Total remaining = 50g + 25g + 6.5625gTotal remaining ≈ 81.5625 the amount of a sample of 100 grams of a radioactive isotope that would remain after 732 days would be 14.0625 grams.

After 732 days, the sample would have decayed by three half-lives (819 days) and an additional 87 days. As a result, 81.5625g of the sample will remain after 732 days. Therefore, 100g - 81.5625g = 18.4375g of the sample would have decayed in 732 days.

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A vessel contains 1 mole of O2​ gas (molar mass=32) at temperature T. The pressure of the gas is P. An identical vessel containing one mole of He gas (molar mass=4) at a temperature 2T, has a pressure of 2P.

We understand that : PV=nRT

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A buffer is prepared which contains 0.10 M nitrous acid, HNO2, and 0.12 M sodium nitrite, NaNO2. (Ka=4.5x10-4) Calculate the pH after 0.016 mol of NaOH is added to 1.00 L of the buffer.

A buffer solution is an aqueous mixture of a weak acid and its conjugate base, or vice versa, known more specifically as a pH buffer or hydrogen ion buffer.

When a modest amount of a strong acid or base is applied to it, the pH hardly changes at all. A multitude of chemical applications use buffer solutions to maintain pH at a practically constant value.

Numerous living systems use buffering to control pH in the natural world. For instance, the pH of blood is controlled by the bicarbonate buffering system, and bicarbonate also serves as a buffer in the ocean is an aqueous mixture of a weak acid and its conjugate base, or vice versa, known more specifically as a pH buffer or hydrogen ion buffer.

When a modest amount of a strong acid or base is applied to it, the pH hardly changes at all. A multitude of chemical applications use buffer solutions to maintain pH at a practically constant value.

Numerous living systems use buffering to control pH in the natural world. For instance, the pH of blood is controlled by the bicarbonate buffering system, and bicarbonate also serves as a buffer in the ocean.

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Answer:

this reaction is

Explanation:

balancing

Zn+ 2AgNO3 ----> 2Ag + Zn(NO3)2

Hope this will help:)

Answer:

Multiply the length, width, and height together.

( length *, width *, height )

The answer to this is multiplication problem is the volume of the object.

Explanation:

- Do not measure the height of the entire container, just the height from one watermark to another.

I hope this helped!

Answer:

287K

Explanation:

To find the increasing in temperature for the sample of copper we must use the equation:

Q = m*C*ΔT

Q is the heat added (353J)

m is the mass of copper (3.6mol * (63.546g / mol) = 228.8g

C is specific heat (0.385J/(gK))

And ΔT is the increasing in temperature.

Solving for ΔT:

Q / m*C = ΔT

353J /228.8g*0.385J/(gK) = 4.0K

That means the final temperature of copper is:

283K + 4K =

Answer:

convection

Explanation:

it is heat transfer, and convection is 1 way of it

Answer:

HgSO₄

Explanation:

% => g => moles => ratio => reduce => empirical ratio

%Hg = 67.6% => 67.6g/201g/mol = 0.34mol

%S    = 10.8% => 10.8g/32g/mol = 0.34mol

%O   = 21.6% => 21.6g/16g/mol = 1.35mol

Hg:S:O => 0.34:0.34:1.35

Reduce to whole number ratio by dividing by the smaller mole value...

Hg:S:O => 0.34/.34:0.34/.34:1.35/.34 => Empirical Ratio = 1:1:4

∴ Empirical Formula is HgSO₄

Empirical formula of the compound is HgSO4.

The empirical formula yields the compound with the lowest whole number ratio of atoms. Empirical formula  specifies the relative number of atoms in each element in the compound. An empirical formula, in other words, provides us the relative ratios of different atoms in a compound.

A compound is a material formed by the interaction of  more than one distinct chemical element.

Calculation of empirical formula is shown as below:

Now,67.6% of Hg = 67.6 g of Hg.

10.8% of S = 10.8 g of S

21.6% of O = 21.6 g of O

Molar mass of each component which exist in compound, Hg = 200.59 g/mol, O = 15.9994 g/mol, S = 32.065 g/mol

Gram to mole conversion:

\(Hg\;=\;67.6\;.\;\frac{1\; mol}{200.59\; g}\;=\;0.337\;mol\;Hg\\S\;\;=\;10.8\;.\;\frac{1\; mol}{32.065\; g}\;=\;0.337\;mol\;S\\O\;\;=\;21.6\;.\;\frac{1\; mol}{15.9994\; g}\;=\;1.35\;mol\;O\)

Calculation of mole of elements.

\({Mole\;of\;S}\;=\;\frac{0.337\;mol}{0.337\;mol} =\frac{1}{1} \\\frac{Mole\;of\;O}{Mole\;of\;S}\;=\;\frac{1.35\;mol}{0.337\;mol} =\frac{4}{1}\)

Hence, the empirical formula will be HgSO4.

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Answer:

B

Explanation:

because b is way more precise for measuring smaller volumes of liquid

Answer:

B

Explanation:

because b is way more precise for measuring smaller volumes of liquid THANKS 00.0(0 votes)Express your feedback with quick commentsNeed a bit more clarification? Get a high-quality answer with step-by-step explanations from a professional in just minutes instead!GET A VERIFIED ANSWERAdvertisementStill have questions?FIND MORE ANSWERSASK YOUR QUESTIONNew questions in ChemistryWhich water-soluble vitamin cannot be absorbed by the intestinal mucosa unless it has been bound to intrinsic factor?What type(s) of bonds is (are) found between atoms within hydrocarbon molecules?Why are mixtures of gases, such as argon and helium, much more likely to form an ideal solution than other combinations such as solids and liquids?The number of covalent bonds that a nitrogen atom is expected to form is?(CO3) 2 is the _______ group of answer choices acetate cyanide hydrogen carbonate (bicarbonate)carbonateAnswer asap have to finish by 1Divide the scientific notationgood morning another free point question:) have a good life and the person who gave me advice i love you​perform the following mathematical operation, and report the answer to the correct numbers of significant figures 2.500 x 10^2 __________= ?x10^? 5….00 x 10^-5What information does an equilibrium constant give about a reaction? A. It tells whether products or reactants are favored at equilibrium. B. It tells…how much energy is required for the reaction to happen. C. It tells how long it takes the reaction to reach equilibrium. D. It tells what the rate constant of the reaction is at equilibrium. SUBMITLOAD MOREPreviousNextplattnicholasrAmbitious2224 pts2Answer MasterNumbers Nerd+16 moreCurrent planBrainly BasicSpecial Offers3View My AchievementsAccount SettingsYour influence2Answering StreakYour Streak is on! Answer another question tomorrow and keep it going.Fun factAn apple, potato, and onion all taste the same if you eat them with your nose plugged 1Fun factBananas are curved because they grow towards the sun ☀️233Get +6 bonus3Last 7 daysOverallYour stats from the last 7 days compared with the previous 7 daysPopularity16People learning from your answers.+1600%Brainliest2This many users said your answers were the best!+200%Thanks7Your effort is appreciated!+700%Questions answered42+4200%17 Aug - 23 Aug

The amount of energy required to boil water depends on the initial temperature of the water, the mass of the water, and the heat of vaporization of water.

The heat of vaporization of water is 40.7 kJ/mol or 2.26 kJ/g.

To completely boil 500g of water that is at 15°C, we need to first heat the water to its boiling point (100°C), and then provide the energy required for the phase change from liquid to gas.

The amount of energy required to heat the water from 15°C to 100°C can be calculated using the specific heat capacity of water, which is 4.184 J/g°C:

Q1 = m * c * ΔT

Q1 = 500g * 4.184 J/g°C * (100°C - 15°C)

Q1 = 191,020 J

The amount of energy required for the phase change from liquid to gas can be calculated as follows:

Q2 = m * Hv

Q2 = 500g * 2.26 kJ/g

Q2 = 1,130 kJ

Therefore, the total amount of energy required to completely boil 500g of water that is at 15°C is:

Qtotal = Q1 + Q2

Qtotal = 191,020 J + 1,130 kJ

Qtotal = 1,321,020 J

So, it would require 1,321,020 joules of energy to completely boil 500g of water that is at 15°C.

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Answer:

ARESENIC is in the 5A category

Explanation:

edge 2020

5A (Nitrogen group) elements tend to react to gain 3 electrons to be like noble gas.

5A group known as nitrogen group. In these group elements contains nonmetals, metals, halogens, noble gases and metalloids.

These elements react with oxygen to form acidic compounds.

Configuration of 5A group: 2s2 2p3, 3s2, 3p2

Example: nitrogen, phosphorus, arsenic etc.

Actinium (Ac) atomic number = 89 (it is a silvery radioactive metallic material. Actinium-227 is extremely radioactive element).

Arsenic (Ar) atomic number = 33 (it found in many minerals usually in combination of sulfur and metals but it also found in pure elemental crystal. It is a metalloid).

Rhenium (Re) atomic number = 75 (it is found in earth crust. It is used in additive to tungsten and molybdenum-based alloys. It is very toxic to humans it may causes skin related disease).

Therefore, 5A (Nitrogen group) elements tend to react to gain 3 electrons to be like a noble gas.

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The pH of the solution will be 10.47.

The pH of a solution is mathematically given as:

 pH = - log [\(H^+\)] of -log [\(H_3O^+\)]

Thus, in this case, with  [\(H_3O^+\)]  of 3.4 x 10-¹¹ M:

pH = -log 3.4 x \(10^-^1^1\) = 10.47

Thus, the pH of the solution will be 10.47.

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Conjugated dienes are two double bonds separated by a single bond. Nonconjugated Dienes are two double bonds are separated by more than one single bond.

In general , p-orbitals were used to identify conjugation. These p-orbitals are significantly used to make double bonds, so a lone pair  is present in p-orbitals if it is conjugate . Hence, To be a conjugated atom it must have three or more p-orbitals in a row.

If we talk about Conjugated system, the covalent chemical compound, a group or chain of atoms that carries valence electrons  and they are not engaged in single-bond formation so they modify the behavior's of each other atoms present in the vicinity .

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Answer:

7 hydrogen atoms

Explanation:

As we can see in the formula of  isopropyl alcohol, C3H70, total 7 hydrogen atoms are bound to three carbon and one oxygen atom in different manner.

Thus, it can be said that there are 7 hydrogen atoms in 1 molecule of isopropyl alcohol, C3H7O

Answer: 8 oxygen atoms and 4 hydrogen atoms. Explanation down below.

Explanation: One molecule of oxygen gas is composed of two oxygen atoms (O2). Here there is four atoms of oxygen gas which in total gives eight oxygen atoms. Same ways One molecule of hydrogen gas is composed of two hydrogen atoms (H2), so 2 atoms of hydrogen gas in total gives four hydrogen atoms. As per the formula of water, 2 (H2) and 1(O) to form a water molecule (H2O). Here there are 4 H2, so divide the number of hydrogen atoms by the number needed per water molecule i.e. 4 / 2 = 2. This means 2 water molecules will be produced.

The efficient quantity of SO2 emissions that should be released from the power plant is 16 hundred tons.

The efficient quantity of SO2 emissions that should be released from the John Amos power plant can be determined by equating the marginal damage costs (MDC) and marginal control costs (MCC). In this case, the MDC is given by 20Q (where Q is the quantity of SO2 emissions in hundreds of tons), and the MCC is given by 400 - 5Q.

To find the efficient quantity, we set MDC equal to MCC:

20Q = 400 - 5Q

Simplifying the equation, we get:

25Q = 400

Dividing both sides by 25, we find:

Q = 16

Therefore, the efficient quantity of SO2 emissions that should be released from the power plant is 16 hundred tons.

In the model representing MDC and MCC, the x-axis represents the quantity of SO2 emissions (Q in hundreds of tons), and the y-axis represents the cost (in hundreds of dollars). The MDC curve is upward-sloping, starting from the origin and increasing at a constant rate of 20. The MCC curve is downward-sloping, starting at 400 and decreasing at a constant rate of 5. The efficient quantity of 16 is labeled on the x-axis.

The areas of total costs for damages and control can be identified on the graph. The area under the MDC curve represents the total cost of damages caused by the emissions, while the area under the MCC curve represents the total cost of implementing control measures to reduce the emissions. The goal is to minimize the sum of these costs, which is achieved at the point where the MDC and MCC curves intersect, corresponding to the efficient quantity of emissions.

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