SOLUTION:
We are to select the quadratic equation that has no real solution.
Facts about Quadratic equations;
When considering,
\(b^2\text{ - 4ac}\)If you get a positive number, the quadratic will have two unique solutions. If you get 0, the quadratic will have exactly one solution, a double root. If you get a negative number, the quadratic will have no real solutions, just two imaginary ones.
Looking at all the four options, I have examined all and the only one found to be negative is the second option. Let's consider it together
a = 9, b = -25 and c = 30
(b x b ) - 4 x a x c
(-25 x -25) - 4 (9) (30)
625 - 1080
- 455
-455 < 0
Since the discriminant is less than this quadratic equation is expected to have no real solution.
You can as well try the other three options one is zero and the remaining two are greater than zero.
A diphosphonate kit contian 180 mCi of Tc99m in 30 ml when it is prepared at 8am. Immediately, a 20 mCi dose is withdrawn for a bone scan. if the patient arrives late at 9:30 and half the volume is accidentally discharged, how much volume from the kit must now be added to the syringe to correct the dose to 20 mCi? (no other doses have been withdrawn meanwhile, and the decay factor for 1.5 hrs is 0.841)
The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.
To solve this problem, we can use the concept of radioactive decay and the decay factor. Here's how we can calculate the required volume to correct the dose:
Determine the initial activity of the kit:
Initial activity = 180 mCi
Calculate the decayed activity at 9:30 (after 1.5 hours):
Decay factor = 0.841
Decay activity = Initial activity * Decay factor
Calculate the remaining activity after withdrawing 20 mCi at 8 am:
Remaining activity = Initial activity - 20 mCi
Calculate the remaining activity at 9:30:
Remaining activity at 9:30 = Remaining activity * Decay factor
Calculate the desired activity at 9:30 (20 mCi):
Desired activity at 9:30 = 20 mCi
Calculate the volume needed to achieve the desired activity:
Volume needed = Desired activity at 9:30 / Remaining activity at 9:30 * Volume at 9:30
Calculate the remaining volume at 9:30:
Remaining volume = Volume at 8 am - Volume withdrawn - Volume accidentally discharged
Calculate the volume that needs to be added:
Volume to be added = Volume needed - Remaining volume
Let's perform the calculations step by step:
Determine the initial activity of the kit:
Initial activity = 180 mCi
Calculate the decayed activity at 9:30 (after 1.5 hours):
Decay factor = 0.841
Decay activity = 180 mCi * 0.841 = 151.38 mCi
Calculate the remaining activity after withdrawing 20 mCi at 8 am:
Remaining activity = 180 mCi - 20 mCi = 160 mCi
Calculate the remaining activity at 9:30:
Remaining activity at 9:30 = 160 mCi * 0.841 = 134.56 mCi
Calculate the desired activity at 9:30 (20 mCi):
Desired activity at 9:30 = 20 mCi
Calculate the volume needed to achieve the desired activity:
Volume needed = (Desired activity at 9:30 / Remaining activity at 9:30) * Volume at 9:30
Volume at 9:30 = Remaining volume = 30 ml - (30 ml / 2) = 15 ml
Volume needed = (20 mCi / 134.56 mCi) * 15 ml = 2.236 ml
Calculate the remaining volume at 9:30:
Remaining volume = 30 ml - (30 ml / 2) = 15 ml
Calculate the volume that needs to be added:
Volume to be added = Volume needed - Remaining volume = 2.236 ml - 15 ml = -12.764 ml
Since the calculated volume to be added is negative, it means that no additional volume is required. The remaining Kit volume in the syringe is sufficient to correct the dose to 20 mCi.
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You have $500,000 saved for retirement. Your account earns 7% interest. How much will you be able to pull out each month, if you want to be able to take withdrawals for 25 years?
$3,244.21 can be withdrawn each month for 25 years, assuming an interest rate of 7% and a starting principal of $500,000.
Formula to calculate the present value of the annuityPV = PMT × [1 - (1 + r)⁻ⁿ] / r
where:
PV is the present value of the annuity
PMT is the payment amount per period
r is the interest rate per period
n is the total number of periods
In this case, we want to withdraw a fixed amount each month for 25 years, which represents 12 ×25 = 300 periods.
The interest rate per period is 7% / 12 = 0.5833%.
Let's assume that you want to withdraw a fixed amount each month, and you want the withdrawals to last for 25 years. To calculate the amount you can withdraw each month,
PV = PMT × [1 - (1 + r)⁻ⁿ] / r
500,000 = PMT × [1 - (1 + 0.005833)⁻³⁰⁰] / 0.005833
Solving for PMT, we get:
PMT = PV × r / [1 - (1 + r)⁻ⁿ]
PMT = 500,000 × 0.005833 / [1 - (1 + 0.005833)⁻³⁰⁰]
PMT = $3,244.21
Therefore, you can withdraw $3,244.21 each month for 25 years, assuming an interest rate of 7% and a starting principal of $500,000.
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Science is the favorite subject of 74% of students
at a school. There are 700 students at the school,
How many of them like science best?
Answer:
518
Step-by-step explanation:
let x be the number of people who likes the science the most.
x / 700 x 100 0.74
x = 518
Answer:
518 students
Step-by-step explanation:
74% of 700
Please Help Me ASAP.
Answer:
Parallel lines ALWAYS have the same slope
Step-by-step explanation:
The equations have unequal slopes, meaning they aren't parallel.
How do you solve this multi-step equations 8q+6=4q-14?
Step-by-step explanation:
8q + 6 = 4q - 14
8q - 4q = - 14 - 6
4q = - 20
q = -20/4 = -5
q = -5
hope this answer helps you dear take care and may u have a great day ahead!
Mai says f(x) is always greater than g(x) for the same value of x. Is this true? Explain how
You know plssss helppp
For Mai's conclusion to be true, the following inequality should be satisfied -
M{x} > G{x} for all {x} ∈ R
What are algebraic expressions?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.
Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.
Given is that Mai says f(x) is always greater than g(x) for the same value of x.
Now, for Mai's conclusion to be true, the following inequality should be satisfied -
M{x} > G{x} for all {x} ∈ R
Therefore, for Mai's conclusion to be true, the following inequality should be satisfied -
M{x} > G{x} for all {x} ∈ R
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How do you write 410,000 in scientific notation?
Answer:
4.1x10^5
Step-by-step explanation:
Suppose the average height of all humans is normally distributed with a mean of 72 inches and a variance of 18 inches.
a. Determine P(7580)
b. Determine P(x<65)
Answer:
a) P(75 < x < 80 ) = 0.2088
b) The probability that average height of all humans less than 65
P( X < 65 ) = 0.0495
Step-by-step explanation:
Step(i):-
Given mean of the Population = 72
Given variance of the Population = 18 inches.
Standard deviation of the Population = √18 = 4.242
Let 'x' be the random variable in Normal distribution
a)
Given X₁ = 75
\(Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{75-72}{4.242} = 0.70721\)
Given X₂= 80
\(Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{80-72}{4.242} = 1.885\)
The probability that average height of all humans between 75 and 80
\(P(75 < X < 80 ) = P(0.70721 < Z < 1.885)\)
= | A ( 1.885) - A( 0.70721|
= 0.4699 - 0.2611
= 0.2088
P(75 < x < 80 ) = 0.2088
b)
Step(ii):-
Given X₁ = 65
\(Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{65-72}{4.242} = -1.650\)
The probability that average height of all humans less than 65
P( X < 65 ) = P( Z < - 1.650 )
= 1 - P( Z > 1.650)
= 1 - ( 0.5 + A (1.650))
= 0.5 - A( 1.65)
= 0.5 - 0.4505
= 0.0495
The probability that average height of all humans less than 65
P( X < 65 ) = 0.0495
x-4=2(y-3) in slope intercept form?
Answer:
y = x/2 + 1
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Step 1: Write equation
x - 4 = 2(y - 3)
Step 2: Solve for slope-intercept form
Distribute 2: x - 4 = 2y - 6Add 6 to both sides: x + 2 = 2yDivide both sides by 2: x/2 + 1 = yRewrite: y = x/2 + 1find xxx
-33 = xxx+1
Answer:
\(\tt x=-34\)Step-by-step explanation:
\(\tt -33=x+1\)
First of all, let's flip the equation:-
\(\tt x+1=-33\)
Subtract 1 from both sides:-
\(\tt x+1-1=-33-1\)
Simplify:-
\(\tt x=-34\)
_________________
Hope this is what you're looking for!
Have a great day!
Answer:
-34
Step-by-step explanation:
find the lettered angles in the figure below (O is the centre of each circle)
Answer:
t and u are supplementary as opposite angles of a cyclic quadrilateral.
t = 180 - (81 + 53) = 46
u = 180 - t = 180 - 46 = 134
v and w are equal as opposite angles to equal sides.
v = w = 1/2(180 - u) = 1/2(180 - 134) = 23
Step-by-step explanation:
the question is 4 1/5 x 5/14
Answer:
3/2
Step-by-step explanation:
Simplify the following:
((4 + 1/5)×5)/14
((4 + 1/5)×5)/14 = ((4 + 1/5)×5)/14:
((4 + 1/5)×5)/14
Put 4 + 1/5 over the common denominator 5. 4 + 1/5 = (5×4)/5 + 1/5:
(((5×4)/5 + 1/5) 5)/14
5×4 = 20:
((20/5 + 1/5)×5)/14
20/5 + 1/5 = (20 + 1)/5:
(((20 + 1)/5)×5)/14
20 + 1 = 21:
(21/5×5)/14
21/5×5 = (21×5)/5:
((21×5)/5)/14
((21×5)/5)/14 = (21×5)/(5×14):
(21×5)/(5×14)
(21×5)/(5×14) = 5/5×21/14 = 21/14:
21/14
The gcd of 21 and 14 is 7, so 21/14 = (7×3)/(7×2) = 7/7×3/2 = 3/2:
Answer: 3/2
Find the value of L that Will Maximize the profit Q=L²e^0.01L
The minimum profit occurs at L = 0, where Q = 0.
To find the value of L that maximizes the profit Q = L²\(e^{(0.01L)\).
We need to differentiate Q with respect to L and find the critical points where the derivative equals zero.
Then we can determine whether each critical point is a maximum or a minimum by examining the second derivative.
Testing for critical points:Q = L²\(e^{(0.01L)\)
Q' = \(2Le^{(0.01L)\) + \(0.01 L^2e^{(0.01L)\)
= 0(2L + 0.01L²) \(e^{(0.01L)\)
= 0L (critical point) or 200 \(e^{(0.01L)\)
= 0 (extraneous, ignore)
2L + 0.01L² = 0L(2 + 0.01L) = 0L = 0 or L = -200 (extraneous, ignore)
The only critical point is at L = 0.
Testing for maximum or minimum:Q'' = \(2e^{(0.01L)\) + 0.02Le^(0.01L) + 0.0001L²\(e^{(0.01L)Q''(0)\)
= \(2e^{(0)\) = 2Since Q''(0) > 0,
The critical point at L = 0 is a minimum.
Therefore, there is no value of L that maximizes the profit.
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The values of L that will maximize the profit are 0 and -200
Finding the value of L that will maximize the profitFrom the question, we have the following parameters that can be used in our computation:
\(Q = L\²e^{0.01L\)
Differentiate the function
So, we have
\(Q' = \frac{L \cdot (L + 200) \cdot e^{0.01L}}{100}\)
Set the equation to 0
\(\frac{L \cdot (L + 200) \cdot e^{0.01L}}{100} = 0\)
Cross multiply
\(L \cdot (L + 200) \cdot e^{0.01L} =0\)
When expanded, we have
L = 0, L + 200 = 0 and \(e^{0.01L} =0\)
When solved for L, we have
L = 0 and L = -200
Hence, the values of L are 0 and -200
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consider the modified keynesian model with a change in the way that taxes are incorporated:
a) The Keynesian cross graphs an economy's planned expenditure function,
\($\mathrm{E}=\mathrm{C}(\mathrm{Y}-\mathrm{T})+\mathrm{I}+\mathrm{G}$\),
and the equilibrium condition that actual expenditure equals planned expenditure.
How do you find the expenditure function?
To derive the expenditure function we can either (i) invert V(·) and solve for M, or (ii) set up the dual of the consumer's choice problem, solve for Hicksian demand functions and substitute them into the objective (i.e., expenditure) function.
The amount by which\($\mathrm{Y}$\)falls is given by the product of the tax multiplier and the increase in taxes
\(: $\Delta \mathrm{Y}=[-\mathrm{MPC} /(1-\mathrm{MPC})] \Delta \mathrm{T}$.\)
c) We can calculate the effect of an equal increase in government expenditure and taxes by adding the two multiplier effects that we used in parts a and b :
\(\Delta \mathrm{Y}=\left[(1 /(1-\mathrm{MPC}))^* \Delta \mathrm{G}\right]-[(\mathrm{MPC} /(1-\mathrm{MPC}))]^* \Delta \mathrm{T}\)
Because government purchases and taxes increase by the same amount, we know that \(\Delta \mathrm{G}=\Delta \mathrm{T}$. Therefore we can rewrite the equation as:$$\Delta \mathrm{Y}=[(1 /(1-\mathrm{MPC}))-(\mathrm{MPC} /(1-\mathrm{MPC}))]^* \Delta \mathrm{G}=\Delta \mathrm{G}\)
This expression tells us that an equal increase in government purchases and taxes increases \($\mathrm{Y}$\) by the amount that \($\mathrm{G}$\) increases. That is, the balanced-budget multiplier is exactly 1 .
Complete question: Consider the Keynesian model with a change in the way that taxes are incorporated: (1) PAE = C + IP + G + NX Definition of Planned Aggregate Expenditure (2) C = C+ mpc (1-1) .y Consumption Function (3) PAE = Y Short-run Equilibrium Condition In this case, taxes paid are proportional to income, i.e. taxes paid are t - Y, where t is the tax rate and 0<t< 1. Disposable income is the part of income after taxes, i.e., (1-t). Y. Solve for the PAE spending line with PAE as a function of Y. What is the slope?
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I am struggling to find domain and range please help thank you
Answer:
Domain: 0, 1, 2, 3, 4,
Range: 1, 2, 3, 4, 5,
Step-by-step explanation:
Based on the graph the domain of the function is 0, 1, 2, 3, 4, and the range is 1, 2, 3, 4, 5, therefore, the answer is:
F(x) {x+5}. f(-4}. Why is the answer 9
Answer:
fudjdhajs gf djdjsiwjsj
or
Rewrite the following equation in slope-intercept form.
9x + 19y = 14
Write your answer using integers, proper fractions, and improper fractions in simplest form.
Choose the best graph that represents the linear equation:
-x = 2y + 1
The line slants downward from left to right, indicating that as x increases, y decreases.
The given linear equation is -x = 2y + 1. To represent this equation graphically, we need to rearrange it into the slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.Rearranging the given equation, we get:2y = -x - 1
Dividing both sides by 2:y = (-1/2)x - 1/2
The slope of the line is -1/2, which means that for every unit increase in x, y decreases by 1/2 unit. The y-intercept is -1/2, indicating that the line intersects the y-axis at (0, -1/2).
Based on this information, the best graph that represents the linear equation y = (-1/2)x - 1/2 is a straight line with a negative slope of -1/2, starting at the point (0, -1/2) and extending infinitely in both directions.
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Let u = 2i + 3j, v = –i, and w = 5i – 6j. What is the magnitude of 2(u – v + w)?
10.0
13.4
17.1
21.6
Answer:
C. 17.1
Step-by-step explanation:
edge
Suppose a random sample of 80 measurements is selected from a population with a mean of 25 and a variance of 200. Select the pair that is the mean and standard error of x. Rstudio
a) [25, 2.081]
b) [25, 1.981]
c) [25, 1.681]
d) [25, 1.581]
e) [80, 1.681]
[ 25 , 1.581 ] is the pair that is the mean and standard error of x.
What does standard error mean?
A statistical concept known as the standard error uses standard deviation to assess how well a sample distribution represents a population.
The standard error of the mean describes the statistical variation between a sample mean and the population's actual mean. Measures of variability include standard error and standard deviation: The standard deviation describes variation within a single sample.
n = 80
μ = 25
σ² = 200
mean of x = μ = 25
standard error = √ σ²/n
= √200/80
= 1.581
= [ 25 , 1.581 ]
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what is 3/7 divieded by 6 in a fraction
Which box plot best represents the data?
The box plot that best represents the data is given as follows:
Box plot C.
What does a box and whisker plot shows?A box and whisker plot shows these five metrics from a data-set, listed and explained as follows:
The minimum non-outlier value.The 25th percentile, representing the value which 25% of the data-set is less than and 75% is greater than.The median, which is the middle value of the data-set, the value which 50% of the data-set is less than and 50% is greater than%.The 75th percentile, representing the value which 75% of the data-set is less than and 25% is greater than.The maximum non-outlier value.The ordered data-set for this problem is given as follows:
0, 4, 4, 5, 6, 6, 8, 8, 12, 12.
The minimum and maximum values are given as follows:
Minimum of 0.Maximum of 12.The two middle elements are given as follows:
6 and 6.
Hence the median is:
(6 + 6)/2 = 6.
The first half is 0, 4, 4, 5, hence the first quartile is given as follows:
4.
The second half is 8, 8, 12, 12, hence the third quartile is given as follows:
8.
Hence box plot C is the correct option.
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quantos algarismos esse número possui??
Quantas classes?? E quantas ordens??
Qual classe mais elevada?? E a ordem??
Qual e o algarismo da unidade de milhar??
Quantas unidades vale??
Que algarismo representa a 3 ordem??
Quantas unidades vale??
Me ajude me pra ontem
Answer:
no habla espanol
Step-by-step explanation:
Pie chart values
20%. Rice
15%. Others
Pulses. 30%
maize 20%
wheat 15%
Percentage distribution of products in exports of the
given countries.
(a) What is the value (in $ billion) of pulses export
by US? on a billion
(6)
What is the ratio of wheat export of UK to
maize export of IND? 4:10
(e) By what percentage is the maize export of
JAP more than the rice export of AUS?
(d) If the export of AUS is doubled and that of US is
halved but percentage distribution of products of
export remains the same, then find the value of
Export of Rice by US
Export of Pulses by AUS
In USSR, find the ratio of maize export to the
rice export.
a.) The value of pulses exported by US in billion would be=30 billion.
b.) The ratio of wheat export of UK to maize export of IND would be= 6:5
How to calculate the value of pulses exported?For question a.)
To calculate the pulses, the following steps should be taken as follows:
From the bar chart, the value of pulses in billions = 30 billions.
For question b.)
The ratio of wheat export at UK and maize export at IND would be calculated as follows:
The quantity of wheat export at UK = 24
The quantity of maize export at IND = 20
Therefore, the ratio of wheat to maize = 24:20= 6:5
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Did the enrollment increase at a faster
rate from 2002 to 2008 or 2008 to 2016?
Answer:
From 2008 to 2016
Step-by-step explanation:
Ashraf takes 1500 steps to walk d metres from his home to the station.
Each step is 90 centimetres correct to the nearest 10 cm.
Find the lower bound and the upper bound for d.
Answer:
lower bound = 90 - 10 = 80 cm
upper bound = 90 + 10 = 100 cm
lower bound d = 1500 x 80 cm = 120,000 cm
upper bound d = 1500 x 100 cm = 150,000 cm
Distance of upper bond and lower bond is 120,000 and 150,000 centimeter
Given:
Number of steps walk = 1500 steps
Each step count = 90 centimetres
Correction in each step = 10 cm nearset
Find:
Lower bound and upper bound for d
Computation:
Lower bound step length = 90 - 10
Lower bound step length = 80 centimetres
Upper bound step length = 90 + 10
Upper bound step length = 100 centimetres
Lower bound d = 1500 × 80
Lower bound d = 120,000 centimetres
Upper bound d = 1500 × 100
Upper bound d = 150,000 centimetres
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Explain in detail using words the step by step process that Maggie took to solve the problem 6.89 x 10^-4 / 7.5 x 10^-6 = .92 x 10^1
The steps in solving the given expression shows that the result is:
0.92 * 10²
How to use Laws of Exponents?The expression is given as:
6.89 * 10⁻⁴/(7.5 * 10⁻⁶) = 0.92 * 10¹
The steps that Maggie followed are:
Step 1: Rewrite the given expression:
6.89 * 10⁻⁴/(7.5 * 10⁻⁶) = 0.92 * 10¹
Step 2: Divide the coefficients:
The coefficient of the numerator (6.89) is divided by the coefficient of the denominator (7.5) to get:
6.89 / 7.5 = 0.9186667.
Step 3: Divide the powers of 10:
This is done by subtracting the exponent of the denominator 10⁻⁶ from the exponent of the numerator 10⁻⁴ to get: 10²
Step 4: Combine the results:
This gives:
0.9186667 * 10²
Step 5: Simplify the coefficient:
She rounded the coefficient (0.9186667) to two decimal places, resulting in 0.92.
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Multiply
(8X + 8)(8x2 + 3x + 7)
(Simplify your answer.)
Step-by-step explanation:
8x^3 + 24x^2 + 56x + 64x^2 +24x +56
8x^3 + 88x^2 + 80x +56
Answer:
64x^3+88x^2+80x+56
Step-by-step explanation:
(8x+8)(8x^2+3x+7)
64x^3+24x^2+56x+64x^2+24x+56
64x^3+24x^2+64x^2+56x+24x+56
64x^3+88x^2+80x+56
What is 7/8 as a number?
The value of the fraction 7/8 is 0.875
Fraction:
In math, a numerical value that expresses a part of a whole is known as fraction.
The standard form of the fraction is written as,
=> a/b
where a refers the numerator and b refers the denominator.
And the value of b is greeter than zero.
For example, 5/3 is a fraction.
Given,
Here we need to find the value of the fraction 7/8.
We know that,
=> 7/8
is the same as
=> 7÷8
Then by using Long Division for 7 divided by 8 and rounding to a Max of 3 Decimal Places gives us
=> 0.875
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In 1995, wolves were introduced into Yellowstone Park.
The function `w\left(x\right)=14\cdot1.08^{x}` models the number of wolves, `w`, in the years since 1995, `x`.
Determine the value of `w(25)`.
What does this value say about the wolf population?
Answer:
w(25) = 96
There are 96 wolves in the year 2020
Step-by-step explanation:
Given:
\(w(x)=14\cdot 1.08^{x}\)
w(25) =
\(w(25)=14\cdot 1.08^{25}\\\\= 14 * (6.848)\\\\=95.872\\\\\approx 96\)
Number of years : 1995 + 25 = 2020
In 2020, there are 96 wolves